Hi,
I've the following kind of data
Time Country Values
2010Q1India 5
2010Q2India 7
2010Q3India 5
2010Q4India
B == Baan baanba...@gmail.com
on Mon, 4 Mar 2013 22:47:10 +0530 writes:
B Thank you Martin. Look forward to the fix.
Committed to the R-forge version of robustbase.
It was a simple integer overflow, indeed,
necessarily happening when the sample size was = 2^16.5.
I'm planning to
Hello,
I am using sm.density() to find the bivariate joint PDFof events:
For eg,
x-cbind(rnorm(30),rnorm(30))
den-sm.density(x)
Then I get the joint pdf from den$estimate in order to constructthe
joint cumulative PDF.
However, summing up all the values from den$estimateisnot equal to
1(have
On Mar 6, 2013, at 03:56 , Rolf Turner wrote:
Your subject line is patent nonsense. The aov() and anova() functions
have been around for decades. If they were doing something wrong
it would have been noticed long since.
You should realize that the fault is in your understanding, not
Hello,
I am a rather unexperienced r-user (learned the language 1 month ago) and
run into the following problem using a local computer with 6 cores 24 GB
RAM and R 2.15 64-bit. I didn't install any additional packages
1. Via the read.table command I load a data table (with different data
types)
All,
I have just returned to R after a decade of absence, and it is good to
see that R has become such a great success! I'm trying to bring Design
of Experiments into some aspects of software performance evaluation, and
to teach myself that, I picked up Experiments: Planning, Analysis and
most likely either 'lower' or 'upper' is NA. put
options(error = recover)
in your script to stop on the error and examine the value. you need to learn
debugging 101 to help yourself out.
Sent from my iPad
On Mar 5, 2013, at 16:00, li li hannah@gmail.com wrote:
Dear all,
I got an
On 03/06/2013 07:06 PM, Anindya Sankar Dey wrote:
Hi,
I've the following kind of data
Time Country Values
2010Q1India 5
2010Q2India 7
2010Q3India
Dear useRs,
I have a matrix in the following form
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11]
1 1 3 2 3 1 1 2 3 3 2
and following is my desired output (combining the column headers, having same
Thanks so much. I see my foolish ways now.
--
View this message in context:
http://r.789695.n4.nabble.com/aov-and-anova-making-faulty-F-tests-tp4660407p4660439.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org
Dear Alex,
Here you have some url's:
http://data.princeton.edu/R/linearModels.html
http://www.r-bloggers.com/r-tutorial-series-simple-linear-regression/
Regards,
Eva
--- El mié, 6/3/13, Alaios ala...@yahoo.com escribió:
De: Alaios ala...@yahoo.com
Asunto: [R] lm and Formula tutorial
Para: R
Dear Eliza,
You question is not very clear. I think you are looking for the which()
function.
Best regards,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie Kwaliteitszorg / team Biometrics Quality Assurance
On 03/06/2013 12:45 AM, km wrote:
Dear All,
I have a table as following
position type count
1 2 100
1 3 51
1 5 64
1 8 81
1 6 32
2 2 41
2 3 85
and so on
Normally if would have a vector of
On Wed, Mar 6, 2013 at 9:51 AM, Jonas125 schleeberge...@pg.com wrote:
Hello,
I am a rather unexperienced r-user (learned the language 1 month ago) and
run into the following problem using a local computer with 6 cores 24 GB
RAM and R 2.15 64-bit. I didn't install any additional packages
1.
Hello,
You've forgot to use a geom.
Also, to have Time be the x axis variable you need to do a conversion.
library(ggplot2)
dat - read.table(text =
Time Country Values
2010Q1India 5
2010Q2India
Hi,
# For publications, I am not allowed to repeat the axes. I have tried to
remove the axes using:
# yaxt=n, but it did not work. I have not understood how to do this in
ggplot2. Can you help me?
# I also do not want loads of space between the graphs (see below script
with Dummy Data).
# If
Hi,
Try this:
mat1- as.matrix(read.table(text=
1 1 3 2 3 1 1 2 3 3 2
,sep=,header=FALSE))
res-lapply(1:3,function(i) which(mat1==i))
names(res)- c(a,c,b)
res
#$a
#[1] 1 2 6 7
#$c
#[1] 4 8 11
#$b
#[1] 3 5 9 10
A.K.
- Original
Look at the function melt and use the factor columns as id variables.
You should be able to do what you want with facet_grid. I have found
inkscape useful to build legends and modify axes labels. I know this is
only a partial answer, but I hope this helps.
Stephen
On Wed 06 Mar 2013
SPPS is offering a chi square exact test for one dimensional data with
small sample size (6).
What is the comparable function in R?
Kind Regards Knut
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PLEASE do read
On 05.03.2013 11:21, Johannes Radinger wrote:
Hi,
I am compiling a R-package and have two tables (.rda files) that are used
by the functions in my package. In the manual for ?data
(http://stat.ethz.ch/R-manual/R-patched/library/utils/html/data.html),
there is a chapter on good practice for
A quick google search produces multiple results. Good luck. :)
~Nicole Ford
Ph.D. Student
Graduate Assistant/ Instructor
Department of Government and International Affairs
University of South Florida
office: SOC 012M
Sent from my iPhone
On Mar 6, 2013, at 6:30 AM, Knut Krueger
Hi HJ,
Tem2- as.data.frame(Tem1)
res-do.call(rbind,split(Tem2,Tem2$V1))
row.names(res)- 1:nrow(res)
head(res,7)
# V1 V2
#1 111 1
#2 111 2
#3 111 3
#4 111 4
#5 111 13
#6 111 14
#7 111 15
A.K.
From: HJ YAN yhj...@googlemail.com
To: arun
Thanks, David! That makes sense. I shall re-read the manual page again.
Regards,
Mike Nielsen
On Wed, Feb 27, 2013 at 12:19 PM, David Winsemius dwinsem...@comcast.netwrote:
On Feb 27, 2013, at 6:39 AM, Mike Nielsen wrote:
Hi r-helpers.
Please forgive my ignorance, but I would like
Kjetil Kjernsmo kjekje at ifi.uio.no writes:
All,
I have just returned to R after a decade of absence, and it is good to
see that R has become such a great success! I'm trying to bring Design
of Experiments into some aspects of software performance evaluation, and
to teach myself
Hi,
You can also try this:
Tem3- list()
for(i in unique(Tem1[,1])) {
Tem3[[i]]- subset(Tem1,Tem1[,1]==i)
Tem4- do.call(rbind,Tem3)
}
head(Tem4)
# V1 V2
#[1,] 111 1
#[2,] 111 2
#[3,] 111 3
#[4,] 111 4
#[5,] 111 13
#[6,] 111 14
#or
Tem3-c(NA,NA)
for(i in unique(Tem1[,1])) {
Tem2-
Le mardi 05 mars 2013 à 15:19 -0800, Benjamin Caldwell a écrit :
Hi all,
Thanks for the suggestions. Updating the function as below to break the
problem into chunks seemed to do the trick - perhaps there is a relatively
small limit to the size of a vector that R can work with?
On the
Hi,
On Wed, Mar 6, 2013 at 5:46 AM, Kjetil Kjernsmo kje...@ifi.uio.no wrote:
All,
I have just returned to R after a decade of absence, and it is good to see
that R has become such a great success! I'm trying to bring Design of
Experiments into some aspects of software performance evaluation,
Hi,
I am trying to create unique filenames for my output text file. The idea is
that I would like to append a string to .zsc.txt so that all my files are
uniquely named but with a similar format. I have tried adding the string
variable to .zsc.txt while creating the output file name, i.e.
On 06.03.2013 15:20, Sahana Srinivasan wrote:
Hi,
I am trying to create unique filenames for my output text file. The idea is
that I would like to append a string to .zsc.txt so that all my files are
uniquely named but with a similar format. I have tried adding the string
variable to .zsc.txt
Hello,
On Mar 6, 2013, at 9:20 AM, Sahana Srinivasan wrote:
Hi,
I am trying to create unique filenames for my output text file. The idea is
that I would like to append a string to .zsc.txt so that all my files are
uniquely named but with a similar format. I have tried adding the string
I may be wrong, but I believe what makes it difficult is that the Help
file assumes some linear model statistics that you may not have. I
suggest that you look for a tutorial on linear models first and then
re-read the Help. Incidentally, the provenance of the syntax is GLIM
(correction requested
On 03/06/2013 02:50 PM, Ben Bolker wrote:
Just a quick thought (sorry for removing context): what happens if
you use sum-to-zero contrasts throughout, i.e. options(contrasts=c(contr.sum,
contr.poly)) ... ?
That works (except for the sign)! What would this mean?
Kjetil
As Ista indicates, the basic issue is that the OP does not understand
linear modeling and is therefore just thrashing around with lm. For
example, the statement about effects being double coefficient is only
true with the orthogonal (-1,1) parameterization of the contrasts.
So I suggest the OP
James,
I did a fresh install from CRAN to get caret_5.15-61 and ran your code with
method.name = nnet and grid.len = 3.
I don't get an error, although there were issues:
In nominalTrainWorkflow(dat = trainData, info = trainInfo, ... :
There were missing values in resampled performance
Hello,
Try
x - scan(text = 1 1 3 2 3 1 1
2 3 3 2)
sapply(unique(x), function(.x) which(x == .x))
Hope this helps,
Rui Barradas
Em 06-03-2013 11:26, eliza botto escreveu:
Dear useRs,
I have a matrix in the following form
[,1] [,2]
On Mar 6, 2013, at 4:46 AM, Kjetil Kjernsmo kje...@ifi.uio.no wrote:
All,
I have just returned to R after a decade of absence, and it is good to see
that R has become such a great success! I'm trying to bring Design of
Experiments into some aspects of software performance evaluation, and
On 03/06/2013 04:18 PM, Peter Claussen wrote:
I'll ignore the rest of your question, in the hope that this will answer them
sufficiently.
OK!
You probably want a simple linear model, specified in R using + instead of
*.
leaf.lm - lm(yavg ~ B + C + D + E + Q, data=leaf)
leaf.lm
Call:
On Mar 6, 2013, at 9:23 AM, Kjetil Kjernsmo kje...@ifi.uio.no wrote:
On 03/06/2013 04:18 PM, Peter Claussen wrote:
I'll ignore the rest of your question, in the hope that this will answer
them sufficiently.
OK!
You probably want a simple linear model, specified in R using + instead of
Hi!
I have problems with labeling x axis while plotting time series data. I have
40 monthly measurement. One period lasts 4 months. I'd like to have 40 ticks
on x axis (10 larger, the rest smaller) and labels just at the beginning of
each period, just like in the image
Hi Arun
Thank you so much for the help, that's really helpful!!
Also I have a quick question about the code below where I can not see why
it doesn't work...
I know the I shou
V1-c(rep(111,4),rep(222,4),rep(333,4),rep(111,4),rep(222,4),rep(333,3))
V2-c(1:23)
Tem1-cbind(V1,V2)
So Tem 1 looks
Dear R users,
I am new to R and looking into using a Friedman test in R with post-hoc
analysis for a time series datset in which I am looking at changes in
multiple features over three time points in a number of individuals. As
well as detecting if there is an overall difference in features
Dear Anna,
Is this what you would like?
Summ - ddply(mydata, .(factor3,factor1), summarize,
mean = mean(var1, na.rm = FALSE),
sdv = sd(var1, na.rm = FALSE),
se = 1.96*(sd(var1, na.rm=FALSE)/sqrt(length(var1
Summ$Grouping
On Mar 6, 2013, at 4:46 AM, Kjetil Kjernsmo kje...@ifi.uio.no wrote:
All,
I have just returned to R after a decade of absence, and it is good to see
that R has become such a great success! I'm trying to bring Design of
Experiments into some aspects of software performance evaluation, and
Hello,
I'm doing a comparative analysis of mammal brain and body size data.
I'm following Charlie Nunn and Natalie Cooper's instructions for
Running PGLS in R using caper.
I run into the following error when I create my comparative dataset,
combining my phylogenetic tree (mammaltree) and taxon
I use R (2.15.2) on a windows 7 (64) for data mining with xcms package. This
is a routine process for me and didn't encount any problems until few weeks
ago when I got an error message for R GUI frond end has stopped working.
The following information was given by windows to describe the error.
On 05/03/2013 7:53 PM, Victor hyk wrote:
Hello everyone,
I have a basic question regarding logical operators.
x-seq(-1,1,by=0.02)
x
[1] -1.00 -0.98 -0.96 -0.94 -0.92 -0.90 -0.88 -0.86 -0.84 -0.82 -0.80 -0.78
[13] -0.76 -0.74 -0.72 -0.70 -0.68 -0.66 -0.64 -0.62 -0.60 -0.58 -0.56
Hi everyone,
I'm trying to print a table justified to the left, but it doesn't work.
Any hints?
KennArt - data.frame(NR=c(171,172,174,175,176,177,181,411,980),
TYP=c(Körnermais,
Corn Cob Mix, Zuckermais, Mischanbau (Silo)Mais/Sonnenblumen,
Mais mit Bejagungsschneise in gutem
Hi,
No problem.
V1-rep(c(rep(111,5),rep(222,5),rep(333,5)),2)
length(V1)
#[1] 30
V2- c(1:30) #should be the same length as V1
Tem1- cbind(V1,V2)
Tem2-Tem1[1:20,]
Tem1[!Tem1[,2]%in%Tem2[,2],]
# V1 V2
#[1,] 222 21
#[2,] 222 22
#[3,] 222 23
#[4,] 222 24
#[5,] 222 25
#[6,] 333 26
Just to add:
Tem1[Tem1[,2]%in%setdiff(Tem1[,2],Tem2[,2]),]
A.K.
- Original Message -
From: arun smartpink...@yahoo.com
To: HJ YAN yhj...@googlemail.com
Cc: R help r-help@r-project.org
Sent: Wednesday, March 6, 2013 11:06 AM
Subject: Re: [R] How to combine conditional argument and
I don't know about justify as an arg to print, but the following should
qualify as a hint.
format(c('a','aa','aaa'), justify='left')
[1] a aa aaa
tmp - data.frame(a=c('a','aa','aaa'))
print(tmp,justify='left')
a
1 a
2 aa
3 aaa
tmp$b - format(c('a','aa','aaa'),justify='left')
Thank you Max. I presume that in order to use caret with nnet and MaxNWts,
I would have to write my custom method for train that supports this new
argument.
From what I read, when writing my custom method, I would need to define
functions parameters, model, prediction, prob and sort and pass
them
The datatable (and the split obviously) only contain characters and numeric
data.
I found that 4 regression in a row work if I don't use the calculated
columns as variables but 2 of the original columns.
RAM usage stays below 3GB!
-- Why does R has such problems with the calculated columns?
Le mercredi 06 mars 2013 à 08:31 -0800, Jonas125 a écrit :
The datatable (and the split obviously) only contain characters and numeric
data.
I found that 4 regression in a row work if I don't use the calculated
columns as variables but 2 of the original columns.
RAM usage stays below 3GB!
x[x0.2]
[1] -1.00 -0.98 -0.96 -0.94 -0.92 -0.90 -0.88 -0.86 -0.84 -0.82 -0.80
-0.78
This is a bit off the original topic, but you should really put spaces around
the .
Otherwise you might be surprised when you compare x to -0.2 instead of +0.2:
x-seq(-1,1,by=0.02)
x[x-0.2]
Am 06.03.2013 14:27, schrieb Nicole Ford:
Dear Nicole,
my be you are wondering about, but I know Google an I am using google
before I am asking here.
If you are more familiar with googl,e please help me to find the search
term where I can find
the R function for
chi square exact usable for
R 2.15.2
OS X
Colleagues,
I often use rainbow to select colors. I encountered a surprise with
rainbow(11). It yielded three greens (in positions 4-6). The first two of
these are quite similar. The man pages suggest that this might be the case:
equispaced hues in RGB space tend to
Length(Datasplit) = 7100
I did a regression for Datasplit[[1]] and the calculated columns -- the
object size is 70 MB. Quite large
Assuming that R cannot handle inf values in regressions (didn't have the
time to google it)
How can I avoid the calculation of infinite values? Like If the
Le mercredi 06 mars 2013 à 09:18 -0800, Jonas125 a écrit :
Length(Datasplit) = 7100
I did a regression for Datasplit[[1]] and the calculated columns -- the
object size is 70 MB. Quite large
7100*70/1024 = 485 (GB)
No wonder why you run out of memory quite fast.
You probably do not need
Le mercredi 06 mars 2013 à 18:03 +0100, Knut Krueger a écrit :
Am 06.03.2013 14:27, schrieb Nicole Ford:
Dear Nicole,
my be you are wondering about, but I know Google an I am using google
before I am asking here.
If you are more familiar with googl,e please help me to find the search
Am 06.03.2013 18:29, schrieb Milan Bouchet-Valat:
Le mercredi 06 mars 2013 à 18:03 +0100, Knut Krueger a écrit :
Am 06.03.2013 14:27, schrieb Nicole Ford:
Dear Nicole,
my be you are wondering about, but I know Google an I am using google
before I am asking here.
If you are more familiar
When the population values are not distributed symmetrically about the mean,
reporting the mean and standard deviation can give the reader an inaccurate
impression of the distribution of values in the population.
I'd like generating random samples with same mean and standard deviation, but
not
For the simplist of the issues use scale_shape(solid = FALSE) to get hollow
points
Using your data (below) this seems to work
p1 - ggplot(SummAB, aes(factor3, mean,
colour = factor1, group = factor1,shape = factor1)) +
scale_y_continuous(guide_legend(legend.position=c(4
On 06/03/2013 12:57 PM, jsdroyster wrote:
Hello kind and R-knowledgeable souls!
I am trying to use read.fortran to read in old datasets in 80-column-card format
with no separators between variables (just 80 columns of solid digits).
I comprehend the instructions for specifying the columns for
Hello kind and R-knowledgeable souls!
I am trying to use read.fortran to read in old datasets in 80-column-card
format
with no separators between variables (just 80 columns of solid digits).
I comprehend the instructions for specifying the columns for each variable, but
I can't understand how
Glad to know. Thanks.
Regards
Baan
On Wednesday 06 March 2013 02:15 PM, Martin Maechler wrote:
B == Baan baanba...@gmail.com
on Mon, 4 Mar 2013 22:47:10 +0530 writes:
B Thank you Martin. Look forward to the fix.
Committed to the R-forge version of robustbase.
It was a simple
Hi,
I'd like to draw a graph like this one from Stanton Glantz book, Primer of
Biostatistics.
Thanks
Angelo
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Placing a legend.
z - ggplot(mtcars, aes(wt, mpg, colour = factor(cyl))) + geom_point()
z + theme(legend.position = c(.5, .5))
Currently this does not appear to work in RStudio but seems fine if I use gedit
or if I run R in a terminal session.
John Kane
Kingston ON Canada
Le mercredi 06 mars 2013 à 18:38 +0100, Knut Krueger a écrit :
Am 06.03.2013 18:29, schrieb Milan Bouchet-Valat:
Le mercredi 06 mars 2013 à 18:03 +0100, Knut Krueger a écrit :
Am 06.03.2013 14:27, schrieb Nicole Ford:
Dear Nicole,
my be you are wondering about, but I know Google an I am
No link and/ no attached file. The list tends to strip most attachments to
reduce virus attacks.
John Kane
Kingston ON Canada
-Original Message-
From: angeloscozzare...@tiscali.it
Sent: Wed, 6 Mar 2013 19:53:18 +0100
To: r-help@r-project.org
Subject: [R] Graph from Glantz
Hi, can I understand why this message was rejected ?
Thanks,
Eliano
Sent from my iPhone
On 6 Mar 2013, at 19:18, Eliano eliano.m.marq...@gmail.com wrote:
Hi everyone,
I am writing some code to generate a function. I am passing that code to a
dataset which i'm importing in R, e.g.
Replying to my own post RStudio is doing this fine once I had rebooted R. I
must have had some strange stuff loaded that I had not realised was there.
John Kane
Kingston ON Canada
-Original Message-
From: jrkrid...@inbox.com
Sent: Wed, 6 Mar 2013 11:16:28 -0800
To:
On 06/03/2013 07:20, Andrew Hoerner wrote:
Dear Patrick--
After the official Core Team's R manuals and the individual function
help pages, I have found The R Inferno to be the single most useful
piece of documentation when I have gotten stuck with a R problems. It is
the only introduction that
On 2013-03-06 06:07, iDa wrote:
Hi!
I have problems with labeling x axis while plotting time series data. I have
40 monthly measurement. One period lasts 4 months. I'd like to have 40 ticks
on x axis (10 larger, the rest smaller) and labels just at the beginning of
each period, just like in the
There are a few places left on the following course: Beginner's Guide
to MCMC, GLM and GAM with R
When: 10 - 13 June 2013
Where: SAMS, Oban, Scotland
Further information: http://www.highstat.com/statscourse.htm
Flyer: http://www.highstat.com/Courses/Flyer2013June_SAMS.pdf
Kind regards,
Hello everyone,
I was reading a table into R, and when trying to retrieve it the following
message appeared:
[ reached getOption(max.print) -- omitted 469376 rows ]
Does this mean that R left out 469376 rows? Or R is taking those 469376
rows as well and the limitation is only for printing
On Wed, 6 Mar 2013, Paul Bernal wrote:
I was reading a table into R, and when trying to retrieve it the following
message appeared:
[ reached getOption(max.print) -- omitted 469376 rows ]
Does this mean that R left out 469376 rows? Or R is taking those 469376
rows as well and the limitation
On 06/03/2013 3:58 PM, Paul Bernal wrote:
Hello everyone,
I was reading a table into R, and when trying to retrieve it the following
message appeared:
[ reached getOption(max.print) -- omitted 469376 rows ]
Does this mean that R left out 469376 rows? Or R is taking those 469376
rows as well
just a limitation on the printing of the data to the console. Change the
'max.print' option if you want more lines output to the console.
On Wed, Mar 6, 2013 at 3:58 PM, Paul Bernal paulberna...@gmail.com wrote:
Hello everyone,
I was reading a table into R, and when trying to retrieve it the
Hi,
I am using xmlToList() in a loop with a call to a webservice, per the code
below.
# Loop thru target locs
for(i in 1:num.target.locs) {
url - paste(sep=/, http://www.earthtools.org/timezone;, lat[i], lon[i])
tmp - xmlToList(url)
df$time.offset[i] - tmp$offset
Actually, the http://www.sussex.ac.uk/its/pdfs/SPSS_Exact_Tests_20.pdf file
indicates that for small samples and a one-way chi square test, SPSS uses a
multinomial distribution to tabulate the distribution of chi square for a given
N, K, and probability of membership in each group. In package
Since nobody else has mentioned it: if you are seeing that message
when you are reading data in, then you probably failed to assign the
data to an R object.
mydata - read.table(somefile) # correct
read.table(somefile) # will simply print your data to the console, not save it
I'm not entirely
Hi,
How about this:
indxTem1-paste0(Tem1[,1],Tem1[,2])
indxTem2-paste0(Tem2[,1],Tem2[,2])
Tem1[!indxTem1%in%indxTem2,]
# V1 V2
#[1,] 333 11
#[2,] 111 16
#[3,] 111 17
#[4,] 111 20
#[5,] 222 21
#[6,] 222 22
#[7,] 222 23
#[8,] 222 1
#[9,] 222 2
#[10,] 333 3
#[11,] 333 4
#[12,]
Hi,
Does anyone know how (or whether or not it's possible) to output an inverse
of a functional object? I haven't found a way, but since derivatives etc.
can be computed using the fda package it seems like this should be
possible using this package or another designed for functional data
Dear Arun
Thanks a million for your prompt reply and I love all four ways in your
reply.
Tried the code and just realised an issue here: in my real work, my data
is about 4GB large and I'm sure that there are many duplicated values in
V2, so that is to say my V1 and V2 should be something like
Hi,
On Mar 6, 2013, at 4:12 PM, Waichler, Scott R wrote:
Hi,
I am using xmlToList() in a loop with a call to a webservice, per the code
below.
# Loop thru target locs
for(i in 1:num.target.locs) {
url - paste(sep=/, http://www.earthtools.org/timezone;, lat[i], lon[i])
tmp -
On 2013-03-06 12:54, zoe richards wrote:
Hi,
Does anyone know how (or whether or not it's possible) to output an inverse
of a functional object? I haven't found a way, but since derivatives etc.
can be computed using the fda package it seems like this should be
possible using this package or
Hi,
I am not sure I understand it correctly.
In the example you gave, there are duplicated rows in Tem1, ie. (222 6 ), (222
7), (333 11), but these rows are also present in Tem2
Is there any chance of triplicates etc..
Also, you wanted to have rows that are not common in Tem1 and Tem2. ie.
On Mar 6, 2013, at 11:25 AM, Eliano Marques wrote:
Hi, can I understand why this message was rejected ?
Thanks,
Eliano
First hit on a Markmail search:
http://markmail.org/message/5xog3ayx4amprsdx?q=list:org%2Er-project%2Er-help+nabble+rejected
--
David.
Sent from my iPhone
On 6 Mar
I am trying to register unemployment rate and inverse of inflation rate to
investigate the phillips
curvehttp://www.econlib.org/library/Enc/PhillipsCurve.html by
looking at the resulting warping function.
On Wed, Mar 6, 2013 at 5:17 PM, Peter Ehlers ehl...@ucalgary.ca wrote:
On 2013-03-06
Hi Arun
Massive thanks for the hints of making use of 'paste0'!
But coincidentally there were no pair of data exactly same in indxTem1 and
indxTem2 in the previous example. I changed data as below which is very
likely to be in my real data...
V1-rep(c(rep(111,5),rep(222,5),rep(333,5)),2) # V1
Hi,
I have a data frame with two columns. I need to remove duplicated rows in
first column, but I need to do it conditionally to values of the second
column.
Example:
Point_counts Psi_Sp
1A 0
2A 1
3B
Thanks. Btw are you able to help with my issue? Thanks, Eliano
Sent from my iPhone
On 6 Mar 2013, at 23:41, David Winsemius [via R]
ml-node+s789695n4660547...@n4.nabble.com wrote:
On Mar 6, 2013, at 11:25 AM, Eliano Marques wrote:
Hi, can I understand why this message was rejected ?
On Wed, Mar 6, 2013 at 4:18 PM, Yao He yao.h.1...@gmail.com wrote:
Dear all:
I have a big data file of 6 columns and 6 rows like that:
AA AC AA AA ...AT
CC CC CT CT...TC
..
.
I want to transpose it and the output is a new
On Wed, Mar 6, 2013 at 7:56 PM, Peter Langfelder
peter.langfel...@gmail.com wrote:
On Wed, Mar 6, 2013 at 4:18 PM, Yao He yao.h.1...@gmail.com wrote:
Dear all:
I have a big data file of 6 columns and 6 rows like that:
AA AC AA AA ...AT
CC CC CT CT...TC
On Mar 6, 2013, at 3:21 PM, Francisco Carvalho Diniz wrote:
Hi,
I have a data frame with two columns. I need to remove duplicated rows in
first column, but I need to do it conditionally to values of the second
column.
Example:
Point_counts Psi_Sp
1A
Hi,
dfrm- read.table(text=
Point_counts Psi_Sp
1 A 0
2 A 1
3 B 1
4 B 2
5 B 0
6 C 1
7
Hi Irucka,
I tried it and was able to plot it without any errors. Here, your code
indicates you need two lines. temper[[i]][1]
temper[[1]][1] # which is the column 1.
Month
1 1
2 2
3 3
temper[[1]][2]
# Data1
#1 1.5
#2 12.3
#3 11.4
Suppose I use names(temper) instead of
On Mar 6, 2013, at 3:44 PM, Eliano wrote:
Thanks. Btw are you able to help with my issue? Thanks, Eliano
I'm sorry, I was too busy answering the question from 'Eliano' over on
StackOverflow. I didn't have time to address this one.
(Please do note that cross-posting questions to Rhelp is
Generic question... I am familiar with generic power calculations in R,
however a lot of the data I primarily work with is multivariate. Is there
any package/function that you would recommend to conduct such power
analysis? Any recommendations would be appreciated.
Thank you for your time,
Is there a R package that use sampling weights in multilevel modeling? The
survey package does not handle multilevel modeling and the weight option in
lmer and nlmer functions from lme4 (used for multilevel modeling) is for
weighted least squares estimation.
Suggestion from one with experience
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