I believe mapshaper has functionality for removing small 'islands'.
There is a webinterface for mapshaper, but I see there is also an
R-package (see
https://search.r-project.org/CRAN/refmans/rmapshaper/html/ms_filter_islands.html
for island removal).
If you want to manually select which
Dear Bert,
Thank you very much for your quick reply.
I have tested this, and it indeed appears to be the source of the discrepancy I
observed.
My apologies for overlooking this in the documentation and thank you for
clarifying.
Cheers,
Jan
From: Bert Gunter
Dear Sir, Madam, or to whom this may concern,
my name is Jan Failenschmid and I am a Ph.D. student at Tilburg University.
For my project I have been looking into different types of kernel regression
estimators and corresponding R functions.
While comparing different functions I noticed
: except perhaps 'V'.
I can't say how the support for non-ascii text is over different OS-es
and localities.
https://cran.r-project.org/doc/manuals/r-release/R-exts.html#Encoding-issues
gives some 'hints'
On 06-10-2023 14:21, Chris Evans via R-help wrote:
Thanks again Jan. That is lovely
t; = "grey",
"C" = "green"),
labels = c("Deteriorated",
"No change",
"Improved")) +
scale_fill_manual(name = "Change",
Does adding
, show.legend = c("color"=TRUE, "fill"=FALSE)
to the geom_point do what you want?
Best,
Jan
On 06-10-2023 11:09, Chris Evans via R-help wrote:
library(tidyverse)
tibble(x = 2:9, y = 2:9, c = c(rep("A", 5), rep("B", 3))) -> tmpTibPoints
Shorter/simpler alternative for adding a alpha channel
adjustcolor("lightblue", alpha = 0.5)
So I would use something like:
# Open new plot; make sure limits are ok; but don't plot
plot(0, 0, xlim=c(1,20),
ylim = range(c(mean1+sd1, mean2+sd2, mean1-sd1, mean2-sd2)),
type="n", las=1,
ied-R² to the result, respectively (this is more efficient
than using r.squaredLR directly).
HTH
Jan
On 17-07-2023 19:24, Paul Bernal wrote:
Dear friends,
I need to automatically fit all possible linear regression models (with all
possible combinations of regressors), and found the MuMI
Perhaps the ragg package? That has an `agg_capture` device "that lets
you access the device buffer directly from your R session."
https://github.com/r-lib/ragg
HTH,
Jan
On 28-05-2023 13:46, Duncan Murdoch wrote:
Is there a way to open a graphics device that plots entirely t
ist(. = .), enclos = parent.frame())
}
1:3 |> dot(func(1, ., mean(.)))
This seams simpler than the lambda notation and more general than your
solution. Not sure if this has any drawbacks.
HTH,
Jan
On 08-03-2023 21:23, avi.e.gr...@gmail.com wrote:
I see many are not thrilled with the co
You could try to see what stattransfer can make of it. They have a free
version that imports only part of the data. You could use that to see if
stattransfer would help and perhaps discover what format it is in.
HTH
Jsn
On 16-01-2023 23:22, Joseph Voelkel wrote:
Dear foreign maintainers and
You're sure the extra column is indeed an extra column? According to the
documentation
(https://artefacts.ceda.ac.uk/badc_datadocs/ukmo-midas/RH_Table.html)
there should be 15 columns.
Could it, for example, be that one of the columns contains records with
commas?
Jan
On 29-09-2022 15
mple(1:9, n, replace = TRUE),
event = sample(0:1, n, replace = TRUE)
)
tab <- dta[, .(n = .N, rate = sum(event)/.N),
by = .(level1, level2, level3)]
treemap(tab, index = names(tab)[1:3], vSize = "n", vColor = "rate",
type = "value", fontsize.labels = 20*c(
I have data in a matrix form of order 1826*24 where 1826 represents the days
and 24 hourly observations on each data. My objective is to split the matrix
into working (Monday to Friday) and non-working (Saturday and Sunday)
submatrices. Can anyone help me that how I will do that splitting using
seems to contain an error: `s = df[df$y == i,]`
should be `s = df$z[df$y == i]` I think.
HTH,
Jan
On 17-11-2021 14:20, Luigi Marongiu wrote:
Hello,
I have a dataframe with 3 variables. I want to loop through it to get
the mean value of the variable `z`, as follows:
```
df = data.frame(x = c
ptions, for example %in%, match, duplicated. These are also
vectorised; so two vectors: one with keys and one with values might
actually be faster than an environment in some use cases.
Best,
Jan
And there are also packages for many features like sets as well as functions
to manipulate these
ate a data.frame with
multiple columns with the same name. But as Duncan Murdoch mentions you
can usually control for that.
Best,
Jan
On 02-11-2021 11:32, Yonghua Peng wrote:
But for data.frame the colnames can be duplicated. Am I right?
Regards.
On Tue, Nov 2, 2021 at 6:29 PM Jan van der L
True, but in a lot of cases where a python user might use a dict an R
user will probably use a list; or when we are talking about arrays of
dicts in python, the R solution will probably be a data.frame (with each
dict field in a separate column).
Jan
On 02-11-2021 11:18, Eric Berger
age? In that case you also have to set the seed in the
parallel workers.
Best,
Jan
On 19-08-2021 11:25, PIKAL Petr wrote:
Hi
Did you try different order?
Step 2: set.seed (123)
Step 1. Self-coded functions (these functions generate random numbers as well)
Step 3: Call those functions.
S
I have data matrix of order 24*2192 where 2192 are the days and 24 are hour's
of a single day,so simple words I have 2192 days and each day having 24
observations.the data matrix is divided into two matrix,the ist matrix is of
order 24*1827 and second is of order 24*365. Suppose the ist column
accept.
Also, because it is a binary compressed format using a compression
method that is fast to read, compressing also to zip seems to defeat the
purpose of fst.
HTH,
Jan
On 09-06-2021 15:28, Duncan Murdoch wrote:
On 09/06/2021 9:12 a.m., Jeff Reichman wrote:
Duncan
Yea that will work
helping you decide which method to use does not fit on this
list. Perhaps de overview linked to above (and the terms 'grid search'
and 'optimization') can help you find an appropriate method.
HTH,
Jan
On 20-04-2021 09:02, PIKAL Petr wrote:
Hi
Keep your mails on the list. Actually you did
600/24/365
[1] 3170.979
years.
--
Jan
On 20-04-2021 03:46, Avi Gross via R-help wrote:
Just some thoughts I am considering about the issue of how to make giant
objects in memory without making them giant or all in memory.
As stupid as this sounds, when things get really big, it ca
-
Hi, hope that you will be fine, I have a problem with functional time series,
I am working with the hourly electricity spot price data, due to the large
dimensionality I convert the discrete data into functional data. The model I
use the functional autoregressive model of order
centrally on the
server/network, so I actually usually end up with a mixture of central,
personal and project libraries. Theory vs practice.
HTH,
Jan
On 08-04-2021 02:58, Dirk Eddelbuettel wrote:
Hi Gene,
"It's complicated". (Not really, but listen for a sec...)
We need to ship a defa
I am new in the functional time series, my question may be stupid as I am
new, I am functional forecasting one year a head, Know I want to check the
forecast accuracy by calculating the mean absolute percentage error, but I am
unable to due this R, please help me or suggest me any link which
I am working in the functional time series, I obtain the one year ahead
forecast in the functional format, Know i want to forecast accuracy for example
mean absolute percentage error in R, please help how i do this in R
[[alternative HTML version deleted]]
I am working in the functional time series, I obtain the one year ahead
forecast in the functional format, Know i want to forecast accuracy for example
mean absolute percentage error in R, please help how i do this in R
[[alternative HTML version deleted]]
lly, I don't find the
results of make.names that useful, though, and I tend to sanitise
them myself when working with data frames with unwieldy column
names).
Best regards, Jan
On Thu, Jan 21, 2021 at 03:58:44PM -0500, Bernard McGarvey wrote:
> Here is an example piece of code to illustrate
a relatively recent version though.
HTH,
Jan
On 14-12-2020 12:54, Michael Dewey wrote:
Just to add to Petr's comment there are other basic editors with syntax
highlighting like Notepad++ which are also OK if you want a fairly
minimalist approach.
Michael
On 14/12/2020 08:16, PIKAL Petr wrote
Good morning, Please help me to code this code in R.
I working in the multivariate time series data, know my objective is that to
one year forecast of the hourly time series data, using first five as a
training set and the remaining one year as validation. For this I transform
the the data
Good morning dear administrators,
Please help me to code this code in R.
I working in the multivariate time series data, know my objective is that to
one year forecast of the hourly time series data, using first five as a
training set and the remaining one year as validation. For this I
Hello, I am working in the nonparametric functional data analysis, i stack in a
simple problem is that i am going to install a package in the name of nfda
which is not present in the R Cran, know how i am going to install this
package in R studio from archives or some thing else. please
Hello , i am working in the functional time series using themultivariate time
series data(hourly time series data). Sir i am usingFAR model more than one
order for which no statistical package is available inR, so for this i convert
my data into functional form and obtained thefunctional
Hello , i am working in the functional time series using the multivariate time
series data(hourly time series data). Sir i am using FAR model more than one
order for which no statistical package is available in R, so for this i convert
my data into functional form and obtained the functional
systems are deals with the Devil. It's what you put up
with and deal with.
As you can see, I opted to go the Windows route again, for probably the next 10
years.
YMMV.
- Jan
On Sat, Aug 29, 2020, at 06:00, r-help-requ...@r-project.org wrote:
> From: "Philip"
> To: "r
ed '%s'.\n", file))
> ip<- D$ip
> withinBlock<- sapply(X=ip, FUN=function(s) as.integer((strsplit(x=s,
> split=".", fixed=TRUE)[[1]])[4]))
> D$within.block<- withinBlock
> return(D)
> }
>
In short, one pass pulls in all the records into an internal
Hi. How to extract a column from the list.. I will be thanks full..
Sent from Yahoo Mail on Android
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attached base packages:
> [1] stats graphics grDevices utils datasets methods base
>
> loaded via a namespace (and not attached):
> [1] compiler_3.6.2
> >
>
Eventually, I get to the end of P and call it done.
Anyone have a suggestion for an easier workaround?
- Jan Galkowsk
Hi, i am try to generalize the Functional autoregressive model of order one
FAR(1) to FAR(p) through functional principle component by choosing a
particular amount of variation, then using the functional scores of functional
principle component for the prediction of vector autoregressive
Subject: How to read a result saved in Rstudio
HI, i run the simulation result in other computer with high speed computer ,i
save the result in the rda file. know i want to open this file rda file in my
laptop, the file loaded in my laptop , i got the error like this
hi, i have a problem that how i could use Durbin- levinson algorithm for
prediction in case of multiple time series? how i could do this in R...
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Hi, my question is related functional data analysis, what is functional final
prediction error how we can use to transform vector autoregressive model to its
functional form...need help in this regard i will be thanks ful..
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I have confirmed that a complete workaround to these problems is available if,
as Bill Dunlap suggested, "version=2" is used in all *save* incantations.
Thanks Bill!
- Jan
On Thu, Jul 18, 2019, at 10:39, William Dunlap wrote:
> Note that you can reproduce this in R-3.5.1 i
> # Test for saving. Jan Galkowski, 17th July 2019.
> # produceProtectionFault.R
>
> library(apcluster)
> cl1 <- cbind(rnorm(100, 0.2, 0.05), rnorm(100, 0.8, 0.06))
> cl2 <- cbind(rnorm(50, 0.7, 0.08), rnorm(50, 0.3, 0.05))
> x <- rbind(cl1, cl2)
>
> ## comput
ars.
My inclination is to drop back to 3.6.0 if it is just me or if no one knows
about this problem.
Thanks,
- Jan Galkowski.
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ht
HI, hope all of you will be fine. i am working in functional time series
analysis. i fit the functional autoregressive model using FAR package in R,
Know i want to generalize our model. How i can do this in R please help in this
regard. i will be thankful
[[alternative HTML version
HI, i am functional data analysis, using times series data to which i fit the
functional autoregressive model of order one using FAR package in R, know i
want to extend my model to order two as it is observed that the FAR package can
only do for order one., can any body help me that how to
Hi, i trying to extend the functional autoregressive model one FAR(1) to fit
the functional autoregressive model of order two FAR(2). the coding i do for
far(1) is library(fda)library(far)# CREATE DUMMY
VARIABLESfactor2dummy=function(x){ n=length(x) tab=as.factor(names(table(x)))
Goodafternoon,
I amcurrently in the process of calibrating an item bank using a GPCM model.
So, amI right to assume that the bifactor model allows me to work with my
generalfactor by assimilating it to a one-factor model, without taking into
account groupfactors? That is, I can estimate my
Hi R programmers
I am reading multiple .xls and .xlsx files from a directory using readxl from
tidyverse. When reading fails, the code should continue on to the next file.
However, when I call the custom function readExcelSheets (in a loop and with
the tryCatch function) I get an error for
Hi Duncan,
On Wed, Jan 23, 2019 at 10:02:00AM -0500, Duncan Murdoch wrote:
> On 23/01/2019 5:27 a.m., Jan T Kim wrote:
> >Hi Ivan & All,
> >
> >R's scoping system basically goes to all environments along the call
> >stack when trying to resolve an unbound variable,
cide whether and how the code should be rewritten,
I'd say that depends on the underlying intentions / purposes. As it
is, the code could be simplified to just
print("secret");
but that's probably missing the point.
Best regards, Jan
[1] https://cran.r-project.org/doc/manuals/r-relea
Ms Fleming,
This blog post (of mine) may be of interest and hopefully of help:
https://667-per-cm.net/2018/11/20/the-johnson-lindenstrauss-lemma-and-the-paradoxical-power-of-random-linear-operators-part-1/
Cheers!
--
Jan Galkowski (o°)
Westwood, MA
(pronouns: *he, him, his*)
*Keep your energy
nted to.
Also, if the object is generated by a package, you might need to load
the package to get the printing etc. of the object right.
HTH,
Jan
On 07-11-18 09:45, Patrick Connolly wrote:
On Wed, 07-Nov-2018 at 08:27AM +, Robert David Burbidge wrote:
|> Hi Patrick,
|>
|> Fr
ng(cbind(d$lon, d$lat))) %>%
unname() %>% # Without the unname it doesn't work for some reason
st_sfc()
# Plot using leaflet
leaflet() %>%
addTiles() %>%
addPolylines(data = lines)
HTH - Jan
On 01-11-18 11:27, Rui Barradas wrote:
Hello,
The following uses ggplot2.
Fi
are probably various other
solutions too.
--
Jan
On 27-10-18 18:04, Aerenbkts bkts wrote:
Dear Jan
Thanks for your help. Actually it works for the first element. But I
tried to calculate distance values for the first N rows. For example;
gower_dist(iris[1:5,], iris) // gower distance f
Using another implementation of the gower distance:
library(gower)
gower_dist(iris[1,], iris)
HTH,
Jan
On 26-10-18 15:07, Aerenbkts bkts wrote:
I have a data-frame with 30k rows and 10 features. I would like to
calculate distance matrix like below;
gower_dist <- daisy(data-fr
relation coefficient, known at least since
Kendall, M. G. (1954). Note on bias in the estimation of autocorrelation.
Biometrika, 41(3-4), 403-404.
The bias is approximately -1/T, with T sample size, which explains why it seems
to disappear in the larger sample size
Did you take into account that the sample serial correlation coefficient has a
bias of approximately -1/T (with T the sample size)? Its variance is
approximately 1/T.
Jan Annaert
-Original Message-
From: R-help On Behalf Of hmh
Sent: donderdag 4 oktober 2018 12:09
To: R
Subject: [R
Or
testdf <- testdf[FALSE, ]
or
testdf <- testdf[numeric(0), ]
which seems to be slightly faster.
Best,
Jan
Op 27-9-2018 om 10:32 schreef PIKAL Petr:
Hm
I would use
testdf<-data.frame(A=c(1,2),B=c(2,3),C=c(3,4))
str(testdf)
'data.frame': 2 obs. of 3 variables:
$ A: num
hmm... I don't see the quote="" paraneter in your read.csv call
Best regards, Jan
--
Sent from my mobile. Apologies for typos and terseness
On Mon, Sep 24, 2018, 20:40 greg holly wrote:
> Hi Jan;
>
> Thanks so much for this. Yes, I did. Her is my code to read
Yet one more: have you tried adding quote="" to your read.table
parameters? Quote characters have a 50% chance of being balanced,
and they can encompass multiple lines...
On Mon, Sep 24, 2018 at 11:40:47AM -0700, Bert Gunter wrote:
> One more question:
>
> 5. Have you tried shutting down,
nstalled Rstudio for some
MOOC, and ended up putting a symlink in somewhere like /usr/lib* ,
because Rstudio was only available as a binary with the location
of the shared lib hard-baked into it.
Depending on your this may be irrelevant, apologies
in that case.
Best regards, Jan
On Thu, Aug
safe.
Jan
On 09-08-18 09:19, Rainer M Krug wrote:
I can not agree more, Barry. Very nicely put.
Rainer
On 8 Aug 2018, at 18:10, Barry Rowlingson wrote:
On Wed, Aug 8, 2018 at 4:09 PM, Laurence Clark
wrote:
Hello all,
I want to download R and use it for work purposes. I hope to use
ot;(Intercept)=0", "x=1"))
Linear hypothesis test
Hypothesis:
(Intercept) = 0
x = 1
Model 1: restricted model
Model 2: y ~ x
Res.Df RSS Df Sum of Sq F Pr(>F)
1 10 10.6218
2 8 9.0001 21.6217 0.7207 0.5155
Jan
From: R-help on
Hi,
thanks a lot! Now it works.
Yours
Jan
Am 10.07.2018 um 09:00 schrieb PIKAL Petr
mailto:petr.pi...@precheza.cz>>:
Hi
see in line
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Werning, Jan-
Philipp
Sent: Monday, July 9, 2018 9:42 PM
ection in R studio, now both are the same,
in the value section as "Numed num"
Yet, the model will not run using these values ultimately coming from the csv.
What am I doing wrong here?
It would be great if you could help.
Thanks a lot in advance
Yours
://universaldependencies.org
all the best,
Jan
Jan Wijffels
Statistician
www.bnosac.be | +32 486 611708
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r-packa...@r-project.org
https://stat.ethz.ch/mailman/listinfo/r-packages
er rather than in the decreasing
order?
Best regards,
Jan Motl
PS: This post is based on discussion on
https://stackoverflow.com/questions/47847295/why-does-chisq-test-sort-data-in-descending-order-before-summation
<https://stackoverflow.com/questions/47847295/why-does-chisq-test-sort-data-i
/vignettes/textrank.html
and it also plays nicely with the udpipe package
https://CRAN.R-project.org/package=udpipe which is good for parts-of-speech
tagging, lemmatisation, dependency parsing and general NLP processing.
all the best,
Jan
Jan Wijffels
Statistician
www.bnosac.be
[[alternative
estep
exists, this is logical. Yet I would expect the movavg function to produce a
new value in each of the 120 timesteps, as it is the case with all other flow,
stock and aux calculations as well.
It would be great if you could help me with fixing this problem.
Many thanks in advance
, assume zero discount
rate.)
Med Vennelig Hilsen
Jan Olsen R�yland
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PLEASE do read the posting
Dear all, I am trying to fit a multiple linear regression model with a
transformed dependant variable (the normality assumption was not verified...).
I have realised a sqrt(variable) transformation... The results are great, but I
don't know how to interprete the beta coefficients... Is it
the maximum
number of iterations. One possible solution is to try to increase the
maximum number of iterations, e.g.:
fit1 <- lrm(DAY30~AGE+HYP+KILLIP+HRT+ANT, data = gusto2, maxit = 100)
HTH,
Jan
On 14-09-17 09:30, Bonnett, Laura wrote:
Dear all,
I am using the publically available Gus
Hello,
I’m trying to do a meta-analysis with R. I tried to use the function
metabin from the package meta :
data <- data.frame(matrix(rnorm(40,25), nrow=17, ncol=8))
5 sums checked
package ‘SparseM’ successfully unpacked and MD5 sums checked
package ‘survival’ successfully unpacked and MD5 sums checked
package ‘VineCopula’ successfully unpacked and MD5 sums checked
The downloaded binary packages are in
C:\Users\Jan\AppData\Local\Temp\Rtmpyekpgu\download
Hi Martin and All,
thanks for your reply, please see my comments inline below:
On Thu, Dec 08, 2016 at 09:09:10AM +0100, Martin Maechler wrote:
> >>>>> Jan T Kim via ESS-help <ess-help@r-project.org>
> >>>>> on Tue, 6 Dec 2016 01:11:20 + writes
es occurs only
after some delay caused by briefly flashing the cursor at the corresponding
opening brace.
Quite possibly I'm using a clumsy approach to try to get indentation during
typing consistent with that produced by indent-region, so suggestions where
I may have messed up are welcome.
Best
many more very useful functions with not too much more typing.
>
> On Thu, Oct 20, 2016 at 5:47 PM, Jan Kacaba <jan.kac...@gmail.com> wrote:
> > Hello dear R-help
> >
> > I tried to find function which returns number of occurrences of a pattern
> > in string.
Hello dear R-help
I tried to find function which returns number of occurrences of a pattern
in string. The closest match I've found is str_locate_all in stringr
package. I can use str_locate_all but write my function but I don't want
reinvent wheel.
JK
[[alternative HTML version
2016-10-01 18:02 GMT+02:00 David Winsemius <dwinsem...@comcast.net>:
>
>> On Oct 1, 2016, at 8:44 AM, Jan Kacaba <jan.kac...@gmail.com> wrote:
>>
>> Hello Dear R-help
>>
>> I tried to understand how recursive programming works in R. Bellow i
Hello Dear R-help
I tried to understand how recursive programming works in R. Bellow is
simple recursive function.
binary1 <- function(n) {
if(n > 1) {
binary(as.integer(n/2))
}
cat(n %% 2)
}
When I call binary1(10) I get 1010. I believe that cat function stores
value to a buffer
Dear R help,
I would like to run script upon saving project files or exiting the R Studio.
For example I would like to backup whole project in another directory.
The backup directory should be named such that incremental version
number will added to project name.
Is it somehow possible? Even
Hello dear R-help
I would like to use some short and simple names multiple times inside
one script without collisions. I need to wrap the variables inside
some object. I know I can use class function or environment. For
example as follows:
exmp1<-function(){
# knowns
pa=0.35
pb=0.35
t(x, at=PartitioningByEnd(ends))
> }
>
> Will be much faster than substring (e.g. 100x or 1000x) when
> chopping a string like a Human chromosome into hundreds or
> thousands of fragments.
>
> Biostrings is a Bioconductor package:
>
> https://bioconductor.org/packag
t;
> On Thu, May 12, 2016 at 10:05 AM, Jim Lemon <drjimle...@gmail.com> wrote:
>> Hi Jan,
>> This might be helpful:
>>
>> chop_string<-function(x,ends) {
>> starts<-c(1,ends[-length(ends)]-1)
>> return(substring(x,starts,ends))
>> }
>>
am's 'stringr' package:
> https://cran.r-project.org/web/packages/stringr/stringr.pdf
>
> Cheers,
>
> Bert
>
>
> Bert Gunter
>
> "The trouble with having an open mind is that people keep coming along
> and sticking things into it."
> -- Opus (aka Berkel
Dear R-help
I would like to split long string at specified precomputed positions.
'substring' needs beginings and ends. Is there a native function which
accepts positions so I don't have to count second argument?
For example I have vector of possitions pos<-c(5,10,19). Substring
needs input
Hi, I'd like to access to the different elements in a svyciprop object (to the
confidence intervals in particular...). But none of the functions I know
works.Thank you for your help !
> grr <- svyciprop(~temp==bzz, dclus1)> grr 2.5%
> 97.5%temp == bzz 0.040719697
Hello dear R helpers,
Is it possible to have more than 1 row for column names in data.frame,
array, tbl_df? I would like to have column numbers in the first row, string
names in the second row, physical unit in third row.
How would I do it?
Derek
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Hello dear R users,
Is there a function or package which can insert row, column or array in
another array at specified place (row or column)?
I have made several attempts at this function optimizing both speed, code
readability and ease of use. The functions are of following format:
Hello dear R, I dont have specific task on mind just learning R.
1) Is it possible to open a document for example path1\myfile.pdf with
program path2\pdfviewer.exe ?
How would I do it in win? Does it differ in linux?
2) Is it possible to run a program and supply to it some streams? The
streams
ring to a
file.
I hope there is no problem processing strings with other functions like
paste, strsplit, grep though.
Derek
2016-03-30 0:56 GMT+02:00 Duncan Murdoch <murdoch.dun...@gmail.com>:
> On 29/03/2016 5:39 PM, Jan Kacaba wrote:
>
>> I have problem with accente
I have problem with accented characters. My OS is Win 8.1 and I'm using
RStudio.
I make string :
av="ěščřž"
When I call "av" I get result bellow.
> av
[1] "ìšèøž"
The resulting characters are different. I have similar problem when I write
string to a file. In RGUI if I call "av" it prints
Hello, is it possible to run kiniter by script instead by clicking on
button compile PDF?
Say I have "texfile.rnw" and "myscript.R". I would like to knit texfile.rnw
by runnig script "myscript.R".
In "myscript.R" I would write something like this:
knit("texfile.rnw")
[[alternative HTML
On Wed, Mar 16, 2016 at 03:18:27PM -0400, Duncan Murdoch wrote:
> On 16/03/2016 1:40 PM, Jan Kim wrote:
> >Barry: that's an interesting hack.
> >
> >I do feel compelled to make two comments, though, regarding the
> >general issue rather than the scraping idea:
&
is normally adequate or at least good
enough, but .RData images are never a good idea.
Best regards, Jan
P.S.: I've seen .RData images containing many months worth of interactive
work, and multiple variants of data frames in variables with more or less
similar names, so the set of strings scraped off these
Hello, I have following problem in loops. It occurred to me multiple times
bellow is an example. Inside if() I have sometimes function f(x) which may
return integer(0). If I test f(x)>1 and f(x)=integer(0) I get error. Maybe
it can be solved more eloquently without loop or swithces. I don't
Hello I would like to assign a vector to list sequence. I'm trying my code
bellow, but the output is not what inteded.
# my code
mls=vector(mode="list") # my list
cseq=c(1:3) # my vector
mls[cseq]=cseq
I get following:
[[1]]
[1] 1
[[1]]
[2] 2
[[1]]
[2] 3
What I need is this:
[[1]]
[1] 1 2 3
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