Tim
Works in Word 2002 on Windows XP with PDF-xchange 3.0 to convert to pdf.
Saw reponse from Duncan - agree might be problem with Word 2007 PDF
converter.
HTH
Schalk
On Sun, Dec 12, 2010 at 3:59 PM, Tim Clark wrote:
> I need help with using graphics in Word 2007 that will later be converted
On Sun, Dec 12, 2010 at 3:59 PM, Tim Clark wrote:
> I need help with using graphics in Word 2007 that will later be converted
> into a
> pdf document. I have tried several formats and found that I get the best
> quality of graphics using .wmf, .eps format, but when I convert it to .pdf
> I get
>
lapply will do the trick, try something like
lapply(1:length(dat1), function(x,dat1,dat2) cbind(dat1[[x]][,1:2],
dat2[[x]]),dat1,dat2)
HTH
Schalk
On Mon, Mar 22, 2010 at 10:18 AM, Ron_M wrote:
>
> Dear all,
>
> I have following two list object, both are basically collection of matrices
> :
>
>
Hi
You can use the reshape package to achieve this. If you don't have it
installed, install.packages('reshape'). Then look at ?cast and (possibly)
?melt
HTH!
Schalk
On Tue, Jan 5, 2010 at 7:59 AM, Noli Sicad wrote:
> Hi,
>
> I need to transpose and aggregate the 4th and 5th column of this d
For normality check out: ?shapiro.test
HTH!
Schalk
On Tue, Jan 5, 2010 at 5:32 AM, Haiyang AI wrote:
> Dear all,
>
> I'm a beginner of R and I need to carry out some three-way mixed ANOVAs.
> Following examples at http://personality-project.org/r/r.anova.html, I
> managed to get the ANOVA part,
Tobias
The grangertest function in the lmtest package might be simpler for your
application.
Regards
Schalk Heunis
On Mon, Nov 16, 2009 at 5:31 PM, tobiasfa wrote:
>
> Hi useRs..
>
> I cant figure out how to test for causality using causality() in vars
> package
>
> I ha
This may be of some help:?try
On Mon, Oct 12, 2009 at 9:42 AM, Arif Chandra wrote:
>
> Hi R-users,
>
> I would like to ask question related to error output.
> If an error comments come out, then the program will automatically stop.
> I want to ask , how I can still continue the program even thoug
Hi Phil
Try the following
> which(names(iris)=='Species')
[1] 5
HTH
Schalk Heunis
On Mon, Oct 12, 2009 at 8:53 AM, tdm wrote:
>
> Hi,
>
> How do I access the index number of a field given I only know the field
> name?
>
> eg - I want to set the probability
Hi
I think the following will help:
#Load some packages
library(lattice)
library(reshape)
#Sample data
dataset.frame
<-
data.frame(id=c("a","b","c","a","c","b","a"),colour=c("blue","green","red","red","red","green","green"))
# calculate the counts
dataset.table <- table(dataset.frame)
#and res
Walt
I get the same message using R2.9.2 on Vista. Using
sqlFetch(con,'Sheet1') seems to however.
HTH
Schalk Heunis
On Thu, Sep 24, 2009 at 6:23 PM, Data Analytics Corp.
wrote:
> Hi,
>
> I'm attempting to use the RODBC package on Windows Vista to import an e
See http://finzi.psych.upenn.edu/Rhelp08/2009-March/192978.html
You can do something like:
default.search = paste(getwd(),"/*.txt",sep="")
infile2 = choose.files(default.search,filters =
Filters[c("txt","All"),], caption = "Choose ECD datafile"
Don't know SAS, but you can use y<<-10 to make the answer available in
the global environement. See ?'<<-'
To define the output see ?return
Schalk Heunis
On Mon, Sep 21, 2009 at 5:29 PM, David Young wrote:
> Hello Group,
>
> I'm trying to learn R and
Ana
Not sure if I understood your problem, but on my side, the lines and
points are both on the same 3-d picture. However, the lines are just
very small: by setting data = data/100, the lines and points are both
visible.
HTH
Schalk Heunis
On Mon, Sep 21, 2009 at 4:38 PM, Ana Kolar wrote
you can set the
breaks property.
> breaks <- c(seq(0, 1-1e-10, length=16) ,1)
> heatmap.2(volcano / max(volcano), col=c(heat.colors(16)[1:15],"black"),
> breaks = breaks)
HTH
Schalk Heunis
On Mon, Sep 21, 2009 at 1:43 PM, bioinformatics_guy
wrote:
>
> I'm tryi
Georg
for example:
>data(swiss)
>data=swiss
>lapply(2:length(data),function(x) lm(data[,1]~data[,x]))
HTH
Schalk Heunis
On Sun, Sep 20, 2009 at 2:05 PM, Georg Ehret wrote:
> Dear R community,
> I have a dataframe with say 100 different variables. I wish to regress
> var
be able to handle a vector of
inputs. Look at sapply if this is an issue.
HTH
Schalk Heunis
On Sun, Sep 20, 2009 at 4:21 AM, Manuj Sharma wrote:
>
> I have fitted Hyperexponential distribution (HED) and Hypoexponential
> distribution (HoED) to two different data sets (of size 1000 numer
Jason
Try this
> Residuals = residuals(lm(y~x))
> plot(x,Residuals)
Schalk Heunis
On Sun, Sep 20, 2009 at 1:36 AM, Jason Priem wrote:
> Hi,
> I want to plot the residuals of a least-squares regression.
>
> plot(lm(y~x), which=1)
>
> does this, but it plots the y-axis
199.9544 202.2562 197.8169 199.3558
C. Draw the histogram
Drawing a histogram of means500 is achieved using the hist function
> hist(means500)
HTH
Schalk Heunis
On Sat, Sep 19, 2009 at 11:24 PM, MikeH78 wrote:
>
> I was wondering if anyone could help me with a problem. I need to
You could plot both histograms into the same file using this:
library(lattice)
jpeg(filename="combined.jpeg")
histogram(~d|f, data = df)
dev.off()
Schalk Heunis
On Sat, Sep 19, 2009 at 11:37 AM, Sam Player wrote:
> # I have a dataframe with data and factors similar to the fol
I think this is what you want
NAD$Sample.Id <- t(Prot.amount[NAD$Sample.Id])
HTH
Schalk Heunis
On Sat, Sep 19, 2009 at 12:18 PM, Monna Nygård wrote:
>
> Hi,
>
>
>
> This is a question of a newbie getting into the exciting world of R.
>
>
>
> I have several
On Fri, Sep 18, 2009 at 8:12 AM, Schalk Heunis
wrote:
> Marcio
> Looking at the script (not much explanation re your intention), I think
> there is a couple of problems:
> 1. Not sure if the attached was supposed to be working code, but the
> assignment operator is <- not <
if(1) >= (1 - r2)) g1 else g2
g[j, i] <- xx(gen, j, i)
}
}
######
HTH
Schalk Heunis
On Fri, Sep 18, 2009 at 4:50 AM, Marcio Resende wrote:
>
> I am new in R and i am having trouble here. I´ve alread
Try this
x[(row(x[1]) %in% 2:5) & x$a==1,4:5] <- c(8,9)
x[(row(x[1]) %in% 2:5) & x$a!=1,4:5] <- c(101,102)
HTH
Schalk Heunis
On Thu, Sep 17, 2009 at 11:17 PM, Dimitri Liakhovitski wrote:
> Hello, dear R-ers!
>
> I have a data frame:
>
> x<-data.frame(a=c(4,2,
Subodh
Assuming the data is ordered by date then you can define
fin.years = (0:(10*12-1)) %/% 12
then use aggregate:
aggregate(x, list(fin.years),sum)
HTH
Schalk Heunis
On Thu, Sep 17, 2009 at 6:11 PM, Subodh Acharya wrote:
> Hi everyone,I have a data daily data (x) for 10 years start
Marcio
Define two functions, e.g.
f1<-function(i,j) i+j
f2<-function(i,j) i-j
then call them based on the probability e.g. 0.7
f <- if(runif(1)>0.7) f1 else f2
f(1,1)
or more compact
(if(runif(1)>0.7) f1 else f2)(1,1)
HTH
Schalk Heunis
On Thu, Sep 17, 2009 at 5:10 PM, Marci
Try placing the column names into labCol and the rownames into labRow
e.g.heatmap.2(mat,dendrogram=c("none"),
Rowv=F, Colv=F, labRow = seq(-7.5,7.5,by=5), labCol=seq(-3,3,by=2))
Schalk Heunis
On Thu, Sep 17, 2009 at 3:53 PM, bioinformatics_guy wrote:
>
> Schalk,
>
> Thats
Hi bioinformatics_guy
I think you are looking for the "image" function:
image(mat)
The heatmap.2 function does hierarchical clustering on rows and columns and
then orders the rows and columns according to the results of the clustering.
Image simply plots the matrix.
HTH
Schalk Heuni
t;
or
>df[,grep('^x',names(df))]
x1 x2 x3
1 1 2 3
2 2 3 4
3 3 4 5
4 4 5 6
5 5 6 7
6 6 7 8
7 7 8 9
8 8 9 10
9 9 10 11
10 10 11 12
11 11 12 13
HTH
Schalk Heunis
On Thu, Sep 17, 2009 at 5:03 AM, Peng Yu wrote:
> Hi,
>
> data.frame(x1=1:11
Instead of eval(expr), use lapply(expr,eval)
HTH
Schalk Heunis
On Wed, Sep 16, 2009 at 5:50 AM, Michael Spiegel <
michael.m.spie...@gmail.com> wrote:
> Hi,
>
> I'm trying to use a list of symbols as one of the values to be
> substituted in a substitute expression, but I
This might be of help, first applies the formatting:print(xtable(prettyNum(d,
decimal.mark=",")))
Schalk Heunis
On Tue, Sep 15, 2009 at 5:06 PM, Jakson A. Aquino wrote:
> Hello,
>
> How can I make xtable print a comma as decimal separator? Setting
> the option OutDec i
3 56849XX QPWOER52E2XX 2000-07-07
4 54982XX FJKLSD67P4XX 2000-12-12
5 56849XX QWERTG50T0XX 2000-03-30
6 12345XX POIQWE74H0XX1999-12-31
HTH
Schalk Heunis
On Mon, Sep 14, 2009 at 4:41 PM, Luca Braglia wrote:
> H
Karen
You can copy and paste data directly into R from Excel:
1. Mark the data including the headings in Excel
2. Ctrl-C
3. In R:
myDF <- read.delim("clipboard")
Following from Milton:
hist(myDF$VARNAME)
or
hist(myD[,1]) #to plot 1st collumn
hist(myD[,2]) #to plot 2nd collumn
Schal
On Mon, Sep 14, 2009 at 5:19 AM, Schalk Heunis
wrote:
> Chris
> try this (assume your dataset is in a dataframe called ms):
> library(lattice)
> xyplot(Value~Time|Name,data = ms)
>
> HTH
> Schalk
>
>
>
> On Mon, Sep 14, 2009 at 2:19 AM, Chris Li wrote:
>
>
Steven
I think list() can help you
##
indlist = list()
for (i in 1:(dim(x)[2])) {
indlist[[paste("ind", i, sep = "")]] <- which(x[ , i] == "y")
}
accum = unlist(indlist)
print(indlist$ind1)
##
e("Spazashop",1:35)))
Hope this helps.
Schalk Heunis
On Wed, Sep 9, 2009 at 2:26 AM, KABELI MEFANE wrote:
> R helpers
>
> Please help me combine the simulated data to a form of table where:
> Hypermarket have 10 rows, supermarket have 15 rows,..., spazashops with
> 35 ro
You want to use list:
a = list()
a[[1]] = c(1,2,3)
a[[2]] = c(1,2,3)
Note the [[..]] operator - check the "An Introduction to R" manual for
more details
Schalk Heunis
On Wed, Sep 9, 2009 at 6:00 AM, wrote:
> I just learned that vectors can't contain vectors, which frankly
have you tried rbind?
On Tue, Sep 8, 2009 at 11:16 AM, FMH wrote:
> Dear All,
>
> I have some data which were stored in few matrices with different orders.
> Let have three different matrices a, b and c, which have the same number of
> column but different number of row.
>
>
> a <- matrix(1, n
bout which colors match which range, consider
specifying the ranges in "breaks".
Schalk Heunis
On Sun, Sep 6, 2009 at 4:50 PM, FMH wrote:
> Hi,
>
> Thank you for your response. I'm looking for the names of the colors denoted
> by these codes and what do these colors
rce(myModels[[",x,"]])",sep = "")})
myParStr = toString(paste( myParameters ))
eval(parse(text = paste("anova(",myParStr,")")))
I would have expected do.call(anova, myModels) to work
Hope this helps
Schalk Heunis
On Sat, Sep 5, 2009 at 10:43 PM, Je
Levi
Thanks for the reply, do you know of any function or package that does
contain an implementation of two-way joining? I looked at the biclust
package which implements several other (more modern?) bi-clustering
techniques, but could not find two-way joining.
Schalk Heunis
On Mon, Aug 31
hat is the relationship (if any) between the "heatmap" function in R
and this technique? Is there an alternative function to use?
Thanks for the help!
Schalk Heunis
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