Re: [R] if statement and for loop question

Dear Kai When you ask again it is best to tell us what your input is and what output you were hoping for and what you actually got. If you can make a small data-set which shows all that then your post will be much more likely to get a helpful response. If you want to transfer the data-set to

Re: [R] if statement and for loop question

Hi Jim, Sorry to post "same" question, because  1. I was asking to use plain text format. I have to post my question again. But I don't know if it is working. 2. I'm a beginner for R (< 2 month). It may not easy for me to ask a "clear" R question. My current work is to transfer my SAS code

Re: [R] if statement and for loop question

Hi Kai, You seem to be asking the same question again and again. This does not give us the warm feeling that you know what you want. testdf<-data.frame(a=c("Negative","Positive","Neutral","Random","VUS"), b=c("No","Yes","No","Maybe","Yes"), c=c("Off","On","Off","Off","On"),

Re: [R] if statement and for loop question

Hello, You don't need a loop, the R way is a vectorized solution and it's also clearer. Create a logical index (note only one &) and assign b, c, d where it's TRUE. i <- try$a != "Positive" & try$a != "VUS" try <- within(try, { b[i] <- '' c[i] <- '' d[i] <- '' }) Hope this helps,

Re: [R] if statement and for loop question

Kai, You have made a simple mistake. And now you cannot see it. I believe this is not uncommon among programmers. It has happened to me more times than I want to recall. > On May 30, 2021, at 9:28 AM, Kai Yang via R-help wrote: > > Hello List,I have a data frame which having the character

Re: [R] if statement and for loop question

Can you make R code that creates an actual sample data frame that looks like you want the answer to look? say, just using the data.frame function and literal strings. Oh, and read the Posting Guide... you need to send your email using plain text format or it may get garbled when the list strips

[R] if statement and for loop question

Hello List,I have a data frame which having the character columns: | a1 | b1 | c1 | d1 | | a2 | b2 | c2 | d2 | | a3 | b3 | c3 | d3 | | a4 | b4 | c4 | d4 | | a5 | b5 | c5 | d5 | I need to do: if a1 not = "Positive" and not = "VUS" then values of  b1, c1 and d1 will be zero out. And do the same

Re: [R] If statement

Use ifelse function, not if. If is only good for one logical value at a time, but you are working with long vectors of values simultaneously. I have no interest in doing all of your workfor you, but the concept is cpl_or_sngl <- dat1$b %in% c( "couple", "single" ) a_pvt <- "private" == dat1$a

Re: [R] If statement

You appear to be confusing && with & and || with | ; (the first of each pair take a logical expression, the second of each a logical vector) ... as well as if ... else with ifelse (the first is a flow control statement taking a logical expression; the second is a function taking a logical vector

[R] If statement

Hi all, I am trying to use the if else statement and create two new columns based on the existing two columns. Below please find my sample data, dat1 <-read.table(text="ID a b c d A private couple 25 35 B private single 24 38 C none single28 32 E none none 20 36

Re: [R] Case statement in sqldf

Thank you very much, I will work on it -Original Message- From: Gabor Grothendieck [mailto:ggrothendi...@gmail.com] Sent: 11 September 2017 06:50 PM To: Mangalani Peter Makananisa Cc: r-help@r-project.org Subject: Re: Case statement in sqldf 2018-03-3 in your code should be 2018-03-31.

Re: [R] Case statement in sqldf

Thanks D, I will work on the solution you gave and give feedback. -Original Message- From: David Winsemius [mailto:dwinsem...@comcast.net] Sent: 11 September 2017 05:19 PM To: Mangalani Peter Makananisa Cc: r-help@r-project.org Subject: Re: [R] Case statement in sqldf > On Sep

Re: [R] Case statement in sqldf

2018-03-3 in your code should be 2018-03-31. The line then'201415' needs to be fixed. When posting please provide minimal self-contained examples. There was no input provided and library statements not relevant to the posted code were included. Fixing the invalid date and bad line, getting

Re: [R] Case statement in sqldf

> On Sep 11, 2017, at 1:05 AM, Mangalani Peter Makananisa > wrote: > > Hi all, > > I am trying to create a new variable called Fiscal Year (FY) using case > expression in sqldf and I am getting a null FY , see the code below . > > Please advise me as to how I can

[R] Case statement in sqldf

Hi all, I am trying to create a new variable called Fiscal Year (FY) using case expression in sqldf and I am getting a null FY , see the code below . Please advise me as to how I can do this mutation. library(zoo) library(lubridate) library(stringr) library(RH2) library(sqldf)

Re: [R] R [loop statement ]

Hi tan sj, It is by no means easy to figure out what you want without the code, but If I read your message correctly, you can run the loops either way. When you have nested loops producing output, it is often a good idea to include the parameters for each run in the output as well as the result so

[R] R [loop statement ]

hi, i am new in this field. I am now writing a code in robustness simulation study. I have written a brief code "for loop" for the factor (samples sizes d,std deviation ) , i wish to test them in gamma distribution with equal and unequal skewness, with the above for loop in a single code if

[R] 'which' statement for recode?

Hi, Is there a way to easily convert the list of course terms into sequential integers in the dataframe (see code below)? eg. 199801 = 1; 199808=2 I know I can use recode but shouldn't which work? Thanks in advance! sc = data.frame(c(200208, 200701, 201201)) names(sc) = c(TERM) TermList =

Re: [R] 'which' statement for recode?

I'm not quite sure, but I think you might want: which(TermList %in% sc$TERM) [1] 11 20 30 instead. Using == ends up with automatic recycling and other things you probably weren't expecting. Sarah On Thu, Jan 22, 2015 at 11:01 AM, Charles Stangor cstan...@gmail.com wrote: Hi, Is there a way

Re: [R] 'which' statement for recode?

You did not show what answer you expected, but does the following do what you want? match(sc$TERM, TermList) [1] 11 20 30 Making a factor whose levels are TermList may also be useful. (The exclude=NULL is to factor doesn't drop NA from the levels). sc$fTERM - factor(sc$fTERM,

Re: [R] 'which' statement for recode?

Message- From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Charles Stangor Sent: January-22-15 11:01 AM To: r-help@r-project.org Subject: [R] 'which' statement for recode? Hi, Is there a way to easily convert the list of course terms into sequential integers

Re: [R] 'which' statement for recode?

?factor You might find the description in the Introduction to R that comes with the R software helpful if the help page seems terse. Please read the Posting Guide and particular post using plain text format, a strong in your email program.

[R] If statement not working in a for loop when making it independent

Dear all, I have a data.frame xy that contains numeric data and data_qual which contains qualitative data which I want to include in a for loop with an if statement (commented out in the code below). The if statement should be applied if the ID in data_qual$ID is the same than in xy$ID. I am

Re: [R] If statement not working in a for loop when making it independent

You have really tied yourself up in a knot here. Last I checked, when A==B, then B==A. You also need to study the difference between ?if and ?ifelse, since you are not giving the if function the scalar it expects. For example, i$ID is a vector of three (identical, due to your use of split)

Re: [R] Ifelse statement on a factor level data frame

I believe you are in Circle 8.2.7 of The R Inferno. http://www.burns-stat.com/documents/books/the-r-inferno/ Pat On 28/09/2014 05:49, Kate Ignatius wrote: Quick question: I am running the following code on some variables that are factors: dbpmn$IID1new - ifelse(as.character(dbpmn[,2]) ==

Re: [R] Ifelse statement on a factor level data frame

Strange that, I did put everything with as.character but all I got was the same... class of dbpmn[,2]) = factor class of dbpmn[,21] = factor class of dbpmn[,20] = data.frame This has to be a problem ??? I can put reproducible output here but not sure if this going to of help here. I think

Re: [R] Ifelse statement on a factor level data frame

Inline. Bert Gunter Genentech Nonclinical Biostatistics (650) 467-7374 Data is not information. Information is not knowledge. And knowledge is certainly not wisdom. Clifford Stoll On Sun, Sep 28, 2014 at 6:38 AM, Kate Ignatius kate.ignat...@gmail.com wrote: Strange that, I did put

Re: [R] Ifelse statement on a factor level data frame

Apologies - you're right. Missed it in the pdf. K. On Sun, Sep 28, 2014 at 10:22 AM, Bert Gunter gunter.ber...@gene.com wrote: Inline. Bert Gunter Genentech Nonclinical Biostatistics (650) 467-7374 Data is not information. Information is not knowledge. And knowledge is certainly not

Re: [R] Ifelse statement on a factor level data frame

ifelse() often has problems constructing the right type of return value. if you want to keep the data as a factor (with its existing levels) use x[condition] - value instead of ifelse(condition, value, x). E.g., x - factor(c(Large,Small,Small,XLarge), levels=c(Small,Med,Large,XLarge)) x

[R] Ifelse statement on a factor level data frame

Quick question: I am running the following code on some variables that are factors: dbpmn$IID1new - ifelse(as.character(dbpmn[,2]) == as.character(dbpmn[,(21)]), dbpmn[,20], '') Instead of returning some value it gives me this: c(1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1)) Playing around

Re: [R] Ifelse statement on a factor level data frame

Not reproducible, ball in your court. However, in the meantime, my suggestion is to not do that. Convert to character before you alter the factor, then convert back when you are done. --- Jeff Newmiller

Re: [R] Ifelse statement on a factor level data frame

On Sun, 28 Sep 2014 12:49:41 AM Kate Ignatius wrote: Quick question: I am running the following code on some variables that are factors: dbpmn$IID1new - ifelse(as.character(dbpmn[,2]) == as.character(dbpmn[,(21)]), dbpmn[,20], '') Instead of returning some value it gives me this:

Re: [R] ifelse statement with two vectors of different length

Hi, Please show a reproducible example. countrydiff - c(Albania, Algeria, Belarus, Canada, Germany) long_df - data.frame(country_name = c(Algeria, Guyana, Hungary, Algeria, Canada, Iran, Iran, Norway,Uruguay, Zimbabwe) )  ifelse(long_df$country_name %in% countrydiff,1,0) # [1] 1 0 0 1 1 0 0 0 0

[R] ifelse statement with two vectors of different length

Dear list-members, I have the following problem: I have a vector (countrydiff) with length 72 and another vector (long_df$country_name) which is about 12000 long. Basically what I want to do is to if the factor level (or string name) in long_df$country_name appears on the countrydiff, then

Re: [R] ifelse statement with two vectors of different length

Dear Arun Thanks for your reply, it made me realize that the problem was not in the code but in the levels() of the factors. Some countries had some extra spacing which made the ifelse() function not work. So if I modify your code (added space to countrydiff), it will then look something like

Re: [R] ifelse statement with two vectors of different length

Hi Adel, If the problem is the spacing, then library(stringr) 1*(long_df$country_name %in% str_trim(countrydiff)) # [1] 1 0 0 1 1 0 0 0 0 0 A.K. Dear Arun Thanks for your reply, it made me realize that the problem was not in the code but in the levels() of the factors. Some countries had

Re: [R] If-statement in for-loop

Hello, gncl dzgn, your problem has a flavor of homework which is usually not delt with on this list. However, a few comments: 0. The description of your problem is rather vague, in particular, the meaning of input in the description of your conditions is unclear! (By the way, your main

[R] If-statement in for-loop

Hi everyone, you might find my question elementary but I am a beginner and unfortunately I can't fix the problem. So, I simulate this following algorithm and some values of c are NA. Therefore, I should add these following two if-statements but I don't know how I should do it in a for-loop.

[R] Two statement logical dealing with NAs

Hello. I have a two statement logical that if NA is returned for the second statement I want to rely on result of the first statement. I still would like to use both when I can though. x - c(1:5) y - c(1,2,NA,4,5) x 5 x-y == 0 How can I trick R to refer back to (x 5) where it is NA on the

Re: [R] Two statement logical dealing with NAs

On 12-12-10 7:55 PM, Hans Thompson wrote: Hello. I have a two statement logical that if NA is returned for the second statement I want to rely on result of the first statement. I still would like to use both when I can though. x - c(1:5) y - c(1,2,NA,4,5) x 5 x-y == 0 How can I trick R to

Re: [R] Two statement logical dealing with NAs

On Dec 10, 2012, at 4:55 PM, Hans Thompson wrote: Hello. I have a two statement logical that if NA is returned for the second statement I want to rely on result of the first statement. I still would like to use both when I can though. x - c(1:5) y - c(1,2,NA,4,5) x 5 x-y == 0 How can

Re: [R] If statement - copying a factor variable to a new variable

On Jun 28, 2012, at 09:42 , Rui Barradas wrote: Hello, Another way is to use index vectors: v1.factor - c(S,S,D,D,D,NA) v2.factor - c(D,D,S,S,S,S) td2 - test.data - data.frame(v1.factor,v2.factor) for (i in 1:nrow(test.data) ) { [... etc ...] } #End FOR # Create index

Re: [R] If statement - copying a factor variable to a new variable

Hi James, On Thu, Jun 28, 2012 at 12:33 AM, James Holland holland.ag...@gmail.com wrote: I need to look through a dataset with two factor variables, and depending on certain criteria, create a new variable containing the data from one of those other variables. The problem is, R keeps making

Re: [R] If statement - copying a factor variable to a new variable

Hello, Another way is to use index vectors: v1.factor - c(S,S,D,D,D,NA) v2.factor - c(D,D,S,S,S,S) td2 - test.data - data.frame(v1.factor,v2.factor) for (i in 1:nrow(test.data) ) { [... etc ...] } #End FOR # Create index vectors na1 - is.na(v1.factor) na2 - is.na(v2.factor) # Create

Re: [R] If statement - copying a factor variable to a new variable

Yeah, the reason I didn't use ifelse is because I've got multiple variables to manipulate based on the if statement, some factors and some numeric. I have to look at the factor variables, and based on that, either use one series of variables or another. With the multiple if statements I need to

Re: [R] If statement - copying a factor variable to a new variable

On Thu, Jun 28, 2012 at 8:47 PM, James Holland holland.ag...@gmail.com wrote: With the multiple if statements I need to check for, I though for statements with the if/else if conditional statement was better than nested ifelse functions. for () gives you a lot of flexibility at the expense of

[R] If statement - copying a factor variable to a new variable

I need to look through a dataset with two factor variables, and depending on certain criteria, create a new variable containing the data from one of those other variables. The problem is, R keeps making my new variable an integer and saving the data as a 1 or 2 (I believe the levels of the

Re: [R] conditional statement to replace values in dataframe with NA

On Jun 7, 2012, at 07:28 , Bert Gunter wrote: Actually, recycling makes the rep(NA,2) business unnecessary. Simply: dat1[dat1$x==1 dat1$y==1,1:2] - rep(NA,2) ##or with(dat1,{dat1[x==1 y==1,1:2] - NA;dat1}) will do it. Or, use the assignment form of is.na: cond - with(dat1,

Re: [R] conditional statement to replace values in dataframe with NA

. - Original Message - From: Daisy Englert Duursma daisy.duur...@gmail.com To: r-help@R-project.org r-help@r-project.org Cc: Sent: Wednesday, June 6, 2012 11:58 PM Subject: [R] conditional statement to replace values in dataframe with NA Hello and thanks for helping. #some data L3

[R] conditional statement to replace values in dataframe with NA

Hello and thanks for helping. #some data L3 - LETTERS[1:3] dat1 - data.frame(cbind(x=1, y=rep(1:3,2), fac=sample(L3, 6, replace=TRUE))) #When x==1 and y==1 I want to replace the 1 values with NA #I can select the rows I want: dat2-subset(dat1,x==1 y==1) #replace the 1 with NA

Re: [R] conditional statement to replace values in dataframe with NA

Have you read An Intro to R? If not,please do so before posting further. The way you are going about things makes me think you haven't, but ... This **is** a slightly tricky application of indexing, if I understand you correctly. Here are two essentially identical ways to do it, but the second is

Re: [R] conditional statement to replace values in dataframe with NA

Actually, recycling makes the rep(NA,2) business unnecessary. Simply: dat1[dat1$x==1 dat1$y==1,1:2] - rep(NA,2) ##or with(dat1,{dat1[x==1 y==1,1:2] - NA;dat1}) will do it. -- Bert On Wed, Jun 6, 2012 at 10:21 PM, Bert Gunter bgun...@gene.com wrote: Have you read An Intro to R? If

Re: [R] conditional statement to replace values in dataframe with NA

Thanks, problem solved. On Thu, Jun 7, 2012 at 1:58 PM, Daisy Englert Duursma daisy.duur...@gmail.com wrote: Hello and thanks for helping. #some data L3 - LETTERS[1:3] dat1 - data.frame(cbind(x=1, y=rep(1:3,2), fac=sample(L3, 6, replace=TRUE))) #When x==1 and y==1 I want to replace the 1

[R] if statement

Hi All, I have one difficulty in using the conditional if statement Assume , x - -1:4 x [1] -1 0 1 2 3 4 if x is lees than want I want to add 1 and I used the following command if(x0) {x=x+1} Warning message: In if (x 0) { : the condition has length 1 and only the first element

Re: [R] if statement

You need ifelse() instead of if(). On Wed, Mar 7, 2012 at 2:12 PM, Val valkr...@gmail.com wrote: Hi All, I have one difficulty in using the conditional if statement Assume , x - -1:4  x [1] -1  0  1  2  3  4 if x is lees than want I want to add 1 and I used the following command  

Re: [R] if statement

Try ifelse( x 0, x + 1, x) [1] 0 0 1 2 3 4 See also ?ifelse. HTH, Jorge.- On Wed, Mar 7, 2012 at 2:12 PM, Val wrote: Hi All, I have one difficulty in using the conditional if statement Assume , x - -1:4 x [1] -1 0 1 2 3 4 if x is lees than want I want to add 1 and I used

Re: [R] if statement

The simplest method would be: x[x0] - x[x0]+1 x - -1:4 x # [1] -1 0 1 2 3 4 x[x0] - x[x0]+1 x # [1] 0 0 1 2 3 4 I think where Val got confused is in thinking that if(x0) is applied separately to each element of x, one at a time. What actually happens, of course, is that

Re: [R] if statement

x - -1:4 x0 # returns TRUE (1) or FALSE (0) [1] TRUE FALSE FALSE FALSE FALSE FALSE x+as.numeric(x0) [1] 0 0 1 2 3 4 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide

Re: [R] if statement

Now I got results as I wanted. Thank you all. On Wed, Mar 7, 2012 at 2:51 PM, AAsk aa2e...@lycos.co.uk wrote: x - -1:4 x0 # returns TRUE (1) or FALSE (0) [1] TRUE FALSE FALSE FALSE FALSE FALSE x+as.numeric(x0) [1] 0 0 1 2 3 4 __

[R] And Statement for two if functions

I want to perform two if functions at the same time: if(home team away team home team = away team + 7) in R but i am struggling to work out how to write this correctly. Thanks for any help. -- View this message in context:

Re: [R] And Statement for two if functions

Hi kerry1912, And what exactly would you like to do after the if(...) statement? How did you read your data in? What's the output of str(yourdata)? Please see http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.htmland help us to help you. Regards, Jorge On

Re: [R] And Statement for two if functions

On Jan 30, 2012, at 9:52 AM, kerry1912 wrote: I want to perform two if functions at the same time: if(home team away team home team = away team + 7) in R but i am struggling to work out how to write this correctly. Generally newcomers to the R language find that the ifelse function does

Re: [R] And Statement for two if functions

Sorry that post was written in a bit if a rush. I am writing a function in which I am trying to create a league table from a data frame of rugby matches with the columns as follows: home team, away team, home score and away score. In rugby you can get an extra bonus point if you are the losing

Re: [R] And Statement for two if functions

Nested if's are fine in R, but as David said you probably want ifelse(). This sounds sufficiently homework-y that I'm hesitant to give example code but it's all over the archives. Just to head off a problem I see in your pesudo-code; you're going to want to use ifelse() to construct the points

Re: [R] if statement problem

On 24.12.2011 12:03, reena wrote: It didn't work. :( What did not work??? Please do not misuse the R-help mailing list! Its posting guide clearly asks you to cite the thread and specify reproducible examples that make other able to help. Best, Uwe Ligges -- View this message in

Re: [R] if statement problem

Hello again. I don't understand what didn't work. First, it seems better to use 'nrow', the result is the same stopifnot(length(x[,1]) == nrow(x)) Then your multiple OR condition. #if((x[i,1] || x[i,2] || x[i,3] || x[i,4]) 5) x - matrix(1:24, ncol=4) for(i in 1:nrow(x))

Re: [R] if statement problem

This is almost Circle 8.1.7 of 'The R Inferno': http://www.burns-stat.com/pages/Tutor/R_inferno.pdf but is making the mistake in the other direction. On 23/12/2011 22:40, reena wrote: Hello, I want to do fisher test for the rows in data file which has value less than 5 otherwise chi square

Re: [R] if statement problem

It didn't work. :( -- View this message in context: http://r.789695.n4.nabble.com/if-statement-problem-tp4230026p4230933.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list

[R] if statement problem

Hello, I want to do fisher test for the rows in data file which has value less than 5 otherwise chi square test .The p values from both test should be stored in one resulted file. but there is some problem with bold if statement. I don't know how implement this line properly. x =

Re: [R] if statement problem

reena wrote Hello, I want to do fisher test for the rows in data file which has value less than 5 otherwise chi square test .The p values from both test should be stored in one resulted file. but there is some problem with bold if statement. I don't know how implement this line

[R] Ifelse statement

Hello everyone, I have a (small) issue. I already googled a lot, so I decided to use ifelse instead of if (){} else{} All the elements seem to work seperately, but combined in the ifelse statement, it doesn't seem to work. #The price function is a function which is normally distributed with

Re: [R] Ifelse statement

Hi, You've got several things going on here. On Mon, Jul 11, 2011 at 3:39 PM, fre fre_stam...@hotmail.com wrote: Hello everyone, I have a (small) issue. I already googled a lot, so I decided to use ifelse instead of if (){} else{} All the elements seem to work seperately, but combined in

[R] If Statement

Hi, I am having some problems using the if statement correctly. I have used it many times previously so I dona't know what is different with this case. Here is my problem: I have a 1X10 matrix of values as follows: H.MC [,1] [1,] 4.257669 [2,] 7.023242 [3,] 4.949857 [4,]

Re: [R] If Statement

Hi, matrix has a 2 dimensions. Is this work: a-matrix(rep(c(1,2),c(5,5)),ncol=1) dim(a) for (i in 1:10) { ifelse(a[i,]==1, a[i,]-runif(1,3,4.5), a[i,]) } a Andrija On Tue, Mar 8, 2011 at 1:07 PM, dpender d.pende...@research.gla.ac.ukwrote: Hi, I am having some problems using the if

Re: [R] If Statement

On Mar 8, 2011, at 7:07 AM, dpender wrote: Hi, I am having some problems using the if statement correctly. I have used it many times previously so I dona't know what is different with this case. Here is my problem: I have a 1X10 matrix of values as follows: H.MC [,1] [1,]

Re: [R] If Statement

On Tue, Mar 08, 2011 at 04:07:03AM -0800, dpender wrote: Hi, I am having some problems using the if statement correctly. I have used it many times previously so I dona't know what is different with this case. Here is my problem: I have a 1X10 matrix of values as follows: H.MC

Re: [R] If Statement

-Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of dpender Sent: Tuesday, March 08, 2011 4:07 AM To: r-help@r-project.org Subject: [R] If Statement Hi, I am having some problems using the if statement correctly. I have

[R] if statement and truncated distribution

Hi R helpers, I am trying to use the if statement to generate a truncated random variable as follows: if (y[i]==0) { v[i] ~ rnorm(1,0,1) | (-inf ,0) } if (y[i]==1) { v[i] ~ rnorm(1,0,1) | (0, inf) } I guess I cannot use | ( , ) to restrict the range of a variable in R. Could you let me know

Re: [R] if statement and truncated distribution

25 oktober 2010 2:01 To: r-help@r-project.org Subject: [R] if statement and truncated distribution Hi R helpers, I am trying to use the if statement to generate a truncated random variable as follows: if (y[i]==0) { v[i] ~ rnorm(1,0,1) | (-inf ,0) } if (y[i]==1) { v[i] ~ rnorm(1,0,1) | (0, inf

[R] If Statement Help

Price 2010-10-11 99 2010-10-12101 2010-10-13102 2010-10-14103 2010-10-15 99 2010-10-18 98 2010-10-19 97 2010-10-20101 2010-10-21101 2010-10-22101 I have this dataset and I only want to return instances when the Price is 100. If I use

Re: [R] If Statement Help

Need to understand how 'indexing' is done in R: x - read.table(textConnection( Price + 2010-10-11 99 + 2010-10-12101 + 2010-10-13102 + 2010-10-14103 + 2010-10-15 99 + 2010-10-18 98 + 2010-10-19 97 + 2010-10-20101 + 2010-10-21101 + 2010-10-22

Re: [R] If Statement Help

Hi Jay, If x is your data, you could use subset() to do what you want: subset(x, Price 100) See ?subset for more information. HTH, Jorge On Sat, Oct 23, 2010 at 9:56 PM, Jason Kwok wrote: Price 2010-10-11 99 2010-10-12101 2010-10-13102 2010-10-14103

Re: [R] If Statement Help

Thanks for the help Jim. As a new user and member of this mailing list, I'm very impressed with all the support! Jay On Sat, Oct 23, 2010 at 10:21 PM, jim holtman jholt...@gmail.com wrote: Need to understand how 'indexing' is done in R: x - read.table(textConnection(

Re: [R] If Statement Help

Thanks Jorge. It works. Is there a way to keep the actual price in the price column instead of TRUE/FALSE but filtering on when price100? Thanks, Jay On Sat, Oct 23, 2010 at 10:37 PM, Jorge Ivan Velez jorgeivanve...@gmail.com wrote: Hi Jay, If x is your data, you could use subset() to do

Re: [R] If Statement Help

On Oct 23, 2010, at 7:44 PM, Jason Kwok wrote: Thanks Jorge. It works. Is there a way to keep the actual price in the price column instead of TRUE/FALSE but filtering on when price100? Huh? When I use subset I get what you ask for: subset(x, Price 100) Price 2010-10-12 101

[R] If Statement with more than one condition

I'm unable to find the OR operator like other language .. any suggestions? I want to do If (condition1 OR condition 2){ do something } Thanks for answering this elementary question. [[alternative HTML version deleted]] __

Re: [R] If Statement with more than one condition

Hi Santosh, I believe you are looking for |. For example: if(3 5 | 3 4) {print(TRUE)} Cheers, Josh On Fri, Oct 22, 2010 at 12:51 AM, Santosh Srinivas santosh.srini...@gmail.com wrote: I'm unable to  find the OR operator like other language .. any suggestions? I want to do If (condition1

Re: [R] If Statement with more than one condition

Joshua Wiley wrote: Hi Santosh, I believe you are looking for |. For example: if(3 5 | 3 4) {print(TRUE)} In an if () statement you use || more often. | is a vector operator that always evaluates both arguments; || is a scalar operator that quits if the left hand argument determines

Re: [R] If Statement with more than one condition

Santosh Srinivas santosh.srini...@gmail.com writes: I'm unable to find the OR operator like other language .. any suggestions? I want to do If (condition1 OR condition 2){ do something } if((condition1) | (condition2)){ do something } -- aleblanc

[R] ifelse statement

Dear list, I have a question I'm trying to use the following command in R, but it gives me an error message.The command is: data-ddply(data,c(year,name), transform, check1=ifelse(check1==1 check2==1, 1,NULL)) so in my data frame I already have the check1 variable, if the conditions

Re: [R] ifelse statement

Hi, Not sure since I've never done it, but shouldn't it be NA instead of NULL? Ivan Le 9/17/2010 15:23, n.via...@libero.it a écrit : Dear list, I have a question I'm trying to use the following command in R, but it gives me an error message.The command is: data-ddply(data,c(year,name),

[R] any statement equals to 'goto'?

I have the following code: - result - matrix(NA, nrow=1, ncol=5) for(i in 1:(nsnp-1)) { for(j in (i+1):nsnp){ tempsnp1 - data.lme[,i] tempsnp2 - data.lme[,j] fm1 -

Re: [R] any statement equals to 'goto'?

Sounds like you want help(tryCatch) # Catch the error and do something help(next) # Go to the next value of the surrounding loop Hope this helps a little. Allan On 31/08/10 19:34, karena wrote: I have the following code:

Re: [R] any statement equals to 'goto'?

these seem something that I am looking for, I will try them, thank you!! -- View this message in context: http://r.789695.n4.nabble.com/any-statement-equals-to-goto-tp2402107p2402264.html Sent from the R help mailing list archive at Nabble.com. __

[R] ifelse statement

Hi, I am a newbie of R, and playing with the ifelse statement. I have the following codes: ## first, for(i in 1:3) { for(j in 2:4) { cor.temp - cor(iris.allnum[,i], iris.allnum[,j]) if(i==1 j==2) corr.iris - cor.temp else corr.iris - c(corr.iris, cor.temp) } } this code is working fine. I

Re: [R] ifelse statement

On 07/07/2010 5:58 PM, karena wrote: Hi, I am a newbie of R, and playing with the ifelse statement. I have the following codes: ## first, for(i in 1:3) { for(j in 2:4) { cor.temp - cor(iris.allnum[,i], iris.allnum[,j]) if(i==1 j==2) corr.iris - cor.temp else corr.iris - c(corr.iris, cor.temp)

Re: [R] ifelse statement

On Wed, Jul 7, 2010 at 7:22 PM, Duncan Murdoch murdoch.dun...@gmail.com wrote: On 07/07/2010 5:58 PM, karena wrote: Hi, I am a newbie of R, and playing with the ifelse statement. I have the following codes: ## first, for(i in 1:3) { for(j in 2:4) { cor.temp - cor(iris.allnum[,i],

Re: [R] ifelse statement

On 07/07/2010 7:32 PM, Gabor Grothendieck wrote: On Wed, Jul 7, 2010 at 7:22 PM, Duncan Murdoch murdoch.dun...@gmail.com wrote: On 07/07/2010 5:58 PM, karena wrote: Hi, I am a newbie of R, and playing with the ifelse statement. I have the following codes: ## first, for(i in 1:3) {

Re: [R] ifelse statement

On 2010-07-08, at 10:33 , Duncan Murdoch wrote: On 07/07/2010 7:32 PM, Gabor Grothendieck wrote: On Wed, Jul 7, 2010 at 7:22 PM, Duncan Murdoch murdoch.dun...@gmail.com wrote: On 07/07/2010 5:58 PM, karena wrote: Hi, I am a newbie of R, and playing with the ifelse statement. I

Re: [R] ifelse statement

that makes sense. thank you, guys! -- View this message in context: http://r.789695.n4.nabble.com/ifelse-statement-tp2281576p2281706.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list

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