Dear List,
why does this not work?
df - data.frame(var1 = c(3,2,1), var2 = c(6,5,4), var3 = c(9,8,7),
fac = c('A', 'A', 'B'))
tapply(cbind(df$var1, df$var2, df$var3), df$fac, mean)
Thank you,
Stefan
__
R-help@r-project.org mailing list
Stefan Uhmann wrote:
Dear List,
why does this not work?
df - data.frame(var1 = c(3,2,1), var2 = c(6,5,4), var3 = c(9,8,7),
fac = c('A', 'A', 'B'))
tapply(cbind(df$var1, df$var2, df$var3), df$fac, mean)
because
length(cbind(df$var1, df$var2, df$var3))
# 9
length(df$fac)
On Tue, Jun 16, 2009 at 5:16 AM, Stefan Uhmann stefan.uhm...@googlemail.com
wrote:
why does this not work?
df - data.frame(var1 = c(3,2,1), var2 = c(6,5,4), var3 = c(9,8,7),
fac = c('A', 'A', 'B'))
tapply(cbind(df$var1, df$var2, df$var3), df$fac, mean)
Because tapply is defined for
Hi
r-help-boun...@r-project.org napsal dne 16.06.2009 12:45:04:
Stefan Uhmann wrote:
Dear List,
why does this not work?
df - data.frame(var1 = c(3,2,1), var2 = c(6,5,4), var3 = c(9,8,7),
fac = c('A', 'A', 'B'))
tapply(cbind(df$var1, df$var2, df$var3), df$fac, mean)
because
Stavros Macrakis wrote:
On Tue, Jun 16, 2009 at 5:16 AM, Stefan Uhmann stefan.uhm...@googlemail.com
wrote:
why does this not work?
df - data.frame(var1 = c(3,2,1), var2 = c(6,5,4), var3 = c(9,8,7),
fac = c('A', 'A', 'B'))
tapply(cbind(df$var1, df$var2, df$var3),
Petr PIKAL wrote:
Hi
r-help-boun...@r-project.org napsal dne 16.06.2009 12:45:04:
Stefan Uhmann wrote:
Dear List,
why does this not work?
df - data.frame(var1 = c(3,2,1), var2 = c(6,5,4), var3 = c(9,8,7),
fac = c('A', 'A', 'B'))
tapply(cbind(df$var1, df$var2, df$var3),
Hi,
Does tapply change the order when applied on a factor? Below is the code I
tried.
mylevels-c(IN0020020155,IN0019800021,IN0020020064)
mydata-c(IN0020020155,IN0019800021,IN0020020064,IN0020020155,IN0019800021,IN0019800021,IN0020020064,IN0020020064,IN0019800021)
The result of 'tapply' is just a named vector and the names are in
alphabetical order. If you want them printed in a different order, then you
have to specify it. Since you have the order in 'mylevels', this will work:
str(mysummary)
int [1:3(1d)] 4 3 2
- attr(*, dimnames)=List of 1
..$ :
Thanks, Jim.
It works!
On Wed, May 6, 2009 at 7:26 PM, jim holtman jholt...@gmail.com wrote:
The result of 'tapply' is just a named vector and the names are in
alphabetical order. If you want them printed in a different order, then you
have to specify it. Since you have the order in
Hi,
I don't believe the problem is related to tapply. I would say it is
because of the factor. In fact, the order of a factor is given by the
alphanumerical order of his levels. You can see it with levels(myfactor).
I you want to change the order, redefine the levels of myfactor with the
Hi Alain,
I tried levels(myfactor) as you suggested.
levels(myfactor)
[1] IN0020020155 IN0019800021 IN0020020064
The order is preserved, no alphanumerical sorting done here.
Regards.
On Wed, May 6, 2009 at 7:35 PM, Alain Guillet alain.guil...@uclouvain.bewrote:
Hi,
I don't believe the
Hi Ellison,
Thanks for pointing it out. Bad miss on my part.
Regards.
On Wed, May 6, 2009 at 7:55 PM, S Ellison s.elli...@lgc.co.uk wrote:
The problem is in the code.
When you say
mysummary-tapply(myfactor,mydata,length)
mysummary
you have used mydata as a factor and myfactor as the
The problem is in the code.
When you say
mysummary-tapply(myfactor,mydata,length)
mysummary
you have used mydata as a factor and myfactor as the data.
tapply has (correctly) used the ordered labels in the grouping factor
(mydata) to label its output.
If you did what you probably intended:
Genentech Nonclinical Statistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of jim holtman
Sent: Wednesday, May 06, 2009 6:57 AM
To: Chirantan Kundu
Cc: r-help@r-project.org
Subject: Re: [R] tapply changing order of factor levels
Hi,
I meant that your problem occured because the levels of mylevels are not
ordered whereas tapply uses the ordered levels for printing. If you
order them (look under), you can see the results of the tapply has the
same order as the levels of myfactor
i use tapply and by often, but i always end up banging my head against
the wall with the output.
is there a simpler way to convert the output of the following tapply to
a dataframe or matrix than what i have here:
# setup data for tapply
dt = data.frame(bucket=rep(1:4,25),val=rnorm(100))
fn =
Dear Dan,
Try this:
do.call(rbind,a)
HTH,
Jorge
On Mon, Apr 13, 2009 at 12:41 PM, Dan Dube dd...@advisen.com wrote:
i use tapply and by often, but i always end up banging my head against
the wall with the output.
is there a simpler way to convert the output of the following tapply to
a
do.call(rbind,a)
[,1] [,2] [,3] [,4]
1 -0.7871502 -0.4437714 0.4011135 -0.2626129
2 -0.9546515 0.2210001 0.816 0.1245766
3 -0.5389725 -0.2750984 0.6655951 -0.1873485
4 -0.8176898 -0.1844181 0.4737187 -0.2688996
On Mon, Apr 13, 2009 at 12:41 PM, Dan Dube
this is what i needed! thank you.
-Original Message-
From: Jorge Ivan Velez [mailto:jorgeivanve...@gmail.com]
Sent: Monday, April 13, 2009 12:50 PM
To: Dan Dube
Cc: r-help@r-project.org
Subject: Re: [R] tapply output as a dataframe
Dear Dan,
Try this:
do.call(rbind
Hello! I have encountered a really weird problem. Maybe you've
encountered it before?
I have a large data frame importances. It has one factor ($A) with 3
levels: 3, 9, and 15. $B is a regular numeric variable.
Below I am picking a really small sub-frame (just 3 rows) based on
indices. indices
on 02/13/2009 11:09 AM Dimitri Liakhovitski wrote:
Hello! I have encountered a really weird problem. Maybe you've
encountered it before?
I have a large data frame importances. It has one factor ($A) with 3
levels: 3, 9, and 15. $B is a regular numeric variable.
Below I am picking a really
On Fri, Feb 13, 2009 at 12:24 PM, Marc Schwartz
marc_schwa...@comcast.net wrote:
on 02/13/2009 11:09 AM Dimitri Liakhovitski wrote:
Hello! I have encountered a really weird problem. Maybe you've
encountered it before?
I have a large data frame importances. It has one factor ($A) with 3
: R-Help List
Subject: Re: [R] tapply bug? - levels of a factor in a data frame after
tapply are intermixed
Sorry - one clarification:
When I run:
test$xx - the what I am currently seeing is:
[1] 9 3 15
Levels: 3 9 15
But what I am expecting to be seeing is:
[1] 9 3 15
Levels: 9
on 02/13/2009 11:38 AM Dimitri Liakhovitski wrote:
On Fri, Feb 13, 2009 at 12:24 PM, Marc Schwartz
marc_schwa...@comcast.net wrote:
on 02/13/2009 11:09 AM Dimitri Liakhovitski wrote:
Hello! I have encountered a really weird problem. Maybe you've
encountered it before?
I have a large data
-
project.org] On Behalf Of Dimitri Liakhovitski
Sent: Friday, February 13, 2009 10:54 AM
To: marc_schwa...@comcast.net
Cc: R-Help List
Subject: Re: [R] tapply bug? - levels of a factor in a data frame after
tapply are intermixed
Sorry - one clarification:
When I run:
test$xx - the what I am currently
You might take a look at the transformBy function in the doBy package
For example,
new.df=transformBy(~group,data=my.df, new=y/max(y))
David Freedman
baptiste auguie-2 wrote:
Dear list,
I have a data.frame with x, y values and a 3-level factor group,
say. I want to create a new
Dear list,
I have a data.frame with x, y values and a 3-level factor group,
say. I want to create a new column in this data.frame with the values
of y scaled to 1 by group. Perhaps the example below describes it best:
x - seq(0, 10, len=100)
my.df - data.frame(x = rep(x, 3), y=c(3*sin(x),
On 12/10/2008 12:02 PM, baptiste auguie wrote:
Dear list,
I have a data.frame with x, y values and a 3-level factor group, say.
I want to create a new column in this data.frame with the values of y
scaled to 1 by group. Perhaps the example below describes it best:
x - seq(0, 10, len=100)
On Wed, Dec 10, 2008 at 11:02 AM, baptiste auguie [EMAIL PROTECTED] wrote:
Dear list,
I have a data.frame with x, y values and a 3-level factor group, say. I
want to create a new column in this data.frame with the values of y scaled
to 1 by group. Perhaps the example below describes it best:
baptiste auguie wrote:
Dear list,
I have a data.frame with x, y values and a 3-level factor group, say.
I want to create a new column in this data.frame with the values of y
scaled to 1 by group. Perhaps the example below describes it best:
x - seq(0, 10, len=100)
my.df - data.frame(x =
Excellent! I completely forgot its name and existence. Perhaps ave
should be mentioned on the help page of either by, tapply, split.
Many thanks,
baptiste
On 10 Dec 2008, at 17:20, Chuck Cleland wrote:
On 12/10/2008 12:02 PM, baptiste auguie wrote:
Dear list,
I have a data.frame with x,
On 10 Dec 2008, at 17:25, hadley wickham wrote:
On Wed, Dec 10, 2008 at 11:02 AM, baptiste auguie
[EMAIL PROTECTED] wrote:
Dear list,
I have a data.frame with x, y values and a 3-level factor group,
say. I
want to create a new column in this data.frame with the values of y
scaled
to 1
Dear all,
A quick question which I somehow cannto figure out: I want to apply
the function any to subsets of a dataset in order to create a vector
with TRUE/FALSE values, depending on whether a subset has the number
5. I.e.,
y - matrix(c(1,2,3,3,4,5,5,6,6,7,5,1,1,3,5,NA,5,1,1,3),ncol=2)
y
Try this:
sapply(tapply(y[,2],na.omit(y[,1]), `==`, 5), any)
On Wed, Nov 19, 2008 at 4:47 PM, Stephan Lindner [EMAIL PROTECTED] wrote:
Dear all,
A quick question which I somehow cannto figure out: I want to apply
the function any to subsets of a dataset in order to create a vector
with
Stephan
Try:
tapply(y[,2], y[,1], function(x) any(x==5))
Peter Alspach
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Stephan Lindner
Sent: Thursday, 20 November 2008 7:48 a.m.
To: [EMAIL PROTECTED]
Subject: [R] tapply and any
Dear all
Hi. I searched the list and didn't found nothing similar to this. I simplified
my example like below:
#I need calculate correlation (for example) between 2 columns classified by a
third one at a data.frame, like below:
#number of rows
nr = 10
#the third column is to enforce that I need
Try this:
sapply(by(dataf[,c(V1,V2)], dataf$class, cor), '[', 3)
On Wed, Oct 1, 2008 at 9:21 AM, Cézar Freitas [EMAIL PROTECTED] wrote:
Hi. I searched the list and didn't found nothing similar to this. I
simplified my example like below:
#I need calculate correlation (for example) between
The first tapply in your question subsets V1 but not V2 so they are
of different length. To subset both tapply over the row names and
perform the subsetting in the function:
tapply(rownames(dataf), dataf$class, function(r) cor(dataf[r, V1],
dataf[r, V2]))
or
tapply(rownames(dataf),
On Wed, Oct 1, 2008 at 7:21 AM, Cézar Freitas [EMAIL PROTECTED] wrote:
Hi. I searched the list and didn't found nothing similar to this. I
simplified my example like below:
#I need calculate correlation (for example) between 2 columns classified by a
third one at a data.frame, like below:
Hello all,
I have a df like this:
w - c(1.20, 1.34, 2.34, 3.12, 2.89, 4.67, 2.43,
2.89, 1.99, 3.45, 2.01, 2.23, 1.45, 1.59)
g - rep(c(a, b), each=7)
df - data.frame(g, w)
df
# 1. Mean for each group
tapply(df$w, df$g, function(x) mean(x))
# 2. Range for each group - fix value 0.15
Is this what you want:
w - c(1.20, 1.34, 2.34, 3.12, 2.89, 4.67, 2.43,
+ 2.89, 1.99, 3.45, 2.01, 2.23, 1.45, 1.59)
g - rep(c(a, b), each=7)
df - data.frame(g, w)
df
gw
1 a 1.20
2 a 1.34
3 a 2.34
4 a 3.12
5 a 2.89
6 a 4.67
7 a 2.43
8 b 2.89
9 b 1.99
10 b 3.45
11 b 2.01
12
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
http://www.student.kuleuven.be/~m0390867/dimitris.htm
- Original Message -
From: Manuel Montes [EMAIL PROTECTED]
To: r-help@r-project.org
Sent: Tuesday, April 08, 2008 11:14 AM
Subject: [R] tapply
Does anyone have something like tapply for matrices? I would like to average
the contents of columns
according to factors but tapply works only with one column at each time. Is
something available to do
everything in one step?
Many thanks.
Manuel Montes
On 4/8/2008 5:14 AM, Manuel Montes wrote:
Does anyone have something like tapply for matrices? I would like to average
the contents of columns
according to factors but tapply works only with one column at each time. Is
something available to do
everything in one step?
Many thanks.
Here is how you can get the proportions from your data frame:
prop.table(table(paste(x$testdate, x$testtime), x$Behavior),margin=1)
EA FL HO MA OS
PE SI
28Mar96 1014 0. 0. 0.5000 0. 0.
One possibility is:
a- V1 V2 F1
+ 1 A 2 0
+ 2 A 3 0
+ 3 A 4 1
+ 4 B 3 0
+ 5 B 2 1
+ 6 C 6 0
+ 7 C 2 0
+ 8 C 6 0
+
b-read.table(textConnection(a),header=TRUE)
f-rep(0,dim(b)[1])
f[b$F1==0] - ave(b$V2[b$F1==0],b$V1[b$F1==0])
cbind(b,f)
V1 V2 F1f
1 A 2 0
Dear list,
I have this dataframe
V1 V2 F1
1 A 2 0
2 A 3 0
3 A 4 1
4 B 3 0
5 B 2 1
6 C 6 0
7 C 2 0
8 C 6 0
and would like to calculate a new column
with mean-values, following this rule
1. If F1 = 0 calculate the mean from V2
for each factor in V1.
2. If F1 = 1, then
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