Sorry I'm not sure that prob is suitable for my purposes(but i'm quite
newbie with R).
If I correctly understand prob allows to set a weight for each row in the
original dataset in order to include the rows on the basis of their
weights). ... I'm not sure to correctly understanding ;-)
In my case
I think you're right -- prob probably isn't quite what you need (at
least, directly): constrained sampling like this is a little trickier
-- I'll leave this to someone who knows more than me.
Michael
On Thu, Jun 14, 2012 at 9:07 AM, Guido Leoni guido.le...@gmail.com wrote:
Sorry I'm not sure
Just for make the archives more complete and simplifing the life of the
following readers.
I think to have solved my problem using the caret packages.
In this package there is a function named createData Partition that after
defining a column of interest in a data.frame allows to split a dataset
Below are two equivalent solutions.
study_df - data.frame(course = c(rep('Mathematics', 80 + 15),
rep('Physics', 32 + 24),
rep('Biology', 18 + 29)),
A = c(rep(1, 80), rep(0, 15),
On Jun 1, 2012, at 00:30 , Mike Hilt wrote:
Could someone help me out and let me know what ‘%?%’
(where ? = a single letter in a 3 character string with ‘%’
being the 1st and 3rd characters), and/or ‘%+%’ does in
R code/function?
They are just a vehicle for defining binary operators:
Hi Kelly,
The function has a limitation that it cannot handle any column in your x that
is a categorical variable with more than 32 categories. One possibility is to
see if you can bin some of the categories into one to get below 32 categories.
Andy
-Original Message-
From:
This is a well-known limitation. You have to group categorical attributes
together to work around.
--
Weifeng (aaron) liu | retail systems pricing | sr research scientist
-Original Message-
From:
On May 28, 2012, at 9:55 AM, gianni lavaredo wrote:
Dear Researchers,
sorry for this simple question. I have a point plot with mean
values and i
wish to plot line with Standard Deviation as Whiskers. I calculate
the
mean+sd and mean-sd, but i can not figure out the way to add the line.
The function i am looking is a bars from the mean points of the plot in
boxplot style. I tryed several forum but I have no clear the way to create
these bars.
Gianni
On Mon, May 28, 2012 at 7:13 PM, David Winsemius dwinsem...@comcast.netwrote:
On May 28, 2012, at 9:55 AM, gianni lavaredo
This post are useful.
http://myowelt.blogspot.com.br/2008/03/beautiful-error-bars-in-r.html
http://mapas.mma.gov.br/i3geo/pacotes/rlib/win/gplots/html/plotCI.html
Walmes.
==
Walmes Marques Zeviani
LEG (Laboratório de
Hello,
The function 'arrows' with angle=90 can do the job.
mydata -
data.frame(mean=c(0.42,0.41,0.41,0.43,0.45,0.43,0.43,0.42,0.44,0.45,0.45,0.45,0.46,0.43,0.42,0.37,0.44,0.46,0.46,0.39,0.40),
On Mon, May 28, 2012 at 3:16 PM, Kelly Cool kellycoo...@yahoo.com wrote:
I was wondering if there was a quick way to extract out certain rows from a
data set in R?
I have a data.frame, LOG, where in one column, sample_data_tx, there is a
list of 62 different types of treatment. I've
Hi Kelly,
Check
?subset
in the R console. Here is a piece of code (untested):
subset(LOG, sample_data %in% c(Noy, PLO))
HTH,
Jorge.-
On Mon, May 28, 2012 at 3:16 PM, Kelly Cool wrote:
I was wondering if there was a quick way to extract out certain rows from
a data set in R?
I have a
Please show us the 'lapply' statement you are using. Here is a simple
case of catching an error in an lapply and continuing:
lapply(c(1,2,-3, 4), function(x){
+ a - try(stopifnot(x 0)) # force an error
+ if (inherits(a, 'try-error')) return(NULL)
+ x
+ })
Error : x 0 is not TRUE
Jim:
That's the ticket! I'm actually using parLapply with a long, ugly function
- so I was loath to post that mess.
Many thanks - you saved my weekend.
On Fri, May 25, 2012 at 2:23 PM, jim holtman jholt...@gmail.com wrote:
Please show us the 'lapply' statement you are using. Here is a
On 5/25/2012 12:48 PM, John Kerpel wrote:
Jim:
That's the ticket! I'm actually using parLapply with a long, ugly function
- so I was loath to post that mess.
Many thanks - you saved my weekend.
In the context of tryCatch in your question
lst - list(1, 2, -3, 4)
sapply(lst, function(x)
Subject: Re: [R] Question on if i am allowed to do something
On May 23, 2012, at 6:51 PM, Duncan Murdoch wrote:
On 12-05-23 1:31 PM, Giannis Mamalikidis wrote:
Hello all.
I would like to know: provided that I absolutely state that R is not mine
and I also include the R’s License which will be shown
in Electrical and Mechanical Engineering
---
-Original Message- From: Marc Schwartz
Sent: Thursday, May 24, 2012 3:58 AM
To: Duncan Murdoch
Cc: Giannis Mamalikidis ; r-help@r-project.org
Subject: Re: [R] Question
---
-Original Message-
From: Marc Schwartz
Sent: Thursday, May 24, 2012 3:58 AM
To: Duncan Murdoch
Cc: Giannis Mamalikidis ; r-help@r-project.org
Subject: Re: [R] Question on if i am allowed to do something
On May 23, 2012, at 6:51 PM, Duncan Murdoch wrote:
On 12-05-23 1:31 PM, Giannis
I see. It is decided then. As it might be possible that the license might be
violated, I certainly will not include R in my programme.
Thank you all for your help, you've been very helpful.
---
Giannis Mamalikidis
On 12-05-23 1:31 PM, Giannis Mamalikidis wrote:
Hello all.
I would like to know: provided that I absolutely state that R is not mine
and I also include the R’s License which will be shown so people know R and
R’s license,
(provided the above) am I allowed to include R’s folder (the folder that
On May 23, 2012, at 6:51 PM, Duncan Murdoch wrote:
On 12-05-23 1:31 PM, Giannis Mamalikidis wrote:
Hello all.
I would like to know: provided that I absolutely state that R is not mine
and I also include the R’s License which will be shown so people know R and
R’s license,
(provided the
Hi,
That seems a reasonable enough approach to me.
(p - pnorm(0, mean = 1, sd = .5))
is the probability of a value being less than or up to 0 from the
distribution you specified. Using that, lets repeat your little test
1000 times using your code, and then using ribnom() where the
probability
try this:
x - read.table(text = 'Not A A
+ Mathematics 80 15
+ Physics 32 24
+ Biology 18 29', skip = 1, as.is = TRUE)
# create the result
result - do.call(rbind, lapply(1:nrow(x), function(.row){
+ data.frame(course = x$V1[.row]
+ , A = c(rep(1, x$V2[.row]), rep(0, x$V3[.row]))
Not sure what your question was. Perhaps you could look up the reshape2 package
and ask a more specific question?
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.us
On May 6, 2012, at 3:56 PM, E Atescelik wrote:
Hi,I had a question about transforming data into data frame object
with two columns. I have data genal2.txt (see attachment) My
data frame called genal2frame has to be in the form:
genal2frame[1:6,]
y mut
1
I don't think you can do it within expand.grid() but something like
this might work:
rownames(x) - apply(x, 1, paste, collapse = )
Michael
On Tue, May 1, 2012 at 5:05 AM, Kelly Cool kellycoo...@yahoo.com wrote:
Hi,
I am extremely new to R, and was wondering if someone would be able to help
Mike,
Try plot(pref, ..., scat1d.opts=list(frac=0.025, lwd=0.3, nhistSpike=i))
where i = 1 to always use spike histograms (default is to use them if n =
2000) or i=1e7 to never use them and to always jitter instead. There are
many other scat1d options you can pass through scat1d.opts.
Frank
On May 1, 2012, at 15:36 , R. Michael Weylandt wrote:
I don't think you can do it within expand.grid() but something like
this might work:
rownames(x) - apply(x, 1, paste, collapse = )
Also
rownames(x) - do.call(paste, c(x, sep=))
or, in recent versions,
rownames(x) - do.call(paste0,
On 12-04-19 3:11 PM, harry mamaysky wrote:
I am new to R, and I have been running into the following situation
when I mistype a variable name in some code:
list1- list( a=1, b=2 )
list2- list( a=1 )
list2$b- list1$c
list2
$a
[1] 1
I would think at the point where I am trying to reference a
You may want to send the files as well as what you exactly typed in the
shell in a private message.
Uwe Ligges
On 15.04.2012 20:09, Katharine Miller wrote:
Yes. I have version 2.15.0 of Rtools as well. I went ahead and
re-installed both R and Rtools just to make sure everything was OK. But
On 14.04.2012 21:53, Katharine Miller wrote:
OK. So, I have 64 bit Windows 7 and I have installed R 2.15.0
Yes, and have you also installed version 2.15 of the Rtools?
Uwe ligges
Thanks
2012/4/14 Uwe Liggeslig...@statistik.tu-dortmund.de
On 14.04.2012 19:01, Katharine Miller
Yes. I have version 2.15.0 of Rtools as well. I went ahead and
re-installed both R and Rtools just to make sure everything was OK. But
that did not fix the problem.
- Katharine
2012/4/15 Uwe Ligges lig...@statistik.tu-dortmund.de
On 14.04.2012 21:53, Katharine Miller wrote:
OK. So, I
On 14.04.2012 00:24, Katharine Miller wrote:
Hi,
I have some C++ code that I compiled into a dll for use in 32 bit R and
would like to recompile for use in 64bit R. I thought it would be as easy
as going to R-2.15.0\bib\x64 and running R CMD SHLIB mfregRF.c
Is this Windows?
1. If so, is
Hi,
Sorry - I should have said that I was using Windows 7 on a 64 bit computer
in my earlier post.
I used the installer to install R, I did not do a build from source. I
have read the installation instructions. Both R and Rtools are first in my
path, but by toolchain do you mean that I need to
On 14.04.2012 19:01, Katharine Miller wrote:
Hi,
Sorry - I should have said that I was using Windows 7 on a 64 bit computer
in my earlier post.
Which Windows 7? 64-bit or 32-bit?
I used the installer to install R, I did not do a build from source. I
have read the installation
OK. So, I have 64 bit Windows 7 and I have installed R 2.15.0
Thanks
2012/4/14 Uwe Ligges lig...@statistik.tu-dortmund.de
On 14.04.2012 19:01, Katharine Miller wrote:
Hi,
Sorry - I should have said that I was using Windows 7 on a 64 bit computer
in my earlier post.
Which Windows 7?
On Apr 11, 2012, at 9:21 AM, Daniel Gabrieli wrote:
Hi,
I hope this is not too trivial, but I've had this recurring problem
and I think there is super easy solution, just not sure what it is.
Please see short example below. I would like to get the frequency
(counts) of all the variables in a
This would do it in your example:
levels(animals$V1) - c(cat,tiger,dog,fish)
table(animals)
cattigerdog fish
2 200
HTH
David
cat tiger dog fish
2 2 0 0
On 11 April 2012 14:21, Daniel Gabrieli daniel.gabri...@gmail.com wrote:
I would like to get the frequency
(counts) of all the variables in a single column (that is
easy), but I would also like to return the value 0 for the
absence of variables defined in another column.
If you use factor() on your columns and include all the animals in the factor
levels, you
-Original Message-
This would do it in your example:
levels(animals$V1) - c(cat,tiger,dog,fish)
table(animals)
cattigerdog fish
2 200
But be very wary of
levels(animals$V2)- c(cat,tiger,dog,fish)
table(animals$V2)
cat tiger dog
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Saruman
I dont see how this answered the original question of the poster.
He was quite clear: the value of the predictions coming out
of RF do not
match what comes out of the predict function using
I dont see how this answered the original question of the poster.
He was quite clear: the value of the predictions coming out of RF do not
match what comes out of the predict function using the same RF object and
the same data. Therefore, what is predict() doing that is different from RF?
Yes, RF
By googling.
On Thu, Mar 22, 2012 at 11:37 PM, Anjana Thampi
thampi.anjana...@gmail.com wrote:
How do you run a regression in R?
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Short answer to a very good question: one has to use function(x)
tail(x, 1) syntax to avoid using the default tail(x, 6). There are
some other ways to achieve the same thing, but I think this syntax is
generally preferred for its clarity.
Other question: yes I believe so.
Michael
On Sun, Feb
On Sun, Feb 26, 2012 at 9:06 AM, knavero knav...@gmail.com wrote:
Quick newb question about R relating to the line of code below:
rawCool = read.zoo(cooling.txt, FUN = as.chron, format = %m/%d/%Y %H:%M,
sep = \t, aggregate = function(x) tail(x, 1))
I'm wondering what the specifics are for
This works for me:
plot(0:6, runif(7), xaxt=n)
axis(1, at=0:6, labels=c(08:00, 12:00, 16:00, 20:00, 24:00,
04:00, 08:00), cex=0.8)
You need the xaxt=n in the plot statement, and the correct form is at=0:6
Sarah
On Mon, Feb 20, 2012 at 6:39 PM, Gerard Smits g_sm...@verizon.net wrote:
Hi
Worked like a charm! Thanks for your help. Gerard
On Feb 20, 2012, at 3:52 PM, Sarah Goslee wrote:
This works for me:
plot(0:6, runif(7), xaxt=n)
axis(1, at=0:6, labels=c(08:00, 12:00, 16:00, 20:00, 24:00,
04:00, 08:00), cex=0.8)
You need the xaxt=n in the plot statement, and the
Sorry about that -- forgot the case where you might only have a
certain entry once: try this,
sapply(split(GS, rownames(GS)), function(x) colSums(as.matrix(x)))
or
sapply(split(GS, rownames(GS)), function(x) if(is.matrix(x)) colSums(x) else x)
I'm not sure if there's a way to force split to
Blah! Forget that first one -- the second one should be fine. (or at
least, I don't see a problem with it immediately)
sapply(split(GS, rownames(GS)), function(x) if(is.matrix(x)) colSums(x) else x)
Michael
On Wed, Feb 15, 2012 at 7:19 AM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
1) The DEA package appears to have been removed from CRAN in 2008, so
it is not likely to be readily available. Old versions are available
from the CRAN archives though but I don't imagine you'll get much
support if you try to use them:
ftp://cran.r-project.org/pub/R/src/contrib/Archive/DEA/
2)
On Feb 15, 2012, at 7:19 AM, R. Michael Weylandt wrote:
Sorry about that -- forgot the case where you might only have a
certain entry once: try this,
sapply(split(GS, rownames(GS)), function(x) colSums(as.matrix(x)))
or
sapply(split(GS, rownames(GS)), function(x) if(is.matrix(x))
But that's dropping unused factor levels, not the drop of `[`
Michael
On Wed, Feb 15, 2012 at 9:16 AM, David Winsemius dwinsem...@comcast.net wrote:
On Feb 15, 2012, at 7:19 AM, R. Michael Weylandt wrote:
Sorry about that -- forgot the case where you might only have a
certain entry once:
On Feb 15, 2012, at 15:17 , R. Michael Weylandt wrote:
But that's dropping unused factor levels, not the drop of `[`
Is there a good reason that nobody has suggested looking at aggregate()? There
would seem to be a little red tape to sort out, but, I mean, this is generally
speaking what
On 02/14/2012 06:19 AM, Michael Methlagl wrote:
Hi everybody,
i made a scatterplot using the command
plot (datafile1, xlim=c(0,10), ylim=c(0.001, 1), log=y, xlab=x Achse, ylab=y
Achse, frame.plot=FALSE, axes = TRUE).
Now i have a problem. There is a gap between the x and the y axis. I want
Perhaps something (untested) like
sapply(split(x, rownames(x)), colSums)
Next time it's suggested you use dput() to send your data.
Michael
On Tue, Feb 14, 2012 at 7:08 AM, Soheila Khodakarim
lkhodaka...@gmail.com wrote:
I have this matrix in R,
s1 s2 s3 s4
g1 1 0 0 0
g1 0 1 0
Hi there,
The command for merging is:
merge
Can you please clarify by which variable you wish to merge by?
Can you maybe use ?dput function in order to give a self contained R code
example of your data - and the output you wish to get?
Best,
Tal
Contact
On Tue, Jan 31, 2012 at 2:24 PM, Tal Galili tal.gal...@gmail.com wrote:
Hi there,
The command for merging is:
merge
A fortunes candidate?
-- Bert
Can you please clarify by which variable you wish to merge by?
Can you maybe use ?dput function in order to give a self contained R code
Without knowing more about what you are trying to accomplish, and what
you have tried so far (code) it's difficult to say. But I'll venture
this: are you sure you need a graph? Seems like a table might suffice.
BT - sample(1:5, 50, replace=TRUE)
RA - sample(1:5, 50, replace=TRUE)
table(BT)
On 02/01/2012 08:13 AM, Rebecca Lisi wrote:
I am having trouble generating a graph.
I want to know the % of respondents who answered that they strongly
agree or agree the America owes R's ethnic group a better chance
(BTTRCHNC) and I want to organize it by racial group (RACESHRT).
BTTRCHNC is
Greetings
On Sat, Jan 28, 2012 at 2:43 PM, Daniel Negusse
daniel.negu...@my.mcphs.edu wrote:
while reading some tutorials, i came across this and i am stuck. i want to
understand it and would appreciate if anyone can tell me.
design - model.matrix(~ -1+factor(c(1,1,2,2,3,3)))
can
Perhaps I'm misunderstanding you, but it doesn't sound like this is
much of an R question at all: what is the code book? If it's an
actual (dead tree) book, I don't think there's much you can do in R to
automate identifications; if it's an online API, you *might* be able
to rig a matching
- Original Message -
From: R. Michael Weylandt michael.weyla...@gmail.com
To: Nicole Marie Ford nmf...@uwm.edu
Cc: r-help r-help@r-project.org
Sent: Sunday, January 29, 2012 9:51:37 PM
Subject: Re: [R] question about ... questions/ code
Perhaps I'm misunderstanding you, but it doesn't
On Jan 24, 2012, at 11:17 AM, Taylor, Brian wrote:
We were looking at conducting a pilot program with Dell to virtualize our lab
environments. We are specifically looking at Dell/Citrix provisioning
servers. The OS in this setup is streamed from the server on every boot. I
was curious
Hcan you give session info (after loading playwith)? I'm able
to get that code to work...also -- can you get the basic RGtk
functions (like gwindow() ) to work?
Michael
On Thu, Jan 19, 2012 at 5:28 PM, Farhat Maha mar...@gmail.com wrote:
Hello, I managed to install playwith package and
Thanks for your reply Michael,
gwindow() command does work. and here is my sessionInfo
gwindow()
guiWidget of type: gWindowRGtk for toolkit: guiWidgetsToolkitRGtk2
*(opens a window)*
sessionInfo()
R version 2.14.1 (2011-12-22)
Platform: i486-pc-linux-gnu (32-bit)
locale:
[1]
I can't replicate the problem on my system (OS X) and I don't know
enough about the Gtk + tcltk frameworks to help diagnose it outside of
R -- it might be worth working up a minimal (non-)working example
along the lines of:
michaelweylandt$ R --vanilla
library(playwith)
playwith(plot(1:10))
Hi
Hi,
I am creating a function and ran into the problem of selecting a column
from a dataset. It seems as though the $ function (as in
data$columnname)
does not apply in the function. In simplified version:
This works:
testf2-function(data,columnnumber){print(data[,columnnumber])}
Just put the columnname variable into the brackets as well: they
accept strings.
As a general rule, always use the brackets (single or double) when
programming: `$` has some great features for interactive use but can
bite if you're not careful.
Michael
On Fri, Jan 13, 2012 at 5:34 PM, Julia
On 10/01/2012 11:31 AM, Wang, Jing wrote:
Dear Sir/Madam,
I want to download R development version 2.15.0 source code. But I just found
the version for windows and MacOS. So would you please give me some instruction
about how can I download the R 2.15.0 source code? Thank you very much for
Hi
[R] question about rev
Hi,all:
I have a vector,and wanna get the opposite value via rev function.
a
[1] FALSE FALSE TRUE TRUE TRUE
rev(a)
[1] TRUE TRUE TRUE FALSE FALSE
I don't know why the 3rd TRUE has not been reversed,while all other
values are reversed?
Yes£¬I find out later.
rev is only reverse the order.
What I use is !
Thanks
At 2012-01-06 16:07:11,Petr PIKAL petr.pi...@precheza.cz wrote:
Hi
[R] question about rev
Hi,all:
I have a vector,and wanna get the opposite value via rev function.
a
[1] FALSE FALSE TRUE TRUE
the function /rev / REVERSEs the order of the vector, as
v= c(1,2,3)
rev(v)= 3,2,1
if you want the opposite value , just add a exclamation in front of the
vector:
v=c(T,F,T,T);
!v is F,T,F,F
--
View this message in context:
http://r.789695.n4.nabble.com/question-about-rev-tp4268518p4268716.html
sorry for the re-post...
On Sun, Dec 11, 2011 at 8:22 PM, Michael comtech@gmail.com wrote:
Hi all,
I just couldn't find a R function which can fit multiple seasonal
patters... i.e. in the following code:
*arima(x = data, order = c(p, d, q), seasonal = list(order = c(P, D, Q),
period
Hi
First of all, it's R, not r, and on this mailing list people care about
this kind of thing.
Second, you will need to provide more information in order to get better
help. Please read the posting guide.
There are a number of introductory level documents available via CRAN,
please
This is not a statistical help list. Post to stats.stackexchange.com
or a similar list to have someone tutor you in regression and explain
why what you are doing is likely to produce utter nonsense.
Or, better yet, get local statistical help in person. You also clearly
need to do some reading on
First of all, it's R, not r, and on this mailing list people care about
this kind of thing.
Second, you will need to provide more information in order to get better
help. Please read the posting guide.
There are a number of introductory level documents available via CRAN,
please pick one and
Vytautas Rakeviius vytautas1...@yahoo.com writes:
But still I have question about results interpretation. In the end I
want to construct prediction function in form:
Y=a1x1+a2x2
The predict() function does the prediction for you. If you want to
construct the prediction _equation_, you can
-project.org
Subject: Re: [R] Question about randomForest
Matthew,
Your intepretation of calculating error rates based on the training
data is incorrect.
In Andy Liaw's help file err.rate-- (classification only) vector
error rates of the prediction on the input data, the i-th element
being
Thanks for the help. Let me explain in more detail how I think that
randomForest works so that you (or others) can more easily see the
error of my ways.
The function first takes a random sample of the data, of the size
specified by the sampsize argument. With this it fully grows a tree
resulting
I am pretty sure that when each tree is fitted the error rate for tree 'i' is
it's performance on the data which was not used to fit the ith tree (OOB). In
this way cross validation is performed for each tree but I do not think that
all trees fitted prior are involved in the computation of that
Matthew,
Your intepretation of calculating error rates based on the training
data is incorrect.
In Andy Liaw's help file err.rate-- (classification only) vector
error rates of the prediction on the input data, the i-th element
being the (OOB) error rate for all trees up to the i-th.
My
Hi Matthew,
The error rate reported by randomForest is the prediction error based
on out-of-bag OOB data. Therefore, it is different from prediction
error on the original data since each tree was built using bootstrap
samples (about 70% of the original data), and the error rate of OOB is
likely
On Thu, 24 Nov 2011, Andreas Klein wrote:
Hello,
I am a little bit confused regarding the density values obtained
from the function kde2d() from the package MASS because the are not
in the intervall [0,1] as I would expect them to be. Here is an
Your expectation is wrong.
example:
x -
I don't really know about the second half of your email, but are you sure you
don't just need to reload the packages with the library() command rather than
reinstalling them?
It's also to set up autoload: google Rprofile for instructions.
Michael
On Nov 18, 2011, at 3:52 PM, Roger Coupal
On Nov 18, 2011, at 3:52 PM, Roger Coupal wrote:
Hi, I am working with R on a Mac. I need to use a couple of packages
that I found on the Web site. I install them using Packages and
Data: Package Manager. I leave R and come back another time and the
installed packages are not installed.
On Nov 14, 2011, at 10:49 PM, Miles Yang wrote:
Hi all,
I wrote a r program as below:
x - 1:10
y - c(3,3,3,3,3,3,3,3,3,3)
fit - lm(log(y) ~ x)
summary(fit)
And I expect to get some error message from R, because y is
constant.
But, I got the message as below:
You are asking R to tell
Dear Miles,
Within rounding error, you got the right intercept, log(3); slope, 0;
residuals, all 0; residual standard error, 0; and standard errors of the
intercept and slope, both 0. The R^2 should have been undefined (i.e., 0/0),
but dividing one number that's 0 within rounding error by another
Jan Kraner jan.kraner at gmx.ch writes:
Dear Sir/Madam:
Could you please help me with this exercise and how I could solve it in R?:
Attachment (PastedGraphic-1.pdf): application/pdf, 84 KiB
I especially have problems with the selection of the 40 datasets,
once taken the 110 (because
Copying David W from another thread:
We don't do homework here. In fact, your instructor is probably watching.
That said, try googling or, even better, using the rseek search. (Or even
better-er RSiteSearch() in your terminal)
Michael
On Nov 15, 2011, at 4:16 PM, Jan Kraner jan.kra...@gmx.ch
What exactly is it that's worrying you? It's a problematic regression
for a few reasons, but ultimately it seems pretty ok, though I'd be
ever so slightly worried about the R^2 value being misinterpreted.
Michael
On Mon, Nov 14, 2011 at 10:49 PM, Miles Yang miles2y...@gmail.com wrote:
Hi all,
I suspect you are lost. This is almost certainly more appropriate on
the BioConductor list. There are relatively few people on this list
who will know what (un-named) packages you might be using. Read the
Posting Guide, note the link to the Bioconductor mailing list page,
configure your
I am not going through all of your code to understand what you are trying to
demonstrate. R uses the IEEE Standard 754 for Floating Point Numbers. There
is a sign bit, 11 bits for the exponent, and 52 bits for the mantissa. Because
the standard normalizes the mantissa you get an extra bit of
Try
library(pracma)
? cross
Michael Weylandt
On Thu, Nov 3, 2011 at 1:17 AM, 阮铮 rz1...@foxmail.com wrote:
The function of crossprod in R puzzled me.
I would like to calculate the cross product of two vectors. According to my
text book, it defines like this:
a = (ax, ay, az)
b = (bx, by,
The crossprod function in base R implements the MATRIX cross product, more
familiarly known as matrix multiplication.
---
Jeff Newmiller The . . Go Live...
DCN:jdnew...@dcn.davis.ca.us Basics: ##.#. ##.#. Live Go...
On 04/11/11 11:30, Jeff Newmiller wrote:
The crossprod function in base R implements the MATRIX cross product, more familiarly
known as matrix multiplication.
The term crossprod is thereby rather misleading, nicht wahr?
Wouldn't it be *nice* to put into the help file a wee warning telling
21:24
An: Thorsten Vogel
Cc: r-help@r-project.org help
Betreff: Re: [R] Question on estimating standard errors with noisy signals
using the quantreg package
On Oct 31, 2011, at 7:30 AM, Thorsten Vogel wrote:
Dear all,
My question might be more of a statistics question than a question on R
On Oct 31, 2011, at 7:30 AM, Thorsten Vogel wrote:
Dear all,
My question might be more of a statistics question than a question on R,
although it's on how to apply the 'quantreg' package. Please accept my
apologies if you believe I am strongly misusing this list.
To be very brief, the
(1,3,4,9,1,9,1,5,4,5,2,1,1,1,6)
Any ideas how to solve this problem?
Cheers, S.B.
-Ursprüngliche Nachricht-
Von: David Winsemius [mailto:dwinsem...@comcast.net]
Gesendet: Donnerstag, 27. Oktober 2011 16:44
An: Duncan Murdoch
Cc: Samir Benzerfa; r-help@r-project.org
Betreff: Re: [R] question R regarding
-project.org
Subject: Re: [R] question R regarding consecutive numbers
In the general case, there is still a gap in your solution sum( tbl[1,
2:ncol(tbl)] ). This solution refers to a specific column number (here:
column number 2) and not to the actual length of the run, doesn't
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