On 19.01.2015 23:58, Glenda Palacios wrote:
I have any problems in R:
The downloaded binary packages are in
/var/folders/s9/kr21631n3nj30hb_4td3pv_8gn/T//RtmpDDAFmJ/downloaded_packages
Warning messages:
1: In download.file(url, destfile, method, mode = wb, ...) :
downloaded length
Hi
here are few points but no answer
Please
- do not use HTML post
- provide some example code and data (preferably by dput function) which
illustrate your point
- check your data by ?str if they really are what you think they are
- be more specific in your statements, we do not know what do
As David suggests, look at your data. For instance, there seems to be only 1
case (#2) for seat.width.club with non-zero data.
I find it hard to believe that the other planes have seat.widths of 0!
I think you probably want to code the 0s as missing, rather than 0.
You also want to rethink
On Jan 11, 2015, at 3:55 AM, 오건희 wrote:
Hi,
I tried to run principal function in the 'psych' package, but it failed
to do..
here is both my code and error message.
I searched on the web, but couldn't find the exact answer I wanted.
data-read.csv(
On 28/12/2014 11:12 AM, Iskender Karagul wrote:
Dear All,
I am a very fresh user of R platform. I completed the download of R for
Windows, from the http://cran.r-project.org/ Web address.
After opening the program I wanted to Go to Packages Tab and firstly Set
CRAN mirror and then
This is (mostly) normal. The R software comes with an initial set of packages
that are kept in the Program Files directory, which is only modifiable using
administrator privileges. If you are running your machine just for you (as most
people do) then I highly advise accepting the option during
On Wed, 17 Dec 2014, Francisco M. da Rocha wrote:
Hallo there,
I would like to work with CHAID, but the newest version of R does have
it. So I thought I could use an older version of R which accepts or has
the library CHAID. Could you tell me which version it is and where to
download it?
Hi,
Ignore the last email - R has plotted the number of data points (100) I
have and using that as a scale rather than the normalised data values
Sorry to be a pest!!
Julie
Julie Hope (NERC PhD Student)
Sediment Ecology Research Group, University of St Andrews
School of Geoscience, Bangor
Nia Gupta nia_gupta at yahoo.com writes:
Hello,
I have a column with a bunch of letters. I would like to keep some
of these letters (A,C,D,L) and turn the rest into 'X'.
I have tried using ifelse with '|' in between the argument but it
didn't work nor did 4 separate ifelse statements.
On 10/4/2014 8:21 AM, Nia Gupta wrote:
Hello,
I have a column with a bunch of letters. I would like to keep some of these
letters (A,C,D,L) and turn the rest into 'X'.
I have tried using ifelse with '|' in between the argument but it didn't work
nor did 4 separate ifelse statements.
You are only able to search twitter history for a short period of time.
gnip.com and similar companies offer historical tweets for sale.
cn
On Sunday, September 7, 2014 9:21:34 AM UTC-5, Axel Urbiz wrote:
Hello,
The function searchTwitter() with the arguments supplied as below would
Twitter tweets aren't a stable database. I wouldn't expect the search results
to stay stable, as tweets are retweeted, deleted, accounts are closed, privacy
settings adjusted, etc. And if there are more than 1000 results, I don't know
that twitter is internally ordered so you'd get the same
I'm no expert on hurdle models, but it seems that you are unaware that the
negative binomial and the truncated negative binomial are quite different
things.
-pd
On 29 Aug 2014, at 05:57 , Nick Livingston nlivings...@ymail.com wrote:
I have sought consultation online and in person, to no
On Fri, 29 Aug 2014, peter dalgaard wrote:
I'm no expert on hurdle models, but it seems that you are unaware that
the negative binomial and the truncated negative binomial are quite
different things.
Yes. You can replicate the truncated count part of the hurdle model with
the zerotrunc()
: [R] Question regarding the discrepancy between count model
parameter estimates between pscl and MASS
To: peter dalgaard pda...@gmail.com
Cc: Nick Livingston nlivings...@ymail.com, r-help@r-project.org
Date: Friday, August 29, 2014, 5:26 AM
On Fri, 29 Aug 2014,
peter dalgaard wrote:
I'm
...@uibk.ac.at wrote:
Subject: Re: [R] Question regarding the discrepancy between count model
parameter estimates between pscl and MASS
To: peter dalgaard pda...@gmail.com
Cc: Nick Livingston nlivings...@ymail.com, r-help@r-project.org
Date: Friday, August 29, 2014, 5:26 AM
On Fri, 29 Aug 2014
: just untick 'binary'.)
Thank you again. I appreciate your input.
-Nick
On Fri, 8/29/14, Achim Zeileis achim.zeil...@uibk.ac.at wrote:
Subject: Re: [R] Question regarding the discrepancy between count model parameter estimates
between pscl and MASS
Hi Farnoosh,
Regarding the first question:
dat2 - dat1
dat1$Mean - setNames(unsplit(sapply(split(dat1[,-1], dat1[,1]),rowMeans,
na.rm=T),dat1[,1]),NULL)
dat1
Unit q1 q2 q3 Mean
1 A 3 1 2 2.00
2 A 2 NA 1 1.50
3 B 2 2 4 2.67
4 B NA 2 5 3.50
5 C 3 2
I am sorry but I think I have been unclear. The problem is not color
theme. Assume I have the original data.frame.
testdf - structure(list(yy = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L), .Label = c(R, L), class = c(ordered,
factor)),
for certain ranges
Duncan
From: Sunny Srivastava [mailto:research.b...@gmail.com]
Sent: Monday, 7 July 2014 18:57
To: Duncan Mackay
Cc: R
Subject: Re: [R] Question regarding lattice::levelplot and distribution of
colors
I am sorry but I think I have been unclear. The problem is not color theme
On Jul 6, 2014, at 4:35 PM, Sunny Srivastava wrote:
Hello R-helpers:
I think there is some problem with my code, but I would like to seek you
help because I can't spot it.
I have a data.frame defined as follows:
testdf - structure(list(yy = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
Your y values are not of the type required by levelplot
? levelplot
I prefer not to use themes as they do not suit my data here is a way to get
what you want - colours are a bit garish but they are some easily to hand
breaks/cuts are just what came in a reasonable sequence - yours to change
Hello David:
Thanks for your response.
I am not sure, but isn't an ordered categorical variable integer for all
practical purposes? (R L)
Further, the problem persists if I change 'at' from seq(-0.3, 0.3, length =
20) to seq(-0.3, 0.3, length = 50; I think this argument is for the color
key
The column labeled Deviance pretty much _is_ the chi-square, specifically the
likelihood ratio test statistic, which has an asymptotic chi-square
distribution. (Using test=Rao gives you the alternative Rao efficient score
test, which in your case doesn't make much of a difference.)
Notice
On 14/06/2014 09:45, peter dalgaard wrote:
The column labeled Deviance pretty much _is_ the chi-square, specifically the
likelihood ratio test statistic, which has an asymptotic chi-square distribution. (Using
test=Rao gives you the alternative Rao efficient score test, which in your case
There are two kinds of set difference: the usual set difference
https://en.wikipedia.org/wiki/Set_difference#Relative_complement, also
called the asymmetric difference or relative complement, and the symmetric
difference https://en.wikipedia.org/wiki/Symmetric_difference.
In R, setdiff(a,b) is
About time for you to adjust your expectations... looks right to me from both a
mathematical sense and as the functions are designed.
---
Jeff NewmillerThe . . Go Live...
Hello,
From the help page: Performs *set* union, intersection, (asymmetric!)
difference, equality and membership on two vectors.
Hope this helps,
Pascal
On Mon, Jun 2, 2014 at 3:57 PM, Raphael Päbst raphael.pae...@gmail.com wrote:
Hello everyone, I have a question which is probably rooted in
Thanks everyone!
It is just as I expected, I just didn't understand how setdiff() works.
Raphael
On 6/2/14, Pascal Oettli kri...@ymail.com wrote:
Hello,
From the help page: Performs *set* union, intersection, (asymmetric!)
difference, equality and membership on two vectors.
Hope this
Hi,
Please check this link:
http://r.789695.n4.nabble.com/meaning-of-asymmetric-on-help-page-for-intersect-td877408.html
union(setdiff(v,w), setdiff(w,v))
#or in this case
setdiff(union(v,w),intersect(v,w))
#or
setdiff(c(v,w),c(v,w)[duplicated(c(v,w))])
A.K.
.pae...@gmail.com wrote:
Hello
Anna F...
on Thu, 1 May 2014 22:09:28 + writes:
Hi Martin,
I am a statistician at National Jewish Health in Colorado, and I have
been working on clustering a dataset using Ward's minimum variance. When
plotting the dendrogram, the y-axis is labeled as 'height'. Can you
Your command will generate 3 random values from gamma distributions,
the first will be from a gamma with shape a[1] and scale b[1], then
the 2nd will come from a gamma with shape a[2] and scale b[2] and the
3rd will have shape a[3] and scale b[3].
On Wed, Apr 30, 2014 at 3:00 PM, Stefano Sofia
The question has been answered here:
http://stackoverflow.com/questions/22892063/do-i-need-to-set-refit-false-when-testing-for-random-effects-in-lmer-models-wi
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
What I would do:
# read in your sample data
mbr - read.table( clipboard, header = TRUE, stringsAsFactors = FALSE )
# create a vector with the codes you want to consider
code.list - c(A,B,C,D,E)
# reduce the data accordingly
mbr - mbr[ mbr$code %in% code.list, ]
# get your model matrix using
Why do you need to use the get() command? If you want to access a
column of a known data frame by name:
R fakedata - data.frame(A=1:3, B=letters[8:10], C=runif(3))
R fakedata[A]
A
1 1
2 2
3 3
If you're trying to access a data frame by name, then you do need get,
but can then subset normally.
Hello Andy,
Do you already understand kde2d output?
if I run
max(tmp$z)
do I take the maximum value of the 2d density?
Cheers,
Peter
Em quinta-feira, 24 de novembro de 2011 16h12min19s UTC-2, Andreas Klein
escreveu:
Hello,
I am a little bit confused regarding the density values
Hello,
Inline.
Em 01-01-2014 22:12, Chee Chen escreveu:
Dear All,
I would like to ask for your help on reproducibility of random sampling with
replacement. For example, one re-samples the rows with replacement of a residual
matrix and uses the new residual matrix thus obtained to produce a
Why on earth would you expect S and T to be the same given
what you have done. I am unable to rightly apprehend the
confusion of ideas that could provoke such a question,
(Charles Babbage).
You have to set the *same* seed before each construction.
I.e. do set.seed(123) before creating S; then
If you want to reproduce the same sequence twice, then you need to set the seed
at the beginning of each calculation. You are only doing it for the second
calculation below.
---
Jeff NewmillerThe
You have to set the same seed before each random number generation!
You did not do this.
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
H. Gilbert Welch
On Wed, Jan 1, 2014 at 2:12
Hello,
Please read carefully the message. It says you three times that the
name is rJava, not rjava.
Regards,
Pascal
On 5 December 2013 13:19, tlw1987 [via R]
ml-node+s789695n4681662...@n4.nabble.com wrote:
Hello, everybody , recently , I want to install the package rjava in
windows 7 64bt.
On 02/12/2013 2:08 PM, Dan Abner wrote:
Hi all,
Can anyone explain what is happening with element 4,4 of c1? ifelse()
is not recongizing it as value 1:
FAQ 7.31.
Duncan Murdoch
c1
q1q2q3q4
q1 1.000 0.6668711 0.6948419 0.5758860
q2 0.6668711
What is the value of
diag(c1) - 1
?
(Or, use digits=16 when printing c1.)
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf
Of Dan Abner
Sent: Monday, December 02, 2013
If you are anything like me, then the main
thing that you could do to win the game is
to type the name of the file correctly.
Given that is a near impossibility for me,
when I'm on Windows I use 'file.choose' to
get the correct name. Your command would
look like:
On Nov 22, 2013, at 1:28 AM, Noor Aziani Bt Harun wrote:
Hi,
I'm going to run my thesis that use R language for Lee-Carter method but
some error occur when I'm running this code.
Please guide me Sir.
male.lca-lca(malaysia.male)
Error in pop * mx : non-numeric argument to binary
-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Carl Witthoft
Sent: Thursday, 21 November 2013 23:22
To: r-help@r-project.org
Subject: Re: [R] Question on xyplot
you didn't show us the code you used to generate the legend.
I'm guessing you want to add to the legend list
you didn't show us the code you used to generate the legend.
I'm guessing you want to add to the legend list something like lty=0:7 .
KB wrote
I recently started using R, so I'm not really experienced with it. My
question is on adjusting xyplots to get lty lines instead of coloured
lines.
I am baffled. Just what do you want it to do? In melted form the data are all
in one column and so are necessarily of one type... there are no mixed types to
cast.
As usual, assistance here will be more useful when you follow the Posting Guide
and post plain text only and give reproducible
Ok,many thanks for your detailed answer.
At 2013-09-18 19:20:26,Duncan Murdoch murdoch.dun...@gmail.com wrote:
On 13-09-18 1:38 AM, meng wrote:
Oh,yes, I found out this according to your reply.Thanks.
As to time series analysis, in order to show the effect of smoothing or
filtering,the
Oh,yes, I found out this according to your reply.Thanks.
As to time series analysis, in order to show the effect of smoothing or
filtering,the common command is:
plot(ts0);
lines(fitted(...))
But not lines(fitted(...) ~ time(ts) )
How to understand this then?
Many thanks.
Best.
At
On 13-09-18 1:38 AM, meng wrote:
Oh,yes, I found out this according to your reply.Thanks.
As to time series analysis, in order to show the effect of smoothing or
filtering,the common command is:
plot(ts0);
lines(fitted(...))
But not lines(fitted(...) ~ time(ts) )
How to understand this then?
Dear
meng,
Re:
Hi all:
I met a question about lines.
attach(cars)
plot(dist ~ speed)
#add the regression line to the plot
lines(fitted(lm(dist~speed)) ~ speed)
plot(dist ~ speed)
#what kind of curve does the following command add to the plot?
lines(fitted(lm(dist~speed)))
On 13-09-17 8:06 AM, meng wrote:
Hi all:
I met a question about lines.
attach(cars)
plot(dist ~ speed)
#add the regression line to the plot
lines(fitted(lm(dist~speed)) ~ speed)
plot(dist ~ speed)
#what kind of curve does the following command add to the plot?
lines(fitted(lm(dist~speed)))
Thanks for your reply.
Is fitted(lm(...)) the same as values of lines(values)?
If yes,then why the range of lines(values) is different from
range(fitted(lm(...)))?
If no, what values refers to?
At 2013-09-17 20:56:04,Duncan Murdoch murdoch.dun...@gmail.com wrote:
On 13-09-17 8:06 AM,
Thanks for your reply.
Yes, abline is much better,but it can only add straight line,and
lines(fitted(lm(y~x)) ~ x) can do the same thing but not constrain to straight
line.
At 2013-09-17 20:45:08,Bretschneider (R) brets...@xs4all.nl wrote:
Dear
meng,
Re:
Hi all:
I met a question
On 13-09-17 6:36 PM, meng wrote:
Thanks for your reply.
Is fitted(lm(...)) the same as values of lines(values)?
If yes,then why the range of lines(values) is different from
range(fitted(lm(...)))?
You are plotting against the wrong x axis, and you don't see all the values.
Duncan Murdoch
Euna Jeong eaje...@gmail.com writes:
I have questions about R2 used in pls (or multivariate analysis).
Is R2 same with the square of the PCC (Pearson Correlation Coefficient)?
If you read the manual for R2 in the pls package, it will tell you how
R2 is calculated there, and that for
Thank you David, it is a good resouce to find related subjects.
I need time to understand the topics.
Thank you again Bjørn-Helge for your response.
Euna
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
On Sep 4, 2013, at 10:39 PM, Euna Jeong wrote:
Hi,
I have questions about R2 used in pls (or multivariate analysis).
Is R2 same with the square of the PCC (Pearson Correlation
Coefficient)?
I found the following description from wiki (Coefficient of
determination)
Euna Jeong eaje...@gmail.com writes:
R plot(gas1, ncomp=2, asp = 1, line = TRUE)
This shows only the cross-validated predictions.
If you add the argument which = c(train, validation) (see
?predplot.mvr), you will get both. However, you will get them in
separate panels in the plot.
If you
Thank you very much!
On Tue, Sep 3, 2013 at 3:18 PM, Bjørn-Helge Mevik b.h.me...@usit.uio.nowrote:
Euna Jeong eaje...@gmail.com writes:
R plot(gas1, ncomp=2, asp = 1, line = TRUE)
This shows only the cross-validated predictions.
If you add the argument which = c(train, validation)
Your post is incomprehensible. Please do read the posting guide:
http://www.R-project.org/posting-guide.html
That said, this might help:
http://stats.stackexchange.com/questions/9099/how-to-perform-diallel-analysis-in-r
Kevin
On Sun, Aug 11, 2013 at 1:02 AM, waqas shafqat waqas1...@gmail.com
Hello,
First of all, do _not_ create a data frame with
as.data.frame(cbind(...))
Instead, use
z = data.frame(x, y)
As for your question, try the following.
library(reshape2)
fun - function(z){
zs - split(z, x)
n - length(zs)
m - nrow(zs[[1]])
zz - cbind(id =
8 c3
-Original Message-
From: Rui Barradas [mailto:ruipbarra...@sapo.pt]
Sent: Sunday, August 04, 2013 1:57 PM
To: Brijesh Gulati
Cc: r-help@r-project.org
Subject: Re: [R] question: data.frame data conversion
Hello,
First of all, do _not_ create a data frame with
as.data.frame(cbind
-Original Message-
From: arun [mailto:smartpink...@yahoo.com]
Sent: Sunday, August 04, 2013 1:30 PM
To: Brijesh Gulati
Cc: R help
Subject: Re: [R] question: data.frame data conversion
#actually, this would be more compact
data.frame(split(z[,-1],z$x))
A.K.
- Original Message -
From
#actually, this would be more compact
data.frame(split(z[,-1],z$x))
A.K.
- Original Message -
From: arun smartpink...@yahoo.com
To: Brijesh Gulati brij...@gmail.com
Cc: R help r-help@r-project.org
Sent: Sunday, August 4, 2013 1:27 PM
Subject: Re: [R] question: data.frame data conversion
Hi,
May be:
z-data.frame(x,y,stringsAsFactors=FALSE)
simplify2array(split(z[,-1],z$x))
# a b
#[1,] 1.0 1.01
#[2,] 1.2 1.03
#[3,] 1.1 1.00
as.data.frame(simplify2array(split(z[,-1],z$x)))
A.K.
- Original Message -
From: Brijesh Gulati brij...@gmail.com
To:
' smartpink...@yahoo.com
Cc: 'R help' r-help@r-project.org
Sent: Sunday, August 4, 2013 3:27 PM
Subject: RE: [R] question: data.frame data conversion
Wow... great and really compact solution. One follow-up question. How do I
solve the problem if the number of repeating values are different. For
instance
[mailto:ruipbarra...@sapo.pt]
Sent: Sunday, August 04, 2013 1:57 PM
To: Brijesh Gulati
Cc: r-help@r-project.org
Subject: Re: [R] question: data.frame data conversion
Hello,
First of all, do _not_ create a data frame with
as.data.frame(cbind(...))
Instead, use
z = data.frame(x, y)
As for your question
Sent: Sunday, August 4, 2013 3:47 PM
Subject: Re: [R] question: data.frame data conversion
Hello,
You're insisting in as.data.frame(cbind(...)). Don't do that. Just see
the difference:
z = data.frame(x, y)
str(z)
'data.frame': 8 obs. of 2 variables:
$ x: Factor w/ 3 levels a,b,c: 1 1 1 2 2
Hi,
dat-read.table(text=
1 0 1 1 1 1
0 0 1 0 0 1
1 0 0 0 0 0
2 1 1 2 1 1
,sep=,header=FALSE)
which(sapply(seq_len(nrow(dat)),function(i)
wilcox.test(unlist(dat[i,]))$p.value)0.05) #there will be warnings() though
#[1] 2 3
table(sapply(seq_len(nrow(dat)),function(i)
Hello Arnaud,
Thank you for your pointer. However I need to more clarification.
I want to control the max. and min. values for the x-axis, as well as
number of vertical gridlines to be displayed. I tried the following:
MyData - data.frame(Names1 = paste(XXX, 1:150), Values1 = 1:150 +
10,
Hi
You can do a rotation and use gvisColumnChart instead gvisBarChart
plot(gvisColumnChart(MyData, xvar=Names1, yvar=c(Values1,
Values2),options=list(width=2500,height=1000)))
Michel
Le 17/07/2013 15:57, Christofer Bogaso a écrit :
Hello Arnaud,
Thank you for your pointer. However I need to
Hi Arnaud,
Thanks for your answer.
However I prefer to have Horizontal bar chart, because length of the
strings for x-axis are quite large, therefore it would be better to
put them vertically one-below-another instead horizontally.
Therefore I would really appreciate if someone points me how to
You can try with list options :
plot(gvisBarChart(MyData, xvar=Names1, yvar=c(Values1, Values2),
options=list(width=1200,height=1500)))
Le 15/07/2013 20:00, Christofer Bogaso a écrit :
Hello again,
Let say I have following data-frame:
MyData - data.frame(Names1 = paste(XXX, 1:150), Values1
The HTKIdentify (requires tcltk package) and HWIdentify (windows only)
functions in the TeachingDemos package will show identifying information on
a plot for the point being hovered over. Both functions are pure R code,
so if they don't work for you as is you can modify the source to make
On 12-06-2013, at 04:53, Abdul Rahman bin Kassim (Dr.) rahm...@frim.gov.my
wrote:
Dear R-User,
Appreciate any helps. It looks simple, but I don't have a clue.
Given that I have a dataframe of tree population with three variables:
sp=species ,
d0=initial_size
grow=growth increment
This might supply a hint on what to look for.
https://stat.ethz.ch/pipermail/r-help/2009-July/204388.html
John Kane
Kingston ON Canada
-Original Message-
From: ecol...@hotmail.com
Sent: Fri, 31 May 2013 12:06:38 +
To: r-help@r-project.org
Subject: [R] question about trpaths
Check out the CRAN task view on Robust Statistical Methods:
http://cran.r-project.org/web/views/Robust.html
and on Multivariate Statistics:
http://cran.r-project.org/web/views/Multivariate.html
Regards,
Pascal
On 05/30/2013 05:07 PM, nafiseh hagiaghamohammadi wrote:
Hi
my data has four
Ye sorry
of course i'm interested to the area ranging from 0;0 to 0.4;0.8
thank you
Guido
2013/5/27 Uwe Ligges lig...@statistik.tu-dortmund.de
On 27.05.2013 16:18, Guido Leoni wrote:
Dear list
I'm testing a predictor and I produced nice performance plots with ROCR
package utilizing the 3
You can access the data directly by using something like perf@x.values[[1]].
Not sure if that helps you.
The package pROC allows you to do partial areas under the curve by
selecting a range of specificity or sensitivity that you're interested in.
On Tue, May 28, 2013 at 2:17 AM, Guido Leoni
On 27.05.2013 16:18, Guido Leoni wrote:
Dear list
I'm testing a predictor and I produced nice performance plots with ROCR
package utilizing the 3 standard command
pred - prediction(predictions, labels)
perf - performance(pred, measure = tpr, x.measure = fpr)
plot(perf, col=rainbow(10))
The
HI,
directory- /home/arunksa111/NewData
GetFileList - function(directory,number){
setwd(directory)
filelist1-dir()[file.info(dir())$isdir]
direct-dir(directory,pattern = paste(MSMS_,number,PepInfo.txt,sep=),
full.names = FALSE, recursive = TRUE)
direct-lapply(direct,function(x)
On Tue, 14 May 2013, meng wrote:
Many thanks.
Another question:
model- glm(count ~ drug*result, family = poisson)
anova(model,test=Chisq)
Df Deviance Resid. Df Resid. Dev Pr(Chi)
NULL 3 47.522
drug 1 0.032 2
Many thanks.
Another question:
model- glm(count ~ drug*result, family = poisson)
anova(model,test=Chisq)
Df Deviance Resid. Df Resid. Dev Pr(Chi)
NULL3 47.522
drug 10.032 2 47.491 0.85858
result 1
On Mon, 13 May 2013, meng wrote:
Hi all:
I have a question about poisson regression.
My data:
drug result count
1 1 8
1 254
2 1 20
2 2 44
My model:
model- glm(count ~ drug*result, family = poisson)
My result:
summary(model)
Coefficients:
On May 11, 2013, at 06:10 , meng wrote:
Hi all:
I have a question about one-way anova.
The data is ¡°sleep¡±which belongs to R.
code1:
summary(lm(extra~group))
Estimate of group2(1.58) is the difference between mean of group1 and
group2,and t value(1.861) and p
The apply() function works on an array or a matrix. There is no need to
guess, just read the manual page:
? apply
So including a character variable forces the entire matrix to characters.
Excluding character variables will let you operate on the numeric values,
but your code suggests you are
On May 9, 2013, at 8:50 AM, Pooya Lalehzari wrote:
Hello,
When I use apply on a data frame, it seems like I get an error when I have
a column that is not numeric. Via trial and error I realized that if I remove
that column, I can get it to run. Is there a better way to tell the function
On 04/30/2013 11:38 AM, Sean Doyle wrote:
Hello, I'm a first semester statistics
studenthttp://r.789695.n4.nabble.com/Question-regarding-error-quot-x-and-y-lengths-differ-quot-td4665773.html#and
I am using R for roughly the third time ever. I am following a
tutorial
and yet I still get the error
On Tue, Apr 23, 2013 at 2:54 PM, nafiseh hagiaghamohammadi
n_hajiaghamohammadi2...@yahoo.com wrote:
Hi
I fit one linear quantile regression with package quantreg and I want to
khow this model is good or not.Is there method for checking it?
Thanks your advice
I ask this question because
good usually means good relative to something else, in this case the comparison
seems, as Michael
has already said, f0 - rq(y ~ 1, tau = ?) and then one can compute the R1
version that I originally
suggested. But since there is still no explicit way to evaluate this, it is
all a bit pointless.
On Tue, Apr 23, 2013 at 2:54 PM, nafiseh hagiaghamohammadi
n_hajiaghamohammadi2...@yahoo.com wrote:
Hi
I fit one linear quantile regression with package quantreg and I want to
khow this model is good or not.Is there method for checking it?
Thanks your advice
How is this different than the
In quantreg if you do
FAQ()
item 4 is:
4. [R^2] I am currently trying to caculate the coefficient of determination
for
different quantile regression models. For example, how do you calculate
the the sum of the weighted absolute deviations in the models ...
R-squared is evil,
Hi,
Thanks for taking the time. Here is a more reproducible example of the
entire process:
# Creating a vector source - stupid text in the Bulgarian language
bg-c('Днес е хубав и слънчев ден, в който всички искат да бъдат
навън.','Утре ще бъде още по-хубав ден.')
# Converting strings from
Le mercredi 10 avril 2013 à 10:50 +0300, Ventseslav Kozarev, MPP a
écrit :
Hi,
Thanks for taking the time. Here is a more reproducible example of the
entire process:
# Creating a vector source - stupid text in the Bulgarian language
bg-c('Днес е хубав и слънчев ден, в който всички искат
Thank you so much! You made it look (almost) so easy. I greatly
appreciate it!
On 10.4.2013 г. 11:29 ч., Milan Bouchet-Valat wrote:
Le mercredi 10 avril 2013 à 10:50 +0300, Ventseslav Kozarev, MPP a
écrit :
Hi,
Thanks for taking the time. Here is a more reproducible example of the
entire
Le mercredi 10 avril 2013 à 13:17 +0200, Ingo Feinerer a écrit :
On Wed, Apr 10, 2013 at 10:29:27AM +0200, Milan Bouchet-Valat wrote:
Thanks for the reproducible example. Indeed, it does not work here
either (Linux with UTF-8 locale). The problem seems to be in the call to
gsub() in
I just wanted to confirm that Milan's suggestion about adding (*UCP) like in
the example below:
gsub(sprintf((*UCP)\\b(%s)\\b, който), , който, perl=TRUE)
solved all problems (under openSuse Linux 12.3 64-bit, R 2.15.2). I reencoded
input files and stop word list in UTF-8, and now stop words
I just wanted to confirm that Milan's suggestion about adding (*UCP) like in
the example below:
gsub(sprintf((*UCP)\\b(%s)\\b, който), , който, perl=TRUE)
solved all problems (under openSuse Linux 12.3 64-bit, R 2.15.2). I reencoded
input files and stop word list in UTF-8, and now stop words
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