This is as much a mathematics as an R question, in the this should be easy but I don't
see it category.
Assume I have a full rank p by p matrix V (aside: V = (X'X)^{-1} for a particular setup),
a p by k matrix B, and I want to complete an orthagonal basis for the space with distance
function
Dear list,
I've been looking at previous posts on the list, but I haven't found any
close enough to my question/problem.
My data can be seen as a matrix of mutiple individuals (columns) with
(rather independent) measures (lines). Now based on supplemental
information, the individuals are organized
Here is one improvement. Avoid dataframes in some of these cases. This
create a character matrix and then converts to a dataframe after doing the
transpose of the matrix. This just takes less than 10 seconds on my system:
library(stringr)
# create character matrix; avoid dataframes in
Say I have a list:
[[1]] I like google
[[2]] Hi Google google
[[3]] what's up
and they are tweets. And I want to find out how many tweets mention google
(the answer should be 2).
If I string split and unlist them, then I would get the answer of 3. How do
I make sure I get just 2?
--
View
Actually looking at the result, you don't need the transpose; that was an
artifact of how you were doing it before.
xm - do.call(rbind, str_split(string = AllpairsTmp, pattern = -))
# convert to dataframe and do transpose on matrix and not dataframe
separoPairs - as.data.frame((xm),
Hi Terry,
maybe I'm missing something, but why not define a matrix BB = V'B;
then t(B) %*% V = t(BB), then your problem reduces to finding A such
that t(BB) %*% A = 0?
Peter
On Thu, Jul 16, 2015 at 10:28 AM, Therneau, Terry M., Ph.D.
thern...@mayo.edu wrote:
This is as much a mathematics as an
On Jul 16, 2015, at 12:40 PM, tryingtolearn inshi...@ymail.com wrote:
Say I have a list:
[[1]] I like google
[[2]] Hi Google google
[[3]] what's up
and they are tweets. And I want to find out how many tweets mention google
(the answer should be 2).
If I string split and unlist
Why would you strsplit them? I would think
length(grep(google, unlist(x), ignore.case = TRUE))
should do it.
Best,
Ista
On Thu, Jul 16, 2015 at 1:40 PM, tryingtolearn inshi...@ymail.com wrote:
Say I have a list:
[[1]] I like google
[[2]] Hi Google google
[[3]] what's up
and they are
On Thu, Jul 16, 2015 at 12:40 PM, tryingtolearn inshi...@ymail.com wrote:
Say I have a list:
[[1]] I like google
[[2]] Hi Google google
[[3]] what's up
and they are tweets. And I want to find out how many tweets mention google
(the answer should be 2).
If I string split and unlist them,
This might do what you want:
OPoly - function(x, degree=1, weight=1, coefs=NULL, rangeX=NULL){
weight - round(weight,0)# weight need to be integer
if(length(weight)!=length(x)) {
weight - rep(1,length(x))
}
if (is.null(rangeX)) {
rangeX - range(x)
}
p -
I suggest you consult a local statistician. You are (way) over your
head statistically here, and statistical matters are off topic on
this list. The brief answer to your question is: you are almost
certainly producing nonsense.
Cheers,
Bert
Bert Gunter
Data is not information. Information is
Dear Brittany,
On Thu, 16 Jul 2015 17:35:38 -0600
Brittany Demmitt demmi...@gmail.com wrote:
Hello,
I have a series of 40 variables that I am trying to transform via the boxcox
method using the powerTransfrom function in R. I have no zero values in any
of my variables. When I run the
Dear useRs,
I am running a wilcox.test() on two subsets of a dataset and get exactly
the same results although the raw data are different in the subsets.
mydata - structure(list(cat1 = structure(c(2L, 2L, 2L, 2L, 2L, 2L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L), .Label = c(high, low),
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
and http://adv-r.had.co.nz/Reproducibility.html
Currently we don't even know what version of Cronbach's alpha you are using.
Also use google as well as help()
Try R statistics Cronbach's alpha
John Kane
Hi Collin,
The objective of the gen.names function is to generate N *unique *random
names, where N is a *large *number. In my computer `gen.names(n = 5)`
takes under a second, so is probably not the root problem in my code. That
said, I would love to improve it. I'm not exactly sure how you
the first error message is
configuration failed for package RCurl
immediately before that it said
Cannot find curl-config.
It would appear that you don't have curl installed on your computer.
Unfortunately, I cannot help you with that. But you might look at the
documentation for RCurl
On 16 Jul 2015, at 15:13 , Ivan Calandra ivan.calan...@univ-reims.fr wrote:
Dear useRs,
I am running a wilcox.test() on two subsets of a dataset and get exactly the
same results although the raw data are different in the subsets.
mydata - structure(list(cat1 = structure(c(2L, 2L, 2L,
I am trying to analyse time-series .netcdf (3D lat,long and time domain)
climate data. I want to apply the SPEI package (calculation of standardized
precipitation evapotranspiration index) on it. But unable to arrange my data
in the required data frame. As I am a beginner in R, it will be very
Hello,
I try to install a course for swirl and got a SSL problem:
install_from_swirl(R Programming)
Error in function (type, msg, asError = TRUE) :
SSL certificate problem: self signed certificate in certificate chain
Found this answer with Google but does not work either:
set_config(
The list rejects almost all attachments.
You could dput the data and put it in your posting.
You may also want to try a Marquardt solver. In R from my nlmrt or
compiled in Kate Mullen's minpack.lm. They are slightly different in
flavour and the call is a bit different from nls.
JN
On 15-07-16
---The las post rejected two files I had attached, so I modified
it.---
Hi. I am trying to make a nls fit for a little bit complicated expression that
includes two integrals with two of the fit parameters in their upper limits.
I got the error Error in nlsModel(formula, mf,
Is there an R package that allows one to calculate skewness and
curtosis - but weighted with individual level weights (one weight per
observation)?
Thank you!
--
Dimitri Liakhovitski
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more,
I have ma matrix which its elements are NA,0,1,2 ! I got my answer bout
removing the columns with 0 or NA or both values but now I want to add
additional condition for deleting the columns! I have to delete the columns
which contain the same value. delete the columns with NA or 0 or both and
the
On 16/07/2015 3:08 AM, MH wrote:
Hello,
I try to install a course for swirl and got a SSL problem:
install_from_swirl(R Programming)
Error in function (type, msg, asError = TRUE) :
SSL certificate problem: self signed certificate in certificate chain
Found this answer with Google
Unfortunately not - more like 0.7654, 1.2345.
I understand that I could multiply each number by 100, round it to no
decimal point and then unroll my data in proportion.
I was just hoping someone has done it in C and put it into a package...
On Thu, Jul 16, 2015 at 11:27 AM, David Winsemius
rep() **does** do it essentially in C !!
See also the moments package, which I found instantly by googling
sample moments in R, though I don't know whether it does what you
want (but probably shouldn't do).
Of course, sample skewness and kurtosis are basically useless, but
that's another, off
On Jul 16, 2015, at 8:10 AM, Dimitri Liakhovitski wrote:
Is there an R package that allows one to calculate skewness and
curtosis - but weighted with individual level weights (one weight per
observation)?
Integer weights?
--
David Winsemius
Alameda, CA, USA
Hello,
I have been running a nonlinear GMM using the nloptr wrapper since the last 7
days. The maximum time I have to run the code on the server that I am using to
run this code is 7 days which expires in about an hour when the server
automatically terminates it. I will like to know if there is
David:
I think you missed my point. As I understand him, Dmitri mentioned
rounding off to e.g. 2 decimal digits and multiplying by 100 to
produce integer weights, which would then lead to unrolling the
vector via rep(). Your weighted moments reference is probably
closer to what he sought,
1. I have no idea.
2. However, I doubt that your strategy would work anyway. If there is
not an outright error, you are probably stuck in some endless loop or
are wandering around at random on an essentially flat hypersurface.
You would need to change convergence criteria or change the
-Original Message-
I compute its regression surface doing polynomical regression (fit)
...
fit - lm(z ~ poly(x,2) + poly(y,2))
.
So I want to repressent the surface
How could I do it? Any idea??
You need to write a function f of x and y that produces the fitted
Thank you!
On Thu, Jul 16, 2015 at 11:45 AM, Bert Gunter bgunter.4...@gmail.com wrote:
rep() **does** do it essentially in C !!
See also the moments package, which I found instantly by googling
sample moments in R, though I don't know whether it does what you
want (but probably shouldn't
On Jul 16, 2015, at 8:37 AM, Dimitri Liakhovitski wrote:
Unfortunately not - more like 0.7654, 1.2345.
I understand that I could multiply each number by 100, round it to no
decimal point and then unroll my data in proportion.
I was just hoping someone has done it in C and put it into a
Yes it is obvious --- once someone else pointed it out.
Thanks for the hint.
Terry T.
On 07/16/2015 12:52 PM, Peter Langfelder wrote:
Hi Terry,
maybe I'm missing something, but why not define a matrix BB = V'B;
then t(B) %*% V = t(BB), then your problem reduces to finding A such
that t(BB)
Read about the 'makepredictcall' generic function. There is a method,
makepredictcall.poly(), for poly() that attaches the polynomial coefficients
used during the fitting procedure to the call to poly() that predict()
makes.
You ought to supply a similar method for your xpoly(), and xpoly() needs
Hello, I have a question about the formula and the user defined function:
I can do following:
###Case 1:
clotting - data.frame(
+ u = c(5,10,15,20,30,40,60,80,100),
+ lot1 = c(118,58,42,35,27,25,21,19,18),
+ lot2 = c(69,35,26,21,18,16,13,12,12))
g1=glm(lot1 ~ log(u) + poly(u,1),
I am developing a marketing (Churn) model that has an event rate of 0.5%. So i
thought to perform oversampling. I mean making the number of events equal to
number of non-events by reducing non-events (50-50 after sampling). After
oversampling, we need to adjust predicted probabilities as it
On Thu, Jul 16, 2015 at 1:00 PM, John McKown john.archie.mck...@gmail.com
wrote:
On Thu, Jul 16, 2015 at 12:40 PM, tryingtolearn inshi...@ymail.com
wrote:
Say I have a list:
[[1]] I like google
[[2]] Hi Google google
[[3]] what's up
and they are tweets. And I want to find out how many
Thank Jim!
This makes a huge difference. Can you explain why are data frame slower
than a matrix? Any other suggestions on how to improve the code would be
greatly appreciated.
Thanks again!
Ignacio
On Thu, Jul 16, 2015 at 1:42 PM jim holtman jholt...@gmail.com wrote:
Actually looking at the
Hi
your example is not reproducible. With ordinal regression the type of the y
values is important
sometimes an ordered factor is required.
Ordinal regression depends on your hypothesis see Ananth and Kleinbaum 1997
functions/packages to look at apart from ordinal
VGAM
polr::MASS
On 17/07/15 03:45, Bert Gunter wrote:
SNIP
Of course, sample skewness and kurtosis are basically useless, but
that's another, off topic, issue.
Fortune nomination!
cheers,
Rolf
--
Technical Editor ANZJS
Department of Statistics
University of Auckland
Phone: +64-9-373-7599 ext. 88276
Hello,
I have a series of 40 variables that I am trying to transform via the boxcox
method using the powerTransfrom function in R. I have no zero values in any of
my variables. When I run the powerTransform function on the full data set I
get the following warning.
Warning message:
In
OPoly-function(x,degree=1,weight=1){
weight=round(weight,0)# weight need to be integer
if(length(weight)!=length(x))weight=rep(1,length(x))
p=poly(4*(rep(x,weight)-mean(range(x)))/diff(range(x)),degree)
Z-(t(t(p[cumsum(weight),])*sqrt(attr(p,coefs)$norm2[-
seq(2)]))[,degree])
Estas comparando listas, prueba más bien
a[,yld:=mapply(setequal,y,z)]
Un saludo. Olivier
- Mensaje original -
De: Patricio Fuenmayor Viteri patricio.fuenma...@outlook.com
Para: r-help-es r-help-es@r-project.org
Enviados: Jueves, 16 de Julio 2015 2:48:35
Asunto: [R-es] Operaciones
Hola:
He probado otra solución: con defmacro del paquete gtools:
=
DATOS - data.frame(SE=c(M, H, M, M, H),
ED=c(50, 60, 20, 18, 30),
GRP=c(B, B, A, A, B))
library(gtools)
MRL - defmacro(XDADES, XVD, XVI,
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