Hi,
I am trying to print several dataset in several different sheets of the
same xlsx file.
I sometimes run the codes more than once, and I need to erase all things in
the target file, and I do not use "append" in the first function call.
However I want to write it in a loop. Is there a way to
Can you use subset?
subset(d, b == 4 & c == 10)
Best
Ulrik
On Tue, 3 May 2016 04:58 jpm miao, wrote:
> Is it possible? I am expecting the result to be the second row of the data
> frame ...
>
>
> d<-data.frame(a=1:3, b=3:5,c=9:11)
> > d
> a b c
> 1 1 3 9
> 2 2 4 10
> 3
Is it possible? I am expecting the result to be the second row of the data
frame ...
d<-data.frame(a=1:3, b=3:5,c=9:11)
> d
a b c
1 1 3 9
2 2 4 10
3 3 5 11
> d[identical(d[c("b","c")],c(4,10)),]
[1] a b c
<0 rows> (or 0-length row.names)
[[alternative HTML version deleted]]
Hi,
On Mon, May 2, 2016 at 8:36 AM, Kushank Chhabra
wrote:
> Hi,
>
>
>
> I am trying to plot a network diagram of around 1500 component (as nodes)
> and many connections (as edges) within them.
> I tried igraph package, however unable to create a layout where
Sorry for the missed braces earlier. I was typing on a phone, not the best
place to conjugate regular expressions.
Using the example you provided:
> df=data.frame(Command=c("_localize_PD", "_localize_tre_t2",
"_abdomen_t1_seq", "knee_pd_t1_localize", "pd_local_abdomen_t2"))
>
Hi,
I am trying to plot a network diagram of around 1500 component (as nodes)
and many connections (as edges) within them.
I tried igraph package, however unable to create a layout where there is no
overlap of nodes or edges.
More or less tried all the things mentioned in this link -
You may look at:
http://rseek.org/?q=community%20detection
--
Best,
GG
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
Don't know if this would help, but you could always set an attribute
of alphatab to be the dimnames. See ?attrib . Of course you would then
have to write a custom print() function, possibly along the lines you
indicated.
You could also do this via S3 (or whatever) classes, of course. But
again,
Hello Lara,
I recently installed a number of packages through compiling. After
downloading the package using 'wget', running R CMD INSTALL package.tar.gz
should work.
Sincerely,
Shouro
On Mon, May 2, 2016 at 5:17 PM, Lars Bishop wrote:
> Thanks Jim. I don't think that is
Hi
I am very new to R studio and R language. I have installed the R studio in
my machine.
I need to do a community detection of a set of message. I have a Matrix for
that.
Is there any sample code /Package/ website is present which will help me to
understand/do this community Detection (like
Thanks Peter, you were right, the exact grepl is
grepl("(.*t2.*pd.*)|(.*pd.*t2.*)",df$Command), but it does not change anything
in Command, when I check the size of it by
sum(grepl("(.*t2.*pd.*)|(.*pd.*t2.*)",df$Command)) the result is 0, but I am
sure that the size is not 0. It seems that
Thanks Jim. I don't think that is the issue...if anyone else can shed some
light here, that would be much appreciated.
Regards
Lars.
On Saturday, 30 April 2016, Jim Lemon wrote:
> Hi Lars,
> A mystery, but for the bodgy characters in your error message. Perhaps
> there is
The first thing I notice here is that your first two subset statements are
searching in an object named Command, not the column df$Command. I'm not at
all sure what you are trying to achieve with the str_extract process but it
is looking for the exact string 'PDT2' the vectors / dataframe formed
Yes it works, but let me explain what I am going to do. I extract all the names
I want and then create a new column out of them for my plot. This is he whole
thing I do:
PD=subset(df,grepl("pd",Command)) //extract names in Command with only "pd"
t2=subset(df,grepl("t2",Command)) //extract
Thanks, John.
The trouble with that solution is that it gives the index for where the
cursor was before clicking rather than the cell that was clicked. The
solution is that the binding gives the x, y pixel coordinates of
the click to the callback, and the pixel coordinates can be translated to
Dear R users,
I am trying to generate a 3D plot using the wireframe() function in the lattice
package.
The corresponding formula in Excel looks as follows and is applied to the
wireframe() function:
MIN(psi/K14,EXP(((ABS(H14)/peak)^omega)*LN(psi/K14)))
I tried to "translate" this formula in
Hi,
Could someone suggest a way to rename a data frame column? For example,
I want to rename the column beta, but I can't do it this way
> d <- data.frame(alpha=1:3, beta=4:6, gamma=7:9)
> mm<-"beta"
> rename(d, c(mm="two", "gamma"="three"))
The following `from` values were not present in
Dear all,I am trying to write in my Figure labels short equations that contain
greek characters
For example: C(h) = sigma^2 * rho(h).
I am googling it and there are many packages available but unfortunately they
do not look available for my 3.2.4 latex version
> Alaios via R-help
> on Mon, 2 May 2016 17:32:34 + writes:
> Dear all,I am trying to write in my Figure labels short equations that
contain greek characters
> For example: C(h) = sigma^2 * rho(h).
> I am googling it and there are many
You need to learn about proper subsetting, and the names() function. Consider
the following:
R > d <- data.frame(alpha=1:3, beta=4:6, gamma=7:9)
R > d
alpha beta gamma
1 14 7
2 25 8
3 36 9
R > names(d)
[1] "alpha" "beta" "gamma"
R > names(d) == "beta"
[1]
I just changed all the names in Command to lowercase, then this str_extract
works fine for "pd" and "t2", but not for "PDT2". Do you have any idea how I
can bring PDT2 also in str_extract?
On Monday, May 2, 2016 9:16 AM, Tom Wright wrote:
The first thing I notice here
> Bert Gunter
> on Mon, 2 May 2016 06:20:52 -0700 writes:
> Martin et. al.:
> na.omit(frame) will remove all rows/cases in which an NA occurs. I'm
> not sure that this is what the OP wanted, which seemed to be to
> separately remove NA's from
Dear R users,
I am trying to backtest VaR using the rugarch package. My code looks as follows
VaRTest(alpha=0.025,Backtesting_BuVaR$Log.return,Backtesting_BuVaR$VaR,conf.level
= 0.975)
R returns following output. I don't understand why I get NAs except for the
critical values.
Does anyone have
Or you dplyr
library(dplyr)
d <- data.frame(alpha=1:3, beta=4:6, gamma=7:9)
mm <- "beta"
rename_(d, "two" = mm, "three" = "gamma")
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie & Kwaliteitszorg / team Biometrics & Quality
On Mon, May 2, 2016 at 1:01 PM, ch.elahe via R-help
wrote:
> I just changed all the names in Command to lowercase, then this
> str_extract works fine for "pd" and "t2", but not for "PDT2". Do you have
> any idea how I can bring PDT2 also in str_extract?
>
Looking at
> On May 2, 2016, at 10:32 AM, Alaios via R-help wrote:
>
> Dear all,I am trying to write in my Figure labels short equations that
> contain greek characters
>
> For example: C(h) = sigma^2 * rho(h).
>
> I am googling it and there are many packages available but
Please try to read my earlier comments.
In the absence of a proper example with expected output I think what you
are trying to achieve is:
# create a sample dataframe
df <- data.frame(Command=c("_localize_PD", "_localize_tre_t2",
"_abdomen_t1_seq", "knee_pd_t1_localize", "pd_local_abdomen_t2"))
For starters, use 'pmin' (parallel min) instead of 'min'.
substitute(MIN(psi/K14,EXP(((ABS(H14)/peak)^omega)*LN(psi/K14))),
list(MIN=quote(pmin), K14=quote(VaR), ABS=quote(abs),
EXP=quote(exp), LN=quote(log), H14=quote(Bmax),
omega=quote(w2)))
# pmin(psi/VaR,
Hi
You can use rbind, cbind but you need to be aware of what objects you are
binding together.
mm<-matrix(rnorm(12), 3,4)
> rbind(mm[1:2,], 1:4, mm[3,])
[,1] [,2] [,3] [,4]
[1,] -0.2029407 -1.5910628 -0.2582281 -0.1649921
[2,] -0.6913951 0.3591561 0.8236836
> Mike Smith
> on Sun, 1 May 2016 08:15:44 +0100 writes:
On Apr 30, 2016, at 12:58 PM, Mike Smith
wrote: Hi
First post and a relative R newbie
I am using the vioplot library to produce some violin
Can anyone tell me how to retrieve the response (dependent) variable
from a probit regression object (as much as model.matrix(obj)
retrieves the data matrix). Below is a self-runnable set of codes.
Thank you!
library(sampleSelection)
Using geom_errorbarh with ggplot, my plot has several error bars. For my
presentation, the order of these bars from top to bottom is important.
But errorbarh seems to put these in a random order I can't change. ( It
does not follow the order in the data.frame. )How can I specify the
order
Hi guys,
If I am applying ctree() on a data (specifying some control parameters like
maxdepth), is there a way I can programmatically access the (smaller)
datasets corresponding to the terminal nodes in the tree? Say, if there are
7 terminal nodes, I need those 7 datasets (of course, I can look
On Mon, 2 May 2016, Preetam Pal wrote:
Hi guys,
If I am applying ctree() on a data (specifying some control parameters like
maxdepth), is there a way I can programmatically access the (smaller)
datasets corresponding to the terminal nodes in the tree? Say, if there are
7 terminal nodes, I need
Again, really appreciate your help on this. Thanks, Achim.
-Preetam
On Tue, May 3, 2016 at 3:22 AM, Achim Zeileis
wrote:
> On Mon, 2 May 2016, Preetam Pal wrote:
>
> Great, thank you so much Achim.But one issue, in case I do not know how
>> many
>> terminal nodes would
What nonsense. There is a group of finger-waggers on this list who jump on
every poster who uses the name of an R function as a variable name. R is
perfectly capable of distinguishing the two, so if 'c' (or 'data' or 'df',
etc.) is the natural name for a variable then go ahead and use it.
Great, thank you so much Achim.
But one issue, in case I do not know how many terminal nodes would be
there, what do I do? Note that I do not need the datasets corresponding to
the intermediate nodes only need the terminal datasets.
Regards,
Preetam
On Tue, May 3, 2016 at 3:08 AM, Achim Zeileis
On Mon, 2 May 2016, Preetam Pal wrote:
Great, thank you so much Achim.But one issue, in case I do not know how many
terminal nodes would be there, what do I do? Note that I do not need the
datasets corresponding to the intermediate nodes only need the terminal
datasets.
With predict(ct, type
On 02 May 2016, at 12:43 , ch.elahe via R-help wrote:
> Thanks for your reply tom. After using
> Subset(df,grepl("(.*t2.*pd.*)|(.*pd.*t2.*)"),df$Command) I get this error:
> Argument "x" is missing, with no default. Actually I don't know how to fix
> this. Do you have
Martin et. al.:
na.omit(frame) will remove all rows/cases in which an NA occurs. I'm
not sure that this is what the OP wanted, which seemed to be to
separately remove NA's from each column and plot the resulting column.
This is what the lapply (and the OP's provided code) does, anyway.
Also,
Hi,
I am writing a Java GUI application which uses Rserve(). I have a java script
which sends a command to the shell to start Rserve(). When I run the Java main
method for the very first time, it calls this script to invoke Rserve() and
starts Rserve(). But, in this first run the Java GUI
As pointed out somewhere in the replies to this you can always use the
exists() function.
for(i in 1:5){
if(exists(output)){
output <- c(output, i )
}else{
output <- i
}
}
On Wed, Apr 27, 2016, 11:15 AM Gordon, Fabiana <
fabiana.gor...@imperial.ac.uk> wrote:
> Hello,
>
You are quite wrong. This is not "nonsense"; it is sound advice. It is
true that R is capable of distinguishing between a function and a
non-function object with the same name. However there are many
circumstances in which using a function's name for the name of a data
object will lead
Hi jpm miao,
After a fair stretch of fooling around with it, I can't see any way to
add the variable names ("varnames") to the output of delim.table
without breaking it for things other than table objects. You can
probably do this as a one-off hack by setting the names of the
dimnames of the
Thanks for your reply tom. After using
Subset(df,grepl("(.*t2.*pd.*)|(.*pd.*t2.*)"),df$Command) I get this error:
Argument "x" is missing, with no default. Actually I don't know how to fix
this. Do you have any idea?
Thanks,
Elahe
On Saturday, April 30, 2016 7:35 PM, Tom Wright
On Mon, 2 May 2016, Steven Yen wrote:
Can anyone tell me how to retrieve the response (dependent) variable
from a probit regression object (as much as model.matrix(obj)
retrieves the data matrix). Below is a self-runnable set of codes.
Thank you!
library(sampleSelection)
Ordering of any discrete values in ggplot goes according to the levels of the
factor. As a convenience, ggplot will convert character values into factor for
you according to the default order alphabetical). To take control of this you
have to convert your discrete columns to factors yourself
Carlos:
Muchísimas gracias nuevamente, en mi anterior había dicho que te
comentaría, y, ahora lo hago.
Quería 'comerme el pastel con una mordida', era necesario tomar un vector y
'exprimirlo' quedando finalmente así:
library(ggplot2)
ogl <- read.csv('T06.csv')
re <- ogl[ogl[,3] <= 9,]#
48 matches
Mail list logo