I wrote a function and I hope this helps
b-c(1,2,3,4);lambda-c(0.3,0.4,0.5,0.6)
m-c(0.10,0.11,0.12,0.13);t-c(7,8,9,10)
N=4
Y-matrix(data=NA,nrow=4, ncol=1)
for (i in 1:N){
y=b*(1-exp(lambda*(t^m)))
Y-matrix(data=y, nrow=4, ncol=1)
Y-as.numeric(Y)
sim-data.frame(t,
keunhchoi at gmail.com writes:
I saw a similar question but I still don't fully understand how to implement
optim.
vol-rep(c(0.03, 0.5, 2, 4, 8, 16, 32), 3)
time-rep(c(2,4,8),each=7)
p.mated-c(0.47, 0.48, 0.43, 0.43, 0.26, 0.23, null, 0.68, 0.62, 0.64,
0.58, 0.53, 0.47,
+ 0.24,
On Sun, Jun 1, 2008 at 8:47 AM, Gabor Grothendieck
[EMAIL PROTECTED] wrote:
On Sun, Jun 1, 2008 at 8:35 AM, Megh Dal [EMAIL PROTECTED] wrote:
Hi all,
I have following monthly time series :
head(data1)
V1 V2 V3
1 Nov-80 NA 1007.44
2 Dec-80 NA 982.05
3 Jan-81 NA 994.25
4
Hi all,
I have following monthly time series :
head(data1)
V1 V2 V3
1 Nov-80 NA 1007.44
2 Dec-80 NA 982.05
3 Jan-81 NA 994.25
4 Feb-81 NA 996.31
5 Mar-81 NA 939.91
6 Apr-81 NA 923.32
Now I want to convert it to a 'zoo' object. I wrote following syntax :
ss = zoo(data1[,3],
On Sun, Jun 1, 2008 at 8:35 AM, Megh Dal [EMAIL PROTECTED] wrote:
Hi all,
I have following monthly time series :
head(data1)
V1 V2 V3
1 Nov-80 NA 1007.44
2 Dec-80 NA 982.05
3 Jan-81 NA 994.25
4 Feb-81 NA 996.31
5 Mar-81 NA 939.91
6 Apr-81 NA 923.32
If the suggestion
I got following:
z - zoo(data1[,3], as.yearmon(data1[,1], %b-%y))
head(z)
Jan 0001 Jan 0002 Jan 0003 Jan 0004 Jan 0005 Jan 0006
1206.68 782.45 1187.00 1398.77 1883.23 1431.80
z - zoo(data1[,3], as.Date(as.yearmon(data1[,1], %b-%y)))
head(z)
0001-01-01 0002-01-01 0003-01-01
You need to unambiguously specify what your data
looks like. Please provide the dput output as previously
requested. Also what version of zoo are you using?
packageDescription(zoo)$Version
On Sun, Jun 1, 2008 at 9:37 AM, Megh Dal [EMAIL PROTECTED] wrote:
I got following:
z - zoo(data1[,3],
Also here is an example showing it works with the assumed
format and zoo version:
data1 - structure(list(V1 = structure(c(6L, 2L, 4L, 3L, 5L, 1L), .Label =
c(Apr-81,
+ Dec-80, Feb-81, Jan-81, Mar-81, Nov-80), class = factor),
+ V2 = c(NA, NA, NA, NA, NA, NA), V3 = c(1007.44, 982.05,
packageDescription(zoo)$Version
[1] 1.1-1
Gabor Grothendieck [EMAIL PROTECTED] wrote: You need to unambiguously specify
what your data
looks like. Please provide the dput output as previously
requested. Also what version of zoo are you using?
packageDescription(zoo)$Version
On Sun, Jun 1,
He creado un perfil en Facebook donde puedo publicar mis imágenes, vÃdeos y
eventos, y quiero agregarte como amigo/a para que puedas verlo. Primero,
necesitas registrarte en Facebook. Una vez registrado/a, puedes también crear
tu propio perfil.
Gracias,
Pau
Esta es la dirección:
Please upgrade to the latest version of zoo. as.yearmon.factor
was only added to zoo in recent versions and its likely your date
column is a factor.
If that is not the problem then please provide the dput output as
requested.
On Sun, Jun 1, 2008 at 9:59 AM, Megh Dal [EMAIL PROTECTED] wrote:
[EMAIL PROTECTED] wrote in
news:[EMAIL PROTECTED]
uk:
I'm attempting to plot a cubic relationship between two variables
controlling for the effects of a third variable. In this short
example, I'm trying to use AGE to predict CORTEX while controlling
for the effects of TIV (total
[EMAIL PROTECTED] wrote in
news:[EMAIL PROTECTED]:
Dear All, I suspect I'm becoming a bit anoying but... following the
question about the low r2 vs signific regression (thru ANCOVA),
the reviewer suggested (and I quote here):
'If you used RNA/DNA ratios as the dependent variable, but
Thanks Gabor, I have updated that and it is now working fine
Gabor Grothendieck [EMAIL PROTECTED] wrote: Please upgrade to the latest
version of zoo. as.yearmon.factor
was only added to zoo in recent versions and its likely your date
column is a factor.
If that is not the problem then please
Hi list,
If I have a matrix,
a-read.table(a.txt,header=TRUE,row.names=1)
dim(a)
[1] 4 3
a
x y z
a1 1 6 3
a2 2 6 3
a3 2 3 8
a4 5 3 4
Can you suggest how to produce a plot like the one attached here? Basically,
I want to plot each sample (each column) using the dots one by one and also
Hi Folks,
This must be easy but I've not managed to locate the solution!
Basically: I'm using sink() to save successively obtained
results, e.g. I construct a set of regression coefficients
etc. with names rows and columne (I want to see the names
in the output) as an object (say Object), and
Dear Ted,
what about
cat(\n)
or
message()
Best,
Matthias
(Ted Harding) wrote:
Hi Folks,
This must be easy but I've not managed to locate the solution!
Basically: I'm using sink() to save successively obtained
results, e.g. I construct a set of
Many thanks, Matthias! cat() did the job, exactly as wanted.
message() won't do, since sink() eother captures output
(type=output, the default) or captures messages
(type=message), in which case it won't capture the ouput!
In any case, even if it captured both, I wouldn't want to
sin() all the
Short form:
How do I transform the output of grid.locator() (or
grid.locator(unit='npc')) to the native (or npc) coordinates of a viewport other
than the top-level viewport?
Thanks in advance. -Ben
Long form:
I would like the user to be able to
Ben,
What if the click occurs over multiple viewports?
Hadley
On Mon, Jun 2, 2008 at 6:50 AM, Wittner, Ben, Ph.D.
[EMAIL PROTECTED] wrote:
Short form:
How do I transform the output of grid.locator() (or
grid.locator(unit='npc')) to the native (or npc) coordinates of a
ss [EMAIL PROTECTED] wrote in
news:[EMAIL PROTECTED]:
Hi list,
If I have a matrix,
a-read.table(a.txt,header=TRUE,row.names=1)
dim(a)
[1] 4 3
a
x y z
a1 1 6 3
a2 2 6 3
a3 2 3 8
a4 5 3 4
Can you suggest how to produce a plot like the one attached here?
Basically, I want to
On 31.05.2008, at 00:11, Prof Brian Ripley wrote:
On Fri, 30 May 2008, Duncan Murdoch wrote:
But I think with Brian Ripley's work over the last while, R for
Windows actually handles utf-8 pretty well. (It might not guess
at that encoding, but if you tell it that's what you're using...)
Hadley, In my application the leaf viewports will not overlap, but I guess that
would not necessarily be the case for all applications. In any event, do you
happen to know how to transform coordinates in the top-level viewport to
coordinates in another viewport in the tree? Thanks. -Ben
On Sat, 31-May-2008 at 06:07PM -0400, Carl Witthoft wrote:
Anyone know what's up w/ tolstoi.newcast.edu.au (home of the
threaded R-help archives)? I've got a can't connect for several
days now.
No luck here either, even with the correct spelling.
$ ping tolstoy.newcastle.edu.au
PING
Here is a clean version. I did this with nls and it works (see below), but
I need to do it with optim. Keun-Hyung
# optim
vol-rep(c(0.03, 0.5, 2, 4, 8, 16, 32), 3)
time-rep(c(2,4,8),each=7)
p.mated-c(0.47, 0.48, 0.43, 0.43, 0.26, 0.23, NA, 0.68, 0.62, 0.64, 0.58,
0.53, 0.47,
0.24, 0.8, 0.79,
try:
vol - rep(c(0.03, 0.5, 2, 4, 8, 16, 32), 3)
time - rep(c(2,4,8),each=7)
p.mated - c(0.47, 0.48, 0.43, 0.43, 0.26, 0.23, NA, 0.68, 0.62, 0.64,
0.58, 0.53, 0.47, 0.24, 0.8, 0.79, 0.71, 0.56, 0.74, 0.8, 0.47)
eury - data.frame(vol=vol, time=time, p.mated=p.mated)
eury - na.omit(eury)
p0 -
hı, I am preparing undergraduate thesis If you help me this would make me
feel good.
First I need to analyze effect of Dow Jones Industrial average(DJIA)'s
return on Istanbul Stock Exchange(ISE). I want to use Markov-Switching
Bayesian Vector Autoregression Models (MSBVAR) that is used to
would you like coffee with that?
From: [EMAIL PROTECTED] [EMAIL PROTECTED] On Behalf Of ensark [EMAIL PROTECTED]
Sent: Sunday, June 01, 2008 5:30 PM
To: r-help@r-project.org
Subject: [R] how to analyze time series structures?
hı, I am preparing
Anything else?
Jorge
On Sun, Jun 1, 2008 at 5:30 PM, ensark [EMAIL PROTECTED] wrote:
hý, I am preparing undergraduate thesis If you help me this would make me
feel good.
First I need to analyze effect of Dow Jones Industrial average(DJIA)'s
return on Istanbul Stock Exchange(ISE). I
Hello R help
I have been trying to use Rob Hyndman's monotonically increasing spline
function. But like another user or two seem have a problem with a
missing DLL (namely spline_coef). None of the previous help postings
seemed to have any solutions to this problem. As per a Ripley
suggestion I
Hello everyone. I have an interest in fitting jump diffusion AR(p)
processes (which will likely form part of a Garch model). Does anyone
know of some R code that will allow this please, hopefully using max
likelihood (or similar) methods?
I'm currently using WinBUGS and RWinBUGS to utilise a
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