On Sat, 14 Jun 2008, Андрей Парамонов wrote:
I use R 2.7.0 on GNU/Linux. I have noticed a problem in cbind method
for multivariate time series (ts) objects. Consider the following
example:
t - ts(data.frame(a = 10:20, b = 20:30, c = 30:40, d = 40:50))
t1 - t[, c('a', 'b')]
t2 - t[, c('c',
2008/6/15 Prof Brian Ripley [EMAIL PROTECTED]:
Consistent with what? This is how all such combinations of matrices in R
work, and avoids duplicate names.
Hm, for data.frames and matrices it works like this:
d - data.frame('a' = 10:20, b = 20:30, c = 30:40, d = 40:50)
d1 - d[c('a', 'b')]
2008/6/15 jim holtman [EMAIL PROTECTED]:
Is this what you want:
t - ts(data.frame(a = 10:20, b = 20:30, c = 30:40, d = 40:50))
t1 - t[, c('a', 'b')]
t2 - t[, c('c', 'd')]
colnames(t1)
[1] a b
colnames(t2)
[1] c d
x - cbind(t1, t2)
colnames(x)
[1] t1.a t1.b t2.c t2.d
colnames(x) -
Dear R-users
with a bit of grief I had to repeat an extensive analysis because I
did not suspect (and therefore did not read the documentation) that
round was implemented as for rounding off a 5, the IEC 60559 standard
is expected to be used, 'go to the even digit', resulting in
round(1.5)
Hi Markus,
The R function round() uses the round-to-even method, which is explained
on http://en.wikipedia.org/wiki/Rounding#Round-to-even_method.
If you would like instead traditional rounding then you should add 0.5
and take the integer part, as is suggested in the examples on ?round, e.g.
Try the zoo package:
library(zoo)
as.ts(cbind(as.zoo(t1), as.zoo(t2)))
Time Series:
Start = 1
End = 11
Frequency = 1
a b c d
1 10 20 30 40
2 11 21 31 41
3 12 22 32 42
4 13 23 33 43
5 14 24 34 44
6 15 25 35 45
7 16 26 36 46
8 17 27 37 47
9 18 28 38 48
10 19 29 39 49
11 20 30 40
I am trying to delete a section of rows from a data frame (based on no
condition). Lets say my data frame has 200 rows and I want to delete rows 1
through 25. How would I do this?
I know x[ -1, ] deletes the first row (or any desired row). I tried using
different variations of this, like x[
hi;
i want to change the police of the title of my graph.i tried to use
font.title and cex.title but there was no changing in characters fount.
is there any one who could help me?
--
View this message in context:
Hi there,
I don´t know if you are trying to solve the delete job or to test how
functions work.
If you really want to delete lines from a data.frame, try something like
this.
rowcount-1:100
x-runif(100)
y-runif(100)
df-data.frame(cbind(rowcount,x,y))
df.subset-subset(df, !(rownames(df) %in%
nmarti wrote:
I am trying to delete a section of rows from a data frame (based on no
condition). Lets say my data frame has 200 rows and I want to delete rows 1
through 25. How would I do this?
I know x[ -1, ] deletes the first row (or any desired row). I tried using
different variations
cch() does not allow for multiple records per person (as it says), and so
doesn't allow for time-dependent covariates.
-thomas
On Thu, 12 Jun 2008, Jin Wang wrote:
same subject id has to be multiple in mutiple times like following format,
Multiple records per id not allowed in cch()
Try survreg(), in the survival package.
-thomas
On Fri, 13 Jun 2008, Bluder Olivia wrote:
Hello,
I'm trying to calculate the Maximum likelihood estimators for a dataset
which contains censored data.
I started by using the function nlm, but isn't there a separate method
for doing
I am relatively new to R, so apologize up front for my long question,
particularly if there is too much or too little information.
I have a large time series data set where each subject's behavior was
originally coded on .25s intervals for 3min task. I am trying to determine
if the findings are
It turns out that the issue is ties in survival times. Repeating the data
produces tied failure times; weighting does not, so you get different results.
The effect is unusually large here, perhaps because of the small sample size.
If you use the (less accurate) Breslow correction for ties,
dear R experts: I have an academic question that borders on asking
for consulting help, so I hope I am not too imposing. If I am, please
ignore me.
My data set has 100MB data set of daily stock returns. I want to
compute rolling (recursive?) betas---either bivariate or
multivariate---with
Hi,
I am working with airborne LiDAR data and R. Do you know of any package
or project designed to achieve that goal ? Largely, if you are using R
and .las files (or lidar data), I would like to hear about your work
flow. Otherwise, if you know of a package that can help handling x,y,z
data
Ivo,
On 15 June 2008 at 12:50, ivo welch wrote:
| dear R experts: I have an academic question that borders on asking
| for consulting help, so I hope I am not too imposing. If I am, please
| ignore me.
|
| My data set has 100MB data set of daily stock returns. I want to
| compute rolling
Hi all,
Basically I want to make a binary hit matrix.
For instance, if I have a file called 'pair.txt':
set_agene_1
set_agene_2
set_agene_3
set_bgene_3
set_bgene_4
set_bgene_5
set_cgene_1
set_cgene_3
And I want to convert it to a binary matrix as:
Rowsset_a
Hi all,
Basically I want to make a binary hit matrix.
For instance, if I have a file called 'pair.txt':
set_agene_1
set_agene_2
set_agene_3
set_bgene_3
set_bgene_4
set_bgene_5
set_cgene_1
set_cgene_3
And I want to convert it to a binary matrix as:
Rowsset_a
on 06/15/2008 12:46 PM ssls sddd wrote:
Hi all,
Basically I want to make a binary hit matrix.
For instance, if I have a file called 'pair.txt':
set_agene_1
set_agene_2
set_agene_3
set_bgene_3
set_bgene_4
set_bgene_5
set_cgene_1
set_cgene_3
And I want to
This will give you an idea of how you might want to approach the problem:
sample -cbind((1:20)*.25,c(1,1,1,2,2,3,3,3,4,5,6,4,4,3,3,3,2,1,1,1))
sample
[,1] [,2]
[1,] 0.251
[2,] 0.501
[3,] 0.751
[4,] 1.002
[5,] 1.252
[6,] 1.503
[7,] 1.753
[8,] 2.003
Thank you very much, Marc!
Have a great weekend!
Alex
On Sun, Jun 15, 2008 at 1:58 PM, Marc Schwartz [EMAIL PROTECTED]
wrote:
on 06/15/2008 12:46 PM ssls sddd wrote:
Hi all,
Basically I want to make a binary hit matrix.
For instance, if I have a file called 'pair.txt':
set_agene_1
Hi R users
I want to use the lme package for a multilevel analysis on the following
example:
math-c(2, 3,2, 5, 6 ,7 , 7)
sex-c(1, 2, 1, 2, 2, 2, 1)
school_A-c(1,1,1,2,2,2,2)
school_B-c(10,10,10,20,20,20,20)
mydata-data.frame(math, sex, school_A, school_B)
mydata
School_A and school_B are
Dear all,
I have a matrix, called newdata1,
dim(newdata1)
[1] 3417683
It looks like:
EntrezIDName S1 S2 S3S4 S5.
1 4076 CAPRIN1 0.1 0.2 0.3...
2 139170WDR40B 0.4 0.5 0.6...
35505PPP1R2P1 0.3 0.3
on 06/15/2008 01:18 PM ss wrote:
Dear all,
I have a matrix, called newdata1,
dim(newdata1)
[1] 3417683
It looks like:
EntrezIDName S1 S2 S3S4 S5.
1 4076 CAPRIN1 0.1 0.2 0.3...
2 139170WDR40B 0.4 0.5 0.6...
3
eugen pircalabelu eugen_pircalabelu at yahoo.com writes:
I want to use the lme package for a multilevel analysis on the
following example:
math-c(2, 3,2, 5, 6 ,7 , 7)
sex-c(1, 2, 1, 2, 2, 2, 1)
school_A-c(1,1,1,2,2,2,2)
school_B-c(10,10,10,20,20,20,20)
mydata-data.frame(math, sex,
On Sat, Jun 14, 2008 at 7:49 AM, Oh Dong-hyun [EMAIL PROTECTED] wrote:
Hi,
my data set is data.frame(id, yr, y, l, e, k).
I would like to estimate Lee and Schmidts (1993, OUP) model in R.
My colleague wrote SAS code as follows:
** procedures for creating dummy variables are omitted **
**
On Sun, Jun 15, 2008 at 8:15 AM, hanen [EMAIL PROTECTED] wrote:
hi;
i want to change the police of the title of my graph.i tried to use
font.title and cex.title but there was no changing in characters fount.
is there any one who could help me?
--
Try 'font.main' and 'cex.main'. The word
On Fri, 13-Jun-2008 at 04:51PM +0200, [EMAIL PROTECTED] wrote:
Hi the list,
I write a package for clusterizing longitudinal data using a non parametric
algorithm. I develop the package under windows. To be as user friendly as
possible, the package use some graphical procedure to show to
Dear R-users,
While making a prediction using the randomForest function (package
randomForest) I'm getting the following error message:
Error in predict.randomForest(model, newdata = CV) : No forest component
in the object
Here's my complete code. For reproducing this task, please find my 2
Hi R-users
I think about some web service with stock charts and I plan use python as
web framework with R as mathematical and chart engine. I use rpy to connect
R with python. It works good.
Is it good idea to use R as chart engine? Maybe it's better (faster) to use
c/c++ plugin?
Daniel
Generally, I like to use a pdf device which can have any number of
pages.
I am proposing a graphical way a selecting a clusterization based a
quality criterion. In order to avoid local maximum, you can build
something like 10 000 clusterization. Exporting all of them has no
sence. So I open
Hi R users!
I am trying to learn some multilevel analysis, but unfortunately i am now very
confused. The reason:
http://www.ats.ucla.edu/stat/hlm/seminars/hlm_mlm/mlm_hlm_seminar.htm
http://www.ats.ucla.edu/stat/sas/seminars/sas_mlm/mlm_sas_seminar.htm
and
MlmSoftRev. pdf from mlmRev package.
Can you put some criteria on 'better'/'faster'. What throughput are
you expecting? How many requests per second will you have to handle?
What is the timing of your current method? What size/type machine
will you be running on? Is data being accessed from a database which
may influence the
Hi,
I am doing canonical discriminant analysis using candisc function from
the candisc package.
My input is a table of species distribution (columns = abundance of each
species in each sample) in samples that are split by categories (rows),
and I want to know whether each category is
Hi,
I have the following data file to be parsed and captured as a data frame:
__DATA__
#GDS_ID GENE_NAME GENE_DESCRIPTION GENE_FUNCTION
1007_s_at | DDR1 | discoidin domain receptor tyrosine kinase 1 | protein-coding
1053_at | RFC2 | replication factor C (activator 1) 2, 40kDa | protein-coding
Does this give you what you want:
x - read.table(textConnection(#GDS_ID GENE_NAME GENE_DESCRIPTION
GENE_FUNCTION
+ 1007_s_at | DDR1 | discoidin domain receptor tyrosine kinase 1 |
protein-coding
+ 1053_at | RFC2 | replication factor C (activator 1) 2, 40kDa | protein-coding
+ 117_at | HSPA6 |
Thanks so much Jim,
It works. However how come the \n was not removed.
Meaning when I do:
print (x$V3)
it gives something like this:
__OUTPUT__
[1] discoidin domain receptor tyrosine kinase 1
[2] replication factor C (activator 1) 2, 40kDa
[3] heat shock 70kDa protein 6
I am not exactly sure what you are after, but if you are just printing
out a single column, then unless you use drop=FALSE in referencing
it, it is a vector:
x - read.table(textConnection(#GDS_ID GENE_NAME GENE_DESCRIPTION
GENE_FUNCTION
+ 1007_s_at | DDR1 | discoidin domain receptor tyrosine
You must use randomForest with keep.forest=TRUE - otherwise the Forest object
is not saved and so no prediction can be made.
--- On Mon, 16/6/08, Jim_S [EMAIL PROTECTED] wrote:
From: Jim_S [EMAIL PROTECTED]
Subject: [R] randomForest, 'No forest component...' error while calling
Predict()
Hi,
I have the following data frame:
print(mydatframe)
__DATAFRAME__
V1V2 V3
1 1007_s_at DDR1 discoidin domain receptor tyrosine kinase 1
2 1053_at RFC2 replication factor C (activator 1) 2, 40kDa
3 117_at HSPA6 heat shock 70kDa protein 6 (HSP70B')
__END__
Is there a way to
here is a way:
x - read.table(textConnection(#GDS_ID GENE_NAME GENE_DESCRIPTION
GENE_FUNCTION
+ 1007_s_at | DDR1 | discoidin domain receptor tyrosine kinase 1 |
protein-coding
+ 1053_at | RFC2 | replication factor C (activator 1) 2, 40kDa | protein-coding
+ 117_at | HSPA6 | heat shock 70kDa
Gundala Viswanath [EMAIL PROTECTED] writes:
Hi,
I have the following data frame:
print(mydatframe)
__DATAFRAME__
V1V2 V3
1 1007_s_at DDR1 discoidin domain receptor tyrosine kinase 1
2 1053_at RFC2 replication factor C (activator 1) 2, 40kDa
3 117_at HSPA6 heat shock 70kDa
Dear Tanya,
If I follow correctly what you're trying to do, you're in effect doing a
one-way MANOVA of 17 response variables on a six-level factor, with only 20
observations. That's not enough data. I'm copying to Michael Friendly in
case he hasn't seen your posting and would like to comment.
I believe that x - x[-(1:25),] should work.
--- On Sun, 15/6/08, nmarti [EMAIL PROTECTED] wrote:
From: nmarti [EMAIL PROTECTED]
Subject: [R] Delete Block of Rows
To: r-help@r-project.org
Received: Sunday, 15 June, 2008, 11:02 PM
I am trying to delete a section of rows from a data frame
On Sun, Jun 15, 2008 at 9:03 PM, jim holtman [EMAIL PROTECTED] wrote:
here is a way:
x - read.table(textConnection(#GDS_ID GENE_NAME GENE_DESCRIPTION
GENE_FUNCTION
+ 1007_s_at | DDR1 | discoidin domain receptor tyrosine kinase 1 |
protein-coding
+ 1053_at | RFC2 | replication factor C
Hi,
the documentation for tm advertises the following:
docs - c(This is a text., This another one.)
Corpus(VectorSource(docs))
but this doesn't work for me:
docs - c(This is a text., This another one.)
Corpus(VectorSource(docs))
Corpus(VectorSource(docs))
Error: could not find function
Hi,
I have a mixture pdf which has three components, each satisfies the
6 dimension normal distribution.
I use mvrnorm() from the MASS library to generate 1000 samples for
each component and I add them
to get the random samples which satisfies with the mixture
distribution.
I
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