Immaterial, yes, but it is always good to test :) and your solution *is*
faster and it is even faster if you can assume byte strings:
strings = sprintf('f:/foo/bar//%s.tif', replicate(1000,
paste(sample(letters, 10), collapse='')))
library(rbenchmark)
benchmark(columns=c('test',
PS == Phil Spector spec...@stat.berkeley.edu
on Tue, 26 May 2009 09:25:26 -0700 (PDT) writes:
PS Janna -
PS Another thing that's sometimes useful with a new package
PS is to run the example function, like
PS example(TTR)
PS This will run the examples from the
Le mardi 26 mai 2009 à 14:11 -0400, Stu @ AGS a écrit :
Hi!
I am a bit new to R.
I am looking for the right function to use for a multiple regression problem
of the form:
y = c1 + x1 + (c2 * x2) - (c3 * x3)
Where c1, c2, and c3 are the desired regression coefficients that are
subject to
You can accommodate the constraints by, e.g., putting
c2 = pnorm(theta2)
c3 = pnorm(theta3)
x1 has a known coefficient (unity) so it becomes an offset. Essentially your
problem can be written
y1 = y-x1 = c1 + pnorm(theta2)*x2 - pnorm(theta3)*x3 + error
This is then a (pretty simple)
mauede at alice.it writes:
I am looking for a package to perform harmonic analysis with the goal of
estimating the period of the
dominant high frequency component in some mono-channel signals.
You should widen your scope by looking a time series instead of harmonic
analysis. There is a
bbouling wrote:
Thanks to Dieter Menne and Spencer Graves I started to get my way through
lsoda()
Now I need to use it in with nls() to assess parameters
I have a go with a basic example
dy/dt = K1*conc
I try to assess the value of K1 from a simulated data set with a K1 close
to
M Berg wrote:
str(rx)
num [1:16] 21 9 8 18 4 12 17 2 9 7 ...
I want to print out the entire vector as part of the problem.
When I use \Sexpr(rx) only the first value (in this case 21) is printed
out.
rx = 1:10
rxs = paste(rx,collapse=, )
So
\Sexpr{paste(rx,collapse=, )}
should
Allan Engelhardt wrote:
Immaterial, yes, but it is always good to test :) and your solution
*is* faster and it is even faster if you can assume byte strings:
:)
indeed; though if the speed is immaterial (and in this case it
supposedly was), it's probably not worth risking fixed=TRUE removing
Hi All,
I am trying to learn Neural Networks. I found that R has packages which can
help build Neural Nets - the popular one being AMORE package. Is there any book
/ resource available which guides us in this subject using the AMORE package?
Any help will be much appreciated.
Thanks,
Greetings,
Does anyone know if the C4.5 algorithm is already implemented in R? If yes,
please let me know the package. Thanks.
--
View this message in context:
http://www.nabble.com/C4.5-implementation-in-R-tp23736785p23736785.html
Sent from the R help mailing list archive at Nabble.com.
Hello,
\Sexpr only displays one value.
Why don't you print your vector into a verbatim environment ?
echo=F,results=verbatim
print(rx)
@
But if you want to generate a table with xtable, one solution :
echo=F,results=tex
print(xtable(as.data.frame(t(rx))), include.rownames = F,
I think Rweka implements the C4.5 (revision 8) algorithm, but it calls
it J4.8 (because it's written in Java instead of C, and also the
revision number, and is uses an open source licence, i think).
You might want to look at this paper by Schauerhuber, Zeileis Hornik
called 'Benchmarking
Am Dienstag, den 26.05.2009, 21:05 +0200 schrieb Romain Francois:
Hi,
You might like tk_choose.files from package tcltk. This comes with R but
your system needs to be capable enough:
capabilities( )[tcktk]
require( tcltk )
tk_choose.files
I suppose it should be
capabilities(
I wonder whether R has methods for constrained fitting of linear models.
I am trying fm-lm(y~x+I(x^2), data=dat) which most of the time gives
indeed the coefficients of an inverted parabola. I know in advance that
it has to be an inverted parabola with the maximum constrained to
positive (or
Farley, Robert FarleyR at metro.net writes:
What is wrong? I've looked into the na commands and the ?xtabs entry, but I
haven't found anything that works.
I never understood the logic that exclude=NULL needs na.action in addition.
test - c(1,2,3,1,2,3,NA,NA,1,2,3)
Hi,
I searched a lot on the internet but was unable to find the function for
calculating the kappa statistics for intra-observer reliabilty.
Can anybody help me in the this regards.
Thanks,
Shreyasee
[[alternative HTML version deleted]]
__
Dear R-community
I have a grueling problem which appears to be impossible to solve:
I want to make a simple plot, here is my code: http://gist.github.com/118550
Unfortunately, the annotation of both the x- and y-axis are not correct, as
you can see in the following picture:
Hello folks,
many multivariate anayses (e.g., structural equation modeling) require
multivariate normal distributions.
Real data, however, most often significantly depart from the multinormal
distribution. Some researchers (e.g., Yuan et al., 2000) have proposed a
multivariate transformation of
There's a link on the CRAN page for the AMORE package which apears to
have some cool information:
http://wiki.r-project.org/rwiki/doku.php?id=packages:cran:amore
Seems like an interesting package, I hadn't actually heard of it
before your post.
HTH,
Tony
On 27 May, 09:13, Indrajit Sengupta
G'day Alex,
On Wed, 27 May 2009 11:51:39 +0200
Alex van der Spek am...@xs4all.nl wrote:
I wonder whether R has methods for constrained fitting of linear
models.
I am trying fm-lm(y~x+I(x^2), data=dat) which most of the time gives
indeed the coefficients of an inverted parabola. I know in
Hi all -
I'm trying to do multiple one-way ANOVA tests of different factors on the
same variable. As a result I have a list with all the ANOVA tables, for
exemple:
$X11_20502
Analysis of Variance Table
Response: MPH
Df Sum Sq Mean Sq F valuePr(F)
x 3 369.9
Dear R helpers,
Following is a R script I am using to run the Fast Fourier Transform. The csv
files has 10 columns with titles m1, m2, m3 .m10.
When I use the following commands, I am getting the required results. The
probelm is if there are 100 columns, it is not wise to define 100
Given an arbitrary data frame, it is easy to exclude a column given its index:
df[,-2]. How to do the same thing given the column name? A naive attempt
df[,-name] did not work :)
__
R-help@r-project.org mailing list
Why did you use different variable names rather than index of list/data.frame?
On Wed, May 27, 2009 at 6:34 PM, Maithili Shiva
maithili_sh...@yahoo.com wrote:
Dear R helpers,
Following is a R script I am using to run the Fast Fourier Transform. The csv
files has 10 columns with titles m1,
Hope this helps:
df - data.frame(matrix(1:10,2))
df
X1 X2 X3 X4 X5
1 1 3 5 7 9
2 2 4 6 8 10
df[,-2]
X1 X3 X4 X5
1 1 5 7 9
2 2 6 8 10
df[,-which(names(df)==X2)]
X1 X3 X4 X5
1 1 5 7 9
2 2 6 8 10
On Wed, May 27, 2009 at 6:37 PM, Zeljko Vrba zv...@ifi.uio.no wrote:
Zeljko Vrba wrote:
Given an arbitrary data frame, it is easy to exclude a column given its index:
df[,-2]. How to do the same thing given the column name? A naive attempt
df[,-name] did not work :)
__
R-help@r-project.org mailing list
On Wed, May 27, 2009 at 12:52:41PM +0200, Paul Hiemstra wrote:
This piece of code does the trick. Most important is the which() command:
df = data.frame(a = runif(10), b = runif(10))
df[,-which(names(df) == a)]
Thanks to you and Linlin. It did not occur to me to use which(); I thought
Paul Hiemstra wrote:
Zeljko Vrba wrote:
Given an arbitrary data frame, it is easy to exclude a column given
its index:
df[,-2]. How to do the same thing given the column name? A naive
attempt
df[,-name] did not work :)
__
R-help@r-project.org
#create some data
y=rnorm(20)
x=factor(rep(c('A','B'),each=10))
#run the anova
my_aov = aov(y~x)
#summarize the anova
my_aov_summary = summary(my_aov)
#show the anova summary
print(my_aov_summary)
#lets see what's in the summary object
str(my_aov_summary)
#looks like it's a list with 1
On Wed, 2009-05-27 at 02:52 -0700, durden10 wrote:
Dear R-community
I have a grueling problem which appears to be impossible to solve:
I want to make a simple plot, here is my code: http://gist.github.com/118550
Unfortunately, the annotation of both the x- and y-axis are not correct, as
you
On Wed, 2009-05-27 at 18:08 +0800, Shreyasee wrote:
Hi,
I searched a lot on the internet but was unable to find the function for
calculating the kappa statistics for intra-observer reliabilty.
Can anybody help me in the this regards.
See classAgreement() in package e1071 for example. There
Shreyasee wrote:
Hi,
I searched a lot on the internet but was unable to find the function for
calculating the kappa statistics for intra-observer reliabilty.
Can anybody help me in the this regards.
Hi Shreyasee,
Thanks for reminding me that I had promised to rewrite Tore
Wentzel-Larsen's
Thanks a lot
On Wed, May 27, 2009 at 7:47 PM, Gavin Simpson gavin.simp...@ucl.ac.ukwrote:
On Wed, 2009-05-27 at 18:08 +0800, Shreyasee wrote:
Hi,
I searched a lot on the internet but was unable to find the function for
calculating the kappa statistics for intra-observer reliabilty.
Dear list,
I want to move some files that should keep their time stamps, which is
not the case if I use file.copy in combination with file.remove.
file.move would be nice, is there a package providing such a function?
Regards,
Stefan
__
Thanks a lot
On Wed, May 27, 2009 at 7:55 PM, Jim Lemon j...@bitwrit.com.au wrote:
Shreyasee wrote:
Hi,
I searched a lot on the internet but was unable to find the function for
calculating the kappa statistics for intra-observer reliabilty.
Can anybody help me in the this regards.
Hi
There's also the nnls (non-negative least squares) package on CRAN
that might be useful, although I'm puzzled by the negative sign in front
of c in Alex post...
Cheers,
Andy
From: Berwin A Turlach
G'day Alex,
On Wed, 27 May 2009 11:51:39 +0200
Alex van der Spek am...@xs4all.nl wrote:
You can try this:
DF[,columnName] - NULL
On Wed, May 27, 2009 at 7:37 AM, Zeljko Vrba zv...@ifi.uio.no wrote:
Given an arbitrary data frame, it is easy to exclude a column given its
index:
df[,-2]. How to do the same thing given the column name? A naive attempt
df[,-name] did not work :)
I want to make a simple plot, here is my code:
http://gist.github.com/118550
Unfortunately, the annotation of both the x- and y-axis are not correct,
as
you can see in the following picture:
http://www.nabble.com/file/p23739356/plot.png
I am not an expert of R, so maybe someone can point
Dieter Menne wrote:
mauede at alice.it writes:
I am looking for a package to perform harmonic analysis with the goal of
estimating the period of the
dominant high frequency component in some mono-channel signals.
You should widen your scope by looking a time series instead of harmonic
I apologize for not pasting a complete example, but the data-set is too large,
so I hope someone can help me just by description of symptoms.
I define a generic plot object name (note the missing y=.. in aes()) to
plot different y-values against the same set of x-values.
p.b4.generic.wg -
R users,
I am making model selection with an accelerated failure time model using the
command survreg within the library survival.
As I want to compare models with different probability distributions I need
to have the full likelihood.
How can I find out what survreg generates: the
Thanks for the answer!!!
I Know how to extract the Pr(F) value from single ANOVA table, but I have a
list of many ANOVA tables recived by :
a-function(x)(aov(MPH~x))
q-apply(assoc[,18:20],2,a) # just for example, I have more than 3
factors(x)
print(q)
$X11_20502
Df Sum Sq Mean Sq
On Wed, May 27, 2009 at 01:40:52PM +0200, Zeljko Vrba wrote:
I apologize for not pasting a complete example, but the data-set is too large,
so I hope someone can help me just by description of symptoms.
-snip-
I have solved the problem by introducing an artificial variable in the original
Hi,
Luckily for me - until now i did not have too many times to do these type of
parsing - but who knows??? Up to now i was pretty happy with strsplit
.Anyway - thanks again for all the help, i really appreciate it.
Monica
From:
Dear Robert,
a different option, just to give you one more choice: you should be able
to keep the standard Xandros and install R if you don't feel like
changing the operating system. You just have to add the standard Debian
repositories. I found it easier to have R, Emacs and LaTeX working on
the
It depends on what you are after. I am by no means a wunderkind when
it comes to transformation, but in the package vegan type
?wisconsin
and that should give you a start, but if you know what
transformations you would like to preform then apply should do what
you need with whatever
Thanks Tony. I will look into it.
Tony Breyal wrote:
I think Rweka implements the C4.5 (revision 8) algorithm, but it calls
it J4.8 (because it's written in Java instead of C, and also the
revision number, and is uses an open source licence, i think).
You might want to look at this
I've got a matrix with 2 columns and n rows. I need to sort it first
by the values in column 1 ascending. Then for values which are the
same in column 1, sort by column 2 decending. For example:
2 .5
1 .3
1 .5
3 .2
Goes to:
1 .5
1 .3
2 .5
3 .2
This is easy to do in spreadsheet programs but I
I am sorry if this question sounds basic but I am having trouble understanding
a warning message I have been receiving in R after attempting logistic
regression.
I have been using the logistic regression function in R to analyse a simulated
data set. The dependent variable failure has an
durden10 wrote:
Dear R-community
I have a grueling problem which appears to be impossible to solve:
I want to make a simple plot, here is my code: http://gist.github.com/118550
Unfortunately, the annotation of both the x- and y-axis are not correct, as
you can see in the following picture:
you could use ldply from the plyr package:
p = ldply(q,function(x){x$P})
Without you data I can't confirm that works, but something like that
should do it
On Wed, May 27, 2009 at 9:23 AM, Imri bisr...@agri.huji.ac.il wrote:
Thanks for the answer!!!
I Know how to extract the Pr(F) value from
why will a fourier transform not work?
2009/5/27 Uwe Ligges lig...@statistik.tu-dortmund.de:
Dieter Menne wrote:
mauede at alice.it writes:
I am looking for a package to perform harmonic analysis with the goal of
estimating the period of the
dominant high frequency component in some
Try this:
cbind(sort(x[,1]), unlist(tapply(x[,2], x[,1], sort, decreasing = T)))
On Wed, May 27, 2009 at 9:39 AM, Paul Geeleher paulgeele...@gmail.comwrote:
I've got a matrix with 2 columns and n rows. I need to sort it first
by the values in column 1 ascending. Then for values which are the
Dear members of the R help list,
I want to do a hierarchical glm with binomial family but am unsure
about how to write the syntax which involves nesting.
I want to test whether the risk of being attacked by Herbivores for
Meadowsweet plants is significantly dependent on the Distance to
Some thought about this overnight led to conclusion that a capability
to follow from one method to another could be quite useful. Moreover,
it should be pretty easy to fit it into our current trial version of
optimx()
as we call the function. More at UseR.
JN
Ravi Varadhan wrote:
Stephen,
My thoughts exactly.
?FFT should do the job.
And define the dominant term - a_n**2 + b_n**2 - the Parseval Relation.
stephen sefick
Try
lapply(ONS, fft)
and take a look here http://cran.r-project.org/doc/manuals/R-intro.html for
the basics of data structures in R and how to apply functions to them.
Andy.
andydol...@gmail.com
2009/5/27 Linlin Yan yanlinli...@gmail.com
Why did you use different variable names rather
Are you looking for file.rename?
Moving files is not really a portable concept, and nor is 'time
stamps' (files usually have three or more times associated with them,
and moving does not keep them all in OSes that implement it).
On Wed, 27 May 2009, Stefan Uhmann wrote:
Dear list,
I want
Nice. Works perfectly.
On Wed, May 27, 2009 at 2:03 PM, Henrique Dallazuanna www...@gmail.com wrote:
Try this:
cbind(sort(x[,1]), unlist(tapply(x[,2], x[,1], sort, decreasing = T)))
On Wed, May 27, 2009 at 9:39 AM, Paul Geeleher paulgeele...@gmail.com
wrote:
I've got a matrix with 2
I define the following function:
(Please don't wonder about the use of this function, this is just a
simplified version of my actual function. And please don't spend your
time in finding an alternate way of doing the same as the following does
not exactly represent my function. I am only
Johan Stenberg-2 wrote:
Dear members of the R help list,
I want to do a hierarchical glm with binomial family but am unsure
about how to write the syntax which involves nesting.
I want to test whether the risk of being attacked by Herbivores for
Meadowsweet plants is significantly
Try reading this thread:
http://thread.gmane.org/gmane.comp.lang.r.general/134368/focus=134475
especially the posts by I Kosmidis which show you how to diagnose
problems in logit model fits like this.
There is a statement about this warning in ?glm as well and a pointer to
a reference which
On Wed, 2009-05-27 at 08:39 -0400, stephen sefick wrote:
It depends on what you are after. I am by no means a wunderkind when
it comes to transformation, but in the package vegan type
?wisconsin
and that should give you a start, but if you know what
transformations you would like to preform
On Wed, May 27, 2009 at 6:37 AM, Zeljko Vrba zv...@ifi.uio.no wrote:
Given an arbitrary data frame, it is easy to exclude a column given its
index:
df[,-2]. How to do the same thing given the column name? A naive attempt
df[,-name] did not work :)
Various ways:
Boolean index vector:
You are right there is a pdf file which describes the function. But let tell
you where I am coming from.
Just to test if a neural network will work better than a ordinary least square
regression, I created a dataset with one dependent variable and 6 other
independent variables. Now I had
On Wed, 27 May 2009, utkarshsinghal wrote:
I define the following function:
(Please don't wonder about the use of this function, this is just a
simplified version of my actual function. And please don't spend your time in
finding an alternate way of doing the same as the following does not
On Wed, 2009-05-27 at 19:41 +0530, utkarshsinghal wrote:
I define the following function:
(Please don't wonder about the use of this function, this is just a
simplified version of my actual function. And please don't spend your
time in finding an alternate way of doing the same as the
Yeah, seems so obvious now. What a blunder, poor me.
Perfect explanation. Thanks
Thomas Lumley wrote:
On Wed, 27 May 2009, utkarshsinghal wrote:
I define the following function:
(Please don't wonder about the use of this function, this is just a
simplified version of my actual function. And
Hello , I do not know anything abount Ubunto, but I found a Portable Ubunto for
Windows and since so many people
prefer Linux to Windows I decided to give it a try.
It runs very nicely, so I tried to load R, following Instructions in CRAN I
added the line
deb
The design decision in metaMDS says that it uses:
Minchin, P.R. (1987) An evaluation of relative robustness of
techniques for ecological ordinations. Vegetatio 71, 145-156.
This is the paper that I found by the same name. Is this the correct reference?
Minchin, Peter R.1987. An Evaluation of
I fed this data into a Neural network (3 hidden layers with 6 neurons in each
layer) and trained the network. When I passed the input dataset and tried to
get the predictions, all the predicted values were identical! This confused
me a bit and was wondering whether my understanding of the
I don't remember what the version of R in deb repositories is, but
2.6.2 is probably about right. One of the things the Debian project
is focused on is the stability of the operating system, so they do not
update packages as readily as some other distributions. I had this
with Debian 5.0 and
Peter Dalgaard P.Dalgaard at biostat.ku.dk writes:
Or, BTW, you can use within()
aq - within(airquality, rm(Day))
Please add this as an example to the docs of within.
Dieter
__
R-help@r-project.org mailing list
The 'ties.method' argument to 'rank' is the *third* positional argument to
'rank', so either you need to put it in the third position or you need to
use a named argument.
The fact that the variable you're using to represent ties.method is called
ties.method is irrelevant. That is, this:
R Heberto Ghezzo, Dr wrote:
Hello , I do not know anything abount Ubunto, but I found a Portable Ubunto for
Windows and since so many people
prefer Linux to Windows I decided to give it a try.
It runs very nicely, so I tried to load R, following Instructions in CRAN I
added the line
deb
Dear R-users,
I have very recently started learning about object-oriented programming
in R. I am far from being an expert in programming, although I do have
an elementary C++ background.
Please take a look at these lines of code.
some.data = data.frame(V1 = 1:5, V2 = 6:10) ;
p.plot =
Having solved this problem, I am posting this so that the next time I search
for how to do this I will find an answer...
Using qqmath(..., groups=num) creates a separate qq distribution for each
group (within a panel). Using the 'col' or 'pch' argument does not
(usually) work because
On Wed, May 27, 2009 at 9:17 AM, Ben Bolker bol...@ufl.edu wrote:
Johan Stenberg-2 wrote:
Dear members of the R help list,
I want to do a hierarchical glm with binomial family but am unsure
about how to write the syntax which involves nesting.
I want to test whether the risk of being
It's a very interesting problem. I just wrote a function for it:
order.matrix - function(m, columnsDecreasing = c('1'=FALSE), rows = 1:nrow(m))
{
if (length(columnsDecreasing) 0)
{
col - as.integer(names(columnsDecreasing[1]));
values - sort(unique(m[rows, col]),
Dear R-users,
To obtain the percentage of deviance explained when fitting a gam model using
the mgcv library is straightforward:
summary(object.gam) $dev.expl
or alternatively, using the deviance (deviance(object.gam)) of the null and the
fitted models, and then using 1 minus
We are reading big tables, such as,
Chemicals -
read.table('ftp://ftp.bls.gov/pub/time.series/wp/wp.data.7.Chemicals',header
= TRUE, sep = '\t', as.is =T)
I was wondering if it is possible to set a filter during loading so that
we just load what we want not the whole table each time. Thanks,
I want to plot quantitative data as a function of three two-level factors.
How do I group the bars on a barplot by level through labeling and spacing?
Here http://www.thomaslevine.org/sample_multiple-factor_barplot.png's what
I'm thinking of. Also, I'm pretty sure that I want a barplot, but there
Dieter Menne wrote:
Peter Dalgaard P.Dalgaard at biostat.ku.dk writes:
Or, BTW, you can use within()
aq - within(airquality, rm(Day))
Please add this as an example to the docs of within.
possibly with the slightly more generic
unwanted - 'Day'
aq -
On Wed, 2009-05-27 at 11:31 -0400, stephen sefick wrote:
The design decision in metaMDS says that it uses:
Minchin, P.R. (1987) An evaluation of relative robustness of
techniques for ecological ordinations. Vegetatio 71, 145-156.
This is the paper that I found by the same name. Is this
See also this tip on the R wiki:
http://wiki.r-project.org/rwiki/doku.php?id=tips:data-frames:sort
Also available as the orderBy function in the doBy package.
Kevin Wright
On Wed, May 27, 2009 at 11:19 AM, Linlin Yan yanlinli...@gmail.com wrote:
It's a very interesting problem. I just wrote
R Heberto Ghezzo, Dr pisze:
Hello , I do not know anything abount Ubunto, but I found a Portable Ubunto for
Windows and since so many people
prefer Linux to Windows I decided to give it a try.
It runs very nicely, so I tried to load R, following Instructions in CRAN I
added the line
deb
On 5/27/2009 8:39 AM, Paul Geeleher wrote:
I've got a matrix with 2 columns and n rows. I need to sort it first
by the values in column 1 ascending. Then for values which are the
same in column 1, sort by column 2 decending. For example:
You've seen a few ways. Here are some more:
1. Use
You can get something close with ggplot2:
library(ggplot2)
my_data = expand.grid(
A = factor(c('A1','A2'))
, B = factor(c('B1','B2'))
, C = factor(c('C1','C2'))
)
my_data$DV = rnorm(8,mean=10,sd=1)
p = ggplot()
p = p + layer(
geom = 'bar'
, stat =
Hi all,
I often have to peek at large data.
While head and tail are convenient, at times I'd like some more
comprehensive.
I guess I debug better in a more visual way?
I was wondering if there's a way to override the default data editor.
I could of course dump to a txt file, and look at it with
library(R2HTML)
Loading required package: R2HTML
Error in .Internal(int.unzip(zipname, NULL, dest)) :
no internal function int.unzip
Error : .onLoad failed in 'loadNamespace' for 'R2HTML'
Error: package 'R2HTML' could not be loaded
Version: R 2.9.0 for Windows
Internet Email
I am writing my first R package, and I have been getting the following series
of errors when I run R CMD check:
* checking S3 generic/method consistency ... WARNING
Error: package/namespace load failed for 'REEMtree'
Call sequence:
2: stop(gettextf(package/namespace load failed for '%s',
Hello folks,
I am a beginner R user. I have been able to make a 3D surface plot using
'persp'. The surface is made by a grid of lines emanating perpendicularly
from each of the x and y axes at regular intervals.
I can get rid of that grid by setting 'border=NA'.
Can anyone suggest some ways to
Here is the code that i had used:
#
## Read in the raw data
fitness - c(44,89.47,44.609,11.37,62,178,182,
40,75.07,45.313,10.07,62,185,185,
44,85.84,54.297,8.65,45,156,168,
42,68.15,59.571,8.17,40,166,172,
38,89.02,49.874,9.22,55,178,180,
Jose Quesada wrote:
Hi all,
I often have to peek at large data.
While head and tail are convenient, at times I'd like some more
comprehensive.
I guess I debug better in a more visual way?
I was wondering if there's a way to override the default data editor.
I could of course dump to a txt file,
Bonjour,
Je recherche une ancienne amie qui porte le nom de Marylin Gabriel originaire
des Seychelles et que j'ai perdu de vue il y à environ 20 ans.
Si cette adresse e-mail est la tienne, tu te souviendra très bien de moi,
j'aimerais beaucoup te revoir car j'ai de superbes souvenirs de toi.
First of all, thanks a lot for your quick helpful comments!
I have come down to this:
Win- c(-0.005276404, 0.081894394, -0.073461539, 0.184371967,
0.133189670, -0.006239016, -0.063616699, 0.196754234, 0.402148743,
0.104408425,
0.036910154, 0.195227863, 0.212743723,
I haven't used the AMORE package before, but it sounds like you
haven't set linear output units or something. Here's an example using
the nnet package of what you're doing i think:
### R START###
# set random seed to a cool number
set.seed(42)
# set up data
x1-rnorm(100); x2-rnorm(100);
Hi,
is it possible to use the writer method from the
weka.core.SerializationHelper class in R?
What could be wrong in my trial.
many thanks
Christian
.jmethods(weka/core/SerializationHelper)
[2] public static void
weka.core.SerializationHelper.write(java.lang.String,java.lang.Object)
Hi,
is it possible to use the writer method from the
weka.core.SerializationHelper class in R?
When yes, what could be wrong in my trial.
many thanks
Christian
.jmethods(weka/core/SerializationHelper)
[2] public static void
Thank you! The script is now adapted to Biostrings and it is really fast! For
example, it does:
alph_sequence - alphabetFrequency(data$sequence, baseOnly=TRUE)
data$GCsequence - rowSums(alph_sequence[,c(G, C)]) /
rowSums(alph_sequence)
in the G+C computation. It also works amazingly fast
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