Dear all,
I have recently installed R on a Red Hat Enterprise Linux
(RHEL5) system. But I am unable to load R and it is giving the following
error :
*/usr/local/lib/R/bin/exec/R: error while loading shared libraries:
libreadline.so.5: cannot open shared object file: No such file
On Thu, May 28, 2009 at 11:42:41AM +0530, anupam sinha wrote:
I have checked for the presence of the above mention library and found that
the library is present. I have run out of ideas. Can anyone help me out???
I will be greatly indebted.
First: how did you check that the library is
Michael Kubovy wrote:
An editor has suggested that I use bar plots to capture an interaction
of two 2-level factors and an interaction of a 2 by 3 factorial
experiment. (It would seem that there's a fear that someone might try
to interpolate between, e.g., 'male' and 'female'.) In
On 28-May-09 00:58:17, Erin Hodgess wrote:
Dear R People:
I would like to set up a plug-in for Rcmdr to do the following:
I would start on a Linux laptop. Then I would log into another
outside system and run a some commands.
Now, when I tried to do
system(ssh e...@xxx.edu)
password
urlwolf wrote:
I often have to peek at large data.
While head and tail are convenient, at times I'd like some more
comprehensive.
I guess I debug better in a more visual way?
I was wondering if there's a way to override the default data editor.
I have never seen the data editor. The
Hi.
Do you need an interactive session at the remote machine, or are you
simply wanting to run a pre-written script?
If the latter, then you can ask ssh to execute a remote command, which
conceivably could be R CMD x
If you explain exactly why and what you are trying to do, then perhaps
Andrey Lyalko wrote:
How do I get removed from this mailing list?
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Hi,
Recently I come through those R-expressions and understood that 1L means
1 and 0L means 0. Why they are so? I mean, what the excess meanings
they carry, instead writing simple 1 or 0? Is there any more this kind
of expressions in R?
Regards
[[alternative HTML version deleted]]
Hi. I remember considering these options myself but concluded that for
most analyses a strictly procedural approach was satisfactory.
Although I may re-run multiple analyses, the data manipulation (and
subsequent analysis - the former always more complex than the latter
IMHO) is fairly project-
Duncan Murdoch wrote:
On 27/05/2009 8:25 PM, Andrey Lyalko wrote:
How do I get removed from this mailing list?
Like most lists nowadays, it gives the instructions in each message header:
List-Unsubscribe: https://stat.ethz.ch/mailman/options/r-help,
Peter Dalgaard wrote:
Duncan Murdoch wrote:
On 27/05/2009 8:25 PM, Andrey Lyalko wrote:
How do I get removed from this mailing list?
Like most lists nowadays, it gives the instructions in each message
header:
List-Unsubscribe: https://stat.ethz.ch/mailman/options/r-help,
check out geom_vline
+ geom_vline(xintercept=as.numeric(as.Date(2002-11-01)))
[you may not need to convert the date to numeric in the most recent
ggplot2 version]
On 27 May 2009, at 20:31, stephen sefick wrote:
library(ggplot2)
melt.updn - (structure(list(date = structure(c(11808,
Dear all
i could not estimate the optima value or range value in unimodal plot in glm
please help me out
thanking you
regard
madan
_
Hotmail® has a new way to see what's up with your friends.
orial_WhatsNew1_052009
On Thu, 2009-05-28 at 12:50 +0530, bogaso.christofer wrote:
Hi,
Recently I come through those R-expressions and understood that 1L means
1 and 0L means 0. Why they are so? I mean, what the excess meanings
they carry, instead writing simple 1 or 0? Is there any more this kind
of expressions
On Thu, 2009-05-28 at 09:33 +0200, Wacek Kusnierczyk wrote:
Peter Dalgaard wrote:
Duncan Murdoch wrote:
On 27/05/2009 8:25 PM, Andrey Lyalko wrote:
How do I get removed from this mailing list?
Like most lists nowadays, it gives the instructions in each message
header:
On Thu, 2009-05-28 at 07:50 +, ms.com wrote:
Dear all
i could not estimate the optima value or range value in unimodal plot in glm
please help me out
thanking you
regard
madan
You're going to have to give us more to go on than that, but...
Are you an ecologist and you want to
Actually I did a search using locate but could not find the file. But when
I do yum install readline (package containing the dependency
libreadline.so.5) I get the following error:
yum install readline
Loading security plugin
Loading rhnplugin plugin
rhel-x86_64-client-5 100%
On Thu, May 28, 2009 at 02:02:52PM +0530, anupam sinha wrote:
Actually I did a search using locate but could not find the file. But when
Locate reports useful results only if its database is up-to-date. Try running
one of
ldd /usr/lib/R/bin/exec/R
ldd /usr/lib64/R/bin/exec/R
and see what it
Hi,
Could some give some ideas on how to compute the spatiotemporal covariance
matrix by a sum of Kronecker products in R. Is there any special function that
can be used?
Cheers.
Firdaus
[[alternative HTML version deleted]]
__
I am interested in modeling hydrological extreme events. I found
MSClaio2008 very interesting function. In this function four
criterions for choosing distributions. Can we call these criterions
as model selection techniques or goodness of fit techniques or both?
Because goodness of fit
Thanks a lot for all the helpful comments! It finally works :handshake:
(I settled with the code of Gavin)
Best,
Durden
--
View this message in context:
http://www.nabble.com/r-plot-tp23739356p23757458.html
Sent from the R help mailing list archive at Nabble.com.
Hi Friends,
I am working on R-2.9.0 and i want to connect oracle through R, but i could
not find ROracle (zip file for windows) on CRAN Packages. Can anyone suggest
me how to connect Oracle from R in windows platform? I would be grateful if
u can provide me code aswell.
Thanks Regards,
Madan
Gavin Simpson wrote:
The View message source would be a more direct way of viewing the full
email, not just the bits TBird shows you in the preview pane. I forget
how it is named exactly and under which menu it is found as it has been
quite a while since I used TBird.
indeed; it's C-U,
The most recent version on CRAN is already fixed. We had a
non-maintainer update end of March that fixed the R2HTML issues - the
maintainer was unresponsive to our requests, unfortunately.
Hence please update from CRAN.
Best,
Uwe Ligges
Romain Francois wrote:
Hi,
I'll try to fix this
On Thu, 28-May-2009 at 09:20AM +0200, Peter Dalgaard wrote:
Duncan Murdoch wrote:
On 27/05/2009 8:25 PM, Andrey Lyalko wrote:
How do I get removed from this mailing list?
Like most lists nowadays, it gives the instructions in each message header:
List-Unsubscribe:
Hello Uwe,
I have recently taken over maintenance of the package, which is now
version controlled at r-forge
(http://r-forge.r-project.org/projects/r2html/), and I am planning these
changes:
- rework the HTML function so that the html code is generated from a
brew template, which in time
Dear R users,
I have a matrix of both negative and positive values that I would like
to randomly sample with the following 2 conditions:
1. only sample positive values
2. once a cell in the matrix has been sampled the row and column of
that cell cannot be sampled from again.
#some dummy data
On 28/05/2009 5:03 AM, Gavin Simpson wrote:
On Thu, 2009-05-28 at 09:33 +0200, Wacek Kusnierczyk wrote:
Peter Dalgaard wrote:
Duncan Murdoch wrote:
On 27/05/2009 8:25 PM, Andrey Lyalko wrote:
How do I get removed from this mailing list?
Like most lists nowadays, it gives the instructions
p.plot is an S3 object and you are attempting to define an S4 class
so you if you really want to do that then you would need this to let
S4 know about the ggplot class:
# S4 class with S3 slot
setClass(ggplot) # make ggplot visible to S4
setClass(AClass, representation(mFirst = numeric, mSecond
Thomas Levine wrote:
I want to plot quantitative data as a function of three two-level factors.
How do I group the bars on a barplot by level through labeling and spacing?
Here http://www.thomaslevine.org/sample_multiple-factor_barplot.png's what
I'm thinking of. Also, I'm pretty sure that I
See http://cran.r-project.org/bin/windows/contrib/2.9/@ReadMe (ReadMe
files are there to be read!) and consider the use of RODBC, which is
used by lots of Oracle users as an R client on Windows.
On Thu, 28 May 2009, Madan Mohan wrote:
Hi Friends,
I am working on R-2.9.0 and i want to
On 28/05/2009 3:20 AM, bogaso.christofer wrote:
Hi,
Recently I come through those R-expressions and understood that 1L means
1 and 0L means 0. Why they are so? I mean, what the excess meanings
they carry, instead writing simple 1 or 0? Is there any more this kind
of expressions in R?
Gavin
On 28/05/2009 6:03 AM, Madan Mohan wrote:
Hi Friends,
I am working on R-2.9.0 and i want to connect oracle through R, but i could
not find ROracle (zip file for windows) on CRAN Packages. Can anyone suggest
me how to connect Oracle from R in windows platform? I would be grateful if
u can
I have a matrix of both negative and positive values that I would like
to randomly sample with the following 2 conditions:
1. only sample positive values
2. once a cell in the matrix has been sampled the row and column of
that cell cannot be sampled from again.
#some dummy data
http://cran.r-project.org/web/views/Survival.html
On May 11, 2009, at 1:46 PM, Nancy Tejerina wrote:
*Dear R Users;*
* *
*I´m writing to ask you how can I do Survivals Curves using Time-
dependent
covariates? Which packages I need to Install?*
*Thanks for your help, I look foward you
On May 28, 2009, at 6:33 AM, jos matejus wrote:
Dear R users,
I have a matrix of both negative and positive values that I would like
to randomly sample with the following 2 conditions:
1. only sample positive values
2. once a cell in the matrix has been sampled the row and column of
that
Will respond privately, since the thread becomes uninteresting for
R-help, I guess.
Uwe
Romain Francois wrote:
Hello Uwe,
I have recently taken over maintenance of the package, which is now
version controlled at r-forge
(http://r-forge.r-project.org/projects/r2html/), and I am planning
I'd like to be able to read multiple sheets from an excel workbook and use
the sheet name to name the resulting dataframe using RODBC. at the moment
i've figured out how to do it the long way (see below) but feel sure that
there is a speedier possibly automatic way to do it in R. i've tried to
How can I find out what survreg generates: the full likelihood or a
likelihood with unnecessary constants dropped?
Survreg returns a log-likelihood, not a deviance (LL with parameters dropped);
and the result is labeled as such.
It turns out that the deviance is not as easily defined for
Wacek Kusnierczyk wrote:
Gavin Simpson wrote:
The View message source would be a more direct way of viewing the full
email, not just the bits TBird shows you in the preview pane. I forget
how it is named exactly and under which menu it is found as it has been
quite a while since I used TBird.
Both of those worked, but hierobarp looked a bit easier, so I used that. The
one annoying thing is that it sorts alphabetically.
Tom
On Thu, May 28, 2009 at 6:46 AM, Jim Lemon j...@bitwrit.com.au wrote:
Thomas Levine wrote:
I want to plot quantitative data as a function of three two-level
Dear Ritchie and David,
Thanks very much for your advice. I had thought of this potential
solution, however it doesn't really fullfill my second criteria which
is that once a particular cell has been sampled, the row and column of
that cell can't be sampled from subsequently. In other words, the
This is one way of sampling all the values in the matrix that meet your
criteria:
set.seed(1)
(x - matrix(rnorm(100), 10))
[,1][,2][,3][,4] [,5]
[,6][,7] [,8] [,9] [,10]
[1,] -0.6264538 1.51178117 0.91897737 1.35867955
(diverted to r-devel, a source code patch attached)
Wacek Kusnierczyk wrote:
Allan Engelhardt wrote:
Immaterial, yes, but it is always good to test :) and your solution
*is* faster and it is even faster if you can assume byte strings:
:)
indeed; though if the speed is immaterial
simeon duckworth wrote:
I'd like to be able to read multiple sheets from an excel workbook and use
the sheet name to name the resulting dataframe using RODBC.
In Microsoft theory, something like the below should be ok (note the $), but
never managed to get this to work. The same method
Farley, Robert wrote:
I can't get the syntax that will allow me to show NA values (rows) in the
xtabs.
lengthy non-reproducible example removed
If you want a reproducible answer, prepare a reproducible result. And check
that the
syntax is
na.action=na.pass
Dieter
--
View this
My goal is for a user to sit down at a Linux laptop, get to an Rcmdr
type screen, submit jobs on a remote system and then get the results
back in R.
We will assume that the user is naive, and the only thing he/she can
do is get to the Rcmdr screen.
The Rcmdr plugin will have a submit jobs menu.
Good morning!
Which is the preferred method to leave a sourced script and returning back to
the '' prompt?
For example I search for certain files to be processed, but nothing should be
done if they
are not present. Normally I do in my script:
f-dir(pattern=qq)
if(length(f) 0) {
...process
From: Jeff Newmiller jdnew...@dcn.davis.ca.us
To: R Heberto Ghezzo, Dr heberto.ghe...@mcgill.ca
Date: Wed, 27 May 2009 09:00:44 -0700
Subject: Re: [R] R in Ubunto
R Heberto Ghezzo, Dr wrote:
Hello , I do not know anything abount Ubunto, but I found a Portable
Ubunto for Windows
hi there :)
i want to use barplot with if else but i dont know how to do it ?
i tried this but it is not working with me
SNP - read.table(my.txt)
SNP[,2]
[1] 1175 483 240 170 99 79 76 45 38 35 21 16 14 19 16
[16]333 10216868
On 5/28/2009 8:58 AM, Mario Valle wrote:
Good morning!
Which is the preferred method to leave a sourced script and returning back to the
'' prompt?
For example I search for certain files to be processed, but nothing should be
done if they
are not present. Normally I do in my script:
2009/5/28 Dieter Menne dieter.me...@menne-biomed.de:
If you only have the sheet names, you should use package xlsReadWrite which
is rather fast, but has some limitations in the non-commercial version.
what limitations, i.e. features do you miss?
Cheers,
Hans-Peter
Bill Dunlap
TIBCO Software Inc - Spotfire Division
wdunlap tibco.com
-Original Message-
From: r-devel-boun...@r-project.org
[mailto:r-devel-boun...@r-project.org] On Behalf Of Wacek Kusnierczyk
Sent: Thursday, May 28, 2009 5:30 AM
Cc: R help project; r-de...@r-project.org; Allan
Hans-Peter Suter wrote:
If you only have the sheet names, you should use package xlsReadWrite
which
is rather fast, but has some limitations in the non-commercial version.
what limitations, i.e. features do you miss?
Reading of named ranges.
Dieter
--
View this message in
Using the package rcom (by Thomas Baier) you can do everything you want
since you have the full power of COM at your disposal.
Dieter Menne wrote:
Hans-Peter Suter wrote:
If you only have the sheet names, you should use package xlsReadWrite
which
is rather fast, but has some limitations
Dear all ...
I need your help for the following purpose :
I would like to create regularly spaced points on a multi-segment line (a
'psp class' object).
A function of the spatstat library( = pointsOnLines() ) is dedicated to that
objective but the problem is that the probability of falling on
Hi,
I am new to R and am using quilt.plot (from fields package) to plot gas
concentrations in Europe.
I am using the following code to plot my data
library(maps)
library(fields)
test = read.csv(%change 1996_2005.txt, sep=\t)
colnames(test) = c(Station, Measurement_BaseO3, Model_BaseO3,
Dear R-list,
I know is going to be weird, but I need to do something about and I know
the R-list is big group of good people. Im moving to Philadelphia in
August 2009 (my fiancé is there) and I need to find a job. I know to do so
many things, but my skill is in science and research. I would like
Hello,
I am an R amateur.
I want to plot data such that the 3 time points(a,b,c) lie on the X-axis and
the values of these times points are on Y-axis for n samples (e.g.100).
So, I have an object x, dim 100 4, it is a dataframe (when checked the
class)
x =
name a b c
1
I want to plot data such that the 3 time points(a,b,c) lie on the X-axis
and
the values of these times points are on Y-axis for n samples (e.g.100).
So, I have an object x, dim 100 4, it is a dataframe (when checked the
class)
x =
name a b c
10.11 1.11 0.86
2
Will R be able to send one batch of commands to the remote machine, then wait
for the output? Or will there be back and forth with new commands based on the
output from the first commands?
You may want to look at the nws package for one way to have jobs run on a
remote machine.
--
Gregory
Hi,
I'm running R 2.7.2 on windows XP. I'd like to find the maximum of a
3-d array over it's third index to create a 2-d array. For example:
x - array(c(1,2,3,10,11,12,3:8),c(2,3,2))
x
, , 1
[,1] [,2] [,3]
[1,]13 11
[2,]2 10 12
, , 2
[,1] [,2] [,3]
[1,]3
Your last step will either be a single number (not really a sampling
operation) or a
non-positive number. So at best you really only have an number that
depends
entirely on the prior sequence of draws.
--
David.
On May 28, 2009, at 8:21 AM, jos matejus wrote:
Dear Ritchie and David,
On May 28, 2009, at 11:25 AM, eric lee wrote:
Hi,
I'm running R 2.7.2 on windows XP. I'd like to find the maximum of a
3-d array over it's third index to create a 2-d array. For example:
x - array(c(1,2,3,10,11,12,3:8),c(2,3,2))
x
, , 1
[,1] [,2] [,3]
[1,]13 11
[2,]2
Dear R-experts,
I need to replace in an expression the character Cl by Cl+beta
But in the following case:
form-expression((Cl-(V *ka) ) +(V *Vm *exp(-(Clm/Vm) *t)))
gsub(Cl,(Cl+beta),as.character(form))
We obtain:
[1] ((Cl+beta) - (V * ka)) + (V * Vm * exp(-((Cl+beta)m/Vm) * t))
Try matching on word boundaries as well:
gsub(\\bCl\\b,(Cl+beta),as.character(form))
[1] ((Cl+beta) - (V * ka)) + (V * Vm * exp(-(Clm/Vm) * t))
See ?regexp
On Thu, May 28, 2009 at 11:41 AM, Caroline Bazzoli
caroline.bazz...@inserm.fr wrote:
Dear R-experts,
I need to replace in an expression
Dear All,
I would like to visualize a tree extracted from a random forest using
getTree {randomForest}.
I'm wondering if there is any way to do it directly or to convert my tree
to any other class of tree repesentation, which then can be plotted?
Thank you in advance,
Karoly
On Thu, 28 May 2009 15:47:18 +0300 NOUF AL NUMAIR
noufalnum...@hotmail.com wrote:
NAN barplot(zz,width = 4,names.arg= xx,axes = TRUE, axisnames = TRUE,
NAN main=title,xlab=xlab,ylab=ylab,ylim=c(0,1175),xlim=c(0,226),col =
NAN c(for (i in zz){if i70 col= lightblue else col= mistyrose))
NAN
NAN
The package AMORE appears to be more flexible, but I got very poor
results using it when I tried to improve the predictive accuracy of a
regression model. I don't understand all the options well enough to be
able to fine tune it to get better predictions. However, using the
nnet() function in
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Caroline Bazzoli
Sent: Thursday, May 28, 2009 8:41 AM
To: r-help@r-project.org
Subject: [R] String replacement in an expression
Dear R-experts,
I need to replace in an expression the character Cl by
amor Gandhi wrote:
Hi gues,
This should read: Hi, guess what I want
amor Gandhi wrote:
Is there any function in R for boxplot with different time points?
t1 - c(rep(1,20),rep(2,20))
t2 - c(rep(1,10),rep(2,10),rep(1,10),rep(2,10))
x - rnorm(40,5,1)
dat - data.frame(t1,t2,x)
One additional question:
It seems that in practice the design effect is often calculated on the
response variable or on individual predictor variables. I have some OLS
models using observational data that are clustered. Does it make sense to
calculate the design effect on the residuals of one of
Hi:
I need some help with the legend. I got 14 samples(Muestreo) and I
am trying to plot a smooth line for each sample. I am able to accomplish that
but the problem is that the legend only displays every other sample. How can I
force the legend to show all of my Muestreos? Thanks in
Apologies once more, there was a slight error in our example. Here is a
correct version of how to color the points in qqmath according to another
variable.
qqmath(~ yield | variety, data = barley, groups=year,
auto.key=TRUE,
prepanel = function(x, ...) {
list(xlim =
I have a time series of about 1500 measurements. There are sporadic data
gaps. I would like to plot the time series with type line. I only want
a line to connect the periods with data; I don't want a line to connect
the points across a data gap. Is there a function or recommended method
to
Just place a point with an NA value between the two segments.
Here is one way to do it in zoo:
set.seed(123)
library(zoo)
# create sample data
tt - c(1:1000, 1200:2000)
z - zoo(rnorm(length(tt)), tt)
# this will fill in omitted values with NAs
z - as.zoo(as.ts(z))
plot(z)
On Thu, May 28,
Dear all
I am trying to install the gRain package on ubuntu 8.10,
running R Vers. 2.9. Unfortunately, I get a bad
Exit-Status. What could cause that problem?
Any help is appreciated.
Many thanks in advance.
A. Biedermann
install.packages(gRain)
Warnung in install.packages(gRain) :
Hi all,
Is there any way to keep numeric colnames as is? Any hint will be appreicated.
Xin Zheng
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the
Caroline Bazzoli wrote:
Dear R-experts,
I need to replace in an expression the character Cl by Cl+beta
But in the following case:
form-expression((Cl-(V *ka) ) +(V *Vm *exp(-(Clm/Vm) *t)))
gsub(Cl,(Cl+beta),as.character(form))
We obtain:
[1] ((Cl+beta) - (V * ka)) + (V * Vm *
?read.table check.names=FALSE
On Thu, May 28, 2009 at 3:25 PM, Zheng, Xin (NIH) [C] zheng...@mail.nih.gov
wrote:
Hi all,
Is there any way to keep numeric colnames as is? Any hint will be
appreicated.
Xin Zheng
[[alternative HTML version deleted]]
This really depends on where the 'X' is coming from, which you did not tell us
(see the posting guide).
For example, if the 'data.frame' function is the one adding the 'X', then you
can use the 'check.names' argument to prevent the addition (or you can use
data.frame with the argument to
Thank you guys. But I also want 'check.names' to help keeping colnames unique.
It seems there's no proper option for that in 'read.table'. I have to alter
colnames with strsplit or other similar functions.
From: jim holtman [mailto:jholt...@gmail.com]
Sent: Thursday, May 28, 2009 3:40 PM
To:
I have following addition :
1:2 + 1:10
[1] 2 4 4 6 6 8 8 10 10 12
I could not understand how R adding those two unequal vector? Any help?
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
substring(header, 2,) works for the purpose perfectly.
Xin Zheng
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
I am trying to use a linear filter to reduce loops and thereby increase
the speed of an existing program. However, while the filter function
(stats package) should have reduced the looping by about 30-fold, the
time to complete the program remained about the same. This surprised
me, because I
Bill Dunlap
TIBCO Software Inc - Spotfire Division
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Wacek Kusnierczyk
Sent: Thursday, May 28, 2009 12:31 PM
To: Caroline Bazzoli
Cc: r-help@r-project.org
Ah, that makes sense. But now another two issues have arisen.
Firstly, the error bars look like confidence intervals, and I'm pretty
sure that they are but does some document verify this? I suppose I
could check the code too.
Secondly, I just read about how dynamite plots should be avoided. It's
On 29/05/2009, at 8:00 AM, bogaso.christofer wrote:
I have following addition :
1:2 + 1:10
[1] 2 4 4 6 6 8 8 10 10 12
I could not understand how R adding those two unequal vector? Any
help?
Look at the help for ``+'' (?+) and look at ``Value''. There you will
see:
These
recycling rule: repeat the shorter element as many times as necessary,
all.equal(1:2 + 1:10 , rep(1:2, length=10) + 1:10)
# TRUE
HTH,
baptiste
On 28 May 2009, at 22:00, bogaso.christofer wrote:
I have following addition :
1:2 + 1:10
[1] 2 4 4 6 6 8 8 10 10 12
I could not
R recycles the shorter one to match the longer one:
1 2 3 4 5 6 7 8 9 10
+
1 2 1 2 1 2 1 2 1 2
=
2 4 4 6 6 8 8 10 10 12
R does this recycling in many cases, and it can sometimes trap the
unwary.
Sarah
On Thu, May 28, 2009 at 4:00 PM, bogaso.christofer
First, your example didn't work because fish_ByMuestreo didn't build
properly (deleting the first structure(list(data = bit solves
this).
To solve your plotting problem, note that as constructed, the Muestreo
column is numeric, whereas you seem to want to treat it as a factor.
Solution: convert
bogaso.christofer wrote:
I have following addition :
1:2 + 1:10
[1] 2 4 4 6 6 8 8 10 10 12
I could not understand how R adding those two unequal vector? Any help?
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Hi,
I think there's some rounding issue with returning the max column.
(running 2.9.0 on an Apple, but my buddy found it on his PC)
x - matrix(c(1234.568,1234.569,1234.567),1)
max.col(x)
[1] 2
x - matrix(c(12345.568,12345.569,12345.567),1)
max.col(x)
[1] 3
x -
Thanks for your help Mike, it works like a charm now!!
--- On Thu, 5/28/09, Mike Lawrence mike.lawre...@dal.ca wrote:
From: Mike Lawrence mike.lawre...@dal.ca
Subject: Re: [R] ggplot2 legend
To: Felipe Carrillo mazatlanmex...@yahoo.com
Cc: r-h...@stat.math.ethz.ch
Date: Thursday, May 28,
Dear All,
Many thanks for all your useful suggestions. Much appreciated.
Jos
2009/5/28 David Winsemius dwinsem...@comcast.net:
Your last step will either be a single number (not really a sampling
operation) or a
non-positive number. So at best you really only have an number that depends
Hi,
Sorry, I was too hasty. I see that the tolerance is in the
documentation (and that random is the default tie-breaker).
Would it be possible to allow tolerance to be a parameter?
thanks, Daryl
Daryl Morris wrote:
Hi,
I think there's some rounding issue with returning the max column.
Try reading the man page, which says:
Details
When ties.method = random, as per default, ties are broken at random. In
this case, the determination of a tie assumes that the entries are
probabilities: there is a relative tolerance of 1e-5, relative to the
largest (in magnitude, omitting
Sounds simple but haven't been able to find it in docs: is it possible to
sort a vector using a user-defined comparison function? Seems it must be,
but sort doesn't seem to provide that option, nor does order sfaics
--
View this message in context:
The warning I met with is attached here:
Warning message:
In heatmap.2(as.matrix(val.sf.ns[-1:-3]), Rowv = F, Colv = T, dendrogram =
column, :
Using scale=row or scale=column when breaks arespecified can produce
unpredictable results.Please consider using only one or the other.
What does
Hello, R users.
I have the following code:
a=1:10
b=-3:15
n=5
x - rep(0,n)
for (i in 1:n) x[i] - sum( outer(a,b, function(s,t) abs(a-b-i)==0) )
Can someone tell me if I could avoid the for command?
Thank you in advance.
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