Or, more general (if you need to include more than just one variable from
TestData), something like
by(TestData, LEAID, function(x) median(x$RATIO))
Agreed, this is less appealing for the given example than Ista's code, but
might help to better understand by and to generalize its use to other
Dear Sayan,
no, unfortunately I don't think it will.
Here's basically how coeftest() works: if you call the coeftest() function on a
model object, say: 'mymodel', it will apply both a 'coef' and a 'vcov' method
to mymodel in order to extract beta and vcov(beta) and do a Wald test.
Hi,
Just a quick note regarding google and R: I use www.rseek.org almost
exclusively, and it tends to give me the results I need. It is based on
google, but uses a number of smart tricks to ferret out R-relevant
information.
/Gustaf
--
Gustaf Rydevik, M.Sci.
tel: +46(0)703 051 451
Dear all,
I'm a lattice graphics newbie. I'm trying to make a cut through the 3D
scatterplot with cloud(), so adding a partially transparent plate
perpendicular to the z-axis in order to separate the cloud.
code:
library(lattice)
cloud(Sepal.Width~Petal.Length*Petal.Width, data=iris)
Could
Try the latex function in the Hmisc package. Using the state.*
variables built into R for sake of example:
library(Hmisc)
latex(table(state.division, state.region), rowlabel = X, collabel =
Y, file = )
On Wed, Dec 9, 2009 at 12:04 AM, Na'im R. Tyson nty...@clovermail.net wrote:
Dear
Dear R users,
again with the hope that this application can also be useful for some R
users,
i like to announce a new Windows version of the ecological modeling software
Bio7.
For information:
Bio7 uses a pure Rserve approach to interface Java and R and has a feature
rich GUI
to access and
On Mon, 7 Dec 2009 13:23:06 -0600 Mark Na mtb...@gmail.com wrote:
This worked very nicely (thanks for plyr, Hadley) but now I would like to
unlist my list into the individual dataframes, preferably with their
original names (data1, etc).
I've tried to do this with:
ldply(datalist,unlist)
Here is an example:
# create test data
N - 100
x - data.frame(a=sample(LETTERS, N, TRUE), b=sample(letters, N, TRUE),
+ c=as.numeric(1:N), d=runif(N))
system.time({
+ x.df - split(x, x$a) # split
+ print(sapply(x.df, function(a) sum(a$c)))
+ })
A B
On Wed, Dec 9, 2009 at 12:11 AM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
Here are a couple of solutions. The first uses by and the second sqldf:
Brilliant! Now I have a whole collection of solutions. I did a simple
performance comparison with a data frame that has 7929 lines.
The
On Wed, Dec 9, 2009 at 7:59 AM, Titus von der Malsburg
malsb...@gmail.com wrote:
On Wed, Dec 9, 2009 at 12:11 AM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
Here are a couple of solutions. The first uses by and the second sqldf:
Brilliant! Now I have a whole collection of solutions.
This is great!! Sqldf is exactly the kind of thing I was looking for,
other stuff.
I suppose you can speed up both functions 1 and 5 using aggregate and
tapply only once, as was suggested earlier. But it comes at the
expense of readability.
Nikhil
On 9 Dec 2009, at 7:59AM, Titus von
Dear all,
I have some error trying to bootstrap from a matrix. The error message is
Error in sample(n, n * R, replace = TRUE) : element 2 is empty;
the part of the args list of '*' being evaluated was: (n, R)
vv - c(0.5,3.2,5.4,1.1,1.4,1.2,2.3,2.0)
Reg - matrix(data=vv, nrow = 4, ncol = 2)
I missed number of bootstrap replicates R
boot(Reg, bootcoeff, R=10)
but still it doesn't work
Error in statistic(data, original, ...) : unused argument(s) (original)
On Wed, Dec 9, 2009 at 2:46 PM, Trafim Vanishek rdapam...@gmail.com wrote:
Dear all,
I have some error trying to bootstrap
On Tue, 2009-12-08 at 23:22 -0500, David Winsemius wrote:
On Dec 8, 2009, at 11:07 PM, rusers.sh wrote:
Hi,
In the following function, i hope to save my simulated data into the
result dataset, but why the final result dataset seems not to be
generated.
#Function
Dear support,
I want to compute the highest probability density for any data. please do you
have any code to help me in this subject.
I am looking forward to hearing from you as soon as possible.
rahim
[[alternative HTML version deleted]]
I somehow missed the response posted by Ben Bolker. He is quite correct
(happily for me!):
\SweaveOpts{keep.source=TRUE}
in your LaTeX code will (I think) keep whatever manual formatting you do,
in all code chunks (or use keep.source=TRUE) for particular code chunks
of concern
This
?density
?max
Rahim Alhamzawi rahimalhamz...@yahoo.co.uk
Sent by: r-help-boun...@r-project.org
12/09/2009 05:23 AM
To
r-h...@stat.math.ethz.ch
cc
Subject
[R] code
Dear support,
I want to compute the highest probability density for any data. please do
you have any code to help me in
In the nodes of the tree, the values of the covariates are represented
with a, b or c (tree attached).
Try help('text.rpart'), and note the 'pretty' argument therein.
There is often not enough room for long labels, and so the default is to
do the severe truncation you speak of.
Terry Therneau
A Singh wrote:
Dear List,
I need to print out each of 'k' levels of a factor 'n' times each, where
'n' is the number of elements belonging to each factor.
I know that this can normally be done using the gl() command,
but in my case, each level 'k' has an unequal number of elements.
On Dec 9, 2009, at 9:05 AM, Trafim Vanishek wrote:
I missed number of bootstrap replicates R
boot(Reg, bootcoeff, R=10)
but still it doesn't work
Error in statistic(data, original, ...) : unused argument(s)
(original)
On Wed, Dec 9, 2009 at 2:46 PM, Trafim Vanishek
rdapam...@gmail.com
Hi All,
I'm trying to write ug/m3 as y-label, with greek letter mu replacing u
AND 3 going as a power.
These commands works in general:
plot.new()
text(0.5, 0.5, expression(symbol(m)))
But, I'm sure about how to do it using barchart() from Lattice. Can anyone
help please?
Thanks,
Peng Cai
Hi,
try this,
barchart(1:2, ylab=expression(mu*g/m^3))
?plotmath
baptiste
2009/12/9 Peng Cai pengcaimaill...@gmail.com:
Hi All,
I'm trying to write ug/m3 as y-label, with greek letter mu replacing u
AND 3 going as a power.
These commands works in general:
plot.new()
text(0.5, 0.5,
I have following the message dim(refdata) and dimnames(refdata) no
longer allow parameter ref=TRUE, use dim(derefdata(refdata)),
dimnames(derefdata(refdata)) instead when I loaded data.table. Is it
from the package ref? Could it be fixed? Or there is something wrong
with my installation?
On Tue, Dec 8, 2009 at 11:06 PM, David Winsemius dwinsem...@comcast.net wrote:
On Dec 9, 2009, at 12:00 AM, Peng Yu wrote:
On Tue, Dec 8, 2009 at 10:37 PM, David Winsemius dwinsem...@comcast.net
wrote:
On Dec 8, 2009, at 11:28 PM, Peng Yu wrote:
I have the following code, which tests the
Dear R helpers,
I am new in R and I am having trouble with a function.
I am proggraming a genetic analysis and there is a script that generates a
lot of different matrix, for example x,y and z.
And what I am trying to do is to loop the same script for different
variables the user will define in
On Tue, Dec 8, 2009 at 11:05 PM, David Winsemius dwinsem...@comcast.net wrote:
On Dec 8, 2009, at 11:37 PM, Peng Yu wrote:
I want to split a matrix, where both 'u' and 'w' are results of
possible ways. However, whenever 'n' changes, the argument passed to
mapply() has to change. Is there a
Hi Baptiste and Others,
Thanks for your help. I'm writing:
ylab=expression(Concentration(mu*g/m^3))
And its working fine, but is it possible to add a space between
Concentration and (mu*g/m^3).
Thanks again,
Peng Cai
On Wed, Dec 9, 2009 at 12:02 PM, baptiste auguie
On Wed, 9 Dec 2009, Peng Yu wrote:
On Tue, Dec 8, 2009 at 11:06 PM, David Winsemius dwinsem...@comcast.net wrote:
On Dec 9, 2009, at 12:00 AM, Peng Yu wrote:
On Tue, Dec 8, 2009 at 10:37 PM, David Winsemius dwinsem...@comcast.net
wrote:
On Dec 8, 2009, at 11:28 PM, Peng Yu wrote:
I have
Hello Elijah,
You could have not made me happier with your letter.
It is a very satisfying compliment for me to be appreciated in general, and
specifically by you.
I will start by responding to the simpler parts of your e-mail and the
proceed into the more interesting parts.
My response grew to
Hi,
Is there any equivalent for ifelse (except if (cond) expr1 else expr2) which
takes an atomic element as argument but returns vector since ifelse returns an
object of the same length as its argument?
x = c(1,2,3)
y = c(4,5,6,7)
z = 3
ifelse(z = 3,x,y)
would return x and not 1
thanks
barchart(1:2, ylab=expression(Concentration (*mu*g/m^3*)))
2009/12/9 Peng Cai pengcaimaill...@gmail.com:
Hi Baptiste and Others,
Thanks for your help. I'm writing:
ylab=expression(Concentration(mu*g/m^3))
And its working fine, but is it possible to add a space between
Concentration and
Try this:
list('TRUE' = x, 'FALSE' = y)[[as.character(as.name(z = 1))]]
On Wed, Dec 9, 2009 at 3:40 PM, carol white wht_...@yahoo.com wrote:
Hi,
Is there any equivalent for ifelse (except if (cond) expr1 else expr2) which
takes an atomic element as argument but returns vector since ifelse
Thanks, it worked!
On Wed, Dec 9, 2009 at 12:46 PM, baptiste auguie
baptiste.aug...@googlemail.com wrote:
barchart(1:2, ylab=expression(Concentration (*mu*g/m^3*)))
2009/12/9 Peng Cai pengcaimaill...@gmail.com:
Hi Baptiste and Others,
Thanks for your help. I'm writing:
On Dec 9, 2009, at 12:40 PM, carol white wrote:
Hi,
Is there any equivalent for ifelse (except if (cond) expr1 else
expr2) which takes an atomic element as argument but returns vector
since ifelse returns an object of the same length as its argument?
x = c(1,2,3)
y = c(4,5,6,7)
z = 3
On Wed, Dec 9, 2009 at 11:20 AM, Charles C. Berry cbe...@tajo.ucsd.edu wrote:
On Wed, 9 Dec 2009, Peng Yu wrote:
On Tue, Dec 8, 2009 at 11:06 PM, David Winsemius dwinsem...@comcast.net
wrote:
On Dec 9, 2009, at 12:00 AM, Peng Yu wrote:
On Tue, Dec 8, 2009 at 10:37 PM, David Winsemius
On 09/12/2009 12:40 PM, carol white wrote:
Hi,
Is there any equivalent for ifelse (except if (cond) expr1 else expr2) which
takes an atomic element as argument but returns vector since ifelse returns an
object of the same length as its argument?
I don't understand what's wrong with if
http://n4.nabble.com/file/n956255/TimeSeries%2BLikelihood.jpg
From the attachment, I need to find out the maximum likelihood value of ξ,
while I stuck to write in R codes. I will appreciate of experts advices.
Thanks.
ryusuke wrote:
To R programming experts,
I am a undergraduate
David Winsemius wrote:
On Dec 9, 2009, at 12:40 PM, carol white wrote:
Hi,
Is there any equivalent for ifelse (except if (cond) expr1 else
expr2) which takes an atomic element as argument but returns vector
since ifelse returns an object of the same length as its argument?
x =
Thanks, all, for the help. Much obliged. I realize now that I should
have said that I am using lattice graphics. The par() command has not
been helpful in convincing lattice to plot outside of the default
window. Any other advice is appreciated. Thanks again.
[[alternative HTML
I think that we are talking past each other here. You are clearly not
understanding (or at least convinced by) what I am saying, and you are not
convincing me (or possibly I am not understanding your arguments). So our
efforts will probably be better spent on things other than continuing this
Gunnar,
Did you find a solution, I'm facing the same problem (would like to load
2868 files in one go). Is it a bug, or just something that should be
documented in the help. Also, the error message is misleading, as it say
it «cannot find» a certain file (the name given here is truncated in my
There is an hpd function in the TeachingDemos package that may do what you
want. There are other hpd related functions in other packages as well. Which
will work best for you depends on details that you did not provide.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain
Dear R users,
I am having a minor but annoying issue with R.app. It doesn't retain
the history information from the previous sessions. By history, I
mean a record of commands/functions entered into R rather than the
list of objects--that is properly recorded in the .Rdata file as well
as in a
How would I make a population histogram in R from an excel file? Thanks
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
On Dec 9, 2009, at 12:14 PM, Peng Yu wrote:
On Tue, Dec 8, 2009 at 11:05 PM, David Winsemius dwinsem...@comcast.net
wrote:
On Dec 8, 2009, at 11:37 PM, Peng Yu wrote:
I want to split a matrix, where both 'u' and 'w' are results of
possible ways. However, whenever 'n' changes, the argument
Geert Janssens janssens-geert at telenet.be writes:
Hi,
I'm quite new to the R-project. I was suggested to look into it because I am
trying to solve the Subset sum problem, which basically is:
Given a set of integers and an integer s, does any non-empty subset sum to s?
(See
I just experimented and I find that, exactly as Maria described,
on my system no commands get added to .Rhistory when I start R using
the GUI.
The ``timestamp'' that is implemented in my .Rprofile gets added, but
no commands
that I typed in the GUI window appeared.
I had never noticed
Maria,
Try changing the name of .Rhistory in the Startup preferences to something like
.Rosxhistory. Press enter to make sure the change is accepted and try again.
The problem is that R itself overwrites the file .Rhistory if it is told to
save the workspace.
Rob
On Dec 9, 2009, at 10:33
On Tue, Dec 8, 2009 at 10:37 PM, David Winsemius dwinsem...@comcast.net wrote:
On Dec 8, 2009, at 11:28 PM, Peng Yu wrote:
I have the following code, which tests the split on a data.frame and
the split on each column (as vector) separately. The runtimes are of
10 time difference. When m and
Thanks very very much. It is really not easy to change from one language to
another. :)
2009/12/9 Gavin Simpson gavin.simp...@ucl.ac.uk
On Tue, 2009-12-08 at 23:22 -0500, David Winsemius wrote:
On Dec 8, 2009, at 11:07 PM, rusers.sh wrote:
Hi,
In the following function, i hope to
Hi.
I am having difficulty creating a formula for use with glm()
I have a matrix of an unknown number of columns and wish to estimate a
coefficient for each column, and one for the each product of a column
with another column.
In the case of a five-column matrix this would be:
x -
On Dec 9, 2009, at 2:22 PM, Dr R.K.S. Hankin wrote:
Hi.
I am having difficulty creating a formula for use with glm()
I have a matrix of an unknown number of columns and wish to estimate a
coefficient for each column, and one for the each product of a column
with another column.
In the case
On Dec 9, 2009, at 2:59 PM, Peng Yu wrote:
On Tue, Dec 8, 2009 at 10:37 PM, David Winsemius dwinsem...@comcast.net
wrote:
On Dec 8, 2009, at 11:28 PM, Peng Yu wrote:
I have the following code, which tests the split on a data.frame and
the split on each column (as vector) separately. The
The new version 0.7 of our RobASt-family of packages is available on
CRAN for several days. As there were many changes we will only sketch
the most important ones here. For more details see the corresponding
NEWS files (e.g. news(package = RobAStBase) or using function NEWS
from package
On Wed, 9 Dec 2009, Peng Yu wrote:
On Wed, Dec 9, 2009 at 11:20 AM, Charles C. Berry cbe...@tajo.ucsd.edu wrote:
On Wed, 9 Dec 2009, Peng Yu wrote:
On Tue, Dec 8, 2009 at 11:06 PM, David Winsemius dwinsem...@comcast.net
wrote:
On Dec 9, 2009, at 12:00 AM, Peng Yu wrote:
On Tue, Dec 8,
I'd like to announce the availability of the new doMPI package, a
parallel backend for the foreach package, which acts as an adaptor to
the Rmpi package. The package has been uploaded to CRAN and is now
available.
Like the doSNOW package, doMPI allows you to execute foreach loops
in parallel
Hi All,
I have a question regarding re-ordering legend labels, I'm not sure if it
would be possible to do what I'm thinking...
Using the following code, I reordered labels for the legend:
Now in the stacked bars, we see 1931 values are plotted below 1932 whereas
in legend 1931 comes above 1932.
Hi all,
I have a somewhat confusing question that I was wondering if someone
could help with. I have a pre-defined environment with some variables,
and I would like to define a function, such that when it is called, it
actually manipulates the variables in that environment, leaving them
to be
I see 'library(stats)' at the beginning of
R-2.10.0/src/library/stats/tests/nls.R.
I'm wondering if I am developing my own package 'mypackage' whether I
should put 'library(mypackage)' in a .R file in mypackage/tests/? If I
do, then it seems awkward to me, because to use 'library(mypackage)',
I
e - new.env()
e$x - 2
f - function(a, e) { e$x - e$x + a; e$x }
f(3, e)
e$x # 5
Another way to accomplish this is to use the proto package which puts
the whole thing into an object oriented framework. See
http://r-proto.googlecode.com
library(proto)
p - proto(x = 2, f = function(this, a) {
Ideally I would like to be able to use the function f (in my example)
as-is, without having to designate the environment as an argument, or
to otherwise have to use e$x in the function body.
thanks for any further advice...
On Wed, Dec 9, 2009 at 2:36 PM, Gabor Grothendieck
1. Read the posting guide:
http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
2. Did you installed R?
2.1. Case yes, go to the help, click on Manual in PDF
bests
miltinho
On Wed, Dec 9, 2009 at 1:47 PM, terry johnson
terry.johnson@gmail.comwrote:
On Wednesday 9 December 2009, Hans W Borchers wrote:
Geert Janssens janssens-geert at telenet.be writes:
Hi,
I'm quite new to the R-project. I was suggested to look into it because I
am trying to solve the Subset sum problem, which basically is:
Given a set of integers and an integer s,
You could write a wrapper function that accepts the output of the
function you don't want to change and then sets the values.
# f is function we don't want to change
f - function(a) x + a
wrapper - function(x, e) {
environment(f) - e
e$x - f(x)
}
e - new.env()
e$x - 2
wrapper(3, e)
e$x #
I've also made some comparisons and taking into account execution
time, sqldf wins. SummaryBy is better then aggregate in some specific
situations I met in practice. I present this situation below. It
assumes, that there are at least two groups with high number of
levels.
n-10;
Hello,
This is a problem for which there seem to be several solutions online, but
not really. My question was about plotting a curve over the histogram. All
the previous posts and messages talk about generating a *density
histogram*using (freq=F) and then plotting the density curve. However,
I
Hi all,
I'm logging into a Debian server and running R remotely using ESS. The
steps I use to do this are below (pasted from my webpage). However,
we're having a problem whenever we want to use the help function,
e.g.,
?hist
The remote buffer gives a warning:
WARNING: terminal is not fully
Gabor,
Thanks for the advice. Using the 'rowlabel' switch works, but when
used with the 'collabel' switch, I received the following error in
Latex 2e:
! LaTeX Error: Illegal character in array arg.
The line that LaTeX has issue with is:
\multicolumn{1}{observed}{uh}
The entire table
On 10/12/2009, at 12:52 PM, Gaurav Moghe wrote:
Hello,
This is a problem for which there seem to be several solutions
online, but
not really. My question was about plotting a curve over the
histogram. All
the previous posts and messages talk about generating a *density
histogram*using
On 09-Dec-09 23:52:20, Gaurav Moghe wrote:
Hello,
This is a problem for which there seem to be several solutions online,
but not really. My question was about plotting a curve over the
histogram.
All the previous posts and messages talk about generating a *density
histogram* using (freq=F)
On Wed, 9 Dec 2009, David Reiss wrote:
Ideally I would like to be able to use the function f (in my example)
as-is, without having to designate the environment as an argument, or
to otherwise have to use e$x in the function body.
thanks for any further advice...
Perhaps you want something
There are a number of functions that are dispatched to from split().
methods('split')
[1] split.data.frame split.Date split.defaultsplit.POSIXct
Is there a way to figure out which of these variants is actually
dispatched to when I call split? I know that if the argument is of the
type
On Dec 9, 2009, at 9:21 PM, casperyc wrote:
does no one know this?
Have you read the Posting Guide?
--
View this message in context:
http://n4.nabble.com/confint-for-glm-general-linear-model-tp954071p956658.html
Sent from the R help mailing list archive at Nabble.com.
David Winsemius,
Both of these applications fulfill a great need of mine: to read data
directly from google spreadsheets that are private to myself and one or two
collaborators. Thanks to the authors. I had been using RGoogleDocs for the
about 6 months (maybe more) but have had to stop using it in the past month
I think the help page are exactly the same...
I just want to verify the confidence interval manually. That's all I want.
Thanks.
casper
brestat wrote:
This functions are different. I advice you study them:
?confint # profile likelihood
?confint.default # t-distribution
Walmes
On Dec 9, 2009, at 9:50 PM, casperyc wrote:
I think the help page are exactly the same...
I cannot tell what you maen by this.
I just want to verify the confidence interval manually. That's all I
want.
Then provide some reproducible code and data. ... as the Posting Guide
explains
I make a version for matrix. Because, it would be more efficient to
split each column of a matrix than to convert a matrix to a data.frame
then call split() on the data.frame. Note that the version for a
matrix and a data.frame is slightly different. Would somebody add this
in R as well?
Sorry. I sent this to r-help by mistake. Could somebody help delete it
from the archive?
On Wed, Dec 9, 2009 at 9:29 PM, Peng Yu pengyu...@gmail.com wrote:
I make a version for matrix. Because, it would be more efficient to
split each column of a matrix than to convert a matrix to a data.frame
I am working with a somewhat complicated structure in which
I need to deal with a function that takes ``basic'' arguments
and also depends on a number of parameters which change depending
on circumstances.
I thought that a sexy way of dealing with this would be to assign
the parameters as
2009/11/22 Uwe Ligges lig...@statistik.tu-dortmund.de:
Either use local as in:
n=10
local(for(i in 1:n){
n=3
print(n)
})
print(n)
'local()' makes everything inside it unavailable outside of it. Is
there a way to make 'n' unavailable outside but still make 'b'
available outside
I did a search on www.rseek.org to look for the function to test if a
vector is ordered or not. But I don't find it. Could somebody let me
know what function I should use?
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
Hi - I'm having difficulty with frequencies in R. I have a table with a
variable (column) called difference 600 observations (rows). I would like
to know how many values are -0.5 as well as how many are 0.5. The rest
are obviously in the middle.
In SAS I could this immediately but am unable to
This functions are different. I advice you study them:
?confint # profile likelihood
?confint.default # t-distribution
Walmes Zeviani - Brazil
casperyc wrote:
Hi,
I have a glm gives summary as follows,
Estimate Std. Errorz valuePr(|z|)
On Wednesday 9 December 2009, Hans W Borchers wrote:
Geert Janssens janssens-geert at telenet.be writes:
Hi,
I'm quite new to the R-project. I was suggested to look into it because I
am trying to solve the Subset sum problem, which basically is:
Given a set of integers and an integer s,
Hi,
Guarav
go for this site.He is the one designed R.
http://www.stat.auckland.ac.nz/~ihaka/courses/120/lectures.html
http://www.stat.auckland.ac.nz/~ihaka/?Teaching
It might be helpful.I am not sure.
thanks.
--
View this message in context:
Hi there
I have a dataframe of a whole lot of variables
lets say, one of my variables is gender
how do I simply get an average of all other variables by gender?
--
View this message in context:
http://n4.nabble.com/simple-data-manipulation-question-tp956600p956600.html
Sent from the R help
Hi,
This is the time series data collected from 2001 to 2008 by every
month.so,there are 96 entries.I have done basic statistics.I need to find a
model fitted to forecast this data.This is the mixedpaper collection for
recycling in the campus.
13251
13754
19061
12631
17414
21350
On Dec 9, 2009, at 10:10 PM, Peng Yu wrote:
I did a search on www.rseek.org to look for the function to test if a
vector is ordered or not. But I don't find it. Could somebody let me
know what function I should use?
If by ordered, you mean sorted, then ?is.unsorted
is.unsorted(c(1, 4, 2,
Geert Janssens janssens-geert at telenet.be writes:
On Wednesday 9 December 2009, Hans W Borchers wrote:
Geert Janssens janssens-geert at telenet.be writes:
[ ... ]
Has anybody tackled this issue before in R ? If so, I would be very
grateful if you could share your solution with me.
R uses lexical scoping, not dynamic scoping. It does not matter where
bar is called from. What matters is where bar was defined and since
bar was defined in the global environment that is where its free
variables are looked up thus environment(bar) is the global
environment. Try changing foo to
Try
all(diff(order(yourVector)) == 1)
On Wed, Dec 9, 2009 at 10:10 PM, Peng Yu pengyu...@gmail.com wrote:
I did a search on www.rseek.org to look for the function to test if a
vector is ordered or not. But I don't find it. Could somebody let me
know what function I should use?
On Wed, Dec 9, 2009 at 9:43 PM, Rolf Turner r.tur...@auckland.ac.nz wrote:
I am working with a somewhat complicated structure in which
I need to deal with a function that takes ``basic'' arguments
and also depends on a number of parameters which change depending
on circumstances.
I thought
x - runif(10, 0, 1)
x2 - x 0.5
x2
[1] TRUE TRUE FALSE FALSE FALSE TRUE TRUE FALSE TRUE FALSE
table(x2)
x2
FALSE TRUE
5 5
On Wed, Dec 9, 2009 at 6:36 PM, BIGBEEF martin.beze...@gmail.com wrote:
Hi - I'm having difficulty with frequencies in R. I have a table with a
On 12/10/2009 05:47 AM, terry johnson wrote:
How would I make a population histogram in R from an excel file? Thanks
Hi Terry,
library(gdata)
ozpop-read.xls(ozpop.xls)
xycol-color.gradient(c(0,0,0.5,1),c(0,0,0.5,1),c(1,1,0.5,1),18)
On 12/10/2009 10:36 AM, BIGBEEF wrote:
Hi - I'm having difficulty with frequencies in R. I have a table with a
variable (column) called difference 600 observations (rows). I would like
to know how many values are -0.5 as well as how many are 0.5. The rest
are obviously in the middle.
In SAS I
On 12/10/2009 04:39 PM, Jim Lemon wrote:
On 12/10/2009 05:47 AM, terry johnson wrote:
How would I make a population histogram in R from an excel file? Thanks
Hi Terry,
library(gdata)
ozpop-read.xls(ozpop.xls)
xycol-color.gradient(c(0,0,0.5,1),c(0,0,0.5,1),c(1,1,0.5,1),18)
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