Thanks. I switched to ggplot2 which offers error bars.
Joh
Dieter Menne wrote:
Johannes wrote:
How can I, given the code snippet below, draw the error bars in the
center of each grouped bar rather than in the center of the group?
http://markmail.org/message/oljgimkav2qcdyre
Hi,
it's generally considered a bad practice but try this,
eval(parse(text=AA))
library(fortunes)
fortune(106)
HTH,
baptiste
On 10 March 2010 07:46, jq81 jingqia...@gmail.com wrote:
My question is represented by the following example.
For example, I have a character string a, which is
To include code in a shared object on x86_64 Linux it must be compiled
with -fPIC (or -fpic), as the error message said quite explicitly.
You seem only to have static netlib libraries: you need dynamic ones
if you installed these from a binary package. However,
'/apps/netcdf/4.0.1/gcc/lib'
Hi all and thanks for your answers.
It is my first attempt to do this kind of transfer and oth machines are 32
bit. The size of my data is 92,3 Mb and I did not try to restart. However,
Steve you are right, I have not installed the same packages in both
computers. Moreoer, I have not used the
Hi
r-help-boun...@r-project.org napsal dne 09.03.2010 22:44:31:
Hi list!
I have recently tried to take my office work home, meaning that I tried
to
transfer my ... .RData workspace from my PC on my laptop. The office
PC
runs on Windows XP and my laptop runs on Windows Vista. I have
Hello,
I'd like to sitch to a monochrome/bw color-palette for the filling of
geom_bar-bars (produced via qplot as in the example below). Hours of
googling didn't yield anything useful, so I thought, I'd just ask ...
Thanks, Joh
library(ggplot2)
qplot(factor(cyl), data=mtcars, geom=bar,
Dear all
recently I tried to split vector of dates according to some particular
date to 2 (more) chunks, but I was not able to perform correct setting.
When I want split to 3 chunks it partially works however from help page I
supposed to get result without NA.
Details:
Using both ‘right
Dear Ben
I haven't looked at the profiles yet, I'm not sure how to.
I'm doing population reconstruction from age-at-harvest data. I'm using a
multinomial distribution to model the observed harvest numbers.
But I didn't know about the Dirichlet-Multinomial so far. I think that might
really be a
Dear all,
I'm trying to write tabular data to a text file, these data will be
the input of a Fortran program. The format needs to be
(i7,2x,7(e15.7,2x)). I have not been able to find a clean way of
producing this output with write.table. I searched for a
write.fortran function similar to
Hi,
last_plot() + scale_fill_grey()
should do it
HTH,
baptiste
On 10 March 2010 09:46, Johannes Graumann johannes_graum...@web.de wrote:
Hello,
I'd like to sitch to a monochrome/bw color-palette for the filling of
geom_bar-bars (produced via qplot as in the example below). Hours of
Indeed. Thank you. Is there a global switch analogous to
theme_set(theme_bw())?
thanks for your help, Joh
On Wednesday 10 March 2010 10:29:05 baptiste auguie wrote:
Hi,
last_plot() + scale_fill_grey()
should do it
HTH,
baptiste
On 10 March 2010 09:46, Johannes Graumann
It worked with the installation of the proper packages!!!
Thanks a lot!
Eleni
On Wed, Mar 10, 2010 at 10:48 AM, Petr PIKAL petr.pi...@precheza.cz wrote:
Hi
r-help-boun...@r-project.org napsal dne 09.03.2010 22:44:31:
Hi list!
I have recently tried to take my office work home, meaning
On Windows, you also could consider installing a statconnDCOM server on
one Windows machine and have the users access this server (e.g. from
within Excel). You would need to set up the correct (D)COM
configuration, which is not trivial.
On 3/9/2010 8:24 PM, Uwe Ligges wrote:
On 08.03.2010
ComRades,
On a recent Windows XP system that I have to use at work, I installed Tinn-R
2.3.4.4 and R 2.10.1
When I mark-select a piece of code, say
summary(x)
written in Tinn-R and send it to the RGui using the send button, the RGui
console instead of showing me my piece of code, it shows
not with the theme, as far as I know, but you can do:
set_default_scale(fill, discrete,grey)
baptiste
On 10 March 2010 10:31, Johannes Graumann johannes_graum...@web.de wrote:
Indeed. Thank you. Is there a global switch analogous to
theme_set(theme_bw())?
thanks for your help, Joh
On
Hi the list
I define a S3 function that can have a various number of argument using
'...'
When some arguments are missing, I would like to give them some default
value:
func.numeric - function(x,...){
if(missing(y)){y-3}
}
But it does not works...
I precise that I can not put 'y'
On Wed, 10 Mar 2010, Christophe Genolini wrote:
Hi the list
I define a S3 function that can have a various number of argument using '...'
When some arguments are missing, I would like to give them some default
value:
func.numeric - function(x,...){
if(missing(y)){y-3}
}
But it does not
sample report data that i want to forecast
quarter quarter_index Revenue
2007 Q1 1 $3,856,799
2007 Q2 2 $4,243,328
2007 Q3 3 $4,930,369
2007 Q4 4 $5,443,579
2008 Q1
k == kMan kchambe...@gmail.com
on Tue, 9 Mar 2010 19:52:40 -0700 writes:
k Dear Dhruv, Your clarification helps, and I'm
k stumped. Sorry I cannot be of more help.
k Sincerely, KeithC.
I'd say *The* answer is to use model.matrix()
This allows to use R's powerful model
Works. Thank you!
Joh
On Wednesday 10 March 2010 11:13:09 you wrote:
not with the theme, as far as I know, but you can do:
set_default_scale(fill, discrete,grey)
baptiste
On 10 March 2010 10:31, Johannes Graumann johannes_graum...@web.de wrote:
Indeed. Thank you. Is there a global
Sure. Say your sample data is a dataframe called sampledata:
sampledata$revenuePredictor - 4032525
You might want to use a different model to predict revenue, though.
On Wed, Mar 10, 2010 at 11:59 AM, chinna durgache...@gmail.com wrote:
sample report data that i want to forecast
quarter
The sqldf package can be used to manipulate R data frames with SQL
statements. See http://sqldf.googlecode.com
On Tue, Mar 9, 2010 at 9:36 PM, James Marca jma...@translab.its.uci.edu wrote:
Hello,
I do not understand the correct way to approach the following problem
in R.
I have
Dear all,
I am new in the R environment. How can I enable political boundaries in R?
I want plot a variable (e.g., temperature) only for Mozambique.
Sincerely,
Arlindo
Arlindo
Veja
baptiste auguie-5 wrote:
I'm trying to write tabular data to a text file, these data will be
the input of a Fortran program. The format needs to be
(i7,2x,7(e15.7,2x)). I have not been able to find a clean way of
producing this output with write.table. I searched for a
write.fortran
Dear forum:
I've been trying like for hours but I cannot solve this. I wonder if you could
give me a hand.
I would like to combine the following elements of an array which I must
generate in order to get the syntax I need for another software, lets say:
c-c(1:7)
zest-c(12,34,45,132,56,23,6)
baptiste auguie-5 wrote:
This is a lot easier
for(k in
seq(1,nrow(m))){cat(c(sprintf(%7d,m[k,1]),sprintf(%16.7e,m[k,2:8]),\n))
Berend
Oops.
Missing sep= and closing }.
The correct line is
for(k in
seq(1,nrow(m))){cat(c(sprintf(%7d,m[k,1]),sprintf(%16.7e,m[k,2:8]),\n),sep=)}
On Tue, 2010-03-09 at 15:59 -0800, mramon wrote:
Anyone know if it is possible to get the R scripts used in the The Elements
of
Statistical Learning book? It is a great book but sometimes some help would
be useful to replicate the results presented in the book and so, understood
things
Hello,
If you do this after the for loop, you'll get what you want:
paste(tre,collapse=)
(you can use whatever separator you want in the collapse argument)
But you don't even need the for loop, just do this instead of the for loop:
paste(con(,p, == ,c,, ,zest,, ,sep=,collapse=)
Best,
Miguel
On Wed, 2010-03-10 at 11:28 +0100, Christophe Genolini wrote:
Hi the list
I define a S3 function that can have a various number of argument using
'...'
When some arguments are missing, I would like to give them some default
value:
func.numeric - function(x,...){
There is likely something wrong with your R installation.
tcltk is a recommended package and normally comes bundled with R. You
should not have to install it separately.
Try reinstalling R.
Alternately, try the older version of gsubfn at:
On Mar 10, 2010, at 5:43 AM, Achim Zeileis wrote:
On Wed, 10 Mar 2010, Christophe Genolini wrote:
Hi the list
I define a S3 function that can have a various number of argument
using '...'
When some arguments are missing, I would like to give them some
default value:
func.numeric -
Dear R users,
I have the following data frame:
PROCHIdate_admission
2 CAO713 1999-12-11
4 CAO713 1999-10-25
21 CAO0001743 1989-05-04
25 CAO0001743 1996-09-12
26 CAO0001743 1989-05-17
27 CAO0001743 1987-09-17
28 CAO0001743 1987-09-19
I have the following function that makes use of lazy loading.
foo - function(x=2*y, y=x/2) cat(x,y)
Now I want to be able to modify it like below:
foo(y=x/3)
Of course, this does not work as the object x is not known. Still I
would like to be able to pass a function as an argument that is
Hi Melanie,
I think you just need
merge(TABLE1, TABLE2)
see ?merge for details.
-Ista
On Wed, Mar 10, 2010 at 12:47 AM, Melanie HAMEL melanie.ha...@ird.fr wrote:
Dear all,
I would like to solve a trivial problem (I guess it is) but can't find the
right way. Maybe someone can help me ?
I'm not sure what's incorrect about your result, but the following works:
d=data.frame(a=sample(letters[1:5],10,rep=T),b=rnorm(10),c=sample(1:10,10));
d
d[order(d$a,d$c),]
or, you can use orderBy:
lib(doBy)
orderBy(~a+b,data=d) #use a - sign to sort in descending sequence
Did you leave off the
Thanks, it is indeed a bit cleaner. I was hoping for a more generic
solution but I guess people use cat() and sprintf() in such cases.
Thanks,
baptiste
On 10 March 2010 12:46, Berend Hasselman b...@xs4all.nl wrote:
baptiste auguie-5 wrote:
This is a lot easier
for(k in
Hi,
can u please elaborate your answer.
using the first report i have to generate second report for the year 2010
quarterly forecasted results.
Thanks in advance.
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Sent from the R help
Hard to say. You might want to run a profile of each set of code and see
where it is spending its time. It looks like from the R code that they are
using vectorized operations and depending on how some of them are
implemented, they might be calling C code to do most of the work. With the
proper
You probably need a shapefile, or other geographic representation for the
administrative boundaries, you can find a shapefile here:
http://www.maplibrary.org/stacks/Africa/Mozambique/index.php?language=german
use the readShapePoly () function in the maptools library to read it in, and
spplot in
Try this. It takes a matrix or data.frame, codes= which is a vector
of % codes and other text and file= and other cat arguments. If no
... args are given it outputs the character string that it would have
handed to cat.
write.mat - function(mat, codes, sep = , ...) {
s - do.call(sprintf,
Is it possible to mix symbols and evaluated objects inside the expression()
function ?
The following example shows what I am trying to achieve:
for (m in 1:3) {
plot(1:10); #just a place holder for the real plots
title(expression(y = m * lambda));
}
I want to actually evaluate the
Hi,
Is there such a thing? If no: is it easily simulated?
thanks, Joh
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R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented,
To answer two of my own questions to get them into the archives (I am slowly
getting the hang of ggplot):
Q1. use opts(axis.text.x = theme_text(size=xx)) to change font size of the
bar labels:
library(ggplot2)
set.seed(5)
dat - sample(1:8,100,replace=TRUE)
smp - ggplot(data.frame(dat),
That's perfect, thanks!
baptiste
On 10 March 2010 14:47, Gabor Grothendieck ggrothendi...@gmail.com wrote:
Try this. It takes a matrix or data.frame, codes= which is a vector
of % codes and other text and file= and other cat arguments. If no
... args are given it outputs the character
On 10/03/2010 8:52 AM, Markus Loecher wrote:
Is it possible to mix symbols and evaluated objects inside the expression()
function ?
The following example shows what I am trying to achieve:
for (m in 1:3) {
plot(1:10); #just a place holder for the real plots
title(expression(y = m *
For Q2 you can use opts(legend.position = c(0.9, 0.9)).
For Q3, you can also use scale_y_sqrt().
Hadley
On Wed, Mar 10, 2010 at 2:05 PM, Tim Howard tghow...@gw.dec.state.ny.us wrote:
To answer two of my own questions to get them into the archives (I am slowly
getting the hang of ggplot):
On Mar 10, 2010, at 1:38 AM, mjlee818 wrote:
Hi,
I am a novice in R. I would like to use a package called mgarch, but I
have trouble installing it. It is not available on CRAN servers. I
downloaded the tar.gz file online. (mgarch_0.00-1.tar.gz) I have tried to
install it using the
Thanks David. Leaving off the tilde was the problem.
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Sent from the R help mailing list archive at Nabble.com.
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R-help@r-project.org
Hello,
does anybody know which command to consider when I'm trying to plot a
stacked barplot with a legend at the most empty portion of the graphic?
I've searched for it, and somebody stated to use the labcurve-command,
but I don't know how to produce stacked barplots with it.
Is there any
Hi Petr,
Thanks again for your post the problem is now solved - thank you so much for
trying and trying to get this to work.
So the final script that actually worked was:
##ALL SUBSET DATA
#Create vector to put data in
mod - vector(1000,mode=list)
#first order your data according to ID2
Thanks Martin for the lead. A new avenue to explore.
Dhruv
-Original Message-
From: Martin Maechler [mailto:maech...@stat.math.ethz.ch]
Sent: Wednesday, March 10, 2010 6:18 AM
To: kMan
Cc: Sharma, Dhruv; r-help@r-project.org
Subject: Re: [R] r code to generate interaction columns
k
Hi tom,
have a look at the emptyspace-function from the plotrix package. Looks
like it does what you want?!
Hth.
t.wun...@stud.uni-heidelberg.de schrieb:
Hello,
does anybody know which command to consider when I'm trying to plot a
stacked barplot with a legend at the most empty portion of
Your choice of subject line alone shows some people that you missed some
small details from the posting guide. The ability to notice small details
may be important for you to demonstrate in future. Any answer in this
thread is unlikely to be found by a topic search on subject lines alone
In the first case you did not look far enough into the data:
dat - seq(c(ISOdate(2000,3,20)), by = day, length.out = 60)
br-dat[c(23, 42)]
cut(dat, breaks=br, right=T, include.lowest=T)
[1] NANANA
NANANA
[7] NANA
Apologies.
from the boxplot documentation:
... if varwidth is TRUE, the boxes are drawn with widths proportional to the
square-roots of the number of observations in the groups.
I find this option often very useful.
Thanks for any insight into how to achieve this with geom_boxplot.
Joh
On
Hi,
I've a beginner question. I'm trying to extract data in my dataframe
according to some nested rules.
I have something like the dataframe test.df:
test.df = data.frame(V1=c(rep(A,10), rep(B,10), rep(C,5)),
V2=c(rep(1,5), rep(2,5), rep(1,5), rep(2,5), rep(1,5)))
V1 V2
1 A 1
2 A 1
3
Every day I get a csv file containing the names of the 64 schools in our
county, the number of students sent home ill, and the number of students
absent (plus lots of other variables). The file is cumulative since fall
of 2009. It is in long format: one line per school per day.
Each line is
Hi,
Thank you for your replies
as for the prediction length, i run this code:
library(arules)
data(AdultUCI)
AdultUCI$workclass-factor(AdultUCI$workclass, levels =
c(levels(AdultUCI$workclass), UNKNOWN))
AdultUCI$workclass[is.na(AdultUCI$workclass)]-UNKNOWN
Dear list,
I have a list of three matrices :
i = list(matrix(1:4,2,2), matrix(3:6,2,2), matrix(9:12,2,2))
I would like to sum the matrices, as follows :
[,1] [,2]
[1,] 13 19
[2,] 16 22
I used this code :
k - i[[1]]
for (j in (2:length(i))) {
k - k + i[[j]]}
But, is it possible to sum
One more bit: I got as far as this, thinking it might help:
Using a data file that I know has all the necessary denominators, I
created a dataframe of school names (as factor) and TotalStudentsEnrolled.
data.frame(data$School[!duplicated(data$School)],
Hi,
Look at the R News 8/1 in the R Help Desk.
Alain
On 10-Mar-10 16:34, Carlos Petti wrote:
Dear list,
I have a list of three matrices :
i = list(matrix(1:4,2,2), matrix(3:6,2,2), matrix(9:12,2,2))
I would like to sum the matrices, as follows :
[,1] [,2]
[1,] 13 19
[2,] 16 22
I used
On Mar 10, 2010, at 10:30 AM, arnaud chozo wrote:
Hi,
I've a beginner question. I'm trying to extract data in my dataframe
according to some nested rules.
I have something like the dataframe test.df:
test.df = data.frame(V1=c(rep(A,10), rep(B,10), rep(C,5)),
V2=c(rep(1,5), rep(2,5),
On Mar 10, 2010, at 10:34 AM, Carlos Petti wrote:
Dear list,
I have a list of three matrices :
i = list(matrix(1:4,2,2), matrix(3:6,2,2), matrix(9:12,2,2))
I would like to sum the matrices, as follows :
[,1] [,2]
[1,] 13 19
[2,] 16 22
Reduce(+, i)
[,1] [,2]
[1,] 13 19
[2,] 16
Hi Jim,
And thanks for helping. My (hopefully) last question concerns the use of
a non-gray color scale.
How do I use e.g. a rainbow colorscale? This issue has already been raised
http://tinyurl.com/ylhcbra
and over there it is dealt with by hand. I just wonder whether anything
similar is
Apologies for the previous email, I think I got it sorted out now.
Lorenzo
rm(list=ls())
library(Cairo)
set.seed(1234)
trivial_matrix-matrix(rnorm(25),nrow=5)
CairoPDF(matrix2D.pdf)
oldpar-par( mar = c(4.5,5, 2, 1) + 0.1,
cex.axis=1.4,cex.lab=1.6,cex.main=1.6)
I'm a fairly new R user and while I have a solution to my problem I'm
wondering if there is a better one.
In SAS it's common to use if/then logic along with a do statement to
make several things happen. While I could do the same thing in R
using a for loop, and if and {}, I've read that loops
Hello Folks, I have a need to generate Graphic output files (gif, jpeg, pdf,
etc..) on a Solaris Environment, however this environment does not have X11
setup and setting up X11 would be a last resort if required. I have attempted
to install GDD and Cairo without success up to this point. Is
Hi All,
If given a dataframe (long form) with Year, Species, and Location,
How would I write a function that would create a unique matrix of Species
Location for each Year?
What I've tried doing is the following:
data #dataframe
dataT-table(data$Species,data$Location,data$Year) #creates tables
Here is how you can do the lookup:
# lookup up the school
lkup - read.table(textConnection(1'BENJAMIN FRANKLIN ES'
465
+ 2'CALVIN COOLIDGE SCHL'379
+ 3'EAST MS' 590
+ 4'HORACE MANN SCHL'374
+ 5'MAC ARTHUR SCHL'
Is this what you want:
yrData - data.frame(year=sample(1990:2000, 100, TRUE),
+ species=sample(1:3,100,TRUE), loc=sample(1:2,100,TRUE))
byYear - split(yrData, yrData$year)
byYear[1:3]
$`1990`
year species loc
39 1990 3 2
57 1990 3 1
62 1990 1 1
68 1990 2
On Mar 10, 2010, at 11:47 AM, David Young wrote:
I'm a fairly new R user and while I have a solution to my problem I'm
wondering if there is a better one.
In SAS it's common to use if/then logic along with a do statement to
make several things happen. While I could do the same thing in R
Your line of code:
zzz.aov - aov(Intensity ~ Group + Error(Sample), data = zzzanova)
indicates that you are trying to do a repeated measures ANOVA, not just an
ANOVA. The Error(Sample) term in your expression indicates that Sample is a
within subjects factor, which I presume is not the
Thanks for providing the code that allows me to reproduce the problem.
It looks like the prediction routine for some reason returns 0 as
prediction for some trees, thus causing the problem observed. I'll look
into it.
Andy
From: Dror
Hi,
Thank you for your replies
as for the prediction
David:
The best advice I can give is: read An Introduction to R carefully, taking
particular note of the examples and the ideas of vectorization, factors,
lists, etc The bottom line is: yes, you can mimic the way SAS or other
ancient procedural languages do things in R (e.g. using nested ifelse()
Dear r-useRs,
After a couple of years in a 'R exile' of sorts, I've recently changed jobs
and my current employer (an American multinational in the food manufacturing
industry) is much more open than my past employer (which wouldn't even want
to hear about anything that didn't begin with SAS...).
Hi R users,
I'm using the survey package to calculate summary statistics for a large
health survey (the Demographic and Health Survey for Honduras, 2006), and
when I try to calculate the variances for several variables, I get negative
numbers. I thought it may be my data, so I ran the example on
This list is the wrong place for that question. The posting guide tells
you, in bold, to contact the package maintainer first.
If you had already done that, and didn't hear back from him, then you
should tell us, so that we know you followed the guide.
Corey Sparks corey.spa...@utsa.edu
Fair enough.
CS
-
Corey Sparks, PhD
Assistant Professor
Department of Demography and Organization Studies
University of Texas at San Antonio
501 West Durango Blvd
Monterey Building 2.270C
San Antonio, TX 78207
210-458-3166
corey.sparks 'at' utsa.edu
On Wed, Mar 10, 2010 at 6:07 PM, Fernando Henrique Ferraz Pereira da
Rosa pess...@fernandohrosa.com.br wrote:
reason I'm writing you. If you have any examples (preferably with
references) and/or experience in a similar scenario please do write me. I've
There is a recent reference in The
Hi Ista,
Many thanks, the plyr package was just what I needed.
Because I did such a bad job with my question (no data, etc etc), here
is my current solution:
First, I grabbed my data from PostgreSQL as follows:
library('RPostgreSQL')
m - dbDriver(PostgreSQL)
con -
Hadley,
Thanks for chiming in.
By Q2 I was trying to refer to the Y-axis labels. For the polar plot, the
Y-axis labels reside left of the panel. I was looking for a way to get the
Y-axis labels to radiate out from the center so it would be clear which line
each label refers to. I still can't
If you're looking for business and technical justifications for a
business to adopt R, I wrote some up last year:
http://blog.revolution-computing.com/2009/02/how-to-get-it-to-accept-and-love-r.html
In summary:
R is mainstream
R is supported
R is high-quality
R leads commercial packages in
Thanks for these suggestions. I tried them out and I get the error message:
Error in qdata$flow : $ operator is invalid for atomic vectors
Can anyone offer further suggestions on how to extract the values from
atomic vectors?
Thanks again
Emma
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James,
you may post your question to the R-SIG finance group with a small example.
If I understand your problem correctly it's like converting tick data of
financial time series into aggregates. (to 1-minute, hourly, daily ... data
sets ). There are packages available for this kind of task
Thanks Gabor,
As I said I would like to use gsubfn, but I am having problems
installing it, which I assume are due to some conflict with the current
tcltk package
Below is the error I got after issuing install.packages(gsubfn)
Any advice?
###
* Installing *source* package
Thank you Gavin for your help.
David, maybe I am not so clear on my question, sorry. My problem was that
when I wanted to reproduce results (or graphs) present in the book,
sometimes my results were quite different or I don not know how to repuduce
them. I will have a look to the documentation
Dear Users,
Can I perform panel data (fixed effects model) out of sample forecasts using R?
Thanks in advance,
Ricardo.
[[alternative HTML version deleted]]
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Thanks much - very nice. I hadn't thought of that approach.
I dug around in the lattice source and found another way to do it so
for what it's worth, I'll post it - maybe it will be useful to
someone. Basically, I made a function from code found in
plot.trellis() that gets the grid
Hi, I am new to R.
What does a negative amount in an index do?
i.e. x[-lenght[x]]
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Sent from the R help mailing list archive at Nabble.com.
__
I'm a fairly new R user and while I have a solution to my problem I'm
wondering if there is a better one.
In SAS it's common to use if/then logic along with a do statement to
make several things happen. While I could do the same thing in R
using a for loop, and if and {}, I've read that loops
If you are interested in machine learning in general, you might also
want to have a look at the CRAN Task View on Machine Learning
Statistical Learning that contains this package, as well as others:
http://cran.r-project.org/web/views/MachineLearning.html
Best,
---
Ralf Bierig
Post-Doctoral
Please learn to Read The Fine Manual:
?[
will give you the answer.
-Ista
On Wed, Mar 10, 2010 at 8:43 AM, ManInMoon xmoon2...@googlemail.com wrote:
Hi, I am new to R.
What does a negative amount in an index do?
i.e. x[-lenght[x]]
--
View this message in context:
By Q2 I was trying to refer to the Y-axis labels. For the polar plot, the
Y-axis labels reside left of the panel. I was looking for a way to get the
Y-axis labels to radiate out from the center so it would be clear which line
each label refers to. I still can't find any reference to moving
On 3/10/2010 1:01 AM, Petr PIKAL wrote:
Dear all
recently I tried to split vector of dates according to some particular
date to 2 (more) chunks, but I was not able to perform correct setting.
When I want split to 3 chunks it partially works however from help page I
supposed to get result
Peter's suggestion
qdata[order(qdata$flow, decreasing=TRUE), ]
would work if qdata were a data.frame, where the
$column syntax picks out a column. You probably
have a matrix so use [,flow] instead of $flow
to extract the column called flow.
qdata[order(qdata[,flow], decreasing=TRUE), ]
(Both
Run that function hourly with plyr
output.hourly - dlply(df.i1,tshour,cor.dat)
Why not
output.hourly - ddply(df.i1,tshour,cor.dat)
? Generally you want to work with data frames in R, if at all possible.
Hadley
--
Assistant Professor / Dobelman Family Junior Chair
Department of Statistics
Got it.
Thanks again so much for the help.
Best,
Tim
hadley wickham h.wick...@gmail.com 3/10/2010 2:46 PM
By Q2 I was trying to refer to the Y-axis labels. For the polar plot, the
Y-axis labels reside left of the panel. I was looking for a way to get the
Y-axis labels to radiate out
Hello R,
I am looking for non-parametric simulation in IRT. Is there any IRT
package that does non-parametric simulation?
helen L
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
There is no function in R AFAIK, where an IRT model is estimated using the
NPMML method (non-parametric marginal maximum likelihood). All MML methods in R
assume the population distribution is normal.
Now, the jml function in the MiscPsycho package uses joint maximum likelihood
for estimating
ManInMoon wrote:
Hi, I am new to R.
What does a negative amount in an index do?
i.e. x[-lenght[x]]
Why don't you try it and see for yourself?
--
Kevin E. Thorpe
Biostatistician/Trialist, Knowledge Translation Program
Assistant Professor, Dalla Lana School of Public Health
University of
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