On Wed, 2010-10-27 at 13:17 -0200, Marcelo Lima wrote:
> Hi,
>
> I would like to add a line on the diagonal of a covariance matrix, is there
> a quick way to do it besides abline?
>
> Thanks!
What's wrong with abline()? It does exactly what you want.
By the way, reproducible example such as re
I am trying to create a function with a package with a NAMESPACE that
will save() some variables, distribute an Rdata file to another
computer, where it will be load()ed. The problem is that this load()
tries to load the namespace of the package on the original computer
that created the .Rdata fil
Hi! I have an input table with a column "Dates" in the format
"month/day/year" (eg. "5/11/1999" and a column "Times" in the format
"hours/minutes" (eg. "15:20"). In R I need to convert them into chron
objects to extract colums only containing months, days, minutes, ..
For the dates it is no probl
Hi all:
I have a dataset which contains two variables: Y and time
y<-c(228,189,232,198,252,315)
time<-2003:2008
How can I find out the trend(increase/decrease) of y along the time period?
If I use:
lm(y~time)
The "lm" command treats time as natural number,but not date.
So maybe "lm" isn't approp
Many thanks for your help!
Thanks to you guys I manage to solve my problem in an efficient way
All the best
J
On Tue, Oct 26, 2010 at 11:04 PM, Remko Duursma wrote:
>
> I don't know why I forgot that you can do this as well :
>
> area.poly(intersect(p1,p2))
>
> ... a bit more straightforward.
>
On Wed, 27 Oct 2010, Alex P. wrote:
Hello All,
I have multiple "list of lists" in the form of
Mylist1[[N]][[K]]$Name_i,
with N=1..6, K=1..3, and i=1..7. Each Name_i is a matrix. I have 30 of these
objects Mylist1, Mylist2, ...
I would like to merge these lists by each Name_i using rbind, bu
Hello All,
I have multiple "list of lists" in the form of
Mylist1[[N]][[K]]$Name_i,
with N=1..6, K=1..3, and i=1..7. Each Name_i is a matrix. I have 30 of these
objects Mylist1, Mylist2, ...
I would like to merge these lists by each Name_i using rbind, but I couldn't
figure out how to do i
Hi:
Is this what you need?
l_one <- data.frame(key = c(2, 1, 2))
l_two <- data.frame(ndx = 1:4, descr = c('this', 'that', 'other', 'finis'))
merge(l_one, l_two, by.x = 'key', by.y = 'ndx')
key descr
1 1 this
2 2 that
3 2 that
HTH,
Dennis
On Wed, Oct 27, 2010 at 10:53 AM, Jim Burke w
Write a function() that does everything you want to do for one
regression, then run that on all of them. It'll look something like
this.
library(car)
myreg=function(X,v1,v2,v3,v4,v5) {
reg=lm(X ~ v1 + v2 + v3 + v4 + v5)
crPlots(reg)
}
Then run the function a lot, maybe in a loop or with sapply()
Hi:
As David originally noted, your dates are going to be read in as factors
with data.frame() unless you explicitly define them as Date objects first.
Here's one way to get the plot using a toy example (since you didn't provide
any data):
library(ggplot2)
dd
[1] "21/2/10" "30/3/10" "30/4/10" "30
I guess you have something like this.
> testlen <- c(sin(seq(0,1.98*pi,length=100))+2+rnorm(100)/10)
> testpos <- seq(0,1.98*pi,length=100)
> radial.plot(testlen,testpos,rp.type="p",main="Test Polygon",line.col="blue")
(http://addictedtor.free.fr/graphiques/graphcode.php?graph=75)
Does this work
On Oct 27, 2010, at 4:33 PM, Czerminski, Ryszard wrote:
David,
Thanks a lot!
panel.grid() does the trick,
but the generated grid extends beyond
the plot region from levelplot()
Is there a way to restrict grid to the plot region
from levelplot() ?
Well, it doesn't when I hack the example on
Thanks, that is awesome!
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Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing li
Here's how I'd approach the problem.
First, read the file:
a = readLines('testOut')
Each different type of line can be identified by the
string at the beginning of the line, based on these
patterns. It seems that you only want the numbers,
so we'll convert them as we extract them:
pats
RExcel has its own mailing list, rcom-l.
Please subscribe on rcom.unvie.ac.at and post your question on that list.
On 10/27/2010 1:29 PM, Puijman, R. wrote:
> I'm using R-Excel's macro mode to make an R based Excel tool for inventory
> management. It's quite a lot of R-code which I made in R at
On Wed, Oct 27, 2010 at 11:26 PM, Marc Schwartz wrote:
> On Oct 27, 2010, at 5:48 AM, L wrote:
>
>> Hi
>> I have R 2.11.1 installed at Fedora 13. when I tried to install RSPerl
>> by command line
>>
>> sudo R CMD INSTALL ~/Download/RSPerl_0.92-1.tar.gz
>> It failed with following errors, could som
David,
Thanks a lot!
panel.grid() does the trick,
but the generated grid extends beyond
the plot region from levelplot()
Is there a way to restrict grid to the plot region
from levelplot() ?
Best regards,
Ryszard
--
Confi
On Wed, Oct 27, 2010 at 3:07 PM, Susanta Mohapatra
wrote:
> I have one more pattern to take care of.
> What is happening is that if a string like "10 minutes and 30 seconds" comes
> for parsing then the function generates 2 values both for 10 minutes and for
> 30 seconds and the result list then h
For those interested in the data, as I did receive at least one request, I'll
post it here:
http://r.789695.n4.nabble.com/file/n3016233/testOut testOut
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Sent fro
On Oct 27, 2010, at 4:02 PM, Sibylle Stöckli wrote:
Dear Ivan,
Thanks a lot. I managed to create a list (KANE.LIST) out of my data
set (KANE).
There is still the problem within the barplot function (non-numeric
argument). There are no NA values and just the variable names are
non-numer
I am creating radial plots to visualise popularity of a series of
topics, I was wondering if someone has come across a radial plot in
which the lines originate from the edge of the plot instead of the
centre, does anyone know how can this be achieved in R? Are there any
good reasons not to do it?
Using the text itself works, although slightly annoying. I ended up just
processing the text each time I wanted a value inside it, which turns out to
be about the same thing. The key to processing the text ended up being a
command: library("CGIwithR") followed by another command scanText(textLine)
Dear Ivan,
Thanks a lot. I managed to create a list (KANE.LIST) out of my data
set (KANE).
There is still the problem within the barplot function (non-numeric
argument). There are no NA values and just the variable names are non-
numeric...
Thanks
Sibylle
> PA<-read.table("Biotree_parti
On Oct 27, 2010, at 3:27 PM, smcguffee wrote:
Actually, I take that back, this is only reading in 18 values at the
most in
a list, but some lists should be over 200 values in length...
I think the read.table and cousins read in some modest fraction of the
data
Probably need to either
On Oct 27, 2010, at 3:27 PM, smcguffee wrote:
Actually, I take that back, this is only reading in 18 values at the
most in
a list, but some lists should be over 200 values in length...
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On Wed, Oct 27, 2010 at 9:21 PM, steven mosher wrote:
> Thanks for the pointer,
>
> After looking at the many folders of R code I have I decided it was time to
> start working in an IDE and also getting my stuff under version control (
> for my own sanity)
>
> I'll have a look at Geany.. for versi
I think I found the first piece of it. Typical SAS:
> fit$linear.predictors[1]-coef(fit)*(ovarian$age[1]-mean(ovarian$age))
age
-4.4408920985e-16
Well misrepresented in several places...
Stephen Bond
-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.ne
Actually, I take that back, this is only reading in 18 values at the most in
a list, but some lists should be over 200 values in length...
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Sent from the R help m
I have one more pattern to take care of.
What is happening is that if a string like "10 minutes and 30 seconds" comes
for parsing then the function generates 2 values both for 10 minutes and for
30 seconds and the result list then has 2 elements. So when I use unlist
function then try to merge wit
Thanks for the pointer,
After looking at the many folders of R code I have I decided it was time to
start working in an IDE and also getting my stuff under version control (
for my own sanity)
I'll have a look at Geany.. for version control.. not so sure.
On Wed, Oct 27, 2010 at 12:14 PM, Liviu
fitLines=read.delim("testOut",header=FALSE,quote="")
worked pretty well.
I have a bunch of NA's that I don't want, but at least I can access the data
I do want.
Thank you,
Sean
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On Wed, Oct 27, 2010 at 9:05 PM, Jonathan P Daily wrote:
> I can second using Geany as an IDE.
>
Great, finally a soulmate! :) More seriously, I think Geany is
under-appreciated and virtually unkonwn in the R community.
> Another large plus for it is that it is cross platform (I work in both
>
What you suggest is exactly what I intended. The big problem is that
X*beta != linear.predictor # it works for glm
That's a big loose end. The survival documentation on p41 implies that the
above should be an equality, but it is not. And I could not produce the surv
vector using a variety o
I can second using Geany as an IDE. Another large plus for it is that it
is cross platform (I work in both Windows and Linux), cross environment (I
also code in Python/Sage), very customizable, and even has a version on
PortableApps for windows so you can take a customized version around on a
U
Hi,
I am using e1071 package and trying to do classification on Iris dataset:
model <- naiveBayes(Species ~ ., data = iris)
pred <- predict(model, iris[,])
How can I see conditional probability distribution of this model? And also how
can I see maximum likelihood estimate for the model?
Thanks
Hi,
I have a data file with hundreds of rows, with every first, second, third,
and fourth line representing a set of numbers for row names x, y, fit, and
residuals, respectively. However, any given group of these lines might be
from 10 to 2 values long.
When I try
fits=read.delim2("test")
E
On Wed, Oct 27, 2010 at 4:05 PM, Lee Hachadoorian
wrote:
> For an R-enabled text editor, I would suggest Tinn-R for Windows or RGedit
> (a gedit plugin) for Linux/Gnome-desktop. Since both are just text
> editors, they will work with whatever version R you have installed
> (criteria 1).
>
> RGedit
Thank you both. Using axis I have gotten exactly what I needed.
Thanks,
Mitch
-Original Message-
From: Thomas Levine [mailto:thomas.lev...@gmail.com]
Sent: Wednesday, October 27, 2010 2:34 PM
To: Sarah Goslee
Cc: Downey, Patrick; r-help@r-project.org
Subject: Re: [R] Y Axis Labels
Oop
Oops. That was backwards
plot(scale~time,axes=F)
axis(2,at=0:4,labels=c("Never", "Once per month", "A few times per
month", "A few times per week","Everyday"))
axis(1)
Tom
2010/10/27 Thomas Levine :
> More specifically
>
> time=rnorm(20)+10
> scale=rep(0:4,4)
> plot(time~scale,axes=F)
> axis(1,a
if your data for the rest of the file looks like this then read.fwf will
work.
depending which vars you want to pull)
widths= c(18,32,41)
E-CBIL-28-raw-cel-1435145228.cel1
would pull 3 vars, E-CBIL-28-raw-cel-; 1435145228.cel;1
widths <-c(32,41)
E-CBIL-28-raw-cel-1435145228.cel;1
you
On Oct 27, 2010, at 2:20 PM, Czerminski, Ryszard wrote:
I would appreciate any advice about how to add rectangular grid to the
plot generated by levelplot()
similarly as grid() function adds grid to the regular plot()
?panel.grid
Best regards,
Ryszard
--
David Winsemius, MD
West Hartford
On Oct 27, 2010, at 1:53 PM, smcguffee wrote:
Hi,
I have a data file with hundreds of rows, with every first, second,
third,
and fourth line representing a set of numbers for row names x, y,
fit, and
residuals, respectively. However, any given group of these lines
might be
from 10 to 20
I would appreciate any advice about how to add rectangular grid to the
plot generated by levelplot()
similarly as grid() function adds grid to the regular plot()
Best regards,
Ryszard
--
Confidentiality Notice: This message
On Oct 27, 2010, at 1:45 PM, Bond, Stephen wrote:
coef(fit)*model.matrix(fit)[1,1]
age
11.69021
I don't know what that might be and you are not telling us what you
think it is.
I think this the calculation of the linear predictor, multiplying
(the beta*X)
I expected that coef(fit)
On 26.10.2010 16:41, Wensui Liu wrote:
morning, all
right now, I have R installed on a 32-bit ubuntu with PAE enabled. And
I can see more than 4-g memory available in system monitor. my
question is: might this 32-bit R take advantage of the extra memory
and handle large data?
No.
Uwe
tha
Hi Jim,
Here is one way:
# How I imagine your data might be stored
l_one <- list(structure(list(key = c(2, 1, 2)), .Names = "key",
row.names = c(NA,
-3L), class = "data.frame"))
l_two <- list(structure(list(ndx = 1:4, descr = c("this", "that", "other",
"finis")), .Names = c("ndx", "descr"), row.n
It's much more elegant if I set the 'type' parameter to "p" in lineplot.CI...
Thank you, that was really helpful
--- Στις Τετ., 27/10/10, ο/η Thomas Levine έγραψε:
> Από: Thomas Levine
> Θέμα: Re: [R] lineplot.CI {sciplot}: continuous line
> Προς: "Fotis Fotiadis"
> Κοιν.: r-help@r-projec
Hi,
I have a data file with hundreds of rows, with every first, second, third,
and fourth line representing a set of numbers for row names x, y, fit, and
residuals, respectively. However, any given group of these lines might be
from 10 to 2 values long.
When I try
fits=read.delim2("test")
E
My two lists look like below
Need an R code example that
combines the two.
l_one
"key"
2
1
2
l_two
"ndx", "descr"
1, "this"
2, "that"
3, "other"
4, "finis"
My goal is a new list that looks
like below.
ndx descr
2 that
1 this
2 that
Thanks,
Jim
__
>>
>> coef(fit)*model.matrix(fit)[1,1]
>> age
>> 11.69021
>>
> I don't know what that might be and you are not telling us what you
> think it is.
I think this the calculation of the linear predictor, multiplying
> (the beta*X)
I expected that coef(fit)*model.matrix(fit)[1,1]= fit$linear.
It could be more elegant, but I think this does what you want.
> ...
> lineplot.CI(blck, perf, group = cnd, xlab="Block", ylab="% Optimal
> Responses", cex.leg=1.2, x.leg = 18, y.leg=0.4, err.width=0.05, pch =
> c(15,15), col=c("grey", "black"), lty=c(1,1), main = "Experiments 2 and 3",
> ylim
On Oct 27, 2010, at 5:17 AM, ashz wrote:
Hi,
I have this script:
dat <- data.frame(X = halistat$Date,Y1 = halistat$avg,Y2 = halistat
$stdev)
ggplot(data = dat, aes(x = X, y = Y1, ymin = Y1 - Y2, ymax = Y1 +
Y2)) +
geom_point() + # points at the means
geom_line() + # if you want lines b
In the sort of problem mentioned below, the suggestion to put in gradients (I
believe this
is what is meant by "minus score vector") is very important. Using analytic
gradients is
almost always a good idea in optimization of smooth functions for both
efficiency of
computation and quality of resu
On Wed, Oct 27, 2010 at 10:01 AM, Wesley Roberts wrote:
> Dear R users,
>
> I have a quick question regarding creating an index for a zoo object. I am
> using R 2.12 on winxp.
>
> I have read through the R archives searching for information on dates and
> time series analysis and nothing seems t
Hello,
I have am plotting a 0-4 ordinal scale (y-axis) against time (x-axis). Is
there a way to label the values on the y-axis with the translation from the
scale? That is, instead of having 0,1,2,3,4 on the y-axis, I would like
"Never", "Once per month", "A few times per month", "A few times per
Hello everyone,
I would like to create a "dynamic" array to keep storing number in it
for (i in c(2:length(final))){
myarray <-final[i]-final[i-1]
myarray2<-2*final[i]
}
At the end I would like to use myarray as the x values of an array
and the myarray2 as the yvalues of the same ar
read.delim2 did the trick -- many thanks!!!
On Wed, Oct 27, 2010 at 10:01 AM, Jorge Ivan Velez wrote:
> ?read.delim2
>
> HTH,
> Jorge
>
>
> On Wed, Oct 27, 2010 at 9:51 AM, Donald Braman wrote:
>
>> Thanks for your advice! I still get the same error, though -- not sure
>> why.
>>
>>
>> > read.t
Hi,
Well, I did it, but all my script was on the first message. I don't have any
other variables. I am just reading a NCDF file and trying to read the
variable "tasmax", that has values of temperatures.
The only "new" information I have is the header of the NCDF file
(Spain02D_tasmax.nc), that I
Dear R users,
I have a quick question regarding creating an index for a zoo object. I am
using R 2.12 on winxp.
I have read through the R archives searching for information on dates and time
series analysis and nothing seems to cover my question.
I am extracting data from a time series of remo
On Wed, Oct 27, 2010 at 10:07 AM, Ivan Calandra
wrote:
>
>
> Le 10/27/2010 15:45, Gabor Grothendieck a écrit :
>>
>> On Wed, Oct 27, 2010 at 8:38 AM, Ivan Calandra
>> wrote:
>>>
>>> What I don't understand is why vectors (with more than one value) don't
>>> have
>>> dimensions. They look like th
I am interested in using "multcompLetters" after running "kruskalmc" but
I'm a newbie and I'm not having luck figuring it out. I can run "kruskalmc"
just fine,
but after studying the documentation for "multcompletters" for a long time,
I cannot figure out how to make it work. Any ideas? R input
On Wed, 27 Oct 2010 16:31:30 +0530, Santosh Srinivas wrote:
> I am looking for suggestions for the "best" IDE for R. Best is obviously
> subjective but I need just the basic features that should function well (and
> I looked through the threads already).
> - Proper integration with R 2.11.1
> - Go
Hello!
This is a sanity check based on my inexperience with mixed effects
models - I'd like to make sure the formula I wrote is correct for what
I am trying to do:
In my data set "MyData", I have a response variable (DV), 8 numeric
predictors (a through h) and a factor "group" with several levels.
Hi,
I have a irregularly spaced time series dataset, which reads in from a .csv.
I need to convert this to a regularly spaced time series by filling in
missing rows of data with NAs.
So my data, called NtuMot, looks like this (I've removed some of the
additional rows for simplicity)
ELEID
Thanks Gabor,
It is a very tricky task and your comment helped. I modified the function to
handle average of two numbers when it is like 2-3 minutes. I also improved
on the regex part to parse the decimal parts also. Right now i can parse
100% of one sample.
Thanks
Susanta
On Wed, Oct 27, 2010 a
Hi,
I just installed R 64bit under Windows 7 64 bit
When trying to readin files I get the following error message:
> > source(file="C:\\Users\\me\\Documents\\My
PhD\\Modelling\\R\\Scripts\\Functions\\functions 20jan10.r")
Error in file(file, "rt") : cannot open the connection
In addition: Warn
Hi,
I have this script:
dat <- data.frame(X = halistat$Date,Y1 = halistat$avg,Y2 = halistat$stdev)
ggplot(data = dat, aes(x = X, y = Y1, ymin = Y1 - Y2, ymax = Y1 + Y2)) +
geom_point() + # points at the means
geom_line() + # if you want lines between pints
geom_errorbar() # error bars, Y1
for the loop part:
put all your xml files in a directory with no other files,
do
setwd("directory/with/xml/files")
files <- list.files()
for (file in files)
kjetil
2010/10/27 Ista Zahn :
> Hi Jørgen,
> You will be better served by learning how to find the answers to these
> kinds of questions
On 27/10/2010 9:51 AM, Donald Braman wrote:
Thanks for your advice! I still get the same error, though -- not sure
why.
> read.table('don.5.clusters.txt', header = TRUE, comment.char = '', quote
='')
Error in read.table("don.5.clusters.txt", header = TRUE, comment.char = "",
:
more col
Le 10/27/2010 15:45, Gabor Grothendieck a écrit :
On Wed, Oct 27, 2010 at 8:38 AM, Ivan Calandra
wrote:
What I don't understand is why vectors (with more than one value) don't have
dimensions. They look like they do have 1 dimension. For me no dimension
would be a scalar. Like in geometry: a
Thanks for your advice! I still get the same error, though -- not sure
why.
> read.table('don.5.clusters.txt', header = TRUE, comment.char = '', quote
='')
Error in read.table("don.5.clusters.txt", header = TRUE, comment.char = "",
:
more columns than column names
Any other thoughts?
--
Thank you for your answer, Jim! I will try it and post what I find.
cheers,
Charles
On Wed, Oct 27, 2010 at 3:46 PM, jim holtman wrote:
> put:
>
> options(error=utils::recover)
>
> in your script so that when an error occurs you are dropped into the
> 'browser' so that you can examine the vari
put:
options(error=utils::recover)
in your script so that when an error occurs you are dropped into the
'browser' so that you can examine the variables at that point in time.
There are several references on how to use the debugging tools in R
that will help you resolve your problem. We can not
On Wed, Oct 27, 2010 at 8:38 AM, Ivan Calandra
wrote:
> What I don't understand is why vectors (with more than one value) don't have
> dimensions. They look like they do have 1 dimension. For me no dimension
> would be a scalar. Like in geometry: a point has no dimension, a line has 1,
> a square
I've found the solution to this in an old post of Deepayan's:
lattice.options(axis.padding = list(numeric=0))
Best,
Peter
On 27 October 2010 09:28, Peter Davenport wrote:
> Unwanted space (padding?) is introduced at the extremes of the x and y
> axes of my lattice plots.
> I've tried defining t
On 2010-10-27 06:21, David Herzberg wrote:
Peter, thanks for this elegant solution that works well and handles the empty cases.
However, the vector it returns includes both the row (case) numbers and the target result
(number of column of first "1"). How can I strip out the row numbers and leav
Hi
r-help-boun...@r-project.org napsal dne 27.10.2010 14:21:14:
> So?
> Do you imply that I do not need to change the precision.. and if yes how
to
> change the default display settings?
> (18-46)/(45-93)
[1] 0.583
> (18-46)/(45-93)*1e12
[1] 5833
So the computation use machine pre
Hi Jørgen,
You will be better served by learning how to find the answers to these
kinds of questions on your own. You can either use a general search
engine such as google:
http://lmgtfy.com/?q=read+multiple+files+in+R
http://lmgtfy.com/?q=read+xml+data+in+R
or using an R specific search engine. At
Hi everyone,
I am a newbie in R and in this discussion list. I am trying to use R package
"ncdf" to read values of temperature from a NCDF file. I did it before to
another file using the function "get.var.ncdf", but now there is an error
that I can not solve, and I would really appreciate if you c
Hi Sibylle,
I was about to send you an email, but I'll modify it thanks to your second!
Is PA what you expect? Does it contain the data you want?
You should provide some sample data.
If the importation worked, try to copy/paste the output of dput(PA),
which we can then copy/paste in our console
On Wed, Oct 27, 2010 at 8:49 AM, wrote:
> Gabor
>
> As someone trying to the rest of my team using Subversion (which I have used
> for a while, but more as a backup / record of changes), have you a neat /
> automated way of building a package from a subversion repository?
>
Normally one keeps
Peter, thanks for this elegant solution that works well and handles the empty
cases. However, the vector it returns includes both the row (case) numbers and
the target result (number of column of first "1"). How can I strip out the row
numbers and leave only the target result.
Regards,
David S
Original-Nachricht
Datum: Wed, 27 Oct 2010 15:09:59 +0200
Von: "Sibylle Stöckli"
An: Rhelp
Betreff: Fwd: as.list
Original-Nachricht
Datum: Wed, 27 Oct 2010 15:03:48 +0200
Von: "Sibylle Stöckli"
An: Rhelp
Betreff: as.list
Dear R-users
sorry, here Rcode incl
I noticed that nabble link presented Notepad++ as having to copy/paste
into the editor. There is a companion to NP++, though, that allows
line/file passing directly to an R console, auto-completion, and a bunch
of other goodies called NppToR.
--
Jonathan P. Da
Original-Nachricht
Datum: Wed, 27 Oct 2010 15:03:48 +0200
Von: "Sibylle Stöckli"
An: Rhelp
Betreff: as.list
Dear R-users
sorry, here Rcode included (attachment has been removed)
I would like to read a txt file as list, to select rows and columns, and to
create barplots.
(1)
Dear R-users
I would like to read a txt file as list, to select rows and columns, and to
create barplots.
(1) selection of parameter site and part: ok
(2) read txt file as list: problem with (1) as there are NA's (the lines not
selected)
(3) barplot: 5 different groups of bars (the selected co
Hi:
This topic came up a couple of days ago:
http://r.789695.n4.nabble.com/R-file-td3009812.html#a3009812
HTH,
Dennis
On Wed, Oct 27, 2010 at 4:01 AM, Santosh Srinivas <
santosh.srini...@gmail.com> wrote:
> Dear R-Group,
>
> I am looking for suggestions for the "best" IDE for R. Best is obviou
You might want to check out the Qt stuff we've been working on. The qtutils
package has a graphics device that supports zooming and other fun stuff.
Also, qtpaint provides a flexible low-level engine for interactive graphics.
See: http://github.com/ggobi/qtpaint and http://github.com/ggobi/qtutils
http://hudson-ci.org
On Wed, Oct 27, 2010 at 8:49 AM, wrote:
> Gabor
>
> As someone trying to the rest of my team using Subversion (which I have used
> for a while, but more as a backup / record of changes), have you a neat /
> automated way of building a package from a subversion repository?
Hi:
Here's another take with ggplot2:
library(ggplot2)
# Define the basic plot elements. First argument is the data frame.
# aes() refers to the plot's aesthetics, which refer to the variables
# mapped to specific 'roles' in the plot 'geoms'
g <- ggplot(x, aes(x = Age, y = Trait))
g + geom_poin
Gabor
As someone trying to the rest of my team using Subversion (which I have used
for a while, but more as a backup / record of changes), have you a neat /
automated way of building a package from a subversion repository?
Thanks
David Jessop
--
David Jessop
Global He
Dear Sirs,
Thanks a lot for your great help. This is going to help me immensely in future
as many times I had found myself struggling with this problem.
Thanks again for the great help.
Regards
Vincy
--- On Wed, 10/27/10, Dimitri Liakhovitski
wrote:
From: Dimitri Liakhovitski
Subject:
Hi:
I'm going to take a different tack from Gabor and Ivan and be strictly
qualitative on the distinctions among vectors, matrices, arrays, data frames
and lists.
As Ivan mentioned, a vector has a single (atomic) mode - i.e., all elements
of a vector must be of the same type. A numeric vector con
As everybody told you in using options with digits... It exactly is what
I made in the sent code.
Alain
On 27-Oct-10 14:21, Alaios wrote:
So?
Do you imply that I do not need to change the precision.. and if yes
how to change the default display settings?
Best regards
Alex
My comments are in the text.
Le 10/27/2010 12:11, Gabor Grothendieck a écrit :
On Wed, Oct 27, 2010 at 4:03 AM, Ivan Calandra
wrote:
Hi,
Gabor gave you a great answer already. But I would add a few precisions.
Someone please correct me if I'm wrong.
Arrays are matrices with more than 2 dime
On Oct 27, 2010, at 5:48 AM, L wrote:
> Hi
> I have R 2.11.1 installed at Fedora 13. when I tried to install RSPerl
> by command line
>
> sudo R CMD INSTALL ~/Download/RSPerl_0.92-1.tar.gz
> It failed with following errors, could some one offer help?
>
> Thanks
>
> Yuan
>
> Converters.c: In fu
So?
Do you imply that I do not need to change the precision.. and if yes how to
change the default display settings?
Best regards
Alex
From: Alain Guillet
Cc: Rhelp
Sent: Wed, October 27, 2010 1:58:46 PM
Subject: Re: [R] Increase R precision
Hi,
It is no
In that case you may wish to look into the rggobi package, which provides
an R interface to the ggobi tools. I haven't used it much, but it has a
lot of interactive options.
--
Jonathan P. Daily
Technician - USGS Leetown Science Center
11649 Leetown Road
Kearne
On Wed, Oct 27, 2010 at 8:04 AM, Manta wrote:
>
> Here it is:
>
> dput(temp_plot)
> structure(c(48608, 46686, 55216, 59268, 50967, 55067, 57783,
> 60021, 61480, 63853, 58267, 72442, 63926, 49102, 74320, 63433,
> 66256, 68483, 67736, 60507, 60888, 78008, 64326, 65665, 57288,
...
> 1L, 1L, 1L, 1L
Here it is:
dput(temp_plot)
structure(c(48608, 46686, 55216, 59268, 50967, 55067, 57783,
60021, 61480, 63853, 58267, 72442, 63926, 49102, 74320, 63433,
66256, 68483, 67736, 60507, 60888, 78008, 64326, 65665, 57288,
54663, 54984, 54073, 59632, 52523, 55266, 54836, 61408, 53813,
85855, 65204, 6
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