Re: [R] extract worksheet names from an Excel file

2011-06-25 Thread Shi, Tao
Thanks, Gabor!  That's really helpful!

...Tao



- Original Message -
 From: Gabor Grothendieck ggrothendi...@gmail.com
 To: Shi, Tao shida...@yahoo.com
 Cc: r-help@r-project.org r-help@r-project.org
 Sent: Friday, June 24, 2011 5:02 AM
 Subject: Re: [R] extract worksheet names from an Excel file
 
 On Fri, Jun 24, 2011 at 12:41 AM, Shi, Tao shida...@yahoo.com wrote:
  Hi list,
 
  Is there a R function I can use to extract the worksheet names from an 
 Excel file?  If no, any other automatic ways (not using R) to do this?
 
  thanks!
 
 
 Many or all of the Excel interfaces listed here:
 
 http://rwiki.sciviews.org/doku.php?id=tips:data-io:ms_windowss=excel
 
 can do that but be careful since one or more the packages listed there
 always returns the sheet names sorted in alphabetical order which
 means that you can't tell which is the first sheet, which is the
 second, etc. (if that is important).
 
 gdata has a specific function to do it:
 
 library(gdata)
 sheetNames(myfile.xls)
 
 -- 
 Statistics  Software Consulting
 GKX Group, GKX Associates Inc.
 tel: 1-877-GKX-GROUP
 email: ggrothendieck at gmail.com


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[R] What does class call mean? How do I make class formula into a call?

2011-06-25 Thread StellathePug
Hello R Users! 
I have a list called tabs that I would like to have the same structure as
my list eqSystem. The two look like they have the same structure but they
are different because when I look at their attributes, class(eqSystem[[1]])
is call but class(tabs[[1]]) is formula. I want to have class(tabs[[1]])
as a call too. 

So what does call mean? 

And how do I make an object of class formula be of class call? 
Thank you so much!!!--Rita


 class(tabs)
[1] list
 class(tabs[1])
[1] list
 class(tabs[[1]])
[1] formula class(eqSystem)
[1] list
 class(eqSystem[1])
[1] list
 class(eqSystem[[1]])
[1] call

Rita
=
If you think education is expensive, try ignorance.--Derek Bok

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[R] Need help on a R script part

2011-06-25 Thread Lusk Aris

Hi all,
I need all your help on this. I have the next part of 
code:e1=x1-mean(x1)e2=x2-mean(x2)n1=length(x1)n2=length(x2N=(n1 + 
n2)nu2=sum( c(  ( x1 -mean(x1) )^2 , ( x2-mean(x2) )^2  ) )/Nss=c(e1,e2) b3= 
N*sum(ss^4)/ (sum( ss^2)^2)what do lines 6-8 (mathematical 
notation)?Also the, what means part?for(j in 1:B){ ss11=sample(x1, 
n1, replace=TRUE) ss12=sample(x2, n2, replace=TRUE) 
}I would appreciate you could help on my inquiry, 
and I am awaiting for your soon answer Thx in advance, Lusk 
 
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[R] Error in qr.solve(crossprod(xsar), t(xsar)) when using SpatialFiltering

2011-06-25 Thread Aquarius
I am using the R function SpatialFiltering to my land value dataset.

I compute a 500 by 500 binary spatial weight matrix (W) based on the x and y
coordinates in my land value dataset. The nearest 6 neighbours were given a
value of 1. By construction Wii=0. So my weight matrix look like
0 ..1 0 0 ... 1 0
0..1.0...
0...1..
# of rows= 500. # of columns =500. Row sum =6 (because of nearest
neighbour=6)

Then I fed the data into the SpatialFiltering fxn:
tmp = mat2listw(wt);
results= SpatialFiltering(LandValue ~ 1+AI+Area_SF_08+Dist2CBD05, data=lu2,
nb=tmp$neighbours, style=W, ExactEV=TRUE, zero.policy=TRUE)

%%%
Then an error message occur:
Error in qr.solve(crossprod(xsar), t(xsar)) : 
  singular matrix 'a' in solve

Can someone help me out?

Thank you so much in advance!

Yiyi

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[R] a Weighted Least Square model for a binary response variable

2011-06-25 Thread Vivian Zhuang
Dear R Users,

I would like to use R to fit a Weighted Least Square model for a
binary response variable, say Y.  The model is actually the model
widely used for a binary dependent variable when the logistic model
has not been invented. The weight is 1/(E(Y)(1-E(Y)).

Could someone help me out? Thanks for any replies in advance!

Best Regards,
Vivian

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Re: [R] Extract character from the end of a string

2011-06-25 Thread jwehr
Thank you, Joshua!

I got what I was looking for using this command:

as.numeric(grepl(\\*$, qb$Player))

Where the variable name is Player in dataset qb.

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[R] about partial response and partial residual

2011-06-25 Thread pigpigmeow
i use mgcv package

First, what is the different between partial response and partial residual
plot? 
actually, is it partial response is as same as partial regression?

second, if I use log-link fuction, how to plot partial response and
partial residual plot by R?

Finally, If I want to plot partial resonse and partial residual plot, Should
I create new gam equation by individual variable or all variables ?

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Re: [R] Fastest way of finding if any members of vector x fall in the range of the rows of matrix y

2011-06-25 Thread Dimitris Rizopoulos

yet another solution is:

v - c(1, 2, 6, 5)
w - matrix(c(1, 4, 3, 5, 8, 10), ncol = 2, byrow = TRUE)

check - outer(w[, 1], v, -) * outer(w[, 2], v, -)
v[which(check = 0, arr.ind = TRUE)[, 2]]


Best,
Dimitris


On 6/24/2011 10:05 PM, Martin Morgan wrote:

On 06/24/2011 11:12 AM, Dennis Murphy wrote:

Hi:

Not much different from Peter's approach, but here's another try:

v- c(1, 2, 6, 5)
w- matrix(c(1, 4, 3, 5, 8, 10), ncol = 2, byrow = TRUE)

w

[,1] [,2]
[1,] 1 4
[2,] 3 5
[3,] 8 10


f- function(x) v[which(v= x[1] v= x[2])]
unlist(apply(w, 1, f))
[1] 1 2 5

If you just do the apply() part, the function will return a list of
those elements of v that fall within the i-th interval.


Maybe

  v = c(1, 2, 6, 5)
  start = c(-Inf, 1, 3, 8)
  end = c(-Inf, 4, 5, 10)
  v[ v = end[findInterval(v, start)] ]

Also IRanges::findOverlaps / countOverlaps in Bioconductor

v[countOverlaps(IRanges(v, v), IRanges(start, end)) != 0]

http://bioconductor.org/install

Martin



HTH,
Dennis

On Fri, Jun 24, 2011 at 9:52 AM, Salih Tunasaliht...@gmail.com wrote:

Hi guys,

let's assume i have the following

1
x = 2
6
5

1 4
y = 3 5
8 10

i want the code to report back 1, 2 and 5 from x.
Basically it shopuld check whether each elements of x falls in the
range of
each row of x. 1 and 2 falls in between 1-4 and 5 falls in between 3-5.
I do this with two for loops but in the case of very large list, it
takes
ages.

best,
salih


On Fri, Jun 24, 2011 at 4:12 PM, Dennis Murphydjmu...@gmail.com wrote:


Hi:

That leaves open several possibilities. Could you please supply a
small, reproducible example (i.e., one that someone can copy and paste
into an R session) that illustrates the problem along with the
solution you expect?

TIA,
Dennis

On Fri, Jun 24, 2011 at 2:30 AM, Salih Tunasaliht...@gmail.com wrote:

Hi Dimitris,
Thanks for your reply. But this is not exactly what i am after. I want
to
find the probes that falls into certain regions. In your solution it
will
ignore the second probe if it falls into the same region as the first
one.
Is there any vector trickb uilt in R to find whether probes fall into
certain regions?
best,
salih

On Fri, Jun 24, 2011 at 10:23 AM, Dimitris Rizopoulos
d.rizopou...@erasmusmc.nl wrote:


One approach is the following:

x- rnorm(5)
y- matrix(rnorm(5*2), 5, 2)

check- y - x
check[, 1] * check[, 2] 0


I hope it helps.

Best,
Dimitris



On 6/24/2011 10:57 AM, Salih Tuna wrote:


Hi All,
What is the fastest way of finding if any members of vector x
fall in
the
range of the rows of matrix y?
I do not want to use two for loops as this will take forever.
Any help will be appreciated,
best,
salih

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Assistant Professor
Department of Biostatistics
Erasmus University Medical Center

Address: PO Box 2040, 3000 CA Rotterdam, the Netherlands
Tel: +31/(0)10/7043478
Fax: +31/(0)10/7043014
Web:
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--
Dimitris Rizopoulos
Assistant Professor
Department of Biostatistics
Erasmus University Medical Center

Address: PO Box 2040, 3000 CA Rotterdam, the Netherlands
Tel: +31/(0)10/7043478
Fax: +31/(0)10/7043014
Web: http://www.erasmusmc.nl/biostatistiek/

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Re: [R] On .. glibc detected home/sguha/lib64/R/bin/exec/R: realloc(): invalid next size: 0x000000000209e210 ***

2011-06-25 Thread Hugo Mildenberger
Saptarshi,

if you look at the sheer number of shared libraries involved, heap 
corruption may have happened due to errors in any of these. 
Finding the reason for such problems is usually difficult, but almost 
impossible without a reproducible example. If you could boil it down 
to a minimal example still triggering the access violation, one could 
try to run it under control of a memory guard like valgrind. 

Best

Hugo

On Friday 24 June 2011 17:12:26 Saptarshi Guha wrote:
 Hello,
 
 I'm trying to use rjson to parse a JSON object. The object can be found here
 
 http://pastebin.com/np0s5hgM
 
 (you'll probably need to add quotes around the content)
 
 
 fromJSON returns the error
  glibc detected home/sguha/lib64/R/bin/exec/R: realloc(): invalid next
 size: 0x0209e210 ***
 
 Is there a fix coming soon? Maybe CRAN should also have an outstanding
 bug field  - packages with unfixed bugs could be removed.
 
 
 Cheers
 Joy
 
 
 rjson- 0.2.3
 and
 
 R.version
_
 platform   x86_64-unknown-linux-gnu
 arch   x86_64
 os linux-gnu
 system x86_64, linux-gnu
 status
 major  2
 minor  13.0
 year   2011
 month  04
 day13
 svn rev55427
 language   R
 version.string R version 2.13.0 (2011-04-13)
 
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[R] Access R functions from web

2011-06-25 Thread Orvalho Augusto
I need a way to send R objects and call R functions from web. Is there any
project close or similar to that?

I want to be able to send an HTTP rquest from an existing application with
some data. And obtain a plot from R.

Thanks in advance
Caveman

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Re: [R] On .. glibc detected home/sguha/lib64/R/bin/exec/R: realloc(): invalid next size: 0x000000000209e210 ***

2011-06-25 Thread Uwe Ligges



On 25.06.2011 02:12, Saptarshi Guha wrote:

Hello,

I'm trying to use rjson to parse a JSON object. The object can be found here

http://pastebin.com/np0s5hgM

(you'll probably need to add quotes around the content)


fromJSON returns the error
  glibc detected home/sguha/lib64/R/bin/exec/R: realloc(): invalid next
size: 0x0209e210 ***

Is there a fix coming soon? Maybe CRAN should also have an outstanding
bug field  - packages with unfixed bugs could be removed.


But rather than posting to this list, you should send a message to the 
package maintainer including reproducible examples. Otherwise the 
package maintainer may not even be aware of any bug nor can he or she 
reproduce.


Uwe Ligges





Cheers
Joy


rjson- 0.2.3
and

R.version
_
platform   x86_64-unknown-linux-gnu
arch   x86_64
os linux-gnu
system x86_64, linux-gnu
status
major  2
minor  13.0
year   2011
month  04
day13
svn rev55427
language   R
version.string R version 2.13.0 (2011-04-13)

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[R] Problems setting language in R-2.13.0 and opening RData

2011-06-25 Thread Manabu Sakamoto
Dear list,

I just recently installed R-2.13.0 on my Windows7. I used to run R-2.10.0.

First of all, I used to be able to install R in English (in R-2.10.0)
during the installation procedure. My PC is in a Japanese environment
but I want R to be in English because I won't be able to interpret any
errors if they are in Japanese (I am Japanese so I can read them but I
won't be able to understand them). However, it seems that under
R-2.13.0, the option to install in English simply does not exist and I
have to associate LANGUAGE=en in the properties of all short cuts to
R.

This leads to my second problem. I usually open a saved work space by
double clicking on a .RData file. I had no problems in R-2.10.0 but in
R-2.13.0, even though I associated R-2.13.0 with RData files during
installation, I had problems opening them by double-clicking (it
always came up with a RTerm window) but I found a R for Windows GUI
front-end that I can associate my RData with which enabled me to open
RData in the R GUI. However, this R window is in Japanese.

So my question is: is there a way to set R itself in English
(including this R for Windows GUI front-end) and not just the pathways
from short cuts? Any suggestions would be most appreciated.

many thanks in advance.
Manabu
-- 
Manabu Sakamoto, PhD
School of Earth Sciences
University of Bristol
manabu.sakam...@googlemail.com

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Re: [R] Extract character from the end of a string

2011-06-25 Thread Uwe Ligges
1. Please always quote the original message when sending messages to 
this *mailing list*.
2. Please send your answers and comments also to the original poster who 
may not be aware you posted to the list.


Uwe Ligges




On 25.06.2011 06:55, jwehr wrote:

Thank you, Joshua!

I got what I was looking for using this command:

as.numeric(grepl(\\*$, qb$Player))

Where the variable name is Player in dataset qb.

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Re: [R] Time-series analysis with treatment effects - statistical approach

2011-06-25 Thread Mike Marchywka




 Date: Thu, 23 Jun 2011 15:41:25 -0700
 From: jmo...@student.canterbury.ac.nz
 To: r-help@r-project.org
 Subject: Re: [R] Time-series analysis with treatment effects - statistical 
 approach
 
 
 Mike Marchywka wrote:
  
  I discovered a way to do repetitive tasks that can be concisely specified
  using
  something called a computer.  
 
 Now that's funny :)

well, there is a point to that and that is that with cheap computations you can
do different analyses than you did in the past. 


 
 There were not controlled tests. It was a field experiment testing the
 effects that various pavement designs have on underlying soil moisture. Two
 designs incorporated a porous pavement surface course, while two others were
 based on standard impervious concrete pavement...the control was just bare,
 exposed soil. 
 
 As you can see from the graph, the control responds quickly to rainfall
 events, but dries out quickly as well due to evaporation. The porous
 pavement allows for quick infiltration of precipitation, while the
 impervious pavement eventually allows infiltration of rainfall, but it's
 delayed. 
 
 My objective is to be able to differentiate between the pavement treatments,
 such that I can state with statistical confidence that porous pavements
 affects underlying soil moisture differently than impervious pavements. 
 
 I think this is obvious just looking at it, but I wanted to be able to back
 it up with stats. What I'd done previously is to average by week. But as  I
 mentioned, I thought that an anova table with 104 rows relating to each week
 was a poor way of analyzing the data. But that being said, it effectively
 allows me to check for treatment-related differences. 

I don't think we've mentioned R in the past few posts but I guess pointing
people to useful things that R can do is not too big a problem and
if you have ever dealt with analysis for the sake of rationalization
you can appreciation that is a huge problem :)  Generally you'd
like to have reproducible results and if you don't have IID ( stationary
parameters of the population you wish to characterize) you
are not even asking a good question about the system.  It may
be helpful as quick check of something but otherwise difficult to
interpret- do your results mean these things are different in the
desert? You appear to have data points from a bunch of different situations.
After the fact selection is often helpful but generally stats people frown
on that as backing up anything ( unless it supports sponsor's opinion LOL). 

http://www.itl.nist.gov/div898/handbook/prc/section4/prc432.htm


I guess I'd either go with dynamic model or convert into dollars and then
see if you have clinically and statistically significant differences in things 
of relevance.



 
 Thanks for the suggestions to date. Maybe the more I explain what I'm trying
 to achieve, the more focussed the suggestions will be. The vaguer the
 question, the broader the response, right?
 
 Thanks again,
 Justin
 
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Re: [R] Need help on a R script part

2011-06-25 Thread Hugo Mildenberger
Lusk, 

if I were in your business, I would tackle such a problem with 
help from a little formatting ...

  e1=x1-mean(x1)
  e2=x2-mean(x2)
  n1=length(x1)
  n2=length(x2)
  N=(n1 + n2)
  nu2=sum( c(  ( x1 -mean(x1)  )^2 , ( x2-mean(x2)  )^2  ) )/N
  ss=c(e1,e2) 
  b3=N*sum(ss^4)/(sum( ss^2)^2)

  for(j in 1:B){ ss11=sample(x1, n1, replace=TRUE) 
  ss12=sample(x2, n2, replace=TRUE) } 


... afterwards I'd correct for missing parenthesis and such. But I 
understand that this approach was really not conducive when the 
main intention was to target the public by giving the unhappy college 
student who infelicitously bumped into a mountain of WWI-style 
razor wire. The wire-cutter equivalent tool the R interpreter provides 
you with is the question mark. Here are some examples how to use it:

?mean
?length
?sum
?sample
?^
?for
?in
?:
?=
?-
?+
?*
?/


Hope this helps.

Kind regards




On Friday 24 June 2011 15:31:44 Lusk Aris wrote:
 
 Hi all,
 I need all your help on this. I have the next part of 
 code:e1=x1-mean(x1)e2=x2-mean(x2)n1=length(x1)n2=length(x2N=(n1 + 
n2)nu2=sum( c(  ( x1 -mean(x1) )^2 , ( x2-mean(x2) )^2  ) )/Nss=c(e1,e2) b3= 
N*sum(ss^4)/ (sum( ss^2)^2)what do lines 6-8 (mathematical 
notation)?Also the, what means part?for(j in 1:B){ ss11=sample(x1, 
n1, replace=TRUE) ss12=sample(x2, n2, replace=TRUE) 
}I would appreciate you could help on my inquiry, 
and I am awaiting for your soon answer Thx in advance, Lusk 

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Re: [R] Competing-risks nomogram

2011-06-25 Thread Firas Abdollah
Many thanks for the prompt response.
However, I am afraid that it is not completely clear for me. I
apologize, I am not a statistician.
Sorry, may be what I will say make totally non sense, but what I
understood is the following:
Let's suppose that I need to predict cancer-specific survival using
the variables X and Y. What I need to do is to develop a model that
include these variables and predict cancer-specific survival using the
competing-risks regression. Then, I shall calculate the predictions
of this model at a certain time point, then I shall use these
prediction as an endpoint, and predict it using a linear regression
model that include the same variables, i.e X and Y. Finally, I use the
coefficients of this final model to develop a nomogram. Is that
correct?

Many thanks again




Should I calculate the prediction of the competing-risks regression
model, and then use this prediction as an endpoint and predict it
using a linear regression by including the same variables as
predictors?

On Fri, Jun 24, 2011 at 1:27 PM, Frank Harrell [via R]
ml-node+3622291-345449798-247...@n4.nabble.com wrote:
 Replace the Design package with the rms package.  Use the ordinary linear
 regression trick to predict the linear predictor from the competing risk
 regression, then use nomogram on this new model (that merely represents the
 fit of interest).
 Frank

 Firas Abdollah wrote:
 Hi R users,

 I'd like to draw a nomogram using a competing-risks regression (crr function
 in R), rather than a cox regression. However, the nomogram function provided
 in the Design package is not good for this purpose.
 Do you have any suggestion.
 I really appreciate your help

 Many thanks

 F.Abdollah, MD
 San-Raffele hospital
 Milan, Italy

 Frank Harrell
 Department of Biostatistics, Vanderbilt University

 
 If you reply to this email, your message will be added to the discussion
 below:
 http://r.789695.n4.nabble.com/Competing-risks-nomogram-tp3621907p3622291.html
 To unsubscribe from Competing-risks nomogram, click here.



-- 
Firas Abdollah, MD
Dept. of Urology
San Raffaele Hospital
Vita-Salute University,
Via Olgettina 60, 20132, Milan, Italy
Tel. +39 02 2643 7286
Fax. +39 02 2643 7298
E-mail: firas.abdol...@gmail.com


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Re: [R] Access R functions from web

2011-06-25 Thread Mike Marchywka




 From: orvaq...@gmail.com
 To: r-help@r-project.org
 Subject: [R] Access R functions from web
 
 I need a way to send R objects and call R functions from web. Is there any
 project close or similar to that?
 
 I want to be able to send an HTTP rquest from an existing application with
 some data. And obtain a plot from R.

This should be a faq but it can take a while to find, see Rserve and Rapache.
I have been using Rapache now on red hat and debian  and it works nicely.
Also, the goog visualization API works in some limited testing but apparently
a lot of that requires flash ( which I either did not have or had turned off 
LOL).




 
 Thanks in advance
 Caveman
 
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Re: [R] Problems setting language in R-2.13.0 and opening RData

2011-06-25 Thread Uwe Ligges



On 25.06.2011 11:48, Manabu Sakamoto wrote:

Dear list,

I just recently installed R-2.13.0 on my Windows7. I used to run R-2.10.0.

First of all, I used to be able to install R in English (in R-2.10.0)
during the installation procedure. My PC is in a Japanese environment
but I want R to be in English because I won't be able to interpret any
errors if they are in Japanese (I am Japanese so I can read them but I
won't be able to understand them). However, it seems that under
R-2.13.0, the option to install in English simply does not exist and I
have to associate LANGUAGE=en in the properties of all short cuts to
R.


The choice for a language in the installer was always just for the 
installer itself, not for R. This has not changed.


Of course you can set a glöobal environment variable LANGUAGE=en, which 
would be used by any R started on your machine (as well as for any other 
software that reads such a variable)


Uwe Ligges




This leads to my second problem. I usually open a saved work space by
double clicking on a .RData file. I had no problems in R-2.10.0 but in
R-2.13.0, even though I associated R-2.13.0 with RData files during
installation, I had problems opening them by double-clicking (it
always came up with a RTerm window) but I found a R for Windows GUI
front-end that I can associate my RData with which enabled me to open
RData in the R GUI. However, this R window is in Japanese.

So my question is: is there a way to set R itself in English
(including this R for Windows GUI front-end) and not just the pathways
from short cuts? Any suggestions would be most appreciated.

many thanks in advance.
Manabu


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Re: [R] try to generate graph for each element of my list

2011-06-25 Thread Uwe Ligges



On 24.06.2011 21:29, n.via...@libero.it wrote:

Dear all,
I have the following problem. I have a List of time series dataframe.I'm
trying to produce specific graph for each element of my list. The code is:
This is my list:
Lista_import-lapply(Lista_import, function(x){
x2-subset(x, select=c(ANNO,DICHIARANTE,PARTNER, quota))
x2-cast(x2, ANNO+DICHIARANTE~PARTNER)
x2- as.xts(as.matrix(as.timeSeries(x2)))
return(x2)})


each list have the following  shape:
$AUS
$DEU
and data inside...I'm not showing you the content cause I think is not
relevant


For the GRaph the code is

c-lapply(Lista_import,function(x){
for(i in names(Lista_import)){

legenda- read.csv
(/home/fturrini/Tessile/01_Dati_complementari/Legenda_paese.csv,header=TRUE)


The lihne above is independent from i in the loop, hence move it outside 
and rename the stuff below.



leg- data.frame(ISO3=colnames(x),inutile=1)
legenda- merge(legenda,leg, by=ISO3, all.y=TRUE)

png(paste(/home/Tessile/Output/Gra/MaxM/QuoteEXperPaese_,i,.png),
width=1661,height=828)



- ou should really prettify your code in order to make it readable. Use 
tabs and spaces where appropriate!


- You probably want paste(., sep=) above




graph-{par(bg=grey97, font=3,font.axis=3,bty=l,las=1, mar=c(8,6,4,2),
xpd=FALSE)
yrange-c(min(x,na.rm=TRUE), 1.05*max(x,na.rm=TRUE))
colori- c(Blue,Aquamarine1, Firebrick3, Chocolate4, BlueViolet,
Yellow3)

chart.TimeSeries(x, type=l,lwd=5, ylab=, xlab=, main=, date.format=%
Y, ylim=yrange, col=colori,
cex.axis=1.6, major.ticks=years, minor.ticks=FALSE, grid.color=gray50,
grid.lty=dotted)
legend(topleft,as.character(legenda$PAESE),bty=n,cex=1.7,lwd=5, ncol=2,
col=colori, horiz=F)


You want to write FALSE rather than F above.

I have not found the actual error, since your example is nopt 
reproducible and we do not know how your data look like.


Uwe Ligges




mtext(Fonte: Unctad, Pctas, side=1,line=5,adj=1,cex=1.8,col=grey20)
mtext(p, side=1,line=5,adj=0,cex=1.5,col=grey10)}}
dev.off()
rm(grafico)
})

The results is that I get the same graph for each element of my list.
Someone knows how to get one graph for each element of my list pasting the
names' list element  in the .png file??
Thanks for your attention!

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Re: [R] What does class call mean? How do I make class formula into a call?

2011-06-25 Thread David Winsemius


On Jun 24, 2011, at 6:12 PM, StellathePug wrote:


Hello R Users!
I have a list called tabs that I would like to have the same  
structure as
my list eqSystem. The two look like they have the same structure  
but they
are different because when I look at their attributes,  
class(eqSystem[[1]])
is call but class(tabs[[1]]) is formula. I want to have  
class(tabs[[1]])

as a call too.

So what does call mean?


An as yet unevaluated function invocation with first as the named  
function followed by quoted arguments is a call:


See the help(call) page:

 f - round
 A - 10.5
 (g - as.call(list(f, quote(A
.Primitive(round)(A)
 eval(g)
[1] 10

 call(mean, quote( c(1,2,3)))
mean(c(1, 2, 3))
 eval( call(mean, quote( c(1,2,3
[1] 2

It seems very unlikely that a formula object could be coerced into a  
valid call simply by altering its class. To convince us otherwise you  
need to provide more information than you have supplied to the  
present. The results of str() on these objects might be a first step.


--
David.


And how do I make an object of class formula be of class call?
Thank you so much!!!--Rita



class(tabs)

[1] list

class(tabs[1])

[1] list

class(tabs[[1]])

[1] formula class(eqSystem)
[1] list

class(eqSystem[1])

[1] list

class(eqSystem[[1]])

[1] call

Rita
=
If you think education is expensive, try ignorance.--Derek Bok

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West Hartford, CT

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Re: [R] Installation of bigmemory fails

2011-06-25 Thread Jay Emerson
Premal,

Package authors generally welcome direct emails.

We've been away from this project since the release of 2.13.0 and I only just
noticed the build errors.  These generally occur because of some (usually
small and solvable) problem with compilers and the BOOST libraries.  We'll
look at it and see what we can do.  Please email us if you don't hear back
in the next week or so.

Thanks,

Jay


---
Hello All,
I tried to intall the bigmemory package from a CRAN mirror site and
received the following output while installing. Any idea what's going
on and how to fix it? The system details are provided below.

- begin error messages ---
* installing *source* package 'bigmemory' ...
 checking for Sun Studio compiler...no
 checking for Darwin...yes
** libs
g++45 -I/usr/local/lib/R/include -I../inst/include -fpic  -O2
-fno-strict-aliasing -pipe -Wl,-rpath=/usr/local/lib/gcc45 -c B\
igMatrix.cpp -o BigMatrix.o
g++45 -I/usr/local/lib/R/include -I../inst/include -fpic  -O2
-fno-strict-aliasing -pipe -Wl,-rpath=/usr/local/lib/gcc45 -c S\
haredCounter.cpp -o SharedCounter.o
g++45 -I/usr/local/lib/R/include -I../inst/include -fpic  -O2
-fno-strict-aliasing -pipe -Wl,-rpath=/usr/local/lib/gcc45 -c b\
igmemory.cpp -o bigmemory.o
bigmemory.cpp: In function 'bool TooManyRIndices(index_type)':
bigmemory.cpp:40:27: error: 'powl' was not declared in this scope
*** Error code 1

Stop in /tmp/Rtmpxwe3p4/R.INSTALL4f539336/bigmemory/src.
ERROR: compilation failed for package 'bigmemory'
* removing '/usr/local/lib/R/library/bigmemory'

The downloaded packages are in
   '/tmp/RtmpMZCOVp/downloaded_packages'
Updating HTML index of packages in '.Library'
Making packages.html  ... done
Warning message:
In install.packages(bigmemory) :
 installation of package 'bigmemory' had non-zero exit status
- end error messages -
It's a 64-bit FreeBSD 7.2 system running R version 2-13.0.
Thanks,
Premal

-- 
John W. Emerson (Jay)
Associate Professor of Statistics
Department of Statistics
Yale University
http://www.stat.yale.edu/~jay

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[R] AUTO: Chalk, Alan has a new email address

2011-06-25 Thread Alan Chalk


I am out of the office until 01/05/2012.

Please note that I have changed email address.  You can contact me at
alan.ch...@uk.rsagroup.com


Note: This is an automated response to your message  R-help Digest, Vol
100, Issue 26 [Virus checked] sent on 25/06/2011 11:00:11.

This is the only notification you will receive while this person is away.

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This transmission contains information that may be confidential and that may 
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Re: [R] texi2dvi runs but produces no output

2011-06-25 Thread David Hewitt
Christiaan,

Sorry I did not respond earlier. I have been away on vacation. With
all the changes in LyX 2.x to make Sweave stuff easier, I suspect this
problem should go away. I have not upgraded my system, but a couple
folks that have done so reported no problems with a setup like yours.
Probably best to send a request to the LyX users' list to get this
resolved, as LyX development is very interested in this aspect
nowadays.

http://www.lyx.org/MailingLists#toc4

- Dave



2011/6/17 Uwe Ligges lig...@statistik.tu-dortmund.de:


 On 17.06.2011 09:24, christiaan pauw wrote:

 Thanks for the advice. I tried to install the package as instructed.
 Command
 and results below:

 install.packages(patchDVI, repos=http://R-Forge.R-project.org;)

 Installing package(s) into ‘C:/Users/nova/Documents/R/win-library/2.13’
 (as ‘lib’ is unspecified)
 Warning message:
 In getDependencies(pkgs, dependencies, available, lib) :
   package ‘patchDVI’ is not available (for R version 2.13.0)


 The problem is that the Windows binary of that package is really not
 available on R-Forge.

 You can install from sources if you ask R to:

 install.packages(patchDVI, repos=http://R-Forge.R-project.org;,
 type=source)

 given you have the Rtools installed.



 I then ran the tests in Rtools.

 Which tests in Rtools???

 I suspect the fact that I have I have
 installed R in a path containing spaces may be the problem - maybe also
 for

 Paths with spaces generate problems for LaTeX and R tries to work around,
 but may fail.


 Not sure why you do the stuff below at all and why R cannot change the
 working directory.

 Uwe Ligges


 the Sweave part. Is there any other remedy but to re-install R or can I
 insert a link in a path without spaces  ?

  library(tools)
      testInstalledBasic(both)



 running strict specific tests
   running code in ‘eval-etc.R’
 unable to open output file
 FAILED
 [1] 1
 Warning message:
 running command 'C:/PROGRA~1/R/R-213~1.0/bin/i386/R CMD BATCH --vanilla
 --no-timing eval-etc.R eval-etc.Rout' had status 2

      testInstalledPackages(base)

 Error in setwd(outDir) : cannot change working directory

      testInstalledPackages(recommended)

 Error in setwd(outDir) : cannot change working directory



 On 16 June 2011 14:10, Duncan Murdochmurdoch.dun...@gmail.com  wrote:

 On 11-06-16 7:50 AM, christiaan pauw wrote:

 Hi everybody.

 Was the problem below ever solved? I have the same problem on Windows 7
 with
 R 2.13.0 and LyX 2 - everything freshly installed. My Rweave.bat and
 MakeSweave.R files are similar to below (I followed
 http://wiki.lyx.org/uploads/**LaTeX/SweaveR/lyx_with_r_and_**

 sweave_instructions.pdfhttp://wiki.lyx.org/uploads/LaTeX/SweaveR/lyx_with_r_and_sweave_instructions.pdf
 )


 I don't use LyX or that batch file, I use some code I wrote that's in the
 patchDVI package
 (https://r-forge.r-project.**org/R/?group_id=233https://r-forge.r-project.org/R/?group_id=233)
 that I wrote.  You might want to try it.

 The single line to run Sweave and pdflatex is

 Rscript -e patchDVI::SweavePDF( '$1' )

 where $1 is the name of the .Rnw file.  If that doesn't work for you, I
 might be able to help with debugging.

 Duncan Murdoch



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Re: [R] Need help on a R script part

2011-06-25 Thread Mike Miller
I'm curious about what would cause this (see below), if it isn't a joke. 
Is it possible that it didn't look ridiculous in the deleted HTML but the 
text looked bad?  It's almost unreadable.  I guess the HTML gets deleted 
because it is a waste of space, but I received a 14 MB message from this 
list the other day.


Mike


On Fri, 24 Jun 2011, Lusk Aris wrote:


Hi all,
I need all your help on this. I have the next part of 
code:e1=x1-mean(x1)e2=x2-mean(x2)n1=length(x1)n2=length(x2N=(n1 + 
n2)nu2=sum( c(  ( x1 -mean(x1) )^2 , ( x2-mean(x2) )^2  ) )/Nss=c(e1,e2) b3= 
N*sum(ss^4)/ (sum( ss^2)^2)what do lines 6-8 (mathematical 
notation)?Also the, what means part?for(j in 1:B){ ss11=sample(x1, 
n1, replace=TRUE) ss12=sample(x2, n2, replace=TRUE) 
}I would appreciate you could help on my inquiry, 
and I am awaiting for your soon answer Thx in advance, Lusk
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[R] integration function

2011-06-25 Thread li li
Hi all,
   Can anyone please take a look at the following two functions.
The answer does not seem to be right.
   Thank you very much!

f1 - function(x)

{integrand - function (x, mu){

dnorm(x, mean=mu, sd=1)*dnorm(mu, mean=2, sd=1)

   }

integrate(integrand, -Inf, Inf,x)$val

}


f2 - function(x)

{integrand - function (x, mu){

dnorm(x, mean=mu, sd=1)*mu^2*dnorm(mu, mean=2, sd=1)

   }

integrate(integrand, -Inf, Inf,x)$val

}

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[R] Vector with factors inside lists/tuples

2011-06-25 Thread Håvard Wahl Kongsgård
Hi, this seems like a strange question, but in R is there a function that
can handle vectors containing factors inside lists/tuples? Or is there some
other approach/functions I can use?
Like for example

V1
{Harry,Brown)
{Brown,Harry)

I want to use these variables in a machine learning setting, And don't want
to convert these into multiple vectors, given share number of factors.

-- 
Håvard Wahl Kongsgård

http://havard.security-review.net/

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Re: [R] integration function

2011-06-25 Thread Peter Ehlers

On 2011-06-25 08:48, li li wrote:

Hi all,
Can anyone please take a look at the following two functions.
The answer does not seem to be right.
Thank you very much!

f1- function(x)

 {integrand- function (x, mu){

 dnorm(x, mean=mu, sd=1)*dnorm(mu, mean=2, sd=1)

}

 integrate(integrand, -Inf, Inf,x)$val

 }


f2- function(x)

 {integrand- function (x, mu){

 dnorm(x, mean=mu, sd=1)*mu^2*dnorm(mu, mean=2, sd=1)

}

 integrate(integrand, -Inf, Inf,x)$val

 }


Your x and mu will get mightily confused.
The argument x in f1 is in fact used as the argument mu
in integrand() because, as the help page clearly indicates,
additional arguments follow the lower/upper limits in integrate().

A cleaner version of what you're doing is the following:

 f1 - function(mu){
   integrand - function (x, mu){
 dnorm(x, mean=mu, sd=1) * dnorm(mu, mean=2, sd=1)
   }
   integrate(integrand, -Inf, Inf, mu)[[value]]
 }

But then again, you could just evaluate dnorm(mu, 2, 1).
So I suspect that you want something different.

Ditto for f2.

Peter Ehlers



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Re: [R] Vector with factors inside lists/tuples

2011-06-25 Thread Håvard Wahl Kongsgård
Well, when a think of it using an array would be a simple solution.
But to what extent are arrays supported by other R functions?

-Håvard

2011/6/25 Håvard Wahl Kongsgård haavard.kongsga...@gmail.com

 Hi, this seems like a strange question, but in R is there a function that
 can handle vectors containing factors inside lists/tuples? Or is there some
 other approach/functions I can use?
 Like for example

 V1
 {Harry,Brown)
 {Brown,Harry)

 I want to use these variables in a machine learning setting, And don't want
 to convert these into multiple vectors, given share number of factors.

 --
 Håvard Wahl Kongsgård

 http://havard.security-review.net/



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Re: [R] Vector with factors inside lists/tuples

2011-06-25 Thread David Winsemius


On Jun 25, 2011, at 12:49 PM, Håvard Wahl Kongsgård wrote:

Hi, this seems like a strange question, but in R is there a function  
that

can handle vectors containing factors inside lists/tuples?


Yes, A very strange question, indeed ... since dataframes are lists  
that commonly contain vectors of factors and you should have  
encountered them very early in your self-study of R. The number of  
functions that operate on dataframes is large. Are you very early in  
efforts at learning R? Have you read the Posting Guide? (You're still  
posting html format.)


?factor
?list
?dataframe


Or is there some
other approach/functions I can use?
Like for example

V1
{Harry,Brown)
{Brown,Harry)


Is that an example that would make sense in some other language?  
(Opening curly-brace and closing paren makes no sense in R or  for  
that matter in what small amount I know of set theory.) Since your  
example makes no sense, it remains possible that you're looking for  
set operations:


?union



I want to use these variables in a machine learning setting, And  
don't want

to convert these into multiple vectors, given share number of factors.


Lists (of which dataframes are one specific example) are the usual  
method of handling structures of arbitrary structure (including  
factors). 'lapply' is the usual choice for repetitive application of a  
function to elements of lists. The is also 'rapply' for recursive  
application


 lapply(list(factor(letters[1:10]), list(c(1:10), c(20:30) ),  
letters[10:20]), length)

[[1]]
[1] 10

[[2]]   # second element is a list with two members
[1] 2   # lapply() only works with the first 'level' of a list

[[3]]
[1] 11
 rapply(list(factor(letters[1:10]), list(c(1:10), c(20:30) ),  
letters[10:20]), length)

[1] 10 10 11 11
 lapply(list(factor(letters[1:10]), list(c(1:10), c(20:30) ),  
letters[10:20]), class)

[[1]]
[1] factor

[[2]]
[1] list

[[3]]
[1] character

--

David Winsemius, MD
West Hartford, CT

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[R] How to export to pdf in landscape orientation?

2011-06-25 Thread Juan Andres Hernandez
Does anybody know how to get a pdf file with landscape orientation?.

  pdf(file= 'my_file.pdf' ,onefile=T,paper='A4')
plot(sin, -pi, 2*pi)
   dev.off()

Thank's in advance

Juan A. Hernandez
Spain

[[alternative HTML version deleted]]

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] Vector with factors inside lists/tuples

2011-06-25 Thread David Winsemius


On Jun 25, 2011, at 1:33 PM, Håvard Wahl Kongsgård wrote:


Well, when a think of it using an array would be a simple solution.
But to what extent are arrays supported by other R functions?


Arrays are well supported by arithmetic, logical and accessor  
functions. Your questions seem very unfocussed. Arrays of factors  
might be a bit difficult since factors in R require preservation of  
attributes which arrays (and matrices) do not allow.




-Håvard

2011/6/25 Håvard Wahl Kongsgård haavard.kongsga...@gmail.com

Hi, this seems like a strange question, but in R is there a  
function that
can handle vectors containing factors inside lists/tuples? Or is  
there some

other approach/functions I can use?
Like for example

V1
{Harry,Brown)
{Brown,Harry)

I want to use these variables in a machine learning setting, And  
don't want
to convert these into multiple vectors, given share number of  
factors.


--
Håvard Wahl Kongsgård

http://havard.security-review.net/




[[alternative HTML version deleted]]


Still posting html format.


PLEASE do read the posting guide http://www.R-project.org/posting-guide.html

--

David Winsemius, MD
West Hartford, CT

__
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and provide commented, minimal, self-contained, reproducible code.


Re: [R] How to export to pdf in landscape orientation?

2011-06-25 Thread Rainer Schuermann
Tell PDF the size of your piece of paper - here is what works for me:

pdf( file = result.pdf, width = 28, height = 18 ) # numbers are cm
some( stuff )
dev.off()

Hope it helps,
Rainer


On Saturday 25 June 2011 18:46:28 Juan Andres Hernandez wrote:
 Does anybody know how to get a pdf file with landscape orientation?.
 
   pdf(file= 'my_file.pdf' ,onefile=T,paper='A4')
 plot(sin, -pi, 2*pi)
dev.off()
 
 Thank's in advance
 
 Juan A. Hernandez
 Spain
 
   [[alternative HTML version deleted]]
 
 __
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 and provide commented, minimal, self-contained, reproducible code.

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] How to export to pdf in landscape orientation?

2011-06-25 Thread Sarah Goslee
From the help for pdf:

  paper: the target paper size.  The choices are ‘a4’, ‘letter’,
  ‘legal’ (or ‘us’) and ‘executive’ (and these can be
  capitalized), or ‘a4r’ and ‘USr’ for rotated
  (‘landscape’).

So I'd use paper='a4r'. You can also set the width and height
directly.

Sarah

On Sat, Jun 25, 2011 at 1:46 PM, Juan Andres Hernandez
jhernandezcabr...@gmail.com wrote:
 Does anybody know how to get a pdf file with landscape orientation?.

  pdf(file= 'my_file.pdf' ,onefile=T,paper='A4')
    plot(sin, -pi, 2*pi)
   dev.off()

 Thank's in advance

 Juan A. Hernandez
 Spain



-- 
Sarah Goslee
http://www.functionaldiversity.org

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Re: [R] Vector with factors inside lists/tuples

2011-06-25 Thread Håvard Wahl Kongsgård
Hi, sorry my question was not really clear

 |Are you very early in efforts at learning R?
No, have been a long term user of R, but only use R for the statistical stuff.

The heart of the issue is that I have list of keywords that I want to
analyse with a machine learning algorithm (20 000 keywords with a
response variables). It's much like micro array data, but in my case
it's not genes, but instead keywords. To get it to work in R, I
could create a data frame with multiple vectors containing different
factors.
That would look like this
V1, V2,
Harry, Kline
Brown, Larry

If I am not mistaken if I used V1 and V2 with the standard GLM
function the result would be like

glm( V0 ~ HARRY  + KLINE + Brown + Larry)

Or I could create a complex ordered array where keywords are
represented 1 and 0.
If I used that in GLM I would get the same result with glm?

But is there a better approach?

-Håvard

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] Vector with factors inside lists/tuples

2011-06-25 Thread David Winsemius


On Jun 25, 2011, at 2:13 PM, Håvard Wahl Kongsgård wrote:


Hi, sorry my question was not really clear

 |Are you very early in efforts at learning R?
No, have been a long term user of R, but only use R for the  
statistical stuff.


The heart of the issue is that I have list of keywords that I want to
analyse with a machine learning algorithm (20 000 keywords with a
response variables). It's much like micro array data, but in my case
it's not genes, but instead keywords. To get it to work in R, I
could create a data frame with multiple vectors containing different
factors.
That would look like this
V1, V2,
Harry, Kline
Brown, Larry

If I am not mistaken if I used V1 and V2 with the standard GLM
function the result would be like

glm( V0 ~ HARRY  + KLINE + Brown + Larry)


No. You are mistaken. Assuming that V0 is defined and has the same  
length as there are rows in that data.frame, then V1 and V2 would be  
the arguments in the formula and they would not be quoted.


?glm   # and work through the examples



Or I could create a complex ordered array where keywords are
represented 1 and 0.
If I used that in GLM I would get the same result with glm?

But is there a better approach?

-Håvard


David Winsemius, MD
West Hartford, CT

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] Problems setting language in R-2.13.0 and opening RData

2011-06-25 Thread Prof Brian Ripley

Please see the rw-FAQ.

And your claims about 2.10.0 are simply not true.  There only ever has 
been an option to choose the language of the installer: see the 
rw-FAQ.


On Sat, 25 Jun 2011, Manabu Sakamoto wrote:


Dear list,

I just recently installed R-2.13.0 on my Windows7. I used to run R-2.10.0.

First of all, I used to be able to install R in English (in R-2.10.0)
during the installation procedure. My PC is in a Japanese environment
but I want R to be in English because I won't be able to interpret any
errors if they are in Japanese (I am Japanese so I can read them but I
won't be able to understand them). However, it seems that under
R-2.13.0, the option to install in English simply does not exist and I
have to associate LANGUAGE=en in the properties of all short cuts to
R.


You can set environment variables globally, which it seems is what you 
want.  Then any product using GNU gettext will give your messages in 
English.  (Windows may still give your Japanese messages.)



This leads to my second problem. I usually open a saved work space by
double clicking on a .RData file. I had no problems in R-2.10.0 but in
R-2.13.0, even though I associated R-2.13.0 with RData files during
installation, I had problems opening them by double-clicking (it
always came up with a RTerm window) but I found a R for Windows GUI
front-end that I can associate my RData with which enabled me to open
RData in the R GUI. However, this R window is in Japanese.

So my question is: is there a way to set R itself in English
(including this R for Windows GUI front-end) and not just the pathways
from short cuts? Any suggestions would be most appreciated.

many thanks in advance.
Manabu
--
Manabu Sakamoto, PhD
School of Earth Sciences
University of Bristol
manabu.sakam...@googlemail.com

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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.



--
Brian D. Ripley,  rip...@stats.ox.ac.uk
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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Re: [R] Need help on a R script part

2011-06-25 Thread Duncan Murdoch

On 11-06-25 11:33 AM, Mike Miller wrote:

I'm curious about what would cause this (see below), if it isn't a joke.
Is it possible that it didn't look ridiculous in the deleted HTML but the
text looked bad?  It's almost unreadable.  I guess the HTML gets deleted
because it is a waste of space, but I received a 14 MB message from this
list the other day.


I imagine you need to contact the poster, and find out what they sent. 
It's hard to diagnose after it's been mangled.


Duncan Murdoch



Mike


On Fri, 24 Jun 2011, Lusk Aris wrote:


Hi all,
I need all your help on this. I have the next part of 
code:e1=x1-mean(x1)e2=x2-mean(x2)n1=length(x1)n2=length(x2N=(n1 + 
n2)nu2=sum( c(  ( x1 -mean(x1) )^2 , ( x2-mean(x2) )^2  ) )/Nss=c(e1,e2) b3= 
N*sum(ss^4)/ (sum( ss^2)^2)what do lines 6-8 (mathematical 
notation)?Also the, what means part?for(j in 1:B){ ss11=sample(x1, 
n1, replace=TRUE) ss12=sample(x2, n2, replace=TRUE) 
}I would appreciate you could help on my inquiry, 
and I am awaiting for your soon answer Thx in advance, Lusk
[[alternative HTML version deleted]]


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Re: [R] Access R functions from web

2011-06-25 Thread Tobias Verbeke

Hi Caveman,

On 06/25/2011 11:18 AM, Orvalho Augusto wrote:


I need a way to send R objects and call R functions from web. Is there any
project close or similar to that?

I want to be able to send an HTTP rquest from an existing application with
some data. And obtain a plot from R.


This is one of the typical integration scenarios
the R Service Bus is able to cope with.

http://www.openanalytics.eu/r-service-bus

The REST interface is documented here

http://rsb.doc.openanalytics.eu/
http://rsb.doc.openanalytics.eu/wsdocs/index.html

Best,
Tobias

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Re: [R] Competing-risks nomogram

2011-06-25 Thread Frank Harrell
Yes you use the linear predictor from your regression as the dependent
variable in the rms package's ols function.  You will get an R^2 of 1.0. 
You can depict the ols model with nomogram().  Note that there are so many
statistical issues in competing risks that doing this without a statistician
is risky.
Frank


-
Frank Harrell
Department of Biostatistics, Vanderbilt University
--
View this message in context: 
http://r.789695.n4.nabble.com/Competing-risks-nomogram-tp3621907p3625011.html
Sent from the R help mailing list archive at Nabble.com.

__
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and provide commented, minimal, self-contained, reproducible code.


Re: [R] Vector with factors inside lists/tuples

2011-06-25 Thread Håvard Wahl Kongsgård
 glm( V0 ~ HARRY  + KLINE + Brown + Larry)

 No. You are mistaken. Assuming that V0 is defined and has the same length as
 there are rows in that data.frame, then V1 and V2 would be the arguments in
 the formula and they would not be quoted.

 ?glm   # and work through the examples

With the example I meant that the factors in the vector V1 and V2
would be treated like individual binary/dummy variables.

Back to my real question; Is there no other way to do this in R???


2011/6/25 David Winsemius dwinsem...@comcast.net:

 On Jun 25, 2011, at 2:13 PM, Håvard Wahl Kongsgård wrote:

 Hi, sorry my question was not really clear

  |Are you very early in efforts at learning R?
 No, have been a long term user of R, but only use R for the statistical
 stuff.

 The heart of the issue is that I have list of keywords that I want to
 analyse with a machine learning algorithm (20 000 keywords with a
 response variables). It's much like micro array data, but in my case
 it's not genes, but instead keywords. To get it to work in R, I
 could create a data frame with multiple vectors containing different
 factors.
 That would look like this
 V1, V2,
 Harry, Kline
 Brown, Larry

 If I am not mistaken if I used V1 and V2 with the standard GLM
 function the result would be like

 glm( V0 ~ HARRY  + KLINE + Brown + Larry)

 No. You are mistaken. Assuming that V0 is defined and has the same length as
 there are rows in that data.frame, then V1 and V2 would be the arguments in
 the formula and they would not be quoted.

 ?glm   # and work through the examples


 Or I could create a complex ordered array where keywords are
 represented 1 and 0.
 If I used that in GLM I would get the same result with glm?

 But is there a better approach?

 -Håvard

 David Winsemius, MD
 West Hartford, CT





-- 
Håvard Wahl Kongsgård

http://havard.security-review.net/

__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] What does class call mean? How do I make class formula into a call?

2011-06-25 Thread peter dalgaard

On Jun 25, 2011, at 15:24 , David Winsemius wrote:

 
 On Jun 24, 2011, at 6:12 PM, StellathePug wrote:
 
 Hello R Users!
 I have a list called tabs that I would like to have the same structure as
 my list eqSystem. The two look like they have the same structure but they
 are different because when I look at their attributes, class(eqSystem[[1]])
 is call but class(tabs[[1]]) is formula. I want to have class(tabs[[1]])
 as a call too.
 
 So what does call mean?
 
 An as yet unevaluated function invocation with first as the named function 
 followed by quoted arguments is a call:
 
 See the help(call) page:
 
  f - round
  A - 10.5
  (g - as.call(list(f, quote(A
 .Primitive(round)(A)
  eval(g)
 [1] 10
 
  call(mean, quote( c(1,2,3)))
 mean(c(1, 2, 3))
  eval( call(mean, quote( c(1,2,3
 [1] 2
 
 It seems very unlikely that a formula object could be coerced into a valid 
 call simply by altering its class. To convince us otherwise you need to 
 provide more information than you have supplied to the present. The results 
 of str() on these objects might be a first step.

Actually, no. Any unevaluated expression in R is mode call, unless atomic or 
symbol. It will also be class call, unless expressedly overridden by an S3 
class assignment. Notice that operators are really function calls.
I.e. 

 mode(quote(x+y))
[1] call
 class(quote(x+y))
[1] call

But 

 class(quote(x))
[1] name
 class(quote(3.14159))
[1] numeric

(This is why the R docs keep talking about unevaluated expressions instead of 
call objects: They aren't always that.)

The ~ operator is also a function call. However, evaluating ~ returns an 
object which is the actual call assigned class formula (plus an environment 
attribute). 
 
 f - y ~ x
 class(f)
[1] formula
 unclass(f)
y ~ x
attr(,.Environment)
environment: R_GlobalEnv
 mode(f)
[1] call
 class(unclass(f))
[1] call

I.e., an unevaluated formulae expression (as in quote(y~x)) is class call, as 
is an unclassed formula object. So it is pretty easy to have objects of class 
formula very similar to objects of class call.

-- 
Peter Dalgaard
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Email: pd@cbs.dk  Priv: pda...@gmail.com

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] Vector with factors inside lists/tuples

2011-06-25 Thread David Winsemius


On Jun 25, 2011, at 4:01 PM, Håvard Wahl Kongsgård wrote:


glm( V0 ~ HARRY  + KLINE + Brown + Larry)


No. You are mistaken. Assuming that V0 is defined and has the same  
length as
there are rows in that data.frame, then V1 and V2 would be the  
arguments in

the formula and they would not be quoted.

?glm   # and work through the examples


With the example I meant that the factors in the vector V1 and V2
would be treated like individual binary/dummy variables.


They would have been with the call I offered. I get the sense that the  
best advice might be to consult a local statistician.




Back to my real question; Is there no other way to do this in R???


Do this? You have offered no workable example and only the vaguest  
of descriptions of the task.


--
David.



2011/6/25 David Winsemius dwinsem...@comcast.net:


On Jun 25, 2011, at 2:13 PM, Håvard Wahl Kongsgård wrote:


Hi, sorry my question was not really clear

 |Are you very early in efforts at learning R?
No, have been a long term user of R, but only use R for the  
statistical

stuff.

The heart of the issue is that I have list of keywords that I want  
to

analyse with a machine learning algorithm (20 000 keywords with a
response variables). It's much like micro array data, but in my  
case

it's not genes, but instead keywords. To get it to work in R, I
could create a data frame with multiple vectors containing different
factors.
That would look like this
V1, V2,
Harry, Kline
Brown, Larry

If I am not mistaken if I used V1 and V2 with the standard GLM
function the result would be like

glm( V0 ~ HARRY  + KLINE + Brown + Larry)


No. You are mistaken. Assuming that V0 is defined and has the same  
length as
there are rows in that data.frame, then V1 and V2 would be the  
arguments in

the formula and they would not be quoted.

?glm   # and work through the examples



Or I could create a complex ordered array where keywords are
represented 1 and 0.
If I used that in GLM I would get the same result with glm?

But is there a better approach?

-Håvard


David Winsemius, MD
West Hartford, CT






--
Håvard Wahl Kongsgård

http://havard.security-review.net/


David Winsemius, MD
West Hartford, CT

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] How to export to pdf in landscape orientation?

2011-06-25 Thread Berry Boessenkool


Hey Juan,

paper=a4r or USr for rotated (‘landscape’))

i.e.

pdf(file='my_file.pdf', onefile=T, paper='A4r')
plot(sin, -pi, 2*pi)  ;  dev.off()


Greetings from Potsdam University, Germany,
Berry Boessenkool




 From: jhernandezcabr...@gmail.com
 Date: Sat, 25 Jun 2011 18:46:28 +0100
 To: r-help@r-project.org
 Subject: [R] How to export to pdf in landscape orientation?
 
 Does anybody know how to get a pdf file with landscape orientation?.
 
   pdf(file= 'my_file.pdf' ,onefile=T,paper='A4')
 plot(sin, -pi, 2*pi)
dev.off()
 
 Thank's in advance
 
 Juan A. Hernandez
 Spain
 
   [[alternative HTML version deleted]]
 
 __
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 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.
  
[[alternative HTML version deleted]]

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and provide commented, minimal, self-contained, reproducible code.


[R] Moving average in a data table

2011-06-25 Thread Roman Naumenko

Hi,

I'm trying to figure out common approach on calculating MA on a dataset 
that contains column time.


After digging around, I believe functions rollmean and rollaply should 
be used.

However I don't quite understand the requirements for the underlying data.
Should it be zoo object type? Formatted in a special way?

As an example, I'm looking to get calculated avg=MA(variable) over 15 
sec period on time_sec column:


 date   variable   time_sec avg
 2011-05-17 132.55 11:29:59.579 132.55
 2011-05-17 132.65 11:29:59.946 132.60
 2011-05-17 132.5  11:29:59.946 132.57
 2011-05-17 132.5  11:29:59.946 132.55
 2011-05-17 132.55 11:29:59.946 132.55
 2011-05-17 132.6  11:29:59.946 132.56
 2011-05-17 132.55 11:29:59.946 132.56
 2011-05-17 132.65 11:29:59.947 132.57
 2011-05-17 132.85 11:30:00.45  132.60
 2011-05-17 132.9  11:30:00.45  132.63
 2011-05-17 133.05 11:30:00.45  132.67
 2011-05-17 132.2  11:30:00.45  132.63
 2011-05-17 132.5  11:30:00.45  132.62
 2011-05-17 132.7  11:30:00.50  132.63
 2011-05-17 132.75 11:30:00.57  132.63
 2011-05-17 132.55 11:30:00.70  132.63
 2011-05-17 132.25 11:30:00.70  132.61
 2011-05-17 132.25 11:30:00.71  132.59
 2011-05-17 132.35 11:30:00.173 132.57
 2011-05-17 132.45 11:30:00.173 132.57


Any help is really appreciated.

Thanks,
--Roman N.

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Re: [R] Competing-risks nomogram

2011-06-25 Thread Firas Abdollah
Many thanks

On Sat, Jun 25, 2011 at 10:00 PM, Frank Harrell [via R]
ml-node+3625011-8897305-247...@n4.nabble.com wrote:
 Yes you use the linear predictor from your regression as the dependent
 variable in the rms package's ols function.  You will get an R^2 of 1.0.
  You can depict the ols model with nomogram().  Note that there are so many
 statistical issues in competing risks that doing this without a statistician
 is risky.
 Frank
 Frank Harrell
 Department of Biostatistics, Vanderbilt University

 
 If you reply to this email, your message will be added to the discussion
 below:
 http://r.789695.n4.nabble.com/Competing-risks-nomogram-tp3621907p3625011.html
 To unsubscribe from Competing-risks nomogram, click here.



-- 
Firas Abdollah, MD
Dept. of Urology
San Raffaele Hospital
Vita-Salute University,
Via Olgettina 60, 20132, Milan, Italy
Tel. +39 02 2643 7286
Fax. +39 02 2643 7298
E-mail: firas.abdol...@gmail.com


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[R] log-link function problem

2011-06-25 Thread pigpigmeow
y-gam(a~s(b),family=gaussian(link=log),data) 
y-gam(loga~s(b), family =gaussian (link=identity),data)
y-gam(loga~s(b),family=gaussian(link=log),data) 
what are the diffent these 3 equations?

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[R] Multivariate normal density in C for R

2011-06-25 Thread zerfetzen
Does anyone know of a package that uses C code to calculate a multivariate
normal density?

My goal is to find a faster way to calculate MVN densities and avoid R loops
or apply functions, such as when X and mu are N x K matrices, as opposed to
vectors, and in this particular case, speed really matters. I would like to
be able to use .C or .Call to pass X, mu, Sigma, and N to a C program and
have it return a vector of log densities to R.

I'm new to putting C in R, but am sure I'll figure it out. Thanks for any
suggestions.

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[R] calling R from C

2011-06-25 Thread Desi Ap
I read R extensions on calling R within c code. I am on windows vista, cygwin 
and R-2.13.0.I can compile  link the c code with following commands$gcc 
-I/cygdrive/c/Progra~1/R/R-2.13.0/include -c -ggdb Rhello.c
gcc-L/cygdrive/c/Progra~1/R/R-2.13.0/bin/i386 -oRhello Rhello.o -lR
However I cant run the resulting .exe file with following command
LD_LIBRARY_PATH=/cygdrive/c/Progra~1/R/R-2.13.0/bin R_HOME=/cygdrive/c/Progra
~1/R/R-2.13.0 ./Rhello.exe
I get a pop up window and it just hangs when I try to run exe file. I assume 
calling R via c program on cygwin/windowsvista is known to be working.
if so, can some one comment on how to run above exe file.
thanks-kris

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Re: [R] ggplot2 month and year boxplot x axis order problem

2011-06-25 Thread philipharrison
Hi,

Thanks, although I dont think it was the Date.Time variable that was the
problem because my x variable was Month.Year. 

I realise now that this month variable was a factor and I changed the order
of the factor using the following :

fish$MonthYr-factor(fish$MOYR,levels=c(05,2010,06,2010,07,2010,08,2010,09,2010,10,2010,11,2010,12,2010,01,2011,02,2011,03,2011,04,2011))

This seems to have ordered my x axis (factors)in the correct fashion.

Thanks again for your help

Phil

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Re: [R] Moving average in a data table

2011-06-25 Thread Gabor Grothendieck
On Sat, Jun 25, 2011 at 3:15 PM, Roman Naumenko ro...@naumenko.ca wrote:
 Hi,

 I'm trying to figure out common approach on calculating MA on a dataset that
 contains column time.

 After digging around, I believe functions rollmean and rollaply should be
 used.
 However I don't quite understand the requirements for the underlying data.
 Should it be zoo object type? Formatted in a special way?

 As an example, I'm looking to get calculated avg=MA(variable) over 15 sec
 period on time_sec column:

  date           variable   time_sec         avg
  2011-05-17     132.55     11:29:59.579     132.55
  2011-05-17     132.65     11:29:59.946     132.60
  2011-05-17     132.5      11:29:59.946     132.57
  2011-05-17     132.5      11:29:59.946     132.55
  2011-05-17     132.55     11:29:59.946     132.55
  2011-05-17     132.6      11:29:59.946     132.56
  2011-05-17     132.55     11:29:59.946     132.56
  2011-05-17     132.65     11:29:59.947     132.57
  2011-05-17     132.85     11:30:00.45      132.60
  2011-05-17     132.9      11:30:00.45      132.63
  2011-05-17     133.05     11:30:00.45      132.67
  2011-05-17     132.2      11:30:00.45      132.63
  2011-05-17     132.5      11:30:00.45      132.62
  2011-05-17     132.7      11:30:00.50      132.63
  2011-05-17     132.75     11:30:00.57      132.63
  2011-05-17     132.55     11:30:00.70      132.63
  2011-05-17     132.25     11:30:00.70      132.61
  2011-05-17     132.25     11:30:00.71      132.59
  2011-05-17     132.35     11:30:00.173     132.57
  2011-05-17     132.45     11:30:00.173     132.57


rollapply and rollmean are for fixed offsets such as 5 rows before and
after.  For this problem modify the following depending on your
precise requirements:

Lines - date   variable   time_sec avg
 2011-05-17 132.55 11:29:59.579 132.55
 2011-05-17 132.65 11:29:59.946 132.60
 2011-05-17 132.5  11:29:59.946 132.57
 2011-05-17 132.5  11:29:59.946 132.55
 2011-05-17 132.55 11:29:59.946 132.55
 2011-05-17 132.6  11:29:59.946 132.56
 2011-05-17 132.55 11:29:59.946 132.56
 2011-05-17 132.65 11:29:59.947 132.57
 2011-05-17 132.85 11:30:00.45  132.60
 2011-05-17 132.9  11:30:00.45  132.63
 2011-05-17 133.05 11:30:00.45  132.67
 2011-05-17 132.2  11:30:00.45  132.63
 2011-05-17 132.5  11:30:00.45  132.62
 2011-05-17 132.7  11:30:00.50  132.63
 2011-05-17 132.75 11:30:00.57  132.63
 2011-05-17 132.55 11:30:00.70  132.63
 2011-05-17 132.25 11:30:00.70  132.61
 2011-05-17 132.25 11:30:00.71  132.59
 2011-05-17 132.35 11:30:00.173 132.57
 2011-05-17 132.45 11:30:00.173 132.57

DF - read.table(textConnection(Lines), header = TRUE)
DF - transform(DF, datetime = as.POSIXct(paste(date, time_sec)))

f - function(i) {
is.near - abs(as.numeric(DF$datetime[i] - DF$datetime))  7.5
mean(DF$variable[is.near])
}
sapply(1:nrow(DF), f)



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Re: [R] What does class call mean? How do I make class formula into a call?

2011-06-25 Thread David Winsemius


On Jun 25, 2011, at 4:33 PM, peter dalgaard wrote:



On Jun 25, 2011, at 15:24 , David Winsemius wrote:



On Jun 24, 2011, at 6:12 PM, StellathePug wrote:


Hello R Users!
I have a list called tabs that I would like to have the same  
structure as
my list eqSystem. The two look like they have the same structure  
but they
are different because when I look at their attributes,  
class(eqSystem[[1]])
is call but class(tabs[[1]]) is formula. I want to have  
class(tabs[[1]])

as a call too.

So what does call mean?


An as yet unevaluated function invocation with first as the named  
function followed by quoted arguments is a call:


See the help(call) page:


f - round
A - 10.5
(g - as.call(list(f, quote(A

.Primitive(round)(A)

eval(g)

[1] 10


call(mean, quote( c(1,2,3)))

mean(c(1, 2, 3))

eval( call(mean, quote( c(1,2,3

[1] 2

It seems very unlikely that a formula object could be coerced into  
a valid call simply by altering its class. To convince us otherwise  
you need to provide more information than you have supplied to the  
present. The results of str() on these objects might be a first step.


Actually, no. Any unevaluated expression in R is mode call, unless  
atomic or symbol. It will also be class call, unless expressedly  
overridden by an S3 class assignment. Notice that operators are  
really function calls.

I.e.


mode(quote(x+y))

[1] call

class(quote(x+y))

[1] call

But


class(quote(x))

[1] name

class(quote(3.14159))

[1] numeric

(This is why the R docs keep talking about unevaluated expressions  
instead of call objects: They aren't always that.)


The ~ operator is also a function call. However, evaluating ~  
returns an object which is the actual call assigned class  
formula (plus an environment attribute).



f - y ~ x
class(f)

[1] formula

unclass(f)

y ~ x
attr(,.Environment)
environment: R_GlobalEnv

mode(f)

[1] call

class(unclass(f))

[1] call

I.e., an unevaluated formulae expression (as in quote(y~x)) is class  
call, as is an unclassed formula object. So it is pretty easy to  
have objects of class formula very similar to objects of class  
call.


Not the first time I have stumbled on such matters. Chamber's SfDA  
would be one obvious place to study. Do yu have any others that pop to  
mind?   The last example suggests that mode and class can each be  
call so that 'call' is somehow more primitive than function or  
formula.


And by way of directly addressing the OP's questions, it sounds as  
though applying unclass() to the formula objects might be attempted?






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Re: [R] calling R from C

2011-06-25 Thread David Winsemius


On Jun 25, 2011, at 11:18 AM, Desi Ap wrote:

I read R extensions on calling R within c code. I am on windows  
vista, cygwin and R-2.13.0.I can compile  link the c code with  
following commands$gcc -I/cygdrive/c/Progra~1/R/R-2.13.0/include -c - 
ggdb Rhello.c

gcc-L/cygdrive/c/Progra~1/R/R-2.13.0/bin/i386 -oRhello Rhello.o -lR
However I cant run the resulting .exe file with following command
LD_LIBRARY_PATH=/cygdrive/c/Progra~1/R/R-2.13.0/bin R_HOME=/cygdrive/ 
c/Progra

~1/R/R-2.13.0 ./Rhello.exe
I get a pop up window and it just hangs when I try to run exe file.  
I assume calling R via c program on cygwin/windowsvista is known to  
be working.

if so, can some one comment on how to run above exe file.


It would be courteous posting behavior to put people on notice that  
this is an identical question to one posed earlier at SO:

http://stackoverflow.com/questions/6478761/problem-running-c-code-that-has-r-in-it

--
David Winsemius, MD
West Hartford, CT

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Re: [R] calling R from C

2011-06-25 Thread Barry Rowlingson
On Sat, Jun 25, 2011 at 4:18 PM, Desi Ap des...@yahoo.com wrote:
 I read R extensions on calling R within c code. I am on windows vista, cygwin 
 and R-2.13.0.I can compile  link the c code with following commands$gcc 
 -I/cygdrive/c/Progra~1/R/R-2.13.0/include -c -ggdb Rhello.c
 gcc-L/cygdrive/c/Progra~1/R/R-2.13.0/bin/i386 -oRhello Rhello.o -lR
 However I cant run the resulting .exe file with following command
 LD_LIBRARY_PATH=/cygdrive/c/Progra~1/R/R-2.13.0/bin R_HOME=/cygdrive/c/Progra
 ~1/R/R-2.13.0 ./Rhello.exe
 I get a pop up window and it just hangs when I try to run exe file. I assume 
 calling R via c program on cygwin/windowsvista is known to be working.
 if so, can some one comment on how to run above exe file.
 thanks-kris

 You need to read the documentation to discover that maybe you should
be using the right tools. Namely MinGW and not Cygwin. Unless you've
managed to compile the whole of R using cygwin of course...

 I hope having identical responses to mailing list messages and SO
questions isn't as annoying as seeing identical questions posted to
each is to everyone on the list...

 Barry

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Re: [R] reading data from password protected url

2011-06-25 Thread Duncan Temple Lang

Hi Steve

 RCurl can help you when you need to have more control over Web requests.
The details vary from Web site to Web site and the different ways to specify
passwords, etc.

If the JSESSIONID and NCES_JSESSIONID are regular cookies and returned in the 
first
request as cookies, then you can just have RCurl handle the cookies
But the basics for your case are

  library(RCurl)
  h = getCurlHandle( cookiefile = )

Then make your Web request using getURLContent(), getForm() or postForm()
but making certain to pass the curl handle  stored in h in each call, e.g.

  ans = getForm(yourURL, login = bob, password = jane, curl = h)

  txt = getURLContent(dataURL, curl = h)


If JSESSIONID and NCES_JSESSIONID are not returned as cookies but HTTP header 
fields, then you
need to process the header.
Something like

  rdr = dynCurlReader(h)

  ans = getForm(yourURL, login = bob, password = jane, curl = h, header = 
rdr$update)

Then the header  from the HTTP response is available as
  rdr$header()

and you can use parseHTTPHeader(rdr$header()) to convert it into a named vector.


 HTH,
D.

On 6/24/11 2:12 PM, Steven R Corsi wrote:
 I am trying to retrieve data from a password protected database. I have login 
 information and the proper url. When I
 make a request to the url, I get back some info, but need to read the hidden 
 header information that has JSESSIONID
 and NCES_JSESSIONID. They need to be used to set cookies before sending off 
 the actual url request that will result in
 the data transfer. Any help would be much appreciated.
 Thanks
 Steve
 
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Re: [R] calling R from C

2011-06-25 Thread Desi Ap
hey David:Newbie here. will avoid duplicates next time. thanks...
-krishna

--- On Sat, 6/25/11, David Winsemius dwinsem...@comcast.net wrote:

From: David Winsemius dwinsem...@comcast.net
Subject: Re: [R] calling R from C
To: Desi Ap des...@yahoo.com
Cc: r-help@r-project.org
Date: Saturday, June 25, 2011, 10:38 PM


On Jun 25, 2011, at 11:18 AM, Desi Ap wrote:

 I read R extensions on calling R within c code. I am on windows vista, cygwin 
 and R-2.13.0.I can compile  link the c code with following commands$gcc 
 -I/cygdrive/c/Progra~1/R/R-2.13.0/include -c -ggdb Rhello.c
 gcc-L/cygdrive/c/Progra~1/R/R-2.13.0/bin/i386 -oRhello Rhello.o -lR
 However I cant run the resulting .exe file with following command
 LD_LIBRARY_PATH=/cygdrive/c/Progra~1/R/R-2.13.0/bin R_HOME=/cygdrive/c/Progra
 ~1/R/R-2.13.0 ./Rhello.exe
 I get a pop up window and it just hangs when I try to run exe file. I assume 
 calling R via c program on cygwin/windowsvista is known to be working.
 if so, can some one comment on how to run above exe file.

It would be courteous posting behavior to put people on notice that this is an 
identical question to one posed earlier at SO:
http://stackoverflow.com/questions/6478761/problem-running-c-code-that-has-r-in-it

--David Winsemius, MD
West Hartford, CT


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