Hi JCFaria,
You package is supposed to be used only under Windows, right? Then, use:
OS_type=windows
in the DESCRIPTION file… and, of course, use R CMD check/R CMD build/ R CMD
INSTALL under Windows only.
Best,
Philippe
On 23 Sep 2013, at 20:55, Jose Claudio Faria joseclaudio.fa...@gmail.com
On 23/09/2013 22:43, MacQueen, Don wrote:
The very first response, from Jeff Newmiller, included a link
http://efele.net/maps/tz/world/
which says it has offers a shapefile of timezones of the world.
An outline of a solution, then it to
download the shapefile
load it into R
input
On 24/09/2013 03:51, Jose Claudio Faria wrote:
I think I found the main problem!
I am developing the package under Linux and after R CMD build,
manually compressing the folder TinnRcom inside of the folder
TinnRcom.RCheck and installing in Windows.
And how on earth did you expect the helpers
Hi David,
Thank you for your interest and advice regarding this analysis.
I went to double check that the subset process worked properly with the
select=c(-time,-status) and I can confirm that it did.
Best,
Erel
-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net]
respectd sir,
i am working on regional frequency analysis of flood flow data and want to use
packages lmomRFA, lmom, imomco,etc andby using these i want to find RMSE ,
errorbounds and absolute biase but could not make it clear to use, please help
regards
atta muhammad asif
assistant professor
I sent this message :
Hello everyone,
R beginner, I am confronted with the need to use
Rmpf.
In my first scripts I made use of
X=read.table(file.choose(), header=FALSE,
sep=,,dec=.)
conne2 - file(C:\\ome1440s.bin,rb)
bioms- readBin(conne2, integer(), size=1, n=1440*720, signed=F)
library(raster)
library(rasterVis)
data(wrld_simpl)
library(maptools) ## needed for wrld_simpl
r - raster(nrow=720, ncol=1440)
r[] - bioms;
Hello,
One way is:
levelplot(r, col.regions=myPal) +
layer(sp.polygons(wrld_simpl, lwd=0.5)) +
layer(panel.rect(2,45,8,51))
Regards,
Pascal
2013/9/24 Jonsson amen.alya...@bordeaux.inra.fr
conne2 - file(C:\\ome1440s.bin,rb)
bioms- readBin(conne2, integer(), size=1, n=1440*720,
At 02:26 23/09/2013, peake wrote:
Thanks for the advice. Like I said, I am still pretty new to R, and stats
in general. I tried wading through the search results on google, but I
didn't really find anything that I could understand. I am working with
percentages as my dependent variable, and I am
Hi Anna
I have never used doubleYScale and I am not sure what you want but try this
You need to do this first if columns not correct saves doing later - I
forgot to mention it for Week but as you have given the order for the
factors do it as well
SummPdata[,1] - as.numeric(SummPdata[,1])
Dear R-useRs,
I'm looking for an R-function for censored linear regression. I have the
following data
x1 - rnorm(100)
x2 - rnorm(100)
y - x1 + 2*x2 + rnorm(100,0,0.5)
stat - rep(1,100)
stat[50:100] - 0
data - data.frame(y,x1,x2,stat)
y is the dependent variable, x1 and x2 are the independent
M == Michel michelgo...@free.fr
on Fri, 20 Sep 2013 17:56:58 +0200 writes:
Hello everyone, R beginner, I am confronted with the need
to use Rmpf.
why ?
In my first scripts I made use of
X=read.table(file.choose(), header=FALSE, sep=,,dec=.)
X=as.matrix(X)
well,
Hi,
I prefer to build my packages on Linux!
I changed the object trPaths as below,
After R CMD build TinnRcom on Linux and did the installation
on Windows from the source code: It worked very well!
I thank all who contributed to the solution and apologize for my lack
of knowledge in this area.
I do the folloowing in order to get 3D Plot:
y-1:(point/2)
x-20:30
z-r[1:(point/2)]
persp(x,y,z,theta = 135, phi = 30, col = green3, scale = FALSE,
ltheta = -120, shade = 0.75,
border = 1)
y:
[1] 1 2 3 4 5
x:
[1] 20 21 22 23 24 25
z:
[1] 4811.003.5930256.968666
That worked fine, thanks. But only worked when the values are positive but
when I added negative values, the box was wrong. May be the order I lat and
long should be different?any ideas
--
View this message in context:
Thanks.That worked fine.Is there a way to print a number like 1 inside the
box plotted?
--
View this message in context:
http://r.789695.n4.nabble.com/how-to-add-a-box-to-map-plotted-by-a-levelplot-tp4676815p4676825.html
Sent from the R help mailing list archive at Nabble.com.
Hi,
I have a problem with running a script in parallel with the foreach function
for computing linear models at every voxel of a set of 3D images. When I run
it using %do%, it runs fine and I get the correct output but when I run it
with %dopar% then my main output is not correct. The problem
On 13-09-24 6:19 AM, Babak Bastan wrote:
I do the folloowing in order to get 3D Plot:
y-1:(point/2)
x-20:30
z-r[1:(point/2)]
persp(x,y,z,theta = 135, phi = 30, col = green3, scale = FALSE,
ltheta = -120, shade = 0.75,
border = 1)
y:
[1] 1 2 3 4 5
x:
[1] 20 21 22 23 24 25
z:
[1]
On 24.09.2013 10:07, Michel wrote:
I sent this message :
Hello everyone,
R beginner, I am confronted with the need to use
Rmpf.
It helps to provide a sensible subject line and not to misspell package
names:Rmpfr.
In
On 23.09.2013 13:48, Rhymes wrote:
I have a problem with comparing dates. i tried it like datesub =
subset(data, 2012-11-19 data$date), but this doesn't work and i don't
know why.
Errr, in R:
2012-11-19 == 1982
You probably want to convert it to a Date object or Posix.. object, but
since
We would like to announce the following statistics course:
Beginner's Guide to MCMC, GAM and GAMM
When: 10-14 March 2014
Where: Elche, Alicante, Spain
For details, see: http://www.highstat.com/statscourse.htm
Course flyer: http://www.highstat.com/Courses/Flyer2014_3ElcheV2.pdf
Kind regards,
Hi,
Sometimes I get a graph like the attached one. The data type could
have something to do with it. This graph does not use the color and does
not draw
a line. Earlier I used to convert the factors in the data frame to another
data type and drew the correct graphs.
Any idea why this
Try:
plot(as.numeric(data$Var1),data$Freq,ylim=c(0,700),col=green,type=o,ylab=,xlab=,las=2,lwd=2.5,xaxt=n)
A.K.
- Original Message -
From: mohan.radhakrish...@polarisft.com mohan.radhakrish...@polarisft.com
To: r-help@r-project.org
Cc:
Sent: Tuesday, September 24, 2013 8:46 AM
Hi Anna
Have a look a ylab in my script - you will need to modify the label I was
going from memory on the exact label argument name . I think it is text =
Np or whatever you want.
The strip arguments are controlled by useOuterStrip see ?useOuterStrip
So you will need to modify as a custom
Dear R experts,
I have 3 matrices - Mx, My and geno that have the same exact dimensions
(attached). I want to calculate a expression matrix (ME) of the same dimension
as well. It is a little complicated.
To calculate and for a specific cell in ME, e.g. ME[2,2],
if value of
Dear useRs,
although we have just (around a month ago) founded the Budapest Users of R
Network, I am more than happy to announce that 75 members already joined
and we are very close to take part in the first official meeting.
We will meet at the ELTE University, Budapest, Hungary at 18:00 (CET)
You might be more successful if:
1. Post in plain text, not HTML, as the posting guide asks;
2. Don't post at all. Instead read the included tutorial, An Introduction
to R, or one of the many on the web that you might prefer. Nothing wrong
with being a newbie; but (imo, of course) there **is**
Hi,
Try:
set.seed(49)
qcd- matrix(sample(1:20,124*69,replace=TRUE),ncol=69)
set.seed(345)
listt- matrix(sample(1:80,124*5,replace=TRUE),ncol=5)
lst1-list(c(15,2),c(56,54),c(15,62),c(4,14))
names(lst1)- 2:5
S- do.call(cbind,lapply(names(lst1),function(i)
Hi,
Try:
ME- matrix(NA,dim(geno[1]),dim(geno)[2])
indx0- geno==0 !is.na(geno)
ME[indx0]- Mx[indx0]+My[indx0]
indx1- geno==1 !is.na(geno)
ME[indx1]- apply(cbind(Mx[indx1],My[indx1]),1,max)
ME
A.K.
- Original Message -
From: JiangZhengyu zhyjiang2...@hotmail.com
To:
On 24-09-2013, at 16:51, arun smartpink...@yahoo.com wrote:
Hi,
Try:
ME- matrix(NA,dim(geno[1]),dim(geno)[2])
indx0- geno==0 !is.na(geno)
ME[indx0]- Mx[indx0]+My[indx0]
indx1- geno==1 !is.na(geno)
ME[indx1]- apply(cbind(Mx[indx1],My[indx1]),1,max)
I would do this to avoid the apply
Time to spend some time with the docs!
?egexp
tells you:
. (Only ^ - \ ] are special inside character classes.)
See also inline below.
Cheers,
Bert
On Tue, Sep 24, 2013 at 8:30 AM, Juliet Hannah juliet.han...@gmail.comwrote:
Is it correct that one does not need to escape special
Is it correct that one does not need to escape special characters such as
* (are these
properly called metacharacters) inside []. If so, what is the logic to this?
mytest - he*llo
sub([*],,mytest)
sub(\\*,,mytest)
[] is easier to read for me than \\. Is this what people tend to use?
Thanks.
On Tue, Sep 24, 2013 at 11:40 AM, Bert Gunter gunter.ber...@gene.com wrote:
Time to spend some time with the docs!
?egexp
Just to avoid any confusion: the documentation topic is ?regexp, not ?egexp
tells you:
. (Only ^ - \ ] are special inside character classes.)
See also inline below.
Thank you! This worked beautifully. Can you help me adapt the code to do
the same thing for a plot of means? The application is not a simple as I
hoped...
plotMeans(rich.small$ALL, rich.small$sample, error.bars=se)
On Mon, Sep 23, 2013 at 10:41 PM, Jim Lemon j...@bitwrit.com.au wrote:
On
On Sep 24, 2013, at 12:47 AM, Jeff Newmiller wrote:
I have stopped using the Berkeley mirror, and just automatically use
UCLA due to missing packages. However, I feel no compulsion to
extrapolate and say that there is some sort of corruption going on
at CRAN mirrors because it is only one
Had yesterday something pretty similar on the 73 installing benchmark:
Error in untar2(tarfile, files, list, exdir, restore_times) :
incomplete block on file
The downloaded source packages are in
‘/private/var/folders/n9/zxfxcd01557dc06bf3c1njy0gn/T/RtmpkwQyuQ/downloaded_packages’
Hello,
I have a large data set that includes many soil parameters (i.e. pH, calcium
levels, enzyme activity, etc) Does anyone have any input as to the easiest
way to check a large data set for normality? Is there an R function/package
that can do this all at once?
Thank you in advance,
--
Ah... Thanks, Ista. Missed that typo.
-- Bert
On Tue, Sep 24, 2013 at 8:48 AM, Ista Zahn istaz...@gmail.com wrote:
On Tue, Sep 24, 2013 at 11:40 AM, Bert Gunter gunter.ber...@gene.com
wrote:
Time to spend some time with the docs!
?egexp
Just to avoid any confusion: the documentation
Check the Jarque-Bera Test for univariate testing
(http://hosho.ees.hokudai.ac.jp/~kubo/Rdoc/library/tseries/html/jarque.bera.test.html)
and Mardia's test for multivariate testing
(http://www.inside-r.org/packages/cran/MVN/docs/mardia.test).
On Sep 24, 2013, at 6:44 PM, steric
The rpart and party packages, among others, calculate recursive
partitioning trees
for regression and classification. There are plot methods available for
showing
various features as, well, trees.
But trees can be displayed more compactly as treemaps, eg with the
treemap packge,
giving a
Hi all,
I am a beginner in R attempting to use TwitteR package to query lists of
Twitter followers for several users. I successfully have set nx as an object
assigned with the screenName I want to query but when I use the method
nx$getFollowerIDs(n=NULL) it returns a list of users from my own
Hello,
i attached an example with two plotted vectors, respectively. And you might
see that the y and x axis are not the same scale (e.g. the third and the
last plot).
I would prefer them to be the same scale.
A toy example:
a - c (1,2,3,4,5,6,9,20)
b - c (0.2,0.4,0.6,1,0.5,1,1,0.1)
plot
Use asp=1 in the plot command. E.g.,
par(mar=c(3,1,1,1), fig=c(0,1,.5,1)) ; plot(1:10, 1:10, asp=1)
par(new=TRUE, fig=c(0,.3,0,.5)) ; plot(1:10, 1:10, asp=1)
par(new=TRUE, fig=c(0.3,1,0,.5)) ; plot(1:10, 1:10, asp=1)
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original
On 09/25/2013 03:25 AM, Hermann Norpois wrote:
Hello,
i attached an example with two plotted vectors, respectively. And you might
see that the y and x axis are not the same scale (e.g. the third and the
last plot).
I would prefer them to be the same scale.
A toy example:
a- c
I got bitten badly when a variable I created for the purpose of
recording an old set of names changed when I didn't think I was going
near it.
I'm not sure if this is a desired behaviour, or documented, or warned
about. I read the data.table intro and the FAQ, and also ?setnames.
Ben Bolker
On 09/24/2013 10:46 PM, mohan.radhakrish...@polarisft.com wrote:
Hi,
Sometimes I get a graph like the attached one. The data type could
have something to do with it. This graph does not use the color and does
not draw
a line. Earlier I used to convert the factors in the data frame to
Hello,
?panel.text
?grid.text
Regards,
Pascal
2013/9/24 Jonsson amen.alya...@bordeaux.inra.fr
Thanks.That worked fine.Is there a way to print a number like 1 inside the
box plotted?
--
View this message in context:
On 09/25/2013 01:56 AM, Sagan Friant wrote:
Thank you! This worked beautifully. Can you help me adapt the code to
do the same thing for a plot of means? The application is not a simple
as I hoped...
plotMeans(rich.small$ALL, rich.small$sample, error.bars=se)
...
Hi Sagan,
Let's see,
I'm a beginner, trying to do a canonical correspondance analysis with the vegan
package, but I come up with that : library(vegan) abondance.txt -
read.table(C:/Users/abondance.txt,header=T,sep=\t) abondance -
cca(abondance[,-c(1,2)]~altitude, data=abondance, nhea) Error in
model.frame(data
Hello, all,
Does anyone know any package in r to fit a log linear model with time
varying coefficients in R? I have googled but with no results. Your help
will be appreciated. J
Shan Xiao
Ph.D. student of Biostatistics,
Department of Biostatistics, IUPUI.
[[alternative
Hi
Attempting to use a display list snapshot (as created by recordPlot())
between R sessions has always been strongly discouraged, but as of about
R 3.0.0 it has become impossible (due to internal changes, which was
part of the reason for strongly discouraging this in the first place).
Hello,
It is kindly requested to post in plain text. HTML is prohibited.
Your data are stored in abondance.txt, not in abondance.
Hope this helps,
Pascal
2013/9/25 Pierre Paradis exod...@hotmail.com
I'm a beginner, trying to do a canonical correspondance analysis with the
vegan package,
On Sep 24, 2013, at 11:44 AM, steric wrote:
Hello,
I have a large data set that includes many soil parameters (i.e. pH,
calcium
levels, enzyme activity, etc) Does anyone have any input as to the
easiest
way to check a large data set for normality? Is there an R function/
package
that
Hi,
Yes. It worked. Is 'stringAsFactors=FALSE' the switch to use
when reading data into a frame ? All the values I use are either numbers
or dates or strings. Sometimes while I manipulate the data by filtering,
the values seem to become factors ?
Thanks,
Mohan
From: Jim Lemon
On Sep 24, 2013, at 3:33 PM, shanxiao wrote:
Hello, all,
Does anyone know any package in r to fit a log linear model with time
varying coefficients in R? I have googled but with no results. Your
help
will be appreciated. J
Perhaps glm (in the default stats package) with an offset of
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