Hi to all,
how can I read exel files where the decimal sign is comma instead dot.
I get the data as ascii and when converting 3,5 with as.numeric the
3,5 will be converted to NA
Kind Regards Knut
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Dear all,
I am trying to convert the following data frame into a format more
useful for me:
library(HSAUR2, lib.loc=C:/Program Files/R/R-3.0.2/library)
Loading required package: tools
Attaching package: ‘HSAUR2’
The following object is masked _by_ ‘.GlobalEnv’:
womensrole
Hi
Either change comma to dot in Excel (but sometimes Excel is rather reluctant to
accept such changes).
Or change commaa to dot in R which probably can be easily done by gsub command
Or read data with option dec=,. I do not know XLConnect but in read.table it
is optional parameter and maybe
Testing for bimodality is rather testing for unimodality. Hartigan and Hartigan
(1985) presented the Dip-Test which is implemented in the R package DipTest
with a much better approximation of the test distribution. If the test
statistic is too high unimodality is rejected. To estimate the dip
Am 25.11.2013 11:29, schrieb PIKAL Petr:
Hi
Either change comma to dot in Excel (but sometimes Excel is rather reluctant to
accept such changes).
Or change commaa to dot in R which probably can be easily done by gsub command
Or read data with option dec=,. I do not know XLConnect but in
I do not agree with a separate beginner's list. But I do stand with moving
to stackoverflow, mainly because of the easier google search than current
mailing list. It could make it more accessible.
On Mon, Nov 25, 2013 at 4:07 AM, John Sorkin jsor...@grecc.umaryland.eduwrote:
Mailing list vs.
Hi!
Im running glmer (lme4) models with biodiversity data and Im having trouble
with understanding/finding information on how the offset() option is
implemented.
Explicitly, Im wondering if the offset is only implemented on the dependent
variable (as I think it is), or does it also affect
Hi All,
I was wondering if someone could help me to solve this issue with lmer.
In order to understand the best mixed effects model to fit my data, I
compared the following options according to the procedures specified in many
papers (i.e. Baayen
If you want a vision of an R-beginners list, it is a boot stamping
ITS IN THE DOCUMENTATION into a newbies face - forever.
http://www.brainyquote.com/quotes/quotes/g/georgeorwe159438.html
slight exaggeration perhaps, but most R-beginners would benefit from
reading a bit more documentation and
Dear Friends, I am looking for an R version of the structural break test in
Andrews (2003). The excellent strucchange package does not include this
test (yet?). Is this test available in another package? If not, might
there already be a function written to do this test? Thank you very much.
I do not see how it can be illegal to download and duplicate the
posts, since all the content is licensed under CC BY-SA. I might have
missed something there: http://stackexchange.com/legal If that is
really the case, I think I will have to reconsider if I should use it
any more.
I'm not a
Dear Benedetta,
I think you might want (1+T+Z|subject) as random effects rather than
(1+T|subject) + (1 + Z|subject). The latter has two random intercepts per
subject: a recipe for disaster.
Follow-up posts should only go to the mixed models mailing list which I'm
cc'ing.
Best regards,
ir.
Hi
I doubt if people start to search answers if they often do not search them in
help pages and documentation provided.
I must agree with Duncan that if Stackoverflow was far more better than this
help list most people would seek advice there then here. Is there any evidence
in decreasing
On Mon, 25 Nov 2013, Geoffrey Smith wrote:
Dear Friends, I am looking for an R version of the structural break test
in Andrews (2003). The excellent strucchange package does not include
this test (yet?). Is this test available in another package? If not,
might there already be a function
I am not sure I have grasped what you want but have a look at this using
ggplot2 with Duncan's modified data set (with his factor and striptime commands
executed)
You will probably need to install ggplot2 :
install.packages(ggplot2)
library(ggplot2)
ggplot(dat, aes(gspd_mps, Station )) +
Hello all,
I have a data frame in the form:
s-expand.grid(x=seq(1,100,by=1),y=seq(1,100,by=1))
w-data.frame(x=s$x,y=s$y,z1=rep(c(1,2,3,4),times=length(s$x/4)),z2=seq(1,le
ngth(s$x),by=1))
The w$x and w$y represent the location of points and z1 and z2 attributes
corresponding to these
Something like this?
s - expand.grid(x=seq(1,100,by=1),y=seq(1,100,by=1))
w -
data.frame(x=s$x,y=s$y,z1=rep(c(1,2,3,4),times=length(s$x/4)),
+ z2=seq(1,length(s$x),by=1))
w$EW - cut(w$x, breaks=c(.5, 50.5, 100.5), labels=c(West,
East))
w$NS - cut(w$y, breaks=c(.5, 50.5, 100.5),
On 25/11/2013 8:47 AM, Hadley Wickham wrote:
I do not see how it can be illegal to download and duplicate the
posts, since all the content is licensed under CC BY-SA. I might have
missed something there: http://stackexchange.com/legal If that is
really the case, I think I will have to
On Nov 25, 2013, at 7:56 AM, PIKAL Petr petr.pi...@precheza.cz wrote:
Hi
I doubt if people start to search answers if they often do not search them in
help pages and documentation provided.
I must agree with Duncan that if Stackoverflow was far more better than this
help list most
Here's a similar plot for stackoverflow:
http://data.stackexchange.com/stackoverflow/query/150130/r-questions-and-answers-per-year#graph
and one broken down by month
http://data.stackexchange.com/stackoverflow/query/150129/r-questions-and-answers-per-month#graph
Hadley
On Mon, Nov 25, 2013 at
Joran (on StackOverflow chat, funnily enough) has just pointed us to this:
http://www.win.tue.nl/~bvasiles/papers/cscw14.pdf How Social QA
Sites are Changing Knowledge Sharing
in Open Source Software Communities
which includes a graph of postings to R-help and questions tagged
'[r]' on
Oops, I misunderstood the database schema, and that only includes
_questions_ tagged R, not the corresponding answers.
Hadley
On Mon, Nov 25, 2013 at 9:55 AM, Hadley Wickham h.wick...@gmail.com wrote:
Here's a similar plot for stackoverflow:
On 13-11-25 06:00 AM, r-help-requ...@r-project.org wrote:
Date: Sun, 24 Nov 2013 13:04:43 -0600
From: Yihui Xiex...@yihui.name
To: Bert Guntergunter.ber...@gene.com
Cc:r-help@r-project.org r-help@r-project.org
Subject: Re: [R] Should there be an R-beginners list?
Message-ID:
In R, as.logical() and other functions treat anything 0 as TRUE. Thus:
Rgames foo-sample(0:5,10,rep=TRUE)
Rgames foo
[1] 0 5 1 0 1 5 2 5 4 5
Rgames as.logical(foo)
[1] FALSE TRUE TRUE FALSE TRUE TRUE TRUE TRUE TRUE TRUE
For your case, simply (womensrole$agreewomensrole$disagree)
A couple things:
First, Beginners' lists never work. Beginners invariably can't read (cf.
posting guidelines), so they will post to the main list anyway.
Second, I see some people prefer to receive email-lists of the topics, and
others prefer to work via a webbrowser interface. I'd have to say
I think the OP was looking to expand the data frame so that each row was a
single observation so that the first row becomes 6 rows, 4-TRUE and 2-FALSE.
Something like this
womensrole - HSAUR::womensrole
step1 - reshape(womensrole, varying=c(agree, disagree),
+ v.names=Freq, timevar=Agree,
ditto to everything Jeff Newmiller said, but I'll take it a little further.
I'm guessing that with
df - data.frame(31790,31790)
you thought you were creating something with 31790 rows and 31790 columns.
You weren't. You were creating a data frame with one row and two columns:
I do not think Carl's solution answers your question. Try this:
z - textConnection(
education gender agree disagree sexe
1 0 Male 420
2 1 Male 200
3 2 Male 400
4 3 Male 630
5 4 Male
Natalie,
I'm assuming this is some kind of passive animal sampling? Instream PIT tags
for fish? In that case, you can get what I think you want using ggplot2 and
something like this:
dat$TagID - as.factor(dat$TagID)
dat$Station - as.factor(dat$Station)
dat$Station2 - as.numeric(dat$Station)
Sending again as apparently did not make the list
Duncan
-Original Message-
From: Duncan Mackay [mailto:dulca...@bigpond.com]
Sent: Monday, 25 November 2013 10:06
To: 'Natalie Houghton McNair'
Cc: R
Subject: RE: [R] Plotting multiple trends on one graph
Hi Natalie
Here is an option
Dear R users,
I have a large data set which includes data from 300 cities. I want to run
a biviriate regression for each city and record the coefficient and the
adjusted R square.
For example, in the following, I have 10 cities represented by numbers from
1 to 10:
x = cumsum(c(0, runif(999, -1,
Hi,
One way would be:
womensrole - read.table(text=education gender agree disagree sexe
1 0 Male 4 2 0
2 1 Male 2 0 0
3 2 Male 4 0 0
4 3 Male 6 3 0
5 4 Male 5 5 0
6 5 Male 13
Hi!
I am trying to retrieve data from a MySQL Database using RODBC with the
commands odbcConnect and sqlFetch. There are different data files in the
database and in some cases it works without any difficulties. Nevertheless I
get an error with some data files. Since I'm not familiar with MySQL I
Dear Thierry,
thank you for the quick reply.
I have only one question about the approach you proposed.
As you suggested, imagine that the model we end up after the model selection
procedure is:
mod2.1 - lmer(dT_purs ~ T + Z + (1 +T+Z| subject), data =x, REML= FALSE)
According to the common
Hi everyone,
I am attempting to bin a vector of numbers between 0 and 1 into intervals
of 0.001 but many values at the endpoints of the intervals are getting
binned into the wrong interval. For example, the first 3 rows are binned
incorrectly here:
library(Hmisc)
Hi,
Try:
dat1- t(dat[,-1])
colnames(dat1) - dat[,1]
covmat - cov(dat1)
A.K.
I'm running into this error and I'm not sure how fix it
Error: is.numeric(x) || is.logical(x) is not TRUE
This is my data frame
geneExpression_Lab10.txt
This is the homework instructions in case you want to see
Hi,
How could I use R to check Durbin Watson Test Bound?
Best,
Rebecca
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide
Bert or anyone else familiar with RColorBrewer:
Has anyone tried to accomplish with RColorBrewer what I asked about in my
original post (below)?
Here is an example cribbed from the levelplot() help examples
x - seq(pi/4, 5 * pi, length.out = 100)
y - seq(pi/4, 5 * pi, length.out = 100)
r -
Never mind. Solved. “cuts” argument back in levelplot(). Duh.
On Nov 25, 2013, at 4:27 PM, Don McKenzie d...@u.washington.edu wrote:
Bert or anyone else familiar with RColorBrewer:
Has anyone tried to accomplish with RColorBrewer what I asked about in my
original post (below)?
Here
FAQ 7.31
Sent from my iPad
On Nov 25, 2013, at 9:01, Maximilian Butler maximilian.but...@gmail.com wrote:
Hi everyone,
I am attempting to bin a vector of numbers between 0 and 1 into intervals
of 0.001 but many values at the endpoints of the intervals are getting
binned into the wrong
On Nov 25, 2013, at 3:35 PM, Gary Dong wrote:
Dear R users,
I have a large data set which includes data from 300 cities. I want to run
a biviriate regression for each city and record the coefficient and the
adjusted R square.
For example, in the following, I have 10 cities represented
I would first enter
?RSiteSearch
at the R console, and learn how to sift through the 5000+ packages at CRAN for
myself.
Then I would enter
RSiteSearch(Durbin)
and then study the many options available.
---
Jeff
In case anyone cares (?), here is a function to do what I was asking, which
doesn’t use colorBrewer but could with some hacking. I’m sure it’s fragile, but
it works with well behaved integers and zero in the middle, which was all I
needed. The output is a palette that can be passed to
Hi,
Try:
res - do.call(rbind,lapply(split(data,data$city),function(z) {fit_city -
lm(y~x,data=z);data.frame(City=unique(z$city),Coefficient=coef(fit_city)[2],Adjusted_R_square=
summary(fit_city)$adj.r.squared)}))
A.K.
On Monday, November 25, 2013 6:37 PM, Gary Dong pdxgary...@gmail.com
Don,
This looks helpful:
https://stat.ethz.ch/pipermail/r-help/2011-March/272361.html
Also, here is some code that I had, and tried to make applicable to your
question:
div.colors -colorRampPalette(c(blue, white, red ))
x-seq(-1,12,1);x
palette(div.colors(length(x)))
y- rep(1,length(x))
Thanks. It is very useful.
Mohan
From: Hadley Wickham h.wick...@gmail.com
To: mohan.radhakrish...@polarisft.com
Cc: R-help r-help@r-project.org
Date: 11/20/2013 06:46 PM
Subject:Re: [R] Functional Programming patterns
I have some notes on functional programming in R at
Hi R-users,
Does anyone know of a package in R that could be used to implement a
multinomial regression model accounting for repeated measures?
Thanks.
[[alternative HTML version deleted]]
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On Mon, 25 Nov 2013, MaXiaoyue wrote:
Hi,
How could I use R to check Durbin Watson Test Bound?
Although the bounds approach to the Durbin-Watson test is still described
in many text books, there are actually various ways to get p-values for
the Durbin-Watson statistic. dwtest() in lmtest
On Mon, 25 Nov 2013, C. Alina Cansler wrote:
Don,
This looks helpful:
https://stat.ethz.ch/pipermail/r-help/2011-March/272361.html
Also, here is some code that I had, and tried to make applicable to your
question:
div.colors -colorRampPalette(c(blue, white, red ))
x-seq(-1,12,1);x
Hello R experts,
I am trying to do a job where I need to take random subsample from a data
and then frequency count of that. Then the median or the frequency from
say, 1000 replicates. Should I try this with subsample in loop or
bootstrap?
My data format is
str(Data)
'data.frame': 155752 obs.
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