annie Zhang annie.zhang2...@gmail.com writes:
## the predicted scores from the model
(pred - predict(data.cpls,n.comp=1:2,newdata=x.new,type=score))
## the predicted scores using x%*%projection
cbind(x.new.centered%*%data.cpls$projection[,1],x.new.centered%*%data.cpls$projection[,2])
Can
On 23.06.2014 19:28, daniel_st...@operamail.com wrote:
I am a bit late for this discussion but hope that I might still get an
answer. I tried to follow your advice and had a look at drawparti but
could not find the relevant section about how to plot specific pairs of
variables
I am trying to
Hi Daniel,
Great! Many thanks!
Dan
On Mon, Jun 23, 2014 at 8:23 PM, Daniel Nordlund
djnordl...@frontier.com wrote:
Something like this could work
x - 0.250
new_sample - function(xx) {
j-c(0.000,0.125,0.250,0.375,0.500,0.625,0.750,0.875,1.000)
Dear R-users,
I have a matrix with a series of not-overlapping in a row dimension vectors
in a given structure. Something like:
|a1, 0, 0, 0|
| 0, a2, a3, 0|
|a4, 0, 0, a5|
where ai are column-vectors of the equal length, m.
My aim is to construct a new matrix formed by diagonal
On 23/06/2014 20:41, Christofer Bogaso wrote:
Hi,
I was reading the help page for as.Date() function for some reason,
and noticed a Matlab link:
http://www.mathworks.com/help/techdoc/matlab_prog/bspgcx2-1.html
It looks like this link is dead. So may be it would be better to put a
correct link
This is almost always user error in setting up the problem, but
without a reproducible example, you won't get any real help on this list.
JN
On 14-06-24 06:00 AM, r-help-requ...@r-project.org wrote:
Message: 11
Date: Mon, 23 Jun 2014 09:14:23 -0700
From: Ferra Xu ferra...@yahoo.com
To:
Hi all,
When making a bunch of plots using a loop function, how to add title to
reflect different plots.
Specifically, for the code below, I generated 9 plots. I would like to add
a title to each plot.
For example, the titles will be respectively, plot1, plot 2, ⦠plot 9.
Thank you very
Hi,
try something like
main=paste(plot,i)
in the plot command.
HTH,
kd
Feladó: r-help-boun...@r-project.org [r-help-boun...@r-project.org] ;
meghatalmaz#243;: li li [hannah@gmail.com]
Küldve: 2014. június 24. 15:17
To: r-help
Tárgy: [R] Making
What about
title(paste(plot, i))
?
Sarah
On Tue, Jun 24, 2014 at 9:17 AM, li li hannah@gmail.com wrote:
Hi all,
When making a bunch of plots using a loop function, how to add title to
reflect different plots.
Specifically, for the code below, I generated 9 plots. I would like to
Ok, yes, I can match them now. Thank you very much!
On Tue, Jun 24, 2014 at 3:58 AM, Bjørn-Helge Mevik b.h.me...@usit.uio.no
wrote:
annie Zhang annie.zhang2...@gmail.com writes:
## the predicted scores from the model
(pred - predict(data.cpls,n.comp=1:2,newdata=x.new,type=score))
##
Well you can use the main argument of the plot function together with a call to
sprintf(). Like this:
main = sprintf(Plot %s, i)
Best regards
Frede
Sendt fra Samsung mobil
Oprindelig meddelelse
Fra: li li
Dato:24/06/2014 15.19 (GMT+01:00)
Til: r-help
Emne: [R] Making
Hi all -
Long-time user, first-time poster.
I added a .First function to my Rprofile.site file to check for updates, clean
the console, and put some fun quotes on startup. This used to work without
error. I hadn't used R (which I usually play with in RStudio) in a few weeks,
but when I
Hi all,
I am currently using package topicmodels to find the topics of a given
text.
The dataset contains 8523 documents. I would like to see which documents
belong to which topic.
Here is my code:
get the documentTermMatrix#
tdm=DocumentTermMatrix(corpus,control)
Hi all,
I am currently using package topicmodels to find the topics of a given
text.
The dataset contains 8523 documents. I would like to see which documents
belong to which topic.
Here is my code:
get the documentTermMatrix#
tdm=DocumentTermMatrix(corpus,control)
I hope the following script is reproducible enough to highlight my issue,
which is to automatically (in this case by loop, but it does not
necessarily have to be by a loop) add geom_line layers for each column of
mydata to the ggplot variable p1. for some reason doing this only works by
manually
the loop is 1 thru 9 but the manual is just 1, 2, 3, 4? change the loop
from 1:dim(mydata)[2] to 1:4 and it works :)
On Tue, Jun 24, 2014 at 9:43 AM, Zayd Farah zaydfa...@gmail.com wrote:
I hope the following script is reproducible enough to highlight my issue,
which is to automatically (in
Reproducibility == good (except for mixing in invalid code and failing to
set RNG seed)
HTML email == bad
Missing subject == bad
Using matrices with ggplot == pushing a rope
Using for loops to build a ggplot == missing the point
Using wide-form data with ggplot == pushing a rope
Study the
Suggestions:
a) Don't post in HTML format... your code appears corrupt.
b) Don't do this. Read the Note in ?.First
On Tue, 24 Jun 2014, Brian Chalfant wrote:
Hi all -
Long-time user, first-time poster.
I added a .First function to my Rprofile.site file to check for updates, clean
the
This is a rope. Don't push it. Been there, been swatted.
The current structure of R cannot support vectors of POSIXt timestamps
that have different tzones in different elements. You can keep a parallel
vector of tzones separately and manage environment variable TZ as needed
if you really must
Fortunately we have the wayback machine:
https://web.archive.org/web/20120425004417/http://www.mathworks.com/help/techdoc/matlab_prog/bspgcx2-1.html
Best,
Ista
On Tue, Jun 24, 2014 at 8:53 AM, Prof Brian Ripley
rip...@stats.ox.ac.uk wrote:
On 23/06/2014 20:41, Christofer Bogaso wrote:
Hi,
Hi,
I m a new user of R. I need to plot distribution of some computed
centrality metrics of my network.
I used ecdf to compute the cumulative distribution of degrees and then
plotted the resultat. However, i got a different distribution from the one
computed using the degree.distribution function
I am having the same problem
trainImp - rfImpute(train[,!colnames(train)==score],train$score)
yields
Error in randomForest.default(xf, y, ntree = ntree, ..., do.trace = ntree,
:
NA not permitted in predictors
any ideas?
--
View this message in context:
Hi,
I am interested in generating all possible contingency table (2 by 2) with
fixed row margins and column margins. Can anyone help me.
Best regards,
Tahira
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
R users,
Abstracts are now being accepted for the 2015 ASA Conference on Statistical
Practice, February 19-21, New Orleans, Louisiana, USA. Each presentation
will have a 45-minute time slot.
If you are interested, you may submit your abstract on the website,
On Tue, Jun 24, 2014 at 10:41 AM, Tahira Jamil tahja...@gmail.com wrote:
Hi,
I am interested in generating all possible contingency table (2 by 2) with
fixed row margins and column margins. Can anyone help me.
If the reason you want this is to sample them then r2dtable can do
that directly.
On 24 Jun 2014, at 16:41 , Tahira Jamil tahja...@gmail.com wrote:
Hi,
I am interested in generating all possible contingency table (2 by 2) with
fixed row margins and column margins. Can anyone help me.
It's pretty easy, just find one compatible solution and add or subtract
1 -1
-1
(a) Sorry, that was my first post. I'll be sure to plain text from here on.
(b) Hmm. It is not intended that there be interaction with the user during
startup code. Attempting to do so can crash the R process, especially so prior
to R 3.0.2. I had been using this with 3.0.1. with no
Dear R users,
I have a list that I'd like to convert to a vector while preserving the
original names.
For example:
test - list(ABCC2=37280,ABCC5=c(12268,13308));
If I do unlist, it automatically renamed the ABCC5 to ABCC51 and ABCC52
unlist(test)
ABCC2 ABCC51 ABCC52
37280 12268 13308
Dear Sir,
I wish to use the ltm package but it gives the following error
Error in library(ltm) : there is no package called âltmâ
How to resolve this issue in R
Looking forward to your reply.
Thanks Regards
anchal
[[alternative HTML version deleted]]
Since a 2x2 table with fixed row and column margins has only one degree of
freedom, it is pretty easy to enumerate them:
AB
A acM[3]
B bdM[4]
M[1] M[2] N
Create a vector of the margins:
M - c(a+b, c+d, a+c, b+d)
The number of possible tables is min(M[c(1, 3)])+1
Have you installed it, perhaps with
install.packages(ltm)
???
If you have, and it installed correctly, then we'll need the
information on your system requested in the posting guide linked at
the end of this message.
Sarah
On Tue, Jun 24, 2014 at 1:49 PM, Anchal garg.anc...@gmail.com wrote:
How about
x - unlist(test)
(names(x) - rep(names(test), times = sapply(test, length)))
?
See also unlist2 from
http://www.bioconductor.org/packages/release/bioc/html/AnnotationDbi.html
Best,
Ista
On Tue, Jun 24, 2014 at 12:56 PM, C Lin bac...@hotmail.com wrote:
Dear R users,
I have a list
David gave a great solution. I think it is better to start from 0 to min(M)
instead of from min(M[c(1,3)]) to avoid negative values in the table. If
the minimum is in M[1] or M[3], a = 1:min(M). Otherwise, d=1:min(M).
Best,
Gang
2014-06-24 13:18 GMT-05:00 David L Carlson dcarl...@tamu.edu:
Michael is correct. I answered too quickly. This will correct the original
suggestion:
M - c(15, 5, 15, 5) # New example where M[2] and M[4] are smaller
M[1]+M[2] == M[3]+M[4]
[1] TRUE
upper - min(M[c(1,3)])
lower - 0
if (min(M) upper) lower - upper - min(M)
all.2x2s -
On Jun 24, 2014, at 7:52 AM, Jeff Newmiller wrote:
Jeff Newmiller's rhelp/ggplot strategy checklist:
Reproducibility == good (except for mixing in invalid code and failing to set
RNG seed)
HTML email == bad
Missing subject == bad
Using matrices with ggplot == pushing a rope
Using for
You're amazing. Thanks so much! That's exactly what I am looking for.
From: istaz...@gmail.com
Date: Tue, 24 Jun 2014 14:32:27 -0400
Subject: Re: [R] converting a list with named member to a vector maintaining
original names
To: bac...@hotmail.com
R community,
Apologies if this has been answered. The concept I'm looking for is to
save() an object retrieved using get() for an object
that resulted from using assign. Something like
save(get(foo),file=paste(foo,'rData',sep=''))
where assign(foo,obj) creates an object named foo with the
You can use the following command:
tmp - get(foo)
save(tmp,file=paste(foo,'.rData',sep=''))
Best,
Mike
2014-06-24 15:35 GMT-05:00 David Stevens david.stev...@usu.edu:
R community,
Apologies if this has been answered. The concept I'm looking for is to
save() an object retrieved using
I think that you are looking for the `list` argument in `save`.
save( list=foo, file=paste0(foo, '.Rdata') )
In general it is best to avoid using the assign function (and get when
possible). Usually there are better alternatives.
On Tue, Jun 24, 2014 at 2:35 PM, David Stevens
Howdy -
I'm wondering if there is a way to force an R dialog window to the front in a
Windows OS. In particular, I defined a .Last function in my Rprofile.site file
that consists only of the updateR() function so as to check for R updates on
close. However, the dialog window for this pops up
Dear all;
I did biplot in R. How can I interpret them in order that i can create two
or more groups in each biplot. I wanna determine the variables that have
the same origin.
please help me.
many thanks.
--
Best Regards
Javad Bayat
M.Sc. Environment Engineering
Shahid Beheshti (National)
I recommend to use saveRDS()/readRDS() instead. More convenient and
avoids the risk that load() has of overwriting existing variables with
the same name.
/Henrik
On Tue, Jun 24, 2014 at 1:45 PM, Greg Snow 538...@gmail.com wrote:
I think that you are looking for the `list` argument in `save`.
Hi,
Thank you all!
Best regards,
Tahira
On Tue, Jun 24, 2014 at 9:07 PM, David L Carlson dcarl...@tamu.edu wrote:
Michael is correct. I answered too quickly. This will correct the original
suggestion:
M - c(15, 5, 15, 5) # New example where M[2] and M[4] are smaller
M[1]+M[2] ==
Thanks to all for the replies. I tried all three and they work great. I
was misinterpreting the list = parameter in save(...) and I get your
point about overwriting existing objects. I've heard about not using
assign/get before. Can anyone point me to why and what alternatives
there are?
Have you read An Introduction to R (ships with R) or other online R
tutorial (there are many good ones). Looks to me like you haven't
these are pretty basic R basics.
But maybe I misinterpret...
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not
The main reason to avoid assign/get is that there are better ways.
You can use a list or environment more directly without using
assign/get. Also the main reason to use assign/get is to work with
global variables which are frowned on in general programming (and
prone to hard to find bugs).
Ideas:
Read the Posting Guide (http://www.R-project.org/posting-guide.html) for this
mailing list (one of the gems in there warns you to not post using HTML email)
Provide a reproducible example (e.g. per [1]) that includes the library/require
statements that load your packages
Consider
Dear R helpers,
I want to generate data for say 1000 patients (i.e., 1000 unique IDs)
having suffered from various diseases in the past (say diseases
A,B,C,D,E,F). The only condition imposed is that each patient should've
suffered from *atleast* two diseases. So my data frame will have two
To get the vector
setNames(stack(test)[,1],stack(test)[,2])
#ABCC2 ABCC5 ABCC5
#37280 12268 13308
#or
setNames(unlist(test),stack(test)[,2])
#ABCC2 ABCC5 ABCC5
#37280 12268 13308
A.K.
On , arun smartpink...@yahoo.com wrote:
You could do:
stack(test)[,2:1]
# ind values
#1 ABCC2
Dear All,
When I do DocumentTermMatrix analysis, can I assign a document id to the
document (i.e., the row in the attached matrix marked in red)?
Here is my code:
tdm=DocumentTermMatrix(corpus,control)
inspect (tdm2[5:20,9:14])
Terms
Docs 002089 002223 002236 002268 002415 002439
5
Gracias Daniel y Carlos, el problema de mi lista es q la columna que queria
modificar estaba como factor entonces no podia modificarla elemento a
elemento.
La solucion que encontre fue primero asignar como character la columna y
luego si modificarla
l3[[1]][1,5]-as.character(l3[[1]][,5])
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