Hola Justo.
Por el error que te da parece que te falta el paquete lme4 para poder
cargar Rcommander. En Windows no estoy 100% seguro, pero al menos en linux
cada vez que actualizo a una versión mayor de R los paquetes me los guarda
en otra carpeta distinta para la nueva versión, por lo que tengo
Hola Justo.
Puede que tu problema tenga que ver con los mirrors httpS (ves menos en
el CRAN porque hay menos que http o ftp) y la instalación de algunos
paquetes.
Aunque usar https es una opción más que recomendable, en determinadas
circunstancias (que todavía no tengo exactamente claras) parece
Buenos días,
He cambiado la versión de R como siempre a través de:
install.packages("installr")
library(installr)
updateR()
En esta ocasión trabajando bajo windows 10. La versión 3.2.2 me ofrece
menos mirror, pero mi principal problema es que no soy capaz de trabajar
con Rcommander (ahora lo hago
Buenos días,
alguien sabe si hay alguna manera de implementar una máquina de soporte
vectorial (svm) con R-hadoop??
Mi interés es hacer procesamiento big data con svm. Se que en R, existen
los paquetes {RtextTools} y {e1071} que permiten hacer svm. Pero no estoy
segura de que el algoritmo sea
Hello All,
I have written the following loop which will apply/split the same vector of
numbers (pc1.eigv) to each (logical) row of a matrix and run a wilcox.test on
those values that line up with TRUE and those that line up with FALSE. It works
fine. However, I am now interested in using the
Try to look at the link:
http://www.cookbook-r.com/Graphs/Legends_(ggplot2)/
Also consider:
help(theme)
legend.backgroundbackground of legend (element_rect; inherits from rect)
legend.margin extra space added around legend (unit)
legend.key background underneath legend keys
Thanks,
Now its work, but I dont get to change te legend position. Look:
ggplot(data1, aes(x=x1, y=y1))+
geom_point()+
geom_smooth(method="glm", family="gaussian",aes(linetype="equation1"))+
geom_smooth(aes(x=x1, y=y1, linetype="equation2"),data=data2,
method="glm",
Could you use expand.grid and loop over each returned row?
Best,
Ulrik
On Wed, 9 Dec 2015 at 13:55 debra ragland via R-help
wrote:
> Hello All,
>
> I have written the following loop which will apply/split the same vector
> of numbers (pc1.eigv) to each (logical) row of a
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of debra ragland
> via R-help
> some sample data
> p<-matrix(c(rep(c(F,T,F),3), rep(c(T,F,T),3), rep(c(T,T,F),3),
> rep(c(F,F,T),3)))
i) Something wrong with p, here; it's a single column matrix. did you mean
Hi,
I'm trying to make a ggplot() graph with a custom legend, but without
success, it is simple, I have somethink like this in traditional plot:
plot(y~x)
curve(equation1,lty=1)
curve(equation2,lty=2)
legend(x,y,legend=c("equation 1","equation 2"),lty=c(1,2),bty="n").
In my ggplot graph I have
Last "+theme_bw()" to be deleted.
Try this:
ggplot(data1, aes(x=x1, y=y1))+
geom_point()+
geom_smooth(method="glm", family="gaussian",aes(linetype="equation1"))+
geom_smooth(aes(x=x1, y=y1, linetype="equation2"),data=data2, method="glm",
family="gaussian")+
scale_linetype_manual(values
Hi,
Now its work, just invert the theme() and theme_bw() position. The
theme_bw() was overlapping the legend position.
Thanks
Ronaldo
Em 09-12-2015 13:11, Ronaldo Reis J�nior escreveu:
> Thanks,
>
> Now its work, but I dont get to change te legend position. Look:
>
>
> ggplot(data1, aes(x=x1,
Hello Petr, hi all,
Thank you very much for trying to help me Petr! Unfortunately it didn't
bring me further.
I do not want to round on full hours but I want uneven intervals to 6
portions. That is probably the biggest part of my problem.
Does anyone know a solution?
That would be very, very
Sorry for the repost, but I want to clarify that I am trying to apply the
wilcox.test to every pairwise combination of rows i.e. row 1 with row 2, row 1
with row 3, row 1 with row 4 and so on until all row combinations have been
achieved.
I've made some corrections.
On Wednesday, December
You can use the approx() function (in that stats package) to put
5 equally spaced times between your high and low water times.
E.g., in the following 'tmp' will be your interpolated times, in seconds
since 1970, which I clumsily convert to POSIX times (I can never
remember how to deal with time
If I understand correctly, this should do what you want, but there will be
warnings for each test about p-values not being exact because you reuse the
pc1.eigv vector for each row so that each value occurs twice:
First we can simplify the original comparisons by using the formula mode for
Thanks for your help Giorgio! Both options worked.
2015-12-09 11:46 GMT-05:00 Giorgio Garziano :
> Looking at the source code of the package drc, there is something that may
> somehow explain what
> you are experiencing:
>
> file: plot.drc.R, function addAxes(),
Dear all,
I use metafor package to generate a forest plot showing the weight of each
study in the plot.
I use the code:
library(metafor)
data(dat.bcg)
res <- rma(ai=tpos, bi=tneg, ci=cpos, di=cneg, data=dat.bcg, measure="RR",
slab=paste(author, year, sep=", "), method="REML")
The error message suggests that you have more than TRUE and FALSE in your
logical matrix. What does str(p) show you? Could you have missing values?
David C
-Original Message-
From: debra ragland [mailto:ragland.de...@yahoo.com]
Sent: Wednesday, December 9, 2015 11:47 AM
To: David L
Message: 30
Date: Tue, 8 Dec 2015 22:56:00 -0500
From: li li
To: Jim Lemon
Cc: r-help
Subject: Re: [R] change the x axis tickmarks when using plot function
in drc package
Message-ID:
Hello all:
I am creating a time series using seq.POSIXt.
ts.full <- as.character(seq.POSIXt(as.POSIXct(start(d.zoo)),
as.POSIXct(end(d.zoo)), by="hour"))
The period crosses the hour of change from "summer time" to "winter
time". When checking with:
duplicated(ts.full)
I see that there are
Hi all,
In drc package, is there a function which can be used to fit restricted
4PL curves? For example, we restrict two 4PL curves have the same lower and
upper asymptotes?
Thanks for the help in advance!
Hanna
[[alternative HTML version deleted]]
1. Don't know, but, assuming I understand you correctly, probably not.
2 Note (subject to my understanding again) that you can rephrase your
query as fitting a 4 parameter logistic to all the data together with
a grouping factor to indicate the separate curves, allowing two of the
parameters
hi all,
there is a vectorinzing version of "[[<-" for "tclArray" class ?
TIA
cleber
#
> library(tcltk); getS3method("[[<-",'tclArray')
function (x, ..., value)
{
name <- as.character(x)
i <- paste(..., sep = ",")
if (is.null(value))
.External(.C_RTcl_RemoveArrayElem,
Estimados
Un día leí algo en el siguiente hipervínculo, pero nunca lo use.
http://blog.revolutionanalytics.com/2015/06/using-hadoop-with-r-it-depends.html
Javier Rubén Marcuzzi
De: Carlos J. Gil Bellosta
Enviado: miércoles, 9 de diciembre de 2015 14:33
Para: MªLuz Morales
CC: r-help-es
> On Dec 9, 2015, at 10:58 AM, Micha Silver wrote:
>
> Hello all:
> I am creating a time series using seq.POSIXt.
>
> ts.full <- as.character(seq.POSIXt(as.POSIXct(start(d.zoo)),
> as.POSIXct(end(d.zoo)), by="hour"))
>
> The period crosses the hour of change from "summer
Hello
Can you help me to do programe or order
For ( estimated of constant stress partially accelerated life testing model
parameter? )
1/what is the package ?
2/what is the order ?
Thank you
Manal Alharbi
[[alternative HTML version deleted]]
Dear all,
I would like to know if it is possible to estimate an integrated choice and
latent variable model with R. If it is so, please send me the name of the
respective package.
Best regards,
Maria Alice P. Jacques
Associated Researcher
University of Brasilia - Brazil
[[alternative
Hello David and David:
Thanks for responding
On 12/10/2015 01:33 AM, David Winsemius wrote:
On Dec 9, 2015, at 10:58 AM, Micha Silver wrote:
Hello all:
I am creating a time series using seq.POSIXt.
ts.full <- as.character(seq.POSIXt(as.POSIXct(start(d.zoo)),
Dear all,
I have worked on AKDEs using the package ctmm. Because my old computer
often crashed, I bought a new one and reinstalled all the software,
including r.
All seemed to work fine, but when I wanted to plot several results I
encountered error messages.
I tried many different plots, some
Hi
1. Do not post in HTML. Your mail is corrupted and almost unreadable.
2. As far I I could decipher it, your plot call is
plot(cilla,AKDE=KD2)
According to docs the plot function does not have parameter called AKDE
plot(x, CTMM=NULL, UD=NULL, level.UD=0.95, level=0.95, DF="CDF", col="red",
library(tcltk)
methods(class = "tclArray")
## [1] [[ [[<- $$<- length length<- namesnames<-
## see '?methods' for accessing help and source code
It should be something like `[<-`. But this one is not defined. Perhaps can you
contribute one here?
Best,
Philippe
Hi
I did not see any answer so I give it a try. Your approach seems to be OK.
However you probably need to polish your code to get the correct part of nested
list.
> lll<-list(a=rnorm(10), b= list(x=1:10, y<-letters))
> lll[[1]]
[1] -0.1876418 1.5933030 -0.1799642 0.1713959 1.1079227
Looking at the source code of the package drc, there is something that may
somehow explain what
you are experiencing:
file: plot.drc.R, function addAxes(), lines 543-626
ceilingxTicks <- ceiling(log10(xaxisTicks[-1]))
...
xaxisTicks <- c(xaxisTicks[1], 10^(unique(ceilingxTicks)))
xLabels
No, no correrán en paralelo si usas los SVM de paquetes como e1071.
No obstante, tienes, por un lado, los trucos habituales para hacer algo
"parecido" a SVM o "basado" en SVM pero que no sea SVM. Si es que eso te
vale.
Puedes probar a hacerlo con mllib (sobre Spark), como aquí
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