The package appears to be referenced in the package "agridat" -
ftp://cran.r-project.org/pub/R/web/packages/agridat/agridat.pdf (Pg 55).
However, even I tried searching for it and there seems to be no reference other
than this source.
Regards,
radmuzom
From: R-help on behalf of David
On 05/07/18 10:21, Nelly Reduan wrote:
Dear all,
I would like to generate N random numbers with a given probability and
condition but I'm not sure how to do this.
For example, I have N = 20 and the vector from which to choose is seq(0, 10,
1). I have tested:
x <- sample(seq(0, 10, 1), 20,
This looks like homework (which is off topic here per the Posting Guide). Also,
please send your emails in plain text format to avoid us seeing your message
differently than you do.
On July 4, 2018 3:21:34 PM PDT, Nelly Reduan wrote:
>Dear all,
>
>I would like to generate N random numbers with
Dear all,
I would like to generate N random numbers with a given probability and
condition but I'm not sure how to do this.
For example, I have N = 20 and the vector from which to choose is seq(0, 10,
1). I have tested:
x <- sample(seq(0, 10, 1), 20, replace=TRUE, prob=rep(0.28,
Estimado Juan Abasolo
Si en su mente puede organizarlo en matrices, utilice su pensamiento, eso
no es malo, pero si piensa en matrices utilice for, if, algunos índices
para acceder a lugares específicos, pase lo que está en lapply a un ciclo
for, todo en matrices, si salta de una forma de
Thank you, Peter!
Sincerely,
KeithC.
On Wed, Jul 4, 2018 at 4:11 AM, Peter Dalgaard wrote:
>> # Extract SEs via vcov()
>> SEvcov1<-exp(coef(fit1)) *sqrt(diag(vcov(fit1)))
>> SEvcov2<-exp(coef(fit2))*sqrt(diag(vcov(fit2)))
>
> What makes you think that you need to multiply with exp(coef())
Muchas gracias, Javier, por tu respuesta.
Me sobrevalorás. Mi última clase de matemática como tal fue en 4º de
secundaria, y era la matemática que nos daban a los de letras. Ni te cuento
hace cuántos años. No puedo seguir la mayoría de lo que comentás sin hacer
un trabajo forense. Así que agarré
It is not obvious that this is an error. If your nominal variable in SAS has a
level which is not present in data, then R might just be making a faithful
translation. There is a distinction between (a) having a gender variable with
two levels of which 0 females and (b) pretending that male is
Hi,
I have imported some sasdata into R using the sas7bdat package. I have some
nominal variables with some missing values.
R is creating a new level which is emty ��.When I ask for tabulate this new
level is presented with 0 as a frequency.
I want to get rid of this level and have my file
I've been following this thread, and wondering where it might lead.
My (possibly naive) view of these matters is basically logical,
relying on (possibly over-simplified) interpretaions of "NA" and "NaN".
These are that:
"NaN" means "Not a Number", though it can result from a
numerical
> On Jul 3, 2018, at 6:34 PM, Mehrshad Barary wrote:
>
> Hi Everyone,
>
> Does anybody know how I can get ASExtras library?
It would be helpful if you would provide information about your reasons for
assuming this package's existence. Cannot find it in CRAN (including a search
for
Estimado Juan Abasolo
Posiblemente lo que usted desea está en
https://cran.r-project.org/web/packages/Matrix/index.html, pero yo también
en su momento me puse a escribir muchas cosas que ya existían y lo
realizaba para aprender (posiblemente todo el que desee aprender
correctamente debe intentar
Buenas,
Sigo aprobechando par aaprender en las vacaciones de alumnos y nuevamente
recurro a Uds. Sé que la perspectiva puede ser erronea, o sea que les pido
que entiendan lo que quiero decir, más que lo que digo.
Tengo una lista de matrices todas de idénticas dimensiones, y necesito
hacer
I'm having deja-vu of a similar discussion on R-devel:
https://stat.ethz.ch/pipermail/r-devel/2018-July/076377.html
This was the funniest inconsistency I could find:
> sum(c(NaN,NA))
[1] NaN
> sum(NaN,NA)
[1] NA
THEY'RE IN THE SAME ORDER!!!
The doc in ?NaN has this clause:
In R,
> # Extract SEs via vcov()
> SEvcov1<-exp(coef(fit1)) *sqrt(diag(vcov(fit1)))
> SEvcov2<-exp(coef(fit2))*sqrt(diag(vcov(fit2)))
What makes you think that you need to multiply with exp(coef()) here???
-pd
> On 4 Jul 2018, at 11:08 , 1/k^c wrote:
>
> Hi R-helpers,
>
> I was working with
Hi R-helpers,
I was working with some count data using gamlss() and glm(), and
noticed that the standard errors from the two functions correspond
when extracting from either the model summary for both functions, or
using vcov for both functions, but the standard errors between those
methods do
For what it's worth, for larger vectors, and following on from your
observation that the do.call() approach is faster, the following provides
some modest additional speedup:
cbind(x,t(do.call(cbind, lapply(x, function(y) vec
Rgds,
Eric
On Tue, Jul 3, 2018 at 8:12 PM, Viechtbauer, Wolfgang
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