See ?%in%
result$Subject %in% c(JEFF, BG)
John Sorkin wrote:
I would like to select rows if a row contains any one of several values. I can
do the selection as follows:
result[,Subject]==JEFF | result[,Subject]==BG
But this is very unwieldily if one wishes to select many, many rows as one
What I want to do is to be able to select certain FTIStandKey's and change
values in the dataset. For example, I would like to select by
FTIStandKey==NAH6253-003, and change the entries for CoverType=
XSOP--C and change the V_SpGrp==T, and also change V_Origin==T. I
only want to change
This is not a reproducible example. You might simply want:
apply(veh_drg_animal1[, c(readCount, gene_length)], 1, stats, arg2,
arg3)
But your two parameters from the data.frame are really going to be
passed as one vector, and then within the stats function you can access
them individually.
Henrique Dallazuanna wrote:
try this:
apply(veh_drg_animal1[ ,c(readCount,gene_length)] ,1,
function(x)stats(x[1], x[2], total=5500))
I agree with this, that was my point in my original reply. Apply is
*not* passing 2 arguments simply because you are selecting two columns
of the
Abhishek Pratap wrote:
Hi Guys
Thank you for clearing something I dint know. Just wondering the
reason of putting the word function(x) in the apply function when we
have already declared stats function separately.
I better understand how the arguments are passed.
Thanks!
-Abhi
That's
Dimitri Shvorob wrote:
... Both readLines() and scan() produce a number_of_lines x 1 vector; trying
paste(s, collapse = NULL) leaves it unaffected. How can I concatenate vector
elements (lines) into a single string?
Thank you.
Read ?paste, specifically:
If a value is specified for
avprix -
structure(list(DESCRIPTION = c(CORN Jul/10, CORN May/10,
ROBUSTA COFFEE (10) Jul/10, SOYBEANS Jul/10, SPCL HIGH GRADE ZINC USD,
STANDARD LEAD USD), prix = c(-1.5, -1082, 11084, 1983.5, -2464,
-118), quantity = c(0, -3, 8, 2, -1, 0), fees = c(-8.64, -30.24,
-26.4, -25.92, -37.5,
someone wrote:
Hi,
I'm using the bwplot from the agsemisc package which has a scattered
attribute which can be set so that the single dots can bee seen better.
my problem is, that I am having so many dots that they still overlap.
I could increase the output of the diagram but thats not really
gerald.j...@dgag.ca wrote:
Hello,
I am running:
R version 2.10.0 (2009-10-26)
Copyright (C) 2009 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
on a RedHat Linux box with 48Gb of memory.
I am trying to create a model.matrix for a big model on a moderately large
data set. It
Perhaps ?read.table, ?file, and ?iconv will offer some information about
how to use different encodings in R.
Michael Steven Rooney wrote:
Does R have package/function that can read a file that has been downloaded
from a mainframe in EBCDIC format?
Thanks,
Mike
[[alternative HTML
Hans Ekbrand wrote:
I want 100 integers. Each integer, x, can be in the range 1 = x = 10.
Does the following code give 1 and 10 the same chances to be selected as
2:8?
round(runif(100, min = 1, max = 10))
If you just want to sample integers, use ?sample
Ted Byers wrote:
I tend to have a lot of packages installed, in part because of a wide
diversity of interests and a disposition of examining different ways to
accomplish a given task.
I am looking for a better way to upgrade all my packages when I upgrade the
version of R that I am running.
song song wrote:
such a factor as a=as.factor(c(1.23, 4.56, 7.89)) and I want to get this
vector: c(1.23, 4.56, 7.89).
You're told how to do this in the help page for ?factor. See the
Warning section.
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Vivek Ayer wrote:
Hi guys,
I was wondering why this piece of code doesn't work:
foreach (i = c(1.25,1.50)) %dopar% {
assign(paste(test_,i,sep=),i)
}
but, this does:
foreach (i = c(1.25,1.50)) %do% {
assign(paste(test_,i,sep=),i)
}
... and which package are these functions in?
Wincent wrote:
Dear all, I have a list like this: l - list(list(a=1,b=NULL), list(a=2,b=2))
I want to find out the elements with value of NULL and replace them with NA.
The actual case has a very long list, so manually find out and replace
them is not an option.
I can use for loop to do this,
I still have little ability to predict how these functions will treat the
columns of data frames:
All of this is explained by knowing what class of data functions *work
on*, and what class of data *you have*.
# Here's a data frame with a column a of integers,
# and a column b of
See ?apply. The apply function works on *matrices*.
Actually arrays, and matrices are arrays with 2 dimensions.
characters. This is all explained in the first paragraph of ?apply.
Also see ?as.matrix
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jh556 wrote:
I'm applying logistic regression to a moderate sized data set for which I
believe Wald based confidence intervals on B coefficients are too
conservative. Some of the literature recommends using confidence intervals
based on the likelihood ratio in such cases, but I'm having
Hello!
I'm reading through a logistic regression book and using R to replicate
the results. Although my question is not directly related to this, it's
the context I discovered it in, so here we go.
Consider these data:
interco - structure(list(white = c(1, 1, 0, 0), male = c(1, 0, 1, 0),
snip
I'm sure it's not a bug, but could someone point to a thread or offer
some gentle advice on what's happening? I think it's related to:
test - data.frame(name1 = 1:5, name2 = 6:10, test = 11:15)
eval(expression(test[c(name1, name2)]))
eval(expression(interco[c(name1, test)]))
scratch
The stringAsFactors = False option did not work either.
False FALSE
in addition Vincent was getting an error since he used stringAsFactors, instead
of stringsAsFactors as the argument name.
__
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Mohamed Lajnef wrote:
Dear All,
I apologize for this trivial question, I can not find the solution
I try to use t.test function per line in the data.frame, But i
dont'understand the error message
my program is as follows
group1-gl(2,20)
fun-function(x){
m-data.frame(group1,x)
One of many possible approaches is called k-means clustering.
my.data - c(1,2,3,2,3,2,3,4,3,2,3,4,3,2,400,340,3,2,4,5,6,4,3,6,4,5,3)
split(my.data, kmeans(my.data, 2)$cluster)
$`1`
[1] 400 340
$`2`
[1] 1 2 3 2 3 2 3 4 3 2 3 4 3 2 3 2 4 5 6 4 3 6 4 5 3
Ralf B wrote:
Hi R friends,
I am
Hello,
I have a csv file that contains weather observation (rows) by days (in
columns).
I open using:
temp = read.csv(Weather.csv, sep=,)
and read:
X X1.Jan X2.Jan X3.Jan X4.Jan
1 Min 2 3 4 1
2 Max 6 10 8 6
3
phoebe kong wrote:
Hi all,
I have problem in ordering data frame. Could anyone help me?
x
[,1] [,2] [,3]
[1,] A 1 2
[2,] G 3 2
[3,] E 2 3
y
[,1] [,2] [,3]
[1,] G 3 3
[2,] A 3 3
[3,] E 3 3
Are these really data.frames? They looks like matrices. You do not
provide
Hello,
Ralf B wrote:
Are there R packages that allow for dynamic clustering, i.e. where the
number of clusters are not predefined? I have a list of numbers that
falls in either 2 or just 1 cluster. Here an example of one that
should be clustered into two clusters:
two -
Paul wrote:
I was googling around today to see if anyone had created any R
wallpapers, given some of the amazing graphics that can be created with
R I'd like to display the capabilities for others. I didn't come up
with much.
Don't know what you mean by 'wallpaper'. This site has a bunch
karena wrote:
I am wondering if there is any function in R that is similar to the scan
function in SAS.
I have a data.frame which has two columns as the following:
one two
1 2
3 4
5 6
I used the paste function to create the third column: three -
paste(one,'-',two,sep=)
so the
Steve Hempell wrote:
I would like to stop recieving all the emails from R-Help. I cannot get
back to the preference page given when I first registered. How do I stop
the e-mails?
It's in the footer of all emails from the list.
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
Wang, Kevin (SYD) wrote:
Hi,
I've got a bunch of datasets (each has an ID column) that I'd like to
merge into one big datasets.
After a google search I found
http://tolstoy.newcastle.edu.au/R/help/05/08/11131.html . However, I'm
wondering if there is an easy way to do this as I've got about
Perhaps even ?View would be useful here. I've never used R Commander,
so don't know it would be useful in that environment.
Michael H wrote:
R experts,
I am working with large multivariable data frames ( 50 variables)
and I would like to scroll horizontally across my output
to view each
mam3xs wrote:
Hi all,
I have a R code with quite a few lines. For instance
AA - read.csv(C:\\AA.txt)
AA.diff - diff(log(AA))
.
Now I want to re-define the code with different object, like BB,
CC..ZZ(the codes are the same). Thus, I was wondering whether their is
an efficient way
David Winsemius wrote:
On May 12, 2010, at 11:57 AM, xin wei wrote:
I am doing very regular stuff like the following:
attach(wtana)
fm- lm(Body.Wt.on.SD1~Heart.Wt, data=wtana)
#fm- lm(wtana$Body.Wt.on.SD1~wtana$Heart.Wt)
lrf- loess(Body.Wt.on.SD1~Heart.Wt, wtana)
#lrf-
Hi, I am brand new to R and not familiar with the language, though I
have been reading the manuals and making some slow going progress. I am
working with some source code from a Global Vector Auto -Regressive
program written by Ranier Puhr from the R-forge group. I need help
interpreting the
help.search(difference)
would lead you to
?diff, see the lag argument
Clark Johnston wrote:
I was looking for a function which would take the difference along a vector?
a-c(1,12,23,44,15,28,7,8,9,10)
if I set the number difference to 3 would return
43
2
5
-37
-7
-19
3
or do I need to
gvrocha wrote:
Hi,
I am using some python code to execute small R code snippets.
I would like to save the messages output to the screen when R is executed.
However, I will just save the opening message a zillion times since many
thousands of little snippets will be executed.
Clark Johnston wrote:
Is there a way to create a new matrix from and existing matrix with
A
[,1] [,2]
[1,] 113
[2.] 218
[3,] 314
[4,] 420
if(A[,2] 15)
B
[,1] [,2]
[1,] 2 18
[2,] 4 20
It's
Shi, Tao wrote:
Hi list,
Excuse me b/c this is probably a more TeX then R
question.
I've been using latex function in my .Rnw file to
generate tables, but I've always been using it without assigning the
result to a object, i.e.
x - matrix(1:6, nrow=2,
Ista Zahn wrote:
Hi Tao,
I think you just need latex(x, file=)
I think I misunderstood the question, I believe that is what is needed
here.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the
While not a direct answer to your question, do
?getwd and ?setwd help at all?
Johannes W. Dietrich wrote:
There is certainly a trivial solution for my question, but I can't find
the answer in the documentation.
I need a platform independent method to obtain the file path of the
current R
Shi, Tao wrote:
Hi Richard,
Obviously, the list doesn't like my attachment. Here it is:
http://i41.tinypic.com/15qz387.jpg
I set the path using Windows control panel. And didn't work means
I'm still getting the same error window shown above.
Well, it's hard to say what's going on
The key is that [ is a function.
So, you have a list, you want to apply a function to a list, and return
a vector, think sapply.
sapply(strsplit(as.character(Elecciones$Municipios),\\.), [, 1)
Luis Felipe Parra wrote:
Hello, i have the following list
(Ted Harding) wrote:
Greetings All,
Out of curiosity, I've just done a very primitive experiment:
Obj - list(Fun=sum, Dat=c(1,2,3,4))
Obj$Fun(Obj$Dat)
# [1] 10
That sort of thing (much more sophisticated) must be documented
mind-blowingly somewhere. Where?
Where I stand right now:
Felipe Carrillo wrote:
HI:
If you don't mind me asking this question about latex:
Based on Duncan's comment:
The print method for latex objects tries to run latex and then display the
resulting .dvi file. (Or maybe it runs pdflatex and displays the .pdf file).
Where in MikTex can I change to
Looks good. I came up with something on my own which was basically to
re-write print.latex. I call pdflatex a few times because with the
longtable package, sometimes things don't line up right until you run
pdflatex multiple times. I think mine is less flexible though, and I
like your
Hello,
Tino Schöllhorn wrote:
Hi,
I am quite new to R - but quite expierience in programming.
Welcome to R! It's easiest if you give reproducible examples so we can
help you. You can include code to create objects, or use the ?dput
function.
Nonetheles
I have some problemes in
snip
Notice that I didn't quite get my function into the Hmisc environment
and that is why you need the awkward phrase
show.dvi(dvi(x.tex - latex(x)))
instead of the smooth phrase
latex(x)
Somehow with my own data and not using the awkward bit, it worked on my
Linux machine? At
Joey Zhou wrote:
Dear All:
I downloaded gee source code and now I am having problem accessing the
file.
download.packages(gee, type=source, destdir=~)
--- Please select a CRAN mirror for use in this session ---
trying URL '
Nish wrote:
Hello,
I would like to know how to display values for points in a plot funtion. For
example,
plot( y=dat$a,
x=dat$b,
main=plot1,
ylab=a,
xlab=b,
ylim=c(-10, 10),
xlim=c(-10, 10),
type = p,
pch=17,
col=vector of colors
There would be several people who could help if you gave us a minimal,
reproducible example like the posting guide asks for.
If you have a vector of continuous data, and need to create a
categorical variable (in R, a factor) from that continuous variable,
then ?cut can help you.
We need a self-contained, reproducible example of what you have, and
what you want.
Is this close?
tmp - data.frame(a = rnorm(278))
tmp$newcol -
tmp[seq(97,278, by = 12), newcol] - A Name
ecvet...@uwaterloo.ca wrote:
Hello,
I have a data frame with many rows, and I want to create a column
Hello,
Adam Sean wrote:
I have an excel file in following shape:
date Category
01/21/2010turf
01/21/2010jack
01/21/2010jack
01/22/2010 turf
01/22/2010 jack
01/22/2010 psi
01/22/2010 psi
01/22/2010 psi
01/23/2010 turf
01/23/2010 turf
01/23/2010 jack
Thomas Levine wrote:
There are loads of resources for users of any other
statistics package who are learning R. For example
http://www.google.com/search?q=r+for+sas-users;
The reverse isn't the case
http://www.google.com/search?q=sas+for+r-users;
snip
I can't wait that long. Until then
Hello,
Good reproducible example.
Is
merge(a[names(a) != weekAvg], b)
what you want?
emorway wrote:
Forum,
with the datasets a and b below, I'm trying to establish a relationship
based on the common column week and insert the value from the column
weekAvg in b to the column weekAvg in a.
You have a list that you want to treat as a vector, so ?unlist it.
Jonathan wrote:
Hi all,
I'm hoping this question has a simple answer, but I can't find it through
searching or trying commands.
I have a list of numeric vectors called 'husk'. I'd just like to treat the
set of all numbers
rajesh j wrote:
Hi,
I wish to plot multiple histograms(representing different data so different
range along xaxis but y axis is the same) horizontally in ggplot2. I'd like
it to look like facets. Is this possible?
Can you give a small example, say, using the diamonds dataset, or one of
Robert U wrote:
Dear R-users,
I'm trying to make the following loop: for (x in 0 : 10) and i would
like x to be decimals rather than integers, giving a x range of e.g.
0.0 0.1 0.2 0.3 ... 9.9, 10. Would anyone know how to do that ?
Please start new threads when you have a new question, do
rajesh j wrote:
Hi,
I wish to plot multiple histograms(representing different data so
different
range along xaxis but y axis is the same) horizontally in ggplot2. I'd
like
it to look like facets. Is this possible?
Can you give a small example, say, using the diamonds dataset, or one of
Hello,
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
We don't know the function you're using or the data you applied the function to,
which makes it almost impossible to help. Can you use ?dput
Alex Ruiz E. wrote:
Dear R helpers,
I created a somewhat big database (+206,700 rows) in MySQL and have
exported into a csv file, but I can't open the whole thing in R. I am
using:
base-read.csv(/path/to/file.csv, header=F, sep=, nrows=206720)
R doesn't complain but it only opens 128,328
Carrie Li wrote:
Dear R-helpers,
I would like to generate a variable that takes 0 or 1, and each subject has
different probabilities of taking the draw.
So, which of the following code I should use ?
snip
I don't think either.
Try this:
probs - seq(0,1, by = .1)
sapply(probs, function(x)
Kang Min wrote:
Hi,
I have a list of 100, each list has 20 elements, and I would like to
select the first 7 elements in each list.
Let's take the alphabet as an example.
x - lapply(1:100, function(i) sample(LETTERS))
I tried x[[1:7]], but it doesn't work. Can anyone enlighten me on how
to do
[ is a function, and you want to use it on each element of the list,
so...
lapply(x, [, c(1:7))
and the call to c() is of course not necessary, since : will generate a
vector.
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Caitlin Sadowski wrote:
I have a large csv table I am trying to read into R. I would like each
column to be of type factor. However, most columns have only numeral
entries (e.g. likert scales), so are automatically imported as type
numeric. Is there a way to convert ALL columns to be of type
Hello,
sedm1000 wrote:
Sorry - I figured that this to be a more common defined error than anything
specific to the data/function... Thanks for looking at this.
The data and function are below. Creating a single line of the data.frame at
a time will work (i.e. fold(s))
For multiple line
thmsfuller...@gmail.com wrote:
Hello All,
sample() only sample on one variable x. But I'm interested in sampling
more than one variable without replacement.
Suppose I have 3 vectors x, y, z. I want to draw samples from all
three vectors such that the combination of the three elements in each
Hello,
Can anyone think of a non-iterative way to generate a decreasing geometric
sequence in R?
For example, for a hypothetical function dg, I would like:
dg(20)
[1] 20 10 5 2 1
where I am using integer division by 2 to get each subsequent value in the
sequence.
There is of course:
Nick Matzke wrote:
Hi all,
If I would like to make a list of complex objects -- in my case,
phylogenetic trees, but it could be e.g. statistical results from
something like lm, or whatever -- how can I put them into a list?
When I try the obvious methods, e.g. cat, append, list, etc., I
Robin Jeffries wrote:
Hallo!
I have a vector of ID's like so,
id - c(1,2,2,3,3,3,4,5,5)
I would like to create a [start,stop] pair of vectors that index the first
and last observation per ID.
For the ID list above, it would look like
1 1
2 3
4 6
7 7
8 9
which(!duplicated(id))
[1] 1 2 4 7 8
Hello,
I wrote a Wordpress blog entry about not only highlighting R syntax, but
embedding R commands within an entry and using Sweave to produce the R output,
all within Emacs. The output of the process is ready to paste Wordpress HTML,
and a few other R blogs have started using it to
Ben,
In general, when you define a, b, and c as below, the c() wrapper is not
needed, since the : operator returns a vector anyway. Also, best not to name
variables 'c' to avoid confusion with the function you're using.
Regarding your actual question, lapply(list(a, b, c), class-, dist)
While what you say is true for base R, someone already mentioned Hmisc's latex
function, and I have written several custom functions to output tables in
LaTeX, the benefit being the elimination of manual formatting and intervention
when preparing tables. Add this in with Sweave and make files,
One option, first, generate the range of x data that you want, then add
normally distributed noise to each x, these will be your y data.
n - 20
x - sample(20:50, n)
y - rnorm(n, mean = x, sd = 3)
plot(y ~ x)
Erik
-Original Message-
From: r-help-boun...@r-project.org
See the example in ?source, which does exactly this... or make a package
depending on your needs.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of ram basnet
Sent: Wednesday, November 25, 2009 8:35 AM
To: R help
Subject: [R]
Simply a manifestation of FAQ 7.31, i.e., a floating-point arithmetic issue.
On my machine,
1.16 * 100 == 116
[1] FALSE
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Rupert Mazzucco
Sent: Monday, November 30, 2009 1:15
intersect(c(1,3,2),c('1','3'))
[1] 1 3
Apparently, intersect() treats num as string. But this is not
documented in the help. Could somebody add it in the future version of
R?
This is more a general coercion feature. For example 1 == 1, see ?Comparison.
Also according to the help, the
It is documented that intersect will return a value of that is same
mode as its y argument. How could it be any more clear?
Oops, this makes my previous response to this question inaccurate, apologies.
__
R-help@r-project.org mailing list
The file is probably called .Rdata and is probably somewhere under your
home directory on Windows, perhaps under C:\documents and settings\username
or even C:\documents and settings\username\My Documents ? Hope that helps. I
don't have R installed on Windows or I would narrow it down for
One problem I've been having is the special case in which only one
row/column remains and the variable gets converted into a vector when
entries are removed by logical masking. This is a problem because
subsequent
code may rely on matrix operations (apply, colsums, dim, etc) For example:
You can use the ifelse function for vectorized conditionals like you have
here. See ?ifelse.
From: r-help-boun...@r-project.org [r-help-boun...@r-project.org] On Behalf Of
Arthur Burke [art.bu...@educationnorthwest.org]
Sent: Tuesday, December 08, 2009
?rowSums
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Tom Pitt
Sent: Tuesday, December 15, 2009 2:57 PM
To: r-help@r-project.org
Subject: [R] Counting in Matrix
Hi All,
Is there an easy way to count TRUEs for each
speretti wrote:
Hi,
I need help to find an efficient way to transform a vector like:
a-c(1,1,0,1,0,0,0,1,1,1,1,0,1,0,1,1)
in a vector that counts only di 1 elements, like:
b-c(1,2,0,1,0,0,0,1,2,3,4,0,1,0,1,2)
Thank you!
One way:
rl - rle(a)
unlist(mapply(*, lapply(rl$lengths,
Is the '`' character supposed to be there before the ## Add error bars
comment?
If that is the problem, let it be a good lessonto use an editor with
syntax highlighting. :)
Brian Frizzelle wrote:
All,
I think there may be some misunderstanding about my problem. In my code,
which
Joris' suggestions are good ones.
I use Emacs with ESS (and now org-babel) for R programming and for
interaction with the R process. But I use Emacs for everything. Emacs is
actually pretty easy to install these days on Windows, and Vincent
Goulet provides a nice package with all you need to
Eric Fail wrote:
Hi Ruser
As so usual I'm trying to replicate some SAS code. I wold like to know
if there is a wildcard operators, as : in SAS, in R?
When running:
lm(y ~ x1 + x2 + x3 + x4 + x5 + x6 x9860, data=mydata)
I would like to be able to get around it by just writing
?try
g...@ucalgary.ca wrote:
As we knew, if a function is not used correctly,
an error message will throw/display in R:
rnorm(-1)
Error in rnorm(-1) : invalid arguments
I would like to catch the error message or assign an error message to a
variable so that I can use them some where else.
Zoppoli, Gabriele (NIH/NCI) [G] wrote:
Hi,
I want to generate a number of vectors and store them with different names,
like this:
x=1
while (x100)
{
vector#x# = rnorm(100)
x=x+1
}
where each vector has, at its hand, instead of #x# a number which goes from 1
to 99.
How can I do
You might want to ask on R-SIG-Debian
https://stat.ethz.ch/mailman/listinfo/r-sig-debian
Cedrick W. Johnson wrote:
Hi-
Looks like this morning, I did the ultimate in foobar to a main prod
box. I was using apt-get upgrade on the box and totally missed the fact
that my entire R installation
It's easiest for us to help if you give us a reproducible example. We
don't have your datasets (ap.dat), so we can't run your code below.
It's easy to create sample data with the random number generators in R,
or use ?dput to give us a sample of your actual data.frame.
I would guess your
Where does the problem comes from?? Maybe from my sytem date ??
Simply from not reading the options carefully enough, from ?strptime,
‘%y’ Year without century (00-99). If you use this on input, which
century you get is system-specific. So don't! Most often
values
Stella Pachidi wrote:
Dear Erik and R experts,
Thank you for the fast response!
I include an example with the ChickWeight dataset:
ap.dat - ChickWeight
matchMeanEx - function(ind,dataTable,aggrTable)
{
index - which((aggrTable[,1]==dataTable[[Diet]][ind])
Noah Silverman wrote:
That's amazing. (It would have taken me many hours to figure this out
on my own.)
Two quick last questions and then I'm off to plotting:
1) How can I reduce the font size of the table. (It is huge on my plot.)
2) How can I control the ratio of plot area to table area in
McGehee, Robert wrote:
R-help,
Sorry if this is more of a regex question than an R question. However,
help would be appreciated on my use of the regexpr function.
In the first example below, I ask for all characters (a-z) in 'abc123';
regexpr returns a 3-character match beginning at the first
Changbin Du wrote:
It does not work.
outcome.label-LETTERS(outcome.predict)
Error: could not find function LETTERS
That is not when Henrique typed. LETTERS is a vector, and must be
indexed as such, i.e., with [].
__
R-help@r-project.org
Changbin Du wrote:
Hi, Dear R- community,
I am use the intToChar function to convert the integers to letters. But the
output is mess. Can you guys give some suggestions? Thanks!
I suggest you tell us what you were expecting to happen, that is, what
do you actually want? It looks like
Bunny, lautloscrew.com wrote:
Dear all,
I am trying to avoid a for loop here and wonder if the following is
possible:
I have a data.frame with 6 columns and i want to get a
cross-correlogram (by using ccf) . Obivously ccf only accepts two
columns at once and then returms a list. In fact,
How could we possibly tell without your code? Do you call glm or fit
*any* models in your code? Can you use traceback() to see the trace of
function calls that generated the error?
Jimmy Söderly wrote:
Dear R users,
After running Sweave, this is what I get :
Warning messages:
1:
Erik Iverson wrote:
How could we possibly tell without your code? Do you call glm or fit
*any* models in your code? Can you use traceback() to see the trace of
function calls that generated the error?
Sorry you aren't getting an error, but a warning, my mistake
dhanush wrote:
can anyone tell me how to import a text file in R? the text file I want to
import is a large file, about 800MB in size. Thanks in advance.
I tried using the following
data-read.table(file,header=T,sep=\t)
And what happened??
Your specification is incomplete, as we don't
Dhanasekaran wrote:
Sorry guys
It is a tab delimited text file which I just exported from SAS. I want to
import this in R. Pl let me know what is the delimiter I should use and R
syntax.
You still don't say the error you're getting when you try your read.table
command.
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