Did you try the example described on the ff man page?
On Monday, April 2, 2012, Bond, Stephen wrote:
Thomas,
I tried biglm and it does not work see
http://r.789695.n4.nabble.com/unable-to-get-bigglm-working-ATTN-Thomas-Lumley-td2276524.html#a2278381
. There are other posts from people
you want to check the ff man page (?ff), there is an example described
there with biglm. b
On 30 March 2012 21:05, Bond, Stephen stephen.b...@cibc.com wrote:
Greetings useRs,
Can anyone provide an example how to use ff to feed a very large data
frame to glm?
The data.frame cannot be loaded
= ',', quote = ', header = TRUE)
On Mon, Mar 26, 2012 at 8:09 PM, Benilton Carvalho
beniltoncarva...@gmail.com wrote:
I need to read in csv files, created by 3rd party, with fields
containing single quotes (as shown below).
header1,header2,header3,header4
field1r1,field2r1,field3r1,field4r1
You probably want:
sql-UPDATE testtable SET vals=21 WHERE countries='NewZealand'
dbGetQuery(con, sql)
instead...
b
On 27 March 2012 14:18, Thomas Adams thomas.ad...@noaa.gov wrote:
All:
I am using RSqlite and want to be able to update individual values in a
record, such as with this
I need to read in csv files, created by 3rd party, with fields
containing single quotes (as shown below).
header1,header2,header3,header4
field1r1,field2r1,field3r1,field4r1
field1r2,field2r2,field3r2PartA), field3r2PartB Very Long,field4r2
field1r3,field2r3,field3r3,field4r3
read.csv(filename,
Hi,
I have a long list of lists from which I want to efficiently extract
and rbind elements. So I'm using the approach below:
f - function(i){
out - replicate(5, list(matrix(rnorm(80), nc=20)))
names(out) - letters[1:5]
out
}
set.seed(1)
lst - lapply(1:1.5e6, f)
(t0 -
Thanks Henrik!!! Hope to pay your beer soon. :) b
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal,
Hi,
what is the proper of of passing a missing value so I can extract
the entire i-th row of a matrix (in a list of lists) without
pre-computing the number of cols?
For example, if I know that the matrices have 2 columns, I can do the following:
set.seed(1)
x0 - lapply(1:10, function(i)
Hi Chuck, thank you *very* much! That really helped! b
On 9 March 2012 17:15, cbe...@tajo.ucsd.edu wrote:
Benilton Carvalho beniltoncarva...@gmail.com writes:
Hi,
what is the proper of of passing a missing value so I can extract
the entire i-th row of a matrix (in a list of lists) without
Thanks guys... I'm already embarrassed given how simple the solutions are. b
On Saturday, 18 February 2012, Hadley Wickham wrote:
On Fri, Feb 17, 2012 at 7:51 PM, Benilton Carvalho
beniltoncarva...@gmail.com javascript:; wrote:
Hi everyone,
For reasons beyond the scope of this message
Hi everyone,
For reasons beyond the scope of this message, I'd like to append a
NULL element to the end of a list.
tmp0 - list(a=1, b=NULL, c=3)
append(tmp0, c(d=4)) ## works as expected
append(tmp0, c(d=NULL)) ## list with a/b/c only
Given that I could use
tmp0$a - NULL
to remove 'a', I seem
Thank you very much, David.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Have you removed the *.so and *.o files prior to R CMD SHLIB hello.c?
b
On Tue, May 11, 2010 at 11:39 PM, Elizabeth Lawson
lawson.elizab...@gmail.com wrote:
I recently bought a new macbook pro 10.6.3 and I am trying to compile some C
code I have. I reinstalled R and Xcode on the Mac but I
or possibly use smoothScatter() to produce the scatter plots
On Fri, Apr 30, 2010 at 12:06 PM, ONKELINX, Thierry
thierry.onkel...@inbo.be wrote:
Dear Nevil,
Converting your pdf to png will be the most efficient way to reduce the
file size with scatter plots.
You can either export
maybe
for (i in 1:10) assign(paste(matrix, i, sep=_), matrix(nrow=i, ncol=i))
suffices?
On Thu, Apr 22, 2010 at 5:08 PM, karena dr.jz...@gmail.com wrote:
I need to create 10 matrices. say matrix 1-10.
matrix_1 is 1 by 1
matrix_2 is 2 by 2
matrix_3 is 3 by 3
.
.
.
matrix_10 is 10
save(list=paste(unislopes, master.i, sep=),
file=paste(unislopes,master.i,.Rdata,sep=))
On Mon, Apr 12, 2010 at 12:06 PM, David Young dyo...@telefonica.net wrote:
I'd like to use a string to refer to an R object with the end
objective of going through a loop and saving various files of the same
maybe
inc.freqy - sapply(unit.dist, function(x) rowSums( test = x))
suffices?
b
On Mon, Apr 5, 2010 at 5:31 PM, pinusan anh...@msu.edu wrote:
Dear R users,
I would like to transform the following for loop from R-code to C-code
because it takes really long time to have inc.freqy table.
FAQ 7.31: Why doesn't R think these numbers are equal?
http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-doesn_0027t-R-think-these-numbers-are-equal_003f
b
On Wed, Mar 31, 2010 at 10:10 AM, Gianluca Baio gianl...@statistica.it wrote:
Dear list,
I have observed a weird behaviour from R ---
if this was to work, wouldn't the object 'v' be identical to 'x'?...
so, why not use 'x' itself?
b
On Tue, Mar 23, 2010 at 2:53 PM, Pj253 pj...@cam.ac.uk wrote:
I have a list of vectors, x, with x[[1]]=1:5, say.
And I need to go through each element of each vector in a for loop.
Something
can you also post an example of A and an example of the expected result?
On Tue, Mar 23, 2010 at 3:36 PM, Pj253 pj...@cam.ac.uk wrote:
Thanks for your reply Ben!
I don't think I want v to be identical to x... I guess I haven't put the
question in the right context. What I'm actually trying
and in addition to bill's suggestion, you may want to consider not
growing a list.
Instead of 'v - list()', use:
v - vector(list, nrow(A))
b
Will your code work as you wish if you
replace the for(v[[1]] in x[[1]]) { ... }
with the following?
for(i in x[[1]]) {
v[[2]] - i
...
To access elements of a list (object returned by split), you need to use [[.
Therefore,
summary(temp[[1]])
is what you meant to use (or even summ = lapply(temp, summary) - which
will give you the summaries for every subject).
About using PDFs, I'd recommend you to take a look at Sweave (
If you could describe exactly what is it that you're trying to
accomplish, we could be of better help (the reason I say this is
because the way you're trying to implement things is a bit
inefficient).
Anyways, you can't use two indices with a list.
One approach would be to nest lists, and you'd
how about
y = X[rep(1:nrow(X), 6), ]
?
On Mon, Mar 15, 2010 at 5:37 PM, jlu...@ria.buffalo.edu wrote:
What is an easy way to stack a matrix multiple times? E.g. I have a 6x6
matrix that I need to stack vertically 154 times to get a 6*154 by 6
matrix. I would rather not rbind(X,X,...,X)
dd = as.POSIXlt(c(2007-02-21 05:19:00, 2007-02-20 14:21:53),
format=%Y-%m-%d %H:%M:%S)
dd[1]-dd[2]
b
On Tue, Feb 23, 2010 at 2:48 PM, karine heerah karine.hee...@hotmail.fr wrote:
Hi,
I have date and time in a format like this: 2007-02-21 05:19:00.
Do you which function i can use to
assigning rownames (after the object is created) triggers a copy of
the object... if you assign the rownames at creation time, no extra
copies...
b
On Mon, Feb 22, 2010 at 9:46 AM, Larson, TR t...@york.ac.uk wrote:
Hi,
On R 2.10.1 for Windows, when I do the following to duplicate the
gsub(one|two, something else, y)
?
On Mon, Feb 22, 2010 at 4:25 PM, Marianne Promberger
marianne.promber...@kcl.ac.uk wrote:
Dear list,
I have two vectors:
x - c(one,two)
y - paste(rep(x,2),blah)
I want to replace all occurrences of each element of x in y with
something else, so that y
x[nrow(x):1,]
b
On Thu, Feb 18, 2010 at 11:45 AM, Amelia Livington
amelia_living...@yahoo.com wrote:
Dear 'R' friends
I have a sort of stupid question to ask.
I have a matrix say of the order 4 X 3 as
83 98 90
21 83 84
70 39 56
65 29 38
Is there any command in
you mean something along the lines of
filter(x, rep(1/4, 4))
(which you can combine with na.omit)
?
On Wed, Feb 17, 2010 at 5:18 PM, Mohsen Jafarikia jafari...@gmail.com wrote:
Hello All:
If I do have:
x = (2, 4, 5, 5, 6, 4, 5, 2, 1)
y = (9, 11.5, 12.5, 13, 14, 19, 20, 21, 22)
I wanted
say you read the quantity.csv file into a variable called
'quantity'... similarly, 'equity_price.csv' to equity.
sweep(equity, 2, quantity, *)
b
On Tue, Feb 16, 2010 at 11:20 AM, Sarah Sanchez
sarah_sanche...@yahoo.com wrote:
Dear Madam / R helpers,
Unfortunately the solution you have
maybe you just want
Y = ONS^2
?
b
On Mon, Feb 15, 2010 at 12:22 PM, Madhavi Bhave madhavi_bh...@yahoo.com wrote:
Dear R Helpers
(There is a small correction in my earlier mail. In the 'instrument.csv'
file, I had mentioned only three columns. Actually there are 7 columns. I
regret the
sorry, meant to type:
B = ONS^2
cheers,
benilton
On Mon, Feb 15, 2010 at 12:28 PM, Benilton Carvalho
beniltoncarva...@gmail.com wrote:
maybe you just want
Y = ONS^2
?
b
On Mon, Feb 15, 2010 at 12:22 PM, Madhavi Bhave madhavi_bh...@yahoo.com
wrote:
Dear R Helpers
(There is a small
Carvalho beniltoncarva...@gmail.com wrote:
From: Benilton Carvalho beniltoncarva...@gmail.com
Subject: Re: [R] CORRECTION - Storing results in a loop
To: Madhavi Bhave madhavi_bh...@yahoo.com
Cc: r-help@r-project.org
Date: Monday, 15 February, 2010, 4:29 AM
sorry, meant to type:
B = ONS^2
http://cran.r-project.org/web/views/HighPerformanceComputing.html
2010/2/15 thomas.schwan...@mvv.de:
Dear all,
I'm sitting here just in front of my new p...@work and wonder about the
following question:
* How can I adress multiple CPUs (cores) out of R to speed up the
simulations
On Thu, Feb 11, 2010 at 4:18 PM, Philipp Rappold
philipp.rapp...@gmail.com wrote:
Dear all,
I have two probably very easy questions:
(1) Is there a way to access certain variables by their string-based name
representation?
Example:
numbers - c(one, two, three)
varname - numbers
Hi Matt,
what's your sessionInfo()? Can you try installing bigmemory as follows:
install.packages(bigmemory, repos=http://R-Forge.R-project.org;)
it'll get you the latest version, in which I cannot reproduce the
problem you're reporting (ie, after gc(), I get all the RAM back)
b
On Sat, Feb
Hi Matt,
you're correct: length(ffObject) must be smaller than 2^31-1... at
least until R has a 64bit integer type, it seems...
in the meantime, use the bigmemory package. ;-)
b
On Fri, Feb 5, 2010 at 4:18 PM, Matthew Keller mckellerc...@gmail.com wrote:
Hello all,
I hate to add to the
use other aproaches to fill in the ff dataframe
b
On Fri, Feb 5, 2010 at 11:43 PM, Benilton Carvalho
beniltoncarva...@gmail.com wrote:
Hi Matt,
you're correct: length(ffObject) must be smaller than 2^31-1... at
least until R has a 64bit integer type, it seems...
in the meantime, use
, when under a 64 bit OS),
wouldn't this allow us to have objects whose length exceeded the
2^31-1 limit?
Benilton Carvalho
The double type in R can hold exact integer values up to around 2^52. So for
example calculations like this work fine:
x - 2^50
y - x + 1
y-x
[1] 1
Just don't ask R
check aggregate() (the examples are quite helpful)
b
On Mon, Jan 25, 2010 at 4:07 PM, james.fo...@diamond.ac.uk wrote:
Dear R community,
I'm trying to develop a fast way of summing specific rows of a large data
frame.
Here is an example of the kind of data frames I'm dealing with:
theFiles - list.files(inputdir, full=T, pattern=\\.[eE][xX][tT]$)
for (file in theFiles){
...
}
On Fri, Jan 15, 2010 at 11:43 AM, Albert Vilella avile...@gmail.com wrote:
Hi all,
I'm trying to process all files with a certain extension *.ext in a
directory like this:
R --slave --args
adapted from the help files of rowsum
x - matrix(runif(100), ncol=5)
group - sample(1:8, 20, TRUE)
xsum - rowsum(x, group)
sweep(xsum, 1, table(group), /)
or
aggregate(x, list(group), mean)[-1]
b
2010/1/15 Joel Fürstenberg-Hägg joel_furstenberg_h...@hotmail.com:
Hi all,
I want to
you need to be more clear on your question...
what is it (exactly) that you want? Is it the following?
y1 ~ x1 + ... + xm
y2 ~ x1 + ... + xm
...
yn ~ x1 + ... + xm
?
if so:
lm(cbind(y1, y2, ..., yn) ~ x1+x2+...+xm)
b
On Dec 24, 2009, at 3:33 PM, Hao Cen wrote:
Hi,
I have multiple
replace data[1:i,] by data[1:i,drop=FALSE].
b
On Dec 24, 2009, at 12:46 AM, Francesco Napolitano wrote:
Hi all,
I'm trying to learn R after years of Matlab's experience. Here is an
issue I couldn't solve today.
Consider the following piece of code (written by memory):
for(i in 1:n){
instead of densityplot(...) use
print(densityplot(...))
b
On Dec 16, 2009, at 3:19 PM, c...@autistici.org wrote:
Hi,
i have a script how i launch lattice to make a densityplot.
in the script:
jpeg(file=XXX.jpg)
densityplot(~f_diametro+m_diametro+n_diametro, plot.points=rug,
auto.key=T)
use tracemem() to figure out... and read its documentation in detail.
b
On Dec 15, 2009, at 1:03 AM, Peng Yu wrote:
I'm wondering if lazy copy is available in R or not. For example, in
the following code, I'm wondering if the memory for y is allocated in
the 2nd line or the 3rd line. Is
oh.. and i just saw the bonus part... just replace lapply() by sapply().
b
On Dec 11, 2009, at 8:33 PM, Jennifer Young wrote:
Good evening
I often have as output from simulations a list of various values, vectors
and matrices.
Supposing that I then run said simulation several times, I
matrix(t(G), nc=1)
b
On Dec 4, 2009, at 1:19 PM, Jose Narillos de Santos wrote:
Hi all,
Imagine I have a matrix G
with N rows
and M columns
So L=NxM is the number of different cells in my matrix.
I want to create a column vector F whose size will be F(L,1)
So the fisrt row
isn't it simpler just to pass two vectors, say v1 and v2, in which one contains
the object names and the other has the associated variances? (btw, data isn't
a good function name)
myData - function(v1, v2){
Vec - matrix(v1)
varF - v2
}
I may have misunderstood your question, but IMHO all
I can't think of anything that is already built in.
But you can always:
read.as.matrix - function(...) as.matrix(read.delim(...))
and now you get one step only ;-)
b
On Nov 20, 2009, at 4:01 PM, Peng Yu wrote:
On Sat, Nov 21, 2009 at 11:55 AM, Steve Lianoglou
mailinglist.honey...@gmail.com
take a look at geshi. b
On Nov 20, 2009, at 4:26 PM, Tal Galili wrote:
My question if in the Subject, but if to extend: I am specifically
curious
about WordPress blogs. But any solution will give me a lead.
Thanks,
Tal
--
Contact me:
readFASTA in the BioConductor Biostrings package.
b
On Nov 18, 2009, at 8:14 AM, Tal Galili wrote:
Hello dear R help group,
I would like to download the tRNA data on:
http://gtrnadb.ucsc.edu/download.html
And then import it into R.
Can anyone direct me as to how to do so?
Thanks,
Tal
it doesn't skip...
think about why:
seq(.30,.5,.01) * 100 - 29 == 1:21
isn't always TRUE.
b
On Nov 17, 2009, at 9:17 PM, Bruno Giovannetti wrote:
Hello,
Sometimes the looping (using for) seems to skip some iterations.
An example:
arg - matrix(NA,length(seq(.30,.5,.01)),1)
for (i in
align the else with the curly brackets
if (yes){
be happy
}else{
complain
}
b
On Nov 13, 2009, at 3:33 PM, anna_l wrote:
Hello, I am getting an error with the following code:
if( P2 P1)
+ {
+ P-P2
+ }
else
Erro: unexpected 'else' in else
{
+ P-P1
+ }
I checked the syntax so I don´t
release.
If you're trying to run RMA on your data, I can think of ways of
working around this problem.
Cheers,
b
On Nov 7, 2009, at 5:46 PM, Benilton Carvalho wrote:
ok, i'll take a look at this and get back to you during the week. b
On Nov 7, 2009, at 1:19 PM, Peng Yu wrote:
Most
Hi Peng,
in a very simplistic manner, what happens is that the Operating System
thinks it is too dangerous to let the R process to use so much
memory. So, to protect the whole system, it kills R, before the system
becomes unstable.
I've been looking at the problem you observed last week
when trying
to read.
best,
b
On Nov 7, 2009, at 10:12 AM, Peng Yu wrote:
On Fri, Nov 6, 2009 at 8:19 PM, Benilton Carvalho
bcarv...@jhsph.edu wrote:
this is converging to bioc.
let me know what your sessionInfo() is and what type of CEL files
you're
trying to read, additionally provide
ok, i'll take a look at this and get back to you during the week. b
On Nov 7, 2009, at 1:19 PM, Peng Yu wrote:
Most of the 8GB was available, when I run the code, because R was the
only computation session running.
On Sat, Nov 7, 2009 at 7:51 AM, Benilton Carvalho
bcarv...@jhsph.edu wrote
it appears that what you really want is to use:
task[[i]]
instead of task[i]
b
On Nov 1, 2009, at 11:04 PM, dadrivr wrote:
I would like to preface this by saying that I am new to R, so I
would ask
that you be patient and thorough, so that I'm not completely
clueless. I am
trying to
bigmemory and biglm packages may be of your interest.
b
On Oct 28, 2009, at 8:50 AM, Georg Ehret wrote:
Dear R community,
I have a fairly large file with variables in rows. Every variable
(thousands) needs to be regressed on a reference variable. The file
is too
big to load into R (or R
or
unlist(l)
and possibly you want a unique() on that...
b
On Oct 28, 2009, at 5:15 PM, Jorge Ivan Velez wrote:
Hi Peng,
Here is a suggestion:
unique(do.call(c, l))
# [1] 1 3 4 6 7
Best regards,
Jorge
On Wed, Oct 28, 2009 at 3:07 PM, Peng Yu wrote:
Suppose that I have a list of
colnames(x) - NULL
On Oct 27, 2009, at 8:09 PM, Peng Yu wrote:
I only see how to assign values to colnames() in help. Is there a way
to remove colnames?
colnames(x) - value
__
R-help@r-project.org mailing list
Dear Lasse,
This won't answer your specific questions and I apologize for that.
AFAIK, pdf() produces uncompressed PDFs only. But you could use tools
like pdftk to compress your PDFs. About the PNGs, you can always set
the 'res' argument to improve resolution, but it won't beat the PDFs.
Maybe
http://cran.r-project.org/doc/manuals/R-exts.pdf
?
b
On Oct 23, 2009, at 2:10 AM, Peng Yu wrote:
I found the following document on making R packages. But it is old.
I'm wondering if there is more current ones and hopefully more
complete ones.
aves = aggregate(df1$score, by=list(col1=df1$col1, col2=df1$col2), mean)
results = merge(df1, aves)
b
On Oct 21, 2009, at 9:03 AM, Tony Breyal wrote:
Dear all,
Lets say I have the following data frame:
set.seed(1)
col1 - c(rep('happy',9), rep('sad', 9))
col2 - rep(c(rep('alpha', 3),
If you change 'area' to an environment, you may be able to get
something close to what you want.
For example:
setClass(Square,
representation(
length='numeric',
width='numeric',
area='environment'
, Benilton Carvalho wrote:
If you change 'area' to an environment, you may be able to get
something close to what you want.
For example:
setClass(Square,
representation(
length='numeric',
width='numeric',
area='environment
align the 'else if' and 'else' with the closing curly brackets.
if (condA){
doStuff()
} else if (condB){
doOtherStuff()
} else {
doWhatever()
}
b
On Oct 3, 2009, at 12:54 PM, Chen Gu wrote:
Hello,
I am doing a simple if else statement in R. But it always comes out
error
such as
for reading the matrix.
I will try the scan() and see if it helps.
Thanks!
Mike
-Original Message-
From: Benilton Carvalho [mailto:bcarv...@jhsph.edu]
Sent: Wednesday, September 23, 2009 4:56 PM
To: Ping-Hsun Hsieh
Cc: r-help@r-project.org
Subject: Re: [R] read.delim very slow in reading
-
From: Benilton Carvalho [mailto:bcarv...@jhsph.edu]
Sent: Wednesday, September 23, 2009 4:56 PM
To: Ping-Hsun Hsieh
Cc: r-help@r-project.org
Subject: Re: [R] read.delim very slow in reading files with lots of
columns
use the 'colClasses' argument and you can also set 'nrows'.
b
On Sep 23, 2009
and note that if, instead of zip files, you were using gzip files, you
could:
conn - gzfile(file.gz, rt)
theData - read.table(conn)
close(conn)
b
On Sep 22, 2009, at 11:21 PM, Gabor Grothendieck wrote:
Linux is a type of UNIX so follow the instructions I gave for UNIX.
On Tue, Sep 22,
if you want to sample integers in [1, 33K] without replacement:
theSample = sample(33000, 18000)
b
On Sep 23, 2009, at 7:29 PM, phoebe kong wrote:
Hi all,
I would like to generate ~18K random number from range 1 to ~33K.
I was thinking to use round(runif(18000,1,33000)), however the some
use the 'colClasses' argument and you can also set 'nrows'.
b
On Sep 23, 2009, at 8:24 PM, Ping-Hsun Hsieh wrote:
Hi,
I am trying to read a tab-delimited file into R (Ver. 2.8). The
machine I am using is 64bit Linux with 16 GB.
The file is basically a matrix(~600x70) and as large
library(Matrix)
a = sparseMatrix(i=c(20, 30, 1), j=rep(1, 3), x=c(2.2, 3.3,
4.4))
b = sparseMatrix(i=c(3, 30), j=rep(1, 2), x=c(0.1, 0.1), dims=dim(a))
theSum = a+b
summary(theSum)
hth,
b
On Sep 8, 2009, at 10:19 AM, Henrique Dallazuanna wrote:
Try this:
abMerge - merge(a, b, by
have you tried:
fits - lm(a~b)
fstat - sapply(summary(fits), function(x) x[[fstatistic]][[value]])
it takes 3secs for 100K columns on my machine (running on batt)
b
On Aug 23, 2009, at 9:55 PM, big permie wrote:
Dear R users,
I have a matrix a and a classification vector b such that
result - Reduce(+, unlist(z, recursive=FALSE))
b
On Aug 22, 2009, at 2:03 PM, kathie wrote:
Dear Gabor Grothendieck,
thank you for your comments.
Ive already tried that. but I've got this error message.
Reduce(+,z)
Error in f(init, x[[i]]) : non-numeric argument to binary operator
it's 'scipen' you want to look at.. b
On Aug 22, 2009, at 11:16 PM, David Winsemius wrote:
On Aug 22, 2009, at 6:13 PM, Dajiang J. Liu wrote:
Dear all,I want to convert a long integer to a string, and for
example,
1
I used as.character(10) e.g, and it gives me back 1e+???.
you may also consider installing from the command line...
R CMD INSTALL ~/Desktop/Camino-downloads/DiagnosisMed_0.2.2.1.tar.gz
b
On Aug 21, 2009, at 11:27 PM, Juliet Hannah wrote:
Hi Janet,
Were you able to install the package? I just installed it without
problems. I don't
think there
Hi,
Here's one toy example that shows what I believe to be a problem with
plot.lm. This was brought up by another user (Marcos Tadeu Andrade
Cordeiro). I took a look at the source and the problem appears to be
related to the fact that you need to reorder the data by the group
means and
set.seed(1)
x - matrix(runif(1000), 100)
system.time(tmp1 - exp(rowMeans(log(x
system.time(tmp2 - apply(x, 1, function(y) prod(y)^(1/length(y
all.equal(tmp1, tmp2)
## tmp1 is more robust, btw
On Aug 20, 2009, at 3:22 PM, Edward Chen wrote:
Is there a function or an easier way to
what do you get with:
capabilities()[[jpeg]]
?
b
On Aug 18, 2009, at 7:27 PM, Edward Chen wrote:
My script:
raw = read.table(c:\\Documents and Settings\\protein\\My Documents\
\My
Fragments\\file1.txt, header = TRUE)
#Normal Average Signal VS Pool
jpeg(Normal Average Signal vs
you could stick everything in a 1-liner, but that would make it less
readable:
myf - function(x){
tmp - as.character(x)
c(tmp[1], paste(tmp[1], tmp[-1], sep=))
}
df2 - as.data.frame(sapply(df, myf))
b
On Aug 12, 2009, at 3:39 AM, milton ruser wrote:
Hi Jill,
Completely not elegant,
what are exactly some operations? if you could provide a
reproducible code, it would make it easier to understand what you're
trying to achieve.
for example, if you were to get the means, you could do something like:
theMeans - rapply(test, mean)
cheers,
b
On Aug 11, 2009, at 8:59 PM,
?assign
b
On Apr 2, 2008, at 4:26 PM, Georg Ehret wrote:
Dear R community,I wish to include a variable (e.g. slice of a
below)
in another variable's name. My objective would be to get a variable-
name
data_A and so on. How can I do this?
a-LETTERS[1:25]
a
[1] A B C D E F G H I J K L M
Brain indeed.
On Mar 19, 2008, at 11:21 AM, sun wrote:
Thanks Prof. Brain,
Following your suggestion I found the reason of my problem in the
document
''R Installation and Administration' and the links it points to'.
After I updated to R2.6.2, the RTools's default compiler chaged to
gcc4
On Mar 18, 2008, at 11:44 PM, Rolf Turner wrote:
On 19/03/2008, at 4:39 PM, Erin Hodgess wrote:
do.call(class,list=ls())
sapply(ls(),function(x){class(get(x))})
or, in case you want to save some typing:
eapply(globalenv(), class)
b__
get(x1)
On Mar 19, 2008, at 1:07 AM, Erin Hodgess wrote:
Dear R People:
I have a function x1
Next, I have a character vector x which has one element, x1.
How would I retrieve the original function x1 from the character
vector, please?
thanks,
Erin
--
Erin Hodgess
Associate Professor
or the suggestive :)
?[
b
On Mar 13, 2008, at 2:58 PM, Henrique Dallazuanna wrote:
On 13/03/2008, John Kane [EMAIL PROTECTED] wrote:
Can you point me to some documentation that discusses
these usages. I have seen them before but I have never
actually figured out how to use them.?
See
gene.pair.tf.lst[sapply(gene.pair.tf.lst, [[, sig.cor)]
b
On Mar 12, 2008, at 5:24 PM, Mark W Kimpel wrote:
I have a very long list that I'd like to subset based on a logical
value
within each element. Example below. I'd like to get just those list
elements for further study whose $sig.cor
imprecise are our eyes :)
check where 4336.543 actually is and note how the range of the data
confused you.
plot(a~b)
abline(model)
abline(h=4336.543, v=10)
b
On Mar 11, 2008, at 11:27 AM, Aad Termorshuizen wrote:
# PROBLEM WITH ABLINE
# I have a question about a seemingly imprecise
and you might want to check ?prop.table
prop.table(a, 2)
[,1] [,2]
[1,] 0.0 0.333
[2,] 0.5 0.333
[3,] 0.5 0.333
or even ?sweep (which will be useful for more complex situations)
sweep(a, 2, colSums(a), /)
[,1] [,2]
[1,] 0.0 0.333
[2,] 0.5 0.333
apparently you forgot the commented, minimal, self-contained,
reproducible code part...
L = 10
M = 20
N = 30
P = 40
set.seed(1)
A = array(rnorm(L*M*N*P), dim=c(L, M, N, P))
B = array(rnorm(L*M*N), dim=c(L, M, N))
B[sample(100, 10)] = 0
C = array(0, dim=c(L, M, N, P))
for (i in 1:L) {
for (j in
no, it won't.
you're doing the right math on the valid subset... but you're not
returning the zeros where needed therefore, the whole thing will
get recycled to match the dimensions.
b
On Mar 6, 2008, at 2:03 PM, Henrique Dallazuanna wrote:
I think this should work:
array(A[abs(B)
apparently you want to check the genefilter package...
it defines functions like:
rowttests
colttests
rowFtests
colFtests
rowVars
rowSds
moreover, a quick look at Biobase is recommended...
that would save you lots of time as you wouldn't have to reinvent the
wheel.
b
On Mar 3, 2008, at
or, in other terms:
set.seed(1)
x - runif(1e7)
x.add - tracemem(x)
y - x
y.add - tracemem(y)
identical(x.add, y.add)
[1] TRUE
ie, both objects have the same memory address - therefore, not a copy:
x.add
[1] 0x200
y.add
[1] 0x200
now, observe what happens when you modify y
target = c(u, d)
apply(expand.grid(rep(list(target), 6)), 1, paste, sep=, collapse=)
b
On Mar 1, 2008, at 9:13 AM, Megh Dal wrote:
Hi all,
Suppose I have to letters 'u' and 'd'. Now I want to find all
combinations like that :
uu
ud
du
.
dd
This type of
have you tried
res - rnorm(10^6)-rnorm(10^6)
?
it take 0.5 sec for me...
b
On Feb 28, 2008, at 3:30 PM, Minimax wrote:
Dear useRs,
Suppose we have loop:
res - c()
for (i in 1:10) {
x - rnorm(2)
res - c(res,x[2]-x[1])
}
and this loop for 10^5 cases runs about
bp = barplot(df$y,names.arg=NULL, yaxt=n, ylim=c(0, 110))
text(bp, df$y+15000, paste(Class, 1:6))
axis(2, df$y)
b
On Feb 26, 2008, at 1:41 AM, milton ruser wrote:
Dear all,
I have some data.frame and I would like (1) change the format of
y=axis to
escape of scientific format (like
?colSums
On Feb 19, 2008, at 6:39 PM, Saurav Pathak wrote:
Hi,
I cannot seem to figure out how to sum over an index of a array.
For example, let A be a 3 dimensional array. I want to, say, find
the sum over the first dimension. That is
S_jk = Sum_i A_ijk
where now S is a 2-dim
apparently you want to check the Introduction to R document I
found it very useful when I started working with R:
http://cran.r-project.org/doc/manuals/R-intro.pdf
try:
names(df) - NULL
b
ps: df is the name of the function to get the density for an F
distribution...
On Feb 18,
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