Hello,
I am trying to include the count labels on stacked bar plots which
represent percentages. I want to show x-amount of individuals make up the
graphed percentages. However, when I include the count labels my y-axis
gets blown out of proportion because it changes to match the count data,
not
Hello r-help,
My question is regarding specific coding in ggmap.
I am mapping radio telemetry detections of shorebirds using ggmap. I want
the map to depict a specific point (lat/lon of a telemetry tower) where the
bird was detected, as well as the following variables associated with that
I am mapping radio telemetry detections of shorebirds using ggmap. I want
the map to depict a specific point (lat/lon) where the bird was detected. I
want this depicted date of detection to be represented by a color scale.
However, multiple birds are detected at the same telemetry tower (lat/lon)
Dear listserv,
Please consider the following dataset:
x - matrix(nrow = 8, ncol = 2)
colnames(matrix) - c(classification, soluble_fiber)
x[1:4,1] - bagel
x[5:8,1] - donut
How would I simulate a dataset for a one-way fixed-effect ANOVA (where
classification is the treatment variable and
Dear R users,
Please consider the following example:
tmp - matrix(rnorm(100),10,10)
tmp[upper.tri(tmp, diag = TRUE)] - NA
heatmap(tmp, col = heat.colors(200), Rowv=NA, Colv=NA)
I have three questions:
(1) How would I change the axis labels from 1:10 to c(apples, pears,
bananas, kiwis,
Dear listserv,
Here is my latest formatting problem. I would like to rotate the x-axis labels
by 45 degrees on a _barplot_. Apparently this is slightly different from the
example given in the R FAQ, which is for rotating the x-axis labels on a
scatterplot
much in advance!
Sincerely,
Josh Banta
From: David Winsemius dwinsem...@comcast.net
Sent: Sat, February 19, 2011 10:24:03 PM
Subject: Re: [R] Partial italic in graph titles when looping
On Feb 19, 2011, at 8:52 PM, Josh B wrote:
Follow-up question: how would I
Dear Listserv,
Here is my latest in a series of simple-seeming questions that dog me.
Consider the following data:
x - read.table(textConnection(temperature probability
0.11 9.4
0 2.3
0.38 8.7
0.43 9.2
0.6 15.6
0.47 8.7
0.09 12.8
0.11 9.4
0.01 7.7
0.83 8
0.65 9.3
0.05 7.4
0.34 10.1
0.02 4.8
Dear all,
I have a rather complicated problem. I am trying to loop through making graphs,
so that the graph-making process is fully automated. For each graph, I'd like
to
make sure the corresponding title is formatted properly. The titles will be a
combination of a gene name and numerical
Hi all,
I'm having a problem once again, trying to do something very simple. Consider
the following data frame:
x - read.table(textConnection(locus1 locus2 locus3
A T C
A T NA
T C C
A T G), header = TRUE)
closeAllConnections()
I am trying to make a new data frame, replacing A with A/A, T with
Hi all,
I am trying to do something simple, but which is deviling me. I want to add an
up-arrow to the x-axis, pointing to a specific location on the axis. I want the
arrow to be as large as possible.
Here is where I'm at with my code:
#this part if from the ?plot example:
require(stats)
Dear Michael,
Thanks very much. I have a follow-up question: how did you know that symbol 255
is the up-arrow?
Josh
From: Michael Bedward michael.bedw...@gmail.com
Cc: R Help r-help@r-project.org
Sent: Wed, October 6, 2010 5:09:48 AM
Subject: Re: [R]
Hello again,
How do I split a data frame into smaller, completely separate data frames
(rather than separate data frames comprising a single list)? Consider the
following data, and my coding attempt:
x - read.table(textConnection(id type number
indv.1 bagel 6
indv.2 bagel 1
indv.3 donuts 10
Hi all,
Please consider the following code:
require(plotrix)
l - list(rnorm(50),rnorm(50,sd=2),rnorm(50,mean=3))
multhist(l)
I have two things I need help with:
(1) In the output, there are empty spaces on the x-axis. How would I eliminate
these spaces? I want a nice, smooth,
y3
[1,] 0.6976063 NA 0.6976063
From: David Winsemius dwinsem...@comcast.net
Cc: R Help r-help@r-project.org
Sent: Sun, July 18, 2010 9:12:44 PM
Subject: Re: [R] Continuing on with a loop when there's a failure
On Jul 18, 2010, at 12:28 PM, Josh B wrote
Hi all,
I am trying to concatenate words together to create new column names, using a
loop.
Please consider the following toy example:
x - matrix(nrow = 1, ncol = 3)
colnames(x) - c(a, b, c)
x[1,1] - 1
x[1,2] - 2
x[1,3] - 3
I would like to create a new matrix with column names based on the
Winsemius dwinsem...@comcast.net
To: David Winsemius dwinsem...@comcast.net
Sent: Tue, July 13, 2010 9:09:04 AM
Subject: Re: [R] Continuing on with a loop when there's a failure
On Jul 13, 2010, at 9:04 AM, David Winsemius wrote:
On Jul 13, 2010, at 8:47 AM, Josh B wrote:
Thanks again
dwinsem...@comcast.net
To: David Winsemius dwinsem...@comcast.net
Sent: Tue, July 13, 2010 9:09:04 AM
Subject: Re: [R] Continuing on with a loop when there's a failure
On Jul 13, 2010, at 9:04 AM, David Winsemius wrote:
On Jul 13, 2010, at 8:47 AM, Josh B wrote:
Thanks again, David.
[[elided
...@comcast.net
Cc: Peter Konings peter.l.e.koni...@gmail.com; R Help r-help@r-project.org
Sent: Sun, July 18, 2010 3:33:07 PM
Subject: Re: [R] Continuing on with a loop when there's a failure
On Jul 18, 2010, at 4:25 AM, Josh B wrote:
Hello Peter,
I tried your suggestion, but I was still not able
.
From: David Winsemius dwinsem...@comcast.net
Cc: R Help r-help@r-project.org
Sent: Mon, July 12, 2010 8:09:03 PM
Subject: Re: [R] Continuing on with a loop when there's a failure
On Jul 12, 2010, at 6:18 PM, Josh B wrote:
Hi R sages,
Here is my latest problem
:09:04 AM
Subject: Re: [R] Continuing on with a loop when there's a failure
On Jul 13, 2010, at 9:04 AM, David Winsemius wrote:
On Jul 13, 2010, at 8:47 AM, Josh B wrote:
Thanks again, David.
[[elided Yahoo spam]]
(BTW, it did work.)
Here's what I'm trying now:
for (i in 1:2
Hi R sages,
Here is my latest problem. Consider the following toy example:
x - read.table(textConnection(y1 y2 y3 x1 x2
indv.1 bagels donuts bagels 4 6
indv.2 donuts donuts donuts 5 1
indv.3 donuts donuts donuts 1 10
indv.4 donuts donuts donuts 10 9
indv.5 bagels donuts bagels 0 2
indv.6 bagels
I just checked, and it doesn't seem to have failed:
model.lrm24$fail
[1] FALSE
Any other possibilities?
From: Christos Argyropoulos argch...@hotmail.com
Sent: Sun, June 20, 2010 7:23:34 AM
Subject: RE: [R] Unable to fit error message from the lrm function
Hello again R users,
I have a devilishly hard problem, which should be very simple. I hope someone
out there will have the answer to this on the tip of their tongue.
Please consider the following toy example:
x - read.table(textConnection(y x1 x2
indv.1 bagels 4 6
indv.2 donuts 5 1
indv.3
Hi all,
I have another question about the lrm function (from the rms library) that I
cannot find the answer to.
I get an error message when I try to fit a model, and I don't know what to make
of it. Please forgive me for not having a toy example, but it appears the size
and complexity of my
Hi all,
I am looking to fit a logistic regression using the lrm function from the
Design library. I am interested in this function because I would like to obtain
pseudo-R2 values (see http://tolstoy.newcastle.edu.au/R/help/02b/1011.html).
Can anyone help me with the syntax?
If I fit the
Hello again,
I was hoping one of you could help me with this problem. Consider the sample
data from R:
summary(prcomp(USArrests))
Importance of components:
PC1 PC2PC3 PC4
Standard deviation 83.732 14.2124 6.4894 2.48279
Proportion of Variance 0.966
Dear listserv,
I am trying to perform a principal components analysis and create an output
table of the eigenvalues for the dependent variables. What I want is to see
which variables are driving each principal components axis, so I can make
statements like, PC1 mostly refers to seed size or
Hi all,
This should be a very simple question for you, whereas it is proving devilish
for me.
How do I output the STANDARD ERROR of the regression coefficient (i.e., the
standard error of b) from a simple linear regression?
Consider this data, taken directly from ?lm:
ctl -
Hi all,
I have a very simple problem that I cannot seem to find the answer to. Consider
the following toy dataset:
x - read.table(textConnection(V1 apples bananas cherries
indv.1 7 8 4 3
indv.2 7 7 4 9), header = TRUE)
How would I change the column name of ONLY the first column, not the
Hello R listserve,
I would appreciate someone's help with this problem. Consider the following toy
dataset:
x - read.table(textConnection(worldclim.1 worldclim.2 cru.1 cru.2
indv.1 7 8 32 658
indv.2 7 7 39 422), header = TRUE)
How could I create a subset of the data based on the column prefix?
Hello Listserve,
Here is another question to keep you on your toes. Please consider the
following toy dataset:
a - read.table(textConnection(fred sam joe alex
measure.1 10 4 10 1
measure.2 10 4 2 8
measure.3 3 1 8 3
measure.4 5 1 3 3
measure.5 8 6 8 3
measure.6 9 5 1 0
measure.7 4 6 10 1
Hi,
I turn to you, the R Sages, once again for help. You've never let me down!
(1) Please make the following toy files:
x - read.table(textConnection(var.1 var.2 var.3 var.1000
indv.1 1 5 9 7
indv.21 2 9 3 8), header = TRUE)
y - read.table(textConnection(var.3 var.1000), header = TRUE)
Hi,
I was hoping someone could help me with the following problem. Consider this
toy example. For the input dataset there are four individuals (rows indv.1
through indv.4), measured for two different variables (columns var.1 and
var.2) at two different levels of a factor (column factor.level).
Hello R Forum users,
I was hoping someone could help me with the following problem. Consider the
following toy dataset:
AccessionSNP_CRY2SNP_FLCPhenotype
1NAA0.783143079
2BQA0.881714811
3BQA0.886619488
4AQB0.416893034
5AQB
.
Thanks very much for your help everyone.
Josh B.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting
Hello,
I was wondering if someone could tell me how to output, to file, the residuals
from a REML model-fit. The type of residuals I am interested in are the simple
original raw values - model fit type.
Thanks in advance,
Josh B.
[[alternative HTML version deleted
-blank observations in each column, but how would I adapt this code to
_delete_ columns from the dataset if they do not have at least 375 non-blank
observations?
lapply(x, function(d)
{
d.2- na.omit(d)
count- length(d.2)
}
)
Many thanks in advance,
Josh B.
[[alternative HTML
? (In my real
dataset, there are 1096 loci, so this cannot be done easily by eye.)
Thanks again in advance for any suggestions!
Josh B.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman
Hello all,
I have a (hopefully) simple question.
If I have a data table (named x) such as this:
daylengthleavesflowering.datefruits
LD1.90055581.64353250.76668986
LD-0.9399410-1.2592968-0.60141837
LD1.0222946-0.9697459 -0.60141837
SD-0.2668132-0.9697459-0.47363322
SD
Hello R list subscribers,
I am trying to use the by command to create line-specific variance covariance
matrices (where x is the original data matrix):
by(x, x$line, function(d) {
d.clean - d[,-1]})
write.table(d.clean$line[1,1], sep = ,, file = covariances.csv, col.names =
FALSE, row.names =
Hello,
My R skills are somewhere between novice and intermediary, and I am hoping that
some of you very helpful forum members, whom I've seen work your magic on other
peoples' problems/questions, can help me here.
I have a matrix with the following format:
(i) individual plants comprising
When I try your suggestion, I get the output, e.g.,:
christina.df$gen: 309
NULL
Returned for each vector. That doesn't seem good (I associate NULL with
something being empty), but perhaps I am misinterpreting it?
- Original Message
From: Dylan Beaudette [EMAIL PROTECTED]
To: Josh B
Works for me:
x - read.csv('christina.txt')
x.list - by(x, x$gen, function(d) {
d.clean - d[,-1]
cov(d.clean, y= NULL, use= complete.obs, method=pearson)
} )
note that the output is a list, where each element corresponds to one
level of 'gen'. if you need to write each element out to a
44 matches
Mail list logo