Re: [R] split a factor into single elements

> correct example is > > > > > > mydf <- data.frame(id_station = 1234, string_data = as.factor(2024, 12, > > 1, 0, 0), rainfall_value= 55) > > > > > > In this case mydf$string_data is a factor, but of length 1 (and not 5 > > like in the initial example

Re: [R] split a factor into single elements

-help@r-project.org Subject: Re: [R] split a factor into single elements [External Email] Hi, why would this simple procedure not work? --- snip --- mydf <- data.frame(id_station = 1234, string_data = c(2024, 12, 1, 0, 0), rainfall_value= 55) mydf$string_data <- as.factor(mydf$strin

Re: [R] split a factor into single elements

s.numeric(mydf[[new_var_name]]) >  } > # remove trash > mydf <- mydf[,-4] > # Provide more useful names > colnames(mydf) <- c("id_station", "string_data", "rainfall_mm", "Year", > "Month", "Day", "hour", "mi

Re: [R] split a factor into single elements

Provide more useful names colnames(mydf) <- c("id_station", "string_data", "rainfall_mm", "Year", "Month", "Day", "hour", "minute") Regards, Tim -Original Message- From: R-help On Behalf Of Stefano Sofia

Re: [R] split a factor into single elements

On 28/03/2024 7:48 a.m., Stefano Sofia wrote: as.factor(2024, 12, 1, 0, 0) That doesn't work. You need to put the numbers in a single vector as Fabio did, or you'll see this: Error in as.factor(2024, 12, 1, 0, 0) : unused arguments (12, 1, 0, 0) Duncan Murdoch

Re: [R] split a factor into single elements

p@R-project.org Oggetto: Re: [R] split a factor into single elements Non si ricevono spesso messaggi di posta elettronica da dagostinof...@gmail.com. Informazioni sul perch� � importante<https://aka.ms/LearnAboutSenderIdentification> Hi Stefano, maybe something like this can help you? myfactor <

Re: [R] split a factor into single elements

-mail: stefano.so...@regione.marche.it ---Oo-oO Da: Fabio D'Agostino Inviato: gioved� 28 marzo 2024 12:20 A: Stefano Sofia; r-help@R-project.org Oggetto: Re: [R] split a factor into single elements Non si ricevono

Re: [R] split a factor into single elements

Hi Stefano, maybe something like this can help you? myfactor <- as.factor(c(2024, 2, 1, 0, 0)) # Convert factor values to integers first_element <- as.integer(as.character(myfactor)[1]) second_element <- as.integer(as.character(myfactor)[2]) third_element <- as.integer(as.character(myfactor)[3])

[R] split a factor into single elements

Dear R-list users, forgive me for this silly question, I did my best to find a solution with no success. Suppose I have a factor type like myfactor <- as.factor(2024, 2, 1, 0, 0) There are no characters (and therefore strsplit for eample does not work). I need to store separately the 1st,

Re: [R] Split String in regex while Keeping Delimiter

Dear Emily, I have written a more robust version of the function: extract.nonLetters = function(x, rm.space = TRUE, normalize=TRUE, sort=TRUE) {     if(normalize) str = stringi::stri_trans_nfc(str);     ch = strsplit(str, "", fixed = TRUE);     ch = unique(unlist(ch));     if(sort) ch =

Re: [R] Split String in regex while Keeping Delimiter

Dear Emily, Using a look-behind solves the split problem in this case. (Note: Using Regex is in most/many cases the simplest solution.) str = c("leucocyten + gramnegatieve staven +++ grampositieve staven ++", "leucocyten – grampositieve coccen +") tokens = strsplit(str, "(?<=[-+])\\s++",

Re: [R] Split String in regex while Keeping Delimiter

Since any space that follows 2 or 3 + signs (or - signs) also follows a single + (or -), this can be done with positive look behind, which may be a little simpler: x <- c( 'leucocyten + gramnegatieve staven +++ grampositieve staven ++', 'leucocyten - grampositieve coccen +' ) strsplit(x,

Re: [R] Split String in regex while Keeping Delimiter

I always find regex puzzles amusing, so after changing the unicode typo quotes and dashes to ascii, the following simple prescription, similar to those proffered by others, seems to produce what you requested with your example: x <- c("leucocyten + gramnegatieve staven +++ grampositieve staven

Re: [R] Split String in regex while Keeping Delimiter

rg Subject: Re: [R] Split String in regex while Keeping Delimiter I thought replacing the spaces following instances of +++,++,+,- with "\n" and then reading with scan should succeed. Like Ivan Krylov I was fairly sure that you meant the minus sign to be "-" rather than "

Re: [R] Split String in regex while Keeping Delimiter

I thought replacing the spaces following instances of +++,++,+,- with "\n" and then reading with scan should succeed. Like Ivan Krylov I was fairly sure that you meant the minus sign to be "-" rather than "–", but perhaps your were using MS Word as an editor which is inconsistent with effective

Re: [R] Split String in regex while Keeping Delimiter

On Wed, 12 Apr 2023 08:29:50 + Emily Bakker wrote: > Some example data: > “leucocyten + gramnegatieve staven +++ grampositieve staven ++” > “leucocyten – grampositieve coccen +” >   > I want to split the strings such that I get the following result: > c(“leucocyten +”,  “gramnegatieve staven

Re: [R] Split String in regex while Keeping Delimiter

This seems to do the job but there are probably more elegant solutions: f <- function(s) { sub("^ ","",unlist(strsplit(gsub("\\+ ","+@ ",s),"@"))) } g <- function(s) { sub("^ ","",unlist(strsplit(gsub("- ","-@ ",s),"@"))) } h <- function(s) { g(f(s)) } To try it out: s <- “leucocyten +

[R] Split String in regex while Keeping Delimiter

Hello List,   I have a dataset consisting of strings that I want to split while saving the delimiter.   Some example data: “leucocyten + gramnegatieve staven +++ grampositieve staven ++” “leucocyten – grampositieve coccen +”   I want to split the strings such that I get the following result:

Re: [R] split apply on multiple variables

-project.org > Subject: [R] split apply on multiple variables > > > I am looking for a more general solution to below exercise. > > Thanks, > Naresh > > library(plyr) > mydf <- data.frame( > date = rep(seq.Date(from = as.Date("2022-06-01"), by = 1, leng

Re: [R] Split plot panel into rows with different columns

Yes, you are right, it works fine when plotting on file. Thank you! On Thu, Oct 21, 2021 at 11:42 PM Bert Gunter wrote: > > The syntax is correct; the default margins are too large for your device. > > For example, using your split screen specs on the RStudioGD > > > split.screen(c(3, 1))

Re: [R] Split plot panel into rows with different columns

Hi Luigi, Bert has identified the problem. If the ordinates in each row are the same, you can save quite a bit of space by setting the left and right margins to zero on all but the left plots in each row. This will jam the plots together at the sides, but that may not matter to you. Remember that

Re: [R] Split plot panel into rows with different columns

The syntax is correct; the default margins are too large for your device. For example, using your split screen specs on the RStudioGD > split.screen(c(3, 1)) # split display into 3 screens [1] 1 2 3 > > split.screen(c(1, 2), screen = 2) # split second screen into two columns [1] 4 5 > >

[R] Split plot panel into rows with different columns

Hello, I would like to draw 5 figures in the same plot. The layout is: first row: 1 column second row: 2 columns third row: 2 columns I have used split.screen: ``` > split.screen(c(3, 1)) # split display into 3 screens [1] 1 2 3 > split.screen(c(1, 2), screen = 2) # split second screen

Re: [R] split element vector

Perfect! thank you On Fri, Aug 6, 2021 at 4:17 PM Bill Dunlap wrote: > > unlist(strsplit(vect, "\n")) > > On Fri, Aug 6, 2021 at 7:13 AM Luigi Marongiu > wrote: >> >> Hello, >> I have a vector that contains some elements with concatenated values, such >> as: >> ``` >> > vect >> [1] "name_1"

Re: [R] split element vector

unlist(strsplit(vect, "\n")) On Fri, Aug 6, 2021 at 7:13 AM Luigi Marongiu wrote: > Hello, > I have a vector that contains some elements with concatenated values, such > as: > ``` > > vect > [1] "name_1" > [2] "name_2" > [3] "name_3\nsurname_3" > [4] "some other text\netc" > ``` > How can I

[R] split element vector

Hello, I have a vector that contains some elements with concatenated values, such as: ``` > vect [1] "name_1" [2] "name_2" [3] "name_3\nsurname_3" [4] "some other text\netc" ``` How can I create a new vector where each component is an element, such as: ``` > vect [1] "name_1" [2] "name_2" [3]

Re: [R] Split Dataframe into several

On 2021-03-08 17:14 +0330, javad bayat wrote: > Dear Rasmus; > Many thanks. It works for me. > Sincerely yours Great :) signature.asc Description: PGP signature __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see

Re: [R] Split Dataframe into several

Dear Javad, data <- "Date Cases Country 2020-12-14 746 Country1 2020-12-15 324 Country1 2020-12-15 1 Country3 2020-12-13 298 Country2" data <- read.table(text=data, header=T) x <- reshape( data=data, timevar =

[R] Split Dataframe into several

Dear R users; Hi. I have a problem with splitting dataframe into several. I have a large dataframe (Length of 61000). It has 4 Columns as below: " Date Cases Country 12020-12-14 746Country1 22020-12-15 324

Re: [R] Split

Thank you again for your help and giving me the opportunity to choose the efficient method. For a small data set there is no discernable difference between the different approaches. I will carry out a comparison using the large data set. On Wed, Sep 23, 2020 at 11:52 AM LMH wrote: > > Below

Re: [R] Split

Below is a script in bash the uses the awk tokenizer to do the work. This assumes that your input and output delimiter is space. The number of consecutive delimiters in the input is not important. This also assumes that the input file does not have a header row. That is easy to modify if you

Re: [R] Split

What is the delimiter is in the input data? Is it tab, space, etc? Is this going to be the same for the output data that you will use for R input? LMH Val wrote: > Thank you all for the help! > > LMH, Yes I would like to see the alternative. I am using this for a > large data set and if the

Re: [R] Split

Hello, If speed is important, and following the previous discussion and Bert's tests, here are two other alternatives, both faster. 1. Bert2 is Bert's original but with scan(., sep = "_") substituted for unlist/strsplit. 2. A package data.table solution. These are always fast, many times the

Re: [R] Split

That was still slower and doesn't quite give what was requested: > cbind(F1,utils::strcapture("([^_]*)_(.*)", F1$text, proto=data.frame(Before_=character(), After_=character( ID1 ID2 text Before_ After_ 1 A1 B1 NONE 2 A1 B1 cf_12 cf 12 3 A1 B1 NONE 4 A2 B2

Re: [R] Split

Another way to make columns out of the stuff before and after the underscore, with NAs if there is no underscore, is utils::strcapture("([^_]*)_(.*)", F1$text, proto=data.frame(Before_=character(), After_=character())) -Bill On Tue, Sep 22, 2020 at 4:25 PM Bert Gunter wrote: > To be clear, I

Re: [R] Split

Oh, if efficiency is a consideration, then my code is about 15 times as fast as Rui's: > F2 <- F1[rep(1:5,1e6),] ## 5 million rows ##Rui's > system.time({ + F2$Y1 <- +grepl("_", F2$text) + tmp <- strsplit(as.character(F2$text), "_") + tmp <- lapply(tmp, function(x) if(length(x) == 1)

Re: [R] Split

Thank you all for the help! LMH, Yes I would like to see the alternative. I am using this for a large data set and if the alternative is more efficient than this then I would be happy. On Tue, Sep 22, 2020 at 6:25 PM Bert Gunter wrote: > > To be clear, I think Rui's solution is perfectly fine

Re: [R] Split

To be clear, I think Rui's solution is perfectly fine and probably better than what I offer below. But just for fun, I wanted to do it without the lapply(). Here is one way. I think my comments suffice to explain. > ## which are the non "_" indices? > wh <- grep("_",F1$text, fixed = TRUE,

Re: [R] Split

Sometimes it just makes more sense to pre-process your data and get it into the format you need. It just depends on whether you are more comfortable programing in R or in some other text manipulation language like bash/sed/awk/grep etc. If you know how to do this with other tools, you could

Re: [R] Split

Hello, A base R solution with strsplit, like in your code. F1$Y1 <- +grepl("_", F1$text) tmp <- strsplit(as.character(F1$text), "_") tmp <- lapply(tmp, function(x) if(length(x) == 1) c(x, ".") else x) tmp <- do.call(rbind, tmp) colnames(tmp) <- c("X1", "X2") F1 <- cbind(F1[-3], tmp)#

Re: [R] Split

Hello, Something like this? F1$Y1 <- +grepl("_", F1$text) F1 <- F1[c(1, 2, 4, 3)] F1 <- tidyr::separate(F1, text, into = c("X1", "X2"), sep = "_", fill = "right") F1 Hope this helps, Rui Barradas Às 19:55 de 22/09/20, Val escreveu: HI All, I am trying to create new columns based on

[R] Split

HI All, I am trying to create new columns based on another column string content. First I want to identify rows that contain a particular string. If it contains, I want to split the string and create two variables. Here is my sample of data. F1<-read.table(text="ID1 ID2 text A1 B1 NONE A1

[R] Split

Dear Burt, you gave a very elegant solution. Many thanks! Jeff, I understand your solution, thank you very much for your time! Colleague Milos, patronage is exactly what I need. I hope for your further guidance! (Rcmdr is not enough for some purposes.) Dear Ivan, I used your solution! It's the

Re: [R] Split

J have just seen your follow-up post (out of tread). I don’t want to be rude or patronizing but few caveats. Neither R nor R help are meant to be user friendly. Learning curve is steep but very rewarding at the end. Problem you have can be solved in a literary hundred ways. Unfortunately, your

Re: [R] Split

Do you mean IQR? -- I don't know what ICR means. If so, see IQR. More generally see ?by or more generally ?tapply to obtain whatever sort of summary you want. e.g. > d <-data.frame( x = runif(10), w = rep(c("a","b"),5)) > by(d$x, d$w, FUN = function(x)c(median = median(x),IQR = IQR(x))) d$w: a

Re: [R] Split

If I understand correctly you need summary by group. I would suggest arsenal package and tableby tab1 <- tableby(group ~ anova(var, "meansd", digits=1) + #mean and sd + round to 1 digit + anova kwt(var, "medianq1q3", digits=1) , #median q1 and q3 + round to 1 digit +

Re: [R] Split

On Mon, 23 Dec 2019 17:56:35 +0300 Medic wrote: > I would like to split > mydata$var > by > mydata$group #to get var1 and var2 There is the split() function that does exactly that (except it returns a list instead of multiple variables)... > And then get > summary (var1, var2) #this is my

[R] Split

I have mydata$var #this is ONE group of patients And I would like to get median and ICR of mydata$var. How can I get this? With summary (mydata$var)! Ok! And now I would like to get THE SAME, but for TWO group: male and female (which are contained in the group mydata$var) How can I get this?

Re: [R] Split

Not clear what you mean by summary (var1, var2) ? That is not a legal way to call summary. Perhaps mt <- mtcars[,c("cyl","hp")] mt$cyl <- factor( mt$cyl ) mtl <- split(mt[,"hp",drop=FALSE], mt$cyl) lapply(mtl,summary) On December 23, 2019 6:56:35 AM PST, Medic wrote: >I have >mydata$var >

Re: [R] Split

?ave Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Mon, Dec 23, 2019 at 6:57 AM Medic wrote: > I have > mydata$var > > and I have > mydata$group #two group

[R] Split

I have mydata$var and I have mydata$group #two group I would like to split mydata$var by mydata$group #to get var1 and var2 And then get summary (var1, var2) #this is my finite aim How to encode it all? __ R-help@r-project.org mailing list -- To

Re: [R] Split a DF on Date column for each single year

Thank you Jeff and Rainer. I will try Jeff's idea using the sub string. function to extract the year and split on that. Thanks again to both--EK On Sat, Mar 16, 2019 at 1:52 AM Jeff Newmiller wrote: > > Couldn't you just use the substr function to pull the year out yourself to > make the

Re: [R] Split a DF on Date column for each single year

In your sample data.frame, MyDate and MyDes are factors; is that what you want? rs On Samstag, 16. März 2019 01:40:01 CET Ek Esawi wrote: > Hi All— > > I have a data frame with over 13000 rows and 4 columns. A mini data > frame is given at the bottom. I want to split the data frame into > lists

Re: [R] Split a DF on Date column for each single year

Couldn't you just use the substr function to pull the year out yourself to make the grouping column? On March 15, 2019 10:40:01 PM PDT, Ek Esawi wrote: >Hi All— > >I have a data frame with over 13000 rows and 4 columns. A mini data >frame is given at the bottom. I want to split the data frame

[R] Split a DF on Date column for each single year

Hi All— I have a data frame with over 13000 rows and 4 columns. A mini data frame is given at the bottom. I want to split the data frame into lists each corresponds to single year which ranges from 1990 to 2018). I wanted to use the split function, but it requires a vector of the same length as

Re: [R] Split a data.frame

Hi! How about this: --- snip -- for (i in 1:(length(split_str)-1)) { assign(paste("DF",i,sep=""),DF[ c((which(DF$name==split_str[i])+1):(which(DF$name==split_str[i+1])-1)), ]) } --- snip --- 'assign' creates for each subset a new data.frame DFn, where n ist a count (1,2,...). But note:

Re: [R] Split a data.frame

Forgot to take care of the boundary conditions: # revised data.frame to take care of boundary conditions DF = data.frame(name = c('b', 'a','v','z', 'c','d'), val = 0); DF ## name val ## 1b 0 ## 2a 0 ## 3v 0 ## 4z 0 ## 5c 0 ## 6d 0 split_str = c('a', 'c') #

Re: [R] Split a data.frame

... yes, but note that: which(data[[col]] %in% s can be replaced directly by match: match(data[[col]], s) Corner cases (nothing matches, etc.) would also have to be checked and probably should sort the matched row numbers for safety. Cheers, Bert Bert Gunter "The trouble with having an open

Re: [R] Split a data.frame

DF = data.frame(name = c('a', 'v', 'c'), val = 0); DF ## name val ## 1a 0 ## 2v 0 ## 3c 0 split_str = c('a', 'c') # If we assume that the values in split_str are ordered in the same order as in the dataframe, then this might work. offsets <- match(split_str, DF$name) # Since

Re: [R] Split a data.frame

Hello, Maybe something like the following. splitDF <- function(data, col, s){ n <- nrow(data) inx <- which(data[[col]] %in% s) lapply(seq_along(inx), function(i){ k <- if(inx[i] < n) (inx[i] + 1):(inx[i + 1]) data[k, ] }) } splitDF(DF, "name", split_str) Hope

[R] Split a data.frame

Hi, I am struggling to split a data.frame as will below scheme : DF = data.frame(name = c('a', 'v', 'c'), val = 0); DF split_str = c('a', 'c') Now, for each element in split_str, R should find which row of DF contains that element, and return DF with all rows starting from next row of the

Re: [R] Split charts with ggplot2, tidyquant

Hi Charlie and Bert, Thank you both for the suggestions and pointers. I will look into them. FYI I repeatedly refer to tidyquant because that package refers to itself as "tidyquant: Tidy Quantitative Financial Analysis" and I am hoping to get the attention of someone who is involved in the

Re: [R] Split charts with ggplot2, tidyquant

Thanks for the reminder about lattice! I did some searching and there's a good example of manipulating the size of subplots using the `position` argument (see pp. 202-203 in the Trellis Users Guide: http://ml.stat.purdue.edu/stat695t/writings/Trellis.User.pdf). This is not within the paneling

Re: [R] Split charts with ggplot2, tidyquant

That (the need for base graphics) is false. It certainly **can** be done in base graphics -- see ?layout for a perhaps more straightforward way to do it along the lines you suggest. However both lattice and ggplot are based on grid graphics, which has a similar but slightly more flexible

Re: [R] Split charts with ggplot2, tidyquant

For this kind of control you will probably need to move to base graphics and utilize the `fig` argument in par(), in which case you would want to run the plot() command twice: once with your first outcome and once with your second, changing the par() settings before each one to control the

Re: [R] Split charts with ggplot2, tidyquant

Hi Charlie, Thanks. This is helpful. As mentioned in my original question, I want to be able to plot a few such charts on the same page, say a 2 x 2 grid with such a chart for each of 4 different stocks. Using your solution I accomplished this by making a list pLst of your ggplots and then calling

Re: [R] Split charts with ggplot2, tidyquant

So the general strategy for getting these into separate panels in ggplot is to have a single variable that will be your response and a factor variable that indexes which original variable it came from. This can be accomplished in many ways, but the way I use is with the melt() function in the

Re: [R] Split charts with ggplot2, tidyquant

If you don't want to wait for a ggplot2 solution, here are two alternatives you can use right now: chartSeries(SPYxts) # or (with xts > 0.10 plot(SPYxts$SPY.Close) addSeries(SPYxts$SPY.Volume, type = "h") You might also try autoplot.zoo(), though I've never used it. On Thu, Jan 18, 2018 at

Re: [R] Split charts with ggplot2, tidyquant

Hi Charlie, I am comfortable to put the data in any way that works best. Here are two possibilities: an xts and a data frame. library(quantmod) quantmod::getSymbols("SPY") # creates xts variable SPY SPYxts <- SPY[,c("SPY.Close","SPY.Volume")] SPYdf <-

Re: [R] Split charts with ggplot2, tidyquant

Could you provide some information on your data structure (e.g., are the two time series in separate columns in the data)? The solution is fairly straightforward once you have the data in the right structure. And I do not think tidyquant is necessary for what you want. Best, Charlie --

[R] Split charts with ggplot2, tidyquant

A very common chart in the financial markets is a split chart with two time series shown in two vertically stacked sub-charts. A classic case would be the top panel showing the time series of historical prices of some stock, and the bottom panel showing the volume traded per day immediately below

Re: [R] Split strings based on multiple patterns

Thanks for the additional approach, Greg. I had success with Gabor's recommendation but will take a look at gsubfn as well. Joe On Wed, Oct 19, 2016 at 10:19 AM, Greg Snow <538...@gmail.com> wrote: > I would suggest looking at the strapply function in the gsubfn > package. That gives you more

Re: [R] Split strings based on multiple patterns

I would suggest looking at the strapply function in the gsubfn package. That gives you more flexibility in specifying what to look for in the structure of the data, then extract only those pieces that you want. On Fri, Oct 14, 2016 at 5:16 PM, Joe Ceradini wrote: >

Re: [R] Split strings based on multiple patterns (plain text)

Thank you David Wolfskill, David Winsemius, and Gabor! All very helpful and interesting fixes for the problem (compiled below)! Now I will see which one works best on the 944 rows that each have a cell of smooshed attributes...the attribute names should be the same in all the rows, if there is any

Re: [R] Split strings based on multiple patterns

Replace newlines and colons with a space since they seem to be junk, generate a pattern to replace the attributes with a comma and do the replacement and finally read in what is left into a data frame using the attributes as column names. (I have indented each line of code below by 2 spaces so if

Re: [R] Split strings based on multiple patterns (plain text)

> On Oct 14, 2016, at 6:53 PM, Joe Ceradini wrote: > > Hopefully this looks better. I did not realize gmail default was html. > > I have a dataframe with a column that has many field smashed together. > I need to split the strings in the column into separate columns

Re: [R] Split strings based on multiple patterns (plain text)

should be strsplit(ugly, attributes) not strplit(ugly, attributes) On Fri, Oct 14, 2016 at 7:53 PM, Joe Ceradini wrote: > Hopefully this looks better. I did not realize gmail default was html. > > I have a dataframe with a column that has many field smashed together. >

[R] Split strings based on multiple patterns (plain text)

Hopefully this looks better. I did not realize gmail default was html. I have a dataframe with a column that has many field smashed together. I need to split the strings in the column into separate columns based on patterns. Example of a string that needs to be split: ugly <- c("Water temp:14:

Re: [R] Split strings based on multiple patterns

> On Oct 14, 2016, at 4:16 PM, Joe Ceradini wrote: > > Afternoon, > > I unfortunately inherited a dataframe with a column that has many fields > smashed together. My goal is to split the strings in the column into > separate columns based on patterns. > > Example of

[R] Split strings based on multiple patterns

Afternoon, I unfortunately inherited a dataframe with a column that has many fields smashed together. My goal is to split the strings in the column into separate columns based on patterns. Example of what I'm working with: ugly <- c("Water temp:14: F Waterbody type:Permanent Lake/Pond: Water

Re: [R] 'split-lapply' vs. 'aggregate'

fox From: R-help [r-help-boun...@r-project.org] on behalf of Massimo Bressan [massimo.bres...@arpa.veneto.it] Sent: March 27, 2016 5:45 PM To: r-help@r-project.org Subject: [R] 'split-lapply' vs. 'aggregate' this might be a trivial question (eventually sorry for that!) but I definit

[R] 'split-lapply' vs. 'aggregate'

this might be a trivial question (eventually sorry for that!) but I definitely can not catch the problem here... please consider the following reproducible example: why of different results through 'split-lapply' vs. 'aggregate'? I've been also through a check against different methods (e.g.

Re: [R] Split a character string with two separators

or strsplit? test <-"k0298_7832_8964" # Split and remove letters test <- unlist(strsplit(test, "\\_")) test <- gsub("[a-z]", "", test[1]) # Split on letters and underscore test <-"k0298_7832_8964" test <- unlist(strsplit(test, "[a-z]|\\_")) test[2] On Thu, 18 Feb 2016 at 18:43 Ben Tupper

Re: [R] Split a character string with two separators

Hi, Will substring work for you? ?substring Cheers, Ben > On Feb 18, 2016, at 12:36 PM, Marine Regis wrote: > > Hello, > >> From this character string: > > test <-"k0298_7832_8964" > > how can I obtain: > > [[1]] > > "0298" > > Thank you very much for your

[R] Split a character string with two separators

Hello, >From this character string: test <-"k0298_7832_8964" how can I obtain: [[1]] "0298" Thank you very much for your help. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see

Re: [R] Split Strings

Hi Miluji, While the other answers are correct in general, I noticed that your request was for the elements of an incomplete string to be placed in the same positions as in the complete strings. Perhaps this will help: strings<-list("pc_m2_45_ssp3_wheat","pc_m2_45_ssp3_wheat",

Re: [R] Split Strings

Thank you everyone for the codes and the link. They work well! Mr. Lemon, thank you for the detailed code and the explanations. I appreciate it. One thing though, in the last line sapply(split_strings,fill_strings,list(max_length,element_sets)) should it be unlist instead of list - I get this

Re: [R] Split Strings

Try this: mylist <- list("pc_m2_45_ssp3_wheat", "pc_m2_45_ssp3_wheat", "ssp3_maize", "m2_wheat") mylist <- lapply(mylist, function(x) unlist(strsplit(x, split="_"))) allstrings <- unique(unlist(mylist)) lapply(mylist, function(x) allstrings[match(allstrings, x)]) [[1]] [1] "pc""m2""45"

[R] Split Strings

I have a list of strings of different lengths and would like to split each string by underscore "_" pc_m2_45_ssp3_wheat pc_m2_45_ssp3_wheat ssp3_maize m2_wheat I would like to separate each part of the string into different columns such as pc m2 45 ssp3 wheat But because of the different

Re: [R] Split Strings

> str_1 <- list("pc_m2_45_ssp3_wheat", "pc_m2_45_ssp3_wheat", "ssp3_maize", > "m2_wheat") > str_2 <- strsplit(unlist(str_1), "_") > max.length <- max(sapply(str_2,length)) > str_3 <- lapply(lapply(str_2, unlist), "length<-", max.length) > str_3 See:

[R] "split" and loop functions

Hello, I wonder if you might be able to help me. I'm enrolled in an R programming course through Coursera. I've done well so far--though it's been challenging!--but I'm having trouble understanding exactly how "split" and the loop functions (like "lapply") work. I keep getting an error that

Re: [R] "split" and loop functions

You should really be asking Coursera for help with its course. However you can figure this out by breaking down your commands into small steps and seeing what each step gives. This is an advantage of an interactive system like R. E.g., suppose you start with > s1 <- data.frame(state=c("Rhode

Re: [R] Split data frame into 250-row chunks

On Jun 10, 2015, at 12:18 PM, David Winsemius wrote: On Jun 10, 2015, at 5:39 AM, Liz Hare wrote: Hi R-Experts, I have a data.frame like this: head(map) chr snp poscm posbpdist 1 1 M1 2.99043 3249189 NA 2 1 M2 3.06457 3273096 0.07414 3 1 M3 3.17018 3307151

Re: [R] Split data frame into 250-row chunks

On Jun 10, 2015, at 2:21 PM, Marc Schwartz marc_schwa...@me.com wrote: On Jun 10, 2015, at 7:39 AM, Liz Hare dogg...@earthlink.net wrote: Hi R-Experts, I have a data.frame like this: head(map) chr snp poscm posbpdist 1 1 M1 2.99043 3249189 NA 2 1 M2 3.06457

Re: [R] Split data frame into 250-row chunks

On Jun 10, 2015, at 5:39 AM, Liz Hare wrote: Hi R-Experts, I have a data.frame like this: head(map) chr snp poscm posbpdist 1 1 M1 2.99043 3249189 NA 2 1 M2 3.06457 3273096 0.07414 3 1 M3 3.17018 3307151 0.10561 4 1 M4 3.20892 3319643 0.03874 5 1 M5

Re: [R] Split data frame into 250-row chunks

On Jun 10, 2015, at 7:39 AM, Liz Hare dogg...@earthlink.net wrote: Hi R-Experts, I have a data.frame like this: head(map) chr snp poscm posbpdist 1 1 M1 2.99043 3249189 NA 2 1 M2 3.06457 3273096 0.07414 3 1 M3 3.17018 3307151 0.10561 4 1 M4 3.20892 3319643

[R] Split data frame into 250-row chunks

Hi R-Experts, I have a data.frame like this: head(map) chr snp poscm posbpdist 1 1 M1 2.99043 3249189 NA 2 1 M2 3.06457 3273096 0.07414 3 1 M3 3.17018 3307151 0.10561 4 1 M4 3.20892 3319643 0.03874 5 1 M5 3.28120 3342947 0.07228 6 1 M6 3.29624 3347798 0.01504 I

Re: [R] Split a dataframe by rownames and/or colnames

Thank you very much for the line. It was doing the split as suggested. However, i want to release all the dataframes to the environment (later on, for each dataframe, some dozen lines of code will be carried out, and i dont know how to do it w lapply or for-looping, so i do it separately):

Re: [R] Split a dataframe by rownames and/or colnames

Did you try dplyr package? Sergio Il 23/feb/2015 13:05 Tim Richter-Heitmann trich...@uni-bremen.de ha scritto: Thank you very much for the line. It was doing the split as suggested. However, i want to release all the dataframes to the environment (later on, for each dataframe, some dozen lines

Re: [R] Split a dataframe by rownames and/or colnames

On Feb 23, 2015, at 4:03 AM, Tim Richter-Heitmann wrote: Thank you very much for the line. It was doing the split as suggested. However, i want to release all the dataframes to the environment (later on, for each dataframe, some dozen lines of code will be carried out, and i dont know how

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