Hi. I'd like to produce a barplot where only the lowest value and the
highest value are labelled on the x-axis. E.g. I might have a list
of numbers and frequencies:
barplot( c( 2, 2, 0, 4, 2 ), names.arg=c( 1, 2, 3, 4, 5 ) )
where the data is a set of counts for some values between 1 and 5.
Liaw, Andy [EMAIL PROTECTED] writes:
But I'm not happy with it because it is not really efficient. Any
other suggestions are welcome!
Anything wrong with x[y,] ???
Well... sometimes:
nm - as.character(sample(1:1e5))
x - data.frame(x1=rnorm(1e5), row.names=1:1e5)
John Fox wrote:
Dear Doug,
I assume that in the absence of a suitable anova() method, there's nothing
wrong with testing the difference between two GLMM objects nested in their
random effects by manually comparing the log-likelihoods as printed or
returned by logLik(). Is that correct?
Regards,
Sir:
Is it possible to stop sending me email till January 12,2005.
I will be away from my workplace.
Partha
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PLEASE do read the posting guide!
On Sat, 2004-11-27 at 08:59 +, Ross Clement wrote:
Hi. I'd like to produce a barplot where only the lowest value and the
highest value are labelled on the x-axis. E.g. I might have a list
of numbers and frequencies:
barplot( c( 2, 2, 0, 4, 2 ), names.arg=c( 1, 2, 3, 4, 5 ) )
where
Anthony Westerling wrote:
Yes. It is looking the correct directory. Note that the package is
installed without errors. The problem is that, even after being newly
reinstalled, it is still not recognized as a valid package for R-2.0
Tony
On Nov 26, 2004, at 9:08 PM, Liaw, Andy wrote:
Have
Huuh ???
Partha == [EMAIL PROTECTED]
on Sat, 27 Nov 2004 09:44:41 -0500 writes:
Partha Sir: Is it possible to stop sending me email till
Partha January 12,2005. I will be away from my workplace.
Partha Partha
What did you think when sending this to the 2500 readers of
Andrew Kniss wrote:
I am attempting to write an R function to aid in time series diagnostics.
The tsdiag() works well, but I would prefer to get a plot with ACF, PACF,
and Ljung-Box p-values of residuals. In my attempt to get to that point, I
am writing a function to calculate Ljung-Box p-values
Stefaan Lhermitte wrote:
Dear R-ians,
I have a question concerning plotting different plots on one figure. I
have written a script to plot an image, a legend (based on different
rectangles) and a timeseries plot on one figure.
In my R-lagnuage it looks like this (without arguments that are not
Christian Schulz wrote:
Hi,
i have list with 2575 cgi files which i have read with readLines - all
Lines have the type chr.
Now i want replace the 2. line with a condition in 4. line and write
the files back to dir.
How i could avoid the incompatible problem, or is it better
doing something
From: Uwe Ligges
Andrew Kniss wrote:
I am attempting to write an R function to aid in time
series diagnostics.
The tsdiag() works well, but I would prefer to get a plot
with ACF, PACF,
and Ljung-Box p-values of residuals. In my attempt to get
to that point, I
am writing a
I used pause() from library(DAAG) to pasue between plots. This works
when I source a script, but seems don't work when I run (ctrl + R) the
script in R.
Did I do something wrong? Thanks.
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Thanks to Tom and Andy for pointing this out and chasing it down. I tried
replacing | by %7C and that seems to fix the problem (at least on a
somewhat outdated release of Firefox). Please let me know if the following
works.
With regard to Gabor's comment: I'd guess R-core would be reluctant to
In appropriate yes, but at least responders will not be getting as many
out of office replies. I am replying for future reference.
Go to https://stat.ethz.ch/mailman/listinfo/r-help and enter your email
address on the unsubscribe or edit options button (the last textbox).
You can also get the
On Sat, 2004-11-27 at 11:42 -0500, Terry Mu wrote:
I used pause() from library(DAAG) to pasue between plots. This works
when I source a script, but seems don't work when I run (ctrl + R) the
script in R.
Did I do something wrong? Thanks.
The standard way to pause between plots is to set
Thank you Uwe
That was indeed the problem. I revised the depends line and removed
the old built line, and then rebuilt the package. Now it is recognized
as valid.
Thanks
Tony
On Nov 27, 2004, at 7:54 AM, Uwe Ligges wrote:
Anthony Westerling wrote:
Yes. It is looking the correct directory.
Hi,
I've been using large datasets (GB) and I've stored them in MySQL
databases and use RMySQL to access them. My feeling is that most of the
times you don't need to keep the dataset in your workspace, but you need
to access parts of it or aggregate it in some way, before run some
analysis. So
Dear Martin,
As it turns out, the test that I proposed (i.e., testing for NULL slotNames)
sometimes fails. For example:
library(car)
data(Prestige)
sum - summary(lm(prestige ~ income + education, data=Prestige))
slotNames(sum)
character(0)
The following, however, seems to work (at least as
Does anybody have an R program to generate row-column designs and to produce
the incidence matrices? I would appreciate if you could share it with me! Thank
you!
Harvey.
-
[[alternative HTML version deleted]]
Thank you.
I am using R 2.0.0 under Windows 2000.
I've tried
1. par(ask=T)
2. readline(prompt = Pause. Press Enter to continue...)
1. script:
x - 0:20
y - 5:25
plot(y)
plot(x)
plot(y~x)
output:
par()$ask
[1] TRUE
x - 0:20
y - 5:25
plot(y)
Hit Return to see next plot: plot(x) R does not
I used pause() from library(DAAG) to pasue between plots. This works
when I source a script, but seems don't work when I run (ctrl + R) the
script in R.
This sounds like a bug to me, but I'm not sure it's going to be an
easy one to fix.
Duncan Murdoch
Hello-
My question is a short one. How can I specify a single point which
through the fitted linear model has to go through? To illustrate my
problem, the fit to following data must go through the point
(-37.25(effect), 50(prob)). Note: you can ignore the label column.
Effect Prob
Hi list,
I have read the mannual of package graph, but it looks that three
functions randomEGraph, randomGraph and randomNodeGraph cannot generate
a random network with given cluster coefficient.
Is there any exisiting R package for such kind job and if no, how can I
perform this job with
Dear Seth,
You don't say which variable is the explanatory variable and which is the
response, but assuming that prob is to be regressed on effect, you can fit
lm(prob - 50 ~ I(effect + 37.25) - 1). That is you can shift the point
through which the regression is to go to the origin and then force
Hi list,
I have read the mannual of package graph, but it looks that three
functions randomEGraph, randomGraph and randomNodeGraph cannot generate
a random network with given cluster coefficient.
Is there any exisiting R package for such kind job and if no, how can I
perform this job with
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