> A-> Hi,> A-> Is there any parser generator like www.antlr.org? Moreover, how
> does simple > A-> code assistance work currently in R? By 'simple code
> assistance' I meant > A-> things like:> > A-> Object$M -->
> Object$Method> > If you really meant a list with components> or an S4 object
>
Hi,
Is there any parser generator like www.antlr.org? Moreover, how does simple
code assistance work currently in R? By 'simple code assistance' I meant
things like:
Object$M --> Object$Method
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Hi Sir
I am very new user of R for the research project on multilevel logistic
regression.
There is confusion about bugs() function in R and BUGS software. Is there any
relation between these two? Is there any comprehensive package for Multilevel
Logistic modelling in R?
Please gu
Hi,
This question seems to be old, however I am asking it from a different point
of view.
R introduces itself as a 'statistical' language and environment. There are
many discussions about comparing R to MATLAB or mathematica (or other
similar software). It seems to me that these other softwa
Hi,
when using the script file for cokriging, is there any way to fit cross
variogram other than linear, I mean what other options can I put in place
of "fit.lmc"
I ll be very appreciated if somebody who know the answer can response to me
thanks
_
>> Do you know why additional graphical parameters (like "type","pch", ...)
>> do not work in the R contour fonction. For example the command
>> 'contour(..., type="o",pch=16)' gives nothing, just simple contour lines.
>
> Please, can you explain why you think it does make sense here?
>
The reas
Hello,
Do you know why additional graphical parameters (like "type","pch", ...) do not
work in the R contour fonction. For example the command 'contour(...,
type="o",pch=16)' gives nothing, just simple contour lines.
Thank you for your response.
Abdou.
[[alternative HTML version deleted
> >
> > Here is an example. Note that $ does not evaluate y so you have
> >to do it yourself:
> >
> >x <- structure(3, class = "myclass")
> >y <- 5
> >foo <- function(x,y) x+y
> >"$.myclass" <- function(x, i) { i <- eval.parent(parse(text=i)); foo(x,
> i)
> >}
> >x$y # structure(8, class = "myclas
This could be really trivial, but I cannot find the right function to get
the name of an object as a character.
Assume we have a function like:
getName <- function(obj)
Now if we call the function like:
getName(blabla)
and 'blabla' is not a defined object, I want getName to return "blabla". In
o
>
> Assume we have a function like:
>
> foo <- function(x, y)
>
> how is it possible to define a binary indexing operator, denoted by $,
so
> that
>
> x$y
>
> functions the same as
>
> foo(x, y)
Here is an example. Note that $ does not evaluate y so you have
to do it yourself:
x <- structure(3
Assume we have a function like:
foo <- function(x, y)
how is it possible to define a binary indexing operator, denoted by $, so
that
x$y
functions the same as
foo(x, y)
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probabilties (i.e. P(X in Quantile i | Y in Quantile i)) , and etc.
Many thanks in advance for any help.
Best,
Ali
library("quantreg")
#help.start()
Data <- read.table("RESvsMOVE2.dat")
#
x <- Data[,2]
y <- Data[,1]
par(mfrow=c(2,2))
qqnorm(x,main="MOVE Norm Q-Q Plot"
Hello,
Is there R command to solve a nonlinear numerical equation.
Thank you.
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Hello,
how can I fill map contour with R without setting the legend. I cannot see an
option to skip the legend for filled.contour.
Thank for your response.
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PLEASE do
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