On Mon, 2006-10-09 at 10:56 -0400, Mike Wolfgang wrote:
Hi list,
I want to add some lines at margin area of one figure. mtext could add text
to these margins, can I add lines with different lty parameters? Thanks,
mike
You can do it, but it will take some fiddling to get the coordinates
On Mon, 2006-10-09 at 17:15 +0200, Yen Ngo wrote:
Hi all R-helpers,
i am a new R-user and have problem with deleting some components in a
column. I have a dataset like
Name Idx
empty 2
empty 3
anone2
bnone3
d
On Mon, 2006-10-09 at 15:43 +, Gregor Gorjanc wrote:
Dieter Menne dieter.menne at menne-biomed.de writes:
Dear friends of lmer,
http://wiki.r-project.org/rwiki/doku.php?id=guides:lmer-tests
I have put a transcript of the long thread on lmer/lme4 statistical test
into the
On Fri, 2006-10-06 at 17:05 +0100, Mike Ford wrote:
When I do lmer models I only get Estimate, Standard Error and t value in
the output for the fixed effects.
Is there a way I get degrees of freedom and p values as well?
I'm a very new to R, so sorry if this a stupid question.
Thank
On Fri, 2006-10-06 at 14:46 -0400, Martin C. Martin wrote:
Hi,
In the Linux (FC3) version of R, ctrl-\ quits R. This wouldn't be so
bad, but on my keyboard, it's right next to ctrl-p and I tend to hit it
by accident.
Is there any way to turn that off?
Open your favorite terminal
On Fri, 2006-10-06 at 16:15 -0400, Eric Harley wrote:
Hi all,
Is there a way to fill a rectangle or polygon with a color and/or
transparency gradient? This would be extremely useful for me in terms
of adding some additional information to some plots I'm making,
especially if I could define
On Tue, 2006-10-03 at 17:03 -0400, Duncan Murdoch wrote:
On 10/3/2006 4:59 PM, roger bos wrote:
Dear useRs,
Trying to replace the diagonal of a matrix is not working for me. I
want a matrix with .6 on the diag and .4 elsewhere. The following
code looks like it should work--when I
(or regression) line which is not sharp like what I
have now. I tried to write density in the code but it tells Error in
xy.coords(x, y) : 'x' and 'y' lengths differ
I appreciate any comment about these questions
Thanks,
Mohsen
On 10/2/06, Marc Schwartz (via MN) [EMAIL PROTECTED] wrote
On Mon, 2006-10-02 at 11:14 -0400, Mohsen Jafarikia wrote:
Hello,
I have used the following data to draw my barplot:
BL LRQ
36.351.00 1.92
36.914.00 0.00
25.706.00 0.00
34.383.00 1.92
05.320.50 0.00
BL-c(36.35, 36.91, 25.70, 34.38, 05.32)
On Mon, 2006-10-02 at 14:58 -0400, Ravi Varadhan wrote:
Hi,
I had sent this email last week, but received no reply. So, I am resending
it - please excuse me for the redundant email.
I have a simple problem that I would appreciate getting some tips. I am
using the truehist
On Fri, 2006-09-29 at 16:13 -0400, bertrand toupin wrote:
Hi! 1st time I'm posting here. I'm beginning to learn R and I've
encountered a problem that I'm unable to solve so far.
I have a 20 000 x 5 matrix. In the 5th column, I have elevation.
Missing value are actually put to -9. I
On Thu, 2006-09-28 at 12:27 +1000, [EMAIL PROTECTED] wrote:
I am hoping for some advice regarding the difficulties I have been having
recoding variables which are contained in a csv file. Table 1 (below)
shows there are two types of blanks - as reported in the first two
columns. I am using
On Thu, 2006-09-28 at 21:49 +0200, Ulrich Keller wrote:
Hello,
and sorry if this is already explained somewhere. I couldn't find anything.
R (2.3.1, Windows) seems to perform some kind of lazy evaluation when
evaluating defaults in function calls that, at least for me, leads to
On Thu, 2006-09-28 at 23:55 +0800, zhijie zhang wrote:
Dear friends,
I met a problem on plotting.
My dataset is :
yearMHBC LHBC MHRC LURC
1993 11.75 4.50 0.43 0.46
19947.25 1.25 0.35 0.51
19958.67 2.17 0.54 0.44
1996 2.67 1.33 0.78 0.47
1997 3.42
On Thu, 2006-09-28 at 12:31 -0700, BBands wrote:
Hello,
For numbers in the range 100 to 100,000,000 I'd like to decimal align
a right-justified comma-delineated column of numbers, but I haven't
been able to work out the proper format statement. format(num,
justify=right, width=15,
On Mon, 2006-09-25 at 11:30 -0500, Marc Schwartz (via MN) wrote:
On Mon, 2006-09-25 at 11:04 -0500, Frank Duan wrote:
Hi All,
I have a data with a variable like this:
Column 1
123abc
12cd34
1e23
...
Now I want to do an operation that can split it into two variables
On Mon, 2006-09-25 at 11:04 -0500, Frank Duan wrote:
Hi All,
I have a data with a variable like this:
Column 1
123abc
12cd34
1e23
...
Now I want to do an operation that can split it into two variables:
Column 1Column 2 Column 3
123abc 123
On Mon, 2006-09-25 at 19:56 +0200, Lothar Botelho-Machado wrote:
Hey R-Comunity,
I'd like to print out an histogram of some experimental data and add a
smooth curve of a normal distribution with an ideally generated
population having the same mean and standard deviation like the
On Mon, 2006-09-25 at 18:58 +0200, Boks, M.P.M. wrote:
Dear R users,
This command works (calling a programm -called whap- with file specifiers
etc.):
system('cmd /c c:\\pheno\\whap --file c:\\pheno\\smri --alt 1 --perm 500',
intern=TRUE)
Now I need to call it from a loop to
On Fri, 2006-09-22 at 10:45 -0400, Mike Wolfgang wrote:
Hi list,
I want to write a general function so that it would take an lm object,
extract its data element, then use the data at another R function (eg, glm).
I searched R-help list, and found this would do the trick of the first part:
On Fri, 2006-09-22 at 20:16 +0200, Mag. Ferri Leberl wrote:
Dear everybody!
take a-c(5,3,NA,6).
if(a[1]!=NA){b-7}
if(a[3]!=5){b-7}
if(a[3]!=NA){b-7}
if(a[3]==NA){b-7}
will alltogeather return
Fehler in if (a[1] != NA) { : Fehlender Wert, wo TRUE/FALSE nötig ist
(or simularly).
On Fri, 2006-09-22 at 17:16 -0400, Philip Bermingham wrote:
I'm hoping someone can help me. I have downloaded the proj4R.zip and
under my version of R (2.3.1) I install the package from local zip
file. This worked great. I then type library(proj4R) to load the
library and I get the error:
On Wed, 2006-09-20 at 13:20 +0200, Kurt Hornik wrote:
Marc Schwartz (via MN) writes:
On Tue, 2006-09-19 at 22:16 +1000, Robert King wrote:
Here is another thing that might help work out what is happening. If I
use --no-install, ade4 actually fails as well, in the same way as zipfR
On Wed, 2006-09-20 at 17:03 +0200, Rainer M Krug wrote:
Hi
I heard so much about Emacs and ESS that I decided to try it out - but I
am stuck at the beginning.
Is there anywhere a beginners manual for Emacs ESS to be used with R?
even M-x S tells me it can't start S-Plus - obviously -
On Wed, 2006-09-20 at 09:09 +0200, Antonio, Fabio Di Narzo wrote:
Hi.
2006/9/20, Marc Schwartz [EMAIL PROTECTED]:
Hi all,
On FC5, using:
Version 2.3.1 Patched (2006-08-06 r38829)
and today's
R version 2.4.0 alpha (2006-09-19 r39397)
with the following .Rnw file:
On Wed, 2006-09-20 at 15:15 -0400, Mathieu Drapeau wrote:
I have this error when I load the library ROracle:
library(ROracle)
Loading required package: DBI
Error in dyn.load(x, as.logical(local), as.logical(now)) :
unable to load shared library
On Tue, 2006-09-19 at 22:16 +1000, Robert King wrote:
Here is another thing that might help work out what is happening. If I
use --no-install, ade4 actually fails as well, in the same way as zipfR.
[Desktop]$ R CMD check --no-install ade4
* checking for working latex ... OK
* using
On Mon, 2006-09-18 at 19:31 +0200, Iñaki Murillo Arcos wrote:
Hello,
I don't know if the result of
acos(0.5) == pi/3
is a bug or not. It looks strange to me.
Inaki Murillo
Seems reasonable to me:
acos(0.5) == pi/3
[1] FALSE
print(acos(0.5), 20)
[1] 1.0471975511965978534
Try something like this:
# Initial data frame
DF
V1 V2 V3 V4
1 A 1.0 200 ID1
2 A 3.0 800 ID1
3 A 2.0 200 ID1
4 B 0.5 20 ID2
5 B 0.9 50 ID2
6 C 5.0 70 ID1
# Now do the aggregation to get the means
DF.1 - aggregate(DF[, 2:3], list(V1 = DF$V1), mean)
DF.1
V1 V2 V3
1 A 2.0
On Tue, 2006-09-12 at 18:42 +0200, Simone Gabbriellini wrote:
Dear List,
how can I coerce a matrix like this
[,1] [,2] [,3] [,4] [,5] [,6]
[1,] 0 1 1 0 0 0
[2,] 1 0 1 0 0 0
[3,] 1 1 0 0 0 0
[4,] 0 0 0 0 1 0
[5,] 0 0 0 1 0 0
[6,] 0 0 0 0 0 0
to be
On Thu, 2006-09-07 at 12:14 -0500, Hao Chen wrote:
Hello Marc Schwartz
On Thu, Sep 07, 2006 at 07:54:05AM -0500, Marc Schwartz wrote:
On Thu, 2006-09-07 at 06:18 -0500, Hao Chen wrote:
Hi,
I am using barplot and would like to know if it is possible to have bars
filled with one
On Thu, 2006-09-07 at 11:57 -0500, Erin Hodgess wrote:
Dear R People:
Way Off Topic:
Is anyone aware of a website that contains important dates
in statistics history, please?
Maybe a sort of This Day in Statistics, please?
I thought that my students might get a kick out of that.
On Thu, 2006-08-24 at 10:53 -0400, roger bos wrote:
I am looking for help install the x86_64 R Binary onto my FC5 machine. At
the risk of subjecting myself to tons of criticism, I must confess that I
don't know anything about Linux and I have never compiled R from source.
Therefore, I choose
Roger,
The Windows packages will not run on Linux. You will need to install
them using the Linux versions (.tar.gz files) of the CRAN packages.
You can copy them from a CRAN mirror to your USB drive and then install
them locally using
R CMD INSTALL PackageName.tar.gz
This will again need
On Thu, 2006-08-24 at 14:01 -0700, Maria Montez wrote:
Hi!
I would like to be able to create formulas automatically. For example, I
want to be able to create a function that takes on two values: resp and
x, and then creates the proper formula to regress resp on x.
My code:
fit.main -
On Tue, 2006-08-22 at 07:32 -0700, Srinivas Iyyer wrote:
Dear marc: thank you for your tip.
cat(x.new, \n)
3\',5\'-cyclic-nucleotide phosphodiesterase activity
here cat is printing on screen.
how can I direct the output to an object.
I cannot do:
y - cat(x.new, \n)
is
On Mon, 2006-08-21 at 13:43 -0700, Srinivas Iyyer wrote:
Dear all:
I have a character object x with ' (single-quote)
character.
x - c('hydrolase activity,actin
binding,3',5'-cyclic-nucleotide phosphodiesterase
activity)
I want to write a function that will identify ' and
replaces
On Fri, 2006-08-18 at 10:41 -0400, Tom Boonen wrote:
Dear List,
why does as.data.frame(cbind()) transform numeric variables to
factors, once one of the other variablesused is a character vector?
#
x.1 - rnorm(10)
x.2 - c(rep(Test,10))
Foo - as.data.frame(cbind(x.1))
is.factor(Foo$x.1)
On Fri, 2006-08-18 at 11:17 -0400, Mike Wolfgang wrote:
Hello list,
I've been searching around trying to find whether somebody has written such
a package of least angle regression on generalized linear models, like what
Lasso2 package does. The extension to generalized linear models is
Andy,
Upon further review of the documentation for lars, you are correct.
Thanks for the pointer to the work by Tim et al.
Regards,
Marc
On Fri, 2006-08-18 at 12:48 -0400, Liaw, Andy wrote:
I believe `lars' does not currently fit glms. For that you'll probably need
to look at `glar', at:
On Fri, 2006-08-18 at 16:44 -0400, Rajarshi Guha wrote:
Hi, I have a situation where I have a list of lists. Each list can
contain elements of different types (but each one will be a scalar) say
of double, integer or character.
However the elements of each list are always in the same order:
On Thu, 2006-08-17 at 11:46 -0700, Pamela Allen wrote:
I am having a problem using boxlpot with my data. I have my data arranged
in a data table, and two of my columns are mass and month. I am trying
to plot the mass of my study animals by month, thus I would like to have it
in the order of
On Wed, 2006-08-16 at 11:36 -0600, Spencer Jones wrote:
I have an array with 44800 columns and 24 rows I would like to compute the
row average for the array 100 columns at a time, so I would like to end up
with an array of 24 rows x 448 columns. I have tried using apply(dataset, 1,
function(x)
On Wed, 2006-08-16 at 14:43 -0400, Doran, Harold wrote:
I'm trying to read in some data from a .csv format and have come across
the following issue. Here is a simple example for replication
# A sample .csv format
schid,sch_name
331-802-7081,School One
464-551-7357,School Two
On Tue, 2006-08-15 at 13:10 -0400, T Mu wrote:
Hi all,
Suppose I have a data frame myDF, col A is factor, col B is numeric, col C
is character. I can get their classes by
class(myDF$A)
but is there a quick way to show what classes of all columns are? Thank you.
Tian
Depending upon
On Mon, 2006-08-14 at 14:12 -0300, Ronaldo Reis-Jr. wrote:
Hi,
is possible to make a R script to run under a console without open the R
environment?
Something like this example.R
#!/usr/bin/R
function(name=Put here your name) {
print(name)
}
In a console I make
./example.R
On Tue, 2006-08-08 at 14:10 -0400, Liaw, Andy wrote:
From: Marc Schwartz
On Fri, 2006-08-04 at 12:46 -0400, Daniel Gerlanc wrote:
Hello all,
Consider the following problem:
There is a matrix of probabilities:
set.seed(1)
probs - array(abs(rnorm(25, sd = 0.33)),
Paulo,
Try the following:
x - rnorm(100)
par(xaxs = i)
par(yaxs = i)
hist(x, breaks = seq(-4, 4, 0.5), ylim = c(0, 40),
xlim = c(-4, 4))
box()
The problem is that graphics:::plot.histogram() is coded in such a way
that the use of 'xaxs' and 'yaxs' are ineffectual, as they are not
On Wed, 2006-08-09 at 18:07 +0200, Christian Oswald wrote:
Dear List,
I neeed a grouped list with two sort of categorical data. I have a data
.frame like this.
yearcat.b c
1 2006a1 125 212
2 2006a2 256 212
3 2005a1 14
[Re-sending to the list only for archiving, as my original reply had too
many recipients and I cancelled it.]
1. One need not be subscribed to the list to be able to post. Thus,
indeed, a poster may not see all postings.
2. On the relatively rare occasion (thanks to Martin) where the server
On Mon, 2006-08-07 at 14:05 -0600, Mark Na wrote:
Dear R community,
I have two dataframes first and second which share a unique identifier.
I wish to make a new dataframe third retaining only the rows in
first which also occur in second.
I have tried using merge but can't seem to figure
On Fri, 2006-08-04 at 09:47 -0600, Andrew Kniss wrote:
I've tried several different ways to accomplish this, but as yet to no
avail. My y-axis for a plot has a rather long label, and thus I have
been using /n to break it into two lines. However, to make it
technically correct for
Actually Gabor, using your solution with 'atop', which I had not
considered, it will work with base graphics:
par(oma = c(0, 0, 2, 0), mar = c(5, 6, 0.25, 2), lheight = 1)
plot(1:10, ylab = expression(atop( ^14*C*-glyphosate line1,
line2)))
HTH,
Marc
On
On Fri, 2006-08-04 at 10:33 -0600, Spencer Jones wrote:
Is there a function in R comparable to rpois that can simulate random
variables from an overdispersed poisson distribution? If there is not a
function any ideas/references on how to program one?
Take a look at
?rnbinom
or
On Fri, 2006-08-04 at 12:46 -0400, Daniel Gerlanc wrote:
Hello all,
Consider the following problem:
There is a matrix of probabilities:
set.seed(1)
probs - array(abs(rnorm(25, sd = 0.33)), dim = c(5,5), dimnames =
list(1:5, letters[1:5]))
probs
a b c d
On Fri, 2006-08-04 at 19:44 +0100, Prof Brian Ripley wrote:
On Fri, 4 Aug 2006, Marc Schwartz (via MN) wrote:
On Fri, 2006-08-04 at 09:47 -0600, Andrew Kniss wrote:
I've tried several different ways to accomplish this, but as yet to no
avail. My y-axis for a plot has a rather long
On Thu, 2006-08-03 at 10:10 -0400, Daniel Gerlanc wrote:
Hello all,
Consider the following problem:
There are two vectors:
rows - c(1, 2, 3, 4, 5)
columns - c(10, 11, 12, 13, 14)
I want to create a matrix with dimensions length(rows) x length(columns):
res - matrix(nrow =
On Thu, 2006-08-03 at 07:46 -0700, Michael Jerosch-Herold wrote:
I have data for several rings of a left heart chamber, and which I
would like to display in concentric rings, with color-encoding of the
values. Each ring corresponds to one slice through the heart, and the
rings correspond to
On Thu, 2006-08-03 at 14:44 -0400, Neil McLeod wrote:
Hi all,
Is there any way to access a column of a data frame by its label (title)
rather than its column index? For example, I'd like to be able to select
animals[,weight] rather than animals[,3], if the third column of the
animals data
On Tue, 2006-08-01 at 07:03 -0700, Kartik Pappu wrote:
Hi all,
I have a matrix with each column containing a large number of integers
(0 and above). in each column beyond a certain row (say row 120 in
column 1, row 134 in column 2, 142 in column 3...) there are only
0's. I want to find,
On Tue, 2006-07-25 at 13:12 -0700, Adrian Dragulescu wrote:
Hello,
I want to have a title that will look something like:
Results for \theta=2.1, given that I have a variable theta=2.1, and
\theta should show on the screen like the greek letter.
I've tried a lot of things:
theta - 2.1
On Mon, 2006-07-24 at 12:00 -0500, [EMAIL PROTECTED] wrote:
?unique says
Value:
An object of the same type of 'x'. but if an element is equal to
one with a smaller index, it is removed.
However, I need to keep the one with the LARGEST index.
Can someone please show me the
On Fri, 2006-07-21 at 05:43 -0700, Ahamarshan jn wrote:
Hi,
I have a dataset saved in *.csv format, that contains
13 columns (the first column being the title name and
the rest experiments) and about 2500 rows.
Not all columns in the row have data in it
i.e for eg
On Fri, 2006-07-21 at 11:47 -0700, Paquet, Agnes wrote:
Dear List,
I am a new Mac user and I am having problem generating png (or jpeg)
using the GUI version of R. I installed R-2.3.1.dmg (custom install with
everything selected) and X11User.pkg but I am still getting the
following X11
On Fri, 2006-07-21 at 15:15 -0500, [EMAIL PROTECTED] wrote:
I have an object of mode character that contains a long sequence of letters.
How can I convert this object into a vector with each element of the vector
containing a single letter? Essentially, I want to break the long string of
On Tue, 2006-07-18 at 11:30 -0700, Darren Weber wrote:
Hi,
I find a lot of the R-help email traffic overloads my inbox. My IT
managers are not really happy for me to be subscribed to several
high-traffic email lists. I don't want to lose my contact with the
R-help emails, so I'm having to
On Mon, 2006-07-17 at 16:07 +0200, Bashir Saghir (Aztek Global) wrote:
I'm trying to write a simple function that does the following:
[command] xify(5.2)
[output] XXX.XX
[command] xify(3)
[output] XXX
Any simple solutions (without using python/perl/unix script/...)?
Thanks,
On Fri, 2006-07-14 at 16:57 +0200, Georg Otto wrote:
Hi,
I want to generate object names out of variables in a sort of variable
substitution.
first i generate some vectors and an empty list:
vector.a-c(a,b)
vector.b-c(c,d)
vector.c-c(e,f)
vectors-c(vector.a, vector.b, vector.c)
On Fri, 2006-07-14 at 18:35 +0200, Mehmet Somel wrote:
Dear /Bill Paterson,
while trying to find a way to convert SAS code into R, I came across
your one time e-mail message
(http://www.ens.gu.edu.au/robertk/R/help/99b/0908.html). I'd appreciate
to learn if anything came out of this, or
On Wed, 2006-07-12 at 17:41 +0100, Jol, Arne wrote:
Dear R,
I import data from spss into a R data.frame. On this rawdata I do some
data processing (selection of observations, normalization, recoding of
variables etc..). The result is stored in a new data.frame, however, in
this new
On Fri, 2006-07-07 at 11:20 -0400, Wade Wall wrote:
Hi all,
I have a three columned list that I have imported into R. The first column
is a plot (ex. Plot1), the second is a species name (ex ACERRUB) and the
third a numeric value. I want to replace some of the second column names
with
On Fri, 2006-07-07 at 11:47 -0400, Lu, Jiang Jane wrote:
Hi,
I am trying to plot odds ratios and the corresponding confidence
intervals in horizontal segments. It would be ideal if the confidence
interval segment can be drawn with little vertical bars at both ends. I
have tried very hard to
Thanks for re-posting onlist. My offlist reply:
The 'list' argument, as per ?replace, needs to be a vector of one or
more indices into another vector, generally the source vector argument
'x', not the actual values that you want to replace. 'list' can either
be explicit integers as the indices,
Wade,
Given that you appear to have multiple search and replace items to deal
with, here is a possible loop based Global Search and Replace
solution:
gsr - function(Source, Search, Replace)
{
if (length(Search) != length(Replace))
stop(Search and Replace Must Have Equal Number of Items\n)
On Mon, 2006-06-26 at 12:40 -0500, [EMAIL PROTECTED] wrote:
Hi : I think I need to use sapply but I can't figure this out.
Suppose I have two vectors : tempa ( 4, 6,10 ) and tempb
( 11,23 ,39 )
I want a function that returns 4:11,6:23 and 10:39 as vectors.
I tried :
On Fri, 2006-06-23 at 11:53 -0400, Mu Tian wrote:
Hi all,
I'd like to do a multiplication between 2 matrices buy only want resulsts of
cloumn 1 * column 1, column 2 * column 2 and so on.
Now I do
C - diag(t(A) %*% B)
Is there a bulit in way to do this?
Thank you.
You just want:
Has anyone tried this with OO.org's Impress or Writer on Windows to see
if the same behavior occurs?
My recollection from prior experience on Windows (it's been a while) is
that a subtle resize takes place when pasting/importing graphics into
the aforementioned apps. You can right click on the
On Fri, 2006-06-23 at 18:16 +0200, Philipp Pagel wrote:
On Fri, Jun 23, 2006 at 09:21:37AM -0400, Gabor Grothendieck wrote:
Note that jpg, bmp and png are in less desirable bit mapped formats whereas
eps is in a more desirable vector format (magnification and shrinking does
not involve loss
On Fri, 2006-06-23 at 17:23 +0100, Vittorio wrote:
I have set up an R procedure that is launched every three hours by
crontab in a unix server. Crontab runs at regular intervals the
following line:
R CMD BATH myprog.R
myprog.R (which by the way uses
R2HTML) should create an updated png
On Fri, 2006-06-23 at 14:02 -0400, Michael H. Prager wrote:
Previous posters have argued for EPS files as a desirable transfer
format for quality reasons. This is of course true when the output is
through a Postscript device.
However, the original poster is making presentations with
On Thu, 2006-06-22 at 15:40 -0500, Jeffrey Horner wrote:
Achim Zeileis wrote:
[...]
The plan is to provide the original presentation slides of the
panelists and a video of the whole panel disc, and probably some minutes
and/or further information.
Did you happen to video Ivan Mizera's
On Wed, 2006-06-21 at 12:22 -0400, Baoqiang Cao wrote:
Dear All,
I tried to plot a variety of lines(curves) on same figure. What I did
is,
plot(x=x1,y=y1)
lines(x=x2,y=y2)
lines(x=x3,y=y3)
...
In my data, the maximum of y1 is much smaller than those maximums of
other y vectors. So, in
On Wed, 2006-06-21 at 11:55 -0500, Marc Schwartz (via MN) wrote:
On Wed, 2006-06-21 at 12:22 -0400, Baoqiang Cao wrote:
Dear All,
I tried to plot a variety of lines(curves) on same figure. What I did
is,
plot(x=x1,y=y1)
lines(x=x2,y=y2)
lines(x=x3,y=y3)
...
In my data
On Fri, 2006-06-09 at 11:01 +, fernando espindola wrote:
Hi user R,
I am try to put degree character in axis x, but don't make this. I have
the next code:
plot(mot[,5],
time1,xlim=c(-45,-10),type=l,yaxt=n,ylab=,col=1,lwd=2,xlab=,xaxt=n)
The range of value in axis-x is -45 to
On Thu, 2006-06-08 at 15:44 +0100, d d [EMAIL PROTECTED] ac uk wrote:
Hello All,
I am trying to format a box plot chart for a report so it matches other
charts I have created in other software programs. My problem is that I
need to rotate the values on the Y axis by 45 degrees, I have
On Wed, 2006-06-07 at 10:30 -0500, Mark L Sessing wrote:
Hello,
I am learning how to use R, and I cannot figure out how to plot more
than one data set on a single plot. Can you help me out?
Cheers,
Mark
It depends upon the type of plot (scatter, lines, bar, etc.) and whether
or not you
On Thu, 2006-06-08 at 00:10 +0800, zhijie zhang wrote:
Dear Rusers,
As we all know , there are many methods to do multiple comparison in the
parametric statistical analysis, But i can't find some in nonparametric
statistical analysis.
Could anybody give some suggestions?
Have you looked at
On Tue, 2006-06-06 at 13:44 -0700, Dirk Vandekerckhove wrote:
Hi,
Is this intended behaviour of cbind?
a-c(0,1,2,3)
a
[1] 0 1 2 3
a-as.ordered(a)
a
[1] 0 1 2 3
Levels: 0 1 2 3
a-a[a!=0] #remove the zero from a
a
[1] 1 2 3
Levels: 0 1 2 3
cbind(a)
a
[1,] 2
On Thu, 2006-06-01 at 11:06 -0400, Mu Tian wrote:
I want to get index number of 0s, like
x - c(1, 2, 0, 3, 0, 4)
I want an output of
3, 5
Thank you.
See ?which
which(x == 0)
[1] 3 5
HTH,
Marc Schwartz
__
R-help@stat.math.ethz.ch
On Tue, 2006-05-30 at 19:08 +0100, Gavin Simpson wrote:
Dear List,
Given,
y - matrix(c(0,1,1,1,0,0,0,4,4), ncol = 3, byrow = TRUE)
rownames(y) - c(a,b,c)
colnames(y) - c(1,2,3)
y
y2 - y[2:3, ]
rownames(y2) - c(x,z)
y2
how can I stop
merge(y, y2, all = TRUE, sort = FALSE)
On Tue, 2006-05-30 at 15:38 -0500, Marc Schwartz (via MN) wrote:
On Tue, 2006-05-30 at 19:08 +0100, Gavin Simpson wrote:
Dear List,
Given,
y - matrix(c(0,1,1,1,0,0,0,4,4), ncol = 3, byrow = TRUE)
rownames(y) - c(a,b,c)
colnames(y) - c(1,2,3)
y
y2 - y[2:3, ]
rownames(y2) - c
On Wed, 2006-05-24 at 17:20 +0100, Heinz Tuechler wrote:
Dear All!
For descriptive purposes I would like to add attributes to objects. These
attributes should be kept, even if by indexing only part of the object is
used.
I noted that some attributes like levels and class of a factor exist
On Wed, 2006-05-24 at 18:51 +0200, Andreas Svensson wrote:
Hi
In R, using plot(x,y) followed by abline(lm(y~x)) produces a graph
with a regression line spanning the whole plot . This means that the
line extends beyond the swarm of data points to the defined of default
plot region.
On Wed, 2006-05-24 at 14:45 -0400, Guenther, Cameron wrote:
Hello,
If I have two variables that are factors or characters and I want to
create a new variable that is the combination of both what function can
I use to accomplish this?
Ex.
Var1 Var2
SA100055113
On Wed, 2006-05-24 at 21:53 +0200, Andreas Svensson wrote:
Thankyou very much Marc for that nifty little script.
When I use it on my real dataset though, the lines are fat in the middle
and thinner towards the ends. I guess it's because lines draw one
fitted line for each x, and if you
On Tue, 2006-05-23 at 11:40 -0700, Sachin J wrote:
Hi
How can do this in R.
df
48
1
35
32
80
If df 30 then replace it with 30 and else if df 60 replace it
with 60. I have a large dataset so I cant afford to
On Mon, 2006-05-22 at 16:24 +0100, Federico Calboli wrote:
Hi All,
I need to write as text files 1000 ish variation of the same data frame,
once I permute a row.
I would like to use the function write.table() to write the files, and
use a loop to do it:
for (i in 1:1000){
bb8[2,]
On Mon, 2006-05-22 at 17:55 -0400, Doran, Harold wrote:
I have a data frame of ~200 columns and ~20,000 rows where each column
consists of binary responses (0,1) and a 9 for missing data. I am
interested in finding the columns for which there are fewer than 100
individuals with responses of 0.
On Fri, 2006-05-19 at 15:37 -0400, Randall C Johnson [Contr.] wrote:
Hello,
I'm trying to install R on a linux machine running Red Hat 8. I ran
./configure
make
and get the following error. I've installed several versions of R (2.2.1
most recently) on this machine and haven't had any
On Fri, 2006-05-19 at 17:59 -0300, Rogerio Porto wrote:
While reading the various answers, I've remembered that
the juridic part can't be that so simple. If I'm not fogeting
something, there are some packages in R that has a more
restrictive licence than GPL.
HTH,
Rogerio.
Any CRAN
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