On Thu, 2005-11-17 at 17:09 +0100, Matthieu Cornec wrote:
Hello,
I am importing the following file
;aa;bb;cc
1988;12;12;12
1989;78;78;12
1990;78;78;12
1991;78;78;12
1992;78;78;12
1993;78;78;12
1994;78;78;12
On Wed, 2005-11-16 at 16:46 +, Jörg Schlingemann wrote:
Hi!
This is probably a very trivial question. Is there an easy way to invert the
y-axis (low values on top) when using the function barplot()?
Thanks,
Jrg
You mean something like this?:
barplot(1:10, ylim =
On Mon, 2005-11-14 at 15:55 +0100, Karin Lagesen wrote:
I have found a bug/feature with barplot that at least to me shows
undesireable behaviour. When using barplot and plotting fewer
groups/levels/factors(I am unsure what they are called) than the number
of colors stated in a col statement,
On Mon, 2005-11-14 at 19:07 +0200, Brandt, T. (Tobias) wrote:
-Original Message-
From: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
Sent: 14 November 2005 06:21 PM
On 11/14/05, Brandt, T. (Tobias) [EMAIL PROTECTED] wrote:
Hi
Given that things like the following work
a
On Mon, 2005-11-14 at 19:01 +, William Astle wrote:
Is there an R function analogous to the C function strtol?
I would like to convert a binary string into an integer.
Cheers for advice
Will
There was some discussion in the past and you might want to search the
archive for a more
On Wed, 2005-11-02 at 16:06 -0600, Michal Lijowski wrote:
Hi,
I have been trying draw tickmark labels along
the y - axis perpendicular to the y axis while
labels along the x - axis parallel to x axis
while making box plot.
Here is my test dataset.
TData
ID Ratio
1 0 7.075
2
On Fri, 2005-10-28 at 10:26 -0700, J.M. Breiwick wrote:
Hello,
I want to plot 3 boxplots [ par(mfrow=c(3,1)) ] but the first one has 8
groups, the 2nd has 7 and the third has 6. But I the groups to line up:
1 2 3 4 5 6 7 8
2 3 4 5 6 7 8
3 4 5 6 7 8
where the numbers
On Thu, 2005-10-27 at 16:15 -0500, Na Li wrote:
On 27 Oct 2005, Duncan Temple Lang wrote:
Yes, it is of interest and was sitting on my todo list at
some time. If you want to go ahead and provide code to do it,
that would be terrific. There are other areas where encryption
would be
On Tue, 2005-10-25 at 11:55 -0600, [EMAIL PROTECTED] wrote:
Does anyone know how I can set up R so that when I make a graphic, the
graphics window remains behind the console window? It's annoying to
have to reach for the mouse every time I want to type another line of
code (e.g., to add
On Tue, 2005-10-25 at 13:07 -0500, Marc Schwartz (via MN) wrote:
On Tue, 2005-10-25 at 11:55 -0600, [EMAIL PROTECTED] wrote:
Does anyone know how I can set up R so that when I make a graphic, the
graphics window remains behind the console window? It's annoying to
have to reach for the mouse
On Mon, 2005-10-24 at 22:32 +0200, Dr. med. Peter Robinson wrote:
Dear List,
I am sorry if this perhaps a too basic question, but I have not found an
answer in Google or in the R help system. I am trying to use R to do a
very simple analysis of some data (RT-PCR and Western analysis) with a
On Fri, 2005-10-21 at 21:13 +0200, Jan Sabee wrote:
Dear all,
I want to make three plot below to only one plot together with legend,
how can I do that?
I have tried with matplot function but I did not succeed.
Thanks for your help.
Sincerelly,
Jan Sabee
test.five.x -
On Fri, 2005-10-21 at 21:32 +, Ben Bolker wrote:
As far as I can tell from reading The Fine Documentation
(R Language Definition and Intro to R), matrices are supposed
to be of homogeneous types. Yet giving matrix() an inhomogeneous
list seems to work, although it produces a peculiar
On Thu, 2005-10-20 at 16:20 +0200, Peter Dalgaard wrote:
Nelson, Gary (FWE) [EMAIL PROTECTED] writes:
Peter,
Thank you for your response. I knew how close the values are to
integers, but I still don't understand why I don't have control over
how the numbers are displayed (rounded or
On Thu, 2005-10-20 at 17:31 +0200, Christian Jones wrote:
Hello,?xml:namespace prefix = o ns =
urn:schemas-microsoft-com:office:office /o:p/o:p
I would like to create a histogram from a data collumn consisting of 4
classes (0; 0.05;0.5;25;75). Due to the difference in scale the
classes
On Thu, 2005-10-20 at 14:46 -0400, Keith Sabol wrote:
I am creating boxplots from a dataframe and would like to add to the
standard output a marker representing the value from a particular row in the
dataframe.
.And I apologize if the solution is as trivial as it seems it should be.
On Thu, 2005-10-20 at 15:41 -0500, Marc Schwartz (via MN) wrote:
On Thu, 2005-10-20 at 14:46 -0400, Keith Sabol wrote:
I am creating boxplots from a dataframe and would like to add to the
standard output a marker representing the value from a particular row in
the
dataframe
On Wed, 2005-10-19 at 18:27 +0100, Rui Cardoso wrote:
Hi,
I have a problem about graphics. I would like to plot two graphs: a barplot
and curve. Here is the code:
barplot(dpois(0:45,20),xlim=c(0,45),names=0:45)
curve(dnorm(x,20,sqrt(20)),from=0,to=45,add=T)
Both graphs are drawn
On Tue, 2005-10-18 at 14:27 +0100, MJ Price, Social Medicine wrote:
Dear all,
I have been trying to find a function to calculate the Breslow-Day test for
homogeneity of the odds ratio in R. I know the test can be preformed in SAS
but i was wondering if anyone could help me to perform this
On Tue, 2005-10-18 at 17:13 +0200, richard mendes wrote:
hello everybody
i'm very new at using R so probably this is a very stupid question.
I have a problem calculating a p-value. When i do this with excel i
can use the method CHIDIST for 1.2654 with 1 freedom degree i get the
answer 0.261
On Wed, 2005-10-19 at 06:47 +1000, Tim Churches wrote:
Marc Schwartz (via MN) wrote:
There is also code for the Woolf test in ?mantelhaen.test
Is there? How is it obtained? The documentation on mantelhaen.test in R
2.2.0 contains a note: Currently, no inference on homogeneity of the
odds
On Mon, 2005-10-17 at 16:51 +0200, Jorge Gaspar Sanz Salinas wrote:
Hi all,
This is my first post, I hope you will help me.
I've some data to present with histograms. I have few values with almost 99%
of
the frequencies (thousands) and some other values with low frequencies (below
one
On Thu, 2005-10-13 at 14:50 +0100, Luis Ridao Cruz wrote:
R-help,
I use the code below to plot some data by applying apply function.
But I don't know how I can get the argument type or col on the
plot function to distinguish the different lines
in the graph:
apply ( my.data, 2, function
On Thu, 2005-10-13 at 10:02 -0400, Duncan Murdoch wrote:
Sorry, a typo in my previous message (parens in the wrong place in the
conversion).
Here it is corrected:
I'm doing a big slow computation, and profiling shows that it is
spending a lot of time in match(), apparently because I have
On Thu, 2005-10-13 at 14:31 -0400, Duncan Murdoch wrote:
On 10/13/2005 1:07 PM, Marc Schwartz (via MN) wrote:
On Thu, 2005-10-13 at 10:02 -0400, Duncan Murdoch wrote:
Sorry, a typo in my previous message (parens in the wrong place in the
conversion).
Here it is corrected:
I'm
On Thu, 2005-10-13 at 19:47 +0200, Jan Sabee wrote:
Is there any routine to generate for one vector matrix.
If I have X I want to generate start from zero to maximum value each vector.
For example, I have a vector x = (4,2,3,1,4)
I want to generate n=6 times, for 4, start 0 to 4, then 2
On Thu, 2005-10-13 at 14:28 -0600, Brian S Cade wrote:
Ok so I see the problem that I'm having creating a new variable (LAG1DBC)
in the example data transformation below is that tapply() is creating a
list that is not dimensionally consistent with the data frame (data). So
how do I go from
On Fri, 2005-10-14 at 00:04 +0200, Benedykt P. Barszcz wrote:
Dnia czwartek, 13 października 2005 23:25, Andrew Robinson napisał:
Marco,
use the system command.
?system
I hope that this helps,
system(ls, intern = FALSE, ignore.stderr = TRUE)
Error in as.character(args[[i]]) :
On Thu, 2005-10-13 at 15:20 -0600, Chris Buddenhagen wrote:
Dear all
I am using R to produce ordinations library(vegan) and the plot function
produced looks great on the screen but when I send it to jpg or pdf or eps
the resolution is not so good. Can you tell me how to get high resolution
On Wed, 2005-10-12 at 08:33 -0500, Charles Dupont wrote:
Marc Schwartz (via MN) wrote:
On Tue, 2005-10-11 at 10:01 -0400, Rick Bilonick wrote:
I'm using R 2.2.0 on an up-to-date version of Fedora Core 4 with the
latest version of Hmisc. When I run an example from the latex function I
get
On Wed, 2005-10-12 at 12:01 -0700, t c wrote:
I have a dataset with three variables: date, var1, var2
How can I calculate the correlation, by date, between var1 and var2?
e.g.
datevar1var2
1/1/200154
1/1/200185
1/1/200197
2/1/200172
I suspect that John may be looking for ?friedman.test, which I believe
will allow for a two-way non-parametric test.
kruskal.test() will perform a non-parametric test on two or more samples
(or factor levels) as a generalization of wilcox.test() for one or two
samples (or factor levels).
HTH,
On Tue, 2005-10-11 at 10:01 -0400, Rick Bilonick wrote:
I'm using R 2.2.0 on an up-to-date version of Fedora Core 4 with the
latest version of Hmisc. When I run an example from the latex function I
get the following:
x - matrix(1:6, nrow=2, dimnames=list(c('a','b'),c('c','d','enLine
2')))
Peter,
Good points all around.
Hopefully John will provide further clarification.
Best regards,
Marc
On Tue, 2005-10-11 at 19:46 +0200, Peter Dalgaard wrote:
Marc Schwartz (via MN) [EMAIL PROTECTED] writes:
I suspect that John may be looking for ?friedman.test, which I believe
On Mon, 2005-10-10 at 10:37 -0400, Afshartous, David wrote:
All,
Is there are a wildcard in R for varible names as in unix? For example,
rm(results*)
to remove all variable or function names that begin w/ results?
cheers,
Dave
ps - please
On Mon, 2005-10-10 at 16:01 +0100, Prof Brian Ripley wrote:
On Mon, 10 Oct 2005, Marc Schwartz (via MN) wrote:
On Mon, 2005-10-10 at 10:37 -0400, Afshartous, David wrote:
All,
Is there are a wildcard in R for varible names as in unix? For example,
rm(results
On Mon, 2005-10-03 at 15:28 -0500, lforzani wrote:
Hello, I am using library fda and I can not run a lot of functions because
I receive the error:
Error in bsplineS(evalarg, breaks, norder, nderiv) :
couldn't find function spline.des
do you know how I can fix that? Thnaks.
On Tue, 2005-10-04 at 08:38 -0500, Robert Baer wrote:
On 03-Oct-05 Marc Schwartz (via MN) wrote:
On Mon, 2005-10-03 at 16:31 -0300, Rolf Turner wrote:
A student in one of my courses has asked me about getting R graphics
output (under Linux) into a Word document. I.e. she wants
On Mon, 2005-10-03 at 18:01 +0100, Prof Brian Ripley wrote:
On Mon, 3 Oct 2005, Daniel Pick wrote:
I have successfully downloaded the sources and built R as a shared
library on a Red Hat Enterprise Level 3 box. I am now trying to build the
GNOME GUI, but configure is barfing on glade.
On Mon, 2005-10-03 at 16:31 -0300, Rolf Turner wrote:
A student in one of my courses has asked me about getting R graphics
output (under Linux) into a Word document. I.e. she wants to do her
R thing under Linux, but then do her word processing using Word.
Scanning around the r-help archives
On Mon, 2005-10-03 at 22:00 +0100, Ted Harding wrote:
Rolf ( Marc)
On 03-Oct-05 Marc Schwartz (via MN) wrote:
On Mon, 2005-10-03 at 16:31 -0300, Rolf Turner wrote:
A student in one of my courses has asked me about getting R graphics
output (under Linux) into a Word document. I.e. she
On Thu, 2005-09-29 at 15:28 +0200, Karin Lagesen wrote:
Petr Pikal [EMAIL PROTECTED] writes:
Hi Karin
I did not have seen any answer for your question yet so here is a
try.
I gues you want the horizotal layout or your boxplot.
boxplot(split(rnorm(30), rep(1:3, each=10)),
On Thu, 2005-09-29 at 14:34 +0200, Volker Rehbock wrote:
Is it possible to automatically display the underlying values of a
piechart/barplot in the graphic? If so, which package/function/argument do I
need for it?
Thanks,
Volker
Using pie charts are not a particularly good way of
On Thu, 2005-09-29 at 18:36 +0200, Jan Verbesselt wrote:
Hi R-help,
When using the package Design and the plot.Design function all the graphs of
an lrm.fit (lrm()) are plotted without a frame (only with axes). How can the
frame be added to these plots?
In the plot.default
On Thu, 2005-09-29 at 18:08 -0400, Johann Park wrote:
Hi to all,
I am a PH.D Student doing statistical analysis.
I am totally new to R. I previously use Stata and am changing into R. I
ususally do with logit regression with binary dependent variable (war
occurence:1 or 0).
I just
On Thu, 2005-09-29 at 06:57 +1000, Stephen Choularton wrote:
Hi
I am trying to produce a little table like this:
0 1
0 601 408
1 290 2655
but I cannot get the syntax right.
Can anyone help.
Stephen
Do you have the raw
On Tue, 2005-09-27 at 19:12 +0200, Søren Højsgaard wrote:
In data OME in MASS I would like to extract the first 5 observations
per subject (=ID). So I do
library(MASS)
OMEsub - split(OME, OME$ID)
OMEsub - lapply(OMEsub,function(x)x[1:5,])
unsplit(OMEsub, OME$ID)
- which results in
On Mon, 2005-09-26 at 17:45 +0200, Shengzhe Wu wrote:
Hello,
In the Unix environment, I open a window by x11(). May I specify the
position of this window by specifying the position of the top left of
the window as in Windows environment? Or some other parameters can be
used to do that?
On Thu, 2005-09-22 at 10:44 -0400, Elisabetta Manduchi wrote:
Can anybody tell me if there is an R implementation of the
Fligner-Policello robust rank test?
Thanks,
Elisabetta
I don't know about the Fligner-Policello test, but the Fligner-Killeen
test has been implemented in fligner.test().
On Mon, 2005-09-19 at 12:30 -0700, shanmuha boopathy wrote:
Dear sir,
i have a matrix like
x-c(1:20)
A-matrix(x,4,5)
A
[,1] [,2] [,3] [,4] [,5]
[1,]159 13 17
[2,]26 10 14 18
[3,]37 11 15 19
[4,]48 12 16 20
I want to
On Fri, 2005-09-16 at 10:34 -0700, Martin Lam wrote:
Hi,
I was wondering if it's possible to get the row
numbers from a filtering. Here's an example:
# give me the rows with sepal.length == 6.2
iris[(iris[,1]==6.2),]
# output
Sepal.Length Sepal.Width Petal.Length Petal.Width
On Thu, 2005-09-15 at 10:43 -0400, Tyler Smith wrote:
Hi,
I'm working on a MEPIS (Debian-based Linux) computer, using the
emacs/ESS package to do my R work. I've got some plots that I label
interactively using the locate function. With the Windows GUI there is
an option to take a
On Wed, 2005-09-14 at 20:17 +0200, Par Leijonhufvud wrote:
I'm trying to create histogram (using hist()) that fullfill the following
criteria:
* data is on a ordinal scale (1, 2, 3, 4, 5)
* I want bars centered over the number on the x-axis
* I want 5 bars of equal
On Thu, 2005-09-01 at 16:58 +0100, [EMAIL PROTECTED] wrote:
hy,
I need to have the 0 on the bottom left corner of the graph being
joined , not with this little hole between x axis and y axis...
I've saw this question with the answer one time but i'm unable to find
it again..
thks.
On Thu, 2005-09-01 at 21:51 +0200, Knut Krueger wrote:
scaling-4
xywidth-480
resolution-150
png(filename = c:/r/anschluss/plots/4.png, width = xywidth*scaling,
height = xywidth*scaling,pointsize = 12, bg = white, res =
resolution*scaling)
..
barplot(xrow,col =
On Tue, 2005-08-30 at 12:28 -0700, Isotta Felli wrote:
Dear list.
New to R, I'm looking for a way of using crosstab to output
low-dimensional (higher than 2) contingency tables (frequencies,
per-cents by rows, % by columns, mean, quantiles) I'm looking for
something of the following
On Mon, 2005-08-29 at 12:58 -0400, Doran, Harold wrote:
Dear list:
I have some data for which I am generating a series of barplots for
percentages. One issue that I am dealing with is that I am trying to get
the legend to print in a fixed location for each chart generated by the
data.
On Fri, 2005-08-26 at 15:25 +0200, Peter Dalgaard wrote:
Marc Schwartz [EMAIL PROTECTED] writes:
x - c(0.005, 0.010, 0.025, 0.05, 0.1, 0.5, 0.9,
0.95, 0.975, 0.99, 0.995)
df - c(1:100)
mat - sapply(x, qchisq, df)
dim(mat)
[1] 100 11
str(mat)
num [1:100,
names-.default
0.29 0.02 0.29 0.02 names
so almost all the time is in qchisq.
On Fri, 26 Aug 2005, Marc Schwartz (via MN) wrote:
On Fri, 2005-08-26 at 15:25 +0200, Peter Dalgaard wrote:
Marc Schwartz [EMAIL PROTECTED] writes:
x - c(0.005, 0.010, 0.025, 0.05
On Fri, 2005-08-26 at 22:39 +0530, A Mani wrote:
Hello,
Easy ways to unpaste?
xp - paste(x2, x3) # x2, x3 are two non-numeric columns.
.
.
xfg - data.frame(xp,sc1, sc2, sc3) # sc1,sc2, sc3 are numeric cols.
I want xp to be split up to form a
That works also (using the example in ?lmList)
library(lme4)
?lmList
fm1 - lmList(breaks ~ wool | tension, warpbreaks)
However, one still would need to use either sapply() or lapply() as
below to get the details that Krishna is looking for.
'fm1' above is a list of models (S4 class
, it would appear that the use of lmList would be
advantageous over the use of by().
Marc
On Thu, 2005-08-25 at 11:52 -0500, Marc Schwartz (via MN) wrote:
That works also (using the example in ?lmList)
library(lme4)
?lmList
fm1 - lmList(breaks ~ wool | tension, warpbreaks)
However
On Wed, 2005-08-24 at 13:06 -0400, Doran, Harold wrote:
Dear List:
I'm creating a series of barplots using Sweave that must assume a
standard format. This is student achievement data and the x-axis must
include all grades 3 to 8. In some cases, the data for a grade (or more
than one grade)
On Tue, 2005-08-23 at 10:12 -0500, Greg Blevins wrote:
Hello,
I have struggled, for longer than I care to admit, with this seemingly
simple problem, but I cannot find a solution other than the use of
long drawn out ifelse statements. I know there has to be a better
way. Here is stripped
On Mon, 2005-08-22 at 12:58 -0400, [EMAIL PROTECTED] wrote:
I have used the 'par' command to
overlay one plot on another. But how
do I overlay it with the x-values
plotted at the same points on the
x-axis?
Thank you,
Steven
The specific answer depends to an extent on the graphics
On Wed, 2005-08-17 at 12:02 -0700, Martin Lam wrote:
Hi,
I am trying to use a vector of indices to select some
rows from a matrix. But before I can do that I somehow
need to convert 'combinations' into a list, since
'mode(combinations)' says it's 'numerical'. Any idea
how I can do that?
On Tue, 2005-08-16 at 13:18 -0400, Allan Strand wrote:
Hi All,
I'm trying to take a numerical vector and produce a new vector of the
same length where each element in the first is placed into a category
given by a 'breaks-like' vector. The values in the result should equal
the lower
On Mon, 2005-08-08 at 11:57 -0700, Kerry Bush wrote:
suppose I have the following data
x-c(rep(.1,5),rep(.2,6),rep(.4,10),rep(.5,20))
y-c(rep(.5,3),rep(.6,8),rep(1.2,8),rep(2.5,18),rep(3,4))
If I plot(x,y) in R, I will only get seven distinct
points. What I want to do is to use different
On Tue, 2005-07-26 at 08:58 +0700, [EMAIL PROTECTED] wrote:
Hello,
Is there any way to use plot() horizontally similar to
boxplot(., horiz=TRUE)? I want to use to illustrate
the distribution of y-values on an adjacent plot using
layout().
Thanks in advance for any help.
Regards,
On Tue, 2005-07-26 at 15:48 -0400, [EMAIL PROTECTED] wrote:
Hi,
I am looking for an elegant way to transform a vector into percentages of
values
that meet certain criteria.
store-c(1,1.4,3,1.1,0.3,0.6,4,5)
# now I want to get the precentages of values
# that fall into the categories
On Fri, 2005-07-22 at 16:26 +0200, Christian Bieli wrote:
Dear all
I've got some problems submitting a manuscript, because I can't
manage
creating the favourable eps-file of a graph created in R. The
journal's
graphic requirements are as followed:
format: eps
width: max. 6 inches
Ok guys,
So I played around with this a bit, going back to Dan's original
requirements and using Thomas' do.call() approach with legend(). Gabor's
approach using sapply() will also work here. I have the following:
# Note the leading spaces here for alignment in the table
# This could be
On Thu, 2005-07-21 at 16:18 +0200, Clark Allan wrote:
hi all
a very simple question.
i have plot(x,y)
but i would like to add in on the plot the observation number associated
with each point.
how can this be done?
/
allan
If you mean the unique observation number associated with
[Note: the initial posts have been re-arranged to attempt to maintain
the flow from top to bottom]
Dan Bolser writes:
I would like to annotate my plot with a little box containing the slope,
intercept and R^2 of a lm on the data.
I would like it to look like...
On Tue, 2005-07-19 at 17:29 +0200, Dirk Enzmann wrote:
Although I tried to find an answer in the manuals and archives, I cannot
solve this (please excuse that my English and/or R programming skills
are not good enough to state my problem more clearly):
I want to write a function with an
On Tue, 2005-07-19 at 12:28 -0400, Duncan Murdoch wrote:
On 7/19/2005 12:10 PM, mark salsburg wrote:
I have two files to compare, one is a regular txt file that I can read
in no prob.
The other is a .gct file (How do I read in this one?)
I tried a simple
read.table(data.gct,
On Tue, 2005-07-19 at 13:16 -0400, mark salsburg wrote:
ok so the gct file looks like this:
#1.2 (version number)
7283 19 (matrix size)
Name Description Values
... ..
How can I tell R to disregard the first two lines and start reading
the 3rd line in this
on the quotation marks..
thanks..
On 7/19/05, Marc Schwartz (via MN) [EMAIL PROTECTED] wrote:
On Tue, 2005-07-19 at 13:16 -0400, mark salsburg wrote:
ok so the gct file looks like this:
#1.2 (version number)
7283 19 (matrix size)
Name Description Values
On Tue, 2005-07-19 at 13:08 -0500, Marc Schwartz (via MN) wrote:
For the TAB delimited columns, adjust the 'sep' argument to:
read.table(data.gct, skip = 2, header = TRUE, sep = \t)
The 'quote' argument is by default:
quote = \'
which should take care of the quoted strings and bring
On Fri, 2005-07-15 at 15:40 -0500, David Groos wrote:
I'm trying to figure out R, a piece at a time, hours at a time... I
was trying to copy the sample function in, An Introduction to R (for
version 2.1.0) by W. N. Venables, D. M. Smith, page 42. Section 10.1
Simple examples provides a
On Thu, 2005-07-14 at 12:30 -0500, Deepayan Sarkar wrote:
On 7/14/05, Kerry Bush [EMAIL PROTECTED] wrote:
Thank you for thinking about the problem for me.
However, I have found that your method doesn't work at
all.
You may test the following example:
On Thu, 2005-07-14 at 15:08 -0500, Deepayan Sarkar wrote:
On 7/14/05, Marc Schwartz (via MN) [EMAIL PROTECTED] wrote:
On Thu, 2005-07-14 at 12:30 -0500, Deepayan Sarkar wrote:
On 7/14/05, Kerry Bush [EMAIL PROTECTED] wrote:
Thank you for thinking about the problem for me.
However, I
On Tue, 2005-07-12 at 16:22 +0200, ecoinfo wrote:
Hi R users,
Maybe the question is too simple.
In a IF ... ELSE ... statement if(cond) cons.expr else alt.expr, IF and
ELSE should be at the same line?
For example,
if (x1==12)
{
y1 - 5
}else
{
y1 - 3
}
is right, while
if
On Tue, 2005-07-12 at 14:37 -0300, Rogério Rosa da Silva wrote:
Dear list,
I will like to learn how to read a lower triangular matrix in R. The
input file *.txt have the following format:
A B C D E
A 0
B 10
C 250
D 3680
E 47
On Thu, 2005-07-07 at 11:47 -0400, [EMAIL PROTECTED] wrote:
Any ideas about the following problem:
I have a matrix (A) that looks like this:
gene_names values
hsa-mir-124 0.3
hsa-mir-234 0.1
hsa-mir-344 0.4
hsa-mir-333 0.7
On Thu, 2005-07-07 at 10:20 -0700, Mikkel Grum wrote:
I have a situation where I'm filling out a dataframe
from a database. Sometimes the database query doesn't
get anything, so I end up trying to place NULL in the
dataframe like below.
temp - NULL
xmat - as.data.frame(matrix(NA, 2, 3))
On Fri, 2005-07-01 at 19:40 +0800, ronggui wrote:
I write a function to get the frequency and prop of a variable.
freq-function(x,digits=3)
{naa-is.na(x)
nas-sum(naa)
if (any(naa))
x-x[!naa]
n-length(x)
ta-table(x)
prop-prop.table(ta)*100
res-rbind(ta,prop)
rownames(res)-c(Freq,Prop)
On Thu, 2005-06-30 at 23:05 +0200, [EMAIL PROTECTED] wrote:
Hi all,
- how can I do a barplot with rotated axis labels? I've seen the example for
just a plot in the FAQ, but I'll missing the coordinates to plot my text at
the right position beneath the bars.
Is there any (easy?) solution?
On Tue, 2005-06-28 at 13:03 -0400, ferdinand principia wrote:
Hi,
I need to calculate Kendall's tau for large data
vectors (length 100'000).
Is somebody aware of a faster algorithm or package
function than cor(, method=kendall)?
There are ties in the data to be considered (Kendall's
On Tue, 2005-06-28 at 17:23 -0400, Anna Oganyan wrote:
Dear List,
How can I convert a list with elements being character strings, like:
c(1,2,3,4), “c(1,3,4,2) … to a list with elements as numerical
vectors: c(1,2,3,4), c(1,3,4,2)…?
Thanks!
Anna
l - list(c(1,2,3,4), c(1,3,4,2))
l
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