Although I am not an expert in NLME modelling, looking at your data it
seems to me that there seems to be no growth pattern in it. Try
library(nlme)
library(reshape)
goat-read.table(clipboard, header=T)
str(goat)
'data.frame': 18 obs. of 15 variables:
$ NoC : int 52 48 54 60 58 42 44 47
...
aggregate(data$percentOld, list(data$state, data$county), topN)
Error in aggregate.data.frame(as.data.frame(x), ...) :
'FUN' must always return a scalar
Thanks
cn
From: Petr PIKAL [mailto:[EMAIL PROTECTED]
Sent: Fri 8/31/2007 8:15 AM
To: Cory Nissen
Cc: r-help@stat.math.ethz.ch
Hi
mapply(+, a, b)
Regards
Petr
[EMAIL PROTECTED] napsal dne 03.09.2007 08:36:10:
I want to try to get a result of element wise addition between a
vector and a list. It can be done with for statement. In order to
reducing computing time, I have tried to avoid for state. If anybody
give me
Try:
boxplot(mLength ~ puntar[drop=T],data=test)
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O
On 30/08/2007, Luis Ridao Cruz [EMAIL PROTECTED] wrote:
R-help,
I'm trying to do a simple box-and-whisker plot to some data.
The data are a subset of
Hi
I am working with census data. My columns of interest are...
PercentOld - the percentage of people in each county that are over 65
County - the county in each state
State - the state in the US
There are about 3100 rows, with each row corresponding to a county
within a state.
I
[EMAIL PROTECTED] napsal dne 28.08.2007 13:33:13:
You don't have installed the akima pakage.
install.packages(akima, dep=T)
And wait about two months and update your R version to 2.6.0. Or update
now to 2.5.1
Regards
Petr
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40
Hi
[EMAIL PROTECTED] napsal dne 22.08.2007 09:10:26:
Hello,
I created a simple scatter diagram:
x= c(53, 52, 55, 65, 71, 69, 75, 78, 88, 70)
y= c(162, 165, 165, 171, 173, 175, 179, 181, 184, 176)
plot(x, y)
Now I would like to display the mean on that diagram.
do you think
Hi
[EMAIL PROTECTED] napsal dne 21.08.2007 17:07:05:
I have found the error in my script which was semi-automatically
translated
from the other person's MATLAB code.
The error is that c was assigned a value inside a function.
That is the function body contained the following
Hi
you do not give much information, even subject line is missing. Try to
follow posting guide and try to explain what you did and how did you fail.
Regards
Petr
[EMAIL PROTECTED] napsal dne 16.08.2007 17:24:24:
hi,
i'm new to R and i'm trying to port a quattro pro spreadsheet into R.
Thank you.
I will try to get the book, althoug I am not sure if I with my tiny
knowledge of mathematics will be able to digest it.
Meanwhile I tried to make 7 min average and then to reanalyze by spectrum,
but the output was not very convincing.
Regards
Petr Pikal
[EMAIL PROTECTED]
Rolf
Hi
for this particular task
rowSums(cbind(a,b), na.rm=T)
gives you c column
Petr
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne 16.08.2007 13:03:51:
Hi All,
I have 2 data frames as follows:
abc
1 NA 1
2 NA 2
NA 3 3
So a, b are the input values and c
regards
Petr Pikal
[EMAIL PROTECTED]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained
Hi
Not being a trained statistician regression with slope = 0 seems odd to
me.
If you do
fit-lm(d~t)
summary(fit)
Call:
lm(formula = d ~ t)
Residuals:
123456
0.04762 -1.43810 0.07619 1.59048 2.10476 -2.38095
Coefficients:
Hi
[EMAIL PROTECTED] napsal dne 14.08.2007 15:11:11:
Hello,
I would like to do a large number of e.g. 1000 paired ttest using the
by-
function. But instead of using only the data within the 1000 groups, R
caclulates 1000 times the ttest for the full data set(The same happens
with
Hi
[EMAIL PROTECTED] napsal dne 13.08.2007 14:04:50:
Dear all,
I have 4 sites and want to determine how different they are from each
other.
For this I have decided to use R though it seems a bit daunting to
learn.
I have read data in from a CSV the structure is :
Species1
Hi
[EMAIL PROTECTED] napsal dne 10.08.2007 13:41:53:
Dear R Help,
I have a set of data of heights of trees described by area that they are
in.
The areas are numerical (0 to 7).
htarea
1 320 3
2 410 4
3 230 2
4 360 3
5 126 1
6 280 2
7 260 2
8
Hi
mat-sample(c(-50,0,-100), 100,replace=T)
dim(mat)-c(10,10)
mat
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
[1,]0000 -500000 0
[2,] -100 -100 -50 -5000 -100 -50 -100 -50
[3,]0 -50 -100 -1000 -50 -10000 -100
Hi
your construction is quite complicated so instead of refining it I tried
to do such task different way. If I understand what you want to do you can
use
set.seed(1)
T - matrix(trunc(runif(20)*10), nrow=10, ncol=2)
T
[,1] [,2]
[1,]22
[2,]31
[3,]56
[4,]
Hi
Far from beeing an expert I can decide from your post that you probably
mix R objects matrix x data frame x list. All of them have specific
features and you sometimes cannot convert one to another easily. See what
your objects are and how they look like by e.g.
str(X1)
or mode or typeof
I
Hi
[EMAIL PROTECTED] napsal dne 04.08.2007 15:04:56:
Hi,
I am sorry
I meant:
mod - lm(y~Worktime+Vacation+Illnes+Bankholidays)
newdate=data.frame(x=c(324,123,0.9,0.1))
your data frame shall have correct column names (Worktime, Vacation, ...)
Regards
Petr
Hi
[EMAIL PROTECTED] napsal dne 04.08.2007 07:49:16:
Well, R has a by() function that does what you want, and its help page
contains an example of doing regression by group.
(There are other ways.)
E.g. you can split your data into list
d.s - split(data, data$site)
and then use lapply
Hi
[EMAIL PROTECTED] napsal dne 06.08.2007 11:41:56:
hello,
I wanna calculate some variances for the bartlett test and I used the
var()
function but I think it isn't a good estimation for the variance I don't
understand why.
In fact when I calculate the variances by myself I don't find
=, to be
on safe side I use - everywhere when I want to do assignment of some
value(s).
Regards
Petr
Regards,
Dong
On 7/31/07, Petr PIKAL [EMAIL PROTECTED] wrote:
Hi
as you say that the computing is part of a function than the best way to
see what is hapenning is to use
debug
Hi
as you say that the computing is part of a function than the best way to
see what is hapenning is to use
debug(your.function)
see ?debug for options.
Regards
Petr
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne 31.07.2007 00:11:00:
Dear all,
here are two arrays: region(26,31,8),
Hi
[EMAIL PROTECTED] napsal dne 30.07.2007 12:09:59:
Dear everyone,
I've got difficulties in realizing the following
task:
I have two vectors:
A - c(1:10)
B- seq(1,10,2)
Now I want to make a table form vectors A and B as rows, and if a value
of A
isn't present B, then I want to
Hi
[EMAIL PROTECTED] napsal dne 28.07.2007 02:18:33:
Dear useR,
I have a data matrix, it has n columns, each column is a two-level
variable
with entires -1 and +1. They are randomly generated, now I want to order
them like (for example, 5 columns case)
--- - -
-- - -
Hi
I am not sure about using loops but something like
colSums(combn(DATA[,1],2))
gives you sums of all pairs and
colSums(combn(DATA[,1],3))
sums of all triplets
etc.
if you want to know which ones they are just use combn on names.
e.g.
y
X1.5
a1
b2
c3
d4
e5
Hi
this particular graph is a combination of several approaches
see
layout # how to split plot window (or ?split)
par(new=TRUE) # how to plot several times to the same window without
erasing previous plot
and of course sophisticated use of all other stuff which is available in
R.
See also
Hi
[EMAIL PROTECTED] napsal dne 25.07.2007 12:17:54:
Hi Sir
I did not find any function of graph which plot one variable on x-axis
and 2
or more than 2 variables on y-axis.
?matplot
or you can do
plot(x,y, ylim=range(all.your.y), type=n)
and add lines/points by
lines(x, one.of.your.y)
Hi
you definitely shall make a quick glance to some documentation which comes
with R e.g. R intro manual. Or look at CRAN where is quite impressive
amount of literature from basic stuff to advanced papers.
To your question:
[EMAIL PROTECTED] napsal dne 25.07.2007 14:23:58:
Hello,
I'am
Hi
far from beeing an expert in graphic devices AFAIK you can either see your
graph on screen (x11 device) or to open other device (pdf, png, ...) and
to issue plotting commands to that device. Do not forget
dev.off()
after your plot is finished.
Or you can save your plot by menu command
Hi
if you change your code
plot(1,10, xlim=range(0,3), ylim=range(0,10), type='n')
aa - rep(1,10)
bb - 1:10
plot(aa,bb, xlim=range(0,3), ylim=range(0,10), new=TRUE)
aa - rep(2,10)
par(new=T)
plot(aa,bb, xlim=range(0,3), ylim=range(0,10), new=TRUE)
you will get both columns plotted.
However you
Hi
try to look at R2HTML package, it can produce report like output.
Petr
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne 02.07.2007 11:08:46:
Hi,
I would like to know whether anybody knows a simple way to combine
textual and graphical output in R.
A typical analysis produces textual
, character) but in data framwe you can mix
columns with different types.
Regards
Petr Pikal
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne 28.06.2007 20:12:49:
You actually got it right.
I didn't realize there was a difference between a data frame and
matrix. What is the difference any
Hi
[EMAIL PROTECTED] napsal dne 27.06.2007 15:43:53:
Thank you, but it still doesn't work completely
Thanks to you and the dec=, option, I can now do cours[5,5]*5 and
get the
exact value
But I still cannot do matrix operations like cours[2,]%*%cours[5,]
As only you have cours we can
Hi
as you did not specify your code (which you said it had failed) I try to
give you a suggestion how I would do such tasks.
for (i in 1:100) {
sample(something, no, replace =TRUE)
result -perform a test
store.a result[i] - result
}
Regards
Petr
[EMAIL PROTECTED] napsal dne 26.06.2007
[EMAIL PROTECTED] napsal dne 20.06.2007 18:02:07:
Hello,
ok I know how to do to merge matrix or data.frame by row.names but my
true
objectif is to merge for example this data.frame:
A
obs
Rép1 Rép2 Rép3 Rép4 Rép5 Rép6
Var1 145 145 150 145 140 145
Var2 150 150
Hi
you can use tail
tail(data, -95)
gives you all but first 95 records.
Regards
Petr Pikal
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne 20.06.2007 12:47:11:
Dear R users,
just another little question... are there other ways, I mean more easy
to
write, to obtain the same result I got
Hi
It often depends on your attitude to limits for outlying observations.
Boxplot has some identifying routine for selecting outlying points.
Any procedure usually requires somebody to choose which observation is
outlying and why. You can use e.g. all values which are beyond some
threshold
[EMAIL PROTECTED] napsal dne 19.06.2007 12:23:58:
Hi
It often depends on your attitude to limits for outlying observations.
Boxplot has some identifying routine for selecting outlying points.
Any procedure usually requires somebody to choose which observation is
outlying and why. You
row.names(d.m) - whatever vector of names you can elaborate
Regards
Petr Pikal
[EMAIL PROTECTED]
BTW. R is not C and you shall use strong features of R not to try to avoid
them.
[EMAIL PROTECTED] napsal dne 18.06.2007 15:40:38:
hello,
I'm trying to write a function which take a matrix and give
Hi
[EMAIL PROTECTED] napsal dne 11.06.2007 14:09:45:
Dear R users,
I have a correlation matrix for a dataframe called synth, for which I
now want to select only those cells that have correlations larger than
+/-0.6:
synth=data.frame(x=rnorm(10,1),y=rnorm(10,2),z=rnorm(10,0.5))
[EMAIL PROTECTED] napsal dne 06.06.2007 10:56:18:
thanks, that works great!!
just have another thing...i the same area
What if the class is list instead of array, how can you name the first
unrecognized column?
Hi
look in some intro manual and learn about R data structures. Matrix,
Hi
If I understand correctly, use split and sample with lapply. If DF is your
dataframe
lapply(split(DF$Tree, DF$Plot), function(x) sample(x,1))
shall select random tree from each plot. Or you can get it in tabular form
with sapply.
Regards
Petr
[EMAIL PROTECTED] napsal dne 05.06.2007
Hi
If I understand correctly, use split and sample with lapply. If DF is
your dataframe
lapply(split(DF$Tree, DF$Plot), function(x) sample(x,1))
shall select random tree from each plot. Or you can get it in tabular
form with sapply.
Regards
Petr
Sorry, you shall use resample from
Hi
If you have tried to go through help pages of max you could find out which
function, which can tell you position of your maximum.
which(x==max(x), arr.ind=T)
Regards
Petr Pikal
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne 01.06.2007 11:09:09:
Dear UseRs,
I have a very simple question
Hi
[EMAIL PROTECTED] napsal dne 31.05.2007 12:48:11:
Is it possible to have one?
I have a data.frame with two character columns and 6 numerical columns.
I converted to a matrix as I needed to use the col() and row()
functions.
However, if I convert the data.frame to a matrix, using
))
}
Is there any reason why these won't work? Am I oversimplifying it?
Seems to me that both works. At least on data.frame I tried it.
Regards
Petr
Mick
-Original Message-
From: Petr PIKAL [mailto:[EMAIL PROTECTED]
Sent: 31 May 2007 12:57
To: michael watson (IAH-C)
Cc: r-help
Hi
[EMAIL PROTECTED] napsal dne 29.05.2007 12:53:14:
Dear all,
I'd like to produce a simple pie chart for a customer (I know it's bad
but
they insist), and I have some difficulties setting the initial angle.
For example:
pie(c(60, 40), init.angle=14)
and
pie(c(80, 20),
From simple geometry
pie(c(x, y), init.angle=(300+y/2*360/100)-360)
shall do what you request. Although I am not sure if it is wise.
Regards
Petr
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne 29.05.2007 13:30:06:
Hi
[EMAIL PROTECTED] napsal dne 29.05.2007 12:53:14:
Dear all,
Hi
problem is with your extra empty levels in your d factor. Without it
d1-factor(d, exclude=NULL)
d1
[1] ABNA NA BCABCABCAB C
ABCABCABCABCABC
Levels: A B C NA
table(b,d1)
d1
bA B
Hi
One possibility is to use scan with combination of skip and nlines
parameters in a body of for cycle and adding read portion to some suitable
object.
Regards
Petr
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne 23.05.2007 19:38:33:
Dear All,
I am on WindowsXP with 512 MB of RAM, R
[EMAIL PROTECTED] napsal dne 15.05.2007 08:41:27:
Dear all,
I would need a function which convert small letter into capital letter
(at
least the first letter of a character variable).
Does such a function exist in R ?
?toupper, ?tolower
Regards
Petr
Thanks by advance
Jessica
Hi
[EMAIL PROTECTED] napsal dne 15.05.2007 16:39:20:
Hi,
I am very new to R. I am trying to perform an Anova Test and see if it
differs or not.
Basically, i have 4 tests and 1 control.
Tester
Test1 Test2 Test3 Test4 Control
20 25 1510 17
The
[EMAIL PROTECTED] napsal dne 15.05.2007 17:32:35:
Thank you Guys.
Let say that from Test1 to control i have multiple data
Tester
Test1 Test2 Test3 Test4 Control
20 25 1510 17
. . . . .
. . .
Hi
[EMAIL PROTECTED] napsal dne 10.05.2007 17:59:22:
or
with(foo, (x y) * (x z))
Should not it be
with(foo, ((x y) | (x z))*1)
Regards
Petr
On 5/10/07, jim holtman [EMAIL PROTECTED] wrote:
You don't need apply. Just do
foo$result - ifelse((foo$x foo$y) | (foo$x
Hi
[EMAIL PROTECTED] napsal dne 11.05.2007 11:30:28:
Hello
I have a problem.
I have a plot, and have made the writing larger with cex.axis and
cex.lab, and
i is working great, BUT the writing is bigger than the window... for
example,
the y-axis writing misses the top of all letters.
Hi
[EMAIL PROTECTED] napsal dne 11.05.2007 11:12:21:
Hi,
I was trying to run the example of Indomethacin kinetics from the book:
## From Pinheiro/Bates, Mixed-Effects-Models in S and S-Plus,
## Springer, Second Printing 2001, Section 6.2
library(nlme)
plot(Indometh)
fm1Indom.nls -
Hi
[EMAIL PROTECTED] napsal dne 10.05.2007 11:08:31:
hi,
I have this error
tr - sample(1:50, 25)
train - rbind(iris3[tr,,1], iris3[tr,,2], iris3[tr,,3])
test - rbind(iris3[-tr,,1], iris3[-tr,,2], iris3[-tr,,3])
cl - factor(c(rep(s,25), rep(c,25), rep(v,25)))
z - lda(train, cl)
Hi
without knowing your code, R version and error message it is hard to say
what is wrong. I think I answered already this or similar question but
nevertheless:
If your data are in data frame
ifelse(mm$censoringTimemm$survivalTime,mm$survivalTime, mm$censoringTime)
gives you a vector of
[EMAIL PROTECTED] napsal dne 02.05.2007 16:47:55:
It was suggested that the 'NAs introduced by coercion' message might be
warning me that my data are not what they should be. I checked this
using
str(PeaksMatrix), as suggested, and the data seem to be what I thought
they
were:
Hi
Did you see FAQ 2.16?
Try file.choose()
Regards
Petr
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne 03.05.2007 02:26:27:
Hi,Dear R users, I have a file text nommed chif which contains 16
lines and
4 columns in the disc dur. I have a difficulty to read this file in R
console
I have
Hi
[EMAIL PROTECTED] napsal dne 03.05.2007 10:33:22:
Hello
i have a plot, and want the axis too be with larger writing, i found
some
functions but they didnt work
this is my plot, and if the axis can be with bigger writing can the
legend
inside the plot be in same the size??
Hi
[EMAIL PROTECTED] napsal dne 03.05.2007 14:01:27:
hi,
I have a problem to use union function because one of the elements is a
character and the others are numeric
for(j in 1:length(I)) {
+ C1 - levels(factor(subset(donParEssai, Id_Essai == 1006961 Id_Cara
==
I[j], select =
Hi
[EMAIL PROTECTED] napsal dne 02.05.2007 14:11:51:
hello,
I need help because I don't understand the syntaxe else how can I
write it
for example I writed a script to cut missings values and I have errors
if(na==length(C)){
+ pos=match(0,match(donGeno[[na-1]],donGeno[[na]],nomatch=0))
Hi
[EMAIL PROTECTED] napsal dne 01.05.2007 09:03:46:
Hello
I would like to simulate datasets in the following way:
x - rpois(999, 2000)
y - sum(exp(rgamma(x, scale=2, shape=0.5)))
You computed sum of your 999 values. Regardless of how many values are
summed the result is always only
Hi
see ?ifelse
ifelse(censoringsurvival, survival, censoring)
Regards
Petr
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne 01.05.2007 13:25:18:
l have the following dataset and would like to calculate the actual
survival time by
if censoring time survival time then actual survival time
steps)
BTW split(don[, some.columns], don$Id_Cara) could maybe do what you want
without using for cycle
Regards
Petr Pikal
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne 24.04.2007 11:48:48:
I wanna display some data which there are subsets of a dataframe called
don
but there are errors
Hi
look at aggregate
something like
mymean-aggregate(mydata[,4:5], list( location, Spezies), mean)
mysd-aggregate(mydata[,4:5], list( location, Spezies), sd)
and then cbind(appropriate columns of resulting data frames)
Petr Pikal
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne
Hi
had you consider to look at help page? How do you expect your written file
to be named?
From help page
write is a wrapper for cat, which gives further details on the format used
cat is useful for producing output in user-defined functions. It converts
its arguments to character strings,
very simple solution to it which I overlooked and
examples in help page did not help me to find it.
Thank you
Best regards
Petr Pikal
[EMAIL PROTECTED]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
Thank you all for your working solutions
Petr Pikal
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne 18.04.2007 13:26:36:
A backreference is contained in parentheses and there are no parentheses
in your regular expression, hence the error message.
Its probably easiest just to remove all non
[EMAIL PROTECTED] napsal dne 16.04.2007 14:52:55:
Hi,
This is a very basic question, but apparently I am too stupid for it.
I have a large matrix A, and I need to avoid for loops. How could I
apply a function f(a,r,c) on each element of A, using the subscript (row
and column) of a as
Hallo
[EMAIL PROTECTED] napsal dne 11.04.2007 22:45:19:
Hi
I am very new to R and have not able to find the answer to my question
in the manual or any other post. I have a dataset that has various
different sites names with data relating to each site. The data is in
one dataset. I want
probably want. And if you have different matrix size
then
1:dim(your.matrix)[1]
can give you suitable sequence.
Regards
Petr Pikal
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne 12.04.2007 10:55:21:
Greetings list,
I have a rectangular 20 x 20 matrix with values in the range of [0 ,
1]. I'd
AT is not at.
Regards
Petr
Petr PIKAL wrote:
Hi
[EMAIL PROTECTED] napsal dne 09.04.2007 22:10:22:
I want to produce some boxplots and plot the logged values but have
the
axis scale in the original, not-logged scale. It seeming like I have
the
first few steps but I'm
Hallo
Seems to me that you can make a summary table using
aggregate(RESPONSE, list(TREATMENT, MEASUREMENT, BLOCK, STUDY), mean)
and then if you want you can use reshape function or melt/cast function
from reshape package to get wide form of your table.
Regards
Petr Pikal
[EMAIL PROTECTED
Hi
[EMAIL PROTECTED] napsal dne 09.04.2007 22:10:22:
I want to produce some boxplots and plot the logged values but have the
axis scale in the original, not-logged scale. It seeming like I have the
first few steps but I'm having trouble with the last. Here's what I'm
doing (which I got
Hi
isnt it a homework?
FYI see
?list
?vector
?data.frame
?sample
?lapply
and some basic stuff like Introduction manual provided with your R
instalation to see how some simple data manipulations can be done.
Regards
Petr Pikal
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne 05.04.2007 05:58
files. Other posibility is to use RODBC - see Data
Export/Import manual.
If you want to write some data and use it in Excel they shall be in matrix
or data.frame form and use
write.table(, sep=\t, row names= FALSE). The file can be directly
used by Excel.
Regards
Petr Pikal
[EMAIL PROTECTED
Hi
[EMAIL PROTECTED] napsal dne 05.04.2007 12:50:09:
Dear R-experts,
I still have problems with the reading of a matrix.
Input: matrixData6.txt
A-Paar B-Paar C-Paar D-Paar E-Paar
A 1 3 5 7 9
B 2 4 6 8 10
R-commands:
[EMAIL PROTECTED] napsal dne 05.04.2007 15:24:57:
Hallo,
does a package for Matlab exist in R?
You probably could get quicker answer trying to use some search
posibilities provided by CRAN. In first few hits from Rseek there is a
package R.matlab. I hope it can be installed by a standard
Hi
do.call(cbind, your.list) # or rbind
gives you rectangular matrix, however shorter items in list are recycled
as necessary. Problem is that you need to specify how shall be shorter
items handeled as it is not obvious. One possibility could be add NAs to
positions where you want them, what
Petr Pikal
[EMAIL PROTECTED]
- Postoupil do Petr PIKAL/CTCAP dne 30.03.2007 15:47 -
Petr PIKAL/CTCAP napsal dne 30.03.2007 15:01:58:
Hi
Do you mean rounding. If yes you can consult
?round, ?floor, ?ceiling.
If you want just to print different amount of digits you can look
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PLEASE do read the posting guide
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minimal, self-contained, reproducible code.
Petr Pikal
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PLEASE do read the posting guide
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Petr Pikal
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PLEASE do read the posting guide http://www.R
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Petr Pikal
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PLEASE do read the posting guide
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Petr Pikal
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, reproducible code.
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html and provide commented,
minimal, self-contained, reproducible code.
Petr Pikal
[EMAIL PROTECTED]
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, reproducible code.
Petr Pikal
[EMAIL PROTECTED]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self
@stat.math.ethz.ch mailing list
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PLEASE do read the posting guide
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Petr Pikal
[EMAIL PROTECTED]
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R
, reproducible code.
Petr Pikal
[EMAIL PROTECTED]
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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read the posting guide
http://www.R-project.org/posting-guide.html and provide commented,
minimal, self-contained, reproducible code.
Petr Pikal
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PLEASE
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PLEASE do read the posting guide
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=format))
}
if(yylab[2]==)
mtext(deparse(substitute(yleft)),side=2,line=2, col=col[2], ...)
else
mtext(yylab[2],side=2,line=2, col=col[2], ...)
if (linky) lines(x,yleft,col=col[2], lty=2, ...)
if (smooth!=0) lines(supsmu(x,yleft,span=smooth),col=col[2], lty=2,
lwd=lwds, ...)
}
Petr Pikal
[EMAIL
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