Dan E. Kelley writes:
Q: Has anyone implemented cartograms [**] in R? A search on the R
site turned up
https://stat.ethz.ch/pipermail/r-sig-geo/2005-December/000698.html
--snip--
and for some elegant examples for election results, see
http://www-personal.umich.edu/~mejn/election
I don't
Dan E. Kelley writes:
Q: Has anyone implemented cartograms [**] in R? A search on the R
site turned up
https://stat.ethz.ch/pipermail/r-sig-geo/2005-December/000698.html
--snip--
and for some elegant examples for election results, see
http://www-personal.umich.edu/~mejn/election
I
From Windows RGui, I tried:
example(plot)
This worked as expected except that the various plots write over top of each
other in the graphics window that is created. I then discovered that graphics
history is not enabled during the example generation.
I used the graphics window menu to
- Original Message -
From: Kort, Eric
Lisa Wang asks...
Subject: [R] How to produce this graphic
Hello there,
I would like to produce a plot of x-c(4,5,6),which is the mean of
each
group and y-c('groupA','groupB','groupC').
plot (x,y) can not produce any graphics because y is not
On Wed, 4 Jan 2006, Roger Bivand wrote:
Could I ask for comments on:
source(url(http://spatial.nhh.no/R/etc/capabilities.R;), echo=TRUE)
as a reproduction of the Stata capabilities session? Both the t test
and
the chi-square from our side point up oddities. I didn't succeed on
This might get you started:
# make data in original format
a=matrix(1:48,12,4)
colnames(a)-c('var1','var2','var3','var4')
rownames(a)-c('a1','a2','a3','b1','b2','b3','c1','c2','c3','d1','d2','d3')
a
#rehape the data
a=data.frame(a)
reshape(a[1:4],idvar=row,
Does this do what you want?
coplot(myvar~myvar | myvar, show.given=FALSE, ylab=, xlab=c(...,A
Title on Top))
Rob
- Original Message -
From: Mihai Nica [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, November 26, 2004 11:30 AM
Subject: [R] Coplot Given text
Greetings:
I am
I went through the following steps using RGUI menus to install gregmisc from
CRAN. It appears to install but at the end R does not seem to be able to
find it. Any idea what I'm doing wrong?
Thankjs,
Rob
local({a - CRAN.packages()
+
not clarify the interaction with the RGUI install procedure for
me.
Thanks again.
Rob
-
- Original Message -
From: Peter Dalgaard [EMAIL PROTECTED]
To: Robert W. Baer, Ph.D. [EMAIL PROTECTED]
Cc: R-Help [EMAIL PROTECTED]
Sent: Wednesday, November 24
It depends on whether you want to do 95% ocnfidence intervals on the
predicition or the mean vital capacity. Try the following and see if it
gets you started:
#Simulate data
height=48:72
vc=height*10+20*rnorm(72-48+1)
# Do regression
lm.vc=lm(vc~height)
# Confidence interval on mean vc
Sorry. The last code line got destroyed by my emailer and should read:
matlines(height,predict.lm(lm.vc,interval=p),
+ lty=c(1,3,3),col=c('black','red','red'))
- Original Message -
From: Robert W. Baer, Ph.D. [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, November 24, 2004 4
Sorry if this was not clear. This is more of a theoreticla question
rather than a R-coding question. I need to calculate
The predicted response and 95% prediction interval for a man of average
height
So I need to predict the average response, which is easily done by taking
the mean height
Uwe Ligges [EMAIL PROTECTED] writes:
Somehow PD got right justified columns with this dataset. Is there a new
way of doing things in version 2.0.0, my ignorance, a bug? I tried making
the columns factors first, but in my hands this did not appear to help
either. Thanks for any insight.
month10
day 04
language R
___
Robert W. Baer, Ph.D.
Department of Physiology
A. T. Still University of Health Science
800 W. Jefferson St.
Kirksville, MO 63501-1497 USA
[[alternative HTML version deleted
The SPSS *.SAV file, when I opened it, proved not to have any data in it.
It only contained the variable view not the data view. But the Excel
file appears to contain the data.
My experience with getting spss files suggests that you might actually be
seeing the file as a list. Look at help
You might find it easier to do this type of thing with an open-source image
analysis program such as ImageJ: http://rsb.info.nih.gov/ij/
Rob
- Original Message -
From: Doug Bourne [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, August 13, 2004 1:10 PM
Subject: [R] cell counting
Not to put too fine a point on it, but did you consider checking the
NEWS file for the most recent version (1.9.0,
http://cran.r-project.org/src/base/NEWS)?
o The cor() function did not remove missing values in the
non-Pearson case.
There is still something a little strange
You want to read the help ?segments. Try the following to get the barplots:
ymean=c(1.25,2.65,3.45)
ysd=c(0.35,0.65,0.50)
xpos=barplot(ymean,ylim=c(0,max(ymean)+max(ysd)),col='yellow')
segments(xpos,ymean-ysd,xpos,ymean+ysd)
HTH,
Rob Baer
- Original Message -
From: Matteo Vidali
From: Christophe Declercq [EMAIL PROTECTED]
Try:
plot(1:10,xlab=expression(phantom(0)^{14}*C))
Just out of interest, how do I find out what phantom(0) does? I tried both
?phantom and help.search(phantom) without getting any hits, and yet the
expression posed above creates a leading blank
All the numeric output looks OK, but the statement that the alternative
hypothesis is accepted seems rather strange.
I think you misread it. It says alternative hypothesis: true mean is not
equal to 0
which should be read as alternative hypothesis: true mean is not equal
to 0
not
P.S. Here is just the input if you want to try it yourself by copying
and pasting into an R session:
If you are using Windows RGUI and you haven't noticed the new Paste
commands only in the Edit menu of R1.9.0, check it out. It is a fantastic
time saver.
Rob
How about:
as.numeric(t.test(rnorm(12))[[1]])
- Original Message -
From: Chuck Cleland [EMAIL PROTECTED]
To: christopher ciotti [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Friday, April 16, 2004 6:25 PM
Subject: Re: [R] t.test formatting question
Sorry, I should have checked
Well I must say that I am still struggling to understand exactly how fdim
works, and what form the first argument is to take. Presumably the function
produces something like 1-slope for a log log plot as a fractal dimension.
I guess it is really the makeline() function I don't understand from the
Here's one simplistic solution, perhaps there are better ones:
# Make some test data and place in dataframe
x1=rnorm(20)
x2=rnorm(20)
x3=rnorm(20)
x4=as.factor(sample(c(G1,G2,G3),20,replace=T))
y1=2*x1+4*x2+0.5*x3+as.numeric(x4)+rnorm(20)
df=data.frame(y1,x1,x2,x3,x4)
# Now create the ouput
Marko,
Looks fine to me. Why do you think the syntax is incorrect? Works for me in
1.8 on Windows.
I have a function I repeatably call which takes input parameters and
outputs columns to various data frames.
Looks fine to me although it is not completely clear that your request for
column and
In a (off-list) response to a question of frequency polygons, Dr Paul
Murrell writes:
There's an ann arg which you can use to turn off the default labels
(ann=FALSE). Have you seen help(plot.default) as well as help(plot)?
Thank you again, Paul. Interestingly, the ?plot help contains no
Martin Maechler writes:
It seems that this needs to be documented, since you are right,
the1 - 6 S(d^2) / (n^3 - n)( d = r1 - r2 ; r{12} := rank(x{12}) )
formula is also in use as *definition* for Spearman's rank correlation.
Since this topic is here...
Although I seen the above
I can't figure out how to get the x-axis to contain the category lables for
my frequency polygon. I'm also not sure if there is a more elegant
approach. Any insights on the labels?
I tried this:
#generate some pseudo data
x=c(sort(sample(1:1500,5)),sort(sample(1:1500,3),dec=T))
# assign names
This might get you started on reading and plotting the dates and times for
levels of a gender factor:
# I assume the following Excel data
date time Sex Value
1 5/5/1999 10:00:00 male 14.987685
2 7/3/1998 20:00:00 female 17.667527
3 8/6/1999 3:23:00 male 3.428401
4 12/7/1997 6:36:00 male 14.977503
On Fri, 5 Mar 2004 09:09:19 -
Simon Fear [EMAIL PROTECTED] wrote:
How great is the demand? I was a translator before I became
a statistician but I think this would be a massive undertaking ...
In the version of the site at: http://zoonek2.free.fr/UNIX/48_R/all.html ,
the author makes
I guess I'm not understanding the object that get.hist.quote makes. In
general, what are R facilities for discovering what a given object is?
I suggest, you study first one of the beginners manuals of the R
environment: http://cran.r-project.org/manuals.html
Then you would easily see that,
Look at:
?plot
?points
- Original Message -
From: Raphael Schoenle [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, March 01, 2004 4:35 PM
Subject: [R] superimposing two scatterplots
Hi,
How can I plot two scatterplots on the same, one panel?
I have two times series (price data
The problem would seem to be that the Windows GUI does not accept the TAB
key as input. There is no whitespace between your values to be recongnized.
Take your sequesnce and save it as a tab separated file in Excel or through
Notepad, and you will be able to scan it in just fine using
The read.spss parameter defaults are:
use.value.labels=TRUE,
to.data.frame=FALSE,
Is there some reasoning other than historical for this choice? In most
instances, it seems that the opposite default choice
(use.value.labels=FALSE, to.data.frame=TRUE,) would better preserve any
existing
For documentation type: ?win.metafile
It is in the base package with the following layout:
win.metafile(filename = , width = 7, height = 7, pointsize = 12)
Rob
- Original Message -
From: Fulvio Copex [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Saturday,
You should make your missing value indicator something other than your
separator indicator:
1. Use a text editor to indicate all missing values as NA or
2. Use a text editor to replace the 3 separator spaces with, for example, a
comma or semicolon and use the argument sep=, or sep=; which
I have seen several posts (but few answers) in R-help search as to whether there are
any packages that use R to process digital images. There are several categories
related to the general type of problem that are useful to know about:
-- Any existing packages for taking a digital image format
Hi list,
I'd like to make a factor with seven 1s and three 2s using the
factor() function.
That is,
1
1
1
1
1
1
1
2
2
2
I will then bind this factor to the matrix below using cbind.data.frame().
0.56 0.48
0.22 0.59
0.32 0.64
0.26 0.60
0.25 0.38
0.24 0.45
0.56 0.67
0.78
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