, Sébastien wrote:
Dear R-users,
I would like to add a legend at the bottom of pairs plots (it's my first
use of this function). With the plot function, I usually add some
additional space at the bottom when I define the size of the graphical
device (using mar); grid functions then allows me
Asteman
--
R version 2.4.0 (2006-10-03)
Copyright (C) 2006 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
R is free software and comes with ABSOLUTELY NO WARRANTY.
You
How can I change the tick marks in a boxplot so that they lie on the
inside of the x and y axes? In plot I have been setting tcl=0.2 but
that doesn't do anything in boxplot. What am I missing?
Thanks,
Emily
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PROTECTED] På vegne af Werner Wernersen
Sendt: 27. august 2007 15:21
Til: r-help@stat.math.ethz.ch
Emne: Re: [R] Column naming mystery
Sorry that the problem description was not sufficient.
Here is a self-contained code replicating the problem:
require(doBy)
x -
as.data.frame(matrix(ncol=3,seq(1,12
, Ltd.URL: http://lcfltd.com/
824 Timberlake Drive Tel: 757-467-0954
Virginia Beach, VA 23464-3239Fax: 757-467-2947
Vere scire est per causas scire
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a constant term,
since the first equation of X'e = 0 gives in this case sum(e)=0.
For decomposing the TSS (y'y) into ESS (b'X'Xb) and RSS (e'e), which is
needed to compute R², you will need X'e=0, because then the
cross-product term b'X'e vanishes.
Correct me if I'm wrong.
Leeds, Mark (IED) schrieb
On 28 August 2007 at 08:04, Frank E Harrell Jr wrote:
| Wentzel-Larsen, Tore wrote:
| Thanks,
| I use Design version 2.1-1 (and as provided, R 2.5.1 on Windows XP).
|
| Sorry I missed the latter.
|
| The redundancies in object names were for my own convience, as part of
| a larger command
Wentzel-Larsen, Tore wrote:
Thanks,
I use Design version 2.1-1 (and as provided, R 2.5.1 on Windows XP).
Sorry I missed the latter.
The redundancies in object names were for my own convience, as part of
a larger command file, and the validation of this univariate model was
only included
Hi,
thank a lot for your answers!
As other people get the correct result but I get this
mysterious result with this script even after running
it on a freshly started R, it must be a problem with
my particular R setup. I'll try updating.
Thanks for the help, now I know where I have to
search
The Netherlands
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[EMAIL PROTECTED] napsal dne 28.08.2007 13:33:13:
You don't have installed the akima pakage.
install.packages(akima, dep=T)
And wait about two months and update your R version to 2.6.0. Or update
now to 2.5.1
Regards
Petr
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40
and Bioinformatics
Leiden University Medical Center
Postzone S-05-P
P.O. Box 9600
2300 RC Leiden
The Netherlands
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On 28-Aug-07 14:12:22, Marie Anouk Simard wrote:
It would seem (from the headers) that Marie sent her message
within a TNEF attachment, which the R-help server has duly
stripped off!
I would suggest thatshe re-sends her message
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(index, count))
It answers correctly, but I feel it's wasteful especially when count
is generally large. So, my question is, is there a way to get
quantiles directly from this table (without coding at a low level)?
Thanks,
Seung
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)?
Thanks,
Seung
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(bar, foo)
Method Definition:
function (object)
{
print([EMAIL PROTECTED])
}
Signatures:
object
target foo
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Dear R-users,
I want to know if there is a package that allows to define different
experimental designs (factorial, orthogonal, taguchi)
and to compare them.
I don't found one in the R-web site, but it is possible I missed it!
Thank you in advance
Sincerely,
Marc
.
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I want to check whether all the components of a vector (or an array)
are 0, and if they are I will skip the later computations. Of course
I can create a loop to go through all the components. However is
there an R function for this purpose more efficient than looping?
Thanks a lot,
Gang
,] -0.31754610+0i 0.19351247+0.1625154i 0.19351247-0.1625154i
-0.73460380+0.i -0.73460380+0.i
[6,] -0.06705781+0i -0.00340804-0.0295753i -0.00340804+0.0295753i
0.30711075+0.13557984i 0.30711075-0.13557984i
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= a)
Coefficients:
b c d e f
0.04232 0.32343 1.36039 -4.67399 3.29727
Thanks so much in advance!
Young
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Hi Edna --
I have Rmpi 0.5-3 under R 2.5.1 with LAM 7.1.2 installed on an x86_64
SuSE 10.0.
I installed (as a regular user, to my own disc space) LAM and ran
through some basic checks (lamboot / lamhalt, checking that I could
compile the demo programs)
After downloading Rmpi_0.5.3.tar.gz, I
-and-construct-data.frame-tf4342441.html#a12370234
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I'm hesitated to use
that..
Thanks a lot for your great help before and this time as well!!
- boy
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Sent from the R help mailing list archive at Nabble.com
PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Marc BERVEILLER
Sent: Tuesday, August 28, 2007 6:12 AM
To: r-help@stat.math.ethz.ch
Subject: [R] Experimental Design with R
Dear R-users,
I want to know if there is a package that allows to define different
experimental designs (factorial, orthogonal
that..
Thanks a lot for your great help before and this time as well!!
- boy
--
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Sent from the R help mailing list archive at Nabble.com
]
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Brian D. Ripley, [EMAIL PROTECTED]
Professor
I was reading a presentation of Professor Peng's and typed the
presentation code into R but I changed it to make plot.polygon a
separate function instread of defining the function in SetMethod itself
as he did. Is that the problem with the code below because
plot(p) just gives me zero. Thanks
Dear R-users,
I have found this not-so-recent post in the archives -
http://tolstoy.newcastle.edu.au/R/devel/00a/0291.html - while I was
looking for a particular way to reorder factor levels. The question
addressed by the author was to know if the read.table function could be
modified
with the --enable-shared
configure option, as documented in the installation guide. (It might
also mean that R was not configure with --enable-R-shlib; the message
is opaque to me).
I believe others on the list have only had success with specific
versions of LAMMPI, so that would be the next place to look (after
as such... and there seem to be no R tools targeted at
process/formulation optimisation at the analysis stage. For example, there
isn't a simple-to-use quadratic response surface modelling widget that allows
you to drop terms quickly and easily and then find maxima on the resulting
fitted surface
is formatted to show 2 decimals. Whoever doesn't pay
attention gets what s/he deserves for trusting Excel in the first
place.
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of David Scott
Sent: Monday, August 27, 2007 10:11 PM
To: r-help@stat.math.ethz.ch
Hi All,
I have some data I need to write as a file from R to use in a different
program.
My data comes as a numeric matrix of n rows and 2 colums, I need to transform
each row as a two rows 1 col output, and separate the output of each row with a
blanck line.
Foe instance I need to go from
A
20 B
30 C
40 A
DF - read.table(textConnection(Input), header = TRUE,
colClasses = c(numeric, my.levels))
str(DF)
# or
DF - read.table(textConnection(Input), header = TRUE,
colClasses = list(Fld2 = my.levels))
str(DF)
On 8/28/07, Sébastien [EMAIL PROTECTED] wrote:
Dear R-users,
I have found
Hi Federico,
Federico Calboli wrote:
Hi All,
I have some data I need to write as a file from R to use in a different
program.
My data comes as a numeric matrix of n rows and 2 colums, I need to transform
each row as a two rows 1 col output, and separate the output of each row
,] -0.31754610+0i 0.19351247+0.1625154i 0.19351247-0.1625154i
-0.73460380+0.i -0.73460380+0.i
[6,] -0.06705781+0i -0.00340804-0.0295753i -0.00340804+0.0295753i
0.30711075+0.13557984i 0.30711075-0.13557984i
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
create a loop to go through all the components. However is
there an R function for this purpose more efficient than looping?
Thanks a lot,
Gang
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PLEASE do read
means that your lam was not built with the --enable-shared
configure option, as documented in the installation guide. (It might
also mean that R was not configure with --enable-R-shlib; the message
is opaque to me).
The line above is
/usr/lib64/gcc/x86_64-suse-linux/4.1.0/../../../../lib64
From: Birgit Lemcke [mailto:[EMAIL PROTECTED]
Sent: Friday, August 24, 2007 2:13 AM
To: Greg Snow
Cc: R Hilfe
Subject: Re: [R] ordered factors in data.frame
Thanks a lot Greg for your help
Hi,
What's a good way to quickly determine the location of a failure in my RUnit
test suite? For instance, if I do the following:
==
library(RUnit)
runTestSuite( defineTestSuite(MyTests, src/r, testFuncRegexp=metrics) )
Executing test function
PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of
[EMAIL PROTECTED]
Sent: Tuesday, August 28, 2007 7:33 AM
To: r-help@stat.math.ethz.ch
Subject: [R] Forcing coefficients in lm object
Dear all,
I would like to use predict.lm() with an existing lm object
but with new arbitrary
, August 28, 2007 8:23 AM
To: r-help@stat.math.ethz.ch
Subject: [R] quntile(table)?
Hi,
I have data in the following form:
index count
-7 32
19382
22192
7 190
11 201
I'd like to get quantiles from the data. I thought about
something like
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##
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AT yorku DOT ca
Professor, Psychology Dept.
York University Voice: 416 736-5115 x66249 Fax: 416 736-5814
4700 Keele Streethttp://www.math.yorku.ca/SCS/friendly.html
Toronto, ONT M3J 1P3 CANADA
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any way to bring flexibility to your method ? Because, it
looks to me as, at this stage, I have to i) know the order of my levels
before I read the table and ii) create one class per factor.
My problem is that I am not really working on a specific dataset. My
goal is to develop R scripts capable
read the table and ii) create one class per factor.
My problem is that I am not really working on a specific dataset. My goal is
to develop R scripts capable of handling datasets which have various
contents but close structures. So, I really need to minimize the quantity of
user-specific code
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,replace=T),c=sample(letters[1:26], 20, replace = T))
mydata
a b c
1 1 176 w
2 2 141 k
3 3 172 r
4 4 182 s
5 5 123 k
6 6 153 p
7 7 176 l
8 8 170 u
9 9 140 z
10 10 194 s
11 11 164 j
12 12 100 j
13 13 127 x
14 14 137 r
15 15 198 d
16 16 173 j
17 17 113 x
18 18 144 w
19 19 198 q
Lu
Sent: Tuesday, August 28, 2007 5:00 PM
To: r-help@stat.math.ethz.ch
Subject: [R] data manipulation help
Dear All:
I have a dataset like
A=c(0,12,34,5,6,0,4,5,6,0,12,3,4,8,7,0,4,3,5,0,...),I want to add a
column to this dataset, it must be in
B=c(1,1,1,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,5
.
Do you want
B - cumsum( A == 0 )
??
Please use spaces and newlines to make your code more readable!
Zheng
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Its the same principle. Just change the function to be suitable. This one
arranges the levels according to the input:
library(methods)
setClass(my.factor)
setAs(character, my.factor,
function(from) factor(from, levels = unique(from)))
Input - a b c
1 1 176 w
2 2 141 k
3 3 172 r
4 4
Sebastain
Does the following work for you?
seb - read.table(file='clipboard', header=T)
seb$c
[1] w k r s k p l u z s j j x r d j x w q f
Levels: d f j k l p q r s u w x z
seb$c - factor(seb$c, levels=unique(seb$c))
seb$c
[1] w k r s k p l u z s j j x r d j x w q f
Levels: w k r s p l u z j x
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Peter, Gabor: thanks to both of you.
This 'unique' function is what I was looking for !
Peter Alspach a écrit :
Sebastain
Does the following work for you?
seb - read.table(file='clipboard', header=T)
seb$c
[1] w k r s k p l u z s j j x r d j x w q f
Levels: d f j k l p q r s u w x z
Hi, I am writing a BRugs code and I need to specify the likelihood for the
gamma distribution and I am specifying it as the pdf:
(pow(b1,a1)/(exp(loggam(a1)))*(exp(-b1*lambda[i]))*pow(lambda[i],(a1-1)))
But it is not accepting it although I know that I could use the pdf in R to
estimate
-to-perform-a-calculation-tf4344469.html#a12376906
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any starter code :D jj. If I've read something wrong or
misunderstood my apologies.
cheers,
Paul
--
Research Technician
Mass Spectrometry
o The
/
o Scripps
\
o Research
/
o Institute
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='', file='tempxx.txt')
On 8/28/07, Federico Calboli [EMAIL PROTECTED] wrote:
Hi All,
I have some data I need to write as a file from R to use in a different
program.
My data comes as a numeric matrix of n rows and 2 colums, I need to transform
each row as a two rows 1 col output
Department of Agronomy and Soil Science
University of New England
Armidale NSW 2351
Email: [EMAIL PROTECTED]
Ph 02 67729794
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(x$x2-xk$xk2[j])
}
Is there a way to do the above calculation without use of a FOR loop?
Thank you
Derek
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values (may be strings or non-sequential integers)
identifying levels (possibly with repeated occurences), how
can I recode them to be sequential from 1 to n?
I can solve both problems in fortran, so could use loops to
do it in R, but feel there should be quicker, more elegant,
more R solution
GeneGO, Inc.
Did you always know?
No, I did not. But I believed...
---Matrix III
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extracting dataset with average imputed values from aregImpute()
Dear all:
after many trials, i am still quite lost on how to exact a dataset with
average imputed values after running aregImpute()
take the eg in the aregImpute(Hmisc) documentation(-- which also appeared in
our R-archive
On 8/22/07, Polly He [EMAIL PROTECTED] wrote:
I'm trying to fit a naive Bayes model and predict on a new data set using
the functions naivebayes and predict (package = e1071).
R version 2.5.1 on a Linux machine
My data set looks like this. class is the response and k1 - k3
Research Center
BioC: http://bioconductor.org/
Blog: http://userprimary.net/user/
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Along with the example I gave using graphAM, you might also want to
look at the help page for the distGraph class which may be more
directly what you want:
library(graph)
class ? distGraph
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wrong or
misunderstood my apologies.
cheers,
Paul
--
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Mass Spectrometry
o The
/
o Scripps
\
o Research
/
o Institute
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PLEASE
, Pakistan.
Email:
[EMAIL PROTECTED]
[EMAIL PROTECTED]
[EMAIL PROTECTED]
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:
Estimate Std. Error t value Pr(|t|)
(Intercept) 1.6210 0.5332 3.040 0.0161 *
b-0.7667 0.5037 -1.522 0.1664
---
Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
Residual standard error: 1.142 on 8 degrees of freedom
Multiple R-Squared: 0.2246
Hi,
I recently discovered the R program and I thought it could be useful to me.
I have to analyse data saved as .Px file (x between 0 and 8 - .P0 files have
18 lines at the beginning that I have to skip). New files are generated
everyday.
This is my strategy :
In order to analyse the data, I
/Problem-with-save-or-and-if-%28I-think-but-maybe-not-...%29-tf4333945.html#a12343633
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On Mon, 27 Aug 2007, Ptit_Bleu wrote:
Hi,
I recently discovered the R program and I thought it could be useful to me.
I have to analyse data saved as .Px file (x between 0 and 8 - .P0 files have
18 lines at the beginning that I have to skip). New files are generated
everyday
-and-white image.
--- Moshe Olshansky [EMAIL PROTECTED] wrote:
Hi Bart,
I have never used image processing software in R (I
was doing this with Matlab), but here is what I
would
have done algorithmically:
1) convert the picture to gray-scale
2) find a threshold value which separates
/31_07_2007.P1 d:/Mydata/31_07_2007.P2
[5] d:/Mydata/31_07_2007.P3
tfichiers
tfichiers
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?
Thank you very much in advance!
Werner
Machen Sie Yahoo! zu Ihrer Startseite. Los geht's:
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and testing manually alternative scripts ...
Hoping to read you again,
Ptit Bleu.
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will also be able to help people).
Have a nice week,
Ptit Bleu.
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Hello,
Here is a late answer, but an answer nonetheless to the question I asked
almost one year ago on this list:
On Wed, 29 Mar 2006, Thibaut Jombart wrote:
Hello list,
http://tolstoy.newcastle.edu.au/R/help/06/03/24318.html#24322qlink1
/ /
/ does anyone know if Monmonier algorithm
Hello,
This is not a purely R-question, but perhaps someone can help me anyway.
I am trying to estimate the correlation between two time series (which
are both basically different types of measurements of the same
phenomena), using both cor.test() (with pearson as method) and ccf().
Now
PROFILE OUTPUT PROCESSING TOOLS FOR R
=
This package provides some simple tools for examining Rprof output
and, in particular, extracting and viewing call graph information.
Call graph information, including which direct calls
to find out any number of R idiosycracies.
However
there is no numbering on the FAQ Table of
Content or
on the Sections Tables of Contents.
Hmm, doc/FAQ does have a numbered table of
contents and numbered sections
and doc/manual/R-FAQ.html does have numbered
sections and my
!
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
it taking advantages of the R
language (which I don't master at all), that is with less if tests.
To sum up :
nfichiers is a list of files (with .P0 or .Px (x0) extension) I have to
copy to a database.
nfichiers can also be 0 if there is no file to copy
p0fichiers is the list of files having the .P0
. Note that
the normal approximation is OK for large samples but may give unacceptable
results for small samples. I am unaware of any packages in R that perform an
exact runs test.
Tom
I have used runs.test (Package tseries) for computes the runs test
for randomness , but I get this result
On 8/27/2007 8:52 AM, John Kane wrote:
--- Duncan Murdoch [EMAIL PROTECTED] wrote:
I like the first, simple suggestion best; I'll put
it into R-devel.
(With the slight change to use ul.menu instead
of just ul, because FAQ 2.7 includes a plain ul
list.)
Duncan Murdoch
Thanks Deepayan
Gabor, That works great!
I think this would be a very helpful addition to the main R
distribution. Perhaps with a single colon representing numerical order
(exactly as you have written it) and two colons representing the order
of the variables as they appear in the data frame (your first example
a; sleep 5; echo b) | tee OUT
|
| the output is timely, not batched.
|
| So, is there a way to tell R (or Rscript) that standard output should be
| unbuffered, even if it is not directly connected to a terminal?
Use explicit print statements, e.g. print(a - 1)
Also, you still have little
Dear R users
I use Windows XP, R2.5.1 (I have read the posting guide, I have
contacted the package maintainer first, it is not homework).
In a research project on renal cell carcinoma we want to compute
Harrell's c index, with optimism correction, for a multivariate
Cox regression and also
On Mon, 27 Aug 2007, Muenchen, Robert A (Bob) wrote:
Gabor, That works great!
I think this would be a very helpful addition to the main R
distribution. Perhaps with a single colon representing numerical order
(exactly as you have written it) and two colons representing the order
Original Message
Subject: [R] R-2.5.1 RedHat EL5 compilation failed
From: Wang Chengbin [EMAIL PROTECTED]
To: r-help@stat.math.ethz.ch
Date: 26.08.2007 15:22
I can't get R-2.5.1 compiled under RedHat EL5 with gcc 4.1.1. Configure
failed at the following:
You don't need
... It refers to the
probability if being farther away from 0 than the observed value *in
either direction*
--
Daniel Lakeland
[EMAIL PROTECTED]
http://www.street-artists.org/~dlakelan
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch
Hi.
I would like to know if is it possible to estimate zero-truncated count
models with robust standard errors in R. In Stata that is possible. I
already made some searches and attempts but not obtained it. In R I made the
estimation of the truncated poisson by the vglm command of VGAM package
Hi R-Masters
I need use a sequential approach in serie of cases, but may data is not
normal.
If data is normal distribution is very easy create analysis using
likelihood ratio like of Wald test.
But in my case I need use a non-parametric test (Mann-Whitney).
I was use: RSiteSearch
Hi Bernardo,
I think that ?wilcox.test will help you.
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O
On 27/08/07, Bernardo Rangel Tura [EMAIL PROTECTED] wrote:
Hi R-Masters
I need use a sequential approach in serie of cases, but may data is not
normal
I looked for the same topic today and found ?wilcox.test in the stats
package.
B
Am 27.08.2007 um 17:33 schrieb Bernardo Rangel Tura:
Hi R-Masters
I need use a sequential approach in serie of cases, but may data
is not
normal.
If data is normal distribution is very easy create
Thomas, that's a good point. I was thinking of anscombe[x1::y1] making
it clear which one, but you would then want just x1::y1 to have
unambiguous meaning on its own, which is impossible.
As for x1:xN, it's unambiguous on its own. I thought one of the great
advantages of R was that it could use
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