Hi Sir
When we use Kendall Package to obtain Kendall's Tau statistic.
Then we also get two-sided p value. What does two-sided p-value mean?
The word two-sided is confusing to understand.
Kindly provide help in this regard.
--
AMINA SHAHZADI
Department of Statistics
GC University Lahore,
On Mon, Aug 27, 2007 at 11:49:19AM +0500, amna khan wrote:
Hi Sir
When we use Kendall Package to obtain Kendall's Tau statistic.
Then we also get two-sided p value. What does two-sided p-value mean?
The word two-sided is confusing to understand.
Two-sided is sometimes also called
Hi,
I conduct a univariate regression with lm function. I would like to get
the p value for the regression. Is there a method that would enable me to
extract the p value into a variable.
Thanks.
Arjun Bhandari
Arjun Bhandari arb.em at adia.ae writes:
I conduct a univariate regression with lm function. I would like to get
the p value for the regression. Is there a method that would enable me to
extract the p value into a variable.
# From lm docs (Sorry, Annette, for misusing your data)
ctl -
The question was how to get the p-value from the fit below, as an S object
sr-survreg(s~groups, dist=gaussian)
Coefficients:
(Intercept) groups
-0.02138485 0.03868351
Scale= 0.01789372
Loglik(model)= 31.1 Loglik(intercept only)= 25.4
Chisq= 11.39 on 1 degrees of freedom, p=
On 7/12/07, Terry Therneau [EMAIL PROTECTED] wrote:
The question was how to get the p-value from the fit below, as an S object
sr-survreg(s~groups, dist=gaussian)
Coefficients:
(Intercept) groups
-0.02138485 0.03868351
Scale= 0.01789372
Loglik(model)= 31.1 Loglik(intercept only)=
dear r experts:
I would appreciate advice on how to get the p-value from the object 'sr'
created with the function survreg() as given below.
vlad
sr-survreg(s~groups, dist=gaussian)
Coefficients:
(Intercept) groups
-0.02138485 0.03868351
Scale= 0.01789372
Loglik(model)= 31.1
dear r experts:
It seems my message got spam filtered, another try:
i would appreciate advice on how to get the p-value from the object 'sr'
created with the function survreg() as given below.
vlad
sr-survreg(s~groups, dist=gaussian)
Coefficients:
(Intercept) groups
-0.02138485 0.03868351
str(survreg(s~groups, dist=gaussian))
is probably a good place to start.
Hadley
On 7/11/07, Vlado Sremac [EMAIL PROTECTED] wrote:
dear r experts:
It seems my message got spam filtered, another try:
i would appreciate advice on how to get the p-value from the object 'sr'
created with the
Try also:
pchisq(summary(sr)$chi, degrees_freedom, lower=FALSE)
*You need know your degrees of freedom
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O
On 11/07/07, Vlado Sremac [EMAIL PROTECTED] wrote:
dear r experts:
It seems my message got spam filtered, another
Actually, in this case, looking at the code for:
survival:::print.survreg
would be better, as the p value is calculate there, rather than being
part of the survreg object. As with many R functions, the p value is
calculated in the print method for the object.
In this case, it is a pretty
On 7/11/07, Marc Schwartz [EMAIL PROTECTED] wrote:
Actually, in this case, looking at the code for:
survival:::print.survreg
would be better, as the p value is calculate there, rather than being
part of the survreg object. As with many R functions, the p value is
calculated in the print
On Wed, 2007-07-11 at 16:41 +0200, hadley wickham wrote:
On 7/11/07, Marc Schwartz [EMAIL PROTECTED] wrote:
Actually, in this case, looking at the code for:
survival:::print.survreg
would be better, as the p value is calculate there, rather than being
part of the survreg object. As
Benilton Carvalho schrieb:
Well, AFAIK, the definition of a p-value is the probability of
observing something at least as extreme as the observed data.
If you observed z, and Z follows a std-normal
p-value = P( Z -abs(z) ) + P( Z abs(z) )
= 2*P ( Z abs(z) )
= 2*pnorm(z,
I got an answer for the other question (thank you)
But there is another question (I am afraid this is a basic question ...)
In this tread there is a hint hwo to calculate the p-vlue of an GEE:
_http://finzi.psych.upenn.edu/R/Rhelp02a/archive/74150.html_
Then, get the P values using a normal
the recommendation was to use lower.tail=FALSE.
b
On Jun 11, 2007, at 11:21 AM, Carmen Meier wrote:
I got an answer for the other question (thank you)
But there is another question (I am afraid this is a basic
question ...)
In this tread there is a hint hwo to calculate the p-vlue of
Benilton Carvalho schrieb:
the recommendation was to use lower.tail=FALSE.
b
O
but then the results are significant and this does not match the
observation.
The results are matching the observations if the formula is
At 11:21 AM 6/11/2007, Carmen wrote:
snip
In this tread there is a hint hwo to calculate the p-vlue of an GEE:
_http://finzi.psych.upenn.edu/R/Rhelp02a/archive/74150.html
Then, get the P values using a normal approximation for the
distribution of z:
/ 2 *
Well, AFAIK, the definition of a p-value is the probability of
observing something at least as extreme as the observed data.
If you observed z, and Z follows a std-normal
p-value = P( Z -abs(z) ) + P( Z abs(z) )
= 2*P ( Z abs(z) )
= 2*pnorm(z, lower.tail=FALSE)
try z=0 (you should
Hi to all,
I found in the R-help archive how to calculate the p-value for a gee result:
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/74150.html
but there are two questions (I am afraid they are basic questions ...)
1. why is the result multiplicated with 2
2. how could I decide between
Hi to all,
I found in the R-help archive how to calculate the p-value for a gee result:
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/74150.html
but there are two questions (I am afraid they are basic questions ...)
1. why is the result multiplicated with 2
2. how could I decide between
Dear R list members.
Is there anyone out there that might be able to explain the difference
between p-values and significance codes for terms in a linear
regression model (as given by summary.lm for example) for me please?
Do they both give the probability that the observed variation in the
Dear all,
1)how can I easily get p value for the coefficients of factors in a multinomial
model?
2)why the p values for type III test with Anova are not identical to that
from SAS?
for example:
A,B and C are categorical variables,but the proportions of each level in each
categorical
://socserv.mcmaster.ca/jfox
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Xingwang Ye
Sent: Thursday, April 05, 2007 9:01 AM
To: r-help
Subject: [R] p value for coefficients in multinomial model
Dear all,
1)how can I
Hello!
I want to compare two Kaplan-Meier-Curves by using the Logrank-Test:
logrank(Surv(time[b], status[b]) ~ group[b])
This way I only get the value of the test-statistic, but not the p-value.
Does anybody know how I can get the p-value?
Thanks in advance!
Verena Hoffmann
On Tue, 3 Jan 2006, Verena Hoffmann wrote:
Hello!
I want to compare two Kaplan-Meier-Curves by using the Logrank-Test:
logrank(Surv(time[b], status[b]) ~ group[b])
This way I only get the value of the test-statistic, but not the p-value.
Does anybody know how I can get the p-value?
You
hello everybody
i'm very new at using R so probably this is a very stupid question.
I have a problem calculating a p-value. When i do this with excel i
can use the method CHIDIST for 1.2654 with 1 freedom degree i get the
answer 0.261
i just want to do the same thing in R but i can't find a
On Tue, 2005-10-18 at 17:13 +0200, richard mendes wrote:
hello everybody
i'm very new at using R so probably this is a very stupid question.
I have a problem calculating a p-value. When i do this with excel i
can use the method CHIDIST for 1.2654 with 1 freedom degree i get the
answer 0.261
pchisq(1.2654,1)
[1] 0.7393686
looks like excel gave you the other tail
bob kinley
richard mendes [EMAIL PROTECTED]
Sent by: [EMAIL PROTECTED]
18/10/2005 16:13
To
R-help@stat.math.ethz.ch
cc
Subject
[R] p-value calculation
hello everybody
i'm very new
pchisq(1.2654,df=1,low=F)
[1] 0.2606314
=== 2005-10-18 23:13:20 您在来信中写道：===
hello everybody
i'm very new at using R so probably this is a very stupid question.
I have a problem calculating a p-value. When i do this with excel i
can use the method CHIDIST for 1.2654 with 1 freedom
richard mendes [EMAIL PROTECTED] writes:
hello everybody
i'm very new at using R so probably this is a very stupid question.
I have a problem calculating a p-value. When i do this with excel i
can use the method CHIDIST for 1.2654 with 1 freedom degree i get the
answer 0.261
i just want
Look at ?pchisq
Daniel Nordlund
Bothell, WA
-Original Message-
From: [EMAIL PROTECTED] [mailto:r-help-
[EMAIL PROTECTED] On Behalf Of richard mendes
Sent: Tuesday, October 18, 2005 8:13 AM
To: R-help@stat.math.ethz.ch
Subject: [R] p-value calculation
hello everybody
i'm very
1-pchisq(1.2654,1)
[1] 0.2606314
-Don
At 5:13 PM +0200 10/18/05, richard mendes wrote:
hello everybody
i'm very new at using R so probably this is a very stupid question.
I have a problem calculating a p-value. When i do this with excel i
can use the method CHIDIST for 1.2654 with 1 freedom
Dear all,
I am fitting an nonlinear glm() using optim() by first minimising
glm(resp~ var1 + var2, family=binomial, data=data)$deviance
where var1= exp(-a1*dist1), and var2= exp(-a2*dist2), where a1 and a2 are
parameters and dist1 and dist2 are independent variables.
Next, I calculate the
Hi,
How can I get the p-value, S.E., and Z from the result of lrm fit? Thank you.
Donglei
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide!
[EMAIL PROTECTED] wrote:
Hi,
How can I get the p-value, S.E., and Z from the result of lrm fit? Thank you.
Donglei
That's automatic. The print method for lrm in the Design package does
that. Better though is the anova method which gives you the right
pooled tests when you have
The following contingency table generates p-value 1 from fisher.test()
ff = c(0,10,250,5000); dim(ff) = c(2,2); fhisher.test(ff)$p.value
Sean
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
Yi-Xiong Zhou [EMAIL PROTECTED] writes:
The following contingency table generates p-value 1 from fisher.test()
ff = c(0,10,250,5000); dim(ff) = c(2,2); fhisher.test(ff)$p.value
On this system (PIII, Fedora Core 3):
ff = c(0,10,250,5000); dim(ff) = c(2,2); fisher.test(ff)$p.value -1
At 10:01 PM +0200 6/3/05, Peter Dalgaard wrote:
Yi-Xiong Zhou [EMAIL PROTECTED] writes:
The following contingency table generates p-value 1 from fisher.test()
ff = c(0,10,250,5000); dim(ff) = c(2,2); fhisher.test(ff)$p.value
On this system (PIII, Fedora Core 3):
ff =
The problem is from the most recent version. Here is the platform:
R 2.1.0 2005-04-18, on winXP SP2,
Sean
-Original Message-
From: Douglas Grove [mailto:[EMAIL PROTECTED]
Sent: Friday, June 03, 2005 12:49 PM
To: Yi-Xiong Zhou
Subject: Re: [R] p-value 1 in fisher.test()
You need
On 03-Jun-05 Peter Dalgaard wrote:
Yi-Xiong Zhou [EMAIL PROTECTED] writes:
The following contingency table generates p-value 1 from
fisher.test()
ff = c(0,10,250,5000); dim(ff) = c(2,2); fhisher.test(ff)$p.value
On this system (PIII, Fedora Core 3):
ff = c(0,10,250,5000);
On 03-Jun-05 Ted Harding wrote:
And on mine
(A: PII, Red Had 9, R-1.8.0):
ff - c(0,10,250,5000); dim(ff) - c(2,2);
1-fisher.test(ff)$p.value
[1] 1.268219e-11
(B: PIII, SuSE 7.2, R-2.1.0beta):
ff - c(0,10,250,5000); dim(ff) - c(2,2);
1-fisher.test(ff)$p.value
[1]
Dear R users,
I wrote a function to perform a nonparametric multiple comparison test. The
function below solves the example 11.10 (pg. 228) from Zars Biostatistical
Analysis (3rd ed.). Nevertheless I couldnt find a function to get the p-value
associated to Q, so I still have to consult Table
Hello,
I want to compute the P-value from the joint cumulative distribution of an
n-dimensional
order statistic in R, using the formula found on
http://cmgm.stanford.edu/%7Ekimlab/multiplespecies/Supplement/methods_network.html
My data consists of three different techniques (G2D, POCUS and
Hello everybody,
I'm seeing some strange behavior on R 1.8.1 on Intel/Linux compiled
with gcc 3.2.2. The p-value calculated from the chisq.test function is
incorrect for some input values:
chisq.test(matrix(c(0, 1, 1, 12555), 2, 2), simulate.p.value=TRUE)
Pearson's
On Tue, 2003-12-09 at 02:23, Torsten Hothorn wrote:
Hello everybody,
I'm seeing some strange behavior on R 1.8.1 on Intel/Linux compiled
with gcc 3.2.2. The p-value calculated from the chisq.test function is
incorrect for some input values:
chisq.test(matrix(c(0, 1, 1, 12555),
It happens with suse 9.0 as well.
...
chisq.test(matrix(c(0, 1, 1, 12556), 2, 2), simulate.p.value=TRUE)
Pearson's Chi-squared test with simulated p-value (based on 2000
On Dec 9, 2003, at 9:37 AM, Peter Dalgaard wrote:
Marc Schwartz [EMAIL PROTECTED] writes:
Confirmed on Fedora Core 1 with R Version 1.8.1 Patched (2003-12-07)
compiled using gcc (GCC) 3.3.2 20031107 (Red Hat Linux 3.3.2-2).
chisq.test(matrix(c(0, 1, 1, 12555), 2, 2), simulate.p.value=TRUE)
...
Hello everybody,
I'm seeing some strange behavior on R 1.8.1 on Intel/Linux compiled
with gcc 3.2.2. The p-value calculated from the chisq.test function is
incorrect for some input values:
chisq.test(matrix(c(0, 1, 1, 12555), 2, 2), simulate.p.value=TRUE)
Pearson's Chi-squared
Dear R users,
Can anyone tell me how to get the p value out of the output from
summary.manova?
I tried all the methods I can think of, but failed.
Many thanks
Yu-Kang
_
MSN Mobile MSN Hotmail
http://msn.com.tw/msnmobile
Hint: print.summary.manova manages it. Try
example(summary.manova)
summary(fit, test=Wilks)$stats[,Pr(F)]
On Thu, 20 Nov 2003, Tu Yu-Kang wrote:
Can anyone tell me how to get the p value out of the output from
summary.manova?
I tried all the methods I can think of, but failed.
--
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