Hi,
I have a file named:
test_R.txt
aaa 2
bbb 5
ccc 7
sss 3
xxx 8
I want to have a plot:
test-read.table(test_R.txt,col.name=c(Name,Score))
par(mfrow=c(1,2))
barplot(test$Score)
name-test$Name
axis(1,at=1:length(test$Name),labels=paste(name))
Q1, if you try the script above,you will get 5
Try something like:
xp - barplot(test$Score, space=.5)
axis(1, at=xp, labels=as.character(test$Name))
See ?barplot more more detail.
Andy
From: jia ding
Hi,
I have a file named:
test_R.txt
aaa 2
bbb 5
ccc 7
sss 3
xxx 8
I want to have a plot:
On Wed, 2006-03-15 at 17:54 +0100, jia ding wrote:
Hi,
I have a file named:
test_R.txt
aaa 2
bbb 5
ccc 7
sss 3
xxx 8
I want to have a plot:
test-read.table(test_R.txt,col.name=c(Name,Score))
par(mfrow=c(1,2))
It's not clear what the purpose is here, at least in this example.
as the
version of R.
Question: Have you tried using method=Laplace or AGQ? The
function lmer actually has three approximate maximum likelihood
methods. The default is penalized quasi-likelihood (PQL), which is what
you get when you don't specify a method or when you request method=ML
On Mon, 27 Feb 2006 11:34:00 -0800,
Elizabeth Purdom (EP) wrote:
Hi,
I'm not sure if Sweave questions should go to the general list, but it
seems to be part of the core R package without a separate maintainer.
I am writing a tutorial for R in a latex file. I'd like to use Sweave,
Michael wrote:
pca=prcomp(training_data, center=TRUE, scale=FALSE, retx=TRUE);
Then I want to rotate the test data set using the
d1=scale(test_data, center=TRUE, scale=FALSE) %*% pca$rotation;
d2=predict(pca, test_data, center=TRUE, scale=FALSE);
these two values are different
Hi all,
I am wondering in R, suppose I did the principal component analysis on
training data set and obtain the rotation matrix, via:
pca=prcomp(training_data, center=TRUE, scale=FALSE, retx=TRUE);
Then I want to rotate the test data set using the
d1=scale(test_data, center=TRUE,
To whom it may concern:
I am using lmer for a statistical model that includes non-normally
distributed data and random effects. I used this same function in the
most recent version of R as of fall 2005, and have re-done some of the
same analyses using all of the same files, but with the
Hi,
I'm not sure if Sweave questions should go to the general list, but it
seems to be part of the core R package without a separate maintainer.
I am writing a tutorial for R in a latex file. I'd like to use Sweave,
since this seems its ideal usage. The problem is that I want to
purposefully
On Mon, 27 Feb 2006, Elizabeth Purdom wrote:
Hi,
I'm not sure if Sweave questions should go to the general list, but it
seems to be part of the core R package without a separate maintainer.
I am writing a tutorial for R in a latex file. I'd like to use Sweave,
since this seems its
://socserv.mcmaster.ca/jfox
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Wensui Liu
Sent: Saturday, February 18, 2006 2:03 PM
To: Liaw, Andy
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] Question about variable
Hello, I am using the Ljung Box test in R to compute
if the resiudals of my fitted model is random or not.
I am not sure though what the results mean, I have
looked at various sources on the internet and have
come up with contrasting explanations (mainly because
these info deal with different
Hopefully the test is the same no matter what software
you are using. A small p-value is an indication that there
is structure in the data. So in your case there is no
indication of autocorrelation up to lag 5, but it appears
that there might be something going on at around lags 6
to 9.
How
Dear all,
I tried to plot cumulative hazard H(t) against t on a log-log sclale by
putting the optional function fun ='cloglog' in the plot function.
However, I came across the following error message
survcs20fit2-survfit(Surv(start,end,status)~sx,data=ALLDPcs20)
plot(survcs20fit2,fun=cloglog)
Hello:
I have problems generating big JPG plots in functions. the following code runs
fine in the script:
runs fine in script, generate 40k test1.jpg in the given directory
plotPlatesAlong - c(1:5)
plotDirPath - paste(dataPath, OutputPlots\\, sep=)
filename -
Most likely this is FAQ 7.22.
althogh how we are supposed to know what plotHeatTrellis does is beyond
me.
On Fri, 10 Feb 2006, [EMAIL PROTECTED] wrote:
Hello:
I have problems generating big JPG plots in functions. the following code
runs
fine in the script:
runs fine in script,
thanks, it works.
best, Alex
On Fri, 10 Feb 2006, Prof Brian Ripley wrote:
Most likely this is FAQ 7.22.
althogh how we are supposed to know what plotHeatTrellis does is beyond
me.
On Fri, 10 Feb 2006, [EMAIL PROTECTED] wrote:
Hello:
I have problems generating big JPG
I have a binary file with data sequence in the order
[age,weight][age,weight]
I know the length of the data and I want to load it into a data.frame. of
course a way to do this is to
read age and weight seperately and then use cbin(age,weight) to combine them
into a dataframe, but is
[EMAIL PROTECTED] wrote:
I have a binary file with data sequence in the order
What do you mean by 'binary file'?
[age,weight][age,weight]
How are age and weight encoded in this 'binary file'?
I know the length of the data and I want to load it into a
data.frame. of course a way to
Each data (edge,weight) is numerical data with type double (4 bytes)
df-file(d:/sim.data,rb)
age[1]-readBin(df,double())
weigt[1]-readBin(df,double())
...
age[10]-readBin(df,double())
weigt[10]-readBin(df,double())
it is not asc file.
=== 2006-02-07 13:03:17 ===
[EMAIL
Read it into a vector and then convert into a matrix; convert to a data
frame:
df - readBin(d:/sim.data, what='double', n=1, size=4) # make n
greater than file size
dim(df) - c(2, length(df) / 2)
df - t(df)
colnames(df) - c('age', 'weight')
df - as.data.frame(df)
On 2/7/06, [EMAIL
dear list,
I am wondering if one can find examples and/or more detailed
descriptions of modifications needed when going beyond standard
corStruct classes (i.e. those already provided for use in lme/nlme)?
When I looked at pages 238-239 of Pinheiro/Bates (2000): Mixed-effects
models in S and
Ing. Marek Brabec PhD [EMAIL PROTECTED] writes:
dear list,
I am wondering if one can find examples and/or more detailed
descriptions of modifications needed when going beyond standard
corStruct classes (i.e. those already provided for use in lme/nlme)?
When I looked at pages 238-239 of
Hello,
I am a research student and I am using R to access my research. I want
to know how to multiple plot , such as for the exponetial distribution,
if I give the covariate different value, how to plot these in the same
figure,
And also I want to add the density plot in the histogramm.
How to do
x - seq(0, 10, by=.1)
plot(x,pexp(x, rate=1))
points(x,pexp(x, rate=2), pch=2, col=blue)
See help(plot), help(points), help(lines).
Gabor
On Fri, Feb 03, 2006 at 01:07:30PM -, Xiao Zhao wrote:
Hello,
I am a research student and I am using R to access my research. I want
to know how to
Did you try 'RSiteSearch(aggregate time series)'? When I did this
just now, the third hit was,
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/55761.html;, which
might help you. See in particular the zoo package and vignette, and
especially the aggregate.zoo function, including the
Hi,
I have a 1-d vector x of values but it is rather noisy. I know a priori
that the density function should be monotonically decreasing, but my data
doesnt have that. Is there a way to transform the data in such a way so
that the resultant density be monotonically decreasing?
Thanks
Debayan
Hi R Users
I am going to write a very short script for my small pilot simulation study.
I need to call a DOS program with different input data files in the middle
of for loop.
There are 100 input data files (e.g., input001.dat, input002.dat, ,
input100.dat)
for (1 in i :100)
{
: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Taka Matzmoto
Sent: Wednesday, January 25, 2006 9:31 PM
To: r-help@stat.math.ethz.ch
Subject: [R] question about system command
Hi R Users
I am going to write a very short script for my small pilot simulation study.
I need to call a DOS program
]
[mailto:[EMAIL PROTECTED] Behalf Of Taka Matzmoto
Sent: Wednesday, January 25, 2006 9:31 PM
To: r-help@stat.math.ethz.ch
Subject: [R] question about system command
Hi R Users
I am going to write a very short script for my small pilot simulation study.
I need to call a DOS program with different
hello,
Suppose you a monthly series you want to aggregate at a quaterly frequency
with the start and the end of your series in the middle of the quarter.
For example
2001M2 2001M3 2001M4 2001M5 2001M6 2001M7
12 13 12 14 16 15
how can you get
Try this:
library(zoo)
z - zooreg(c(12, 13, 12, 14, 16, 15), start = c(2001, 2), freq = 12)
aggregate(z, trunc(4 * time(z))/4, mean)
2001(1) 2001(2) 2001(3)
12.514.015.0
On 1/25/06, Matthieu Cornec [EMAIL PROTECTED] wrote:
hello,
Suppose you a monthly series you want to
Hi R users
I'm trying to fit a model y=ax^b.
I know if I made ln(y)=ln(a)+bln(x) this is a linear regression.
But I obtain differente results with nls() and lm()
My commands are: nls(CV ~a*Est^b, data=limiares, start =list(a=100,b=0),
trace = TRUE) for nonlinear regression
The two methods are fitting different models. With lm(), the model is
y = a * x^b * error
or, equivalently,
ln(y) = ln(a) + b * ln(x) + ln(error)
With nls(), the model is
y = a * x^b + error
Thus you will get two different estimates.
Andy
From: Ana Quitério
Hi R users
I'm
-Original Message-
From: [EMAIL PROTECTED] [SMTP:[EMAIL PROTECTED] On Behalf Of Ana Quitério
Sent: Wednesday, January 25, 2006 3:33 PM
To: r-help@stat.math.ethz.ch
Subject: [R] Question about fitting power
From: Ana Quitério
Hi R users
I'm trying to fit a model y
I have a vector x with #'s ( 1 or -1 in them ) in it and I want to
mark a new vector with the sign of the value of the a streak
of H where H = some number ( at the next spot in the vector )
So, say H was equal to 3 and
I had a vector of
[1] [2] [3] [4] [5] [6] [7] [8] [9] [10]
1
see ?rle
url:www.econ.uiuc.edu/~rogerRoger Koenker
email[EMAIL PROTECTED]Department of Economics
vox: 217-333-4558University of Illinois
fax: 217-244-6678Champaign, IL 61820
On Jan 12, 2006, at 9:56 AM, Mark Leeds wrote:
Hi,
I have a question about the p-value of mshapiro test. I simulated data
from bivariate normal 1000 times and used mshapiro test to see how many
times the test would reject the null hypothesis when the p-value is 0.05.
The answer should be around 50 since the p-value is 0.05. But I got a much
Dear R-helpers,
While plotting a hclust tree, is it possible to mark group information on it?
Suppose I have a hclust tree ClusTree, and I use cutree to cut the
tree into different groups as following
a=cutree(ClusTree,h=10)
How do I mark the grouping info stored in a while I plot ClusTree?
Martin Erwig wrote:
Considering the R function/plot shown below, I wonder whether
it is possible to do the following changes:
(1) Change the color of each point to be picked from
list of colors according to its z-value. (The range
should be from blue (z=0) to red (z=1).) The grid
should
Considering the R function/plot shown below, I wonder whether
it is possible to do the following changes:
(1) Change the color of each point to be picked from
list of colors according to its z-value. (The range
should be from blue (z=0) to red (z=1).) The grid
should then be omitted. [I have seen
On 1/7/2006 12:47 PM, Martin Erwig wrote:
Considering the R function/plot shown below, I wonder whether
it is possible to do the following changes:
(1) Change the color of each point to be picked from
list of colors according to its z-value. (The range
should be from blue (z=0) to red
Why said stupid question ? be positive next time
Best wishes.
Peter Dalgaard [EMAIL PROTECTED] a écrit :
Mark Leeds writes:
I'm sorry to bother everyone with a stupid
question but, when I am at an R prompt in Windows,
is there a way to see what packages
you already have installed from
I'm sorry to bother everyone with a stupid
question but, when I am at an R prompt in Windows,
is there a way to see what packages
you already have installed from the R site so
that you can just do library(name_of_package)
and it will work.
I've looked at help etc but I can't find
a command like
Mark Leeds [EMAIL PROTECTED] writes:
I'm sorry to bother everyone with a stupid
question but, when I am at an R prompt in Windows,
is there a way to see what packages
you already have installed from the R site so
that you can just do library(name_of_package)
and it will work.
I've
On Tue, 2006-01-03 at 16:07 -0500, Mark Leeds wrote:
I'm sorry to bother everyone with a stupid
question but, when I am at an R prompt in Windows,
is there a way to see what packages
you already have installed from the R site so
that you can just do library(name_of_package)
and it will work.
On Tue, 3 Jan 2006, Mark Leeds wrote:
I'm sorry to bother everyone with a stupid
question but, when I am at an R prompt in Windows,
is there a way to see what packages
you already have installed from the R site so
that you can just do library(name_of_package)
and it will work.
I've
On Tue, 3 Jan 2006, Mark Leeds wrote:
I'm sorry to bother everyone with a stupid
question but, when I am at an R prompt in Windows,
is there a way to see what packages
you already have installed from the R site so
that you can just do library(name_of_package)
and it will work.
I've looked
in R by everyone. Truly
amazing. You should
all be quite proud
about what you have created.
Mark
-Original Message-
From: Prof Brian Ripley [mailto:[EMAIL PROTECTED]
Sent: Tuesday, January 03, 2006 4:16 PM
To: Mark Leeds
Cc: R-Stat Help
Subject: Re: [R] newbie R question
Hi,
I have a question on write.table:
I have a data.frame called t7 as below:
dim(t7)
[1] 140151846
t7[1:5,]
uci uce par line graphical.forms stems
1 0 0 00 active activ
2 0 0 00 policy polici
3 0 0 00 wc PC
4 0 0
Weiwei Shi [EMAIL PROTECTED] writes:
Hi,
I have a question on write.table:
I have a data.frame called t7 as below:
dim(t7)
[1] 140151846
t7[1:5,]
uci uce par line graphical.forms stems
1 0 0 00 active activ
2 0 0 00 policy polici
3
Note that write.table is very much faster in current versions of R.
So you could save the object, read it into 2.2.1 (beta) and write it out
there.
On Thu, 15 Dec 2005, Weiwei Shi wrote:
Hi,
I have a question on write.table:
I have a data.frame called t7 as below:
dim(t7)
[1] 14015184
Hello,
I have a problem that I am trying to solve and I am not sure how to
do it in R.
Suppose, that 16 numbers are choosen at random from 0 to 9, what's
the probability that their average will be between 4 and 6. I typed
the following code:
set.seed(100)
sample(0:9, 16, replace =TRUE)
Please disregard this message and don't post it to the web. I found
the answer.
Thanks
Davia S. Cox
517-575-8031 cell
[EMAIL PROTECTED]
Human potential, though not always apparent, is there waiting to be
discovered and invited forth. -William W. Purkey
On Dec 13, 2005, at 6:20 AM, Davia
On 12/13/05 6:20 AM, Davia Cox [EMAIL PROTECTED] wrote:
Hello,
I have a problem that I am trying to solve and I am not sure how to
do it in R.
Suppose, that 16 numbers are choosen at random from 0 to 9, what's
the probability that their average will be between 4 and 6. I typed
the
Davia Cox wrote:
Hello,
I have a problem that I am trying to solve and I am not sure how to
do it in R.
Suppose, that 16 numbers are choosen at random from 0 to 9, what's
the probability that their average will be between 4 and 6. I typed
the following code:
set.seed(100)
On 13-Dec-05 Uwe Ligges wrote:
Davia Cox wrote:
[...]
My question is in order to run a true random sample,
We have to disappoint you: Your computer cannot generate
true random samples.
At least on Linux (and probably most Unix) systems,
/dev/random must be a pretty good approximation
On Tue, 13 Dec 2005 [EMAIL PROTECTED] wrote:
On 13-Dec-05 Uwe Ligges wrote:
Davia Cox wrote:
[...]
My question is in order to run a true random sample,
We have to disappoint you: Your computer cannot generate
true random samples.
At least on Linux (and probably most Unix) systems,
On 13-Dec-05 Prof Brian Ripley wrote:
On Tue, 13 Dec 2005 [EMAIL PROTECTED] wrote:
On 13-Dec-05 Uwe Ligges wrote:
Davia Cox wrote:
[...]
My question is in order to run a true random sample,
We have to disappoint you: Your computer cannot generate
true random samples.
At least on Linux
Hi,
Given a frame with calendar date's:
2005-07-01, 2005-07-02,2005-07-03,2005-07-04,2005-07-05,etc.
I want to extract the following from these dates:
week number
month number
year number
Any ideas how to accomplish this?
Many thanks.
Regards,
Richard
This is one way to do it.
x-c(2005-07-01, 2005-07-02,2005-07-03,2005-07-04,2005-07-05)
x
[1] 2005-07-01 2005-07-02 2005-07-03 2005-07-04 2005-07-05
substr(x,1,4)
[1] 2005 2005 2005 2005 2005
substr(x,6,7)
[1] 07 07 07 07 07
substr(x,9,10)
[1] 01 02 03 04 05
=== 2005-12-12 20:06:00
do.call(rbind, strsplit(as.character(date.vector), -))
Richard van Wingerden a écrit :
Hi,
Given a frame with calendar date's:
2005-07-01, 2005-07-02,2005-07-03,2005-07-04,2005-07-05,etc.
I want to extract the following from these dates:
week number
month number
year number
Any ideas how
x-as.Date(c(2005-07-01,
2005-07-02,2005-07-03,2005-07-04,2005-07-05))
weekdays(x)
[1] 星期五 星期六 星期日 星期一 星期二
months(x)
[1] 七月 七月 七月 七月 七月
=== 2005-12-12 20:17:38 您在来信中写道：===
Thanks!
That solves my problem for year numbers and month numbers
Any idea how to do this for week numbers?
On Mon, 12 Dec 2005, ronggui wrote:
x-as.Date(c(2005-07-01, 2005-07-02,2005-07-03,2005-07-04,2005-07-05))
weekdays(x)
[1] ÐÇÆÚÎå ÐÇÆÚÁù ÐÇÆÚÈÕ ÐÇÆÚÒ» ÐÇÆÚ¶þ
months(x)
[1] ÆßÔÂ ÆßÔÂ ÆßÔÂ ÆßÔÂ ÆßÔÂ
He asked for week numbers. That's nothing like as easy, as it is not
well-defined. But
this is what I was looking for!
many many thanks!
regards,
richard
On 12/12/05, Prof Brian Ripley [EMAIL PROTECTED] wrote:
On Mon, 12 Dec 2005, ronggui wrote:
x-as.Date(c(2005-07-01,
2005-07-02,2005-07-03,2005-07-04,2005-07-05))
weekdays(x)
[1] 星期五 星期六 星期日 星期一 星期二
months(x)
[1]
Prof Brian Ripley [EMAIL PROTECTED] writes:
On Mon, 12 Dec 2005, ronggui wrote:
x-as.Date(c(2005-07-01,
2005-07-02,2005-07-03,2005-07-04,2005-07-05))
weekdays(x)
[1] ÐÇÆÚÎå ÐÇÆÚÁù ÐÇÆÚÈÕ ÐÇÆÚÒ» ÐÇÆÚ¶þ
months(x)
[1] ÆßÔÂ ÆßÔÂ ÆßÔÂ ÆßÔÂ ÆßÔÂ
He asked for week numbers. That's
On Mon, 12 Dec 2005, Peter Dalgaard wrote:
Prof Brian Ripley [EMAIL PROTECTED] writes:
On Mon, 12 Dec 2005, ronggui wrote:
x-as.Date(c(2005-07-01, 2005-07-02,2005-07-03,2005-07-04,2005-07-05))
weekdays(x)
[1] ÐÇÆÚÎå ÐÇÆÚÁù ÐÇÆÚÈÕ ÐÇÆÚÒ» ÐÇÆÚ¶þ
months(x)
[1] ÆßÔÂ ÆßÔÂ ÆßÔÂ ÆßÔÂ ÆßÔÂ
Prof Brian Ripley [EMAIL PROTECTED] writes:
%W seems to be what is known as ISO dates (week starts on Monday),
except that
strftime(as.POSIXlt(as.Date(2005-01-01)), %U)
[1] 00
should be week 53, 2004 according to my printed calendar, and emacs
calendar-mode too.
I _did_ say
You asked about the behavior of KalmanSmooth(...)$var with missing
values. I also got very counterintuitive results from your excellent,
reproducible example using R 2.2.0 under Windows XP:
* With no missing values, KalmanSmooth(...)$var = 2, independent of
the data and
I am trying to use KalmanSmooth to smooth a time series
fitted by arima (and with missing values), but the $smooth component
of the output baffles me. Look at the following example:
testts - arima.sim(list(ar=0.9),n=100)
testts[6:14] - NA
testmod - arima(testts, c(1,0,0))
testsmooth -
Please,
1. read the posting guide
2. use a sensible subject line
3. this is NOT an r question
4. ask your teacher to explain your homeworks, but not this list
Uwe Ligges
yuying shi wrote:
If there are two random variable X1 and X2 which have
a bivariate normal distribution with mean vector
Uwe Ligges [EMAIL PROTECTED] writes:
Please,
1. read the posting guide
2. use a sensible subject line
3. this is NOT an r question
4. ask your teacher to explain your homeworks, but not this list
Uwe Ligges
And, btw, neither the mean nor the variance exists, so the question
If there are two random variable X1 and X2 which have
a bivariate normal distribution with mean vector (10,
10)and variance covariance matrix
[21.95
1.953]
How to calculate the mean and variance of the function
Y=X1/X2?
Thanks a lot!
xingyu
Dera all,
a simple question on rpart: when I run rpart on some data sets, I do not
always get the surrogate splits at the root node. This does not depend on the
presence of missing data because none of my data sets contains any,
nevertheless sometimes i get them sometimes no, I wonder why!
Does 'rug' help you ?
example(rug)
?rug
Cheers
Mathieu.
jia ding a écrit :
-- Forwarded message --
From: jia ding [EMAIL PROTECTED]
Date: Nov 2, 2005 4:03 PM
Subject: question about R graphics-example plot attached
To: [EMAIL PROTECTED]
Suppose I have the data set
Dear sir or ma'am,
I have a question about the dataset fgl. The dataset seems to be in
the VR package, so I tried to download it from CRAN. However, after
downloading, when I tried to load the package, it was not in my package
list. I am wondering what is wrong.
Any advice on how to access
`VR' is a bundle consisting of `MASS', `class', `nnet' and `spatial', as the
description says. The fgl data is in the MASS package, so you need to load
that one. In any case, data() would have told you that after the bundle is
installed.
Andy
From: Huh, Seungho
Dear sir or ma'am,
I
-- Forwarded message --
From: jia ding [EMAIL PROTECTED]
Date: Nov 2, 2005 4:03 PM
Subject: question about R graphics-example plot attached
To: [EMAIL PROTECTED]
Suppose I have the data set like this:
A 1
3
7
10
B 5
9
13
The numbers here actually is A or B's occurence
On Tue, 2005-11-08 at 14:08 +0100, jia ding wrote:
-- Forwarded message --
From: jia ding [EMAIL PROTECTED]
Date: Nov 2, 2005 4:03 PM
Subject: question about R graphics-example plot attached
To: [EMAIL PROTECTED]
Suppose I have the data set like this:
A 1
3
7
10
B 5
On Fri, 04-Nov-2005 at 04:58PM +0100, Peter Dalgaard wrote:
| In this particular case, it is slightly odd that we can't get an exact
| answer for operations that could in principle be carried out using
| integer arithmetic, but we're actually calculating log(8)/log(2).
|
| (Curiously, the same
Have you considered arima and predict.Arima?
spencer graves
Renuka Sane wrote:
I am trying to do a forecasting exercise for a series, x. My forecast
model consists of the following
I first regress log(x) on time and dummy variables for each month.
lm(log(x) ~ time +
Dear Sir/Madam,
If I have matrics as follows:
a - c(1,1,0,0)
b - c(4,4,0,0)
c - c(3,5,5,6)
How can I use R code to solve the equation ax^2+bx+c=0.
thanks!
yuying shi
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R-help@stat.math.ethz.ch mailing
Dear Sir/Madam,
If I have matrics as follows:
a - c(1,1,0,0)
b - c(4,4,0,0)
c - c(3,5,5,6)
How can I use R code to solve the equation ax^2+bx+c=0.
thanks!
yuying shi
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R-help@stat.math.ethz.ch mailing
On 05-Nov-05 Yuying Shi wrote:
Dear Sir/Madam,
If I have matrics as follows:
a - c(1,1,0,0)
b - c(4,4,0,0)
c - c(3,5,5,6)
How can I use R code to solve the equation ax^2+bx+c=0.
thanks!
yuying shi
I'm not sure what your question really should be, but taking
it at face value and not
At the risk of being beaten about the face and body, can somebody explain
why the middle example: log2(2^3); floor(log2(2^3)) is different than
examples 1 and 3?
log2(2^2); floor(log2(2^2))
[1] 2
[1] 2
log2(2^3); floor(log2(2^3))
[1] 3
[1] 2
log2(2^4); floor(log2(2^4))
[1] 4
[1] 4
DrC
Dr Carbon wrote:
At the risk of being beaten about the face and body, can somebody explain
why the middle example: log2(2^3); floor(log2(2^3)) is different than
examples 1 and 3?
Because
log2(2^3) - 3
[1] -4.440892e-16
see the R FAQ Why doesn't R think these numbers are equal?.
Uwe
Uwe Ligges [EMAIL PROTECTED] writes:
Dr Carbon wrote:
At the risk of being beaten about the face and body, can somebody explain
why the middle example: log2(2^3); floor(log2(2^3)) is different than
examples 1 and 3?
Because
log2(2^3) - 3
[1] -4.440892e-16
see the R FAQ Why
On Fri, 4 Nov 2005, Peter Dalgaard wrote:
Uwe Ligges [EMAIL PROTECTED] writes:
Dr Carbon wrote:
At the risk of being beaten about the face and body, can somebody explain
why the middle example: log2(2^3); floor(log2(2^3)) is different than
examples 1 and 3?
Because
log2(2^3) - 3
[1]
In this particular case, it is slightly odd that we can't get an exact
answer for operations that could in principle be carried out using
integer arithmetic, but we're actually calculating log(8)/log(2).
(Curiously, the same effect is not seen on Linux or Solaris until
log2(2^29)-29
On 11/4/2005 10:58 AM, Peter Dalgaard wrote:
Uwe Ligges [EMAIL PROTECTED] writes:
Dr Carbon wrote:
At the risk of being beaten about the face and body, can somebody explain
why the middle example: log2(2^3); floor(log2(2^3)) is different than
examples 1 and 3?
Because
On Fri, 4 Nov 2005, Uwe Ligges wrote:
Dr Carbon wrote:
At the risk of being beaten about the face and body, can somebody explain
why the middle example: log2(2^3); floor(log2(2^3)) is different than
examples 1 and 3?
Because
log2(2^3) - 3
[1] -4.440892e-16
This is a less
On Fri, 4 Nov 2005, Thomas Lumley wrote:
On Fri, 4 Nov 2005, Uwe Ligges wrote:
Dr Carbon wrote:
At the risk of being beaten about the face and body, can somebody explain
why the middle example: log2(2^3); floor(log2(2^3)) is different than
examples 1 and 3?
Because
log2(2^3) - 3
[1]
I am trying to do a forecasting exercise for a series, x. My forecast
model consists of the following
I first regress log(x) on time and dummy variables for each month.
lm(log(x) ~ time + monthly dummies)
I then use predict() to obtain a prediction for the next year.
I then fit an AR(6)/AR(12)
PROTECTED]
To: r-help@stat.math.ethz.ch
Subject: [R] question about sm.density
Date: Thu, 27 Oct 2005 18:47:28 -0700 (PDT)
How can I draw a 95% contour in sm.density?
For example,
y - cbind(rnorm(50), rnorm(50))
sm.density(y, display = slice)
will give 25%, 50% and 75% contours automatically
How can I draw a 95% contour in sm.density?
For example,
y - cbind(rnorm(50), rnorm(50))
sm.density(y, display = slice)
will give 25%, 50% and 75% contours automatically, but
no reference on other values.
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R-help@stat.math.ethz.ch mailing
On Thu, 27 Oct 2005, Cunningham Kerry wrote:
How can I draw a 95% contour in sm.density?
For example,
y - cbind(rnorm(50), rnorm(50))
sm.density(y, display = slice)
will give 25%, 50% and 75% contours automatically, but
no reference on other values.
See ?sm.options, the place to set
ronggui wrote:
The green book tells:The basic technique is classic :keep it simple .A long
,complicated expression or function is less fravorable than a relatively
small computations that combines calls to a few other functions to perform
its tasks.
But I don't get the point totally.Can
The green book tells:The basic technique is classic :keep it simple .A long
,complicated expression or function is less fravorable than a relatively small
computations that combines calls to a few other functions to perform its tasks.
But I don't get the point totally.Can anyone give me an
The help page means exactly what it says, but the English is too subtle
and I have reworded it.
I have no idea why you are interested in pairlists (they are hardly used
at user-visible level these days). The point is that pairlist() is NULL
and so strictly not a pairlist at all (try typeof()
the help page says:
'is.list' returns 'TRUE' iff its argument is a 'list' _or_ a
'pairlist' of 'length' 0, whereas 'is.pairlist' only returns
'TRUE' in the latter case.
does the latter case mean a 'pairlist' of 'length' 0?
but
is.pairlist(pairlist())
[1] TRUE
length(pairlist())
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