On Wed, 02 May 2007 11:37:22 +1000
Kate Stark <[EMAIL PROTECTED]> wrote:
> [...] My model is:
>
> fit <- glm(Mature ~ Season * Size - 1, family = binomial, data=dat)
>
> where Mature is a binary response, 0 for immature, 1 for mature. There
> are 3 Seasons.
I would use:
fit <- gl
Dear All,
I recently wrote a package in R and did a check on my package, all is
well except for two warnings:
* checking package dependencies ... WARNING
'library' or 'require' calls not declared from:
MASS
See the information on DESCRIPTION files in the chapter 'Creating R
packages'
This email is intended to highlight 2 problems that I encountered
running R 2.5.0 alpha on a Windows XP machine.
#1 - Open script error
If I click the "Open folder" icon on the toolbar, R opens my script
files perfectly. However, when I select "File > Open Script >
MyFileLocation", I get a fat
Try using the following (without naming the arguments) - it should work.
Surv(fup, status)
I think what is happening is that if you use one or two arguments (unnamed),
Surv assumes that you have right-censored data, with the first argument
being time and the second being status. By specifying 'e
Hi,
I'm trying to do a simple survival analysis on some data, and I'm having the
following problem (here's my code and the error message):
out <- Surv(fup,event=status)
Error in Surv(fup, event = status) : argument "time2" is missing, with no
default
>From reading the documentation, it seems tha
Duncan:
Thanks for taking a stab at my questions -- in following up I discovered the
root of my difficulties -- I had not noticed document R-lang.pdf ("R Language
Definition"). This clarifies a great deal.
FWIW, it seems to me that a number of things I was hung up on (and which you
discusse
Hi,
I was wondering if someone could please help me. I am doing a logistic
regression to compare size at maturity between 3 seasons. My model is:
fit <- glm(Mature ~ Season * Size - 1, family = binomial, data=dat)
where Mature is a binary response, 0 for immature, 1 for mature. There
are 3 Seas
Dear R experts,
I am relatively new to R and am interested in whether there is a package
which will fit data with a swag of distributions and determine the
optimal fit such as stat::fit from technical software solutions?
As is discussed in the following r-help posting goodfit in vcd seems to
d
let me amend my previous message to remove a silly mistake:
I have a (non-normal) distribution S that is a mixture of two normal
distributions C and C-bar. I need to find the percentage of the area
of S that both C and C-bar occupy.
Thanks again,
Alan Gibson
On 5/1/07, Leeds, Mark (IED) <[EMAIL
It seems like this should be pretty straight forward, but for some
reason the answer escapes me.
I have a normal distribution S made up of two normal distributions C
and C-bar. I need to find the percentage of the area of S that both C
and C-bar occupy.
Any suggestions?
Thanks in advance,
Alan G
Hi
Paulo Barata wrote:
> Dr. Murrell and all,
>
> One final suggestion: a future function arc() in package graphics,
> with centre-radius-angle parameterisation, could also include an
> option to draw arrows at either end of the arc, as one can find
> in function arrows().
... and in grid.xspl
Dr. Murrell and all,
One final suggestion: a future function arc() in package graphics,
with centre-radius-angle parameterisation, could also include an
option to draw arrows at either end of the arc, as one can find
in function arrows().
Thank you.
Paulo Barata
---
Hi,
I am using dlda algorithm from supclust package and I am wondering if
the output can be a continuous probability instead of discrete class
label (zero or one) since it puts some restriction on convariance
matrix, compared with lda, while the latter can.
thanks,
--
Weiwei Shi, Ph.D
Research
Dear R-users,
I am trying to use R to calculate sums like the ones in the file attached.
Would you please provide some help? At the moment I have no clue about how
to due...
Thank you in advance,
Kind regards,
Pedro
__
R-help@stat.math.ethz.ch mailing
You seem to be looking for matrix.a[,-1, drop = TRUE]
On Tue, 1 May 2007, alex lam (RI) wrote:
> Dear R users,
>
> Having searched the mail archive I think the conclusion was that it is
> not possible to have a column name when there is only one column in the
> matrix. But I thought I'd check wit
Hi
Paulo Barata wrote:
> Dr. Snow and Prof. Ripley,
>
> Dr. Snow's suggestion, using clipplot (package TeachingDemos),
> is maybe a partial solution to the problem of drawing an arc of
> a circle (as long as the line width of the arc is not that large,
> as pointed out by Prof. Ripley). If the a
ONLINE VENDOR NEUTRAL INTRO TO DATA MINING FOR ABSOLUTE BEGINNERS
(no charge)
A non-technical data mining introduction for absolute beginners
May 23, 2007, 10AM - 11AM PST
Future Sessions (June 14, Sept 7)
To register for the webinar
---
1. Go
On 01-May-07 17:03:46, Thür Brigitte wrote:
>
> Hi
>
> My simulation with the followin R code works perfectly:
> sim <- replicate(999, sum(exp(rgamma(rpois(1,2000),
> scale = 0.5, shape = 12
>
> But now I do not want to have values in object "sim" exceeding
> 5'000'000, that means that I am
On Tue, 2007-05-01 at 19:33 +0200, [EMAIL PROTECTED] wrote:
> Hello,
>
> I'm trying to sort my bargraph.CI plot (function like barplot in the
> SCIPLOT package) by the mean of the response variable.
>
> Does somebody have a trick for it.
>
> Thank you.
>
> Romain Mayor, PHD student.
If it is b
Hello,
I'm trying to sort my bargraph.CI plot (function like barplot in the
SCIPLOT package) by the mean of the response variable.
Does somebody have a trick for it.
Thank you.
Romain Mayor, PHD student.
__
R-help@stat.math.ethz.ch mailing list
http
Dr. Snow and Prof. Ripley,
Dr. Snow's suggestion, using clipplot (package TeachingDemos),
is maybe a partial solution to the problem of drawing an arc of
a circle (as long as the line width of the arc is not that large,
as pointed out by Prof. Ripley). If the arc is symmetrical around
a vertical
Hi,
I recently did a study where we gathered decisions and confidence
ratings. My understanding is that I can convert this to a ROC curve
by getting hits and false alarms at the various confidence ratings.
I figured out that part of the problem. I noticed a few functions
for calc
On Tue, 2007-05-01 at 18:03 +0100, alex lam (RI) wrote:
> Dear R users,
>
> Having searched the mail archive I think the conclusion was that it is
> not possible to have a column name when there is only one column in the
> matrix. But I thought I'd check with the more experienced users.
>
> What
Hi
My simulation with the followin R code works perfectly:
sim <- replicate(999, sum(exp(rgamma(rpois(1,2000), scale = 0.5, shape = 12
But now I do not want to have values in object "sim" exceeding 5'000'000, that
means that I am just using the beginning of densitiy function gamma x < 15.4.
Dear R users,
Having searched the mail archive I think the conclusion was that it is
not possible to have a column name when there is only one column in the
matrix. But I thought I'd check with the more experienced users.
What I tried to do was: in a loop I pick a column, record the column
name a
And since Peter Dalgaard also just answered (without advertising his book):
if you (or your library) happen to have 'Introductory Statistics with R' by
Peter Dalgaard, have a look at section 12.4.
Best,
Roland
On 5/1/07, raymond chiruka <[EMAIL PROTECTED]> wrote:
>
> how do l programme the logran
On Tue, 1 May 2007, Greg Snow wrote:
> Here is an approach that clips the circle you like from symbols down to
> an arc (this will work as long as the arc is less than half a circle,
> for arcs greater than half a circle, you could draw the whole circle
> then use this to draw an arc of the bacgro
Hello,
I am trying to figure out what nnet does when you select nnet =TRUE, I
understand that it provides you with linear outputs, but I don't understand
how it arrives at those linear outputs. I assume that nnet still applies the
logistic function as the activation function for the nodes in the h
On Tue, 2007-05-01 at 08:34 -0700, raymond chiruka wrote:
> how do l programme the logrank test. l am trying to compare 2 survival curves
See:
library(survival)
?survdiff
and take note of the 'rho' argument, which when set to 0 is the logrank
test.
HTH,
Marc Schwartz
Hi,
On 5/1/07, raymond chiruka <[EMAIL PROTECTED]> wrote:
>
> how do l programme the logrank test. l am trying to compare 2 survival
> curves
if you simply want to use the logrank test, have a look at the first example
of the function survdiff in the survival package. If you read the help page
t
raymond chiruka wrote:
> how do l programme the logrank test. l am trying to compare 2 survival curves
>
>
>
library(survival)
?survdiff
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the pos
how do l programme the logrank test. l am trying to compare 2 survival curves
-
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-
On Tue, 1 May 2007, Duncan Murdoch wrote:
> On 01/05/2007 12:29 AM, Graham Wideman wrote:
>> Folks:
>>
>> I'd appreciate if someone could straighten me out on a few concepts which
>> are described a bit ambiguously in the docs.
>>
>> 1. data.frame:
>>
>> Refan p84: 'A data frame
On Tue, 1 May 2007, Tak Wing Chan wrote:
> Hello,
>
> For a long time, I have been creating eps files from R using the
> following command:
>
> dev.copy2eps(file="my.eps")
>
> This has worked very well. But recently, the compositor of a journal is
> complaining that
>
> "The eps files would be use
Here is an approach that clips the circle you like from symbols down to
an arc (this will work as long as the arc is less than half a circle,
for arcs greater than half a circle, you could draw the whole circle
then use this to draw an arc of the bacground color over the section you
don't want):
l
Hello,
For a long time, I have been creating eps files from R using the
following command:
dev.copy2eps(file="my.eps")
This has worked very well. But recently, the compositor of a journal is
complaining that
"The eps files would be useable except that they have not converted the
type to outl
"Alan E. Davis" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
>I have been trying to visualize times of lowest tides, month by month.
> I have tide predictions with times either in unix time or a text
> format, and heights in feet or meters. I had been able to derive the
> clock tim
There is the grid.xspline function in the grid package that allows for
things like this (the control points, though more general than what you
state). I don't know if it uses the postscript curveto, or approximates
using line segments.
You can also use the xfig device, then use xfig, winfig, or j
I have been trying to visualize times of lowest tides, month by month.
I have tide predictions with times either in unix time or a text
format, and heights in feet or meters. I had been able to derive the
clock times of each prediction. I would now like to graph this data
with points showing he
This thread prompts me to ask about something I've
been pondering for a while, as to whether there's an
implementation somewhere ticked away in the R resources.
So far, people have been responding to the original query
in terms of increasing the numbers of points, and joining
these by lines.
Howe
Vipin Singhal wrote:
(nothing, except for an attached file)
configure:3749: checking for gcc
configure:3778: result: no
configure:3829: checking for cc
configure:3858: result: no
configure:3871: checking for cc
configure:3917: result: no
configure:3970: checking for cl
configure:3999: result: no
Greetings.
It looks like your R config can't find your C compiler. Do you have /
usr/ccs/bin in your path? Or, if you installed Studio 11, do you have
/usr/ccs/bin and /opt/SUNWspro/bin in your path?
Hope this helps,
Jon
__
R-help@stat.math.ethz.ch
--- "Liaw, Andy" <[EMAIL PROTECTED]> wrote:
> Looks very neat, Gabor!
>
> I just cannot fathom why anyone who want to write
> numerics with those
> separators in a flat file. That's usually not for
> human consumption,
> and computers don't need those separators!
>
> Andy
It' often a cas
R has a file INSTALL which asks you to read R-admin.html if you have a
problem. That manual explains that you need a C (preferably C99) and a
Fortran compiler. This extensive posting merely says that you don't have
a C compiler in your path. That's not something we can help you with.
(Lots of
Ken,
Take a look at the just released contrast package.
Max
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Ken Nussear
Sent: Monday, April 30, 2007 6:12 PM
To: r-help@stat.math.ethz.ch
Subject: [R] Independent contrasts from lme with interactions
Hi
On Tue, 1 May 2007, Jim Lemon wrote:
> Paulo Barata wrote:
>> Dear R-list members,
>>
>> I would like to draw a smooth arc. I can draw an arc
>> parametrically, but this produces an arc too coarse,
>> even allowing for different increments in sequence t
>> in the example below. Function "symbols"
Hi
see ?ifelse
ifelse(censoring>survival, survival, censoring)
Regards
Petr
[EMAIL PROTECTED]
[EMAIL PROTECTED] napsal dne 01.05.2007 13:25:18:
> l have the following dataset and would like to calculate the actual
survival time by
> if censoring time > survival time then actual survival t
Paulo Barata wrote:
> Dear R-list members,
>
> I would like to draw a smooth arc. I can draw an arc
> parametrically, but this produces an arc too coarse,
> even allowing for different increments in sequence t
> in the example below. Function "symbols" (graphics) does
> produce a smooth circle, bu
On Mon, 30 Apr 2007, Pedro Mardones wrote:
> Dear R users;
>
> Is there any way to intersect a filled contour image and a polygon? My
> problem is that I want to create a kriging map and the boundaries of
> my map are given by the coordinates of the polygon.
>
> So far I can superompose the poly
l have the following dataset and would like to calculate the actual survival
time by
if censoring time > survival time then actual survival time =survival time
else its= censoring time.
treatmentgrp strata censoringTimesurvivalTime censoring
actualsurvivaltim
[1,]
On 01/05/2007 12:29 AM, Graham Wideman wrote:
> Folks:
>
> I'd appreciate if someone could straighten me out on a few concepts which
> are described a bit ambiguously in the docs.
>
> 1. data.frame:
>
> Refan p84: 'A data frame is a list of variables of the same length with
>
This file contains any messages produced by compilers while
running configure, to aid debugging if configure makes a mistake.
It was created by R configure 2.4.1, which was
generated by GNU Autoconf 2.59. Invocation command line was
$ ./configure
## - ##
## Platform. ##
## -
David Barron gave me a good tip that I had not seen:
> Have a look at FAQ 2.16 in the R for Windows FAQ.
Knut Krueger wrote:
> My workaround for that problem is to build the data sheet in Excel and
> import it to SPSS and R.
> Or to export the SPSS sheet to CSV (or maybe if it is possible to
>
Thats exactly what I am looking for! Thanks for your help!
-Ursprüngliche Nachricht-
Von: Peter Dalgaard [mailto:[EMAIL PROTECTED]
Gesendet: Dienstag, 1. Mai 2007 11:46
An: Dimitris Rizopoulos
Cc: Thür Brigitte; r-help@stat.math.ethz.ch
Betreff: Re: [R] simulation
Dimitris Rizopoulos w
Dimitris Rizopoulos wrote:
> maybe you're looking for something like this:
>
> x <- rpois(999, 2000)
> y <- numeric(length(x))
> for (i in seq_along(x))
> y[i] <- sum(exp(rgamma(x[i], scale = 2, shape = 0.5)))
>
>
Or use sapply,
sapply(x, function(x) sum(exp(rgamma(x[i], scale = 2, shape =
Robert A LaBudde wrote:
> At 11:32 PM 4/30/2007, Deepankar wrote:
>
>> Hi all,
>>
>> I am trying to do a maximum likelihood estimation. In my likelihood
>> function, I have to evaluate a double integral of the bivariate
>> normal density over a subset of the points of the plane. For
>> instan
Liaw, Andy wrote:
> Looks very neat, Gabor!
>
> I just cannot fathom why anyone who want to write numerics with those
> separators in a flat file. That's usually not for human consumption,
> and computers don't need those separators!
>
> Andy
>
>
The world is stranger than you think...
(O
maybe you're looking for something like this:
x <- rpois(999, 2000)
y <- numeric(length(x))
for (i in seq_along(x))
y[i] <- sum(exp(rgamma(x[i], scale = 2, shape = 0.5)))
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
C
Hi
[EMAIL PROTECTED] napsal dne 01.05.2007 09:03:46:
>
> Hello
>
> I would like to simulate datasets in the following way:
>
> x <- rpois(999, 2000)
> y <- sum(exp(rgamma(x, scale=2, shape=0.5)))
You computed sum of your 999 values. Regardless of how many values are
summed the result is alwa
That's fantastic, guys! Thank you very much. Paul's solution will
definitely suffice until the perpendicular symbol is implemented in
plotmath.
-Matt
On 1 May 2007, at 00:40, Paul Murrell wrote:
> Hi
>
>
> Matthew Neilson wrote:
>> Thanks for your response, Gabor.
>>
>> That works quite nic
On Tue, 1 May 2007, Robert A LaBudde wrote:
> At 11:32 PM 4/30/2007, Deepankar wrote:
>> Hi all,
>>
>> I am trying to do a maximum likelihood estimation. In my likelihood
>> function, I have to evaluate a double integral of the bivariate
>> normal density over a subset of the points of the plane.
Hello
I would like to simulate datasets in the following way:
x <- rpois(999, 2000)
y <- sum(exp(rgamma(x, scale=2, shape=0.5)))
The problem is, that by calling "y" I just get 1 value back and not 999 values.
Can anyone help me? Thanks!
Brigitte
[[alternative HTML version dele
62 matches
Mail list logo
