I just came across another package for irregular dates, zoo,
giving another alternative.
It can be used together with dates, chron or POSIXct. For
example, using chron:
require(zoo)
require(chron)
z.zoo - zoo(z$Data, chron(z$Date, format=y-m-d))
---
Date: Mon, 23 Feb 2004 17:22:42 -0500
You have to read the LAPACK code. It says
* INFO(output) INTEGER
* = 0: successful exit.
* 0: if INFO = -i, the i-th argument had an illegal value.
* 0: DBDSDC did not converge, updating process failed.
and 1 0 so this was a convergence failure inside the
filter.matrix.center implements Manhattan or L 1 distance.
If you want to define neighbor points
by Euklidean distances (L 2) use filter.matrix.center(p=2):
filter.matrix.center.p - function(n=9,size=5,p=2){
x-matrix(1,n,n)
center-(n+1)/2
(abs(row(x)-center)^p+abs(col(x)-center)^p)^(1/p)
Torsten Steuernagel wrote:
On 24 Feb 2004 at 21:38, Uwe Ligges wrote:
setClass(myclass, representation(ANY, x = numeric, y
=numeric))
new(myclass, 1:10)# works
new(myclass, Test) # works
new(myclass, factor(1:10))# fails
Why do you think it fails?
I was typing faster
Hello,
I am using the function lm to fit several responses at the same time (100
responses). At the end of the fit, I get an object of class mlm.
I would like to know if there is a way to access to each of the 100
underlying models separately (is it a list, ... ?). Which syntax should I
use to
Hi,
Id like to perform statistical tests on Excel with the RExcel package.
Is it possible ? If yes, how to do that ?
Thanks for your help
Benoît SECHET
mailto:[EMAIL PROTECTED] [EMAIL PROTECTED]
http://benoit.sechet.9online.fr http://benoit.sechet.9online.fr
[[alternative
On Wed, 25 Feb 2004, ZABALZA-MEZGHANI Isabelle wrote:
I am using the function lm to fit several responses at the same time (100
responses). At the end of the fit, I get an object of class mlm.
Actually of class c(mlm, lm).
I would like to know if there is a way to access to each of the 100
On 25 Feb 2004 at 10:00, Uwe Ligges wrote:
So you are going to handle/mix the S4 class like/with S3 classes? Hmm.
Yes, and there is the problem. With S4 classes, it works. Now I would
expect that is(factor(S3object, ANY) will be FALSE for factor and any
other S3 class, but is(S3object, ANY)
I have two dataframes A and B consisting of latitude longitude coordinates
of points. For each point in A I want to find the k-nearest neighbours in B.
Currently, I calculate the distance from each point in A to all the points
in B (using rdist.earth() in fields package), sort the points of B by
Spencer Graves [EMAIL PROTECTED] writes:
How about the following: set.seed(5)
N - 8 # later 10
(nPois - rpois(N, 2))
[1] 1 3 4 1 0 3 2 3
z - rnorm(sum(nPois))
?
I read the original request as simulating the sum of a
Poisson distributed number of Normals. So I'd suggest
Hello
I'm starting to use R on a Windows XP Pro machine which is not connected to
the internet;
I want to use database connection so I downloaded the file RODBC_1.0-4.tar
from CRAN;
this file is not accepted by the
Packages-Install Packages from local zip file menu function of R!!!
I would
You need the precompiled binaries of packages for that:
http://cran.at.r-project.org/bin/windows/contrib/1.8/RODBC_1.0-4.zip
-Heinrich.
-Ursprüngliche Nachricht-
Von: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Im Auftrag von
pascal dessaux
Gesendet: Mittwoch, 25. Februar 2004
Hallo
I use following function to produce graph of yright and yleft against x with
additional options (like smoothing the lines, colour, line and point type choice and
an options for some axes formating.
Cheers
Petr
Hi all
I use the function simtest for execute a Dunnett's test
See:
y-c(6.5,1.60E+01,1.05E+01,6.7,1.78E+01,6.6,4.7,7.5,1.63E+01,4.2,1.15E+01,2.
79E+01,9,1.07E+01,3.00E+01,9.5,1.42E+01,1.40E+01,9.4,6.1,3.00E+01,8.4,3.00E+
Deepayan,
Thanks for the quick response. Just to make sure I understand, let me
explain in a bit more detail what I am trying to do.
I have created a levelplot (with contour lines and colored regions), and
what I am trying to figure out now is how to add a series of horizontal
lines across
On Wednesday 25 February 2004 08:13, Jeff Jorgensen wrote:
Deepayan,
Thanks for the quick response. Just to make sure I understand, let me
explain in a bit more detail what I am trying to do.
I have created a levelplot (with contour lines and colored regions), and
what I am trying to
I am not sure a previous e-mail reached the list (no mail aknowledgement from
R-boundle etc.). The question was how to write polygon
or segment coordinates into a shapefile set or any other ArcGIS supported format. The
library shapefiles seems to do something but
the documentation is a bit
Hi,
when I write the likelihood function as
fn-function(x) -50*log(2*pi)-100*log(sigma)-(1/2*(sum((x-mu)/sigma)^2))
then what should I do since it shows that Error in log(sigma) : Object
sigma not found.
Thanks
edward
From: Edward Sun
Dear Sir/Madam,
I am using R version 1.8.1. I am
Edward -
Either optim() or fitdistr() has an additional required
argument which specifies the names (and incidentally starting
values) for the parameters to be estimated. Did you supply
that argument ? See help(optim), help(fitdistr).
- tom blackwell - u michigan medical school -
Have you worked through the posting guide at the end of each
r-help email? In particular, have you worked the examples in
help('fitdistr') in library MASS and optim?
hope this helps. spencer graves
Edward Sun wrote:
Hi,
when I write the likelihood function as
fn-function(x)
I think It could not be done for the moment .. Perhaps, I am wrong !
In the package maptools, there is read.shape shape2poly, shape2line...
These functions allow to read shapefiles files but not to write it.
With the shapefiles package you can write shape object to files. I think
that one
Do:
library(mle)
?mle
and read the documentation and the example. That should get you on the
right track.
Andy
From: Edward Sun
Hi,
when I write the likelihood function as
fn-function(x)
-50*log(2*pi)-100*log(sigma)-(1/2*(sum((x-mu)/sigma)^2))
then what should I do since it
There is a little problem with the approach I described in my previous email.
In ADE-4, coordinates are given in pixel and so Y are inverted. You must
invert your Y coordinates to obtain the good representation in ArcView. An
example:
library(ade4)
library(shapefiles)
library(maptools)
try1
The read.spss parameter defaults are:
use.value.labels=TRUE,
to.data.frame=FALSE,
Is there some reasoning other than historical for this choice? In most
instances, it seems that the opposite default choice
(use.value.labels=FALSE, to.data.frame=TRUE,) would better preserve any
existing
I saw a Help e-mail related to MLE. Does R have a probability weighted method (PWM)
estimator function? I can't seem to find anything on PWM, unless my eyes are playing
trick on me.
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On Wed, 25 Feb 2004, Robert W. Baer, Ph.D. wrote:
The read.spss parameter defaults are:
use.value.labels=TRUE,
to.data.frame=FALSE,
Is there some reasoning other than historical for this choice? In most
instances, it seems that the opposite default choice
(use.value.labels=FALSE,
On Wed, 25 Feb 2004, Jonathan Wang wrote:
I saw a Help e-mail related to MLE. Does R have a probability weighted
method (PWM) estimator function? I can't seem to find anything on PWM,
unless my eyes are playing trick on me.
The survey package has a function for maximising
Hello All,
I have a 131072x132 matrix for which I need to compute a regular euclidean distance
matrix, which I then need to transform and run agnes() on this transformed matrix. I
am having trouble computing the distance matrix as it is fairly large and I am sure I
have gone over the max.
Arnav -
A suggestion I have made in the past is to run Chris Fraley
and Adrian Raftery's mclust() procedure instead of Rousseuw's
agnes(), if you are willing to use a different clustering method.
The pdf instruction manual for the mclust package includes
explicit suggestions for how to use
If that's 131072 points, not 132 points, the memory needed to store that is:
131072^2 * 8 / 1024^3
[1] 128
That's in gigabytes. When you have a Windows machine that has at least that
much memory, you can try to do that. Before then, try something else.
Andy
From: Arnav Sheth
Hello
On Wed, 25 Feb 2004, Arnav Sheth wrote:
Hello All,
I have a 131072x132 matrix for which I need to compute a regular euclidean distance
matrix, which I then need to transform and run agnes() on this transformed matrix. I
am having trouble computing the distance matrix as it is fairly
Thanks a lot for the hints. I will try. Actually I was focusing (in a first stage) on
simple segments (small mammal traplines...).
I turned the problem out writing some lines to export the coordinates into a simple
GRASS ascii file, imported it into GRASS as
vector file and then used the export
Thanks for putting me on the right track. Sorry to be bothersome with
another follow-up, but the code that calls the panel function (see below)
doesn't seem to be working. What am I doing wrong?
Thanks,
Jeff
levelplot(matrix,contour=T, cuts=15,at=seq(...), labels=T, region=T,
Can someone help me with performing leave-out-one cross validation using
R (model built is a Cox model)? Thanks.
-
David Verbel, MPH
Senior Biostatistician
Aureon Biosciences
28 Wells Avenue
Yonkers, NY 10701
Phone: (914) 377-4021
Fax: (914)
You can try and see if the errorest function in the `ipred' package can do
the job.
HTH,
Andy
From: David Verbel
Can someone help me with performing leave-out-one cross
validation using
R (model built is a Cox model)? Thanks.
-
David
Hi,
Could someone please compare Programming with Data: A Guide to the S
Language by J. Chambers and S Programming by W. Venables and B.
Ripley? Ideally, I need a guide for writing R OO-style packages that
intensively interact with C/C++ libraries.
The specific project I have in mind is to
library(survival)
library(boot)
help(coxph)
help(boot)
- tom blackwell - u michigan medical school - ann arbor -
On Wed, 25 Feb 2004, David Verbel wrote:
Can someone help me with performing leave-out-one cross validation using
R (model built is a Cox model)? Thanks.
Not precisely an answer to your question but here are some
OO R links that I have collected over time. Not sure if
all these links still work.
a href=http://www.stat.wisc.edu/~st771-1/slides/wk2-4.pdf;Bates/a |
a href=http://www.maths.lth.se/help/R/;Bengtsson/a |
a
How to express n distinct numbers between 0 and m? ( In R )
Thanks!
-
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PLEASE do read
?sample
sample(0:m, n)
-sd
li xian wrote:
How to express n distinct numbers between 0 and m? ( In R )
Thanks!
-
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Hello,
Thank you all for your replies.
I have just discovered that now, for some reason, R does not let me increase
its memory limit beyond 4095 Mb.
Also, I get a different error message when computing the matrix using
daisy() as opposed to dist():
Error: Cannot allocate vector of size 135168
Hi all,
Just to follow up Don Driscoll's earlier post, can anyone please explain
why se.contrast fails here??
shp-factor(rep(c(reserve,strip),each=96))
site-factor(rep(c(1g,1p,1t,2g,2p,2t,3g,3p,3t,4g,4p
,4t),each=16))
pit-factor(rep(1:16,12))
The problem is not with R; the problem is with Windows, as well
as the x86 architecture. You'll never really be able to access
more than 3GB of physical memory (for a single process).
Accessing more than 4GB requires a 64 bit processor.
-roger
Arnav Sheth wrote:
Hello,
Thank you all for
Roger D. Peng wrote:
The problem is not with R; the problem is with Windows, as well as the
x86 architecture. You'll never really be able to access more than 3GB
of physical memory (for a single process). Accessing more than 4GB
requires a 64 bit processor.
-roger
Alternatively, if you move
From: Joel Pitt
Roger D. Peng wrote:
The problem is not with R; the problem is with Windows, as
well as the
x86 architecture. You'll never really be able to access
more than 3GB
of physical memory (for a single process). Accessing more than 4GB
requires a 64 bit processor.
suppose I have a function example:
getMatrix - function(a,b){
A1-diag(1,2,2)
}
If I want to get the both the A1 and dim(A1) from the function, Can I do
return(A1,dim(A1)) inside the function ? And how can I access A1 and dim(A1) later on?
suppose I have a function example:
getMatrix - function(a,b){
A1-diag(1,2,2)
}
If I want to get the both the A1 and dim(A1) from the function, Can I do
return(A1,dim(A1)) inside the function ? And how can I access A1 and
dim(A1) later on?
The general approach for this is to use a
In general, one would use a list to wrap all objects to be returned into one
object; e.g.,
getMatrix - function(a, b) {
A1 - diag(1,2,2)
return(list(matrix=A1, dim=dim(A1)))
}
You can then access them as:
mat - getMatrix(1,1)
mat$matrix
mat$dim
My question is, why do you need to return
suppose I have a vector called v,
how can I get the index of the minimum element of vector v?
Thanks!
-
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min(v)
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of li xian
Sent: Wednesday, February 25, 2004 8:46 PM
To: [EMAIL PROTECTED]
Subject: [R] minimum value
suppose I have a vector called v,
how can I get the index of the minimum element of vector v?
Hi all,
As happens from time to time, discussions on this list appear regarding
the use of popular spreadsheets for statistical analysis. One such
thread (post of mine) is here:
http://maths.newcastle.edu.au/~rking/R/help/03a/6326.html
While not advocating such use, these discussions have
I almost said the same. But he wanted the index.
which.min(v)
min(v)
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of li xian
Sent: Wednesday, February 25, 2004 8:46 PM
To: [EMAIL PROTECTED]
Subject: [R] minimum value
suppose I have a vector
I appreciate the help I've been given so far. The issue I face is
that the data I'm working with has 53000 rows, so in calculating
distance, finding all recids that fall within 2km and summing the
population, etc. - a) takes too long and b) have no sense of progress.
Below is a loop that reads
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