when we applied box priece Q statistic in stat library how does it work?
suppose we have series Yt then either it apply on residuals obtained by
regressing
yt on Yt-1 .or apply direct on the series Yt
-
[[alternative HTML version deleted
> I learned to do this by studying Alfredo Pontillo and Angelo Mineo's
> R-php (http://dssm.unipa.it/R-php). Specifically, look at the file
> pages/result/index.php They have done lots of other good stuff in
> their project, like filtering dangerous commands - you would not want
> to let a user ju
Dear all R users,
Thank you Greg for having time in my problem. Your suggestion is working pretty
fine for my problem. But here I am involved for some teaching assignments in a
local school. If at least I could use sliders for changing values, it would be
very fine.
Have anyone any suggestion
Hie,
I've used GLM function, n try to get a convergence by using a while loop and
break it when my absolute value between the 2 values is less than 1e-09. But
i got this warning message, what does this mean? how should i correct my
algorithm? my start value is 0.5.
Error in if (abs((phi_0) - (phi
This is not an error in R. It is a problem of your permissions under
Vista, and was discussed here:
https://stat.ethz.ch/pipermail/r-help/2007-April/129661.html
a few days ago.
On Thu, 19 Apr 2007, Roberto Mario Domínguez Olivero wrote:
Mrs and Mr
My operative system is "Windows Vista" and
Mrs and Mr
My operative system is "Windows Vista" and can't update or install pakages of
CRAN, the message for all pakages is for example:
Erro en zip.unpack(pkg, tmpDir) : no fue posible abrir el archivo 'C:/Program
Files/R/R-2.4.1pat/library/file8f653c7/MASS/chtml/MASS.chm'
Help me
thank yo
Hi all,
I'm usually comfortable using the *apply functions for vectorizing loops
in R. However, my particular problem now is using it in a sequential
operation, which uses values evaluated in an offset of the loop vector.
Here is my example using a for loop approach:
dat <- data.frame(year=rep
You can also set this option globally with options(stringsAsFactors = TRUE)
I believe this was added in R 2.4.0.
--- Gabor Grothendieck <[EMAIL PROTECTED]> wrote:
> Try this:
>
> DF <- data.frame(let = letters[1:3], num = 1:3, stringsAsFactors = FALSE)
> str(DF)
>
>
> On 4/19/07, John Kane
On Thu, 19 Apr 2007, Ranjan Maitra wrote:
> Hi,
>
> I have a vector of p*(p+1)/2 elements, essentially the lower triangle of
> a symmetric matrix. I was wondering if there is an easy way to make it
> fill a symmetric matrix. I have to do it several times, hence some
> efficient approach would b
Le 07-04-19 à 19:02, Peter Dalgaard a écrit :
> Dirk Eddelbuettel wrote:
>> On Thu, Apr 19, 2007 at 10:51:58PM +0200, Peter Dalgaard wrote:
>>
>>> Deepankar Basu wrote:
>>>
I tried to install the package "tseries" but could not do so. Any
suggestions are welcome. I am using Ubuntu Linux
Hi Lukas,
Using by() or its cousins tapply() etc. is tricky,
as you need to properly merge results back into X.
You can do that by adding a key ID variable to X,
and carrying along that key ID variable in calls
to by() etc., though I haven't tested out a method.
You can also create a new column
Deepankar,
On 19 April 2007 at 21:32, DEEPANKAR BASU wrote:
| Thanks Dirk, that worked.
|
| $ sudo apt-get install r-base-dev r-cran-tseries
Glad to be of help, and thanks for reporting back. Now that you have
r-base-dev and what it pulled it, your next attempts at installing from CRAN
(under s
Emmanuel
One option which appears to work:
emmanuel <- c(1,1,1,2,2,3,3,3)
#emmanuel <- c(1,1,2,3,4,5,6,6,6,6,6,6,6,6,7,8)
runs <- rle(emmanuel)[[1]]
shuffle <- sample(1:length(runs))
newEmm <- rep(emmanuel[cumsum(runs)[shuffle]], runs[shuffle])
startPos <- sample(1:length(emmanuel), 1)
if (start
Thanks Dirk, that worked.
$ sudo apt-get install r-base-dev r-cran-tseries
Deepankar
- Original Message -
From: Dirk Eddelbuettel <[EMAIL PROTECTED]>
Date: Thursday, April 19, 2007 5:32 pm
Subject: Re: [R] Problem installing packages
> On Thu, Apr 19, 2007 at 05:19:37PM -0400, Deepanka
Hi,
I have a vector of p*(p+1)/2 elements, essentially the lower triangle of a
symmetric matrix. I was wondering if there is an easy way to make it fill a
symmetric matrix. I have to do it several times, hence some efficient approach
would be very useful.
Many thanks and best wishes,
Ranjan
_
This is in the FAQ, if I remember correctly... However, alternatively:
As Jeff Horner recently pointed out on the list, the Cairo package is a
good way of generating png without needing an X display. You may want
to look into that. I've just installed cairo on our CentOS boxes and
the Cairo pac
Try using png2() in R.utils, which immitates png() but uses bitmap()
and ghostscript to create the PNG file. You need to set 'R_GSCMD' to
tell R where ghostscript is located - you can use
System$findGhostscript() at startup to let R try to locate ghostscript
for you.
/H
On 4/19/07, Mark Liberman
Hello,
I was wondering if anyone can think of a straightforward way (without
loops) to do the following shuffling:
Let's imagine a vector:
c(1,1,1,2,2,3,3,3)
I would like to derive shuffled vectors __where the same digits are
never separated__, although they can be at both ends (periodicity).
S
>Is this a consequence of machine error or something else?
>Could this be overcome? (It works correctly when integers are used in
>the sequences as well as in many other circumstances)
The usual solution for testing a==b with floating-point round-off error is
abs(a-b) X1=seq(0,1,len=11)
> X2=seq(
I'd like to use an R CMD BATCH script as part of a chron job that is set
up to run every hour.
The trouble is that the script creates a graphical output in a file via
png(), and apparently this in turn works through X.
When cron invokes the job, no X server is available -- I suppose that
the DISP
Hello,
I am playing around with the R_X11.c source code and wanted to load
the compiled DLL via dyn.load.
It loads properly (and masks the old X11 device) when i load it in
the console R (version: version.string R version 2.4.1 (2006-12-18) )
However the same command doe
There are some examples here:
library(zoo)
?aggregate.zoo
and also in
vignette("zoo")
On 4/19/07, Soare Marcian-Alin <[EMAIL PROTECTED]> wrote:
> Hello Everybody,
>
> How can I filter a dataset?
>
> Im trying to filter the dataset EuStockMarkets monthly and quarter.
>
> data(EuStockMarkets)
>
On 4/19/07, Spencer Graves <[EMAIL PROTECTED]> wrote:
> Have you tried 'getVariable' from Matlab? I also recently failed
> to get 'readMat' to work for me -- probably because I hadn't saved the
> files using the options Henrik suggested below.
>
> Fortunately, I was able to get somethi
Try this:
DF <- data.frame(let = letters[1:3], num = 1:3, stringsAsFactors = FALSE)
str(DF)
On 4/19/07, John Kane <[EMAIL PROTECTED]> wrote:
>
> --- Tyler Smith <[EMAIL PROTECTED]> wrote:
>
> > I really need to sit down with the manual and sort
> > factors and classes
> > properly. In your case,
Hello Everybody,
How can I filter a dataset?
Im trying to filter the dataset EuStockMarkets monthly and quarter.
data(EuStockMarkets)
ftse = EuStockMarkets[,4]
Alin
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing lis
Dirk Eddelbuettel wrote:
> On Thu, Apr 19, 2007 at 10:51:58PM +0200, Peter Dalgaard wrote:
>
>> Deepankar Basu wrote:
>>
>>> I tried to install the package "tseries" but could not do so. Any
>>> suggestions are welcome. I am using Ubuntu Linux and here is what I did:
>>>
>>> $ sudo R
>>>
I've been using R actively for only the past few months under Mac OS
X, but have found a few situations where I cannot get a package to
load. This seems like the same situation reported recently on the
thread "R-2.4.1 for MacOS X - languageR, acepack, Hmisc":
> > library(Hmisc)
> Error in d
Have you tried 'getVariable' from Matlab? I also recently failed
to get 'readMat' to work for me -- probably because I hadn't saved the
files using the options Henrik suggested below.
Fortunately, I was able to get something like the following to work:
# Start Matlab server
Matla
On Thu, 19 Apr 2007, Albrecht, Dr. Stefan (AZ Private Equity Partner) wrote:
> I would like to inquire, if it is a desired feature that the combination
> with rbind() of two data frames with factors columns does not sort the
> factors levels of the combined data frame.
Yes, and a documented one
On Thu, Apr 19, 2007 at 05:19:37PM -0400, Deepankar Basu wrote:
> While installing R (version 2.4.0) on my Dell desktop (Optiplex GX 270)
> on a Ubuntu Linux platform, I had followed the advice contained in the
> following link:
> http://cran.r-project.org/bin/linux/debian/README
>
> Briefly, what
...and so say google [http://www.google.com/search?q=1%250.1]:
"1 modulo 0.1 = 0.1",
so end of discussion ;)
In bit of a food coma now, but the following is interesting:
r = a %% b
<=>
r = (b*a/b) %% (b*b/b)
<=>
r = b*((a/b) %% 1)
> modulo <- function(a, b) { b * ((a/b) %% 1) }
On Thu, Apr 19, 2007 at 09:53:04PM +0100, Prof Brian Ripley wrote:
> 'grid' is an integral part of R, so this suggests your R installation is
> broken. (You could have found that out from the R FAQ Q5.1.1.)
Just for the record, it is close to impossible to detach grid from R.
Both are in the r-b
It has nothing to do with round() -- it's the "digits" argument of the print
method that controls the number of digits in the output, print.default in
this case. And the documentation from print.default says for the digits
argument:
"digits: a non-null value for digits specifies the minimum number
On Thu, Apr 19, 2007 at 10:51:58PM +0200, Peter Dalgaard wrote:
> Deepankar Basu wrote:
> > I tried to install the package "tseries" but could not do so. Any
> > suggestions are welcome. I am using Ubuntu Linux and here is what I did:
> >
> > $ sudo R
> >
> > Then once in R, I did
> >
> >
> >>
Dear Thomas and Simon,
On Thu, 19 Apr 2007 07:37:28 -0700 (PDT)
Thomas Lumley <[EMAIL PROTECTED]> wrote:
> On Thu, 19 Apr 2007, Simon Pickett wrote:
>
> > Hi all,
> >
> > I have been bumbling around with r for years now and still havent
> come up
> > with a solution for plotting reliable graphs
While installing R (version 2.4.0) on my Dell desktop (Optiplex GX 270)
on a Ubuntu Linux platform, I had followed the advice contained in the
following link:
http://cran.r-project.org/bin/linux/debian/README
Briefly, what I had done is the following:
I had added "deb http://cran.R-project.org/bi
Peter,
Many thanks. I have never seen a confidence interval from 0.000 to
6265941604681544800.000 - this is a worry.
I am also still puzzled why use of digits = 3, produced output which
includes 2, 3 and 4 decimal points as per below. The two decimal
point values for the coef should h
On 4/19/2007 4:29 PM, Bernhard Klingenberg wrote:
> Thank you! Is floating point arithmetic also the reason why
>
> 1 %% 0.1
>
> gives the "surprising" answer 0.1 (because 0.1 cannot be written as a
> fraction with denominator a power of 2, e.g. 1%%0.5 correctly gives 0).
>
> This seems to go
Please, no. It is already annoying enough that levels are sorted
when creating a factor. Don't compound it by extending this to
other functions.
In concept the order of the levels of a factor is irrelevant (although
in practice it makes a big difference, e.g. when plotting). If so,
then why i
Hi,
as already mentioned, do not save MAT files in ASCII format but save
to binary formats, i.e. do *not* use "-ascii". Moreover, from
?readMat, you find that:
"From Matlab v7, _compressed_ MAT version 5 files are used by
default [3]. These are not supported. Use 'save -V6' in Matlab t
HI Mayte & Gregory,
This is probably a question needing to be posted to r-sig-mac. A
search for this problem on that forum turns up lots of hits. I think
everyone is having these problems (which makes me pause about whether
to switch to Mac, given how much I use R). Below is a message from the
r-s
'grid' is an integral part of R, so this suggests your R installation is
broken. (You could have found that out from the R FAQ Q5.1.1.)
You have told us very little (please study the posting guide), not
including which version of R and how you installed it. Please try
reinstalling R, from th
Deepankar Basu wrote:
> I tried to install the package "tseries" but could not do so. Any
> suggestions are welcome. I am using Ubuntu Linux and here is what I did:
>
> $ sudo R
>
> Then once in R, I did
>
>
>> install.packages("tseries", dep=TRUE)
>>
>
> which gave a long list of errors.
Bernhard Klingenberg wrote:
>
> Thank you! Is floating point arithmetic also the reason why
>
> 1 %% 0.1
>
> gives the "surprising" answer 0.1
>
Floating point arithmetic is one of the most Evil things
computer science imposed against the mathematicians; any
reasonable person, back when comput
Thank you! Is floating point arithmetic also the reason why
1 %% 0.1
gives the "surprising" answer 0.1 (because 0.1 cannot be written as a
fraction with denominator a power of 2, e.g. 1%%0.5 correctly gives 0).
This seems to go a bit against the statement in the help for '%%', which
states "F
Hi,
I would like to compare results from a k-means analysis to that done with PAM.
However, when I ran the k-means on four clusters it gave me the means for each
result with the number of each cluster e.g.
variable1
1 33.33
2 12.00
3 109.00
4 67.98
So I know for instance cluster 1 has a
I tried to install the package "tseries" but could not do so. Any
suggestions are welcome. I am using Ubuntu Linux and here is what I did:
$ sudo R
Then once in R, I did
> install.packages("tseries", dep=TRUE)
which gave a long list of errors. Going through them, I saw that the
basic problem w
t;,"cc","st")
> > dd1
> > typeof(dd1$st); class(dd1$st)
> >
> > dd2 <- cbind(dd, as.character(st))
> > names(dd2) <- c("aa","bb","cc","st&quo
--- Tyler Smith <[EMAIL PROTECTED]> wrote:
> I really need to sit down with the manual and sort
> factors and classes
> properly. In your case, I think the problem has
> something to do with
> the way a list behaves? I'm not sure, but if you
> convert your list to
> a dataframe it seems to work
I really need to sit down with the manual and sort factors and classes
properly. In your case, I think the problem has something to do with
the way a list behaves? I'm not sure, but if you convert your list to
a dataframe it seems to work ok:
> dd3 <- as.data.frame(dd1)
> typeof(dd3$st)
[1] "inte
On Thu, 19 Apr 2007, tkobayas wrote:
> I use Redhat Linux for R. Now I am trying to use the rJava library. I
> downloaded JRE beta 2 from Sun. I typed
I am not sure why, as JRE 1.6.0 was released a while back.
> [EMAIL PROTECTED] R CMD javareconf
In what R version?
> Java interpreter : /usr/bi
Ravi,
Thanks a lot for that clarification. Now I see that the code works.
Deepankar
On Thu, 2007-04-19 at 14:01 -0400, Ravi Varadhan wrote:
> Hi Deepankar,
>
> Dimitris' code works just fine. Your problem is that the output of optim
> does not have a corresponding "summary" method. Instead yo
Hi Deepankar,
Dimitris' code works just fine. Your problem is that the output of optim
does not have a corresponding "summary" method. Instead you should simply
type the name of the object returned by "optim" to look at the results.
> out <- optim(mu.start, mlogl, method = "CG", y = women$J, X
Hi,
I use Redhat Linux for R. Now I am trying to use the rJava library. I
downloaded JRE beta 2 from Sun. I typed
[EMAIL PROTECTED] R CMD javareconf
Java interpreter : /usr/bin/java
Java version : 1.6.0-beta2
Java home path : /usr/java/jre1.6.0
Java library path:
$(JAVA_HOME)/lib/amd64/se
will this work for you?
x <- runif(1000, 0, 40)
x.c <- cut(x, breaks=c(0, 1, 3, 6, 10, Inf))
barplot(table(x.c))
On 4/19/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
> Hi R-helpers
>
> I would like to produce a histogram with uneven bins (e.g., 0, 1-2, 3-5,
> 6-10, 10-20, >20) but I would li
Something along these lines is on my todo list for the TeachingDemos
package, so any thoughts on what you want the user interface to be would
be helpful (do you want sliders to set the x-value? Do you want to click
on the plot to see an update? Or just moving the mouse over the plot
without clicki
On Thu, 19 Apr 2007, Gavin Simpson wrote:
> On Wed, 2007-04-18 at 16:06 +0100, Barry Rowlingson wrote:
>> Schmitt, Corinna wrote:
>>> Dear R-Experts,
>>>
>>> how can I divide the number 0.285 with 2. I need a function.
>>> Result: 0.285 / 2 = 0.1425
>>
>> Just get the / operator:
>>
>> > divide
Dimitris,
Thanks a lot for your suggestion and also for suggestions that others
have provided. I am learning fast and with the help of the R community
will be able to get this going pretty soon. Of course, right now I am
just trying to learn the language; so I am trying to program a standard
probi
I guess you would have to do all those step for a Internet based portal,
but if you just want to have a web interface on a _Intranet_ portal
where you trust your users, you can use Rpad which is much easier in
that you don't really have to write any code, just do the install
procedure. There is a
you have to use "POSIXct" classes to include date-time objects into data
frames. strptime() returns an object of class of "POSIXlt". when you do the
cbind(), it automatically converts test2 into "POSIXct"
you probably want
bsamp$spltime<-as.POSIXct(strptime(test,format="%d-%B-%y %H:%M"))
(but ple
Ok I am replying to my own message! I wrote a "function", it works well but
it's a bit twisted because you will have to edit the last file in excel or
other.
This is to analyze the bayesian predictive power in an analysis where
treatment x is compared to treatment y. Example: Total final subject n
Something probably obivous but I don't see it. I
needed to find the first 1 or two digits of some 5 and
6 digit numbers since they identified research sites
while the rest of the number was the plot id.
I converted the numbers to characters, got the first 1
or 2 characters as appropriate and w
Hi,
> hello I'd like know if it's possible to write macro variables under
> R as we know do it with SAS thanks
For what I know of both softwares, R and SAS are two very different
languages. You don't have "Macros" in R, because you don't need them :
you use functions, which are much more powerful
On Wed, 2007-04-18 at 16:06 +0100, Barry Rowlingson wrote:
> Schmitt, Corinna wrote:
> > Dear R-Experts,
> >
> > how can I divide the number 0.285 with 2. I need a function.
> > Result: 0.285 / 2 = 0.1425
>
> Just get the / operator:
>
> > divide = get("/")
> >
> > divide(0.285,2)
> [1
Sarthi,
I have done what you describe using PHP and R on a linux server.
Basically, you follow these steps:
- Create a form to gather input
- Parse input from the form with PHP into a file that R can read
- Run R commands from PHP with exec().
- Convert the postscript output to an image a web br
Dear all,
I would like to inquire, if it is a desired feature that the combination with
rbind() of two data frames with factors columns does not sort the factors
levels of the combined data frame.
> str(rbind(data.frame(a = factor(c(4, 3))), data.frame(a = factor(c(2, 1)
'data.frame': 4
Let's say I have some data DIFF, then I do
> a <- acf(DIFF, lag.max=2)
> a$acf
, , 1
[,1]
[1,] 1.000
[2,] -0.2085724
[3,] -0.1597789
> a <- acf(DIFF)
> a$acf
, , 1
[,1]
[1,] 1.
[2,] -0.20857236
[3,] -0.15977892
How come they are different? I thought the
OK it works thanks.
francogrex wrote:
> Hello I am using the "for (i...)" and a sink() into a file. But the output
> I
> am having is not arranged in either a vector or any other good structure.
> I
> would like to have the output in a file directly as a vector so that I do
> not have to edit th
I am an undergraduate student in Isik University, in Istanbul/TURKEY. For
my term project, I am studying on the relationship between the prices and
market shares of 3 automobile models. I need to find estimates for the
parameters so that I can continue my study. I found about your MNP package
a
Try this:
# test data
Input <- "4547;1970.01.01 00:00-1970.01.01 01:00; noData
4547;1970.01.01 00:00-1970.01.01 01:00; noData"
# replace next line with Lines <- readLines("myfile.dat")
Lines <- readLines(textConnection(Input))
Lines <- gsub("[;-]", " ", Lines)
read.table(textConnection(Lines
Hi R-helpers
I would like to produce a histogram with uneven bins (e.g., 0, 1-2, 3-5,
6-10, 10-20, >20) but I would like the resulting bars to be the same width (
i.e., a bar's width would not be proportional to its corresponding bin
size).
Also, the x and y axes of my histograms frequently (almo
## making data up
# make matrix with some equal values
> mat <- cbind(x=rnorm(10),y=rnorm(10),z=rnorm(10))
> mat[c(8,9),"y"] <- mat[c(1,7),"x"]
> mat
x y z
[1,] 0.26116849 0.5823529 -0.96924020
[2,] -0.21415406 0.1085396 2.00542549
[3,] 0.56890081 -1.25263
Introduction to R Ch. 10. Writing your own
functions.
--- elyakhlifi mustapha <[EMAIL PROTECTED]>
wrote:
> hello I'd like know if it's possible to write macro
> variables under R as we know do it with SAS
> thanks
__
R-help@stat.math.ethz.ch mailing
Dear All,
I am trying to convert to POSIXct after pasting a date and a time in
character format with strptime.
It is probably obvious but I don't understand why I get an error message
after
bsamp$spltime<-strptime(test,format="%d-%B-%y %H:%M")
whereas I can get what I want if I do it in 2 steps
hello I'd like know if it's possible to write macro variables under R as we
know do it with SAS
thanks
-
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat
Hi,
> I've got a matrix (mail end) with the colnames x, y, z. In this matrix
> are different measurements. x and y are risign coordinates.
>
> My question. Always, if the "x" AND "y" coordinates are the same, I want to
> get the mean of their z values.
Maybe you could try with the aggregate func
Hans-Peter wrote:
>
>> This works in most cases.
>
> Huu? (the package is supposed to work in *all* cases...!). Do you use
> the newest version (v1.3.1 or v1.3.2)? If there are any bugs/issues,
> please report them to me and they - most likely - will get fixed.
>
Here a
On Thu, 19 Apr 2007, Simon Pickett wrote:
> Hi all,
>
> I have been bumbling around with r for years now and still havent come up
> with a solution for plotting reliable graphs of relationships from a
> linear regression.
termplot() does this for a range of regression models (without interaction
d. sarthi maheshwari wrote:
> Hi
>
> I am trying to provide web interface to my R application. My requirements
> are simple and can be written down as follows :
>
> 1) User must provide all the input parameters on web interface.
> 2) Based on the input values, R will do some computations.
> 3) Pr
Dear List,
somebody knows, if the following operation can be done in an easier way?
The data rows which should be read into R look like that:
4547;1970.01.01 00:00-1970.01.01 01:00; noData
Unitil now we are doing this procedure:
1. Dividing columns which are separated by ";"
=> temp <- re
No.
---
Ravi Varadhan, Ph.D.
Assistant Professor, The Center on Aging and Health
Division of Geriatric Medicine and Gerontology
Johns Hopkins University
Ph: (410) 502-2619
Fax: (410) 614-9625
Email: [EMAIL PRO
look at R FAQ 7.10
http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-do-I-convert-factors-to-numeric_003f
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgiu
[EMAIL PROTECTED] wrote:
> ?as.numeric
in response to
> ok how can I do to cancel le function factor for the moment ican't do
> this and I'm stuck with my problem for exemple
...
The use of as.numeric() to convert a factor to a numeric
vector is fraught wi
Thanks. I will try it. Perhaps it works.
Corinna
-Ursprüngliche Nachricht-
Von: Jim Lemon [mailto:[EMAIL PROTECTED]
Gesendet: Donnerstag, 19. April 2007 15:16
An: Schmitt, Corinna
Betreff: Re: [R] plotting command trouble
Schmitt, Corinna wrote:
> I know, but it is needed. Any other i
Ted Harding wrote:
>
> There are various ways round this, but a 'for' loop with
> a fixed number of iterations is not usully one of them!
>
> The simplest is to use while(). A possibly strategy is
>
> Y.old <- initial.Y
> while(TRUE){
> Y <- compute.Y(Y.old, ...)
> if(abs(Y - Y.old)
Classification: UNCLASSIFIED
Caveats: NONE
I have a large group randomized trial (pre-post design) where the
randomization was marginally successful. Given the pre-existing
differences among groups, it makes sense to report adjusted means (aka
least squares means though I estimated them via pre
Hello,
I have got a question.
I've got a matrix (mail end) with the colnames x, y, z. In this matrix
are different measurements. x and y are risign coordinates.
My question. Always, if the "x" AND "y" coordinates are the same, I want to
get the mean of their z values.
e.q. "
x" AND "y" in line
?as.numeric
-Message d'origine-
De : [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] De la part de elyakhlifi
mustapha
Envoyé : jeudi 19 avril 2007 15:30
À : R-help@stat.math.ethz.ch
Objet : [R] hello
ok how can I do to cancel le function factor for the moment ican't do this and
I'm stuck w
On Thu, Apr 19, 2007 at 02:10:37PM +0200, Schmitt, Corinna wrote:
>> Hi, the length of the coordinates are different.
>>
>> Try:
>> plot(seq(0,60, l=100), seq(0,0.896, l=100), type="n", xlab="Zeit [min]",
>> ylab="Absorptionsmessung
>>bei 600nm",main="Zellwandstabilit?t" )
> I know, but it
2007/4/19, Schmitt, Corinna <[EMAIL PROTECTED]>:
> Thanks.
>
> I did read everything I could but could not understand everything. Hopefully
> with more programming practice it will become more less.
Here is a great book:
Uwe Ligges: Programmieren mit R.
worth every "Rappen"
:-)
_
ok how can I do to cancel le function factor for the moment ican't do this and
I'm stuck with my problem for exemple
Id_Rep Id_Geno Val_O Id_TrT1
1 1 64238 145 2
2 1 64238 1 1
3 1 64238 2 1
4 1 64238 1 1
5 1 64
Thanks Torsten,
That seems to fit the bill nicely!
Best,
Florian
Florian Koller-Meinfelder
Research Consulting & Development
__
GfK Fernsehforschung GmbH
Nordwestring 101
90319 Nürnberg
Tel +49 (0)911 395-3554
Fax +49 (0)911 395-4130
www.gfk.com/gfkfernseh
Bob Green wrote:
> I am hoping for some advice regarding limiting decimal points to 3.
> 'Round' produces the desired results except for the 97.5% confidence interval.
> Any advice as to how I modify the code to obtain output to 3 decimal
> points for all ouput is appreciated,
>
The rounding
On Thu, 19 Apr 2007, Florian Koller-Meinfelder wrote:
Dear R-helpers,
I am looking for a segmentation package that gives some "tree identifier"
as output for every observation in the data set (my response variable is
binary). I have skimmed through "rpart", "ada" and "adabag": The output
"tree
rach.s wrote:
> hie..
> how can i write a loop that makes algorithm keeps repeating until a solution
> is converged?do i use a for loop? i know that we can use for loop to ask for
> a number of repetitions, but how to use it to ask the algorithm to keep
> repeating until a solution is converged?
g
No, use a while loop. Something like
change <- 1
while(abs(change) > .001 ){
do stuff
change <- updated change
}
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of rach.s
> Sent: Thursday, April 19, 2007 8:00 AM
> To: r-help@stat.math.
On 19-Apr-07 12:00:17, rach.s wrote:
>
> hie..
> how can i write a loop that makes algorithm keeps repeating
> until a solution is converged?do i use a for loop? i know
> that we can use for loop to ask for a number of repetitions,
> but how to use it to ask the algorithm to keep repeating
> until
I suspect you'll greatly benefit a read of Prof. Fox's book(s) on
regression models, as well as making use of his "car" package. You may
want to read up on partial residual plots and partial regression plots.
Andy
From: Simon Pickett
>
> Hi all,
>
> I have been bumbling around with r for years
Hi Jenny,
On Thu, 19 Apr 2007 12:48:50 +0100 (BST) Jenny Barnes <[EMAIL PROTECTED]> wrote:
> Dear R-Help,
>
> I am trying to find a function that will give me the significance of the
> correlation of 2 variables (in the same dimension arrays) correcting for
> serial
> autocorrelation.
I am n
Hi,
> I did read everything I could but could not understand everything. Hopefully
with more programming
> practice it will become more less.
Then maybe you read everything you could a bit too fast. Because the answer to
your question is in the first document to read, "An introduction to R", sect
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