- this.is.R
identical(f, eval(parse(text=attr(f, source))[[1]]))
[1] FALSE
f - function() TRUE
identical(f, eval(parse(text=attr(f, source))[[1]]))
[1] TRUE
-- Tony Plate
At Thursday 09:12 PM 10/23/2003 +0200, Peter Dalgaard wrote:
Tony Plate [EMAIL PROTECTED] writes:
Why is the body
median() has this test in it:
if (mode(x) != numeric)
stop(need numeric data)
Note the following:
is.numeric(factor(letters))
[1] FALSE
mode(factor(letters))
[1] numeric
It seems as though median() is using the wrong test.
-- Tony Plate
At Friday 03:37 PM 10/31/2003 -0500, [EMAIL
). Also, note
that this technique produces a NA fitted value where a non-NA one could be
produced (use predict(m, newdata=data) to get those values.)
hope this helps,
Tony Plate
At Thursday 11:40 AM 11/13/2003 +1300, Murray Jorgensen wrote:
Suppose you fit a linear model
model.1 ~ lm(v1
Is there some reason that the simple obvious does not work or is in some
way not adequate?
data - data.frame(x=c(1:5), y=c(1,3,2,NA,4))
nls(y ~ A*x^2 +sqrt(0.08*A)*x, data=data, start=list(A=0))
Nonlinear regression model
model: y ~ A * x^2 + sqrt(0.08 * A) * x
data: data
A
))
+ }
x - sample(c(T,F),1e7,rep=T)
system.time(most.recent.cut(x))
[1] 41.21 0.54 41.98NANA
system.time(most.recent(x))
[1] 2.67 0.08 2.78 NA NA
-- Tony Plate
At Friday 10:21 PM 11/14/2003 -0500, Gabor Grothendieck wrote:
From: Tony Plate [EMAIL PROTECTED]:
Here's a function
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Tony Plate [EMAIL PROTECTED]
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).
hope this helps,
Tony Plate
At Wednesday 02:31 PM 12/3/2003 -0800, [EMAIL PROTECTED] wrote:
Hi,
This is more a statistics question rather than R question. But I thought
people on this list may have some pointers.
MY question is like the following:
I would like to have a robust regression
this helps,
Tony Plate
At Friday 04:33 PM 12/5/2003 +, Ognen Duzlevski wrote:
Hi, I have a piece of code originally written for s-plus - I am trying to
run it in R now. The code was obtained from someone who is now not
available to give any pointers and I am a beginner in R. Here is where
34
hope this helps,
Tony Plate
PS. To advanced R users: Is the above usage of the colnames- function
within an expression regarded as acceptable or as undesirable programming
style? -- I've rarely seen it used, but it can be quite useful.
At Wednesday 09:28 PM 12/17/2003 +0200, Adrian Dusa
Thanks. As a follow-up question, is it considered acceptable programming
practice for - functions to modify their x argument?
-- Tony Plate
At Thursday 12:23 AM 12/18/2003 +0100, Peter Dalgaard wrote:
Tony Plate [EMAIL PROTECTED] writes:
xx - rbind(colnames-(x[,c(rel1,age0,age1,sex0,sex1
, people told that they
should have contacted the package maintainer first.)
-- Tony Plate
At Wednesday 07:26 PM 12/17/2003 -0500, Liaw, Andy wrote:
From: Tom Mulholland
I have empathy for lots of the points already made, more
often on the life
is not always easy and you have to work
())
-- Tony Plate
At Tuesday 11:46 AM 2/4/2003 -0500, Mark G Orr wrote:
Hello, I'm somewhat new to R. I've searched the archive for the last year
and tried to consult the manual pages for the following problem, but did
not find an answer.
I want to sort an array by the index values. Here
Does this do what you want?
x - c(2.503,2.477,0.1204)
sapply(signif(x,3), sprintf, fmt=%#.3g)
[1] 2.50 2.48 0.120
This will give you scientific notation for very large or small numbers.
At Friday 02:17 PM 3/14/2003 -0800, Don MacQueen wrote:
I need a function like signif(), but returns
As wolski/Eryk's example shows, it seems that [[ for lists accepts abbreviations,
whereas [ does not. Is this intended? (This is a difference from S-plus - both [
and [[ for lists accept abbreviations in S-plus (V6.1 for Windows at least.)
I couldn't find any mention of this difference in
At Monday 07:31 PM 3/24/2003 +0100, Uwe Ligges wrote:
Tony Plate wrote:
As wolski/Eryk's example shows, it seems that [[ for lists accepts abbreviations,
whereas [ does not. Is this intended? (This is a difference from S-plus - both
[ and [[ for lists accept abbreviations in S-plus (V6.1
The [ operator also takes a drop= argument (type ?[ to see the help page and find
details.)
So you can do what you want in a single step, as follows:
subData - dataFrame[dataFrame[,2]=Min dataFrame[,2]=Max, , drop=F]
[If your dataFrame object really is a data.frame, the drop=F shouldn't be
From ?paste:
If a value is specified for `collapse', the values in the result
are then concatenated into a single string, with the elements
being separated by the value of `collapse'.
paste(c(Bob, loves, Sally), collapse= )
[1] Bob loves Sally
At Wednesday 03:54 PM 4/2/2003 -0800,
At Wednesday 03:28 AM 6/11/2003 +0200, Jonck van der Kogel wrote:
Hi all,
I have (yet another) question about a function in R. What I would like to
do is test for the presence of a certain value in a vector, and have the
positions that this value is at returned to me.
For example, let's say I
).
hope this helps,
Tony Plate
At Thursday 04:37 PM 7/10/2003 -0400, kschlauc wrote:
Can someone tell me which version of R began to order
alpha-numeric strings in this manner:
ABC 10 ABC 2
rather than
ABC 2 ABC 10 ?
And, is there a way to force ABC 2
to be ordered as a value less than ABC 10?
thank
hist(sample(0:3, 10, T), breaks=(0:4)-0.5)
At Thursday 02:32 PM 7/17/2003 -0700, Jay Pfaffman wrote:
I've got a data set with integer codes from 0--3. I'd like a
histogram with a single bar for 0, 1, 2 and 3. I'd like each of the 4
bars centered over a label.
hist(mydata, breaks=4,
that the x and y elements
have different lengths, to provide a quick check that the x and y
dimensions were not swapped somewhere along the way.
hope this helps,
Tony Plate
At Monday 01:45 PM 7/21/2003 -0400, john lewis wrote:
R- Users:
Can someone indicate what I am during wrong
]
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Tony Plate [EMAIL PROTECTED]
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giving the probability of each presence matrix being
generated for each component of the mixture model, but I don't know how
hard it would be implement the EM search for an appropriate mixture model.)
-- Tony Plate
At Thursday 08:55 PM 12/18/2003 +, Jarrod Hadfield wrote:
Dear All,
I have
guidelines
on what to post and how to post in a way that maximizes your
chances of getting useful answers, please read the posting
guide...
-- Tony Plate
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guide
before posting here. Several correspondents liked this idea. Is this desirable
and/or doable?
thanks for all the assistance,
Tony Plate
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to a
package that is downloaded from CRAN try contacting the package maintainers
first.
Comments welcome, however, at this point, perhaps it would be better to
send comments to me privately, as most people have probably had enough of
this discussion.
cheers,
Tony Plate
PS. There is a slightly
) %*% coef
where data is n x k matrix, coef is a vector of length k+1, and the
intercept is the first element of coef.
hope this helps,
Tony Plate
At Tuesday 10:04 AM 1/6/2004 -0500, Alexander Wise wrote:
Hello, this probably seems like an odd question, but...
If I have the formula and the coefficients
misspecification). However, because the
issues are subtle, it is easy to get results that appear significant...
hope this helps,
Tony Plate
At Tuesday 04:31 PM 1/6/2004 +0100, Christoph Lehmann wrote:
Hi
what would you recommend to compare classification methods such as LDA,
classification trees
is that you can cut and paste from script
files in order to try to track down errors. Did you try that with the
QQQ- line? (It looks fine to me, and this works for me to read .csv files.)
-- Tony Plate
At Tuesday 11:46 AM 1/6/2004 -0500, Ashutosh Tayshete wrote:
I have this line at the start of my
, MD, MSc
National Institute of Cardiology Laranjeiras
Rio de Janeiro Brazil
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PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Tony Plate
might want to check that your objective does not have local optima (in
which case the assumption that minimizing the sum-squared residual will
minimize your objective may be false).
hope this helps,
Tony Plate
At Friday 04:35 PM 1/9/2004 -0200, Bernardo Rangel Tura wrote:
Hi R masters,
Sorry
array() a data value of the correct length:
array(list()[1:4], c(2,2))
[,1] [,2]
[1,] NULL NULL
[2,] NULL NULL
-- Tony Plate
At Wednesday 10:35 AM 1/14/2004 +0100, you wrote:
Hi
In R 1.7 the following worked fine:
array(list(),c(2,5))
[,1] [,2] [,3] [,4] [,5]
[1,] NULL NULL NULL NULL
generate multiple
single-page postscript files, and then use gs to wrap them up in a pdf).
hope this helps,
Tony Plate
At Wednesday 02:19 PM 1/28/2004 -0600, Brad Holmes wrote:
Hi,
I am only a few months old at R and I have encountered an interesting issue.
Would it be possible to read in a pre
a
2 2 b
3 3 c
11 4 d
21 5 e
-- Tony Plate
At Tuesday 05:00 PM 3/9/2004, Tom Blackwell wrote:
John -
The function rbind() operates on pairs of data frames, and
(somewhat arcane and definitely NOT for beginning users)
do.call(rbind, list(df1, df2, df3, df4, df5)))
will combine any number
(i.e.,
trial and error), so they may not be particularly good or
elegant. However, I'm sure that others will point out both any problems
with these suggestions and some better solutions!
hope this helps,
Tony Plate
At Wednesday 09:05 AM 3/10/2004, Thomas Petzoldt wrote:
Hello,
I want to call
If you want to use call() with a list of arguments, the easiest way I know
of is to use do.call() (if anyone knows a better way, please say so!)
myfun2 - function(method, x, ...) {
+method.call - do.call(call, list(method, x, ...))
+eval(method.call)
+ }
myfun2('sqrt',2)
[1] 1.414214
)
attributes(ze)
$source
[1] function(){a+1}
attr(ze, source) - NULL
ze
function ()
{
b + 1
}
I previously wrote on this topic:
Date: Fri, 24 Oct 2003 09:42:55 -0600
To: [EMAIL PROTECTED], Peter Dalgaard [EMAIL PROTECTED]
From: Tony Plate [EMAIL PROTECTED]
Subject: Re: [R] what's going on here
() {
a + 1
}, list(a = quote(b)))
eval(z)
function() {
b + 1
}
eval(eval(z)) # this displays the source attribute
function(){a+1}
body(eval(eval(z)))
{
b + 1
}
hope this helps,
Tony Plate
At Thursday 12:00 PM 3/18/2004, you wrote:
Tony, Thomas. Thanks for your help. Your comments were
()) (but I haven't carefully reasoned through this being
an explanation for your particular frustration here.)
hope this might help,
Tony Plate
At Thursday 04:06 PM 3/18/2004, Gabor Grothendieck wrote:
Date: 18 Mar 2004 23:52:47 +0100
From: Peter Dalgaard [EMAIL PROTECTED]
To: [EMAIL
when requested, not by default.
* R/adrop.R man/adrop.Rd
added new function adrop(). This is a function like drop(), but it
allows to user to specify which of the dimensions with extent one
will be dropped.
Please let me know of any problems.
-- Tony Plate
Tony
before multiplying and then add
one back in at the end. However, this really was a minor inconvenience,
and if I wanted I could have written a function to do my index computations
for me. What other more significant computations are so much easier with
zero-based indexing?
-- Tony Plate
cryptic error messages.
-- Tony Plate
At Wednesday 01:07 PM 4/7/2004, Shin wrote:
When I tried the following commands, I got a strange message.
x-data.frame(y=c(1:10))
plot(x$z)
Error in xy.coords(x, y, xlabel, ylabel, log) :
x and y lengths differ
The data frame, x, does not have a field
in the function
code.) If line info was printed out only when source was saved in the
source attribute, this could still be useful.
-- Tony Plate
At Monday 05:41 PM 4/12/2004, Duncan Murdoch wrote:
On Mon, 12 Apr 2004 15:20:58 -0700, you wrote:
Hi Patrick,
It's very simple using a browser() line in your
as.numeric() (and its siblings) strip the names from vectors, e.g.:
as.numeric(t.test(rnorm(1001))$statistic)
[1] -0.6320304
hth,
Tony Plate
At Friday 05:14 PM 4/16/2004, christopher ciotti wrote:
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Hello all -
I'm trying to format some data where
(X=a, Y=b, FUN=f, d=additional)
In f: 12 12
[,1] [,2] [,3] [,4]
[1,] 53.61985 54.61985 55.61985 56.61985
[2,] 54.61985 56.61985 58.61985 60.61985
[3,] 55.61985 58.61985 61.61985 64.61985
Note that f is called only once, with vectors for a and b.
-- Tony Plate
Rau, Roland
are passing essentially a random value. By luck,
in your example, the first element was T, which is why you got a value
of 1.707825 as the result, and not NA. The rest might fall into place
when this understanding is cleared up.
-- Tony Plate
__
R-help
This is very useful, thanks for posting!
I created a page for this at the R Wiki:
http://fawn.unibw-hamburg.de/cgi-bin/Rwiki.pl?DataBases
If any one has any info to add, go at it!
-- Tony Plate
charles loboz wrote:
1. That was a part of a private email exchange. It has
been suggested
does not report all the information
that 'version' does (it omits at least Status and svn rev). R-core
members are aware of this -- whether or not they change this is up to them.]
-- Tony Plate
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R-help@stat.math.ethz.ch mailing list
https
momentum?
-- Tony Plate
Frank E Harrell Jr wrote:
I feel that as long as people continue to provide help on r-help wikis
will not be successful. I think we need to move to a central wiki or
discussion board and to move away from e-mail. People are extremely
helpful but e-mail seems
There's a gotcha in using identical() to compare dimensions -- it also
compares names, e.g.:
x - array(1:14, dim=c(rows=3,cols=5))
dim(x)
rows cols
35
identical(dim(x)+0, c(3,5))
[1] FALSE
identical(as.numeric(dim(x)+0), c(3,5))
[1] TRUE
Gabor Grothendieck wrote:
If its just
it didn't work for
you? (e.g., show the exact error message).
-- Tony Plate
Chia, Yen Lin wrote:
Hi all,
I wonder how could I convert a matrix A to a dataframe such that
whenever I'm running a linear model such lme, I can use A$x1? I tried
data.frame(A), it didn't work. Should I initialize
(2, len=length(x)-1) or seq(along=x)[-1].
-- Tony Plate
johan Faux wrote:
Hello ,
a-c(1)
for(i in 2:length(a))
do.something with a[[i]]
I get :
Error in a[[i]] : subscript out of bounds
Am I missing something here? Doesnt R check the value of i inside
- list(a=a,b=b)
x2 - list(a=a,b=b,c=c)
do.call(cbind, x1)
a b
[1,] 1 4
[2,] 2 5
[3,] 3 6
do.call(cbind, x2)
a b c
[1,] 1 4 7
[2,] 2 5 8
[3,] 3 6 9
-- Tony Plate
Leeds, Mark (IED) wrote:
I did a ?do.call but i don't think i understand it.
if a, b,c,d are numeric vectors
Your problem is that you are using cat() on a factor. Use
as.character() or format() to convert the factor to character data,
which cat will then print in the way you want.
x - data.frame(L=letters[1:3])
x
L
1 a
2 b
3 c
x$L
[1] a b c
Levels: a b c
cat(x$L, \n)
1 2 3
together vectors
and arrays into higher dimensional arrays -- it might come in handy for you.
-- Tony Plate
Piet van Remortel wrote:
Hi all,
I am faced with the situation where I want to store/analyze
relatively large, organized sets of numerical data, which depend on a
number
you try using that optimization routine with this problem?
-- Tony Plate
dave fournier wrote:
There has recently been some discussion on the list about
AD Model builder and the suitability of R for constructing the
types of models used in fisheries management.
https://stat.ethz.ch
, 11:14)
-- Tony Plate
Jacques Ropers wrote:
But you got only two (eventually one) distinct values, right? Look at
the code for 'ifelse': yes and no are only called once each, then
recycled to desired length.
I guess you want something like
x - rnorm(10)
y - rnorm(10)
z - rnorm(10)
y1 - ifelse(x
unwanted interpretations of certain bit patterns.
-- Tony Plate
Knut M. Wittkowski wrote:
We have packed logical vectors into integers, 32 flags at a time and
then want to AND or OR these vectors of integers using other C functions.
The problem: occasionally, the packed sequence of 32 logical
date
1 1 2005-01-24
2 2 2006-01-23
3 3 2006-01-23
class(x)
[1] data.frame
sapply(x, class)
int date
integerDate
-- Tony Plate
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
By-Conversation.
Hope this helps (in case the horse was not thoroughly dead already.)
-- Tony Plate
Kimpel, Mark William wrote:
See below for Bert Gunter's off list reply to me (which I do
appreciate). I'm putting it back on the list because it seems there is
still confusion regarding
a - data.frame(value=c(6.5,7.5,8.5,12.0),class=c(1,3,5,2))
x - c(1,1,2,7,6,5,4,3,2,2,2)
match(x, a$class)
[1] 1 1 4 NA NA 3 NA 2 4 4 4
a[match(x, a$class), value]
[1] 6.5 6.5 12.0 NA NA 8.5 NA 7.5 12.0 12.0 12.0
-- Tony Plate
javier garcia-pintado wrote:
Hello
cat('Open fnd test\n')
Open fnd test
cat(Open fnd \test\\n)
Open fnd test
Bos, Roger wrote:
Can anyone tell me how to get R to include a double quote in the middle
of a character string?
For example, the following code is close:
fnd-Open fnd 'test'
cat(fnd)
Open fnd
-behaved
function. It may be possible to increase the number of steps, but I
don't see how from the docs for ?optim. Of course, the source is available.
hope this helps,
Tony Plate
Petr Klasterecky wrote:
Hi,
my call of optim() with the L-BFGS-B method ended with the following
error message
States.1252
attached base packages:
[1] stats graphics grDevices utils datasets methods
[7] base
other attached packages:
fCalendar fEcofin
240.10068 240.10067
Sys.getenv(TZ)
TZ
-- Tony Plate
Michael Toews wrote:
Those numbers look like ... well, numbers. You want
’timeDate’ and ’timeSeries’ Classes for R, Diethelm W¨urtz
http://www.itp.phys.ethz.ch/econophysics/R/pdf/calendar.pdf
-- Tony Plate
Michael Toews wrote:
Sadly, I don't know of any tutorials or much help on the web for R ...
that doesn't mean it doesn't exist ... you might just have to look
around
columns in a data frame, then just do
table(X$factor1, X$factor2)
hope this helps,
Tony Plate
Michela Cameletti wrote:
Dear R-users,
I have a little problem that I can't solve by myself.
I have a data frame with 2 factors and 8 observations (see the following
code):
y - c
on the Wiki, please go ahead!)
-- Tony Plate
Petr Pikal wrote:
Hi
On 27 Mar 2007 at 9:09, Charles Dupont wrote:
Date sent:Tue, 27 Mar 2007 09:09:27 -0500
From: Charles Dupont [EMAIL PROTECTED]
Organization: Vanderbilt University; Department
Peter Dalgaard wrote:
Daniel Berg wrote:
Dear all,
Suppose I have a very long expression e. Lets assume, for simplicity, that
it is
e = expression(u1+u2+u3)
Now I wish to replace u2 with x and u3 with 1. I.e. the 'new'
expression, after replacement, should be:
e
Here's some timings on seemingly minor variations of data structure
showing timings ranging by a factor of 100 (factor of 3 if the worst is
omitted). One of the keys is to avoid use of the partial string match
that happens with ordinary data frame subscripting.
-- Tony Plate
n - 1
to know for myself what sort of speed differences there was now
among the various approaches.
-- Tony Plate
Iestyn Lewis wrote:
This is fantastic. I just tested the first match() method and it is
acceptably fast. I'll look into some of the even better methods
later. Thank you for taking
Try the following and look at what they return:
str(ca)
dimnames(ca)
-- Tony Plate
[EMAIL PROTECTED] wrote:
Dear R-Experts,
I just imported a workspace from Matlab. I know that I can get the names of
the imported variables with names(). It works. The variable ca consists of
several
I don't think there's that sort of apply-reduce function in R, but for
this problem, the last line below happens to be a one-liner:
set.seed(1)
x - lapply(1:10, function(i) sample(letters, 20))
table(unlist(x))
a b c d e f g h i j k l m n o p q r s t u v w x
y
I use regexpr() instead of grep() in cases like this, e.g.:
x2[regexpr(exclude,x2)==-1]
(regexpr returns a vector of the same length as character vector given
it, so there's no problem with it returning a zero length vector)
-- Tony Plate
Peter Dalgaard wrote:
Stephen Tucker wrote:
Dear R
do.call(rbind, l)
or, in the case of matrices, using the abind package:
abind(l, along=1)
library(abind)
l - list(matrix(1:6, ncol=2), matrix(11:14, ncol=2))
abind(l, along=1)
[,1] [,2]
[1,]14
[2,]25
[3,]36
[4,] 11 13
[5,] 12 14
Hendrik Fuß wrote:
the DESCRIPTION file:
Package: RSVGTipsDevice
Version: 0.7.0
Date:04/30/2007
Title: An R SVG graphics device with dynamic tips and hyperlinks
Author: Tony Plate [EMAIL PROTECTED], based on RSvgDevice by T Jake
Luciani [EMAIL PROTECTED]
Maintainer: Tony Plate [EMAIL PROTECTED]
Depends: R
in
this type of situation? I couldn't find any help in the section
Debugging R Code in R-exts (or anything at all relevant in R-intro).
(Different values for options(error=...) and different formatting of the
function made no difference.)
-- Tony Plate
sessionInfo()
R version 2.5.0 (2007-04-23
, and on developer.r-project.org but was unable to
find clear guidance there either.
-- Tony Plate
On Mon, 7 May 2007, Tony Plate wrote:
Certain errors seem to generate messages that are less informative than
most -- they just tell you which function an error happened in, but
don't indicate
(assuming model has intercept) computations for R^2:
SSE - sum((y.hat - data$y)^2)
SST - sum((data$y - mean(data$y))^2)
SSR - sum((y.hat - mean(data$y))^2)
1 - SSE/SST
[1] 0.6427161
SSR/SST
[1] 0.6427161
hope this helps,
Tony Plate
Disclaimer: I too do not have any degrees in statistics
The package RSVGTipsDevice allows you to do just it just -- you create a
plot in an SVG file that can be viewed in a browser like FireFox, and
the points (or shapes) in that plot can have pop-up tooltips.
-- Tony Plate
mister_bluesman wrote:
Hi there.
I have a matrix that provides place
does not include diagonal neighbors).
And of course, ties make things more complicated (note that the above
simple algorithm misses the local maximum consisting of two 8's in the
last row.)
-- Tony Plate
Patrick Wang wrote:
Hi,
Does anyone know how to count the number of modes in 2
The new version of RSVGTipsDevice (0.7.1) that is now available on CRAN
should fix this problem. Please let me know if it doesn't, or if there
are other problems.
-- Tony Plate
mister_bluesman wrote:
Hi there.
I am still trying to get the RSVGTipsDevice to work, yet I can not.
I have
expressions can be composed into a single
expression if you want)
-- Tony Plate
Aydemir, Zava (FID) wrote:
Hi
I rbind data frames in a loop in a cumulative way and the performance
detriorates very quickly.
My code looks like this:
for( k in 1:N)
{
filename - paste(/tmp/myData_
One simple way that I haven't seen mentioned yet is to do:
get(a)$x
(which of course allows further variants such as get(a)$x[3:6] ...)
-- Tony Plate
Juan Manuel Barreneche wrote:
my problem can be explained with the following example:
x - 1:12
y - 13:24
a - data.frame(x = x, y = y
of Observations: 20
Equivalent Number of Parameters: 4.87
Residual Standard Error: 1.179
hope this helps,
Tony Plate
D. R. Evans wrote:
I am 100% certain that there is an easy way to do this, but after
experimenting off and on for a couple of days, and searching everywhere I
could think of, I haven't
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-- Tony Plate
D. R. Evans wrote:
D. R. Evans said the following at 09/04/2007 04:14 PM :
I am 100% certain that there is an easy way to do this, but after
I have reconsidered this and now believe it to be essentially impossible
(or at the very least
result from
resource limitiations, e.g., being unable to write a save file due
to lack of disk space, or from manual tinkering, e.g., dropping a
new save file into a tracking directory.)
[truncated here -- see ?trackObjs]
-- Tony Plate
PS: to give credit where due, the end
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