That explains. Thanks!
On Sun, Oct 29, 2017 at 11:20 AM, Sam Tobin-Hochstadt
wrote:
> If you look at what `(quote-module-path food)` produces, it's just
> `(submod "/path/to/go.rkt" food)`. The issue is just that
> `namespace-require` needs a reference that it can resolve without
> knowing what f
If you look at what `(quote-module-path food)` produces, it's just
`(submod "/path/to/go.rkt" food)`. The issue is just that
`namespace-require` needs a reference that it can resolve without
knowing what file it's in -- `namespace-require`, unlike `require`, is
a just a function and doesn't know an
Thanks! That works.
I am still not sure what is the thing that I don't know. Why do we need a
compile-time reference here?
On Sun, Oct 29, 2017 at 9:59 AM, Sam Tobin-Hochstadt
wrote:
> I think you want to use `quote-module-path` here:
>
> #lang racket
>
> (require syntax/location)
>
> (module f
I think you want to use `quote-module-path` here:
#lang racket
(require syntax/location)
(module food racket
(provide apple)
(define apple "pie"))
(parameterize ([current-namespace (make-base-namespace)])
(namespace-require (quote-module-path food))
(eval 'apple))
On Sun, Oct 29, 2
Hello list,
I am trying to do namespace-require to a submodule, racket complains about
unknown module, as below:
$ cat go.rkt
#lang racket
(module food racket
(provide apple)
(define apple "pie"))
(parameterize ([current-namespace (make-base-namespace)])
(namespace-require ''food)
(
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