Follow the code :-
class Sample
def bar
p method(__method__).receiver # only `self` would do the trick.
end
end
n1=Sample.new # = #Sample:0x13bc648
n2=Sample.new # = #Sample:0x13bc630
n1.bar# = #Sample:0x13bc648
n2.bar# = #Sample:0x13bc630
But this is my try. I am looking for any
I don't think that will be possible.
A variable has an identifier ( in your case, n1 ) and a reference to an
object ( Sample:0x13bc648 ) so when you say n1 , it knows which object it
references and returns that. As far as I know Ruby doesn't keep track of
reference counts of an object and the
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