On 2012-12-05, Andrew Mathas andrew.mat...@sydney.edu.au wrote:
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- Matrices with rows and columns indexed by whatever objects
I have a (very) rough prototype for this as it is one of the things that I
huh?
sage: m=matrix([[1,2],[3,4]])
sage: m
[1 2]
[3 4]
sage: m[1,1]=100
sage: m
[ 1 2]
[ 3 100]
sage:
Yes, you're right. My issue with matrices is that I can't write something
like:
sage: matrix([[1,0],[None,0]])
(Unless, of course, you want to correct me again:)
A.
Hey Andrew,
It sounds more like you want to use a spare matrix (or even just a
dictionary with a tuple as the key) and fill in entries as you compute them.
Best,
Travis
On Wednesday, December 5, 2012 3:29:27 AM UTC-8, Andrew Mathas wrote:
huh?
sage: m=matrix([[1,2],[3,4]])
sage: m
Here's a related question: suppose I have an object G in sage. Is there a
correct way to ask G if is it a CombinatorialFreeModule? I can check for
if hasattr(G,'_basis_keys'): ...
but I would have thought that there was a better way to do this...
Andrew
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On 2012-12-05, Andrew Mathas andrew.mat...@sydney.edu.au wrote:
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Here's a related question: suppose I have an object G in sage. Is there a
correct way to ask G if is it a CombinatorialFreeModule? I can check
Yes, I worked it out and deleted my question bot before you replied it
seems.
Thanks anyway,
Andrew
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On Thu, Dec 06, 2012 at 01:13:09AM +, Dima Pasechnik wrote:
Here's a related question: suppose I have an object G in sage. Is there a
correct way to ask G if is it a CombinatorialFreeModule? I can check for
if hasattr(G,'_basis_keys'): ...
but I would have thought that there was a
