On Feb 28, 5:44 am, Marshall Hampton hampto...@gmail.com wrote:
I'm not sure this is the best answer, but you could do:
A = matrix(SR,[[a,b],[c,d]])
v1,v2 = A.eigenvalues()
show((A-v1).left_kernel().basis()[0])
show((A-v2).left_kernel().basis()[0])
Perhaps part of the issue is that these
I'm not sure this is the best answer, but you could do:
A = matrix(SR,[[a,b],[c,d]])
v1,v2 = A.eigenvalues()
show((A-v1).left_kernel().basis()[0])
show((A-v2).left_kernel().basis()[0])
Perhaps part of the issue is that these do not have to be distinct.
-M. Hampton
On Feb 27, 5:39 pm, harven