Hi all,
I am new to sage, so please forgive me if this is a trivial question.
I am trying to express certain polynomials, which are symmetric in a subset
of the variables, in terms of elementary symmetric polynomials on the
symmetric subset (with coefficients that are polynomials in the other
I was happy to see that Sage gives you the explicit map between your cubic
to its Weierstrass form. However, rather than having to do so by hand, I
was wondering if Sage is capable of giving the map from the Weierstrass
form to the original cubic, since I'd like a quick way of finding rational
Its a 4:1 map so you can't invert it...
On Saturday, May 24, 2014 4:45:11 PM UTC+1, diophan wrote:
Defn: Defined on coordinates by sending (x : y : z) to
(1/8*x*y - 1/16*y^2 - 1/8*y*z : -x^2 + 1/8*x*y + 3/16*y^2 + x*z
+ 3/8*y*z : -1/256*y^2)
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Sorry, early weekend and the brain isn't working yet. The documentation
says if morphism=True is passed, then a birational equivalence between F
and the Weierstrass curve is returned. If the point happens to be a flex,
then this is an isomorphism and I wasn't thinking.
If I find the flex point
Thanks to you, Keith!
-- Share_The_Sage!
On Saturday, May 24, 2014 1:03:21 AM UTC-3, Keith Clawson wrote:
Hi,
I fixed the problem (it was an incorrect IP address).
Thanks,
Keith
On Friday, May 23, 2014 3:59:50 PM UTC-7, share the sage wrote:
Hi sage community!
Right now aleph
On Saturday, May 24, 2014 9:18:29 AM UTC-7, Volker Braun wrote:
Its a 4:1 map so you can't invert it...
I would find that surprising. For a general plane cubic, there are good
recipes for getting a 9:1 map to a Weierstrass model in general and a 1:1
map when a rational point is specified. A
Yes I just started looking at this again about an hour ago. It looks like
the way Sage gets the map is only by doing linear changes of coordinates on
P^2 and a Cremona, as outlined here:
To get back to the question, did you find the inverse by hand or is there
something in Sage to help out? I have potentially a large number of cubics
I'd like to carry this out with and if there's a way to avoid doing it by
hand each time that'd be great.
On Saturday, May 24, 2014 4:38:48 PM
diophan wrote:
To get back to the question, did you find the inverse by hand or is
there something in Sage to help out? I have potentially a large number
of cubics I'd like to carry this out with and if there's a way to avoid
doing it by hand each time that'd be great.
Ahem, ever heard of tab
On Saturday, May 24, 2014 9:38:48 PM UTC+1, Nils Bruin wrote:
You'd expect that from a y^2=quartic in x model.
Yes, I was thinking about the degree-2 case... which is also implemented
btw ;-)
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