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From: Willy Leenders [EMAIL PROTECTED]
To: sundial@rrz.uni-koeln.de
Sent: Thursday, September 12, 2002 12:23 PM
Subject: Re: On bifilar polar sundial
Dear Frans, Jose, Anselmo and all,
There is an other analytical equation for the curved gnomon of the
Appingedam-sundial::
x = (1 - z) * ((1 - z
Message -
From: Jose Luis Diaz [EMAIL PROTECTED]
To: sundial@rrz.uni-koeln.de
Sent: Tuesday, September 10, 2002 2:10 PM
Subject: RE: On bifilar polar sundial
I think the result is x^2 = (1 - 2z + 2z^3 - z^4) / z^2.
Kind regards,
- Original Message -
From
the
acceleration due to gravity and H the tension in the cable and C a constant.
Roger Bailey
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Willy Leenders
Sent: September 12, 2002 4:24 AM
To: sundial@rrz.uni-koeln.de
Subject: Re: On bifilar polar sundial
Dear
: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Willy Leenders
Sent: September 12, 2002 4:24 AM
To: sundial@rrz.uni-koeln.de
Subject: Re: On bifilar polar sundial
Dear Frans, Jose, Anselmo and all,
There is an other analytical equation for the curved gnomon of the
Appingedam-sundial
, 2002 12:23 PM
Subject: Re: On bifilar polar sundial
Dear Frans, Jose, Anselmo and all,
There is an other analytical equation for the curved gnomon of the
Appingedam-sundial::
x = (1 - z) * ((1 - z^2)^0.5) / z
Willy Leenders
Hasselt, Flanders in Belgium
Frans W. Maes wrote:
You
a constant.
Roger Bailey
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Willy Leenders
Sent: September 12, 2002 4:24 AM
To: sundial@rrz.uni-koeln.de
Subject: Re: On bifilar polar sundial
Dear Frans, Jose, Anselmo and all,
There is an other
Subject: On bifilar polar sundial
Hoi, Frans!
I have been playing a bit with the equations for a bifilar dial trying
to
reproduce the bifilar polar dial that I saw in your web. There you say
that the transversal gnomon is a piece of hyperbola, but I have found
that it is really a piece
I think the result is x^2 = (1 - 2z + 2z^3 - z^4) / z^2.
Kind regards,
- Original Message -
From: Frans W. Maes [EMAIL PROTECTED]
To: sundial@rrz.uni-koeln.de
Sent: Tuesday, September 10, 2002 9:13 AM
Subject: Re: On bifilar polar sundial
Dear Anselmo and all
You are right, Jose. Thanks for checking!
Frans
- Original Message -
From: Jose Luis Diaz [EMAIL PROTECTED]
To: sundial@rrz.uni-koeln.de
Sent: Tuesday, September 10, 2002 2:10 PM
Subject: RE: On bifilar polar sundial
I think the result is x^2 = (1 - 2z + 2z^3 - z^4) / z^2
: On bifilar polar sundial
Hoi, Frans!
I have been playing a bit with the equations for a bifilar dial trying
to
reproduce the bifilar polar dial that I saw in your web. There you say
that the transversal gnomon is a piece of hyperbola, but I have found
that it is really a piece of ellipse
I have been playing a bit with the equations for a bifilar dial trying to
reproduce the bifilar polar dial that I saw in your web. There you say
that the transversal gnomon is a piece of hyperbola, but I have found
that it is really a piece of ellipse (there are more solutions, but none
is an
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