Is there a way to substitute the integration variable inside an
Integral class. subs works on non integration variables, but not the
integration variable.
>>> print Integral(sin(x**2),x)
Integral(sin(x**2), x)
>>> print Integral(sin(x**2),x).subs(x,y) # I want
Integral(sin(y**2),y)
Integ
On Wed, May 27, 2009 at 6:05 PM, Luke wrote:
>
> I like the first way for the fact that it just has 'x' instead of 'x
> (t)', but I like the second way because it is simpler and easier to
> implement.
The first way needs patching sympy, exactly because it things that "x"
is just "x" and thus if
I like the first way for the fact that it just has 'x' instead of 'x
(t)', but I like the second way because it is simpler and easier to
implement.
Is there a way to redefined how x = Symbol('x')(t) would print? I
guess subclassing would be one option, take care of it there, and then
use the sec
We discuss this on IRC with Luke and Fabian. Now I understand -- Luke
wants the result of differentiating not to be instances of
Derivative() class, but rather some other symbols, e.g it should
substitute them for symbols at the end.
One way to do it is to subclass the Symbol() class that does the
On Wed, May 27, 2009 at 12:53 PM, Luke wrote:
>
> Fabian,
> I think the example you gave is good, but I think it would be better
> if you could imply that x == x(t) upon instantiation, rather than
> anytime you need to take the derivative, so that you would have
> something like:
> In [1]: t = S
Here is a concrete example of the behavior that I think would be very
useful:
(1) variables x{3}'
(2) e = sin(x1 - x2)
-> (3) e = SIN(x1-x2)
(4) f = x3*e*tan(x2)*sin(e)
-> (5) f = x3*TAN(x2)*e*SIN(e)
(6) test = dt(f)
-> (7) test = TAN(x2)*e*SIN(e)*x3' + x3*e*SIN(e)*x2'/COS(x2)^2 + x3
Jurgis Pralgauskis wrote:
> Hello,
>
> a while ago I was reading through sympy source
> and noticed You are trying to implement RETE algorithm...
> now I am in library computer, so can't find the right source file
> where it was mentioned
> but it was comment of Ondrej, that it is hard to implemen
Fabian,
I think the example you gave is good, but I think it would be better
if you could imply that x == x(t) upon instantiation, rather than
anytime you need to take the derivative, so that you would have
something like:
In [1]: t = Symbol('t')
In [2]: x = Symbol('x', args=[t])
In [3]: x.diff(
On Wed, May 27, 2009 at 12:58, Jurgis Pralgauskis
wrote:
>
> Hello,
>
> a while ago I was reading through sympy source
> and noticed You are trying to implement RETE algorithm...
> now I am in library computer, so can't find the right source file
> where it was mentioned
> but it was comment of O
Hello,
a while ago I was reading through sympy source
and noticed You are trying to implement RETE algorithm...
now I am in library computer, so can't find the right source file
where it was mentioned
but it was comment of Ondrej, that it is hard to implement it fully
CLIPS expert system tool ha
Luke wrote:
> I'm trying to better understand how Sympy is structured with regard to
> Function and Symbol.
>
> In most problems I have encountered with ODE's (and PDE's, but I'll
> limit my discussion to ODE's) of the form:
> dx/dt = f(x, t) x \in R^n, f: R^n x R ---> R^n
> there simply
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