On 05/19/2015 07:48 AM, Joachim Durchholz wrote:
An external dictionary isn't ideal but better than this, at least from
the maintainer's perspective.
Maybe we can give you better help if you describe your use case in some
more detail.
At some point I create symbols from which I know,
On 05/19/2015 02:39 AM, Aaron Meurer wrote:
On Mon, May 18, 2015 at 12:29 PM, Joachim Durchholz j...@durchholz.org
wrote:
Am 18.05.2015 um 15:56 schrieb Carsten Knoll:
I want to equip an Symbol with an additional attribute to store some
specific information right in place.
For 'normal'
Hello,
I tried to find the roots of : 2*sqrt(x)*sqrt(x**3 - x**2 + 1) + 2*x**3 -
x**2 + x*sqrt(x**3 - x**2 + 1) + 2*x**1.5 + 2*x**2.5*sqrt(x**3 - x**2 + 1)
- 3*x**2.5 - 4*x**3.5*sqrt(x**3 - x**2 + 1) - 2*x**3.5 + 5*x**4.5 -
3*x**5.5 - 1 = 0.
x = symbols('x', real=True)
f = Lambda(x,
Hi,
I have : Python 3.4.2 (v3.4.2:ab2c023a9432, Oct 6 2014, 22:15:05) [MSC
v.1600 32 bit (Intel)] on win32
Le mardi 19 mai 2015 18:25:33 UTC+2, Aaron Meurer a écrit :
What version of SymPy is this? On master I get
In [1]: x = symbols('x', real=True)
In [2]: f = Lambda(x,
You gave Python version not sympy.__version__
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Right,
I have sympy-0.7.6.win32.
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Good points.
So I conclude that it would be nice if somebody came up with a way to
allow user-defined attributes without running into namespace conflicts.
Oh, and the mechanism should be easy to use for the casual user. I have
some ideas in that direction, but I'd like to see what others think
On Tue, May 19, 2015 at 4:41 AM, Carsten Knoll carstenkn...@gmx.de wrote:
On 05/19/2015 07:48 AM, Joachim Durchholz wrote:
An external dictionary isn't ideal but better than this, at least from
the maintainer's perspective.
Maybe we can give you better help if you describe your use case in
Am I misunderstanding something here (using master):
$ isympy
Couldn't locate IPython. Having IPython installed is greatly recommended.
...
z = (4+3*I)/(3-4*I)
z
4 + 3⋅ⅈ
───
3 - 4⋅ⅈ
abs(z)
│ 1 │
5⋅│───│
│3 - 4⋅ⅈ│
simplify(abs(z))
│ 1 │
5⋅│───│
│3 - 4⋅ⅈ│
Theano is doing floating point computations whereas SymPy does the
computation using arbitrary precision.
Jason
moorepants.info
+01 530-601-9791
On Tue, May 19, 2015 at 3:14 PM, drazi...@gmail.com wrote:
Hi,
I was experimenting with the following code:
import sympy
from sympy.abc import
Well, that is exactly the problem, and what I think is a bugit should
not work like that..
Den tisdag 19 maj 2015 kl. 22:00:46 UTC+2 skrev Alexander Lindsay:
Not to hijack this post, but why does subs(phi(z,t).diff(z),...) work
when phi(z,t).diff(t,2) does not contain any derivatives of
Hi,
I was experimenting with the following code:
import sympy
from sympy.abc import x
expr = sympy.exp(-x ** 2)
from sympy.printing.theanocode import theano_function
fn_theano = theano_function([x], [expr], dims={x: 1}, dtypes={x:
'float64'})
print fn_theano([29.]),sympy.exp(-29.**2)
I got
Not to hijack this post, but why does subs(phi(z,t).diff(z),...) work
when phi(z,t).diff(t,2) does not contain any derivatives of phi with
respect to z? It seems like this substitution is saying that
phi(z,t).diff(z) = phi(z,t)
I'm new to sympy, so I apologize if this is a stupid question.
What version of SymPy is this? On master I get
In [1]: x = symbols('x', real=True)
In [2]: f = Lambda(x, 2*sqrt(x)*sqrt(x**3 - x**2 + 1) + 2*x**3 - x**2
+ x*sqrt(x**3 - x**2 + 1) + 2*x**1.5 + 2*x**2.5*sqrt(x**3 - x**2 + 1)
- 3*x**2.5 - 4*x**3.5*sqrt(x**3 - x**2 + 1) - 2*x**3.5 + 5*x**4.5 -
Hi--
This seems as good a place as any to mention something I'd been trying to
do some time ago where I ran into the same battle versus __slots__.
I wanted to add a description attribute to my Symbols for documentation
purposes. I use Sympy almost exclusively inside of the IPython notebook
I recently updated from sympy 0.7.4 (I tihnk) to 0.7.6 and now I have some
very strange behaviour with subs. The following code
from sympy.abc import phi
import sympy as sp
z=sp.Symbol('z')
t=sp.Symbol('t')
sp.pprint((phi(z,t).diff(t,2)).subs(phi(z,t).diff(z),sp.Symbol('b')(z,t)).expand())
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