Re: [sympy] Re: GSoc'16 Solver and Solveset

>I appreciate you effort, I wanted to point out that you can use the SymPy wiki >[2] to maintain your notes about your solvers and other modules. It would be >helpful to you and other people who would want to work on solvers in future. I have shifted some discussions in sympy wiki page

Re: [sympy] integration with the square root of a non-negative expressions

Oscar, Thanks again for your response and clarification, > If you want to do sqrt(P(x)) with P(x) polynomial of degree k then I > think you can have general solutions for k=1,2,3 and 4 (assuming P(x) > has no repeated roots). Sympy can do k=1 and should be able to do 2 > with a bit of help. For

Re: [sympy] A dedicated bug fixing project in GSoC

I'd be curious to hear from other organizations if such projects have been successful. I'm mainly worried that if we put such an idea on the ideas page that it would attract low quality proposals. Aaron Meurer On Sat, Feb 13, 2016 at 6:05 AM, Sumith 1896 wrote: > Hi all,

Re: [sympy] integration with the square root of a non-negative expressions

On 15 February 2016 at 15:01, Andrew Corrigan wrote: > Thank you both for your replies. I'm not sure I follow the discussion to be > honest as to how it applies to my original problem. In particular: >>> >>> Distilling this down you want to compute the integral of the

Re: [sympy] integration with the square root of a non-negative expressions

Your are talking about reduction to elliptic integrals - https://en.wikipedia.org/wiki/Elliptic_integral I do not think that sympy can currently do this (it would be a great project)! On Mon, Feb 15, 2016 at 10:01 AM, Andrew Corrigan wrote: > Thank you both for

Re: [sympy] integration with the square root of a non-negative expressions

Thank you both for your replies. I'm not sure I follow the discussion to be honest as to how it applies to my original problem. In particular: > Distilling this down you want to compute the integral of the square >> root of a quadratic > > I'm not sure that is accurate. If you are just