Sounds good, go for it!
If you can organize or link to the scattered ideas on the rest of the wiki,
all the better.
Jason
moorepants.info
+01 530-601-9791
On Sun, Apr 10, 2016 at 5:14 PM, James Milam wrote:
> Hi all,
>
> I was looking through the wiki for an ideas page
Hi, regarding the below, is it possible to increase precision for this past
(15) ? Im a little bit confused are you saying that a float set to the
default
precision will not return the accurate result but specifying the precision
will?
Also you mentioned a non float expression will return
Hi Aaron,
In tried ;
import mpmath
x = Float("1.4142", 950)
x**6000%400
But got the same sort of error message again ;
>>> x = Float("1.4142", 950)
Traceback (most recent call last):
File "", line 1, in
NameError: name 'Float' is not defined
Also, I thought I read recently that the float
Oscar you mentioned below finding the # of digits using log
and the code ;
In [1]: from sympy import mpmath
In [2]: mpmath.mp.dps = 950
In [3]: mpmath.mpf('1.4142') ** 6000 % 400
How accurate of a return do you feel this will give? Are we losing
any data, will the return be very accurate?
When using numpy Ive been using the code lines;
>
> import numpy
> (np.longdouble(1.4142)** 6000 )%400
>
> I am not sure how accurate the result is, and I have tried using other
> methods too
> but recently I found a post comparing sympy to numpy and it seems someone
> is claiming that sympy can
Hi Aaron
I tried ;
import mpmath
x = mpmath.mpf("1.4142")
x**6000 % 400
but this returned "32" for me, not 272 like you got?
Also when I tried ;
>>> x = Float("1.4142", 100)
I got this error message ?
Traceback (most recent call last):
File "", line 1, in
NameError: name 'Float' is not
Hi all,
I was looking through the wiki for an ideas page where I could post some
thoughts on a contribution idea that I do not have the time to implement.
While looking, I found a couple of idea pages but they were very old and
did not seem to be relevant. I was wondering if a general ideas
On 9 April 2016 at 19:56, Amy Valhausen wrote:
> In the thread ; https://groups.google.com/forum/#!topic/sympy/eUfW6C_nHdI
>
> I was seeking feedback and help with the problem of type ;
>
> ( 1.414213562^6000) % 400)
>
> After reviewing all the excellent collaboration at
On Saturday, April 9, 2016 at 3:36:10 PM UTC-7, Amy Valhausen wrote:
>
> Hi Case,
>
> thanks for your reply - in the thread cited ;
> https://groups.google.com/forum/#!topic/sympy/eUfW6C_nHdI
>
> The impression I get (please keep in mind Im a newbie), was that most
> of the gentleman came to