Is there any way to determine whether integral can be calculated in terms
of elementary functions?
I.e. without erf, airy, etc.
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I want to rewrite Integral of 10x^7-xy+y/x+2x^5 as sum of integrals.
Something like
Int(10x^7-xy+y/x+2x^5) = Int(10x^7)-Int(xy)+Int(y/x)+Int(2x^5)
But sympy makes its own ordering and outputs
Int(10x^7-xy+y/x+2x^5) = Int(2x^5)+Int(10x^7)+Int(y/x)-Int(xy)
Where can I override this behaviour
Suppose that I have an expression
e = x**2+sqrt(a**2*b**2)
What is the best way to assign to expression assumption that all variables
are Positive, so that equivalent of e is x**2+ab?
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I know this way, but is there any way to change this after symbol creation?
On Thursday, December 4, 2014 6:29:27 PM UTC+2, Ondřej Čertík wrote:
On Thu, Dec 4, 2014 at 7:38 AM, Paul Royik distan...@gmail.com
javascript: wrote:
Suppose that I have an expression
e = x**2+sqrt(a**2*b
How should I use factor to factor expression over irrational numbers?
For example,
x^2-4 produces (x-2)(x+2)
x^2-2 produces (x-sqrt(2))(x+sqrt(2))
x^4+1 produces (x^2-sqrt(2) x+1) (x^2+sqrt(2) x+1)
x^2+1 produces x^2+1 (only complex roots)
x^4-9 x^2-22 produces (x^2+2)(x-sqrt(11))(x+sqrt(11))
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Exactly.
Thanks.
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from sympy import *
a = symbols('a',positive=True)
(1/(sec(a)**2-1)**(3/2)).subs(sec(a)**2-1,tan(a)**2)
last statement should output something close to 1/tan^3(a), or
abs(tan(a))/tan^4(a)
But instead it outputs something unrelated: abs(tan(a))/tan^2(a)
Is this a bug or I'm missing something?
or Rational(3, 2)
On Tuesday, December 9, 2014 6:22:00 AM UTC-6, Paul Royik wrote:
from sympy import *
a = symbols('a',positive=True)
(1/(sec(a)**2-1)**(3/2)).subs(sec(a)**2-1,tan(a)**2)
last statement should output something close to 1/tan^3(a), or
abs(tan(a))/tan^4(a)
But instead
Can somebody explain how find works.
For example,
a = sympy.Wild('a', exclude=[x])
b = sympy.Wild('b', exclude=[x])
c = sympy.Wild('c', exclude=[x])
pattern = sympy.sqrt(a*x**2+b*x+c)
1/((x^2+a^2)+sqrt(a^2-x^2)).find(pattern) # - set([sqrt(a^2-x^2)])
1/((x^2+a^2)*sqrt(a^2-x^2)).find(pattern) # -
What function should I use to rewrite 2/(a*(u**2 + 1) - b*(u**2 - 1)) into
2/((a-b)*u**2+(a+b))?
Thanks.
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live.sympy.org gives Abs(tan(a))/tan(a)**2
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I need the freshest version of sympy.
Developers told me that they solved issue with inverse laplace trhansform
(1/(s-2)+3/s^7 raised an exception in 0.7.6)
How can I install it from git?
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it).
Aaron Meurer
On Wed, Dec 24, 2014 at 5:55 AM, Paul Royik distan...@gmail.com
javascript: wrote:
I need the freshest version of sympy.
Developers told me that they solved issue with inverse laplace
trhansform
(1/(s-2)+3/s^7 raised an exception in 0.7.6)
How can I install
I'm using sympy in my web-based project.
Specifically, I need to calculate integral.
However, I need to limit time and interrupt function.
Code, that I use.
import multiprocessing
class RunableProcessing(multiprocessing.Process):
def __init__(self, func, *args, **kwargs):
self.queue
Just noticed, that official example works:
from sympy.parsing.sympy_parser import (parse_expr,
standard_transformations, implicit_multiplication_application)
parse_expr(10sin**2 x**2 + 3xyz + tan
theta,transformations=(standard_transformations
+(implicit_multiplication_application,)))
But
Is there any way to stop long running function?
Simplify sometimes runs too long.
I want to terminate it after 30 seconds.
Thank you.
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I mean in program, not in command window.
On Saturday, February 21, 2015 at 1:08:10 AM UTC+2, Jason Moore wrote:
ctrl-C will terminate a running command.
Jason
moorepants.info
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On Fri, Feb 20, 2015 at 2:53 PM, Paul Royik distan...@gmail.com
javascript: wrote
Can you explain more deeply concerning integration?
How many people can access integration simultaneously?
On Thursday, March 12, 2015 at 2:25:53 PM UTC+2, Joachim Durchholz wrote:
Am 12.03.2015 um 13:17 schrieb Paul Royik:
How many concurrent instances can Sympy handle?
I.e, how many
schrieb Paul Royik:
Can you explain more deeply concerning integration?
How many people can access integration simultaneously?
Can you explain what scenario you mean?
I.e. how many people accessing SymPy via what means on what machine(s)?
I suspect a misunderstanding somewhere, but I
Thank you will look.
On Thursday, March 12, 2015 at 10:50:28 PM UTC+2, Joachim Durchholz wrote:
Am 12.03.2015 um 21:48 schrieb Paul Royik:
That's what I asked.
How to configure sympy?
SymPy does not manage multiple processes at all, it's a single-threaded
application.
You'd have
That's what I asked.
How to configure sympy?
On Thursday, March 12, 2015 at 10:30:56 PM UTC+2, Joachim Durchholz wrote:
Am 12.03.2015 um 21:14 schrieb Paul Royik:
But if integral is easy (take not much memory) is number of people is
restricted only by available memory? Can Sympy serve
But if integral is easy (take not much memory) is number of people is
restricted only by available memory? Can Sympy serve as much as memory
allows?
On Thursday, March 12, 2015 at 8:44:44 PM UTC+2, Joachim Durchholz wrote:
Am 12.03.2015 um 17:39 schrieb Paul Royik:
I'm running my site
How many concurrent instances can Sympy handle?
I.e, how many people can simultenously access diff function?
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Maybe this is property of Python, but I'm not aware about it.
expr = 1/(2*sin(x/2 + pi/4)*cos(x/2 + pi/4))
equation = Eq(expr,expr)
equation == True # outputs True
equation is True # outputs False
Why True equation is not True?
Moreover, in IDE in which I'm working, when I write equation !=
What is the difference between above two properties?
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, 2015 at 7:32 AM, Paul Royik distan...@gmail.com
javascript: wrote:
What is the difference between above two properties?
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Is there any way I can rewrite
x^2y^4 to (xy^2)^2 or x^3(x+y)^6 to (x(x+y)^2)^3
, i.e. combine base?
Exponents are guaranteed to be integers.
Thank you.
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No, there is no way.
You can use evaluate=False, when creating expressions, but it will help
partly.
For example, Add(4*x*y,-6*x*y, evaluate=False) will output -6xy+4xy (notice
order changed), but Add(4*x*y,-6*x*y) will output -2xy
On Tuesday, March 31, 2015 at 5:40:31 PM UTC+3, Milos Bogataj
I used as_numer_denom earlier and now found fraction.
Is there any difference between them?
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of fractions (e.g., fraction(1/x + 1/y) gives (1/x + 1/y, 1),
whereas (1/x + 1/y).as_numer_denom() gives (x + y, x*y)).
Aaron Meurer
On Thu, Mar 26, 2015 at 12:09 PM, Paul Royik distan...@gmail.com
javascript: wrote:
I used as_numer_denom earlier and now found fraction.
Is there any
, 2015 at 6:20 PM, Paul Royik distan...@gmail.com
javascript: wrote:
Thank you.
Got it!
On Friday, February 27, 2015 at 1:52:32 AM UTC+2, Ondřej Čertík wrote:
On Thu, Feb 26, 2015 at 4:05 PM, Paul Royik distan...@gmail.com
wrote:
It doesn't work if x is positive
Thank you.
Got it!
On Friday, February 27, 2015 at 1:52:32 AM UTC+2, Ondřej Čertík wrote:
On Thu, Feb 26, 2015 at 4:05 PM, Paul Royik distan...@gmail.com
javascript: wrote:
It doesn't work if x is positive.
Indeed, looks like a bug. As a workaround, you can always substitute
general x
Hello.
I recently needed to make all variables in expression positive.
I do this like following:
f = log(x)
a=Wild('a')
symbols = f.free_symbols
for symbol in symbols:
f = f.subs(symbol, dummy)
f = f.subs(symbol, sympy.Symbol(symbol.name, positive=True))
Now, when I do f.replace(log(a),
It appeared, that problem is with cache.
Clearing cache solves the problem.
Now, I want to ask, how cache is working in multithreaded environment?
Do all people share same cache?
On Wednesday, February 25, 2015 at 4:11:03 PM UTC+2, Paul Royik wrote:
Hello.
I recently needed to make all
symbols = f.free_symbols
for symbol in symbols:
f = f.subs(symbol, sympy.Symbol(symbol.name))
print f.replace(log(a),log(Abs(a))) # OOPS! prints log(x) instead of
log(|x|)
On Wednesday, February 25, 2015 at 6:38:12 PM UTC+2, Joachim Durchholz
wrote:
Am 25.02.2015 um 17:04 schrieb Paul Royik
a new cache)? And if so,
are you using fastcache?
Aaron Meurer
On Wed, Feb 25, 2015 at 10:04 AM, Paul Royik distan...@gmail.com
javascript: wrote:
It appeared, that problem is with cache.
Clearing cache solves the problem.
Now, I want to ask, how cache is working in multithreaded
25.02.2015 um 18:10 schrieb Paul Royik:
I mean in multithreaded environment, do people share same cache (and
same
symbols)
If person1 created x=Symbol('x') and this is cached, and person2 created
x=Symbol('x', positive=True), do they have separate x's or they mixed,
so
person1 can get
What is the best way to convert sqrt(x)*sqrt(x-4) to sqrt(x^2-4x) or
(x^2+5x+4)/sqrt(x)/sqrt(x-4) to (x^2+5x+4)/sqrt(x^2-4x)
I tried replace, but it doesn't work in second case.
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I have assumption that x is positive.
a, b = Wild...
I use like f.replace(sqrt(a)*sqrt(b), sqrt((a*b).expand()))
On Thursday, February 26, 2015 at 7:51:17 PM UTC+2, Ondřej Čertík wrote:
Hi Paul,
On Thu, Feb 26, 2015 at 8:32 AM, Paul Royik distan...@gmail.com
javascript: wrote:
What
I need something more general
On Thursday, February 26, 2015 at 7:50:15 PM UTC+2, John Peterson wrote:
On Thursday, February 26, 2015 at 8:32:11 AM UTC-7, Paul Royik wrote:
What is the best way to convert sqrt(x)*sqrt(x-4) to sqrt(x^2-4x) or
(x^2+5x+4)/sqrt(x)/sqrt(x-4) to (x^2+5x+4)/sqrt
...@gmail.com
javascript: wrote:
Maybe this:
http://stackoverflow.com/questions/366682/how-to-limit-execution-time-of-a-function-call-in-python
Jason
moorepants.info
+01 530-601-9791
On Fri, Feb 20, 2015 at 3:12 PM, Paul Royik distan...@gmail.com
javascript
I see.
On Saturday, February 21, 2015 at 4:45:49 PM UTC+2, Joachim Durchholz wrote:
Am 21.02.2015 um 11:32 schrieb Paul Royik:
So, this feature is closed?
We'd really like to have that, we're just not sure how to implement it.
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=True) will do what you want.
Aaron Meurer
On Thu, Feb 26, 2015 at 12:18 PM, Paul Royik distan...@gmail.com
javascript: wrote:
I need something more general
On Thursday, February 26, 2015 at 7:50:15 PM UTC+2, John Peterson wrote:
On Thursday, February 26, 2015 at 8:32:11 AM
Hello, Jeremy.
Try this:
from sympy.simplify.fu import TR7
TR7(cos(x)**2)
On Friday, March 27, 2015 at 8:36:43 PM UTC+2, Jeremy Holleman wrote:
Hi,
I'm relatively new to SymPy, and enjoying it so far. I'm trying to
analyze the harmonics that result when a sinusoid goes through a
*y**2*x, y, x, domain='ZZ')
The order of the generators is the same as the order in the Poly. I
don't remember if there is a better method on Poly for reordering
generators, but in the above example Poly(p, x, y) will reorder them.
Aaron Meurer
On Fri, Mar 27, 2015 at 2:50 PM, Paul
What do you mean how I would do that in a programmatic way?
On Friday, March 27, 2015 at 11:33:27 PM UTC+2, Jeremy Holleman wrote:
Update - Some combination of TR7, TR8, and expand() seems to work for
powers that I've tried. For example:
In [5]: TR8(expand(TR8(cos(x)**7)))
Out[5]:
Meurer
On Fri, Mar 27, 2015 at 1:47 PM, Paul Royik distan...@gmail.com
javascript: wrote:
This dosn't seem reasonable.
Expanding goes on the line Mul(*numer). Mul(*numer, evaluate=False)
fixes
things.
On Friday, March 27, 2015 at 4:31:58 PM UTC+2, Chris Smith wrote
It seems like TR7 reduces only cos(x)**2
On Saturday, March 28, 2015 at 3:16:53 AM UTC+2, Jeremy Holleman wrote:
I'll do that. Thanks to both of you for the help!
On Friday, March 27, 2015 at 8:30:03 PM UTC-4, Aaron Meurer wrote:
I would take a look at the fu paper for more references on
-sqrt(x+1), x)[0])
Out[2]:
2 ╱ 2
y + ╲╱ y + 2
If *y* is declared to be positive, you get the right expression.
On Wednesday, April 1, 2015 at 7:01:29 PM UTC+2, Paul Royik wrote:
Is there a function that will convert sqrt(x+1)+x+3 into y^2+y+2 with
y=sqrt
OK. Thank you.
On Friday, April 3, 2015 at 4:06:29 AM UTC+3, Francesco Bonazzi wrote:
Maybe you should read the documentation. Have a look at unevaluated
expressions.
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Thanks.
On Thursday, April 23, 2015 at 8:04:46 PM UTC+3, Matthew Brett wrote:
Hi,
On Wed, Apr 22, 2015 at 11:51 PM, Paul Royik distan...@gmail.com
javascript: wrote:
I'm looking for numerical answer. No need to find analytical solution.
On Wednesday, April 22, 2015 at 6:38:29 PM
.
Aaron Meurer
On Wed, Apr 22, 2015 at 6:17 AM, Paul Royik distan...@gmail.com
javascript: wrote:
I need to calculate P(X1.2) where X follows T distribution with 5
degrees
of freedom.
cdf(StudentT('x',5))(1.2) takes too much time.
Is there another way?
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I need to calculate P(X1.2) where X follows T distribution with 5 degrees
of freedom.
cdf(StudentT('x',5))(1.2) takes too much time.
Is there another way?
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How?
On Tuesday, April 28, 2015 at 2:04:07 PM UTC+3, Joachim Durchholz wrote:
Am 28.04.2015 um 12:42 schrieb Paul Royik:
How can I solve equation on the interval?
For example sin(x)=0, 2pi=x=4pi
Apply an assumption to x.
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Am 28.04.2015 um 13:08 schrieb Paul Royik:
How?
On Tuesday, April 28, 2015 at 2:04:07 PM UTC+3, Joachim Durchholz wrote:
Am 28.04.2015 um 12:42 schrieb Paul Royik:
How can I solve equation on the interval?
For example sin(x)=0, 2pi=x=4pi
Apply an assumption to x
How can I solve equation on the interval?
For example sin(x)=0, 2pi=x=4pi
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expr
=
2682469501914725726236807146020965585039500052171867725591732162347*exp(-60)/48648670709168952944186714683693506574127
N(expr) outputs 0.482830727370627
but
N(expr, chop=True) outputs 0
In some other expressions chop doesn't make 0.
So, how chop works?
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Hello.
I'm trying to calulate limit as x approaches infinity of e^((t-1)x)
Naturally, I got Notimplemented error Result depends on the sign of sign(t
- 1).
My question how can I in general make assumption that this limit is finite?
I mean in general, because expression for limit can be
Thank you for your response.
I made a mistake, wanted (sqrt(x)+2)(sqrt(x)-1).
But, in general, I've got the idea.
On Sunday, April 5, 2015 at 7:45:51 AM UTC+3, Ondřej Čertík wrote:
On Sat, Apr 4, 2015 at 7:15 AM, Paul Royik distan...@gmail.com
javascript: wrote:
Hwow can I make sympy
Hwow can I make sympy factor x+sqrt(x)-2 into (sqrt(x)+1)(sqrt(x)-2) ?
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Is there a function that will convert sqrt(x+1)+x+3 into y^2+y+2 with
y=sqrt(x+1)?
Subs is smart enough to make (x**4+x**2+2).subs(x**2, y) into y**2+y+2.
But it doesn't work with initial example. Even sqrt(x+1)+x+1 is not
converted into y^2+y
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Your aaproach fails when we want to substitute sqrt(xy+1) for u.
What to solve here?
On Thursday, April 2, 2015 at 4:17:54 PM UTC+3, Paul Royik wrote:
Another smart solution. Thanks a ton.
Maybe you can tell me why the following code doesn't work:
https://github.com/sympy/sympy/issues/9233
[2]:
2 ╱ 2
y + ╲╱ y + 2
If *y* is declared to be positive, you get the right expression.
On Wednesday, April 1, 2015 at 7:01:29 PM UTC+2, Paul Royik wrote:
Is there a function that will convert sqrt(x+1)+x+3 into y^2+y+2 with
y=sqrt(x+1)?
Subs is smart
]: Pow(mt[w], 2, evaluate=False)
Out[6]:
2
⎛ 2⎞
⎝x⋅y ⎠
On Tuesday, March 31, 2015 at 4:50:59 PM UTC+2, Paul Royik wrote:
Is there any way I can rewrite
x^2y^4 to (xy^2)^2 or x^3(x+y)^6 to (x(x+y)^2)^3
, i.e. combine base?
Exponents are guaranteed to be integers
Why 1/0 is complex infinity and log(0) is complex infinity?
I also found a bug with oo**zoo. It is recursion error.
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Hello.
Why solve(-(21/20)**(12*x) + 120, x) gives empty set?
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Aaron Meurer
On Fri, Jun 5, 2015 at 10:56 AM, Paul Royik distan...@gmail.com
javascript: wrote:
Hello.
Why solve(-(21/20)**(12*x) + 120, x) gives empty set?
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. I think the solution should be
log(120)/log(S(21)/20)/12. This is related to this issue
https://github.com/sympy/sympy/issues/2999.
Aaron Meurer
On Fri, Jun 5, 2015 at 10:56 AM, Paul Royik distan...@gmail.com
javascript: wrote:
Hello.
Why solve(-(21/20)**(12*x) + 120, x
Thank you.
How to make it work in real field?
On Monday, June 8, 2015 at 12:05:24 PM UTC+3, Kalevi Suominen wrote:
On Sunday, June 7, 2015 at 2:52:52 PM UTC+3, Paul Royik wrote:
Why 1/0 is complex infinity and log(0) is complex infinity?
They are shorthand notations for the limits of 1/z
at 11:53 AM, Paul Royik distan...@gmail.com
javascript: wrote:
Hello.
I noticed that sympy uses much CPU.
Is there any way I can control its usage or control the code where it
might
occur.
For now my code uses match extensively, but I still don't know what
functions use much CPU
to them.
Aaron Meurer
On Tue, Jun 2, 2015 at 11:53 AM, Paul Royik distan...@gmail.com
javascript: wrote:
Hello.
I noticed that sympy uses much CPU.
Is there any way I can control its usage or control the code where it
might
occur.
For now my code uses match extensively
Is it possible to make sympy to return oo instead of zoo for expressions
like 1/0 and tan(pi/2).
What I need is real field.
-1/0 is -oo, not zoo.
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SystemError: Parent module 'sympy.core' not loaded, cannot perform relative
import
When I try to run the following:
expr=sqrt(pi)*(sqrt(2)*(1 - I)*erf(sqrt(-I)) + sqrt(2)*(-1 +
I)*erf(sqrt(2)*(-1/2 + I/2)) + sqrt(2)*(1 + I)*erf((-1)**(1/4)) +
sqrt(2)*(1 + I)*erf(sqrt(2)*(1/2 + I/2)))/16
at
infinities than using the infinites directly, as at best an expression
simplifying itself at infinities naively will lead to nan when there
is finite limit, and at worst it will lead to a wrong result.
Aaron Meurer
On Tue, Jun 9, 2015 at 9:23 AM, Paul Royik distan...@gmail.com
javascript
limit(sin(x)**15,x,0,'+') works
limit(sin(x)**15,x,0,'-') hangs
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Can't rewrite sin(x)**17/x**17 as (sin(x)/x)**17.
Is there any way to do that?
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To
Why limit(1/x,x,0) gives me infinity?
I digged in the code and saw that default direction is right.
But how to make sympy to compute two-sided limit?
limit(1/x,x,0) should return something like nana, because one-sided limits
are not equal.
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I'm curently try to implement a little tutorial concerning limits.
On this stage I'm trying to explain inifnite limits, solved by factoring.
For example, lim x-oo
(sqrt(x^2+x))/(2x+5)=(xsqrt(1+1/x))/(x(2+5/x))=sqrt(1+0)/(2+5)=1/2
So, basically, I need to extract highest power from expression
if you
specify chop smaller than that you will not get 0 for the result:
expr.n(chop=1e-27)
0.482830727370613
expr.n(chop=1e-26)
0
On Thursday, May 21, 2015 at 1:49:34 PM UTC-5, Paul Royik wrote:
OK.
Thank you.
Could you move it to issues?
On Thursday, May 21, 2015 at 6:45:41 PM
Hello.
I noticed that sympy uses much CPU.
Is there any way I can control its usage or control the code where it might
occur.
For now my code uses match extensively, but I still don't know what
functions use much CPU: simplify, integrate, match etc.
Also, is clear_cache impacts CPU usage?
Thank
OK.
Thanks.
On Friday, July 3, 2015 at 2:47:19 PM UTC+3, Kalevi Suominen wrote:
On Friday, July 3, 2015 at 1:58:06 PM UTC+3, Paul Royik wrote:
I want to calculate inverse laplace of e^(-2s) which is dirac(t-2), but
sympy gives unevaluated.
It is currently not possible to compute
I want to calculate inverse laplace of e^(-2s) which is dirac(t-2), but
sympy gives unevaluated.
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at 8:53 AM, Paul Royik distan...@gmail.com
javascript: wrote:
Nobody could tell how chop works?
On Tuesday, May 5, 2015 at 11:41:24 AM UTC+3, Paul Royik wrote:
expr =
2682469501914725726236807146020965585039500052171867725591732162347*exp(-60
Nobody could tell how chop works?
On Tuesday, May 5, 2015 at 11:41:24 AM UTC+3, Paul Royik wrote:
expr
=
2682469501914725726236807146020965585039500052171867725591732162347*exp(-60)/48648670709168952944186714683693506574127
N(expr) outputs 0.482830727370627
but
N(expr, chop=True
Cache is cleared every request.
On Saturday, August 1, 2015 at 2:11:12 PM UTC+3, Denis Akhiyarov wrote:
Have you checked caching in sympy? I have to force clean the sympy cache
for long-term simulations.
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Again I'm asking about mod_wsgi.
I'm running some sort of webservice that uses sympy.
Site is running under apache mod_wsgi.
Users access it an everything is fine.
But sometimes when I access the page, it loads too long (even simple
example).
It looks like memory used and another query just
It never happens on the development server.
On Saturday, July 25, 2015 at 6:36:42 AM UTC+3, Sudhanshu Mishra wrote:
Hi,
Does it happen on development server too?
On Jul 25, 2015 1:39 AM, Paul Royik distan...@gmail.com javascript:
wrote:
Again I'm asking about mod_wsgi.
I'm running some
str(a).rstrip('0') trick won't won't work with complex numbers, like
0.3+0.500i
On Monday, July 13, 2015 at 7:08:27 PM UTC+3, Vinzent Steinberg wrote:
On Sunday, July 12, 2015 at 6:18:26 PM UTC+2, Paul Royik wrote:
Is it possible to set for float precision of 50
Thank you.
On Tuesday, July 14, 2015 at 11:10:38 PM UTC+3, Aaron Meurer wrote:
The printer has an option to do this. Use sstr() and set the full_prec
flag.
Aaron Meurer
On Tue, Jul 14, 2015 at 2:53 PM, Paul Royik distan...@gmail.com
javascript: wrote:
str(a).rstrip('0') trick won't
OK. Thanks.
On Monday, November 9, 2015 at 12:42:51 PM UTC+2, Mateusz Paprocki wrote:
>
> Hi,
>
> On 9 November 2015 at 09:49, Paul Royik <distan...@gmail.com >
> wrote:
> > In Mul class I see this piece of code:
> >
> > def _eval_is_real(self):
&g
In Mul class I see this piece of code:
def _eval_is_real(self):
real = True
zero = one_neither = False
for t in self.args:
if not t.is_complex:
return t.is_complex
Don't understand last two lines. How is it possible that if t is not
tom Pow subclass that evaluates like
> you want, and replace instances of Pow with your class before doing a
> substitution.
>
> Aaron Meurer
>
> On Wed, Nov 4, 2015 at 1:19 PM, Paul Royik <distan...@gmail.com
> > wrote:
> > So, there is no way to do it us
> Out[3]: -1
>
> In [4]: real_root(-1, 3)**2
> Out[4]: 1
>
> SymPy, like most math libraries, uses complex roots (i.e., principal
> roots) because they have nicer mathematical properties.
>
> Aaron Meurer
>
> On Wed, Nov 4, 2015 at 3:30 AM, Paul Royik <distan...
I have the following expresssion:
f=x**(Rational(2,3))
How can I get 1, when substituting (-1) instead of complex number?
For now, I got complex number when run f.subs(x,-1).evalf()
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(replace -1 with whatever value you want to replace). A "cleaner"
> solution would be to create a custom Pow subclass that evaluates like
> you want, and replace instances of Pow with your class before doing a
> substitution.
>
> Aaron Meurer
>
> On Wed, Nov
>
> Aaron Meurer
>
> On Fri, Nov 6, 2015 at 1:42 PM, Paul Royik <distan...@gmail.com
> > wrote:
> > I decided to use "cleaner" solution: create a custom Pow subclass that
> > evaluates. What method should I override?
> >
> > On Wed
simplify(2log(5)) returns log(25)
How to revert this?
On Monday, October 19, 2015 at 10:35:45 AM UTC+3, Francesco Bonazzi wrote:
>
>
>
> On Monday, 19 October 2015 07:12:46 UTC+2, Paul Royik wrote:
>>
>> Hello.
>> I noticed that simplify moves coefficient of logarith
s:
>
> In [6]: l = log(25)
>
> In [7]: l.replace(lambda expr: isinstance(expr, log), lambda expr: factor(
> expr))
> Out[7]: 2*log(5)
>
>
>
> On Monday, 19 October 2015 11:32:34 UTC+2, Paul Royik wrote:
>>
>> simplify(2log(5)) returns log(25)
>> How to re
But this can't be reproduced.
It is a bug from time to time.
How can this be possible?
On Friday, July 10, 2015 at 1:49:56 AM UTC+3, Aaron Meurer wrote:
This looks like a bug. Numerical values should be evaluated in
inequalities.
Aaron Meurer
On Thu, Jul 9, 2015 at 5:23 PM, Paul Royik
I'm using sympy on my site together with django and mod_wsgi.
From time to time (i.e. this error is not reproducible) I've got the
following error:
TypeError: cannot determine truth value of
3*pi/8 = 7*pi/8
In other words, error is raised when I try to compare numerical values.
Can someone
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